Consider the reaction below.
HI + H20 → H30* +1
Which is an acid-conjugate base pair?
HI and H20
H2O and H307
H30+ and I
CHI and I

Answer:

False

Explanation:

The slope of a velocity-time graph gives acceleration. Acceleration can be defined as the change in velocity with time.

A slope denotes the gradient of line. It takes into consideration the changes on both y and x axis. The ratio of the changes gives the slope.

On a velocity-time graph, the y-axis is the velocity and the x-axis is time. The change in velocity with time gives acceleration.

The slope of an acceleration

-time graph is not velocity.

Answer:

Erosion involves movement to a new location, Weathering occurs in place, although they can occur together and  both are caused by similar factors of wind, water, ice, temperature, and even biological action.

Answer:

O3

Explanation:

The answer to the question is O3 .

Hope this helped! Have an amazing day :)

The gas substance at 20˚C and one atmosphere of pressure is carbon dioxide.

Out of the options given, the substance that is a gas at 20˚C and one atmosphere of pressure is A. C. C stands for carbon, which exists in its gaseous form as carbon dioxide (CO2) at this temperature and pressure. Carbon dioxide is a compound composed of one carbon atom bonded to two oxygen atoms.

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Answer:

They did not have accurate data and information.

Answer:

Explanation:

Supposing that both scientific had objectivity and no bias in their research, the results most likely provide new testable ideas. This type of situation occurs when new theories are being proved for first time. Most of people thing that scientific laws were proved in one experiment, but the reality is that experiments need plenty reproductions, even after hundreds of years of research.

Answer:

The correct answer is option D.

Explanation:

5 g/gal to [tex]oz/m^3[/tex]

[tex]1 gal = 0.00378541 m^3[/tex]

[tex]1 oz = 28.3495 g[/tex]

[tex]\frac{5g}{1 gal}\times \frac{1 gal}{0.00378541 m^3}\times \frac{1 m^3}{28.3495 g}=45.59 [/tex] unitless (not possible)

Common unit present in denominator and numerator will get cancelled.

[tex]\frac{5g}{1 gal}\times \frac{1 gal}{0.00378541 m^3}\times \frac{1 oz}{28.3495 g}=46.59 oz/m^3[/tex]

The error in the conversion was instead of [tex]1 m^3[/tex] 1 oz should be written.

The correct answer is  D.

The conversion of 5 g/gal to oz/m^3 is as follows:-

Given:-1 gal = 0.00378541 m^3

           1 oz = 28.3495 g

Accoring to sue:-

[tex]\frac{5\ g}{1\ gal} \times\frac{1\ gal}{0.00378541\ m^{3} }\times\frac{1\ m^{3}}{28.3495\ g} \\=45.59[/tex]

Common units present in numerator and denominator will get canceled.  

The correct conversion is as follows:-

[tex]\frac{5\ g}{1\ gal} \times\frac{1\ gal}{0.00378541\ m^{3} }\times\frac{1\ oz}{28.3495\ g} \\=45.59\ oz/m^{3}[/tex]

The error in the conversion was instead of [tex]1\ m^{3}[/tex], 1 oz should be written.

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Answer:

a.) It is a chemical reaction because a new substance was formed and a colour change occurred in the reaction.

b.) Iron- Metallic element

sulpher- Non-Metalic element

Iron Sulphide- Compound

HOPE IT HELPS....

Answer:

Felsic, intermediate, mafic, ultramafic

Explanation:

Ferromagnesian igneous rocks are those that contains ferromagnesian silicate minerals with magnesium and iron in their structure. Some of these minerals are olivine, pyroxene, amphibole, calcic palgioclase e.tc. Ultramafic rocks have these silicate minerals in them. They impart a dark coloration on their outlook.

Felsic minerals on the other extreme are rich in non-ferromagesian minerals such as quartz, feldspars which lacks magnesium and iron in their structures. The intermediate and the mafic igneous rocks are a mix between the two extremes. So in terms of ferromagnesian silicates component:

    felsic < intermediate < mafic < ultramafic

The correct order of igneous rocks from least to most ferromagnesian silicates is: Felsic, Intermediate, Mafic, Ultramafic. The sequence represents a gradation from rocks with the lowest content of ferromagnesian minerals to the ones with the highest content.

The correct order of igneous rocks from least to most ferromagnesian silicates is: Felsic, Intermediate, Mafic, Ultramafic. This order represents a sequence from rocks with the lowest amount of ferromagnesian silicates to the highest amount. Felsic rocks are typically light in color and contain less than 20% ferromagnesian minerals, which are rich in iron and magnesium. Intermediate rocks contain 20-45% ferromagnesian minerals. Mafic rocks are darker and contain 45-85% of these minerals. Lastly, ultramafic rocks have more than 85% ferromagnesian minerals, being the rock type with the highest content.

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Answer:

This reaction is A. Spontaneous at high temperatures, and non-spontaneous at low temperatures.

Explanation:

Both the enthalpy change [tex]\Delta H[/tex] and the entropy change [tex]\Delta S[/tex] due to this reaction are positive. A chemical reaction will be spontaneous only if the change in its Gibbs Free Energy [tex]\Delta G = \Delta H - T \cdot \Delta S[/tex] is negative. [tex]T[/tex] is the absolute temperature in degrees Kelvins.

Assume that both [tex]\Delta H[/tex] and [tex]\Delta S[/tex] doesn't change much as [tex]T[/tex] increases. The value of [tex]\Delta G[/tex] will initially be close to [tex]\Delta H[/tex] when [tex]T[/tex] is small. The sign of [tex]\Delta G[/tex] will depends on that of [tex]\Delta H[/tex]. However, [tex]\Delta H[/tex] is positive, so at low temperatures [tex]\Delta G[/tex] will be positive and the reaction will be non-spontaneous.

However, as [tex]T[/tex] increases, the role of entropy change becomes more significant. The sign of [tex]\Delta G[/tex] will eventually be the opposite of [tex]\Delta S[/tex]. The value of [tex]\Delta G[/tex] will eventually drop below zero after the value of [tex]T[/tex] rises above [tex]\Delta H / \Delta S[/tex]. The reaction will eventually become spontaneous.

Answer:

A.) spontaneous at high temperatures, non-spontaneous at low temperatures

Explanation:

Edge2021

Answer:

C. CH₄+2O₂ →2H₂O+CO₂

Explanation:

This is a popular combustion reaction.

            C. CH₄+2O₂ →2H₂O+CO₂

In combustion, hydrocarbons burn in the presence of oxygen gas and they produce water and carbon dioxide only. The process is accompanied with the release of energy.

We simply say for the above reaction that:

           One molecule of methane(CH₄) reacts with two molecules of oxygen gas(O₂) to produce two molecules of water(H₂O) and one molecule of carbon dioxide only

Answer:

the answer is C

Explanation:

because I just took the a quiz with this same question and it was right.

HF     hydrofluoric acid

HBr   hydrobromic acid

HI      hydroiodic acid

H₂S   hydrogen sulfide

Answer:

Fe(iii)2O3 + 3CO ===> 2Fe + 3CO2

Explanation:

Fe(iii)2O3 + CO ===> Fe + CO2    

The best thing to do is start with the Oxygens. They are the most complicated.

 Fe(iii)2O3 +    3 CO ===> Fe +  3 CO2

Unfortunately this equation is a bit of by guess and by gosh. You need to balance the oxygens so that the total is an even number. That's because the right hand side is always going to be even. [The 2 on CO2 will make anything in front of it even).

So there are 6 oxygens on the left and 6 on the right. The carbons by accident are balanced with this maneuver. So all that is left is the irons.

Fe(iii)2O3 + 3CO ===> 2Fe + 3CO2

This equation is a bit nasty, but in higher chemistry courses, you will learn how to make it a whole lot simpler. For now you are just going to have to put up with the nastiness of the question and guess.

Answer:

                Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

Percent Composition is defined as the %age by mass of each element present in a compound. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

              a) Na  =  22.99 g/mol

             b) H  =  1.01 g/mol

              c) C  =  12.01 g/mol

              d) O₃  =  16.0 × 3 =  48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

              Na  =  22.99 g/mol

             H    =  1.01 g/mol

              C    =  12.01 g/mol

              O₃  =  48 g/mol

                       ----------------------------------  

Total                  84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

                 =  22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  27.36 %

For H:

                 =  1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  1.20 %

For C:

                 =  12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  14.29 % ≈ 14.30 %

For O:

                 =  48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  57.13 % ≈ 57.14 %

Answer:

Great Explanation and Answer Above, Just confirming its the correct answer.

Hope This Helps!

C: 27.36% Na, 1.20% H, 14.30% C, and 57.14% O

Explanation:

Answer:

Does the article contain facts or only opinions? - B)

Answer:

The correct answer will be option-B.

Explanation:

Global warming is a hot topic of debate in the science world on how to resolve the environmental issues created by global warming. The scientific journals usually contain the articles related to the new research and scientific discoveries reviewed by the peer-review fellow scientists.

The journals ensure that the research articles to be published containing the experimental data which supports the hypothesis which should not be plagiarized. The article should be based on the reviewed facts and not personal small opinions. So to evaluate articles on global warming, one must ensure that the data should not be plagiarized.

Thus, Option-B is the correct answer.

The net ionic equation for this reaction is [tex]Fe(s) \ + \ Cu^{2+}(aq) \ \rightarrow \ Fe^{2+}(aq) \ + \ Cu(s)[/tex]. In ionic equations the soluble compounds are written in their dissociated ion forms. The ionic equation can be determined by knowing the general solubility rules.  In this problem there are sulfate compounds involved. It is important to know that sulfates are generally soluble except for sulfates of Ba, Pb, Ag, and Sr. Therefore, the ones dealt with in this problem, CuSO4 and FeSO4, are both soluble in water.

Further Explanation:

The complete equation for this reaction is:

[tex]Fe(s) \ + \ CuSO_{4}(aq) \rightarrow \ FeSO_{4}(aq) \ + \ Cu(s)[/tex]

CuSO4 and FeSO4 are soluble in water which will lead to the ionic equation:

[tex]Fe(s) \ + \ Cu^{2+}(aq) \ + \ SO_{4}^ {2-}(aq) \ \rightarrow \ Fe^{2+}(aq) \ + \ SO_{4}^{2-}(aq) \ + \ Cu(s)[/tex]

Since the sulfate ion appears on both sides, it is a spectator ion. Spectator ions are unchanged in the chemical reaction and are removed from the net ionic equation:

[tex]\boxed {Fe(s) \ + \ Cu^{2+}(aq) \ \rightarrow \ Fe^{2+}(aq) \ + \ Cu(s)}[/tex]

Based on the net ionic equation it can be seen that this is a reduction-oxidation reaction. Iron was oxidized and copper was reduced.

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Keywords: ionic equation, solubility

Electrons affect the structure of a molecule by playing a role in chemical bonding. They are involved in the formation of chemical bonds between atoms, which determines the shape and stability of the molecule.

The structure of a molecule is affected by electrons because electrons play a significant role in chemical bonding. Electrons are negatively charged particles that orbit the nucleus of an atom. When atoms come together to form a molecule, the electrons are involved in the formation of chemical bonds between the atoms.

For example, in covalent bonding, atoms share electrons, which can result in the formation of single, double, or triple bonds. The arrangement and distribution of electrons determine the shape and stability of the molecule.

Answer:

Boiling.

Explanation:

So, the right choice is: Boiling.

Answer:

A. Boiling

Explanation:

Just tested

Option A. Nitrogen is not in a carbohydrate

carbo-(carbon)

Hydrate-water

Nitrogen is not contained carbohydrate, Nitrogen is in the soil under our feet, in the water we drink, and in the air we breathe. In fact, nitrogen is the most abundant element in Earth's atmosphere: approximately 78% of the atmosphere is nitrogen! Nitrogen is important to all living things, including us.

In addition to what we might think of as the classical elements: earth, water, fire, air, and gas (space), in many ancient eastern concepts of self there are an additional two: consciousness (or thought itself) and the element of spirit. Each of us is comprised of all seven elements

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Answer:

[tex]\boxed{5.6 \times 10^{5}\text{ nm}}[/tex]

Explanation:

1 nm = 10⁻⁹ m

[tex]5.6 \times 10^{-4}\text{ m} \times \dfrac{\text{1 nm}}{10^{-9}\text{ m}} = \mathbf{5.6 \times 10^{5}}\textbf{ nm}\\\\\text{There are } \boxed{\mathbf{5.6 \times 10^{5}}\textbf{ nm}} \text{ in 5.6 $\times 10^{-4}$ m}[/tex]

5.4 × [tex]10^{5}[/tex] nanometers are in 5.6 x [tex]10^{-4}[/tex] meters

Calculation,

Since, 1 nanometer = [tex]10^{-9}[/tex] meter.

1 meter = [tex]10^{9}[/tex] nanometer

5.6 x [tex]10^{-4}[/tex] meters = 5.6 x [tex]10^{-4}[/tex] ×  [tex]10^{9}[/tex] nanometer = 5.4 × [tex]10^{5}[/tex] nanometer

The distance or length can be measured by many units like,

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Answer:

C

Explanation:

The first and most obvious statement is that [OH-] is increased, but that is not offered to you.

The second most obvious statement is that the [H+] ion is decreased. That is offered to you. It is C

Answer:

[H+] is decreased.

Explanation:

Arrhenius Theory:

An acid is a substance which produces one or more hydrogen ions, (H+) in aqueous solution.

Examples:

[tex]HCl(aq)>H^+(aq)+Cl^-(aq)\\\\HBr(aq)>H^+(aq)+Br^- (aq)\\\\H_2 SO_4(aq)>2H^+(aq)+SO_4^2- (aq)\\\\H_3 PO_4(aq) >3H^+ (aq)+PO_4^3-(aq)\\\\CH_3 COOH(aq)>CH_3 COO^- (aq)+H^+ (aq)[/tex]

A Base is a substance which produces one or more hydroxyl ion or  hydroxide ion (OH-) in aqueous solution.

Examples

[tex]NaOH(s)>Na^+ (aq) + OH^- (aq)\\\\KOH(s)>K^+ (aq) +OH^- (aq)\\\\Ca(OH)_2 (s)>Ca^{2+} (aq)+2OH^-(aq)\\\\Al(OH)_3 (s)> Al^{3+}(aq)+ 3OH^- (aq)[/tex]

Please note:

(aq) stands for aqueous which means in the presence of water that is, water  acts as a solvent

So, on adding a base to the water increase in [tex][OH^-][/tex] will take place and this will decrease the Hydrogen ion concentration  

Pure water contains [tex][H^+]=[OH^-][/tex]

if the solution is acidic [tex][H^+ ]>[OH^- ][/tex]

if the solution is Basic [tex][H^+ ]<[OH^- ][/tex]

Answer:

32.5% female

67.5% male

Explanation:

To find a percentage, you need your total.

To find your total, add the amount of men and the amount of women.

[tex]162+78=240[/tex]

240 total people were enrolled in chemistry at that high school.

Next, to solve for your percentage of female participants, divide the amount of women by your total.

[tex]\frac{78}{240} =32.5[/tex]

32.5% were women. Do the same with your male participants for your male percentage.

[tex]\frac{162}{240} =67.5[/tex]

67.5% were men.

The percentage of women taking chemistry is 32.5%, while the percentage of men taking chemistry is 67.5%.

Chemistry may be defined as a branch of science that significantly deals with the composition, properties, and structure of chemical elements and compounds. It also involves a brief study of how they can alter and the energy that is liberated or absorbed when they change.

According to the question, the number of women enrolled in chemistry = 78.

The number of men enrolled in chemistry = 162.

∴ The total number of individual = 78 + 162 = 240.

Now, the percentage of women taking chemistry is calculated by the following formula:

[tex]\frac{number of women enrolled in chemistry}{ the total number of individual}[/tex]

= 78/240 = 32.5%.

Similarly, the percentage of men taking chemistry is calculated by the following formula:

[tex]\frac{number of men enrolled in chemistry}{the total number of individuals}[/tex]

= 162/240 = 67.5%.

Therefore, it is clear that 32.5% of women were enrolled in chemistry, while 67.5% of men were enrolled themselves in chemistry.

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Answer:

Explanation:

Similarities

Differences

Sapphire.

It  is a stone not a metal.

Answer: Option B

Explanation:

The plants uses sunlight to convert carbon dioxide and water into more complex carbohydrate known as glucose.

Plants utilize carbon dioxide during photosynthesis. Plants absorb water through roots and leaves.

Plants release oxygen as a by-product which is used by animals and other organism.

The carbohydrates inside the plants is broken down into simpler form and the energy released is used by plants for its cellular processes. This is known as cellular respiration.

Answer:

Plants take in carbon dioxide during photosynthesis and absorb water through their leaves and roots.

Answer:

The no. of moles will be doubled as the pressure is doubled.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(P₁n₂) = (P₂n₁).

P₂ = 2P₁,

∴ n₂ = (P₂n₁)/(P₁) = (2P₁n₁)/(P₁) = 2n₁.

So, the no. of moles will be doubled as the pressure is doubled.

The number of moles (n) of O2 would remain unchanged if the atmospheric pressure doubled but all other variables, such as temperature, volume, and the amount of gas, stayed the same.

According to the Ideal Gas Law, the relationship between pressure (P), volume (V), number of moles (n), and temperature (T) is given by:

[tex]\[ PV = nRT \][/tex]

where R is the ideal gas constant.

If the atmospheric pressure doubles, we can denote the new pressure as [tex]\( 2P \)[/tex]. Assuming that the volume (V), temperature (T), and the amount of gas (n) remain constant, the Ideal Gas Law for the new conditions would be:

[tex]\[ (2P)V = nRT \][/tex]

Since the volume (V), temperature (T), and the gas constant (R) are unchanged, the equation simplifies to:

[tex]\[ 2PV = nRT \][/tex]

Comparing this to the original Ideal Gas Law [tex]\( PV = nRT \),[/tex] we can see that the number of moles (n) does not change. The pressure and volume are directly proportional to each other according to Boyle's Law, which is a special case of the Ideal Gas Law when temperature and number of moles are constant. Therefore, if the volume were to decrease by half to maintain the relationship [tex]\( PV = nRT \)[/tex], the number of moles would remain the same. However, if the volume is not changed and only the pressure is doubled, the equation does not hold true unless the number of moles is also doubled. But in the context of the atmosphere, the volume would naturally decrease as the pressure increases (assuming a closed system), and thus the number of moles of O2 would not change.

Answer:

[tex]\boxed{1.2 \times 10^{23}\text{ atoms}}[/tex]

Explanation:

6.023 × 10²³ atoms of Ca are in 1 mol of Ca

[tex]\text{No. of atoms} = \text{0.2 mol} \times \dfrac{6.023 \times 10^{23}\text{atoms }}{\text{1 mol }} = \mathbf{1.2 \times 10^{23}} \textbf{ atoms}}\\\\\text{There are }\boxed{\mathbf{1.2 \times 10^{23}} \textbf{ atoms}} \text{ atoms in 0.20 mol of Ca}[/tex]

Answer:

Silicon can be used to make glass. So your 3rd option.

Explanation:

The elements with similar chemical properties are found in the same group of the periodic table. Thus, the correct option is B.

Chemical properties may be defined as those properties of matter or substances that can be observed in a chemical reaction. Some of them are flammability, toxicity, the heat of combustion, pH value, rate of radioactive decay, chemical stability, etc.

The groups are arranged vertically in a periodic table that shares identical chemical properties of the elements. There are 18 groups present in the modern periodic table.

Each group of the periodic table illustrates its own unique properties in terms of valance shell, electron, identity, and reactivity. For example, group 17 is known as halogen.

Therefore, the elements with similar chemical properties are found in the same group of the periodic table. Thus, the correct option is B.

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Answer:

Carbon disulfide

Explanation:

Carbon disulfide is the chemical name of the compound,  CS2.

Carbon disulfide is a clear or colorless liquid that is often used in organic chemistry.

Given 275 grams of sodium, approximately 3.6 x 10^24 molecules of sodium oxide are created when this reacts with excess oxygen, as per the provided balanced chemical equation.

To find out how many molecules of sodium oxide will be created, we need to first calculate the number of moles of sodium being reacted. Given that the molar mass of sodium is about 23g/mol, if we have 275 grams of sodium, that would translate to about 275/23 = 11.96 moles of sodium.

Using the molar ratio in the balanced chemical equation, 4 moles of sodium produce 2 moles of sodium oxide. So, 11.96 moles of sodium would produce 11.96/4 * 2 = 5.98 moles of sodium oxide.

Avogadro's number tells us that one mole of any substance contains 6.022 x 1023 molecules. Therefore, 5.98 moles of sodium oxide would contain 5.98 * 6.022 x 1023 = 3.6 x 1024 molecules of sodium oxide.

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When 275 grams of sodium reacts with excess oxygen, approximately 3.6 x 10^24 molecules of sodium oxide will be created.

To determine the number of molecules of sodium oxide produced, we need to use the given equation balanced equation 4Na + O2 -> 2Na2O. The molar mass of sodium (Na) is 22.99 g/mol and the molar mass of sodium oxide (Na2O) is 61.98 g/mol. We can use these molar masses and the given mass of sodium to calculate the number of moles of sodium, and then use the stoichiometric coefficients in the balanced equation to find the number of moles of sodium oxide produced. Finally, we can convert the number of moles to molecules using Avogadro's number (6.022 x 10^23).

First, we calculate the number of moles of sodium using the formula:

Moles = Mass / Molar mass

Moles of sodium = 275 g / 22.99 g/mol = 11.97 mol (approximately)

According to the balanced equation, 4 moles of sodium react to form 2 moles of sodium oxide. So, using the molar ratio, we can determine the number of moles of sodium oxide produced:

Moles of sodium oxide = 2/4 * 11.97 mol = 5.98 mol (approximately)

Finally, we can convert the number of moles of sodium oxide to molecules using Avogadro's number:

Number of molecules of sodium oxide = Moles of sodium oxide * Avogadro's number
Number of molecules of sodium oxide = 5.98 mol * 6.022 x 10^23 molecules/mol = 3.6 x 10^24 molecules

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Answer:  5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

[tex]\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}[/tex]

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

[tex]no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}[/tex]

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Keywords: moles conversion, Avogadro's number

Final answer:

To find the number of moles of silver nitrate in a sample with 5.3x10^24 molecules, divide the number of molecules by Avogadro's number. This results in approximately 8.8 moles of silver nitrate.

Explanation:

To determine how many moles are present in a sample of silver nitrate with 5.3x1024 molecules, you can use Avogadro's number, which is 6.022 x 1023 molecules per mol. By dividing the number of molecules in the sample by Avogadro's number, you will get the number of moles in the sample.

To perform the calculation:

Therefore, the sample contains approximately 8.8 moles of silver nitrate.