Hey there!:
K = Ka * Kb / Kw
Ka = 1.8*10⁻⁴
Kb = 10⁻¹⁴ / 6.8*10⁻⁴
K = 1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )
K = = 1.8 / 6.8
K = 0.265
Answer A
Therefore:
K is less than on the forward reaction is not favorable .
Hope That helps!
What is the Kb of a 0.0200 M (at equilibrium) solution of methylamine, CH3NH2, that has a pH = 11.40?
A.8.61
B. 7.92 × 10−22
C. 1.26 × 10−7
D. 3.15 × 10−4
The answer is D. 3.15 × 10−4
Now the dissolution of methylamine can be represented as follows:
CH3NH2 + H2O → CH3NH3OH
The product formed dissociates and it is represented as given below
CH3NH3OH ↔ CH3CH3+ + OH-
Now pH = 11.4 ,
Then pOH = 2.6
[OH-] = 10^-2.6
[OH-] = 2.51*10^-3
Considering the below equation again
CH3NH3OH ↔ CH3CH3+ + OH-
We can calculate Kb = [CH3NH3] [ OH-] / [CH3NH3OH]
where Kb is the equilibrium constant.
Now [CH3NH3] = [OH-] = 2.51 × 10^-3
and [CH3NH3OH] = 0.020M (given)
Substituting these values we get
Kb = ( 2.51 × 10^-3)² / 0.02
Kb = 6.31 × 10^-6 / 0.02
Kb = 3.15 × 10^-4
Consider the reaction cl2(g) + i2(g) <=> 2 icl(g), which is endothermic as written. what would be the effect on the equilibrium position of removing cl2(g)? 1. reaction would go to the left, making more "reactants" 2. no change on the equilibrium position 3. reaction would go to the right, making more "reactants" 4. reaction would go to the left, making more "products" 5. reaction would go to the right, making more "products"
1. The position of equilibrium would shift to the left, making more reactants.
Cl₂(g) + I₂(g) + heat ⇌ 2ICl(g)
Le Châtelier’s Principle states that, if you add a stress to a system at equilibrium, the system will respond in a direction that will remove the stress.
Here, the stress is the removal of Cl₂. The system will respond by generating more Cl₂ to replace what was removed.
The position of equilibriumwill move to the left.
Removing Cl2(g) from the system would cause the equilibrium to shift to the left according to Le Chatelier's principle, resulting in the production of more reactants.
Removing Cl2(g) from the reaction Cl2(g) + I2(g) <=> 2 ICl(g), which is endothermic, would cause the equilibrium position to shift to the left. This is because according to Le Chatelier's principle, when a reactant is removed, the equilibrium shifts in the direction that replaces the removed substance, in this case, to the left to replenish the lost Cl2(g).
When considering the endothermic reaction Cl2(g) + I2(g) <=> 2 ICl(g), and analyzing the effect of removing Cl2(g) from the system, we apply Le Chatelier's principle. This principle states that if a change is imposed on a system at equilibrium, the system will adjust to counteract that change. In this case, removing Cl2(g) will result in the system shifting to the left to produce more reactants and re-establish equilibrium. Therefore, the correct answer is (1) the reaction would go to the left, making more "reactants".
What is the pH of 0.0050 M NH3 (Kb = 1.8 x 10-5)
11.70
2.30
3.52
10.48
At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. You may want to reference (pages 641 - 644) section 15.6 while completing this problem. Part a if the initial concentration of no is 0.175 m, what is the equilibrium concentration of no? G
The equilibrium concentration of NO is [tex]\boxed{{\text{0}}{\text{.0018 M}}}[/tex].
Further Explanation:
Chemical equilibrium is a stage where the rate at which forward reaction proceeds becomes equal to the rate at which the backward reaction occurs. At equilibrium, the formation of product from reactant gets balanced out by the formation of reactants from products so there is no change in concentrations of both reactants and products.
The expression for a general equilibrium is,
[tex]a{\text{A}} + b{\text{B}} \rightleftharpoons c{\text{C}} + d{\text{D}}[/tex]
Here,
A and B are the reactants.
C and D are the products.
a and b are the stoichiometric coefficients of reactants.
c and d are the stoichiometric coefficients of products.
The expression for the equilibrium constant for the general reaction is as follows:
[tex]{K_{\text{c}}}=\dfrac{{{{\left[ {\text{C}} \right]}^c}{{\left[ {\text{D}} \right]}^d}}}{{{{\left[ {\text{A}} \right]}^a}{{\left[ {\text{B}} \right]}^b}}}[/tex]
Here,
[tex]{K_{\text{c}}}[/tex] is the equilibrium constant.
[C] is the concentration of C.
[D] is the concentration of D.
[A] is the concentration of A.
[B] is the concentration of B.
The given reaction occurs as follows:
[tex]2{\text{NO}}\left( g \right) \rightleftharpoons {{\text{N}}_2}\left( g \right) + {{\text{O}}_{\text{2}}}\left( g \right)[/tex]
The initial concentration of NO is 0.175 M. Let x to be the change in concentration at equilibrium. Therefore, the concentration of NO becomes 0.175-2x at equilibrium. The concentration of both [tex]{{\text{N}}_{\text{2}}}[/tex] and [tex]{{\text{O}}_{\text{2}}}[/tex] become x at equilibrium.
The expression of [tex]{K_{\text{c}}}[/tex] for the above reaction is as follows:
[tex]{K_{\text{c}}}=\dfrac{{\left[ {{{\text{N}}_2}} \right]\left[{{{\text{O}}_2}} \right]}}{{{{\left[ {{\text{NO}}} \right]}^2}}}[/tex] …… (1)
Substitute x for [tex]{{\text{N}}_{\text{2}}}[/tex], x for [tex]{{\text{O}}_{\text{2}}}[/tex], 0.175-2x for [NO] and [tex]2.4 \times {10^3}[/tex] for [tex]{K_{\text{c}}}[/tex] in equation (1).
[tex]2.4 \times {10^3} = \dfrac{{\left( {\text{x}}\right)\left({\text{x}} \right)}}{{{{\left( {0.175 - 2x}\right)}^2}}}[/tex] …… (2)
Solve for x,
[tex]{\text{x}} = 0.0866[/tex]
Or,
[tex]{\text{x}} = 0.0884[/tex]
The value of [tex]{\text{x}} = 0.0884[/tex] is rejected as it makes concentration of NO negative that is not possible. So the value of x is 0.0866.
The concentration of NO at equilibrium is calculated as follows:
[tex]\begin{aligned}\left[ {{\text{NO}}} \right]&= 0.175 - 2\left( {0.0866} \right)\\&= {\text{ 0}}{\text{.0018 M}}\\\end{aligned}[/tex]
Learn more:
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Equilibrium
Keywords: chemical equilibrium, reactants, products, concentration, A, B, C, D, a, b, c, d, kc, equilibrium constant, 0.0018 M, NO, N2, O2.
The problem involves calculating equilibrium concentrations using the law of mass action and the given equilibrium constant. By setting up the equilibrium constant equation and solving the resulting quadratic equation, we can determine the required equilibrium concentration.
Explanation:This Chemistry problem involves calculating equilibrium concentration using the Law of Mass Action and the given equilibrium constant (Kc). Let's denote the change in concentration of NO as '-2x' (since two moles of NO are consumed), and the change in concentration of N2 and O2 as '+x' (since one mole of each is produced).
At equilibrium, the concentration of NO would be 0.175 - 2x, N2 would be x and O2 would be x. The equilibrium constant expression (Kc) for this reaction would be Kc = [N2][O2] / [NO]². Substituting the equilibrium constant value (Kc=2.4×10³), and the equilibrium concentrations into the Kc expression, we get 2.4 x 10³ = x² / (0.175 - 2x)².
Solving this quadratic equation, we can find the value of 'x' and thus, the equilibrium concentration of NO (which would be 0.175 - 2x). Note that if 'x' is small compared to 0.175, it can be neglected to simplify the calculation. This assumption should then be verified. Law of Mass Action, equilibrium constant, and equilibrium concentration are key concepts involved in the solution.
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a roller coaster car moving along a track is energy conserved in this system
Yes- as long as the roller coaster car is not powered once it leaves the station and energy loss due to resistance can be ignored.
Energies of a system:
Potential EnergyKinetic EnergyThe term "Mechanical Energy" refers to the sum of both types of energy.A roller coaster car moving along a level track with an initial velocity has mechanical energy in the form of kinetic energy.
The car would slow down while gaining height as its kinetic energy converts to gravitational potential energy when moving upwards along the track. It would have no kinetic energy since all its mechanical energy are now in the form of gravitational potential energy in case it comes to a stop before reaching the top of the track.
Similarly, the car gains speed while losing height as some of its gravitational energy is converted to kinetic energy when it travels downwards.
The mechanical energy of this vehicle conserves since any of the movements, moving upslope, downslope, or level, would ensure that
Loss in Potential Energy = Gain in Kinetic Energy
and vice versa.
Final answer:
Energy is conserved in a roller coaster system when ignoring friction and air resistance. The total mechanical energy remains constant as potential energy is converted to kinetic energy and vice versa throughout the ride.
Explanation:
Yes, energy is conserved in the system of a roller coaster car moving along a track, provided that we neglect any losses due to friction or air resistance. According to the law of conservation of energy, the total mechanical energy of a closed system remains constant. This is represented by the equation E = T + U, where E stands for the total mechanical energy, T is the kinetic energy, and U is the potential energy.
At the top of the first hill, the roller coaster car has its maximum potential energy, which is then converted to kinetic energy as it descends. The conversions between potential and kinetic energy continue throughout the ride, with energy transitioning as the car goes up and down the track. At the bottom of each descent, the car reaches its maximum kinetic energy, which becomes potential energy again as the car rises.
The total mechanical energy at any point in the ride should be the same as it was at the start of the coaster's trip, assuming no energy is lost. Remember that both kinetic and potential energies are forms of mechanical energy and are measured in joules, indicating the capacity for doing work.
what carboxylic acid describes this? have a long chain of carbons with hydrogen attached to each one. The end carbon has a hydroxyl group and an oxygen attached. Saturated fatty acids have 2 hydrogen atoms bound to each carbon while unsaturated fatty acids have some double bonds between carbons.
Fatty acids are carboxylic acids with a carboxylate group and a hydrocarbon chain. Saturated fatty acids have no double bonds and are fully 'saturated' with hydrogen, while unsaturated fatty acids contain one or more double bonds and have fewer hydrogen atoms.
Differences and Similarities Between Saturated and Unsaturated Fatty Acids
Fatty acids are carboxylic acids that serve as building blocks for various types of lipids. All fatty acids have a carboxylate group (-COOH) attached to a hydrocarbon chain. The primary difference between saturated and unsaturated fatty acids lies in the hydrocarbon chain's bond types. In saturated fatty acids, all the carbons are connected by single covalent bonds, and each carbon atom is 'saturated' with hydrogen atoms. This means that there are no double or triple bonds, allowing for the maximum number of hydrogen atoms to be attached to the carbon skeleton. Stearic acid is an example of a saturated fatty acid. On the other hand, unsaturated fatty acids contain one or more double bonds within the hydrocarbon chain. These double bonds reduce the number of hydrogen atoms attached to the carbon skeleton. They are called unsaturated because they do not contain the maximum amount of hydrogen possible.
In an effort to try winning World War I, many countries broke previously created treaties and pacts that banned the use of chemical-based weapons.
Based on the excerpt, how did chemical warfare advance during World War I?
a) Allied powers set bundles of wood and sulfur (S) on fire to smoke their enemies out of the trenches.
b) Production of ammonia for fertilizer was re purposed to cause enemies in the trenches to scatter because of the smell it produced.
c) Scientists were forced to stop their research on specific chemicals in order to fight in World War I.
d) Lethal gases, such as chlorine (Cl), were experimented with and used on enemy troops.
d?
D the belguim people atacked using it
What patten emerges over time as the plates spread apart forming new rock?
The earth's surface will split due to the rising currents of magma. When two oceanic plates drift apart a ridge is formed. When two continental plates drift apart a ridge push is formed.
The Magma rises, spreads outwards,cools and forms new rock and the older rocks are pushed away.
How can heat be used to determine if a mineral is metallic in nature?
Metals conduct heat from one to another end.....this property will help you
Heat is used to measure a mineral's thermal conductivity and specific heat to determine its metallic nature. By comparing these values with known metallic minerals and observing properties like color and luster, one can identify if a mineral is metallic.
Heat can be utilized to determine if a mineral has a metallic nature by examining its thermal conductivity and specific heat. Metallic minerals generally conduct heat more efficiently than non-metallic minerals due to the movement of free electrons. To quantify this, the specific heat of a mineral could be measured by transferring a known quantity of heat to the mineral and observing the change in its temperature.
For example, consider a scenario where a piece of metal at a known temperature is placed in water at a different temperature. By measuring the resulting temperature change in the water, and knowing the mass and specific heat of the water, the specific heat of the metal can be calculated. This value can then be compared against known values for metallic minerals to help identify the mineral in question.
If the measured specific heat is close to known values for metals such as gold or lead, additional observations such as color and luster can help refine the identification. For instance, a silver/gray color, when paired with an appropriate specific heat value, suggests a lead mineral over gold, which has a yellowish color.
Why are mixtures of gases, such as argon and helium, much more likely to form an ideal solution than other combinations such as solids and liquids?
A. Gases are more polar than liquid solvents.
B. When gases are mixed, the resulting solution has significantly different properties from the original components
C. The gases experience little or no interaction between molecules or atoms.
D. None of the above.
Mixtures of gases such as argon and helium are more likely to form an ideal solution because they experience insignificant intermolecular interactions, making their mixture thermally neutral with an increase in entropy. Option C is correct.
The intermolecular forces in ideal gases are considered to be nonexistent, and gases behave more ideally than solids or liquids. In an ideal solution, gases mix without any energy change due to similar intermolecular forces of attraction between the mixed gases as those present in the separated components.
This process is thermally neutral, and the formation of the gas solution results in increased disorder, or entropy, as gases like helium and argon will spread out and occupy a larger volume when mixed.
Hence, C. is the correct option.
Calculate the volume of liquid in the round flask sketched below. give your answer in liters, and round to the nearest 0.01l .
Hey There!
Assuming the part of the round flask containing liquid to be perfect sphere, we can calculate it's volume.
Given diameter of sphere = 24 cm
Therefore radius of the sphere, r= 24/2= 12 cm
Volume of the sphere of diameter 24 cm = (4/3)*pi*r³ = 7,238.23 cm3
Conversion of cm³ to L
1 L= 1 dm³
1 dm = 10 cm
Therefore 1L= 1 dm³ = 1000 cm³
So the volume of liquid in the round flask = 7.24 L( round of to nearest 0.01 L)
The volume of a round flask can be calculated using the formula: Volume = 4/3 * π * radius³. The calculated volume should then be converted from cubic meters to liters, and rounded to the nearest 0.01 liters.
The volume of a round flask or sphere can be calculated using the mathematical formula: Volume = 4/3 * π * radius³. Assuming you have the radius of the flask, you plug it into this formula, calculate the volume in cubic meters, and then convert to liters (since 1 cubic meter equals 1000 liters). If you are given the diameter, remember to divide it by 2 to find the radius. Once you have your answer, round to the nearest 0.01 liters as per the question's instructions.
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please help fast
Rock sediments are carried to other places by the wind, running water, and gravity. As these forces lose energy settling takes place. The sediments settle out of the air or water in rock particles graded by size with heavier pieces settle out first. Which term of describes this process of sedimentary rock formation. A: Deposition B:litthification. C:physical weathering. D: Chemical weathering
A) deposition is the processes where particles of rock or laid down in sections with heavier sediments building up first
Answer:
The correct answer is option A, that is, deposition.
Explanation:
The erosion, weathering, and deposition refer to the procedures, which works spontaneously on or close to the surface of the Earth. With time, these procedures lead to the generation of sedimentary rocks.
Deposition refers to the procedure where the rocks particles are laid down in segments with the heavier sediments forming up initially. It is the geological phenomenon in which the soil, sediments, and rocks are supplemented to a land mass or landform. Water, ice, wind, and gravity carry the previously weathered surface material that at the expense of adequate kinetic energy in the fluid gets deposited, forming up the sediment layers.
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How many Ni atoms are in 100 moles of nickel (II) chloride?
1 mole has 6.02*10^23 molecules in it.
1 nickel (II) chloride molecule, NiCl2, has 1 Ni atom in it.
so 1 mole of nickel (II) chloride molecule has 1 mole of Ni atom in it.
so 100 moles of nickel (II) chloride molecule has 100*6.02*10^23
= 6.02*10^25 Ni atom in it.
Nickel (II) chloride has the chemical formula of NiCl2. So 1 mole of NiCl2 contains 1 mole of Ni atoms.
1 mole contains 6.02*10^23 atoms. So 100 moles of Nickel (II) chloride contains 6.02*10^25 Ni atoms.
Which compound will precipitate when solutions of iron(II) acetate, Fe(C2H3O2)2, and potassium iodide (KI) are mixed?
A.
Fe(C2H3O2)2
B.
FeI2
C.
KCH3CO2
D.
none
Answer: Option (B) is the correct answer.
Explanation:
Reaction between the given reactants will be as follows.
[tex]Fe(C_{2}H_{3}O_{2})_{2} + KI \rightarrow K(C_{2}H_{3}O_{2})_{2} + FeI_{2}[/tex]
Therefore, we can see that the above reaction results in the formation of potassium acetate and iron(II) iodide.
Out of which iron(II) iodide [tex](FeI_{2})[/tex] is the precipitate.
When solutions of iron(II) acetate and potassium iodide are mixed, the precipitate formed is FeI2, Iron (II) Iodide(B). This happens because of a double displacement reaction, where the iodide ions from potassium iodide and iron(II) ions from iron(II) acetate combine to form a precipitate.
Explanation:When solutions of iron(II) acetate, which is Fe(C2H3O2)2, and potassium iodide (KI) are mixed, the resulting compound is FeI2 or known as Iron (II) Iodide. This is due to a chemical reaction known as a double displacement reaction where the iodide ions (I-) from the potassium iodide (KI) solution and the iron(II) ions (Fe2+) from the iron(II) acetate solution will combine and precipitate out of the solution. The resulting compound, FeI2, is insoluble in water and hence forms the precipitate. Therefore, the correct answer to the question is option B: FeI2.
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I need help with my chemistry homework. SHOW WORK
1) The density of tin (Sn) is the 5.75 g/cm^3. How many cubic decimeters (dm^3) does 17.2 kg of Sn occupy?
2) If half a liter (500 mL) of olive oil weights 425g, what is its density?
3) The density of silver is 10.5 g/cm^3. What is the mass of 0.987 dm^3 of silver ?
1) The gold will occupy a volume of 2.99 dm³.
[tex]\text{Volume = 17 200 g} \times \frac{\text{1 cm}^{3}}{\text{5.75 g}} = \text{2990 cm}^{3} = \textbf{2.99 dm}^{3}\\[/tex]
2) The density of the olive oil is 0.850 g/cm³.
[tex]\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{425 g}}{\text{500 cm}^{3}}= \textbf{0.850 g/cm}^{3}[/tex]
3) The mass of the silver is 10.4 kg.
[tex]\text{Mass} = \text{987 cm}^{3} \times \frac{\text{10.5 g} }{\text{1 cm}^{3 }} = \textbf{10 400 g = 10.4 kg}\\[/tex]
Which of the following statements is correct
A.) Blue litmus paper turns red when placed in a base
B.) Blue litmus paper stays blue when placed in a acid
C.) Red litmus paper stays red when placed in a base
D.) Red litmus paper turns blue when placed in a base
answer D)
explanation:
Bases turn the red litmus to Blue
while aciDs turn blue litmus to reD.
Answer: The correct answer is Option d.
Explanation:
Litmus paper is defined as the indicator which is used to determine the nature of the solution, whether it is acidic or basic.
There are 2 types of litmus paper:
Red litmus paper: This paper will turn blue if it is dipped in basic solution and it remains as such if it is dipped in acidic solution.Blue litmus paper: This paper will turn red if it is dipped in acidic solution and remains as such if it is dipped in basic solution.Hence, the correct answer is Option d.
what forces of molecular attraction is weakest?
A. Dipole interaction
B. Dispersion
C. Hydrogen bond
D. Single covalent bond
b. dispersion
Definition of Dispersion by Mimiwhatsup: a mixture in which fine particles of one kind of substance is scattered throughout another substance.
The weakest force of molecular attraction is dispersion.
(Option B)
What is Dispersion forces?The dispersion force is also known as London dispersion forces is a weak intermolecular force.
These dispersion forces arise due to temporary fluctuations in electron distribution within molecules, creating temporary dipoles.
These temporary dipoles induce similar dipoles in neighboring molecules, resulting in attractive forces between them.
Dispersion forces are present in all molecules, regardless of their polarity or the presence of other types of bonds or interactions.
However, they tend to be weaker compared to other intermolecular forces, such as dipole-dipole interactions and hydrogen bonds.
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A cylinder with a movable piston contains 2.00 g of helium, He, at room temperature. More helium was added to the cylinder and the volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 L to 3.70 L ? (The temperature was held constant.)
Hey There!
Ideal gas equation: PV = nRT where P is pressure, V is volume, n is moles of gas, R is molar gas constant and T is temperature.
Since P, R and T are constant, V/n = constant
V1 = 2.00 L, V2 = 3.30 L
n1 = (2.00 g)/(4.00 g/mol) = 0.5 mol, n2 = ?
V1/n1 = V2/n2
2.00/0.5 = 3.30/n2
n2 = 0.825 mol
Moles of He added = n2 - n1
= 0.825 - 0.5 = 0.325 mol
Mass of He added = moles x atomic mass
= 0.325 * 4.00 = 1.30 g of He
The amount of helium added to the cylinder, while keeping the pressure and temperature constant and increasing the volume from 2.00L to 3.70L, is approximately 1.70 grams.
Explanation:The problem you've presented involves the concept of an ideal gas law which states that the number of moles of gas is directly proportional to the volume it occupies, provided that temperature and pressure remain constant. Considering that you are keeping the pressure and temperature constant, and you have increased the volume from 2.00 L to 3.70 L, the mass of helium will also increase proportionally.
To find out how much helium was added, we first must determine the initial number of moles of helium using its given mass (2.00 g) and the molar mass of helium (around 4 g/mol). That is, initial moles of helium = 2.00 g / 4 g/mol = 0.5 mol. Since number of moles is directly proportional to volume, we can set up a proportion: initial volume/initial moles = final volume/final moles (2.00 L / 0.5 mol) = (3.70 L / x mol), which yields a solution of roughly 0.925 mol for 'x', the final number of moles.
Subtracting the initial moles (0.5 mol) from the final moles (0.925 mol), we find that around 0.425 mol of helium has been added. The mass of the added helium equals the moles of added helium multiplied by the molar mass, i.e., 0.425 mol * 4 g/mol = 1.70 g.
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Please help I don't understand this.
If the density of an object is affected by its mass, then ____________will have the highest density and
___________will have the lowest density
If the density of an object is affected by its mass, then osmium will have the highest density and hydrogen will have the lowest density
Density = mass/volume or D = m/V
If we hold V constant, we can write D = km. where k = 1/V.
Thus, D ∝ m. As the mass of a fixed volume of a substance increases, the density increases.
The mass of H₂ in 1 cm³ 0.080 g. The mass of Os in 1 cm³ is 22.6 g.
However, there are substances with even higher densities. For example, the material at the centre of a neutron star is so dense that 1 cm³ of the material has a mass of 10¹² kg!
Put the elements in order from lowest (1) to highest (6) electronegativity.
aluminum
barium
copper
fluoride
phosphorus
francium
The order of the electronegativity for the given elements is:
Fluorine > Phosphorous > Copper > Aluminium > Barium > Francium
What is electronegativity?Electronegativity measures the tendency of an element to attract electrons of bonded pairs towards itself. The value of electronegativity of an atom is with respect to another bonded atom.
When two atoms are bonded with each other through a bond and one of them is more electronegative than another bonded atom. Then the electron density of the bond will lie closer to the more electronegative atom.
Firstly, Fluorine is the most electronegative element in the modern periodic table. Aluminium and phosphorous are both present in the 2nd period. As we know, the electronegativity increases as we move from left to right in the periodic table.
Therefore phosphorous is more electronegative than aluminium. Copper is more electronegative than aluminium as the value of the electronegativity for copper is 1.92 and for aluminium is 1.6.
Barium and Francium lie at the bottom of the periodic table, Therefore they are the least electronegative. But the electronegativity of the Braium is more than that of Francium.
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(scientific investigations) help please.
I agree with what you've chosen for question two and three.
I would choose C for the fourth question and argue that you shall also go with C for question five.
One of the main ideas about repetition is to have multiple Trials- or independent experiments- for a single independent variable using identical experimental setup. The table presented in option C is the only one among the four choices that allots spaces for measurements from multiple independent experiments.
Hypotheses are predictions of the outcome of a particular experiment. A hypothesis is correct only if it accurately describes the outcome of an experiment. The hypothesis, not the data, would have to be revised if the two doesn't fit. The researcher could keep developing and testing new hypotheses until arriving at a correct one.
Additionally, I would prefer option B over option D in the first question- responses to that question can depends on what your teacher says about the validity of different sources, given that neither B nor D are reliable as sources that one would like to cite in a paper.
How many electrons are in an atom of elemental sodium?
A) equal to the number of neutrons
B) equal to the number of protons
C) equal to the number of protons and neutrons
correct answer is B) equal to the number of protons
The spectrophotometer really measures the percent of light that is transmitted through the solution. The instrument then converts %T (transmittance) into absorbance by using the equation you determined in the prelab section. If the absorbance of a sample is 0.85, what is the percent light transmitted through the colored sample at this collected wavelength?
Hey there!:
absorbance = log 100 - log Transmitance
absorbace = 0.85
log 100 = 2
- log transmitance = absorbace / log 100
0.85 / 2= 0.425
transmitance = 10 ^ ( - 0.425 )
transmitance = 0.376
Given a stock solution of 0.128 m bromide, solve for the bromide concentration obtained by diluting a 450 µl aliquot to the mark in a 25 ml volumetric flask.
Hey there!
Stock solution:
Concentracion bromide = 0.128 M
initial solution in volumetric flask = 450 µl
So , moles of bromide present:
450 µl in liters :
1 µl = = 1*10⁻⁶ liters
450 * ( 1*10⁻⁶ ) = 0.00045
0.128 * 0.00045 => 57.6 * 10⁻⁶ moles
Now volume final is 25 mL , in liters : 0.025 L ou 25*10⁻³
so new bromide concentration:
57.6*10⁻⁶ / 25*10⁻³=> 2.304*10⁻³ M
To find the bromide concentration in the diluted solution, use the formula for dilution C1V1 = C2V2. Your values are C1= 0.128 M, V1= 0.45 ml, and V2= 25 ml. Solve the equation for C2 to obtain the required bromide concentration.
Explanation:The bromide concentration in the diluted solution can be calculated using the formula for dilution: C1V1 = C2V2. Where C is concentration, V is volume, 1 refers to initial conditions, and 2 refers to conditions after dilution.
Here, C1 is 0.128 M (the initial concentration of bromide in the stock solution), V1 is 450 μl (the volume of the aliquot), V2 is 25 ml (the volume of the diluted solution in the volumetric flask). Inserting these values into the formula, we need to find C2 (unknown concentration of diluted solution).
Therefore, C2 = C1V1 / V2.
Before doing calculations, make sure that all volumes are in the same unit. In this case, convert μl to ml: 1μl = 0.001 ml, so 450 μl = 0.45 ml.
The calculation becomes: C2 = (0.128 M * 0.45 ml) / 25 ml, which, when calculated, provides the concentration of bromide in the diluted solution.
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In the following balanced reaction, what volume of a 3.0 M H2SO4 is required to completely neutralize 200.0 ml of a 2.5 M NaOH?
H2SO4 + 2NaOH → Na2SO4 + 2H2O
A. 200 ml
B. 83 ml
C. 50 ml
D. 170 ml
B) 83 mL
Find the moles of NaOH by using Molarity=moles/volume(L) so Moles = molarity x volume.
Then use the mol ratio to go from moles of NaOH to moles of H2SO4 by dividing the moles of NaOH by 2. Now you're in moles of H2SO4 so again use M = moles/Volume to find the volume. Volume = moles/M.
(The volume is in Liters in the equation but you can use the mL on this problem because your conversions cancel each other out.)
Answer:
B Plato
Explanation:
Element X has two isotopes. The table gives information about these isotopes.
X-63: Has an atomic mass of 62.9296 amu and an abundance of 69.15%
X-64: Has an atomic mass of 64.9278 amu and an abundance of 30.85%
The average atomic mass of element X is ____
amu.
[tex]A_r = 62.9296 \; \text{amu} \times 69.15 \% + 64.9278 \; \text{amu} \times 30.85 \%\\\phantom{A_r} = 63.5460 \; \text{amu}[/tex]
The idea is to sum up the product of atomic mass and abundance for each of the isotope- e.g. 62.9296 and 69.15% for X-63- to find the average of isotope atomic mass weighted regarding their abundance, which is by definition the relative atomic mass of the element.
Answer : The average atomic mass of an element X is, 63.546 amu
Solution : Given,
Mass of isotope X-63 = 62.9296 amu
% abundance of isotope X-63 = 69.15% = 0.6915
Mass of isotope X-64 = 64.9278 amu
% abundance of isotope X-64 = 30.85% = 0.3085
Formula used for average atomic mass of an element X :
[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]
[tex]\text{ Average atomic mass of an element X}=\sum[(62.9296\times0.6915)+(64.9278\times 0.3085)][/tex]
[tex]\text{ Average atomic mass of an element X}=63.546amu[/tex]
Therefore, the average atomic mass of an element X is, 63.546 amu
A certain reaction has an activation energy of 49.40 kJ/mol. At what Kelvin temperature will the reaction proceed 4.50 times faster than it did at 355 K?
[tex]390 \; \text{K}[/tex]
Explanation
The rate of a chemical reaction is directly related to its rate constant [tex]k[/tex] if the concentration of all reactants in its rate-determining step is held constant. The rate "constant" is dependent on both the temperature and the activation energy of this particular reaction, as seen in the Arrhenius equation:
[tex]k = A \cdot e^{-E_A/( R\cdot T)[/tex]
where
[tex]A[/tex] the frequency factor constant unique to this reaction[tex]e[/tex] the base of natural logarithms, and[tex]R[/tex] the ideal gas constant.Taking natural logarithms of both sides of the expression yields:
[tex]\ln k = \ln A - {E_a}/ ({R \cdot T})[/tex]
[tex]k_2 = 4.50 \; k_1[/tex], such that
[tex]\ln k_2 = \ln 4.5 + \ln k_1[/tex]
[tex]\ln A- {E_a}/ ({R \cdot T_2}) = \ln k_2 \\\phantom{\ln A-{E_a}/ ({R \cdot T_2})} = \ln 4.5 + \ln k_1\\ \phantom{\ln A- {E_a}/ ({R \cdot T_2})} = \ln 4.5 +\ln A- {E_a}/ ({R \cdot T_1})[/tex]
Rearranging gives
[tex]-{E_a}/ ({R \cdot T_2}) = \ln 4.5- {E_a}/ ({R \cdot T_1})[/tex]
Given the initial temperature [tex]T_1 = 355 \; \text{K}[/tex] and activation energy [tex]E_A = 49.40 \; \text{kJ} \cdot \text{mol}^{-1}[/tex]- assumed to be independent of temperature variations,
[tex]- {49.40 \; \text{kJ} \cdot \text{mol}^{-1}}/ ({8.314 \times 10^{-3} \; \text{kJ} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \cdot T_2}) \\= \ln 4.5- {49.40 \; \text{kJ} \cdot \text{mol}^{-1}}/ ({355 \; \text{K}\cdot 8.314 \times 10^{-3} \; \text{kJ} \cdot \text{mol}^{-1} \cdot \text{K}^{-1}})[/tex]
Solve for [tex]T_2[/tex]:
[tex]-(8.314 \times 10^{-3}/ 49.40) \; T_2 = 1/ (\ln 4.5 - 49.40 / (355 \times 8.314 \times 10^{-3})[/tex]
[tex]T_2 = 390 \; \text{K}[/tex]
Given:
Ea(Activationenergy):49.4kJ/molecule
k1: the rate constant of the first reaction
k2 : rate constant of the second reaction.
T2: Temperature of the second reaction.
T1: Temperature of the first reaction.
k2/k1=4.55
Now by Arrhenius equation we get
log(k2/k1)=[Ea/(2.303xR)] x[(1/T1)-(1/T2)]
Where k1 is the rate constant of the first reaction.
k2 is the rate constant of the second equation.
T2 is the temperature of the second reaction measured in K
T1 is the temperature of the first reaction measured in K
Ea is the activation energy kJ/mol
R is the gas constant measured in J/mol.K
Now substituting the given values in the Arrhenius equation we get:
log(k2/k1)=[Ea/(2.303xR)] x[(1/T1)-(1/T2)]
log(4.55)=[Ea/(2.303xR)] x[(1/T1)-(1/T2)]
0.66=[49.4/(2.303x8.314x10^-3)]x[(1/355)-(1/T2)]
0.66= 2579.75x [(1/355)-(1/T2)]
0.000256= (T2-355)/355T2
0.0908T2-T2= -355
0.9092T2=355
T2=390.46K
iron has a density of 7.874 g/mL. if a sample of iron has a mass of 7.75 grams, what is the volume of this sample in dL
Given:
Density of iron:7.874g/mL
Mass of iron : 7.75 gms
Now we know that
Volume = Mass/density
Substituting the given values in the above formula we get
Volume of iron= 7.874/7.75= 1.016 mL
Volume of iron = 0.01016 dL
The volume of a 7.75 gram iron sample, with a density of 7.874 g/mL, is approximately 0.9843 mL, which converts to approximately 0.009843 dL.
To calculate the volume of an iron sample with a mass of 7.75 grams, given the density of iron is 7.874 g/mL, use the density formula:
Density = Mass/Volume
By rearranging the formula to solve for volume, we get:
Volume = Mass/Density
Substitute in the known values:
Volume = 7.75 g / 7.874 g/mL
Volume ≈ 0.9843 mL
To convert milliliters to deciliters (dL), use the conversion factor that 1 dL = 100 mL:
Volume ≈ 0.9843 mL × (1 dL / 100 mL)
Volume ≈ 0.009843 dL
Therefore, the volume of the sample of iron in deciliters is approximately 0.009843 dL.
Which unit would be most appropriate for measuring the mass of a black bean? kilograms or milligrams
milligrams. kilograms are too big.
Answer:
B) Milligrams
Explanation:
just did the test on usatestprep
HELP!!!!!!!!!!! *What are some of the safety concerns for Barium sulfate & Barium Sulfide? Explain
BaSO₄ is relatively harmless, but BaS is highly toxic.
BaSO₄ is quite insoluble (240 µg/100 mL). It is a mild irritant in cases of skin contact and inhalation. However, it is safe enough that health professionals ask patients to drink a suspension of BaSO₄. The Ba is opaque to X-rays, so it makes the stomach and intestines more visible to radiographers.
BaS is soluble (7.7 g/100 mL). It reacts slowly with water and more rapidly in the acid conditions of the stomach to release H₂S.
BaS + 2HCl ⟶ BaCl₂ + H₂S
An H₂S concentration of 60 mg/100 mL can be fatal within 30 min.
Don’t eat barium sulfide!