Answer: The maximum amount of C that can be produced is 2.0 mol.
Explanation:
The balanced equation will be as follows.
[tex]4A + 3B \rightarrow 4C[/tex]
As we are given that,
moles of C = moles of A = [tex]\frac{4}{3}[/tex] moles of B
When we react 2.0 mol A with 3.0 mol B then the limiting reagent is A as specie A has less number of moles. Therefore, the maximum amount of C which can be produced is as follows.
[tex]\frac{2.0}{4} \times 4[/tex]
= 2.0 mol
Therefore, we can conclude that the maximum amount of C that can be produced is 2.0 mol.
The maximum amount of product C that can be produced when reacting 2.0 mol A with 3.0 mol B is 2.0 mol C.
This is because the stoichiometry of the reaction indicates that 2.0 mol A can produce a maximum of 2.0 mol C, and this is the limiting reactant in the reaction. The information that 3.0 mol B can produce 4.0 mol C is irrelevant in this case since B is in excess and the amount of product C formed is limited by the amount of reactant A.
To understand this, let's consider the stoichiometry of the reaction:
[tex]\[ aA + bB \rightarrow cC \][/tex]
From the given information, we can deduce the following stoichiometric coefficients for the reactants:
[tex]\[ 2.0 \text{ mol A} \rightarrow 2.0 \text{ mol C} \] \[ 3.0 \text{ mol B} \rightarrow 4.0 \text{ mol C} \][/tex]
However, since A is the limiting reactant, we use its stoichiometry to determine the maximum amount of C that can be produced:
[tex]\[ 2.0 \text{ mol A} \rightarrow 2.0 \text{ mol C} \][/tex]
Thus, even though there is excess B that could theoretically produce more C, the actual amount of C produced is constrained by the amount of A present. Therefore, the reaction of 2.0 mol A with 3.0 mol B will yield 2.0 mol C, as A is the limiting reactant.
how much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Answer:
13mL
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
HNO3 + KOH —> KNO3 + H2O
From the balanced equation above, we obtained the following data:
Mole ratio of the acid (nA) = 1
Mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question.
This includes the following:
Molarity of the acid (Ma) = 6M
Volume of the acid (Va) =?
Volume of the base (Vb) = 39mL
Molarity of the base (Mb) = 2M
Step 3:
Determination of the volume of the acid.
Using the equation:
MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:
MaVa/MbVb = nA/nB
6 x Va / 2 x 39 = 1/1
Cross multiply to express in linear form
6 x Va = 2 x 39
Divide both side by 6
Va = (2 x 39)/6
Va = 13mL
Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL
What volume of water should be used to dissolve 19.6 g of LiF to create a 0.320 M solution?
Answer:
2.4 L
Explanation:
Given data:
Mass of LiF = 19.6 g
Molarity of solution = 0.320 M
Volume of water used = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 19.6 g/ 26 g/mol
Number of moles = 0.75 mol
Volume required:
Molarity = number of moles/ volume in L
0.320 M = 0.75 mol / volume in L
Volume in L = 0.75 mol /0.320 M
M = mol/L
Volume in L = 2.4 L
At room temperature, which answer is the most compressible?
one liter of water, a liquid
one liter of oxygen, a gas
one liter of iron, a solid
one liter of mercury, a liquid
Answer:
i think its 1 liter of oxygen , a gas
Final answer:
One liter of oxygen gas is the most compressible among the options given, due to the significant spaces between gas molecules allowing for easier compression.
Explanation:
When considering the compressibility of various substances at room temperature, gases such as oxygen are the most compressible due to the large spaces between their molecules. In comparison, liquids like water and mercury are less compressible because their molecules are closer together, but they still offer some degree of compressibility. Solids like iron, however, are much less compressible because their atoms are tightly packed in a lattice structure. Of the options provided, one liter of oxygen gas would be the most compressible, as the spacing between gas molecules allows them to be pushed closer together far more easily than molecules in a liquid or atoms in a solid.
the amount of calcium hydroxide needed to react completely with a 100.0 g of nitric acid
Answer:
The answer to your question is 58.7 g of Ca(OH)₂
Explanation:
Data
mass of Ca(OH)₂ = ?
mass of HNO₃ = 100 g
Process
1.- Write the balanced chemical reaction
Ca(OH)₂ + 2HNO₃ ⇒ Ca(NO₃)₂ + 2H₂O
2.- Calculate the molar mass of the reactants
Ca(OH)₂ = 40 + 32 + 2 = 74 g
HNO₃ = 1 + 14 + 48 = 63 g
3.- Use proportions to calculate the mass of Ca(OH)₂
74 g of Ca(OH)₂ ----------------- 2(63) g of HNO₃
x ----------------- 100 g of HNO₃
x = (100 x 74) / 2(63)
x = 7400 / 126
x = 58.7 g
How many dots should be shown in the Lewis dot diagram of carbon?
1
2
3
4
Answer:
Im 90% sure its 3.
Explanation:
Answer:
4
Explanation:
Consider the equation ; N₂ + 3 H₂ → 2 NH₃ What is the mole ratio of hydrogen to ammonia (NH₃)?
1. 1:1
2. 1:2
3. 3:2
4 5:4
Answer:
3. 3:2
Explanation:
in the reactants, 3 is the coefficient for the hydrogen atoms.
In the products, 2 is the coefficient for the ammonia atoms.
how is temperature related to the physical change of a substance ?
Answer: Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.
Explanation:
If 35 mL of 0.10 Macid solution is neutralized by 21.8 mL of a basic solution, what is the molarity
of the base? MaVa = MbVb
11. A wasp lays its eggs on a caterpillar. When the wasp eggs hatch, the larva will eat the caterpillar
and kill it. *
(2 Points)
O
A. Parasitism
O
B. Mutualism
O
C. Commensalism
Answer:
A
Explanation:
That is the only one that makes sense. Parasitism harms the the host while the parasite gains.
Ozone reacts completely with NO, producing NO2 and O2. A 13.0 L vessel is filled with 1.30 mol of NO and 1.30 mol of O3 at 401.0 K. Find the partial pressure of each product and the total pressure in the flask at the end of the reaction.
Answer:
6.58 atm total
3.29 atm NO2
3.29 atm O2
Explanation:
Balanced equation:
O3 + NO → NO2 + O2
There are equal numbers of moles of both reactants, so neither is in excess and either could be considered the limiting reactant.
( 1.30 mol NO) x (1 mol NO2 / 1 mol NO) = 1.30 mol NO2
( 1.30 mol NO) x (1 mol O2 / 1 mol NO) = 1.30 mol O2
Total pressure by using the formula;
P = nRT / V
= ( 1.30 mol + 1.30 mol) x (0.08205746 L atm/K mol) x (401.0 K) / (13.0 L)
= 6.58 atm
Partial pressure for NO2;
(6.58 atm) x (1.30 mol NO2) / (1.30 mol + 1.30 mol)
= 3.29 atm NO2
Partial pressure for O2
6.58 atm total - 3.29 atm NO2
= 3.29 atm O2
1. The partial pressure of nitrogen dioxide ([tex]NO_2[/tex]) is equal to 3.29 atm.
2. The partial pressure of oxygen gas ([tex]O_2[/tex]) is equal to 3.29 atm.
3. The total pressure in the flask at the end of the chemical reaction is 6.58 atm.
Given the following data:
Volume of flask = 13.0 LitersNumber of moles of NO = 1.30 moles.Number of moles of [tex]O_3[/tex] = 1.30 moles.Temperature = 401.0 K.Scientific data:
Ideal gas constant, R = 0.0821L⋅atm/mol⋅KTo determine the partial pressure of each product and the total pressure in the flask at the end of the chemical reaction:
First of all, we would write a balanced chemical equation for the chemical reaction as follows:
[tex]O_3 + NO \rightarrow NO_2+O_2[/tex]
Since the numbers of moles of reactants are equal, the total number of moles of products is:
[tex]n=1.3+1.3[/tex]
n = 2.6 moles
Now, we can find the total pressure in the flask at the end of the chemical reaction by using the ideal gas law equation;
[tex]PV=n RT[/tex]
Where;
P is the pressure.V is the volume.n is the numbers of moles of gas.R is the ideal gas constant.T is the temperature.Making P the subject of formula, we have;
[tex]P=\frac{nRT}{V}[/tex]
Substituting the parameters into the formula, we have;
[tex]P=\frac{2.6 \times 0.0821 \times 401}{13}\\\\P=\frac{85.597}{13}[/tex]
Total pressure, P = 6.58 atm.
Next, we would determine the partial pressure of each product:
[tex]Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}[/tex]
[tex]Molefraction \;of \;a \;substance =\frac{1.3}{2.6} \\\\Molefraction \;of \;a \;substance =0.5[/tex]
For [tex]NO_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]NO_2[/tex] = 3.29 atm.
For [tex]O_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]O_2[/tex] = 3.29 atm.
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Carbon-14 is an element which loses exactly half of its mass every 5730 years. The mass of a sample of
carbon-14 can be modeled by a function, M, which depends on its age, t (in years).
We measure that the initial mass of a sample of carbon-14 is 741 grams.
Answer:
[tex]M=741\times (0.5)^{\frac{t}{5730}}[/tex]
Explanation:
by using well known formula for disintegration
[tex]M=M_0\times (0.5)^{\frac{t}{T}}[/tex]
Final answer:
To calculate the original mass of carbon-14 in an artifact aged 10,670 years, given it now contains 8.4 × 10⁽⁻⁹⁾ grams of carbon-14, we use the half-life of carbon-14 (5,730 years) and the formula for exponential decay. The original mass is found to be 33.6 × 10⁽⁻⁹⁾ grams.
Explanation:
The subject of the question involves using exponential decay to calculate the original mass of carbon-14 in an archaeological artifact, taking into account the half-life of carbon-14, which is 5,730 years. Given that a sample now contains 8.4 × 10-9 grams of carbon-14 and its age is 10,670 years, we can calculate the original amount of carbon-14 it contained. To find the original mass of carbon-14, we can use the formula for exponential decay, M = M0(1/2)t/T, where M is the final mass, M0 is the original mass, t is the time elapsed, and T is the half-life of the substance.
Since 10,670 years is exactly two half-lives of carbon-14 (2 × 5,730), we can calculate that the artifact originally contained 8.4 × 10-9 grams × 22 = 33.6 × 10-9 grams of carbon-14.
The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224 g of this metal by 71°C.
Answer:
Preceding accumulative aggregate of energy indispensable is disseminated as 5455 J.
Explanation:
Allotted the contiguous information:
Q: Not identified.
M: 224 g
S: 0.343 J/g°C
Final thermodynamics: 71°C
Initial thermodynamics: 0°C
ΔT = 71°C
We can equate as imminent:
Q = 224 g · 0.343 J/g°C · 71°C
Q ⇒ 5455 J
Hence, the pertaining preeminent albeit paramount indispensable consignment or quantity of energy obligated, concerning an augmentation in thermodynamics subject to the undisclosed metal by 71°C is 5,455 J.
The energy required to raise the temperature of the metal is 5365.256 J.
Explanation:To calculate the energy required to raise the temperature of a substance, we use the formula:
q = m * c * ΔT
The energy required to raise the temperature of a substance can be calculated using the formula: q = mcΔT where q is the energy in joules, m is the mass in grams, c is specific heat capacity in J/(g•°C), and ΔT is the change in temperature in °C.
Given that the mass (m) of the metal is 224 g, the specific heat capacity (c) is 0.343 J/(g•°C), and the temperature change (ΔT) is 71°C, you can substitute these values into the formula:
Plugging in the values given:
q = (224 g) * (0.343 J/(g•°C)) * (71°C)
Simplifying the equation gives:
q = 5365.256 J
Therefore, the energy required to raise the temperature of 224 g of this metal by 71°C is 5365.256 J.
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A unicellular, prokaryotic organism is discovered by scientists. Are these characteristics enough to place it in a domain, or is more information needed?
PLZ HELP!!! WILL GIVE YOU BRAINLIEST 100 POINTS!!!
Answer:
yes
Explanation:
Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat is absorbed (3) reaction is exothermic (4) reaction is endothermic (5) products have higher enthalpy content than reactants (6) reactants have higher enthalpy content than products A) 1, 3, and 5 B) 1, 3, and 6 C) 2, 4, and 6 D) 2, 4, and 5
Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
Answer:
D
Explanation:
Which element will have the following property in the periodic table 1)Largest atomic size 2) Highest electron affinity 3) lowest ionisation enthalpy in group II 4) gaseous form at room temperature
In the periodic table, Francium has the largest atomic size, Chlorine has the highest electron affinity, Barium has the lowest ionization enthalpy in Group II, and gaseous elements at room temperature include noble gases and some non-metals like Fluorine and Oxygen.
The periodic table organizes elements in such a way that we can predict their properties based on their position. These properties, including atomic size, electron affinity, and ionization enthalpy, show clear patterns or trends within the table. As a tutor from the Brainly platform, let's address the specific properties asked in the question.
The element with the largest atomic size is typically found at the bottom left of the periodic table. Francium (Fr) is generally considered to have the largest atomic radius because it belongs to Group 1 and is the heaviest alkali metal. The atomic size increases down a group and decreases across a period from left to right.Highest electron affinity is generally observed in halogens. Chlorine (Cl), being very eager to gain an electron to achieve a noble gas electron configuration, has one of the highest electron affinities.The element with the lowest ionization enthalpy in Group II is expected to be at the bottom of the group. Barium (Ba), being at the lower part of Group II, has lower ionization energy compared to its counterparts up the group.Gases at room temperature from Group II are notable as they are non-existent; however, elements that are in gaseous form at room temperature from the periodic table include the noble gases such as Radon (Rn), Xenon (Xe), Krypton (Kr), Argon (Ar), Neon (Ne), Helium (He), and some non-metals like Fluorine (F), Chlorine (Cl), Oxygen (O), Nitrogen (N), and Hydrogen (H).For a reaction system at equilibrium, LeChatelier's principle can be used to predict the A) activation energy for the system B) type of bonds in the reactants C) effect of a stress on the system D) polarity of the product molecules
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the "effect of a stress on the system".
Option: C
Explanation:
Le Chatelier's theory can be implemented to forecast a system's behavior due to variations in pressure, temperature, or concentration that will lead in predictable and contested variations in the system adjustments to establish a new state of equilibrium. This means that adding heat to a process would favor the endothermic path of a reaction, because this decreases the amount of heat generated in the system.
Here shift in equilibrium take place when volume increase, the total pressure decreases, which have potential to reverse the reaction, while on increasing pressure of system, the total volume decreases of the gaseous system, which can shift an equilibrium in the direction of the fewer molecules.
For a reaction system at equilibrium, the Le principle can be used to predict the effect of a stress on the system.
The Le principle is an observation about chemical equilibria of reactions. Le principle can be used to predict the effect of a stress like changing concentration of a substance has on a reaction system at equilibrium.
If the concentration of a reaction species is increased at constant Temperature and Volume, the equilibrium system will shift in the direction that reduces the concentration of that substance so we can conclude that the Le principle can be used to predict the effect of a stress on the system.
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The diagram shows a pump. Which labels can replace
X and the Y in the diagram?
X: potassium, Y: sodium
X: sodium, Y potassium
X: sodium, Y: calcium
X: calcium, Y: potassium
Answer: The Answer is B. X: Sodium, Y: Potassium
Explanation: No Explanation I just Guessed. Hope This Help's Someone
Answer:
The answer is
X:Sodium Y:Potassium
Explanation:
I took the course and got it right
How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the molecules in dry air.) (Enter your answer using either standard or scientific notation. For scientific notation, 6.02 x 10^{23} is written as 6.02E23.)
To determine the number of moles of O2 molecules in the given sample of dry air, we need to use the ideal gas law equation PV = nRT. We are given the pressure (P), volume (V), and temperature (T) of the sample, and we can calculate the number of moles (n) of oxygen molecules.
Explanation:To determine the number of moles of O2 molecules in the given sample of dry air, we need to use the ideal gas law equation PV = nRT. We are given the pressure (P), volume (V), and temperature (T) of the sample, and we can calculate the number of moles (n) of oxygen molecules.
First, we need to calculate the partial pressure of oxygen in the air using the percent content in the mixture. Oxygen constitutes 20.94% of the molecules in dry air, so the partial pressure of oxygen (PO2) is calculated as PO2 = (Patm) X (percent content of oxygen). Given that the atmospheric pressure (Patm) is 0.0395 atm, the partial pressure of oxygen is PO2 = (0.0395 atm) X (0.2094).
Once we have the partial pressure of oxygen, we can use PV = nRT to calculate the number of moles of oxygen molecules (n). Rearranging the equation, n = PV / RT, where P is the partial pressure of oxygen, V is the volume of the sample, R is the ideal gas constant, and T is the temperature in Kelvin. Plugging in the values, we get n = (PO2)(V) / (RT).
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2. If 6.0g of carbon is heated in air, the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of air present. Show that this verifies the law of multiple proportions.
3. Alaxin, (C5H8)nO5, is a new malaria drug. Determine the molecular formula of alaxin if its relative molecular mass is 284.
(H = 1, C = 12, O = 16)
i dont seem to remeber
2 . The ratio of 1:2 in the mass of second element, oxygen in CO and CO2 verifies the law of proportion.
3. [tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the new malaria drug given.
Explanation:
Balanced chemical reaction:
C + O ⇒ C0
C + O2 ⇒ CO2
law of multiple formulation states that when two elements combine to form a compound the ratio of the mass of elements is a whole number.
Carbon reacts with oxygen to produce:
Mass of carbon mass of oxygen ratio of O in CO2 to O in CO
CO = 12 16 3:4
CO2 = 12 32 3:8
CO 6 gm 8 3:4
CO2 6 16 3:8
The ratio of the mass of the second element i.e oxygen is CO:CO2 is 1:2, hence it shows law of multiple proportions.
3. given,
(C5H8)nO5 = emperical formula
relative molecular mass = 284
molecular formula= ?
The value of n will be calculated as:
(12x5)+ (1x8)n + (16x5) = 284
(60 +8)n + 80 = 284
68n + 80 = 284
68n = 284 - 80
68n = 204
n = 3
Multiplying the emperical formula by n
(C5H8)3O5
[tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the drug.
The formation of different carbon oxide compounds with differing masses of oxygen that combine with a fixed mass of carbon demonstrates the law of multiple proportions with a small whole number ratio. To find the molecular formula of Alaxin, the relative molecular mass is divided by the mass of its empirical formula, yielding a molecular formula of C10H16O10.
Explanation:The law of multiple proportions states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in the ratio of small whole numbers. To verify this with carbon and oxygen, we consider the two cases: carbon dioxide (CO2) and carbon monoxide (CO).
When 6.0g of carbon reacts with oxygen, we can get either 22.0g of carbon dioxide or 14.0g of carbon monoxide. The mass of oxygen that combines with the 6.0g of carbon can be calculated for each compound:
For carbon dioxide: Mass of oxygen = 22.0g (total mass) - 6.0g (carbon) = 16.0gFor carbon monoxide: Mass of oxygen = 14.0g (total mass) - 6.0g (carbon) = 8.0gThe ratio of the mass of oxygen in carbon dioxide to the mass of oxygen in carbon monoxide is 16.0g : 8.0g = 2:1, which is a small whole number ratio, thus verifying the law of multiple proportions.
To determine the molecular formula of Alaxin, given its relative molecular mass is 284:
Calculate the relative molecular mass of the empirical formula (C5H8O5): (12*5) + (1*8) + (16*5) = 60 + 8 + 80 = 148 g/mol.Divide the relative molecular mass of Alaxin by the empirical formula mass to find n: 284 / 148 = 1.92, approximately 2.The molecular formula is (C5H8O5)2, or C10H16O10.
NEED HELP WITH CHEM :)
What volume of a 3.70 M NaCl solution is needed for a reaction that requires 118 g of NaCl?
Answer:
volume of solution L =0.54 L
Explanation:
Given data:
Molarity of NaCl solution = 3.70 M
Mass of NaCl = 118 g
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 118 g/ 58.5 g
Number of moles = 2 mol
Now we will calculate the volume from molarity formula:
Molarity = number of moles / volume of solution L
3.70 M = 2 mol / volume of solution L
volume of solution L = 2 mol / 3.70 M
volume of solution L =0.54 L
A neutral solution has a pH =
When a solution is basic, the pH is always greater than
When a solution is basic, the pOH is always less than
Answer:
7.
Explanation:
A neutral solution has a pH=7.
A basic solution has a pH>7.
An acidic solution has a pH<7.
Answer:
7,7,7
Explanation:
If 2.87 g of aluminum are reacted with excess copper (II) sulfate and 9.2 g of copper are produced what is the percent yield
92.8 % is the percent yield when 2.87 g of aluminum are reacted with excess copper (II) sulfate and 9.2 g of copper are produced.
Explanation:
Mass of aluminum = 2.87 grams
mass of copper produced = 9.2 grams ( actual yield)
the balanced chemical reaction is given as:
2 Al + 3 CuSO4 ⇒ ( AL2(SO4)3 +3 Cu.
from the reaction it is found that
2 moles of aluminum reacted to give 3 moles of copper
so converting them in to mass.
number of moles of copper in 2.8 grams = [tex]\frac{2.8}{63.4}[/tex]
number of moles = 0.104 moles of copper
atomic mass of aluminum = 26.98 grams/mole
atomic mass of copper = 63.54 grams/mole
From the given data
2.87 grams Al gives 9.2 grams of Cu.
2 moles of aluminum reacted to give 3 moles of copper
0.104 moles of aluminum will give
[tex]\frac{3}{2}[/tex] =[tex]\frac{x}{0.104}[/tex]
2x = 0.132
x = 0.156 moles of Cu will be formed.
Hence theoretical yield should be = 0.156 x 63.54
= 9.91 grams
Percent yield = [tex]\frac{actual yield}{theoretical yield}[/tex] x 100
= [tex]\frac{9.2}{9.91}[/tex] x 100
percent yield = 92.8 % is the yield percent.
How many moles are there in 24.00 g of NaCl
Answer:
The answer to your question is 0.41 moles
Explanation:
Data
moles of NaCl = ?
mass of NaCl = 24 g
Process
To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.
1.- Calculate the molar mass
NaCl = 23 + 35.5 = 58.5 g
2.- Use proportions and cross multiplication
58.5 g of NaCl ------------------- 1 mol
24.0 g ------------------- x
x = (24 x 1) / 58.5
x = 0.41 moles
how many moles are in 10.0 grams of sodium hydroxide?
Heat transfer focuses on transfers between the system and _____
A. accessories
B. universe
C. phases
D. surroundings
• A gas occupies what volume at a pressure of 5.4
atm, 3.5 moles of gas, at 333 K?
Answer: 17.71L
Explanation:
The volume can be calculated by using the ideal gas equation which is given as:
PV =nRT
Where P = Pressure, V= Volume, n= number of moles, R= gas constant and T = Temperature
From the above question :
P =5.4 ATM, V= ? n = 3.5 , R =0.082057 L atm /mol/K, T= 333K
PV = nRT
Make V subject of the formula we then have:
V= nRT/P
= 3.5 x 0.082507 L x 333 / 5.4
= 95.64 / 5.4 = 17.7L
Chemistry: Gas Laws Problems!
Answer : The final volume at STP is, 1000 L
Explanation :
According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 1520 mmHg = 2 atm (1 atm = 760 mmHg)
[tex]P_2[/tex] = final pressure at STP = 1 atm
[tex]V_1[/tex] = initial volume = 500.0 L
[tex]V_2[/tex] = final volume at STP = ?
Now put all the given values in the above formula, we get:
[tex]2atm\times 500.0L=1atm\times V_2[/tex]
[tex]V_2=1000L[/tex]
Therefore, the final volume at STP is, 1000 L
The volume of the gas at STP is [tex]\(1000.0 \, \text{L}\)[/tex].
1. Convert initial pressure to atm:
[tex]\[ P_1 = \frac{1520 \, \text{mm Hg}}{760 \, \text{mm Hg/atm}} = 2 \, \text{atm} \][/tex]
2. Apply the Combined Gas Law:
[tex]\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \][/tex]
Given:
[tex]\[ V_1 = 500.0 \, \text{L} \][/tex]
[tex]\[ P_1 = 2 \, \text{atm} \][/tex]
[tex]\[ P_2 = 1 \, \text{atm} \][/tex]
[tex]\[ T_1 = T_2 \][/tex] (temperature does not change)
Substituting the values, we get:
[tex]\[ \frac{(2 \, \text{atm} \cdot 500.0 \, \text{L})}{T} = \frac{(1 \, \text{atm} \cdot V_2)}{T} \][/tex]
3. Solve for [tex]\(V_2\)[/tex]:
Cross-multiply and solve for [tex]\(V_2\)[/tex]:
[tex]\[ 2 \cdot 500.0 = 1 \cdot V_2 \][/tex]
[tex]\[ V_2 = \frac{2 \cdot 500.0}{1} \][/tex]
[tex]\[ V_2 = 1000.0 \, \text{L} \][/tex]
C. Describe ONE way in which relocation diffusion resulted in the cultural landscapes shown in both photographs.
D. Explain how the cultural landscapes shown in the photographs represent more than one culture,
Answer:
Explanation:
THIS IS THE COMPLETE QUESTION
A)Identify TWO cultural traits shown in one or both of the photographs that are indicative of ethnicity.
B)Describe the process of relocation diffusion.
C)Describe ONE way in which relocation diffusion resulted in cultural landscapes shown in both photographs.
D)explain how the cultural landscapes shown in the photographs represent more than one culture.
EXPLANATION:
A)the two cultural traits shown in the photographs that are indicative of ethnicity are;
1) the torri
2)the logograms
B)The process of relocation diffusion provide an idea as a result of people moving from one place to another especially the adopters, they move from their base to new place.
C)Relocation diffusion resulted in the cultural landscapes that is shown in both photographs just gave the intance of migration process.
for instance, those that migrated to CALI and UK from china came along with their cultural trait too. As well as their custom
D)The cultural landscapes that is shown in the photographs gives the representation of multiple culture through displaying of
architectural styles from different culture.
Cultural landscapes display a linguistic features of more than one languages.
Relocation diffusion contributes to cultural landscapes by introducing new cultural elements through migration. Such landscapes often represent multiple cultures, as both local and migrated cultures can leave their imprint on the environment.
Explanation:Relocation diffusion refers to the spread of a cultural trait by individuals who migrate and carry this trait with them to new locales. For example, when individuals who practice a particular religion migrate to a new location, they might build places of worship resembling those in their homeland, thus altering the cultural landscape of their new locale.
Cultural landscapes can often represent more than one culture because both the local and migrated cultures influence the landscapes. For example, in a cultural landscape where a McDonald's (representing American fast food culture) is situated next to a Buddhist temple (representing Asian religious culture), it is evident that more than one culture is influencing the setting.
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A mixture of 8.0 mol Ne and 8.0 mol Xe are at STP in a rigid container. Which of the following statements is TRUE?
A) Both gases have the same average kinetic energy.
B) Both gases contribute equally to the density of the mixture under these conditions.
C) Both gases have the same molecular speed.
D) The mixture has a volume of 22.4 L
E) All of the above are TRUE.
OPTION A. A) Both gases have the same average kinetic energy.
In the given gas mixture of Neon (Ne) and Xenon (Xe) at Standard Temperature and Pressure (STP), both gases only share the same average kinetic energy. However, they do not contribute equally to the mixture's density, they do not share the same molecular speed, and the total volume of the mixture is not 22.4L.
Explanation:The TRUE statement among the options given is A) Both gases have the same average kinetic energy. The average kinetic energy of gas molecules is determined by temperature, not the type of gas, according to kinetic molecular theory. Therefore, since both gases are at the same temperature (Standard Temperature and Pressure, STP), they will have the same average kinetic energy.
B) is incorrect since each gas contributes to the mixture's density based on its own molar mass, and Xenon's molar mass is much greater than Neon's.
Option C is not correct because molecular speed is influenced by molar mass. Neon, having a smaller molar mass, will have a higher average speed than Xenon.
Statement D) is incorrect because according to Avogadro's law, one mole of any gas at STP occupies a volume of 22.4L, and we have a total of 16 moles of gas (8.0 mol of Ne and 8.0 mol of Xe) which will occupy a volume of 16 times 22.4L.
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Which process is used to determine the concentration of an acid?
Answer:
testing
Explanation:
some scientist somewhere made acid and probably forgot the recipe/ingredients so they kept making it and used plastic to see if it would melt it