Consider f and c below. f(x, y) = (3 + 4xy2)i + 4x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a function f such that f = ∇f. f(x, y) = (b) use part (a) to evaluate c f · dr along the given curve
c.

Answers

Answer 1
We want to find a scalar function [tex]f(x,y)[/tex] such that [tex]\nabla f(x,y)=\mathbf f(x,y)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j[/tex].
So we need to have
[tex]\dfrac{\partial f}{\partial x}=3+4xy^2[/tex]
Integrating both sides with respect to [tex]x[/tex] gives
[tex]f(x,y)=3x+2x^2y^2+g(y)[/tex]
Differentiating with respect to [tex]y[/tex] gives
[tex]\dfrac{\partial f}{\partial y}=4x^2y+\dfrac{\mathrm dg}{\mathrm dy}=4x^2y[/tex][tex]\implies\dfrac{\mathrm dg}{\mathrm dy}=0[/tex][tex]\implies g(y)=C[/tex]
So we find that
[tex]f(x,y)=3x+2x^2y^2+C[/tex]
By the fundamental theorem of calculus, we then know the line integral depends only on the values of [tex]f(x,y)[/tex] at the endpoints of the path. Therefore

[tex]\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(3,\frac13\right)-f(1,1)=11-5=6[/tex]
Answer 2
Final answer:

Find the function f whose gradient is equal to the vector function f, then evaluate the line integral of f along the given hyperbolic arc from (1,1) to (3,1/3). This involves calculus and the concept of vector fields.

Explanation:

This problem involves calculus, specifically the concept of vector fields and line integrals. First, we are asked to find a function f(x, y) such that its gradient is equal to a given vector function f(x, y). To find this scalar function, we need to perform the integral of each component of the vector function f in terms of x and y.

Then we need to evaluate the line integral of the vector function f along a curve c, which is given as an arc of the hyperbola y = 1/x. The definite integral from point (1,1) to point (3,1/3) should be calculated. This integral represents the work done by the field f along the curve c.

Keep in mind that when you perform a line integral, you are adding up the contributions of a field (in this case, the vector field f) along a path (here, the hyperbola). Therefore, the path must be parameterized, and the limits of integration should be the parameter values that correspond to the points (1, 1) and (3, 1/3).

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Related Questions

What is the explicit formula for the sequence? 6, 5, 4, 3, 2, . .

Answers

This arithmetic sequence has first term 6 and common difference -1. The general formula is
  an = a1 +(n-1)d

For your sequence, this is
  an = 6 +(n-1)*(-1)
  an = 7 - n

Answer: [tex]a_n=5+n[/tex]

Step-by-step explanation:

The explicit formula for an arithmetic sequence is given by:-

[tex]a_n=a+d(n-1)[/tex], where a is the first term , di sthe common difference and n is the number of terms.

The given sequence : 6, 5, 4, 3, 2, . .

Common difference  d = 1

First term = 1

Now, the explicit formula for given arithmetic sequence will be:

[tex]a_n=6+1(n-1)\\\\\Rightarrow\ a_n=6+n-1\\\\\Rightarrow\ a_n=5+n[/tex]

Hence, the explicit formula for given arithmetic sequence :  [tex]a_n=5+n[/tex]

How to find the of each figure #5,6,7,8

Answers

5. The base area = (1/2)(6.1 m apothem)(6*7 m perimeter) = 128.1 m^2. The height = 8 m, so the volume of a pyramid = (1/3)bh = 341.6 m^3.
6. The base area = (8 yd)(10 yd) = 80 yd^2. The height = 11 yd, so the volume = (1/3)bh = 293.3 yd^3.
7. The lateral area is (11)(10) for the slanted surface, (11)(6) for the vertical rectangular surface, and (1/2)(8)(6) for each of the triangular surfaces. This is a lateral area of 110 + 66 + 2(24) = 224 in^2.The bottom surface is (11)(8) = 88, so the total surface area is 312 in^2.
8. The lateral area is (5 triangles)(1/2)(7.3 yd height)(6 yd base) = 109.5 sq. yd.The base is (1/2)(4.1 yd apothem)(5*6 yd perimeter) = 61.5 sq. yd. This is a total surface area of 109.5+61.5 = 171 sq yd.
Hello,
Please, see the attached files.
Thanks.

Yahtzee is played with 5 dice player attempt to score point buy rolling various combinations. when all 5 dice show the same nubmer

Answers

I cant answer if I do not understand what you are asking.

25 pt question amd will mark brainliest

Answers

Hello!

The angles are supplementary meaning they add to 180°

a + 2a + 3 = 180

Combine like terms

3a + 3 =  180

Subtract 3 from both sides

3a = 177

Divide both sides by 3

a = 59

the answer is 59°

Hope this helps!
The two angles labeled are alternate corresponding.

These angle are supplementary.

use the following equation to solve for a.

2a + 3 + a = 180

Solve for a now.

3a + 3 = 180
3a = 177
a = 59

Hope this helps :)

Suppose the spread of a direct contact disease in a school is modeled by the exponential function P(t) =
2,000
1 + e3 − t
where P(t) is the total number of people infected after t hours. What does 2,000 represent in equation?
A) the rate at which the disease spreads
B) the number of the people in the school
C) the expected change in number of people infected
Eliminate
D) the total number of people infected after t hours

Answers

B. The number of people in the school, in an exponential function, the first number should always be the initial amount.

if 3 m equals 12 what is the value of 6(m-1)

Answers

find m in the first equation:
3m = 12
divide both sides by 3:
m = 12/3
m = 4

now yo know m so replace m with 4 in the second equation:

6(m-1) = 6(4-1)
do the subtraction inside the parenthesis first
6(4-1) = 6(3)

now multiply 6 and 3:  6 x 3 = 18

Cable hangs between two poles of equal height and 37 feet apart. at a point on the ground directly under the cable and x feet from the point on the ground halfway between the poles the height of the cable in feet is

Answers

Weight= (38.55 ft)(11.7 lb/ft) = 451 pounds

What is the LCD of the following rational expressions?
x/x+1 , 7x/x-1

please help I'm so confused!?

Answers

[tex] \dfrac{x}{x+1} \ , \ \dfrac{7x}{x-1}[/tex]

[tex] \dfrac{x (x -1)}{(x+1)(x -1)} \ , \ \dfrac{7x(x+1)}{(x-1)(x+ 1)} [/tex]

We know that (a + b)(a - b) = a² - b²:

[tex]\dfrac{x (x -1)}{x^2 - 1}} \ , \ \dfrac{7x(x+1)} {x^2 - 1}[/tex]

Answer: LCD = ( x + 1) (x - 1)
[tex] \frac{x}{x + 1} [/tex], [tex] \frac{7x}{x - 1} [/tex]

To find the least common denominator, multiply [tex] \frac{x}{x + 1} [/tex] by (x - 1) and multiply [tex] \frac{7x}{x - 1} [/tex] by (x + 1).

(x + 1)(x - 1) = x² - x + x - 1 ⇒ x² - 1

x² - 1 is the LCD.

the lengths of three line segments are 4 centimeters,5 centimeters,and 9 centimeters?is it 1,

Answers

9 is the base of the triangle 4 is the leg and 5 is the

No triangles can be constructed from line segments of 4 cm, 5 cm, and 9 cm in length, because the Triangle Inequality Theorem requires the sum of any two sides to be greater than the third side, which is not the case here.

The lengths of three line segments are 4 centimeters, 5 centimeters, and 9 centimeters. To determine how many triangles can be constructed with these segments as sides, we need to apply the Triangle Inequality Theorem. This theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

In this case, the sum of the two shortest sides, 4 cm and 5 cm, is 9 cm, which is equal to the length of the longest side. Because one condition for the Triangle Inequality Theorem is not strictly being met (the sum must be greater, not equal), we can conclude that no triangles can be constructed using these three segments as sides.

When constructing triangles from three measures of angles or sides, it's important to realize that these conditions determine whether you can create a unique triangle, more than one triangle, or no triangle at all.

I don't understand this problem can you help?

Answers

Comment
The question is the same as drawing a Black marble. That's one way to look at it. Another is to draw a gray and then subtract that probability of not drawing a gray. I'll do both. Choose the one that is clearest in your mind.

Method One
Total number of marbles = 21 + 11 = 32 marbles of both colors. Probability of drawing a black marble = 
P(B) = P(~gray) = 11 / 32

Method Two
A. Find the probability of drawing a gray marble.
There are 21 gray marbles and 32 total
P(G) = Number of Gray's / total
P(G) = 21 / 32
P(~G) = 1 - 21/32
P(~G) = 32/32 - 21/32
P(~G) = 11/32  <<<< Answer

what are the discontinuities of the function f(x) = x^2+5x+6/2x+16

Answers

As written (without grouping symbols), there are no discontinuities.

If you mean ...
[tex]f(x)=\dfrac{x^{2}+5x+6}{2x+16}[/tex]
it will have a discontinuity where the denominator is zero, at x=-8.

Answer:

The discontinuity of the function is at x=-8.        

Step-by-step explanation:

Given : Function [tex]f(x)=\frac{x^2+5x+6}{2x+16}[/tex]

To find : What are the discontinuities of the function?

Solution :

Discontinuity of the function is happen when denominator is zero.

First we factor the function,

[tex]f(x)=\frac{x^2+5x+6}{2x+16}[/tex]

[tex]f(x)=\frac{(x+2)(x+3)}{2(x+8)}[/tex]

Denominator = 0

[tex]2(x+8)=0[/tex]

[tex]x+8=0[/tex]

[tex]x=-8[/tex]

The discontinuity of the function is at x=-8.

To test upper h 0​: muequals50 versus upper h 1​: muless than50​, a random sample of size nequals22 is obtained from a population that is known to be normally distributed. complete parts​ (a) through​ (d) below.

Answers

Final answer:

The question relates to a statistical hypothesis test, specifically comparing a sample mean to a known population mean. This involves recognizing null and alternative hypotheses, identifying and calculating a test statistic, deciding a significance level, determining a critical value, and finally comparing the test statistic to this critical value to decide whether to reject or not reject the null hypothesis.

Explanation:

The subject matter posed in the question concerns a statistical hypothesis test.

In these cases, we have two contradictory hypotheses about a population: the null hypothesis, denoted as 'H₀', which generally represents the status quo or a statement of no effect (e.g. a population mean is equal to 50), and the alternative hypothesis, denoted 'H₁', the contrary of the null hypothesis (population mean is not equal to 50). In your specific case, the null hypothesis 'H₀' is that the mean is equal to 50 (μ = 50) and the alternative hypothesis 'H₁' is that the mean is less than 50 (μ < 50).

To test these hypotheses, you could follow these steps:

Identify a test statistic: Since we know the population is normally distributed and we are comparing the sample mean to the population mean, we can use a z-test statistic.

Compare the test statistic to the critical value to decide whether to reject or fail to reject the null hypothesis.

 

After these steps, interpret the results in terms of the problem.

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The histogram shows the number of vacation days taken by employees in the past year. Based on the histogram, which statement is true?


A.)Four employees took 20 vacation days in the past year.



B.) Four employees took 25 vacation days in the past year.



C.) Four employees took between 20 and 25 vacation days in the past year.



D.) Between 20 and 25 employees took four vacation days in the past year.

Answers

look at the chart and you would see between 20 and 25 vacations days taken last year by 4 employees 

so answer is
C.) Four employees took between 20 and 25 vacation days in the past year.

Answer:

Option(C)

Step-by-step explanation:

As per histogram, given below

3 students took holidays between 5-10 days.

5 students took holidays between 10-15 days.

5 students took holidays between 15-20 days.

4 students took holidays between 20-25 days.

3 students took holidays between 25-30 days.

therefore, option (C) is correct.

Please help me understand this.

Answers

Number of tiles in blue ring = 6
Number of tiles in yellow ring = 12
Number of tiles in blue ring = 18

Observe the terms, they are forming an Arithmetic series as each term is 6 more than the previous term. We are to find the number of tiles in 30th ring, which will be the 30th term of the A.P.

So,

30th term of AP = 1st term +(30 - 1) x Common Difference
30th term of AP = 6 + 29 x 6 = 180

Thus, there will be 180 tiles in the 30th ring of white tiles

Quadrilateral ABCD is an isosceles trapezoid. If AB || CD, AB = m + 6, CD = 3m + 2, BC = 3m, and AD = 7m - 16, solve for m.

A.) 2
B.) 3
C.) 4
D.) 5

Answers

Answer:

C.) 4

Step-by-step explanation:

we are given ABCD is an isosceles trapezoid

AB || CD

AB = m + 6

CD = 3m + 2

BC = 3m

AD = 7m - 16

Since, ABCD is an isosceles trapezoid

so, two sides must be equal

[tex]BC=AD[/tex]

now, we can plug values

[tex]3m=7m-16[/tex]

now, we can solve for m

[tex]3m-7m=7m-16-7m[/tex]

[tex]-4m=-16[/tex]

Divide both sides by -4

and we get

[tex]m=4[/tex]

Answer:

M= 4

Step-by-step explanation:

In Ms. Dole's class, students received grades of 87, 72, 99, 93, and 84 on yesterday's quiz. What was the mean of the quiz grades?

Answers

Hello!

The mean is the average of the numbers

To find the average you add them all up and divide the sum by the amount of numbers added

87 + 72 + 99 + 93 + 84 = 435

Divide the sum by the amount of numbers added

435 / 5 = 87

The answer is 87

Hope this helps!
The mean of a set of numbers is the average of all the numbers

To find the average, or the mean, the numbers must be added together and then the sum is divided by the total amount of numbers in the set.

87 + 72 + 99 + 93 + 84 = 435
435 / 5 = 87

The mean of the quiz grades is 87

A 25-foot-long footbridge has two diagonal supports that meet in the center of the bridge. Each support makes a 65∘ angle with a short vertical support.

What is the length x of a diagonal support, to the nearest tenth of a foot?

x≈_____ feet

Answers

Consider the diagram. From SOH CAH TOA, you know that
  sin(65°) = (12.5 ft)/x
  x = (12.5 ft)/sin(65°)
  x ≈ 13.8 ft

Answer:

13.

Step-by-step explanation:

Use a calculator to find the mean and standard deviation of the data. Round to the nearest tenth. 6, 7, 19, 7, 18, 7

Answers

Answer:

The mean is 10.7 and the standard deviation is 5.6.

Step-by-step explanation:

To find the mean, add together all of the data and divide by the number of data points:

(6+7+19+7+18+7)/6 = 64/6 = 10.7

To find the standard deviation, subtract each data point from the mean, square them and find the sum:

(6-10.7)²+(7-10.7)²+(19-10.7)²+(7-10.7)²+(18-10.7)²+(7-10.7)²

=(-4.7)²+(-3.7)²+(8.3)²+(-3.7)²+(7.3)²+(-3.7)²

=22.09+13.69+68.89+13.69+53.29+13.69 = 185.34

Next divide this by 6, the number of data points:

185.34/6 = 30.89

Lastly, take the square root:

√30.89 = 5.6

Which of the following points are more than 5 vertical units away from the point left-parenthesis 0 comma negative 2 right-parenthesis? Choose all that apply. (2 points) left-parenthesis 6 comma negative 2 right-parenthesis left-parenthesis negative 8 comma negative 2 right-parenthesis left-parenthesis 0 comma negative 8 right-parenthesis left-parenthesis 0 comma 4 right-parenthesis

Answers

right-parenthesis left-parenthesis 0 comma negative 8 

Given point is (0, -2).

Given options are A(6, -2); B(-8, -2); C(0, -8); D(0, 4).

It says to select the options that are more than five units vertically away from the given point.

"Vertically away" means the x-coordinate would be same and y-coordinate would be shifted up or down.

Since it says to shift more than five units vertically away, so we must have :-

y > -2 + 5 or y < -2 - 5.  

Therefore, y > 3 or y < -7.

Hence, option C and D are correct i.e. (0, -8) and (0, 4).

Estimate the probability that if the company books 225 persons. not enough seats will be available. 1-.81^225

Answers

Simply the expression.

1-.81^225 = 1

1. demand for product
2. example of fixed cost buyer's
3. sales receipts
4. credit discount
5. example of variable cost
6. moves slow-moving goods
7. business upturn
8. used for business expansion
9. depends on prime rate
10. assures profit on item sold

2/10, net 30
credit
interest rate
workers' wages
revenue
recovery
rent
markdown
markup
buyer's willingness to pay

Answers

1. demand for product       buyer's willingness to pay .   
2. example of fixed cost buyer's ----rent
3. sales receipts 
4. credit discount 
5. example of variable cost 
6. moves slow-moving goods ---markdown
7. business upturn 
8. used for business expansion 
9. depends on prime rate
10. assures profit on item sold       markup     

2/10, net 30 
credit 
interest rate
 workers' wages
revenue 
recovery


Answer:

Interest rate - 9

Revenue - 3

Recovery - 7

Markdown - 6

Buyer's willingness to pay - 1

Markup - 10

Worker's wages - 5

2/10 net 30 - 4

Credit - 8

Rent - 2

Step-by-step explanation:

Just did this on odyssey

78 million in scientific notation

Answers

[tex]=78\cdot1,000,000=78\cdot10^6=7,8\cdot10^7[/tex]

Answer:

[tex]78\ million=7.80\times 10^7[/tex]

Step-by-step explanation:

A number N can be written in scientific notation as :

[tex]N=p{\circ}0\times 10^q[/tex]

Where

p is the any real number

q is any integer

Here, the given number is 78 million. Firstly, we must know meaning of 1 million.

Since, [tex]1\ million=10^6[/tex]

[tex]78\ million=78.0\times 10^6[/tex]

To convert the above number in scientific notation, we can shift the decimal before 8 such that,

[tex]78\ million=7.80\times 10^7[/tex]

Hence, this is the required solution.

Suppose you invest $1600 at an annual interest rate of 4.6% compounded continuously. Using the formula A(t) =P*e^rt , how much will you have in the account after 4 years

Answers

Just fill in the given data and evaluate the expression:

A = $1600*e^(0.046*4) = $1923.23 (rounded up to the nearest cent)

Which equation represents a hyperbola with a center at (0,0), a vertex at (0,60), and a focus at (0,-65)

Answers

Answer:

So for everybody in the future, a clarification is d)y^2/60^2 -x^2/25^2=1

Ans: [tex]\( \frac{y^2}{60^2} - \frac{x^2}{25^2} = 1 \)[/tex]

The standard form equation of a hyperbola with the center at the origin (0,0), a vertical axis, a vertex at (0, a), and a focus at (0, c) is given by:

[tex]\[\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\][/tex]

where [tex]\(c\)[/tex] is the distance from the center to the focus, and [tex]\(b\)[/tex] is related to [tex]\(a\) and \(c\)[/tex] by the equation [tex]\(c^2 = a^2 + b^2\)[/tex].

In your case, the center is at (0,0), the vertex is at (0,60), and the focus is at (0,-65). The distance from the center to the focus is [tex]\(c = 65\)[/tex], and the distance from the center to the vertex is [tex]\(a = 60\)[/tex]. Using the relationship [tex]\(c^2 = a^2 + b^2\)[/tex], we can find b:

[tex]\[65^2 = 60^2 + b^2\][/tex]

Solving for b:

[tex]\[4225 = 3600 + b^2\][/tex]

[tex]\[b^2 = 625\][/tex]

[tex]\[b = 25\][/tex]

Now, substitute [tex]\(a\), \(b\), and \((h, k) = (0, 0)\)[/tex] into the standard form equation:

[tex]\[\frac{y^2}{60^2} - \frac{x^2}{25^2} = 1\][/tex]

So, the equation of the hyperbola is:

[tex]\[\frac{y^2}{3600} - \frac{x^2}{625} = 1\][/tex]

[tex]\( \frac{y^2}{60^2} - \frac{x^2}{25^2} = 1 \)[/tex]

43 coins, no nickels, $4.51 equal amount amount of pennies and dimes, how many of each coin

Answers

Set up
Let the dimes = d
Let the pennies = p
Let the quarters = q

Equations
You cannot mean that the pennies and dimes have equal numbers. That would mean that each had 21.5 members. Now could you mean that the dime and penny amount could be the same with 43 coins that total 4.00. Four dollars means that you need 40 dimes alone. It must mean that you are including quarters. 

p + d + p = 43          (1)
p = d                        (2)
p +10d +25q = 451  (3)

Note how this last equation = was derived. You have to multiply the dimes by 10 and he quarters by 100 and the total by 100 to get the numbers all in pennies.

Put the results of 2 into 1.
2p  + q = 43                   (4)  
You need to modify equation 3 as well.
p + 10p + 25q = 451
11p + 25q  = 451           (5)

Solve the new equations
2p +  q = 43               (4)
11p + 25q = 451        (5)

Multiply 4 by 25
25(2p- + q = 43)
50p + 25q = 1075     (6)  Subtract (5) from (6)
11p + 25q = 451
39p = 624                        Divide by 39
p = 624 / 39
p = 16

Since the pennies and dimes are equal there are 16 dimes
p + d + q = 43
16 + 16 + q = 43
32 + q = 43
q = 11

Check
16 + 10*16 + 11*25 = ?
16 + 160 + 275  = ?
451 = ?

Nice problem. Thanks for posting.

If Henry's home has a market value of $145000 and the assessment rate is 35% what is its assessed valuation

Answers

It is just a percentage problem. By finding 35% of 145000, we can solve it. [tex] \frac{145000*35}{100} = 50750[/tex]. So that, the assessed value is $50,750

Answer:

Assessment value of Henry's home is $50750

Step-by-step explanation:

Henry's home has a market value of $145000 and the assessment rate is 35%.

This means value of home is 35% of the total cost $145000

Now we will solve it by calculating percentage

Assessment = 35% of 145000 = [tex](145000)(\frac{35}{100})=(1450).(35)=50750[/tex]

So the answer is assessment of Henry's home = $50750.

The digits 1,2,3,4,5,6,7 and 8 are arranged randomly to form a three-digit number find the probability that the number is even and greater than 800

Answers

So each digits can only be selected once.

Let's start counting desired outcome.

Hundred position need to be at least 8. There is only one possible digits. So we will go with 8 and then there are 7 remaining digits.

One position can only be 2,4,6. because we need number to be even. So that's 3 possible digits. We will take one. 6 digits remaining.

Ten position can be anything so that would be 6 possible digits.

So the number of desired outcomes is 3·6 = 18.

Now count all outcomes.

Hundred, ten, and one position can get any digits

So that's 8·7·6 = 336

So the probability would be 18 / 336 = 3 / 56 ≈ 0.0536

Hope this helps.

[tex] |\Omega|=8\cdot7\cdot6=336\\
|A|=\underbrace{1\cdot6\cdot3}_{\text{8,any,even}}=18\\\\
P(A)=\dfrac{18}{336}=\dfrac{3}{56}=5\% [/tex]

Look at the table. Make a conjecture about the sum of the first 15 positive even numbers.

Answers

The conjecture about the sum of the first 15 positive even numbers is 15 * 16

Making a conjecture about the sum of the first 15 positive even numbers.

From the question, we have the following parameters that can be used in our computation:

The table of values

Where, we have

2 = 1 * 2

2 + 4 = 2 * 3

2 + 4 + 6 = 3 * 4

And so on

This means that

Sum of first n positive even numbers = n * (n + 1)

So, for the first positive even numbers, we have

n = 15

This gives

Sum of first 15 positive even numbers = 15 * (15 + 1)

Evaluate

Sum = 15 * 16

Sum = 240

Hence, the sum is 15 * 16

Write the standard form of the equation of the circle with the given center and radius.

(-3, 6); 10

Answers

The std eqn is  (x-h)^2 + (y-k)^2 = r^2.

Here we have   (x+3)^2 + (y-6)^2 = 10^2    (answer)

Answer:

A circle with center at (-3, 6) and a radius of 10 has the following standard form equation

[tex](x+3)^2+(y-6)^2=100[/tex]

Step-by-step explanation:

This is the general standard equation for the circle centered at (h, k) with radius r

[tex](x-h)^2+(y-k)^2=r^2[/tex]

It shows all the important information at a glance: the center (h, k) and the radius r.

A circle with center at (-3, 6) and a radius of 10 has the following standard form equation

Start with:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Put in (h, k) and r

[tex](x-(-3))^2+(y-6)^2=10^2\\(x+3)^2+(y-6)^2=100[/tex]

find the value of q in the following system so that the solution to the system is(4,2) 3x-2y=8
2x+3y=Q

Answers

we have that
3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2

the solution is the point (4,2)
in the equation 2 substitute the value of
x=4
y=2
so
2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14

the answer is
Q=14

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