Answer:
Without doing any calculations it is possible to determine that silver chromate is more soluble than C,D , and silver chromate is less soluble than none .
It is not possible to determine whether silver chromate is more or less soluble than A,B by simply comparing Kspvalues
Explanation:
For this kind of question you need to obtain the balanced equation for the solubility, first, you will write the dissociation equation for every molecule, obtaining the ions in which it dissociates. Then you substitute in the Kps equation
[tex]A_{n}B_{m} -> nA^{m+}+mB^{n-} \\K_{s}=[A^{m}]^{n}[B^{n}]^{m}[/tex]
Considering the corresponding stoichiometry you'll substitute in your dissociation equations as follow.
[tex]Ag_{2}CrO_{4}(s)->2Ag^{+}(aq)+CrO_{4} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\A) PbF_{2}(s)->Pb^{2+} (aq)+2F^{-}\\s->s+2s\\s->[s][2s]^{2}=4s^{3}\\\\\\B)Ag_{2}SO_{3}(s)->2Ag^{+}(aq)+SO_{3} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\\\C)NiCO_{3}(s)->Ni^{2+}(aq)+CO_{3} ^{2-}\\ s ->s+s\\s->[s][s]=s^{2} \\\\\\D)AgCl(s)->Ag^{+}(aq)+Cl^{-}(aq)\\ s ->s+s\\s->[s][s]=s^{2} \\[/tex]
IIn this case, the silver chromate has a Kps of [tex]4sx^{3}[/tex], same as the compound in options A and B, comparing these numbers you can't determine which one is bigger. Finally, options C and D have a kps of [tex]s^{2}[/tex], this value is smaller than silver chromate's kps.
I hope you find this information useful! good luck!
The solubility of silver chromate compared to PbF2, Ag2SO3, NiCO3, AgCl cannot be definitively determined without empirical data or additional information. Factors influencing solubility include temperature, nature of the solute and solvent, pressure, and presence of other substances. Ksp values alone don't provide sufficient comparisons.
Explanation:Without empirical data or additional information, it isn't possible to definitively determine which of the compounds (PbF2, Ag2SO3, NiCO3, AgCl) silver chromate is more or less soluble than. Solubility often depends on various factors, including temperature, nature of the solute and solvent, pressure, and presence of other substances. The Ksp (solubility product constant) values, which are a measure of the amount of a compound that can dissolve in a solution, are unique to each substance and are empirically determined in a lab. Therefore, we cannot just compare the Ksp values to decide which compounds are more or less soluble than silver chromate.
Learn more about Solubility here:https://brainly.com/question/28170449
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Define the terms "Aldonic Acid", "uronic Acid", and "Aldaric Acid"
Explanation:
Aldonic Acid:
Aldonic acids are suger acids.
General formula of aldonic acid = [tex]HOOC-(CHOH)_n-CH_2OH[/tex]
Aldonic acids are obtained by the oxidation of aldehydic group of suger.
So, aldonic acids have hydroxyl group at one terminal and carboxylic group at another terminal.
Gluconic acid is an example of aldonic acid.
Uronic Acid:
It is also a type of suger acid having carbonyl functional group at one terminal and carboxylic group at other terminal.
It is obtained by oxidation of hydroxyl group of the sugar.
Aldaric Acid:
Aldaric acid is also a type of sugar acid having carboxylic acid functional group at both the ends.
Both the hydroxyl group and aldehydic group are oxidized to form class of compound, called aldaric acid.
Which model of election configuration is the most accurate? The quantum mechanical atomic model The Rutherford atomic model The Bohr atomic model O Plum pudding atomic model The quantum gravity atomic model
Answer:
Quantum mechanical atomic model.
Explanation:
The first model of electronic configuration was given by Bohr's model.
The most accurate model of electronic configuration is the quantum mechanical atomic model.
Bohr's model has various limitations:
1. It does not explain the Zeeman effect and stark effect.
2. It is not valid for multi-electron system.
3. Heisenberg uncertainty principle is not followed by this model
The quantum mechanical atomic model explains all the four quantum numbers for the electronic configuration of an atom in the periodic table.
The quantum mechanical atomic model considered the Heisenberg uncertainty principle.
Answer:
Quantum mechanical atomic model.
Explanation:
The atom model given by quantum mechanics is the most modern, precise and complex, based on the mathematical form of the atomic structure.
Quantum theory states that matter has properties associated with waves, which is why the atom model was based on this theory. The so-called “Uncertainty Principle” states that the electron has no exact position in the electrosphere, no definite speed and direction. This is why the Bohr atom, with electrons spinning in circular orbits, is surpassed by the quantum model.
Activity of the bacterial enzyme acetoacetate decarboxylase sharply declines below pH 6, suggesting there is an ionizable catalytic residue with pKa ~ 6. Using mutagenesis, this critical catalytic residue was determined to be Lys-115. a) What is the typical pKa of a lysine side chain and what ratio of deprotonated to protonated lysine would be expected at pH 7.5 (standard pH inside a bacterium)
Answer:
The typical pka of a lysine side chain is 10.5At pH=7-5 the ratio of deprotonated to protonated lysine is 0.001Explanation:
From literature, we know that the typical pka of a lysine side is 10.3.
Then we use the Henderson-Hasselbalch equation:
[tex]pH=pka+log\frac{[A^{-} ]}{[HA]}[/tex]
In this case, [A⁻] is the concentration of deprotonated lysine, and [HA] is the concentration of protonated lysine.
We put the data from the problem in the equation and calculate the ratio of deprotonated to protonated lysine:
[tex]7.5=10.5+log\frac{[A^{-} ]}{[HA]}\\-3.0=log\frac{[A^{-} ]}{[HA]}\\10^{-3.0}=\frac{[A^{-} ]}{[HA]}\\0.001=\frac{[A^{-} ]}{[HA]}[/tex]
13. Which ONE of the following is a chemical process? A. The liquid propane in a gas grill burns in a flame. B. Salt (sodium chloride) dissolves in water. C. Ice melts to form liquid water. D. The liquid propane in a gas grill evaporates because the user left the valve open. E. All of the above are chemical processes.
Answer:
A. The liquid propane in a gas grill burns in a flame.
Explanation:
Chemical changes is the change which occur when the substance combines with the another to form a completely new substance.
Considering Options B, C and D, the identity of each specie is not changed but the state is changed and thus, these are physical changes.
On the other hand, Option A, when propane is being burnt in the flame , it changes to gas and its identity is lost. Thus, is a chemical change.
The correct answer to the student's question is A, as the burning of liquid propane in a gas grill is a chemical process that results in the formation of new substances, which is the definition of a chemical change.
Explanation:The student's question pertains to identifying a chemical process from a list of options. To differentiate between physical and chemical changes, we recall that a physical change is a change in the state or form of a substance without changing its chemical composition, whereas a chemical change results in the formation of one or more new substances with different properties.
A. The liquid propane in a gas grill burns in a flame. This is a combustion reaction, where propane reacts with oxygen to produce carbon dioxide, water, and heat, making it a chemical process.B. Salt (sodium chloride) dissolving in water is a physical process, as the chemical composition of salt remains unchanged.C. Ice melting to form liquid water is a physical process because the chemical identity of the substance does not change.D. The liquid propane in a gas grill evaporating is also a physical process, as it involves the phase change from liquid to gas without altering the chemical composition of the propane.E. Not all of the listed options are chemical processes; hence, this option is incorrect.Therefore, the correct answer to the question is option A, where the burning of liquid propane in a gas grill is a chemical process resulting in new substances.
4. Each time that you prepare a diluted bleach solution you will want it to have a [OH-] = 0.02. Calculate how much 1.00 M NaOH you need to add to d.1. water to get every 20 mL of this concentration of OH- ion. Express your answer in drops of 1.00 M NaOH. (Assume that there are 20 drops in 1 m.)
Answer:
8 drops of 1.00 M NaOH will be needed.
Explanation:
Concentration of [tex][OH^-][/tex] in bleach solution = 0.02 M
[tex]NaOH\rightarrow OH^-+Na^+[/tex]
[tex]NaOH=[OH^-]=0.02M[/tex]
Concentration of bleach solution we want ,[tex]M_1[/tex] = 0.02 M
Volume of the bleach solution,[tex]V_1[/tex] = 20 ml
Concentration of NaOH solution,[tex]M_2[/tex] = 1.00 M
Volume of the NaOH solution required ,[tex]V_2[/tex] = ?
[tex]M_1V_1=M_2V_2[/tex]
[tex]0.02 M\times 20 mL=1.00 M\times V_2[/tex]
[tex]V_2=\frac{0.02 M\times 20 mL}{1.00 M}=0.4 mL[/tex]
1 mL = 20 drops
0.4 mL = 0.4 × 20 drops = 8 drops
8 drops of 1.00 M NaOH will be needed.
Assume that the NO, concentration in a house with a gas stove is 150 pg/m°. Calculate the equivalent concentration in ppm at STP.
Explanation:
It is known that for [tex]NO_{2}[/tex], ppm present in 1 [tex]mg/m^{3}[/tex] are as follows.
1 [tex]\frac{mg}{m^{3}}[/tex] = 0.494 ppm
So, 150 [tex]pg/m^{3}[/tex] = [tex]\frac{150}{1000} mg/m^{3}[/tex]
= 0.15 [tex]mg/m^{3}[/tex]
Therefore, calculate the equivalent concentration in ppm as follows.
[tex]0.15 \times 0.494 ppm[/tex]
= 0.074 ppm
Thus, we can conclude that the equivalent concentration in ppm at STP is 0.074 ppm.
An aqueous solution of sulfuric acid has a composition of 25.0 wt% sulfuric acid and a specific gravity of 1.22. Calculate the volume of solution that contains 245 kg of sulfuric acid.
Answer: The volume of solution is [tex]8.03\times 10^5mL[/tex]
Explanation:
The relationship between specific gravity and density of a substance is given as:
[tex]\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}[/tex]
Specific gravity of sulfuric acid solution = 1.22
Density of water = 1.00 g/mL
Putting values in above equation we get:
[tex]1.22=\frac{\text{Density of sulfuric acid solution}}{1.00g/mL}\\\\\text{Density of sulfuric acid solution}=(1.22\times 1.00g/mL)=1.22g/mL[/tex]
We are given:
25% (m/m) sulfuric acid solution. This means that 25 g of sulfuric acid is present in 100 g of solution
Conversion factor: 1 kg = 1000 g
Mass of solution having 254 kg or 245000 g of sulfuric acid is calculated by using unitary method:
If 25 grams of sulfuric acid is present in 100 g of solution.
So, 245000 grams of sulfuric acid will be present in = [tex]\frac{100}{25}\times 245000=980000g[/tex]
To calculate volume of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of solution = 1.22 g/mL
Mass of Solution = 980000 g
Putting values in above equation, we get:
[tex]1.22g/mL=\frac{980000g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{980000g}{1.22g/mL}=8.03\times 10^5mL[/tex]
Hence, the volume of solution is [tex]8.03\times 10^5mL[/tex]
when doing a problem like .3065g/138.03ml is the answer 2.220532X10(^3) g/ml or is it written differently?
Answer:
It is written differently.
Explanation:
The answer as given is not written correctly.
First, we must consider significant figures. Any non-zero number is a significant figure, and zeroes between significant figures are also significant, so 0.3065 has four significant figures and 138.03 has five significant figures. (Leading zeroes before the decimal point are not significant)
When two numbers are multiplied or divided, the answer has the same number of significant figures as the number that had the least number of significant figures. So in this case, the result will have four significant figures.
The result is written in scientific notation:
(0.3065)/(138.03) = 2.221 x 10⁻³
How many bonds can each of the elements below form with neighboring atoms in a compound? CHON BOSCH
Answer:
Maximum number of bonds each of the elements can form:
C: 4 bonds, H: 1 bonds, O: 2 bonds, N: 3 bonds, B: 3 bonds, S: 4 bonds.
Explanation:
The elements C, O, S and N follows the octet rule which establishes that every atom must have eight valence electrons to be stable. Thus, Carbon has 4 valence electrons, so could link 4 atoms. Nitrogen has 5 valence electrons, so could link 3 atoms. Oxygen and Sulfur have 6 valence electrons, so could link 2 atoms. Hydrogen and Boron are exceptions to the octet rule, therefore, the first one only needs 2 valence electron to be stable and the second one only needs 6 valence electron to be stable.
Final answer:
The number of covalent bonds an element can form generally corresponds with its group on the periodic table and its need to complete an octet, except for hydrogen which needs only two electrons. Group 4A elements like carbon form four bonds, Group 5A like nitrogen three, and Group 6A like oxygen and sulfur two. Boron typically forms three bonds but can form compounds or ions to achieve stability.
Explanation:
The number of covalent bonds an element can form is often related to its group number on the periodic table and its need to complete an octet of valence electrons. For example:
Carbon (C) is in group 4A, has four valence electrons, and tends to form four covalent bonds.
Hydrogen (H) needs two electrons for a full outer shell, so it forms one covalent bond.
Oxygen (O) is in group 6A with six valence electrons and forms two covalent bonds.
Nitrogen (N) is in group 5A, has five valence electrons, and forms three covalent bonds.
Boron (B) usually forms three covalent bonds, leaving it with six valence electrons.
Sulfur (S) is able to form two covalent bonds like oxygen, due to its position in group 6A.
Elements such as boron are unique in their bonding behaviors, often forming compounds or ions in order to achieve a more stable configuration, such as in the borohydride anion (BH4-). Transition elements and inner transition elements, with their d and f electrons, don't always follow the octet rule and can have variable bonding capacities.
A space shuttle moves through the atmosphere on its return from space. At point 1 on its wing, the air temperature and pressure are measured to be T1 = 300°C and p1 = 10,000 Pa while at point 2 they are T, = 700°C and p2 = 575,000 Pa. Calculate the air density in kg/m3 at both points 1 and 2.
Answer:
The air density in at points 1 is [tex]60.7 kg/m^3[/tex] and 2 is [tex]2060 kg/m^3[/tex].
Explanation:
Average molecular weight of an air ,M= 28.97 g/mol
[tex]PV=nRT[/tex]
or [tex] PM=dRT[/tex]
P = Pressure of the gas
n = moles of gas
T = Temperature of the gas
d = Density of the gas
M = molar mass of the gas
R = universal gas constant
Density at point-1 = [tex]d_1[/tex]
[tex]P_1 = 10,000 Pa=0.0986 atm[/tex]
[tex]1 Pa=9.86923\times 10^{-6} atm[/tex]
[tex]T_1 = 300^oC = 573.15 K[/tex]
M = 28.97 g/mol
[tex]d_1=\frac{PM}{RT}=\frac{0.0986 atm\times 28.97 g/mol}{0.0821 atm L/ mol K\times 573.15 K}[/tex]
[tex]d_1 =0.0607 g/ml[/tex]
1 g = 0.001 kg
[tex]1 mL = 10^{-6} m^3[/tex]
[tex]d_1=\frac{0.0607\times 0.001 kg}{10^{-6} m^3}=60.7 kg/m^3[/tex]
Density at point-2 = [tex]d_2[/tex]
[tex]P_2 = 575,000 Pa=5.67 atm[/tex]
[tex]T_2 = 700^oC = 973.15 K[/tex]
M = 28.97 g/mol
[tex]d_2=\frac{PM}{RT}=\frac{5.67 atm\times 28.97 g/mol}{0.0821 atm L/ mol K\times 973.15 K}[/tex]
[tex]d_2 =2.06 g/ml=2060 kg/m^3[/tex]
Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.
Answer: The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.
Explanation:
Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized [tex]\pi-[/tex] electrons are calculated by using the equation:
[tex]\text{Number of delocalized }\pi-\text{ electrons}=4n+2[/tex]
where,
n = 0 or any whole number
Calculating the value of electrons for n = 0Putting values in above equation, we get:
[tex]\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2[/tex]
Calculating the value of electrons for n = 1Putting values in above equation, we get:
[tex]\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6[/tex]
Calculating the value of electrons for n = 2Putting values in above equation, we get:
[tex]\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10[/tex]
Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.
A 2.60 gram sample of a compound know to contain only indium and chlorine is dissolved in 50.0 g of tin(IV) chloride (Kb = 9.43oC kg mol-1). The normal boiling point is raised from 114.1oC for pure SnCl4 to 116.3oC for the solution. What is the molecular weight and probable molecular formula of the solute?
Answer: 1. The molecular weight of the compound is 222.8 g/mol
2. The probable molecular formula of the solute is [tex]InCl_3[/tex]
Explanation:
Elevation in boiling point is given by:
[tex]\Delta T_b=i\times K_f\times m[/tex]
[tex]\Delta T_b=T_b-T_b^0=(116.3-114.1)^0C=2.2^0C[/tex] = elevation in boiling point
i= vant hoff factor = 1 (for non electrolyte)
[tex]K_b[/tex] = boiling point constant = [tex]9.43^0Ckg/mol[/tex]
m= molality
[tex]\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]
Weight of solvent (tin chloride)= 50.0 g =0.05 kg
Molar mass of unknown solute = M g/mol
Mass of unknown solute = 2.6 g
[tex]2.2=1\times 9.43\times \frac{2.6g}{M g/mol\times 0.05kg}[/tex]
[tex]M=222.8g/mol[/tex]
The possible formula for the compound would be [tex]InCl_3[/tex] as indium has valency of 3 and chlorine has valency of 1 has molecular mass almost equal to 222.8.
A chemist must prepare 200.0 mL of hydrochloric acid solution with a pH of 0.60 at 25 °C. He will do this in three steps: • Fill a 200.0 mL volumetric flask about halfway with distilled water. • Measure out a small volume of concentrated (6.0M) stock hydrochloric acid solution and add it to the flask. • Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits. mL X 5 ?
Answer:
In the second step, the chemist must measure 8.3 ml of concentrated acid
Explanation:
The concentration of the final solution can be obtained using the pH value:
pH = -log[H] = 0.60
[H] = 10^(-0.60) = 0.25 M
Then, the final concentration of HCl will be 0.25 M because HCl is a monoprotic acid, which means that HCl only has one hydrolyzable proton. Therefore: [HCl] = [H].
The number of moles of HCl in the final solution will be equal to the number of moles present in the volume taken from the stock solution:
n° of moles in the volume taken from stock solution = n° moles in the final solution.
The number of moles can be calculated as follows:
number of moles = concentration * volume
Then:
Ci * Vi = Cf * Vf
where
Ci = concentration of the stock solution
Vi = volume taken from the stock solution
Cf = concentration of the final solution
Vf = volume of the final solution
Replacing with the data, we can obtain Vi:
6.0 M * Vi = 0.25 M * 200.0 ml
Vi = 8.3 ml
maximum heat transfer in heat exchanger happend in :
a) Turbulant
b) Counter current
c) Co-current
Answer:
b) Counter current
Explanation:
In mechanical, chemical, nuclear and other systems, it happens that heat must be transferred from one place to another or from one fluid to another. Heat exchangers are the devices that allow you to perform this task the types of exchangers are presented of heat as a function of flow: parallel flow; counterflow; cross flow.
Among the main reasons why exchangers are used
Heat are as follows:
• Heat a cold fluid using a fluid with a higher temperature.
• Reduce the temperature of a fluid by means of a fluid with a lower temperature.
• Bring the fluid to the boiling point using a fluid with a higher temperature.
• Condense a fluid in a gaseous state by means of a cold fluid
A backflow occurs when the two fluids flow in the same direction but in opposite way. Each of the fluids enters the exchanger through different ends Since the fluid with less temperature goes backflow from the heat exchanger at the end where the fluid enters with higher temperature, the temperature of the coldest fluid will approach the temperature of the inlet fluid.
This type of exchanger turns out to be more efficient than the other two types mentioned above. In contract with the exchanger parallel flow heat, the counterflow exchanger may have the highest temperature in the cold fluid and the lower temperature in the hot fluid after heat transfer in the exchanger.
Be careful with turbulent that it is not a type of exchanger but a system in which a fluid is found.
What is the mass of a proton in Gigagrams? ) 1.67 10-39Gg C ) 1.67 10-33 Gg D) 1.67 10-30G
Answer: The mass of proton is [tex]1.67\times 10^{-33}Gg[/tex]
Explanation:
Proton is one of the sub-atomic particle which is present in the nucleus of the atom.
We know that:
Mass of proton = [tex]1.67\times 10^{-27}kg[/tex]
To convert this into Giga grams, we use the conversion factor:
[tex]1Gg=1\times 10^6kg[/tex]
Converting the given value into Giga grams, we get:
[tex]\Rightarrow 1.67\times 10^{-27}kg\times \frac{1Gg}{1\times 10^6kg}=1.67\times 10^{-33}Gg[/tex]
Hence, the mass of proton is [tex]1.67\times 10^{-33}Gg[/tex]
How many neutrons and protons are there in the nuclei of the following atoms. a. Li-7 b. O-16 c. Th-232 d. Pu-239
Answer:
a.
P = 3 , N = 4
b.
P = 8 , N = 8
c.
P = 90 , N = 142
d.
P = 94 , N = 145
Explanation:
Mass number = Number of protons + Number of neutrons
Also,
Atomic number = Number of protons
Li - 7
Given, Mass number of Lithium = 7
For lithium, atomic number = 3
So,
Number of protons = 3
Number of neutrons = Mass number - Number of protons = 7 - 3 = 4
O - 16
Given, Mass number of oxygen = 16
For oxygen, atomic number = 8
So,
Number of protons = 8
Number of neutrons = Mass number - Number of protons = 16 - 8 = 8
Th - 232
Given, Mass number of Thorium = 232
For Thorium, atomic number = 90
So,
Number of protons = 90
Number of neutrons = Mass number - Number of protons = 232 - 90 = 142
Pu - 239
Given, Mass number of Plutonium = 239
For Plutonium, atomic number = 94
So,
Number of protons = 94
Number of neutrons = Mass number - Number of protons = 239 - 94 = 145
AG' for the isomerization reaction glucose-1-phosphate (GIP) $ glucose-6-phosphate (G6P) is -7.1 kJ/mol. Calculate the equilibrium ratio of [G1P] to (G6P) at 25°C. Read this carefully to make sure you solve for the correct ratio! SHOW WORK! [G1P][G6P] =
Answer:
The ratio [G1P]/[G6P] = 5.7 . 10⁻².
Explanation:
Let us consider the reaction G1P ⇄ G6P, with ΔG° = -7.1 kJ/mol. According to Hess's Law, we can write the inverse reaction, and Gibbs free energy would have an opposite sign.
G6P ⇄ G1P ΔG° = 7.1 kJ/mol
This is the reaction for which we want to find the equilibrium constant (the equilibrium ratio of [G1P] to [G6P]):
[tex]Kc=\frac{[G1P]}{[G6P]}[/tex]
The equilibrium constant and Gibbs free energy are related by the following expression:
[tex]Kc=e^{-\Delta G\si{\textdegree}/R.T } } =e^{-7.1kJ/mol/8.314.10^{-3}kJ/mol.K.298K} } }=5.7.10^{-2}[/tex]
where,
R is the ideal gas constant (8.314 . 10⁻3 kJ/mol.K)
T is the absolute temperature (in kelvins)
Final answer:
To calculate the equilibrium ratio of [G1P] to [G6P], the Gibbs free energy equation is used with ΔG', universal gas constant R, and the temperature T substituted. The result is that the concentration of G6P is approximately 1.331 times that of G1P at equilibrium and at 25°C.
Explanation:
The student is asking about the equilibrium ratio of concentrations of glucose-1-phosphate ([G1P]) to glucose-6-phosphate ([G6P]) at 25°C when the standard free energy change (ΔG') for the isomerization reaction is given as -7.1 kJ/mol. To calculate this ratio, we can use the Gibbs free energy equation for the equilibrium constant (Keq):
ΔG' = -RT ln(Keq)
Where ΔG' is the standard free energy change, R is the universal gas constant (8.314 J/mol K), T is the temperature in Kelvin (25°C + 273.15 = 298.15 K), and Keq is the equilibrium constant which for this reaction is [G6P]/[G1P].
Substituting the values into the equation we get:
-7100 J/mol = -(8.314 J/mol K)(298.15 K) ln([G6P]/[G1P])
Now, we solve for ln([G6P]/[G1P]):
ln([G6P]/[G1P]) = ΔG' / (-R * T)
ln([G6P]/[G1P]) = -7100 J/mol / (-(8.314 J/mol K)(298.15 K))
ln([G6P]/[G1P]) = 0.286
Exponentiating both sides to remove the natural logarithm, we get:
[G6P]/[G1P] = e0.286 = 1.331
Therefore, at equilibrium and at 25°C, the concentration of G6P is approximately 1.331 times that of G1P.
Calculate the total number of days therapy available within a 300 ml bottle of ranitidine (as hydrochloride) 75 mg/5 ml. oral solution, when it is prescribed at a dose of 300 mg at night?
Answer: This therapy is available for 15 days.
Explanation:
We are given:
Oral solution dosage = 75 mg/5 mL
To calculate the volume of oral situation for single dose per, we use unitary method:
The volume required for 75 mg of solution is 5 mL
So, the volume required for 300 mg of solution will be = [tex]\frac{5mL}{75mg}\times 300mg=20mL[/tex]
The total volume of the ranitidine bottle = 300 mL
To calculate the number of days, we divide the total volume of the bottle by the volume of dose taken per night, we get:
[tex]\text{Number of days}=\frac{\text{Total volume}}{\text{Volume of dose taken per night}}=\frac{300mL}{20mL}=15[/tex]
Hence, this therapy is available for 15 days.
Show that 1 kJ/kg = 1000 m2/S2
Answer:
1000m2 / s2
Explanation:
Hello! In order to verify this, we have to do unit conversion. We also have to know that J (Joule) = kg * m2 / s2
Then we can start with the test.
1kJ / kg * (1000J / 1kJ) = 1000J / kg
1000J / kg = 1000kg * m2 / kg * s2
In this step we can simplify "kg".
So the result is
1000m2 / s2
Final answer:
To demonstrate that 1 kJ/kg equals 1000 m²/s², we recognize that the joule (J) is defined as kg-m²/s², and by converting kJ to J and canceling out the kg units, we affirm the equality.
Explanation:
To show that 1 kJ/kg is equal to 1000 m²/s², we start by recognizing that the unit of energy, the joule (J), is defined as 1 kilogram-meter²/second² (kg-m²/s²). Therefore, when we talk about energy per unit mass, we are effectively dividing energy by mass, leaving us with units of m²/s².
Given that 1 joule is 1 kg·m²/s², 1 kJ is 1000 joules (since the prefix 'kilo' means 1000). So when we have 1 kJ/kg, it's the same as saying 1000 J/kg. When we divide each term (kg·m²/s²) by kg, the kilograms cancel out, leaving us with m²/s². Thus, 1 kJ/kg is indeed equivalent to 1000 m²/s².
Which of the following is a diprotic acid? a. H2SO4 b. CH3COOH c. HC d. H3PO4
Answer:
The correct option is: A. H₂SO₄
Explanation:
Acid is a charged or a neutral molecule that is a proton donor and electron pair acceptors.
Acids can be classified into monoprotic acids and polyprotic acids.
Monoprotic acids are the acids that can release only one proton on dissociation.
Whereas, polyprotic acids are the acids that can release more than one proton on dissociation.
Diprotic acid is a type of polyprotic acid that can release two protons on dissociation. Example: H₂SO₄
A diprotic acid is an acid that contains two ionizable hydrogen atoms per molecule. Among the provided options, H2SO4 or sulfuric acid is such a diprotic acid. It ionizes in two stages, forming sulfates and hydrogen sulfates.
Explanation:The question asks about which of the given substances is a diprotic acid. Diprotic acids are those that contain two ionizable hydrogen atoms per molecule, which can release two protons or hydrogen ions. The ionization (release of protons) occurs in two steps: the first ionization generally takes place to a greater extent than the second.
By examining the chemical formulas of the options provided, we can identify H2SO4 (Sulfuric acid) as a diprotic acid. The ionization process works as following:
First ionization: H₂SO4 (aq) + H₂O(l) = H3O+ (aq) + HSO4¯(aq)Second ionization: HSO4¯ (aq) + H₂O(l) ⇒ H3O+ (aq) + SO4²- (aq)A significant attribute of diprotic acids like sulfuric acid is that they form both sulfates (e.g., Na2SO4) and hydrogen sulfates (e.g., NaHSO4).
Learn more about Diprotic Acids here:https://brainly.com/question/31732916
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Calculating molarity using solute moles A chemist prepares a solution of sodium chloride (NaCl) by measuring out 6.89 mol of sodium chloride into a 200 ml volumetric flask and filling the the mark with water. Calculate the concentration in mol/L of the chemist's sodium chloride solution. Round your answer to 3 significant digits. X 5 ? Explanation Check
Answer: Concentration of the chemist's sodium chloride solution is 34.4 mol/L.
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]V_s[/tex] = volume of solution in ml
Given : moles of [tex]NaCl[/tex] = 6.89
volume of solution = 200 ml
Putting in the values we get:
[tex]Molarity=\frac{6.89\times 1000}{200}=34.4mol/L[/tex]
Thus the concentration of the chemist's sodium chloride solution is 34.4 mol/L.
Dinitrogen monoxide gas is collected at-3.0 °C in an evacuated flask with a measured volume of 5.0 L. When all the gas has been collected, the press the flask is measured to be 0.100 atm . Calculate the mass and number of moles of dinitrogen monoxide gas that were collected. Round your answer to 2 significant digits. mass: mole: nol Explanation Check 2019 McGraw-Hill Education All Rights Reserved
Answer:
0.971 grams
Explanation:
Given:
Temperature = 3.0° C = 3 + 273 = 276 K
Volume, V = 5.0 L
Pressure, P = 0.100 atm
Now, from the relation
PV = nRT
where,
n is the number of moles,
R is the ideal gas constant = 0.082057 L atm/mol.K
thus,
0.1 × 5 = n × 0.082057 × 276
or
n = 0.022 moles
Also,
Molar mass of the Dinitrogen monoxide gas (N₂O)
= 2 × Molar mass of nitrogen + 1 × Molar mass of oxygen
= 2 × 14 + 16 = 44 grams/mol
Therefore, Mass of 0.022 moles of N₂O = 0.022 × 44 = 0.971 grams
If pressure p A + B/T+C/T, where A, B, and C are constants, and T is the temperature. What is the unit of A, B and C? Problem 2 (3 pts): If a system is at steady state, do properties vary with time? Can properties vary with location under steady state?
Answer:
The unit of A must be 'atm', and the units of B and C must be 'atmxK'.
If a system is at steady state it means the properties do not vary over time.
Explanation:
The units of pressure must be atm, bar, Pa or mmHg. If we use the atm unit the result of the equation should be the pressure in 'atm'. Thus, the unit of A must be 'atm', and the units of B and C must be 'atmxK'. So, If we replace the equation with the temperatures (T) in Kelvin (K) the result will be in 'atm'.
[tex]P (atm) = A(atm) + \frac{B(atm.K)}{T(K)} + \frac{C(atm.K)}{T(K)}[/tex]
Problem 2: If a system is at steady state it means the properties do not vary over time. This is the definition of a steady state. Also, every particular steady state will define their own properties but each steady state will no vary their properties over time.
A pipe of diameter 10 cm carries water at a velocity of 5 m/s. Determine the volumetric flow rate in m'/min (2 pts) a. b. the mass flow rate in kg/min (use the density of water on Thatcher's sheet)
Explanation:
It is given that diameter of the pipe is 10 cm which is also equal to [tex]10 \times 10^{-2}m[/tex].
Velocity of water = 5 m/s
(a) Formula to calculate volumetric flow rate is as follows.
Q = Area of the pipe (A) × Velocity of water (V)
= [tex]\frac{\pi}{4} \times 10 \times 10^{-2} \times 5 m^{3}/sec[/tex]
= 0.039 [/tex]m^{3}/sec[/tex]
= [tex]\frac{0.039 m^{3}/sec \times 60 sec}{1 min}[/tex]
= 2.36 [tex]m^{3} min^{-1}[/tex]
Hence, the volumetric flow rate is 2.36 [tex]m^{3} min^{-1}[/tex].
(b) Formula to calculate mass flow rate is as follows.
[tex]Q \times \rho[/tex]
= [tex]2.36 m^{3} min^{-1} \times 1000 kg m^{-3}[/tex]
= 2356.19 kg/min
Therefore, the mass flow rate is 2356.19 kg/min.
A certain rock has a mass of 125 g. The rock is gently lowered into a graduated cylinder whose water level is 250 mL. When the rock is completely submerged, the water level rises to 300 mL What is the volume of the rock?
Answer:
50 mL
Explanation:
Calculate the freezing temperature of the following solution of 0.50 M glucose (a covalent compound). Assume that the molality of the solution is 0.50 m. (The molar and molal concentrations of dilute aqueous solutions are often identical to two significant figures.) Enter your answer in the provided box. 0.50 m glucose (a covalent compound) °C
Answer:
-0.93 °C
Explanation:
Hello,
The freezing-point depression is given by:
[tex]T_f-T_f^*=-iK_{solvent}m_{solute}[/tex]
Whereas [tex]T_f[/tex] is the freezing temperature of the solution, [tex]T_f^*[/tex] is the freezing temperature of the pure solvent (0 °C since it is water), [tex]i[/tex] the Van't Hoff factor (1 since the solute is covalent), [tex]K_{f,solvent}[/tex] the solvent's freezing point depression point constant (in this case [tex]1.86 C\frac{kg}{mol}[/tex]) and [tex]m_{solute}[/tex] the molality of the glucose.
As long as the unknown is [tex]T_f[/tex], solving for it:
[tex]T_f=T_f^*-iK_fm\\T_f=0C-1*1.86C\frac{kg}{mol}*0.5\frac{mol}{kg} \\T_f=-0.93C[/tex]
Best regards.
Enter your answer in the provided box. Calculate the number of g of CO2 produced from the combustion of 5.24 mol of CzHg. The balanced equation is: C3H2(g) + 502(g) → 3CO2(g) + 4H2O(g). g CO2
Answer:
691.84g
Explanation:
I'm assuming that by CzHg, you mean C3H2
First, use the mole ratio in the equation to find the moles of CO2
n (CO2)= n ( C3H2) × 3
= 5.24 × 3
= 15.72
To find the mass of CO2 produced in grams, complete the following calculation
m= n × MM
where
m = mass
n= moles
MM= molecular mass
m= 15.72 × (12.01 +( 16×2))
m =691.8372
m= 691.84g
How many significant figures are represented in each of the following numbers? a) 7.1 x 10^-5 b) 0.00677 c) 750
Answer:
a) 7.1 x 10⁻⁵ : 2 significant figures
b) 0.00677 : 3 significant figures
c) 750 : 2 significant figure
Explanation:
The significant digits or figures refers to the digits of a given number that carry meaning and also contributes to precision of the given number.
a) 7.1 x 10⁻⁵ = 0.000071 : 2 significant figures, leading zeros are not significant.
b) 0.00677 : 3 significant figures, leading zeros are not significant.
c) 750 : 2 significant figure, trailing zeros are not significant.
Define "Triose", "Tetrose", "Pentose", and "Hexose" and identify which of these is/are most abundant
Answer:
Monosaccharides are the simplest form of carbohydrates that cannot be hydrolyzed to smaller compounds. Monosaccharides are the basic units of carbohydrates and are also known as simple sugars.
The monosaccharides are classified on the basis of number of carbon atoms present.
Triose is a type of monosaccharide molecule, which is composed of 3 carbon atoms.
Tetrose is a type of monosaccharide molecule, which is composed of 4 carbon atoms.
Pentose is a type of monosaccharide molecule, which is composed of 5 carbon atoms.
Hexose is a type of monosaccharide molecule, which is composed of 6 carbon atoms.
D-glucose is a hexose sugar and it is the most abundant monosaccharide in the nature.
Identify which two compounds below are constitutional isomers
(CH3)3COCH3
(CH3)2CHOCH3
(CH3)2CHOCH2CH3
Answer:
(CH₃)₃COCH3₃ and (CH₃)₂CHOCH₂CH₃
Explanation:
Isomers are compounds which have the same molecular formula. Constitutional isomers have different connectivity; the atoms are connected in different ways.
1. (CH₃)₃COCH₃
2. (CH₃)₂CHOCH3₃
3. (CH₃)₂CHOCH₂CH₃
Molecules 1 and 3 have the same formula (C₅H₁₂O) and are isomers. Molecule 2 is not an isomer. From the structural formula, it is clear that Molecules 1 and 3 have different connectivity.