Consider the low-speed flight of the Space Shuttle as it is nearing a landing. If the air pressure and temperature at the nose of the shuttle are 1.2 atm and 300 K, respectively, what are the density and specific volume?

Answer:

The shortest braking distance is 35.8 m

Explanation:

To solve this problem we must use Newton's second law applied to the boxes, on the vertical axis we have the norm up and the weight vertically down

On the horizontal axis we fear the force of friction (fr) that opposes the movement and acceleration of the train, write the equation for each axis

    Y axis

     N- W = 0

     N = W = mg

  X axis

     -Fr = m a

     -μ N = m a

     -μ mg = ma

     a = μ g

     a  = - 0.32 9.8

     a =  - 3.14 m/s²

We calculate the distance using the kinematics equations

    Vf² = Vo² + 2 a x

     x = (Vf² - Vo²) / 2 a

When the train stops the speed is zero (Vf = 0)

 Vo = 54 km/h (1000m/1km) (1 h/3600s)= 15 m/s

     x = ( 0 - 15²) / 2 (-3.14)

     x=  35.8 m

The shortest braking distance is  35.8 m

Final answer:

To stop the train without crates sliding, we need to determine the stopping distance. By using the equation v^2 = u^2 + 2aS and considering the maximum static friction force, the stopping distance is found to be 225 / (0.64g) meters.

Explanation:

To determine the stopping distance of the train without causing the crates to slide over the floor, we need to find the maximum deceleration the train can have. Given that the coefficient of static friction is 0.32 and the initial speed of the train is 54 km/h, we can convert the speed to m/s by multiplying it by 5/18. Therefore, the initial speed of the train is 15 m/s. Using the equation v^2 = u^2 + 2aS, where v is the final velocity (0 m/s), u is the initial velocity (15 m/s), a is the acceleration, and S is the stopping distance, we can solve for the stopping distance.

Rearranging the equation, we have 0 = (15 m/s)^2 + 2aS. Since the train is stopping, the final velocity is 0. Plugging in the values, we get 0 = 225 + 2aS.

Now, we know that the coefficient of static friction (μ) is 0.32. The maximum static friction force (fs) can be calculated by multiplying the coefficient of static friction by the normal force (mg), where m is the mass of the crates and g is the acceleration due to gravity. However, since the crates are not sliding and the train is being stopped, the static friction force must be equal to or greater than the force required to stop the train (ma), where m is the mass of the crates and a is the deceleration. Therefore, we have fs ≥ ma.

Substituting the values, we get 0.32mg ≥ ma. Canceling out the mass, we have 0.32g ≥ a.

Now we have two equations: 0 = 225 + 2aS and 0.32g ≥ a. By substituting 0.32g for a in the first equation, we can solve for S.

Plugging in the values, we get 0 = 225 + 2(0.32g)S. Simplifying the equation, we get -225 = 0.64gS. Rearranging the equation to solve for S, we have S = -225 / (0.64g). Taking the negative sign out, as distance can't be negative, S = 225 / (0.64g). Therefore, the train can be stopped at a distance of 225 / (0.64g) meters without causing the crates to slide over the floor.

Final answer:

The volume of a python egg can be calculated using the formula V = 4/3πr³. By substituting the given values, the volume is found to be 16π cubic inches.

Explanation:

The volume V of a python egg can be calculated using the formula V = 4/3πr³. In this case, a = 2 inches, b = 2 inches, and c = 3 inches. To find the volume, substitute the given values into the formula:

V = (4/3)π(2)(2)(3) = (4/3)π(12) = 16π cubic inches.

Therefore, the volume of the python egg is 16π cubic inches.

Answer:

y = 297.34 m

Explanation:

When coin is dropped from the balloon then due to inertia the initial speed of the coin will be same as the speed of the balloon

So here we have

[tex]v_i = 12.0 m/s[/tex]

initial height of the coin is

[tex]y_i = 290 m[/tex]

now at the maximum height final speed of the coin will be zero

so we will have

[tex]v_f^2 - v_i^2 = 2 a (\Delta y)[/tex]

[tex]0 - 12^2 = 2(-9.81)(y - 290)[/tex]

[tex]7.34 + 290 = y[/tex]

[tex]y = 297.34 m[/tex]

The maximum height reached by the coin, initially rising at 12.0 m/s from 290 m, is calculated by kinematic to be 297.35 m.

Initial velocity (u) of the coin is 12.0 m/s upward.

Initial height (h) is 290 m above the ground.

Acceleration due to gravity (g) is -9.8 m/s² (negative because it acts downward).

Calculate the maximum height:

Using the kinematic equation: v² = u² + 2a(s)

Where v = final velocity (0 m/s at the maximum height), u = initial velocity (12.0 m/s), a = acceleration (-9.8 m/s²), and s = displacement.

Set v = 0 and solve for s: 0 = (12.0 m/s)² + 2(-9.8 m/s²)s

0 = 144 - 19.6s

19.6s = 144

s = 144 / 19.6

s = 7.35 m

This displacement (s) is the distance the coin moves upward from the initial point.

Therefore, the maximum height above the ground is 290 m + 7.35 m = 297.35 m

Maximum height reached by the coin is 297.35 m.

Answer:

It is the energy in/of a fluid due to applied pressure (force per area). For example, if there is a static fluid in an enclosed container, the energy of the system is only due to the pressure; if the fluid is moving along a flow, then the energy of the system is the kinetic energy as well as the pressure.

Explanation:

physics.stackexchange.com

The 'energy of pressure' in physics signifies the concept that pressure can be represented as energy per unit volume, particularly for fluids. Hydrostatic pressure reflects energy density due to a fluid's internal forces. Pressure multiplied by volume gives units of energy, aligning with the ideal gas law.

The term energy of pressure refers to a concept in physics where pressure is understood as a measure of energy per unit volume. This approach to describing pressure is particularly useful when discussing fluids, such as gases and liquids.

The traditional definition of pressure as force per unit area is related to energy by the work done (W = F.d); since work is a form of energy, we can derive an expression for pressure as an energy density (energy per unit volume).

In the context of fluids at rest, we talk about hydrostatic pressure, which is uniform in all directions within a fluid and equals the energy density due to the fluid's internal forces. The internal pressure, which is a property of the fluid, is indicative of the strength of intermolecular forces and is positive when these attractive forces dominate. This relates to the internal energy of a fluid, which is made up of potential and thermal energy.

When we consider the energy content of a gas, for example, we typically use the ideal gas law which relates pressure and volume to temperature. Through this relationship, we see that pressure multiplied by volume has units of energy (joules), and thus we view pressure as being indicative of the potential energy in a fluid per unit volume.

Answer:

Explanation:

a ) The velocity will never be zero . The velocity will be minimum at the highest point of projectile,  which will be equal to the horizontal component of the initial velocity.

b ) The velocity will be minimum when its kinetic energy will be minimum . Kinetic energy will be minimum when its potential energy will be maximum.

Its potential energy will be maximum at the highest point so velocity will be minimum at the highest point.

c ) Velocity will never be the same as initial velocity because constant force of gravitation is acting on the projectile all the time.

d ) At the moment when the projectile returns back and hits the ground, the speed becomes equal to the initial speed ( at t = 0 ) because its kinetic energy becomes the same as initial energy , the height becoming zero.  

In projectile motion on level ground, the velocity is never zero. The velocity is minimum at the apex of the trajectory and maximum at the launch and impact points. The velocity can never be the same as the initial velocity at a time other than t=0, but the speed can be the same as the initial speed at a time other than t=0 when the projectile lands.

a) In projectile motion on level ground with negligible air resistance, the velocity is never zero. The horizontal velocity remains constant throughout the motion, while the vertical velocity changes. However, the total velocity (magnitude of the velocity vector) is always non-zero.

b) The velocity is minimum when the projectile reaches its highest point, called the apex of the trajectory. The velocity is maximum at both the launch and impact points.

c) No, the velocity can never be the same as the initial velocity at a time other than t = 0. This is because the horizontal velocity remains constant during the motion, while the vertical velocity changes.

d) Yes, the speed (magnitude of the velocity vector) can be the same as the initial speed at a time other than t = 0. This occurs when the projectile lands, as the horizontal velocity is constant and the vertical velocity becomes opposite in direction but equal in magnitude to the initial vertical velocity.

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The velocity of the object at time t0 = -5 can be found by taking the derivative of the position function, which results in v(t) = -22t. Substituting t = -5 into this velocity function yields v(-5) = 110 m/s.

The student asks for the velocity of an object at time t0 = -5 given the position function f(t) = −11t2. To find the velocity, we use the limit definition of the derivative. The derivative of the position function with respect to time gives the velocity function:

v(t) = f'(t) = d/dt (-11t2)

This results in:

v(t) = -22t

Now, we can find the velocity at t0 = -5 by plugging the value into the velocity function:

v(-5) = -22(-5) = 110 m/s

Therefore, the velocity of the object at t0 = -5 is 110 m/s.

To find the velocity of the cart when it reaches its greatest y coordinate, we can combine the x and y components of the velocity. The x-component can be found using Ux = v0x + ax*t, and the y-component can be found using Uy = v0y + ay*t. The total velocity, v, can then be found using v = sqrt(Ux^2 + Uy^2).

The velocity of the cart can be found by combining its x and y components. The x-component of the velocity, Ux, can be found using the equation Ux = v0x + ax*t. The y-component of the velocity, Uy, can be found using the equation Uy = v0y + ay*t. The total velocity, v, can be found using the equation v = sqrt(Ux^2 + Uy^2).

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Answer:

33.4°C .

Explanation:

mass of bullet, m = 15 g = 0.015 kg

velocity of bullet, v = 1502 m/s

mass of wax, M = 2.5 kg

Initial temperature of wax, T1 = 31°C

Let T2 be the final temperature of wax.

Specific heat of wax, c = 0.7 cal/g°C = 0.7 x 1000 x 4 J/kg°C = 2800 J/kg°C

The kinetic energy of the bullet is converted into heat energy which is used to heat the wax.

[tex]\frac{1}{2}mv^{2}= M \times c \times \left ( T_{2}-T_{1} \right )[/tex]

[tex]0.5\times 0.015\times 1502 \times 1502 = 2.5 \times 2800 \times\left ( T_{2}-31 \right )[/tex]

[tex]2.42 =\left ( T_{2}-31 \right )[/tex]

[tex]T_{2}=33.4^{o}C[/tex]

thus, the final temperature of wax is 33.4°C .

Answer:

1600 kJ/h per K, 888.88 kJ/h per °F and 888.88kJ/h per R

Explanation:

We make use of relations between temperature scales with respect to degrees celsius:

[tex]1 K= 1^{\circ}C+273\\1^{\circ}F= (1^{\circ}C*1.8)+32\\1 R= (1^{\circ}C*1.8)+491.67[/tex]

This means that a change in one degree celsius is equivalent to a change of one kelvin, while for a degree farenheit and rankine this is equivalent to a change of 1.8 on both scales.

So:

[tex]\frac{Q}{\Delta T(K)}=\frac{Q}{\Delta T(^\circ C)}=1600 \frac{kJ}{h} per K\\\frac{Q}{\Delta T(^\circ F)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per ^\circ F\\\frac{Q}{\Delta T(R)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per R[/tex]

Answer:

b. Friction decreased when he went from pavement to ice and then increased two more times.

Explanation:

Frictional force depends on the normal force of the surface and a friction coefficient.

[tex]F_{f} = -\mu N[/tex]

Since we're talking about the same car, the value of [tex]N[/tex] will remain constant whereas μ will represent the change in the frictional coefficient of the surface. Now we consider the different surfaces, cars will slide in an icy road which means that the frictional coefficient is smaller than the pavement.

After Joshua returns to the pavement road, the resulting frictional force increases and will do so one more time when he reaches the gravel road. Gravel roads have greater frictional coefficients than pavement roads which means the frictional force will increase a second time.

Answer:

B

Explanation:

Right on edge 2021

Answer: [tex]204.8\ miles[/tex]

Explanation:

Remember that:

[tex]V=\frac{d}{t}[/tex]

Where "V" is the speed, "d" is the distance and "t" is the time.

You are are driving home from school steadily at 65 miles per hour for 130 miles, then we can find the driving time at  65 miles per hour:

[tex]V_1=\frac{d_1}{t_1}\\\\65\ \frac{mi}{h}=\frac{130\ mi}{t}\\\\t_1=\frac{130\ mi}{65\ \frac{mi}{h}}\\\\t_1=2\ h[/tex]

You slow down to 55 miles per hour and you arrive home after driving 3 hours and 22 minutes, then we need to find the driving time at  55 miles per hour. But first you need to convert 22 minutes to hours:

[tex](22\ min)(\frac{1\ h}{60\ min})=0.36\ h[/tex]

Since the total time is:

[tex]t_{total}=t_1+t_2[/tex]

We can calculate [tex]t_2[/tex]:

[tex]t_2=t_{total}-t_1\\\\t_2=(3\ h+0.36\ h)-2\ h\\\\t_2=1.36\ h[/tex]

In order to calculate the distance from that point (where you slow down to 55 iles per hour) to your home, we need to solve for [tex]d_2[/tex] from the following formula and substitute values:

[tex]V_2=\frac{d_2}{t_2}\\\\V_2*t_2=d_2\\\\d_2=(55\ \frac{mi}{h})(1.36\ h)\\\\d_2=74.8\ mi[/tex]

Therefore, the distance between your hometown and your school is:

[tex]d_{total}=d_1+d_2\\\\d_{total}=130\ mi+74.8\ mi\\\\d_{total}=204.8\ mi[/tex]

Final answer:

To find the total distance to the student's hometown from school, first calculate the distance for each portion of the trip where speed is constant and then sum these distances. Use the formula distance = speed × time.

Explanation:

To solve the problem of finding how far the student's hometown is from school, we can use the simple formula for distance: distance = speed × time. However, given that the speeds vary over the journey, we must break the journey into parts where the speed is constant, calculate the distance for each part, and then sum those distances to find the total.

Firstly, we know the student drove 130 miles at 65mph. This part is straightforward. However, the overall time of travel is given as 3 hours and 22 minutes. To work seamlessly with speeds and distances, it's easier to convert this total travel time into hours, which is 3.367 hours (22 minutes is approximately 0.367 hours).

To find the distance traveled at 55mph, we subtract the time taken to travel the first 130 miles from the total time. The time taken to travel the first 130 miles at 65mph can be calculated as: time = distance / speed, which will give us the time in hours. Subtracting this time from the total time will give us the time spent traveling at 55mph, allowing us to calculate the second part of the journey's distance using the distance = speed × time formula.

Finally, to find the total distance to the student's hometown, we simply add the 130 miles to the distance traveled at 55mph.

Answer:

1.78 m upward

Explanation:

We can find the displacement of the volleyball by using the SUVAT equation:

[tex]v^2 - u^2 = 2ad[/tex]

where, assuming upward as positive direction:

u = 6.0 m/s is the initial velocity

v = 1.1 m/s is the final velocity

a = g = -9.8 m/s^2 is the acceleration of gravity

d is the displacement

Solving the equation for d, we find:

[tex]d=\frac{v^2-u^2}{2a}=\frac{1.1^2-6.0^2}{2(-9.8)}=1.78 m[/tex]

And since it is positive, the displacement is upward.

The integral concepts applied include kinematics and gravitational acceleration. Given initial velocity, final velocity, and knowing gravitational due to acceleration, we can determine the time of flight up to its highest point and the maximal height or displacement through kinematic equations. In this particular case, displacement happens to be approximately 2.275 meters upwards.

The subject of this question is Physics, specifically, it deals with the concept of kinematics. The first step to solve the problem is to use the final velocity equation in kinematics, v = u + at, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration (which would be gravity in this case, ‐9.8 m/s² since it's acting downward or against the direction of the initial velocity), and 't' time. From the given values, we know that v = 1.1 m/s (these are vector quantities, hence the direction is important, and in this case, both v and u are in the same direction, up the way), u = 6.0 m/s and a = -9.8 m/s². You should set up the equation as follows: 1.1 = 6 + (-9.8)t. By simplifying, we get t = (1.1 - 6) / -9.8 ≈ 0.5s. Next, to get the displacement, you can use another kinematic equation s = ut + (1/2)a*t² ('s' stands for displacement). Once you plug in the known values, you'll get s = 6*0.5 + 1/2*(-9.8)*(0.5)² ≈ 2.275 m.

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Answer:

The horizontal distance travelled in that time lapse is 12.94 m

Explanation:

In order to solve this problem, we'll need:

At the lowest point of the roof, the hammer has a 9.88 m/s speed that makes an angle of 27° with the horizontal, so we can calculate the horizontal and vertical speed with trigonometry. If we take right as x positive and down as y positive we get

[tex]v_{x}=v*cos(27)=9.88 m/s *cos(27)=8.80 m/s \\v_{y}=v*sen(27)=9.88 m/s *sen(27)=4.49 m/s[/tex]

Now, we make two movement equation as we have a URM (no acceleration) in x and an ARM (gravity as acceleration) in y. We will wisely pick the lowest point of the roof as the origin of coordinates

[tex]x(t)=8.8 m/s *t[/tex]

[tex]y(t)=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}[/tex]

Now we calculate the time the hammer takes to get to the floor

[tex]17.1m=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}\\t=1.47s[/tex] or [tex]t=-2.38s[/tex]

Now, we keep the positive time result and calculate the horizontal distance travelled

[tex]x(1.47s)=8.8m/s*1.47s=12.94m[/tex]

Final answer:

Negative intrapleural pressure is caused by the natural elasticity of the lungs contracting and the thoracic wall expanding, with transpulmonary pressure determining lung size.

Explanation:

The pressure that results from the natural tendency of the lungs to decrease their size, due to elasticity, and the opposing tendency of the thoracic wall to pull outward and enlarge the lungs, is known as negative intrapleural pressure. This pressure is a result of two main forces: the inward pull due to the elastic recoil of the lung tissue and the surface tension of the alveolar fluid, and the outward pull from the pleural fluid and thoracic wall. The balance of these forces creates a negative pressure within the pleural cavity, which is crucial for the proper function of the lungs during breathing. The transpulmonary pressure, which is the difference between the intrapleural and the intra-alveolar pressures, determines the size of the lungs during the respiratory cycle.

Answer:

A) adding hydrogens, decreasing the number of double bonds in the molecules.

Explanation:

The complete Question is:

An oil may be converted into a substance that is solid at room temperature by

A) adding hydrogens, decreasing the number of double bonds in the molecules.

B) removing water, causing a dehydration synthesis reaction to occur.

C) removing hydrogens, increasing the number of double bonds.

D) cooling it, so that double bonds form and the fats solidify.

Hydrogenation is a process that is commonly used in food industry to reduce the vegetable oil to solid or semi-soild state which is suitable for preserving. Oil is an unsaturated fatty acid having Carbon - Carbon double bonds. Hydrogenation i.e. addition of hydrogen in presence of catalysts to these oils reduce these double bonds to single bonds. This reduction of double bonds also change some physical properties of the oil, the most obvious of which is the melting point. The melting point increases and the oil is converted to a substance that is sold at room temperature.

Therefore, the correct answer to this question is given by option A.

Final answer:

An oil can be converted into a solid fat by hydrogenation, which involves adding hydrogen to unsaturated fatty acids to raise the melting point and create a solid at room temperature, commonly used in making margarine or shortening.

Explanation:

An oil can be converted into a solid fat through a process known as hydrogenation. During this chemical reaction, hydrogen is added to the unsaturated fatty acids present in the oil. This transformation is achieved using a catalyst such as nickel (Ni), platinum (Pt), or palladium (Pd), which facilitates the addition of hydrogen atoms to the oil's fat molecules. The result of these additions changes the molecular structure, thus converting unsaturated fatty acids into saturated fatty acids. This increase in saturation raises the melting point of the triglycerides found in the oil, often turning a liquid oil, like vegetable oil, into a semi-solid or solid form similar to margarine or shortening.

Saturated fats tend to be solid at room temperature due to their chemical structure, which lacks double bonds, allowing them to pack tightly together. Unsaturated fats, which have one or more double bonds in their hydrocarbon chains, are typically liquid at room temperature. The hydrogenation process effectively reduces or eliminates double bonds, increasing the degree of saturation and thereby raising the melting point of the fat. This is a common practice in the food industry to alter the texture and stability of edible fats for various applications.

Answer:

Waning gibbous.

Explanation:

The same side that you see in one place of the continent at night, you will also see in other place on earth, regardless of the hemisphere. There is however a slight difference, but not ecognizable to the human eye thus Waning Gibbous will also be seen everywhere else in the night sky that night.

Final answer:

Your friend in Panama City will see the same waning gibbous moon phase as you see in New York, with only slight variances in the moon's position in the sky and visibility times due to the locations' relatively close longitude.

Explanation:

If you are in New York and you observe a waning gibbous moon, your friend in Panama City will see the same moon phase, provided the sky is clear. The moon goes through its phases at the same rate all over the world as it orbits Earth.

The difference in geographical location does not change the phase of the moon that is visible; it only changes the moon's position in the sky and the time it is visible.

Since New York and Panama City are relatively close in longitude, with Panama City being slightly to the west, the time difference for moonrise and moonset will not be significantly different. Therefore, both you and your friend should be able to witness the waning gibbous moon at approximately the same time during a clear night.

Answer:

2,829 meters

Explanation:

X= Vo t + 1/2 a t^2

Being

X=1,5 m, t=0,18 s and a=9,81 m/s2

Then

Vo=7, 45 m/s

Then we use

V=a.t

Being

V=Vo, and a=9,81 m/s2

t=0,75 seconds to my window

We use again

X= 1/2 a t^2

Being

t=0,75 s and a=9,81 m/s2

X=2,82 m

Answer:

1. Public Welfare, 2. Public Safety, 3. Public Works

Explanation:

I got them all right, if you go according to my answer, you will too

The government service to complete each sentence is

Government Services are services intended to serve all members of a community; it is usually provided by the government to people living within its jurisdiction. Examples are policing health care, and education.

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Answer:

[tex]V_B-V_A=-20736-0=-20736volt[/tex]

Explanation:

We have given charge on the particle [tex]q=-4\mu C=-4\times 10^{-6}C[/tex]

Mass of the charge particle [tex]m=3.2\times 10^{-6}kg[/tex]

From energy of conservation kinetic energy will be equal to potential energy

So at point A

[tex]\frac{1}{2}mv^2=qV[/tex]

At point a velocity is zero

So [tex]\frac{1}{2}(3.2\times10^{-6} )0^2=-4\times 10^{-6}V_a[/tex]

[tex]V_A=0volt[/tex]

At point B velocity will be 72 m/sec

So [tex]\frac{1}{2}\times 3.2\times 10^{-6}72^2=-4\times 10^{-6}V_b[/tex]

[tex]V_B=-20736volt[/tex]

So [tex]V_B-V_A=-20736-0=-20736volt[/tex]

Final answer:

The potential difference VB - VA between points A and B is -648 Volts, indicating that point A is at a higher electric potential than point B.

Explanation:

To find the potential difference VB - VA between points A and B, we use energy conservation. The work done by the electric field on the particle is equal to the change in kinetic energy of the particle. Since the particle starts from rest, its initial kinetic energy is 0, and its final kinetic energy is given by ½ mv2.

Therefore, the work done, which is equal to the potential energy change, is Work = ½ mv2 = q(VB - VA), where q is the charge of the particle. We can rearrange this to find the potential difference, VB - VA = ½ mv2/q. By plugging in m = 3.2 x 10-6 kg, v = 72 m/s, and q = -4.0 μC, we can calculate the potential difference.

First, convert the charge from microcoulombs to coulombs: -4.0 μC = -4.0 x 10-6 C. Then, plug the values into the formula: VB - VA = (0.5 * 3.2 x 10-6 kg * (72 m/s)2) / (-4.0 x 10-6 C). After calculating this expression, we get VB - VA = -648 Volts, which means VA is higher than VB by 648 Volts.

True, we see an emission spectrum from a neon sign due to the neon gas emitting light in the red-orange spectrum when electrically excited, with other gases emitting different signature colors.

The statement that one sees an emission spectrum from a neon sign is indeed true. A neon sign emits light because of the emission spectrum of neon gas inside the tube. When an electrical discharge excites neon atoms to a higher energy state, they emit light upon returning to their ground state. The characteristic red color of neon signs is due to the emission spectrum, with the most intense emission lines at 589 nm.

Signs that shine in colors other than red-orange contain different gases or mixtures of gases, which produce different emission spectra responsible for their signature colors. For instance, mercury vapor emits light with emission lines below 450 nm, resulting in a blue light, and sodium vapor emits light at 589 nm, creating an intense yellow light.

A normal distribution displays the highest data scores in the middle of the distribution.

A normal distribution curve, is used to represent symmetrical data set. A data set is a said to be symmetrical curve if the mean is equal to the median.

General properties of normal distribution curve include;

Thus, we can conclude that a normal distribution displays the highest data scores in the middle of the distribution.

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Answer:

The answer is the third option, C. A normal distribution displays the highest data scores in the middle of the distribution. Took the practice and this was correct.

Explanation:

Psychology 2022

Answer:1.2 m/s

Explanation:

mass of ball[tex]`(m_1)=2 kg[/tex]`

initial Velocity of [tex]m_1=3 m/s[/tex]`

mass of another ball [tex](m_2)=2 kg[/tex]`

initial velocity of [tex]m_2=0[/tex]`

Conserving momentum

[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]`

[tex]2\times 3+2\times 0=(2+3)v[/tex]`

[tex]v=\frac{6}{5}=1.2 m/s[/tex]`

Answer:

Duration

Explanation:

According to my research on different job requirements and terminology, I can say that based on the information provided within the question the term being defined is called Duration. When speaking in terms of Job Assignments/Projects, Duration (like described in the question) is the amount of time that you have before that assignment or project needs to be finished.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Final answer:

The term defined as the total number of work periods required to complete a schedule activity is known as 'duration' or 'work duration.' It is crucial for building an effective work schedule that considers member availability, project deadlines, and meeting times while also ensuring work-life balance.

Explanation:

The term defined as the total number of work periods required to complete a schedule activity is often referred to as duration or work duration. It is expressed in workdays or work weeks, and it does not account for holidays or other non-work periods. A clear understanding of duration is critical for constructing an effective work schedule or task schedule, and a timeline that takes into account the availability of team members, project deadlines, and meeting schedules.

Duration encompasses the work accomplished in the preceding periods, work currently being performed, and the work planned for the next periods. It also accounts for instances where workloads increase and might require adjustment to an employee's regular duty assignment. This could mean altering an employee's tour of duty to include hours when excess work needs to be completed over several days.

It is important to balance the hours worked during a workday with the need for rest, considering the average hours worked by full-time and part-time workers. Furthermore, maintaining productivity while being mindful of when meetings are scheduled and integrating work-related activities into the workday are all part of effective time management that reflects on an employee's job satisfaction and overall work-life balance.

When a car traveling in the negative x-direction (-x or westward direction) begins to slow down, it is decelerating. However, this deceleration while moving in the negative direction translates into positive acceleration. The example provided illustrates this with the change in velocity demonstrating a positive acceleration.

Considering a car traveling to the west (negative x-direction) that begins to slow down as it approaches a traffic light, the car is decelerating. However, because it is moving in the negative direction, the deceleration or slowing down translates into a positive acceleration. This epitomizes the fundamental rule that acceleration is in the same direction as the change in velocity.

To illustrate this, let's take the initial velocity of the car to be -25 m/s (moving to the west). As the car slows down, it ends at a speed less than that, say -5 m/s. The change in velocity is now given by final velocity - initial velocity, which equals -5 m/s - (-25 m/s) = 20 m/s.

This demonstrates a positive change in velocity. Hence, the slowing down of the car in a negative direction results in a positive acceleration.

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Answer:

distance of 2nd team from 1st team will be:  58.2

Direction of 2nd team from 1st team will be:  14.90 deg North of east

Explanation:

ASSUME Vector is R and  makes angle A with +x-axis,

therefore component of vector R is

[tex]R_x = Rcos A[/tex]

[tex]R_y = Rsin A[/tex]

From above relation

Assuming base camp as the origin, location of 1st team is

[tex]R_1 = 37 km[/tex] away at 21 deg North of west (North of west is in 2nd quadrant, So x is -ve and y is positive)

[tex]R_{1x} = -R_1*cos A_1 = -37*cos 21 deg = -34.54 km[/tex]

[tex]R_{1y} = R_1*sin A_1 = 37*sin 21 deg = 13.25 km[/tex]

location of 2nd team is at

[tex]R_2 = 32 km[/tex], at 38 deg East of North = 32 km, at 58 deg North of east (North of east is in 1st quadrant, So x and y both are +ve)

[tex]R_{2x} = R_2*cos A_2 = 32*cos 58 deg = 16.95 km[/tex]

[tex]R_{2y} = R_2*sin A_2 = 32*sin 58 deg = 27.13 km[/tex]

Now position of 2nd team with respect to 1st team will be given by:

[tex]R_3 = R_2 - R_1[/tex]

[tex]R_3 = (R_{2x} - R_{1x}) i + (R_{2y} - R_{1y}) j[/tex]

Using above values:

[tex]R_3 = (16.95 - (-34.54)) i + (27.13 - 13.42) j[/tex]

[tex]R_3 = 51.49 i + 13.71 j[/tex]

distance of 2nd team from 1st team will be:

[tex]\left | R_3 \right | = \sqrt (51.49^2 +13.71^2)[/tex]

[tex]\left | R_3 \right | = 53.28 km = 58.2 km[/tex]

Direction of 2nd team from 1st team will be:

[tex]Direction = tan^{-1} \frac{R_{3y}}{R_{3x}} = tan^{-1}[ \frac{13.71}{51.49}][/tex]

Direction = 14.90 deg North of east

Answer:

Option c that it means cm/year.

Explanation:

Nm means nanometer, 1x10^9m

Km/s^2 is acceleration

h.. it may be height

Answer:

D, km/s^2

Explanation:

This is a unit of speed because it is saying kilometers over seconds squared, and that is a unit of speed similar to miles per hour or mph or m/h.

Answer:

The material stretched across the drum vibrates to produce the sound waves.

Explanation:

A drum is one of the oldest musical instrument made by man. It is made of a hollow body over which a material such as skin is stretched. When a drum is struck with a stick, the material vibrates up and down. This makes the air above the drum to contract and relax rhythmically resulting in soundwaves. The soundwaves travel through air to reach our ears where they are heard.

The quality of sound produced by  a drum is affected by its shape. A larger drum produces a lower pitched sound.

Answer:

Displacement: 2.230 km    Average velocity: 1.274[tex]\frac{km}{h}[/tex]

Explanation:

Let's represent displacement by the letter S and the displacement in direction 49.7° as A. Displaement is a vector, so we need to decompose all the bird's displacement into their X-Y compoments. Let's go one by one:

First of all. We need to sum all the X components and all the Y componets.

∑[tex]Sx = Ax -0.916[/tex] ⇒  ∑[tex]Sx = [tex]3.52cos(49.7) - 0.916[/tex]

∑[tex]Sx = 1.361 km[/tex]

∑[tex]Sy = Ay - 0.918[/tex] ⇒ ∑[tex]Sy = 3.52sin(49.7) - 0.918[/tex]

∑[tex]Sy = 1.767[/tex]

The total displacement is calculated using Pythagoeran therorem:

[tex]S_{total} =\sqrt{Sx^{2}+ Sy^{2} }[/tex] ⇒

[tex]S_{total} = 2.230 km[/tex]

With displacement calculated, we can find the average speed as follows:

[tex]V = S/t[/tex]  ⇒  [tex]V = \frac{2.230}{1.750}[/tex]

[tex]V = 1.274\frac{km}{h}[/tex]

Answer:

neutrons, more, physical, biological

Explanation:

Radioisotopes are those isotopes of an atom which due to excessive energies are unstable, this unstability results from combination of protons and neutrons which are unstable.

Thus to achieve stability, these isotopes loses their energy when they decay or disintegrate.

The time taken by the radioisotope to achieve about 50% stability after disintegration is known as Physical half-life.

The biological half-life refer to the time taken by the radioisotope for the elimination of about 50% of the radioactive substance.

Radioisotopes are unstable due to an excess number of neutrons, and as they decay, they become more stable. The physical half-life is the time for 50% to decay, while the biological half-life refers to the time till 50% leaves the body.

Radioisotopes are unstable forms of isotopes because they contain an excess number of neutrons. Radioisotopes lose nuclear energy as they decay or break down, thus becoming more stable. Radioisotopes are unstable forms of isotopes because they contain an excess number of neutrons. Radioisotopes lose nuclear energy as they decay or break down, thus becoming more stable. The physical half-life is the amount of time it takes for 50% of the radioisotope to become stable. The amount of time it takes for 50% of radioactive material to leave the body is referred to as the biological half-life.The physical half-life is the amount of time it takes for 50% of the radioisotope to become stable. The amount of time it takes for 50% of radioactive material to leave the body is referred to as the biological half-li.

Answer:

110 N

Explanation:

When a force is applied on a body and body does not move, it means the body remains at rest.

In this condition, there is a contact force between the body and the floor which is called static friction.

Th static friction force is a self adjusting force and comes into play when the body is at rest.

Here, the applied force is 110 N and the chest is not moving, that means a static friction force is acting between the chest and the floor. This static friction force is the force of contact between the chest and the floor. The static friction force is equal to the applied force when the body does not move.

So, the contact force between the chest and the floor is 100 N.