Convenience sampling can be produce biased research results. True or false?

That's true, and there are also other mechanisms that can also create floods.

A. Igneous

Extrusive igneous rocks cool and solidify quicker than intrusive igneous rocks. They are formed by the cooling of molten magma on the earth's surface.

Sedimentary (sed-uh-MEN-tuh-ree) rocks, unlike the other two kinds of rocks, are formed on or near Earth's surface. They form from sediments eroded from other rocks. The sediments may come from igneous, metamorphic, or other sedimentary rocks.

Answer and explanation;

In 1670 Gabriel Mouton, Vicar of St. Paul’s Church and an astronomer proposed the swing  length  of  a  pendulum  with  a  frequency  of  one  beat  per  second  as  the  unit  of length.

In 1791 the Commission of the French Academy of Sciences proposed the name meter to the unit of length. It would equal one tens-millionth of the distance from the North Pole to the equator along the meridian through Paris.It is realistically represented by the distance between two marks on an iron bar kept in Paris.

In 1889 the 1st General Conference on Weights and Measures define the meter as the distance between two lines on a standard bar that made of an alloy of 90%platinum with 10%iridium.

In 1960 the meter was redefined as 1650763.73 wavelengths of orange-red light, in a vacuum, produced by burning the element krypton (Kr-86).

In 1984 the Geneva Conference on Weights and Measures has  defined  the  meter  as  the  distance  light  travels,  in  a  vacuum,  in 1299792458⁄ seconds  with  time  measured  by  a  cesium-133  atomic  clock  which  emits  pulses  of radiation at very rapid, regular intervals.

The metric system was first put into practice in 1799, during the French Revolution, when the existing system of measures became impractical for trade and was supplanted by a decimal system based on the kilogram and the meter.

During the French Revolution, the existing system of measures became impractical for trade and was replaced by a decimal system based on the kilogram and the meter, and the metric system was born.

In 1793, the meter was defined as one ten-millionth of the distance from the equator to the North Pole along a great circle, implying that the Earth's circumference is approximately 40000 km.

The meter was redefined in 1799 in terms of a prototype meter bar.

The meter was introduced as a new unit of length, defined as one ten-millionth of the shortest distance between the North Pole and the Equator passing through Paris, assuming an Earth flattening of 1/334.

Thus, this is the history of the metric system as it applies to the meter.

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Answer:

Mechanical energy  = 3.92 J

exactly 3.92 j

Explanation:

As we know that mechanical energy is sum of kinetic energy and potential energy of the system

so here we can say that mechanical energy is sum of kinetic energy of ball and its potential energy

Since ball is at rest so kinetic energy of the ball must be ZERO

Now for potential energy we know that

[tex]U = mgh[/tex]

now we know

m = 0.2 kg

h = 2 m

now for potential ene'rgy

[tex]U = (0.20)(9.8)(2)[/tex]

[tex]U = 3.92 J[/tex]

so mechanical energy is given as

Mechanical Energy = 3.92 + 0 = 3.92 J

Answer:

b

Explanation:

When driving in rain, the road becomes the most slippery right after it starts to rain.

As the first rainwater hits the road, it mixes with the oil, rubber tire particles, and other gunk on the pavement, forming a very slippery coating on the surface.

After it has rained for a while, a lot of that gunk gets washed away, and most of the slipperiness is just water ... which is pretty slippery on its own, but not as slippery as it is when it has oil and rubber particles in it too.

For artificial gravity the the position of rim we have to rotate the space station

Due to rotation it will experience centripetal acceleration at the position of rim

Now in order to experience this acceleration to be same as gravity we can say centripetal acceleration must be equal to gravity here

[tex]a_c = g[/tex]

as we know that centripetal acceleration is given as

[tex]a_c = w^2R[/tex]

[tex]a_c = w^2*200 = g[/tex]

[tex]w^2* 200 = 9.8[/tex]

[tex]w = \sqrt{\frac{9.8}{200}}[/tex]

[tex]w = 0.22 rad/s[/tex]

now we know that angular frequency will be related to time period as

[tex]T = \frac{2\pi}{w}[/tex]

[tex]T = \frac{2\pi}{0.22}[/tex]

[tex]T = 28.4 s[/tex]

so it will rotated by time period T = 28.4 s

a. Turbine

The turbine converts the kinetic energy of falling water into mechanical energy.

Answer : Turbine is used to generate electricity in tidal power plant.

Explanation :

In tidal power plant, the kinetic energy of moving water is used to generate electricity. It is one of the renewable source of energy.

The turbine is a part of the tidal power plant which is used to generate electricity. It is kept on the floor of the sea where there is a very strong tidal flow.

The turbines used in tidal power plant is very expensive as compared with the wind turbines.

Hence, the correct option is (a) " turbine ".

(1)

Cheetah speed: [tex]v_c = 97.8 km/h=27.2 m/s[/tex]

Its position at time t is given by

[tex]S_c (t)= v_c t[/tex] (1)

Gazelle speed: [tex]v_g = 78.2 km/h=21.7 m/s[/tex]

the gazelle starts S0=96.8 m ahead, therefore its position at time t is given by

[tex]S_g(t)=S_0 +v_g t[/tex] (2)

The cheetah reaches the gazelle when [tex]S_c=S_g[/tex]. Therefore, equalizing (1) and (2) and solving for t, we find the time the cheetah needs to catch the gazelle:

[tex]v_c t=S_0 + v_g t[/tex]

[tex](v_c -v_g t)=S_0[/tex]

[tex]t=\frac{S_0}{v_c-v_t}=\frac{96.8 m}{27.2 m/s-21.7 m/s}=17.6 s[/tex]

(2) To solve the problem, we have to calculate the distance that the two animals can cover in t=7.5 s.

Cheetah: [tex]S_c = v_c t =(27.2 m/s)(7.5 s)=204 m[/tex]

Gazelle: [tex]S_g = v_g t =(21.7 m/s)(7.5 s)=162.8 m[/tex]

So, the gazelle should be ahead of the cheetah of at least

[tex]d=S_c -S_g =204 m-162.8 m=41.2 m[/tex]

The cheetah catches the prey [tex]\fbox{17.78 s}[/tex] before the gazelle.

The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is [tex]\fbox{40.83 m}[/tex].

Further Explanation:

The speed is the rate of change of the distance and the relative speed is the speed of the one object in respect of another object. If two body moves in same direction then the relative speed in respect of the one body is given by subtract of both speed and it they are moving in opposite direction the relative speed in respect of the one body is given by sum of both speeds.

Given:

The maximum speed of the cheetah is [tex]97.8 km/h[/tex].

The maximum speed of the gazelle is [tex]78.2 km/h[/tex].

The distance between the starting points of cheetah and the gazelle is [tex]96.8 m[/tex].

Concept:

The expression for the position of the cheetah at some time t is:

[tex]{S_1}={v_c}t[/tex]                                            …… (1)

Here, [tex]{S_1}[/tex]the position of the cheetah at some time [tex]t[/tex], [tex]{v_c}[/tex] is the speed of the cheetah and [tex]{S_1}[/tex] is the distance covered at time [tex]t[/tex].

The expression for the position of the gazelle at some time [tex]t[/tex] is:

[tex]{S_2}={S_o}+{v_g}t[/tex]                                              …… (2)

Here, [tex]{S_2}[/tex] the position of the gazelle at some time [tex]t[/tex], [tex]{v_g}[/tex] is the speed of the gazelle, [tex]{S_o}[/tex] is the distance between the starting points of cheetah and the gazelle.

At the time when the cheetah reached the gazelle then [tex]{S_1}={S_2}[/tex].

Equate equation (1) and (2).

[tex]\begin{aligned}{v_c}t&={S_o}+{v_g}t\hfill\\{v_c}t-{v_g}t&={S_o}\hfill\\t\left( {{v_c} - {v_g}}\right)&={S_o}\hfill\\t&=\frac{{{S_o}}}{{\left( {{v_c} - {v_g}} \right)}}\hfill\\\end{aligned}[/tex]

Substitute [tex]97.8 km/h[/tex] for [tex]{v_c}[/tex], [tex]78.2 km/h[/tex] for [tex]{v_g}[/tex] and [tex]96.8 m[/tex] for [tex]{S_o}[/tex] in the above equation.

[tex]\begin{aligned}t&=\frac{{96.8{\text{ m}}}}{{\left( {97.8 - 78.2} \right){\text{km/h}}\left({\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)}}\\&=\frac{{96.8{\text{ m}}}}{{{\text{19}}{\text{.6 m/s}}\left( {\frac{5}{{18}}}\right)}}\\&=17.78{\text{s}}\\\end{aligned}[/tex]

Therefore, the cheetah catches the prey [tex]17.78 s[/tex] before the gazelle.

To calculate the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape we should subtract the distance covered by the cheetah and gazelle in [tex]7.5 s[/tex].

The expression for the distance covered is:

[tex]S = vt[/tex]

Here, [tex]S[/tex] is the distance covered, [tex]v[/tex] is the speed and [tex]t[/tex] is the travel time.

Substitute [tex]97.8 km/h[/tex] for [tex]v[/tex] and [tex]7.5 s[/tex] for [tex]t[/tex] in the above equation.

[tex]\begin{aligned}S&=\left( {97.8{\text{ km/h}}} \right)\left( {\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)\left( {7.5{\text{ s}}} \right)\\&=\left( {97.8{\text{ m/s}}} \right)\left( {\frac{5}{{18}}} \right)\left( {7.5{\text{ s}}} \right)\\&=203.75{\text{m}}\\\end{aligned}[/tex]

Therefore, the distance covered by the cheetah in [tex]7.5 s[/tex] is [tex]203.75 m[/tex].

Substitute [tex]78.2 km/h[/tex] for [tex]v[/tex] and [tex]7.5 s[/tex] for [tex]t[/tex] in the above equation.

[tex]\begin{aligned}S&=\left( {78.2{\text{ km/h}}} \right)\left( {\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)\left( {7.5{\text{ s}}} \right)\\&=\left( {78.2{\text{ m/s}}} \right)\left( {\frac{5}{{18}}} \right)\left( {7.5{\text{ s}}} \right)\\&=162.92{\text{ m}}\\\end{aligned}[/tex]

Therefore, the distance covered by gazelle in [tex]7.5 s[/tex] is [tex]162.92 m[/tex].

The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is:

[tex]\begin{aligned}d&=\left( {203.75 - 162.92} \right){\text{ m}}\\&=40.83{\text{ m}}\\\end{aligned}[/tex]

Therefore, the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is [tex]\fbox{40.83 m}[/tex].

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Answer Details:

Grade: High school

Subject: Physics

Chapter: Kinematics

Keywords:

Cheetah, 97.8 km/h, gazelle, 78.2 km/h, full speed, 96.8 m. ahead, catches, prey, 7.5 s, minimum, ahead, escape, answer, unit, s, m, 40.83 m.

In the A case, v0=0, in the B case v0 >0, so v is greater in the B case. In other words, v is related to the kinetic energy, since the rock B has a larger kinetic energy in the beginning, it also has a larger kinetic energy (larger velocity) in the end.

The correct answer is that rock a has a greater velocity when each rock reaches the ground at the bottom of the cliff.

To understand why rock a has a greater velocity upon impact with the ground, let's consider the physics of free-falling objects under the influence of gravity. Both rocks are subject to the acceleration due to gravity, which is approximately[tex]\(9.81 \, \text{m/s}^2\)[/tex] downward.

For rock a, which is simply dropped from rest, its initial velocity is zero. The only force acting on it is gravity, pulling it downward. Its velocity at any time \(t\) before it hits the ground can be calculated using the equation for uniformly accelerated motion:

[tex]\[ v_{a} = u_{a} + gt \][/tex]

where[tex]\(v_{a}\)[/tex] is the final velocity, [tex]\(u_{a}\)[/tex] is the initial velocity (which is zero for rock a), [tex]\(g\)[/tex] is the acceleration due to gravity, and [tex]\(t\)[/tex] is the time of fall. Since [tex]\(u_{a} = 0\)[/tex], the equation simplifies to:

[tex]\[ v_{a} = gt \][/tex]

For rock b, which is thrown upward, its initial velocity[tex]\(u_{b}\)[/tex] is upward and has some positive value. As it rises, it slows down due to the acceleration due to gravity acting in the opposite direction of its motion. At its highest point, its velocity will be zero, and then it will start to fall back down, accelerating due to gravity until it hits the ground. The velocity of rock b just before impact can be calculated using the same equation for uniformly accelerated motion, but taking into account that it starts with an initial upward velocity and then reverses direction:

[tex]\[ v_{b} = u_{b} - gt_{up} + gt_{down} \][/tex]

where [tex]\(t_{up}\)[/tex]is the time it takes for rock b to reach its highest point and \[tex](t_{down}\)[/tex]is the time it takes to fall back to the ground. Since the acceleration due to gravity is the same for both rocks, and assuming that air resistance is negligible, the time of ascent [tex]\(t_{up}\)[/tex] for rock b is equal to the time of descent [tex]\(t_{down}\), so \(t_{up} = t_{down} = t/2\).[/tex] The equation for rock b's velocity upon impact becomes:

[tex]\[ v_{b} = u_{b} - g(t/2) + g(t/2) \] \[ v_{b} = u_{b} \][/tex]

Since rock a was dropped from rest, its velocity upon impact is due solely to the acceleration due to gravity over the entire time \(t\) of its fall, while rock b's velocity upon impact is its initial launch velocity minus the effect of gravity over half the time (as it rises) and plus the effect of gravity over the other half of the time (as it falls).

Because rock a starts from rest and only accelerates downward, it will have a greater velocity upon impact than rock b, which has its initial upward velocity reduced by the same gravitational acceleration over the time of its ascent and then increased by the same gravitational acceleration over the time of its descent. Thus, rock a's velocity at the moment of impact will be greater than rock b's velocity at the moment of impact, assuming they both hit the ground at the same time and air resistance is negligible.

They want to fill up their outer electron shell in order to become stable.  All things in life are made from atoms and all atoms want to reside in their lowest energy state because it is most stable.  To do so, atom either share, give, or gain electrons to achieve this stability.

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

[tex]d = v_i * t + \frac{1}{2} at^2[/tex]

[tex]d = 0 + \frac{1}{2}*9.8* 1.5^2[/tex]

[tex]d = 4.9 * 2.25[/tex]

[tex]d = 11.025 m[/tex]

so the bag will fall down by total distance of 11.025 m from its initial released position.

The 1.0 lb bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds, assuming it is in free fall and subject to Earth's gravitational acceleration of 9.8 m/s².

To determine the distance the 1.0 lb bag of feathers has traveled after falling for 1.5 seconds, assuming it has reached free fall and is only affected by gravitational acceleration, we can use the formula for the distance covered by an object in free fall:

d = ½ * g * t²,

where g is the acceleration due to gravity (9.8 m/s²) and t is the time in seconds.

Plugging in the values:

d = ½ * 9.8 m/s² * (1.5 s)²

d = ½ * 9.8 * 2.25

d = ½ * 22.05

d = 11.025 meters

Therefore, the bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds.

From that graph of the force of the sun on a comet, you can see that the force increases as the distance decreases. (A)

Here, we are required to determine the relationship between the force exerted by the sun on a Comet and the distance between the sun and the comet.

From the graph, the force exerted by the sun on the comet increases as the distance between them decreases.

From the graph, it is evident that the slope of the graph is negative.

Although, the slope of the graph is not constant as in the case of linear graphs (equation of a straight line).

However, the positioning of the line joining all points on the graph suggests that the slope of the graph is negative.

Consequently, the parameters ( i.e the force and distance) are inversely proportional to one another.

Therefore, as the force increases, the distance decreases.

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Answer:

Distance between moon and earth = [tex]3.84*10^{5}km[/tex]

Explanation:

 Distance traveled by radio waves = Velocity of radio waves * Time taken by radio waves

 Velocity of radio waves = [tex]3*10^{8}m/s[/tex]

 Time taken by radio waves = 1.28 seconds

 So distance traveled by radio wave = [tex]3*10^{8}*1.28=3.84*10^{8}m[/tex]

 Distance between moon and earth = [tex]3.84*10^{8}m[/tex]=[tex]3.84*10^{5}km[/tex]

Density: g/mL, kg/cubic meter  

Volume: L, teaspoon  

Mass: g, MeV/sq. C

The common units for length, weight, and time in the American system are foot, pound, and second, respectively. In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively.

In the American system of measurement, the common units for length, weight, and time are foot, pound, and second, respectively. For example, the ton (2240 lb) is a larger unit of weight, the yard (3 ft) is a smaller unit of length, and the minute (60 s) is a smaller unit of time.

In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively. For example, the kilometer (1000 m) is a larger unit of length, the gram (0.001 kg) is a smaller unit of weight, and the millisecond (0.001 s) is a smaller unit of time.

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Usually fossils are formed when a layer of sediment covers dead plants, animals and microorganisms. This makes sedimentary rocks like limestone and shale the best in the formation of fossils.

The final speed of the car is 4.131 m/s and it covers 5.78 m during this acceleration .

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given that: The forward force on the car is 2830 N while the resisting forces total 130 N.

Net force acting on the car is = 2830 N - 130 N = 2700 N.

The car has a mass of 1830 kg.

The acceleration of the car is = force/mass = 2700 N / 1830 m/s^2

= 1.475 m/s^2.

The acceleration lasts for 2.8 s.

Hence,  the final speed of the car is =  1.475 m/s^2 × 2.8 s = 4.131 m/s.

Hence,  it covers during this acceleration = (acceleration × time²)/2

= ( 1.475 × 2.8²)/2 m.

= 5.78 m.

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1. Kinetic

2. Chemical

3. Potential

Remark

Tension is a type of force. In this case the total force is that of the chain and the reflector  are both vertical and therefore acted on by gravity.

Step One

Find the total mass

Mass = m = M1 + M2

M1 = 170 kg

M2 = 8.0 kg

m= 178.0

Step Two

Find the tension

m = 178.0 kg

a = 9.81

T = ???

Formula

T  = m * a

T = 178 * 9.81

T = 1746 N

Comment

If this seems a little strange to you, remember that you are actually finding the downward force felt by the hook holding up the chain and reflector. That hook is going to experience the weight of both. I think the question used 9.8 rather than 9.81. That's what it did.

Answer

C

we know that

the speed is equal to

[tex]speed=\frac{distance}{time}[/tex]

The slope of the line on the graph is equal to the speed of the car

so

during the segment B the slope of the line is equal to zero

that means

the speed of the car is zero

therefore

the answer is the option B

The car has come to a stop and has zero velocity

Option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Further Explanation:

According to the theory of graphs, ‘the straight line parallel to x axis’ means the quantity given on y axis is not changing or is constant with respect to the change in the quantity on x axis. This is why because the slope of that particular straight line is zero.

Concept:

Mathematically, the slope is defined as the tangent (trigonometry) of the angle made by the segment with the x axis or it is also defined as the ratio of change in the quantity on y-axis to change in the quantity on x-axis.

[tex]\boxed{\text{slope}=\tan(\theta)}[/tex]

Here, [tex]\theta[/tex] is the angle made by the segment of graph with x-axis

The slope can also be expressed as:

[tex]\boxed{\text{slope}=\dfrac{\text{change in quantity given on y-axis}}{\text{change in quantity given on x-axis}}}[/tex]

Here, the quantity given on y axis is car’s position and that given on x axis is time taken by the car to travel.

The slope of position-time graph gives velocity.  So, by the definition of slope, we have  

[tex]{\text{velocity}=\dfrac{\text{change in position}}{{\text{change in time}}}[/tex]

Here, as shown in the graph, the two ends of the segment B have same values of position on y axis. So, change in position will be zero.

Substitute [tex]0[/tex] for [tex]\text{change in position}[/tex] in above expression.

[tex]\text{Velocity}=0\text{ m/s}[/tex]

This shows that the speed of the car in the segment B of the graph will be zero as there is no change in the position of the car with respect to time.

Thus, option (B) is correct .i.e. the car has come to a stop and has zero velocity.

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Position, car, relation to time, segment B, 80 sec, zero velocity, travelling, faster, graph, position vs time, constant velocity, slope, change in position, change in time.

 In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties

To provide a solution to the question, we need to understand the key differences between vectors and scalars as described by the students in the chart. Here are the typical characteristics that distinguish vectors from scalars:

1. Magnitude and Direction: Vectors have both magnitude and direction, whereas scalars have only magnitude. This is the fundamental difference between the two. For example, velocity is a vector quantity because it describes both the speed (magnitude) and the direction of motion, while speed alone is a scalar quantity.

 2. Representation: Vectors are often represented by arrows, where the length of the arrow corresponds to the magnitude and the arrowhead indicates the direction. Scalars are typically represented by a number with units, if applicable.

 3. Addition: When adding vectors, both their magnitudes and directions must be considered, which often involves geometric construction or trigonometric calculations. In contrast, scalar addition is straightforward and involves simply adding the numerical values.

 4. Multiplication by a Scalar: Multiplying a vector by a scalar changes the magnitude of the vector but not its direction. The result is a vector that is parallel to the original vector.

 5. Dimensionality: Vectors can be one-dimensional (straight line), two-dimensional (plane), or three-dimensional (space). Scalars are zero-dimensional, as they are just single values without direction.

6. Physical Quantities: Examples of vector quantities include displacement, velocity, acceleration, and force. Examples of scalar quantities include mass, temperature, energy, and time.

 Based on these characteristics, the students' statements can be analyzed to determine if they are correct or incorrect. For instance, if a student says that a vector has only magnitude, this statement is incorrect because vectors must have both magnitude and direction.

To solve the question accurately, we would need to see the specific statements made by each student in the chart. However, without the actual statements, we can only provide a general explanation of the differences between vectors and scalars.

 In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties."

Answer:

C. 1.00 m/s^2

Explanation:

We can solve the problem by using Newton's second law:

[tex]F=ma[/tex]

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this case, the net force applied by Amber is F=35 N, while the total mass of the brother+the wagon is

[tex]m=32 kg+3 kg=35 kg[/tex]

Therefore, we can re-arrange the previous equation to find the acceleration:

[tex]a=\frac{F}{m}=\frac{35 N}{35 kg}=1.00 m/s^2[/tex]

slope= Force/Mass

force is measured in Newtons (N) and mass in kilograms (kg). This means that the units of the slope are N/kg. However a Newton is also equal to one kg*m/s2, so if we divide this by one kg we are left with a slope with units m/s2, which acceleration is measured in!  

Answer:

 The velocity of a falling object

Explanation:

  The positive X axis is towards right and positive Y axis is towards up, so North direction is positive

  A vector with less than 1 magnitude is not negative, because its magnitude may be in between 0 and 1 which is positive vector.

  Any vector whose magnitude is greater than 1 is never be a negative vector.

  The velocity of a falling object is towards bottom, that is towards negative Y axis. So that vector is negative.

a ) study of the different amounts of time it takes water to evaporate completely.

i always end up helping u <3 lol

Answer: A . A study of the different amounts of time it takes water to evaporate completely

Explanation:

The quantitative data can be define as the property or parameter which can be measured in units and counted in numbers. It can be represented in symbols, units and number code.  

A is the correct option this is because of the fact that time can be measured in seconds, minutes and hours. Thus different amounts of time it takes water to evaporate completely can be a approach to conduct the experiment using quantitative data.  

Answer:

  His kinetic energy increases, potential energy decreases

  The sum of kinetic and potential energy is a constant at any instant before he comes to rest.

Explanation:

  Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression [tex]\frac{1}{2} mv^2[/tex], so as he moves his kinetic energy increases.

  When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.

  Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.

                             mgh+[tex]\frac{1}{2} mv^2[/tex]= Constant

Answer:

Answer:

 His kinetic energy increases, potential energy decreases

 The sum of kinetic and potential energy is a constant at any instant before he comes to rest.

Explanation:

 Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression , so as he moves his kinetic energy increases.

 When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.

 Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.

The value of R3 is A) 10 Ω

Answer:

Resistor R₃ = 10 Ω

Explanation:

It is given that,

Current flowing in the circuit, I = 2 A

Resistors R₁ = 2 Ω

Resistor R₂ = 3 Ω

Voltage, V = 30 V

We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :

[tex]R_{eq}=R_1+R_2+R_3[/tex]

[tex]R_{eq}=2\ \Omega+3\ \Omega+R_3[/tex]    

[tex]R_{eq}=5\ \Omega+R_3[/tex]..............(1)

Using Ohm's law : [tex]V=IR_{eq}[/tex]

[tex]30\ V=2\ A\times (5 + R_{3})[/tex]

On solving above equation : [tex]R_3=10\ \Omega[/tex]

Hence, the correct option is (A) " 10 Ω "                                            

Answer: The correct answer is option A.

Explanation:

Kinetic friction is defined as the frictional force acting between the two objects in contact. It resists the motion of one object over the other.

Rolling friction is defined as the frictional force which acts on the rolling object.

Static friction is the frictional force that keeps an object at rest.

Cohesive friction is defined as the frictional force that hold the particles together.

We need to drag a sled across the ground, so the frictional force is acting between two objects. Here, one object is sled and other is the ground. So, in order to move the sled, it must overcome kinetic friction.

Hence, the correct option is A.

Answer:you are very flexible

Explanation:

That’s a very high score.