Answer:
[tex]Keq=\frac{[O_{2}]^{3} }{[H_{2}O]^{2} }[/tex]
Explanation:
The equilibrium constant (Keq) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. In Keq we include gases and aqueous species, but not solids nor pure liquids because their concentration remains almost constant over time.
Let's consider the following reaction.
4 KO₂(s) + 2 H₂O(g) ⇄ 4 KOH(s) + 3 O₂(g)
Then, the equilibrium constant is:
[tex]Keq=\frac{[O_{2}]^{3} }{[H_{2}O]^{2} }[/tex]
_____________ means that animals within a population have a variety of strengths.
Problem page liquid hexane ch3ch24ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 1.72 g of hexane is mixed with 1.8 g of oxygen. calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. be sure your answer has the correct number of significant digits.
Answer:
[tex]m_{CO_2}=1.6gCO_2[/tex]
Explanation:
Hello,
In this case, hexane's combustion is stood for the following chemical reaction:
[tex]C_6H_{14}+\frac{19}{2} O_2-->6CO_2+7H_2O[/tex]
Now, we need to identify the limiting reactant for which we compute both hexane's and oxygen's moles as shown below:
[tex]n_{C_6H_{14}}=1.72g\frac{1molC_6H_{14}}{86gC_6H_{14}}=0.02molC_6H_{14}\\n_{O_2}=1.8g\frac{1molO_2}{32gO_2}=0.056molO_2[/tex]
Afterwards, we compute the moles of hexane that completely react with 0.056 moles of oxygen via the stoichiometry:
[tex]n_{C_6H_{14}}^{reacting}=0.056molO_2\frac{1molC_6H_{14}}{\frac{19}{2}molO_2}=0.0059molC_6H_{14}[/tex]
Now, since 0.02 moles of hexane are available but just 0.0059 moles react, the hexane is in excess and the oxygen is the limiting reactant, thus, the maximum mass of carbon dioxide is computed as shown below with two significant figures (due to the significant figures of the oxygen's initial mass) by using the moles of oxygen as the limiting reactant:
[tex]m_{CO_2}=0.056molO_2*\frac{6molCO_2}{\frac{19}{2}molO_2}*\frac{44gCO_2}{1molCO_2} \\m_{CO_2}=1.6gCO_2[/tex]
Best regards.
Draw one of the isomeric c5h12o alcohols that can be prepared by lithium aluminum hydride reduction of a ketone.
The part of the flower responsible for producing pollen (sperm) is the _______.
filament
anther
stigma
style
Which of the following is a possible application for discoveries made during ocean exploration?
Ocean exploration can lead to cultural and historical insights through the excavation of shipwrecks, aid in the discovery and mapping of natural resources like oil, and contribute to marine biology by discovering new species, ecosystems, and fossil sites.
Explanation:A possible application for discoveries made during ocean exploration includes the excavation of historical shipwrecks to shed light on cultural interactions and trade routes of the past. For instance, the excavation of the Byzantine Serçe Limanı Shipwreck provides valuable information about cross-cultural artistic exchanges during the Middle Byzantine period. Similarly, studies of the Battle of Bạch Đằng help map the cultural landscape associated with historical Vietnamese maritime events. Ocean exploration can also lead to the discovery and mapping of natural resources such as oil deposits, which is vital for their utilization, drawing a parallel to the need for exploration before the extraction of resources, much like we can't produce more oil than we discover. Additionally, marine ecologists involved in ocean exploration contribute to the study of marine life and ecosystems, which includes discovering new fossil sites, organizing and classifying organisms, and identifying new species.
Ocean exploration can lead to potential ocean floor colonization, historical insights from shipwrecks, new resource discoveries, and innovations in resource extraction methods. Marine ecologists also benefit from discoveries made, which contribute to scientific and environmental understanding.
Explanation:Discoveries made during ocean exploration have a multitude of applications, one of which is the possibility of colonizing the ocean floor. This could serve as a precursor to space colonization due to similar challenges faced in both environments, such as the development of sealed-off, self-sustaining habitats. Additionally, research on historic shipwrecks, like the Byzantine Serçe Limanı Shipwreck, provides invaluable insights into historical trade routes and cross-cultural interactions.
Further benefits of ocean exploration include advancements in navigational technology, which were historically influenced by the contributions of Muslim and Chinese inventions. These innovations enabled European explorers to sail across the Atlantic Ocean, leading to the discovery of new trade routes and the establishment of new markets. Ocean exploration also plays a critical role in uncovering new natural resources, like oil deposits, and in the development of innovative methods to extract and utilize these resources effectively.
Moreover, a marine ecologist might conduct studies to discover new fossil sites, classify organisms, or name new species, underlining the scientific and environmental significance of oceanic discoveries.
ben helps his dad make chicken soup. their recipe makes 15 cups of soup. if they each eat 2 cups and freeze the rest will the leftovers fit in a 64 ounce container? 1 cup = 8 ounces
how many moles are there in 78.3g of CO2?
Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 10.0 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3.
a lemon with mass 0.3 kg falls out of a tree from a height of 18 m. how much mechanical energy does the lemon have just before it hits the ground?
Answer
is: the objects mechanical energy is 52,92 J.
m(object) = 0,3 kg.
h(object) = 18 m.
g = 9,8 m/s².
E(object) = m·g·h.
E(object) = 0,3 kg · 9,8 m/s² · 18 m.
E(object) = 52,92 N·m = 52,92 J..
g - the acceleration of free fall.
mg - weight of the object.
How many grams of silver chloride (AgCl) can be produced if you start with 12.5 grams of barium chloride (BaCl2)?
2AgNO3 + BaCl ==> 2AgCl + Ba(No3)2
Wade thinks it would be really cool to become a radiologist. Which two skills are important for him to have in order to excel in this career?
A-leadership skills to help oversee the members of the staff within the hospital
B- physical strength to lift heavy equipment and machinery
C-interpersonal skills to talk to patients and help them feel comfortable
D-technical skills to know how to use the machinery and equipment needed for the job
E-public speaking skills to announce research findings in conferences
Final answer:
To excel in radiology, Wade needs to develop strong interpersonal skills to communicate effectively with patients and excellent technical skills for using and understanding complex radiological equipment and procedures. So the correct options are C and D.
Explanation:
For Wade to excel as a radiologist, there are two essential skills that are particularly important. One of these skills is interpersonal skills, which would allow him to communicate effectively with patients, help them to relax, and explain procedures to provide a comfortable experience. The other key skill is technical skills relating to the use of radiological machinery and equipment. These skills are necessary for accurately performing and interpreting medical imaging, such as computed tomography (CT), magnetic resonance imaging (MRI), and mammography which involves complex operation of medical devices and analysis of the resulting images for diagnostic purposes.
While leadership skills and public speaking abilities can be beneficial in any profession, they are not as central as interpersonal and technical skills for the day-to-day responsibilities of a radiologist. Physical strength is generally less critical, given that lifting heavy equipment is not a common task for radiologists.
Determine the limiting reactant. 2al(s)+3br2(g)→2albr3(s)
The limiting reactant in a chemical reaction is determined by calculating the amount of product (AlBr3 in this case) that would be produced from the complete reaction of each of the reactants separately. The reactant yielding the lesser amount of product is the limiting reactant.
Explanation:To determine the limiting reactant in a chemical reaction, you can use a method where you compare the amount of each reactant to the amount of product expected from its complete reaction. Taking the given equation, 2Al(s)+3Br2(g)→2AlBr3(s), we would calculate the amount of the product AlBr3 that would be formed from the complete reaction of each reactant, Al and Br2, separately. The reactant that yields the lesser amount of the product AlBr3 is the limiting reactant. This concept can be understood using a simple analogy. Let's think of making a sandwich: 2 slices of bread + 1 slice of cheese yields 1 sandwich. If you have an excess of bread but only one slice of cheese, you can only make one sandwich. The cheese is the limiting reactant as it limits the yield of sandwich and the amount of bread left unreacted is the excess reactant. Similarly, in the chemical reaction given above, the reactant that produces less amount of product (AlBr3) acts as the limiting reactant.
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What are the 3 parts of the modern cell theory
Using the chemical equation: 4NO2(g) + O2(g) + 2H2O(l) = 4HNO3 (aq) : Calculate the theoretical yield in grams of nitric acid when 2.0 moles nitrogen dioxide react with 2.0 moles of oxygen gas.
Final answer:
The theoretical yield of nitric acid, when 2.0 moles of nitrogen dioxide react with sufficient oxygen, is calculated using stoichiometry and comes out to be 126.02 grams.
Explanation:
The question involves using a chemical equation and stoichiometry to calculate the theoretical yield of a compound, specifically nitric acid (HNO3), from a given amount of reactants. We start by balancing the chemical equation: 4NO2(g) + O2(g) + 2H2O(l) = 4HNO3(aq). This shows that 4 moles of NO2 react with 1 mole of O2 to produce 4 moles of HNO3. With 2.0 moles of NO2 present, NO2 is the limiting reactant since it reacts in a 4:1 ratio with O2, and there is enough O2 provided (2.0 moles).
To calculate the theoretical yield of nitric acid, we use the molar ratio from the balanced equation. Since 4 moles of NO2 produce 4 moles of HNO3, 2.0 moles of NO2 will produce 2.0 moles of HNO3. Now, we need to convert moles of nitric acid to grams using its molar mass. The molar mass of HNO3 is approximately 63.01 g/mol, so:
Theoretical yield of HNO3 = moles of HNO3 × molar mass of HNO3
Theoretical yield of HNO3 = 2.0 moles × 63.01 g/mol = 126.02 grams
Thus, the theoretical yield of nitric acid when 2.0 moles of nitrogen dioxide react with enough oxygen is 126.02 grams.
What is the total number of valence electrons for cesium??
One Valence electron
A sample of gas in a sealed container (fixed volume) is heated from room temperature to 80.0°C.
A. Does the pressure inside the container increase or decrease?
B. The effect of temperature on the pressure of a gas illustrates _____'s Law.
C. Explain what happens at the molecular level to change the pressure as the temperature is raised.
Use the word part meanings to figure out which term describes a desert plant, such as a cactus.
a. mesophyte
b. hydrophyte
c. xerophyte
the career area of chemistry which is involved in the manufacturing of products is:
Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 24.3, and the temperature is 37.0 °c? δg°\' for the reaction is –16.7 kj/mol. the constant r = 8.3145 j/(mol·k)
17.g to mL
Density= 3.291g/mL
Write the atomic cores for potassium and chloride ions
The atomic core for a potassium ion (K+) is [Ar]4s¹ without the one electron it loses to become an ion. The atomic core for a chloride ion (Cl-) is [Ne]3s² 3p⁵ with an extra electron gained to fill its 3p orbital.
Explanation:The atomic cores for potassium and chloride ions are represented by their respective electron configurations and their charges after ion formation. Potassium (K) has an atomic number of 19, which means it has 19 electrons. The electron configuration is [Ar]4s¹. When potassium forms an ion, it loses one electron to achieve a noble gas configuration, making it a potassium ion with a charge of +1, represented as K⁺.
Chlorine (Cl) has an atomic number of 17, which means it has 17 electrons. The electron configuration is [Ne]3s² 3p⁵. When chlorine forms an ion, it gains one electron to fill its 3p orbital, becoming a chloride ion with a charge of -1, represented as Cl⁻.
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Label each description as ionic, covalent, or both.
Atoms share pairs of electrons:
Atoms transfer electrons:
Atoms have electrostatic attraction:
Atoms bond together:
Answer :
Atoms share pairs of electrons : Covalent
Atoms transfer electrons : Ionic
Atoms have electrostatic attraction : Ionic
Atoms bond together : Both
Explanation :
Covalent compound : The compounds where the atoms are covalently bonded.
Covalent bonds are formed by the equal sharing of electrons. These bonds are commonly formed between two non-metals.
Ionic compound : The compounds where the atoms are bonded through ionic bond and atoms are bonded by the electrotstatic attraction.
Ionic bonds are formed by the complete transfer of electrons. The atom which looses the electron is considered as an electropositive atom and the atom which gains the electron is considered as electronegative atom. These bonds are formed between one metal and one non-metal.
What is the ph of a solution whose hydroxide ion concentration, [oh−], is 4.3 × 10−4 m? mastering chemistry?
The hydroxide ion concentration = 4.3 X 10^-4 M
so we will calculate pOH first
pOH = -log[OH-] = - log (4.3 X 10^-4) = 3.37
we know that
pH +pOH = 14
so pH = 14-3.37 = 10.63
The thermodynamic law that explains the movement of heat energy during the refrigeration cycle is the first/zeroth/second.
Thorium-234 undergoes beta decay to form a daughter nuclide and a beta particle. what are the mass number and atomic number for the daughter nuclide?
what happens when you put on deodorant? does it absorb heat and give off thermal energy
Which of the following elements makes up the tissues and organs of animals? A.Carbon B.Hydrogen C. Nitrogen D.Oxygen
Answer:
A. Carbon
Explanation:
Carbon is one of the most important elements for the structure of living things. It is responsible for 19% of the body composition of animals, behind only oxygen, which contributes 61%. The head is one of the main elements that make up the tissues and organs of animals.
Carbon has a special property: it can make four different chemical bonds. This means that, in addition to being able to bond with atoms of other elements such as hydrogen, oxygen, nitrogen, sulfur and phosphorus, carbon can also bond in different ways with other carbon atoms.
The result is the formation of thousands of carbon compounds that are present in nature, rocks, minerals, products made in industries, plastics, smoke, oil, plants, animals and within our own bodies.
Consider the unbalanced equation for the combustion of hexane: αc6h14(g)+βo2(g)→γco2(g)+δh2o(g) part a balance the equation. give your answer as an ordered set of numbers α, β, γ, ... use the least possible integers for the coefficients. α, β, γ, δ = request answer part b determine how many moles of o2 are required to react completely with 6.4 moles c6h14. express your answer using two significant figures. n = mol
Answer :
Part A : The value of [tex]\alpha, \beta, \gamma \text{ and }\delta[/tex] are 2, 19, 12 and 14 respectively.
Part B : [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].
Solution :
Part A :
The given unbalanced equation is,
[tex]\alpha C_6H_{14}(g)+\beta O_2(g)\rightarrow \gamma CO_2(g)+\delta H_2O(g)[/tex]
The balanced equation is,
[tex]2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)[/tex]
Part B :
From the balanced equation, we conclude that
2 moles of [tex]C_6H_{14}[/tex] react with 19 moles of [tex]O_2[/tex]
6.4 moles of [tex]C_6H_{14}[/tex] react with [tex]\frac{19moles}{2moles}\times 6.4moles=60.8moles=6.0\times 10^1moles[/tex] of [tex]O_2[/tex]
Therefore, [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].
The balanced equation is 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g), therefore the coefficients α, β, γ, δ are 2,9,6,7, respectively. And 29 moles of O2 are required to react completely with 6.4 moles of C6H14.
Explanation:For part a, to balance the equation for the combustion of hexane, we have to adjust the coefficients in the equation C6H14(g) + αO2(g) → βCO2(g) + γH2O(g) such that the number of atoms of each element on both sides of the equation are equal. The balanced equation becomes: 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g) . It means that α, β, γ, δ = 2, 9, 6, 7 respectively.
For part b, according to the balanced equation, 9 moles of O2 are required to react completely with 2 moles of C6H14. So, if there are 6.4 moles of C6H14, you will need: (6.4 moles C6H14 * 9 moles O2) / 2 moles C6H14 = 28.8 ≈ 29 moles of O2. In this case 'n' equals 29 moles.
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A flask contains 0.230 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.
Answer:
There are [tex]1.38506\times 10^{23} [/tex] of bromine molecules present in the flask.
Explanation:
Moles of liquid bromine in the flask = 0.230 mol
As we know that 1 mole is equal to the Avogadro number.
[tex]1 mol=6.022\times 10^{23}[/tex] atoms/ molecules
So, number of bromine molecules in 0.230 moles of liquid bromine is:
[tex]=0.230\times 6.022\times 10^{23}=1.38506\times 10^{23} molecules[/tex]
There are [tex]1.38506\times 10^{23} [/tex] of bromine molecules present in the flask.
A 45-g aluminum spoon (specific heat 0.88 j/g °c) at 24 °c is placed in 180 ml (180 g) of coffee at 85 °c andthe temperature of the two become equal.(a) what is the final temperature when the two become equal? assume that coffee has the same specific heat aswater.
The final equilibrium temperature when a 45-g aluminum spoon at 24 °c is placed in 180 ml of coffee at 85 °c, can be calculated using the heat transfer formula. Equating the heat lost by the coffee to the heat gained by the spoon, and substituting the given values will help you solve for the final temperature.
Explanation:In this problem, you are being asked to solve for the final equilibrium temperature of a system that consists of a hot coffee and a cool aluminum spoon. The heat lost by the hotter object (coffee) is equal to the heat gained by the colder object (spoon), assuming no energy is lost to the surroundings. This situation is a classical problem of heat transfer which can be addressed by use of the formula Q = mcΔT, where Q is the heat transferred, m is mass, c is specific heat and ΔT is temperature change.
The equation becomes Qcoffee = Qspoon, resulting in mcoffeeccoffee (Tinitial, coffee - Tfinal) = mspooncspoon(Tfinal - Tinitial, spoon). With the given values, we can solve for Tfinal. Solving this equation will yield your desired final equilibrium temperature.
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