Correct reason why (x+y)^2 is not equal to x^2+y^2

Answer:

(-1,-6) , (7,0) and (11,3)

Step-by-step explanation:

3x - 4y = 21

4y = 3x - 21

y = 3/4x - 21/4 , the slope(m) of this line is 3/4

The x and y intercepts are (0,-5.25) and (7,0)

Taking a point (-3,3):

Slope(m) = change in y ÷ change in x

Slope = (3 - 0) ÷ (-3 - 7) = -0.3

Since the slope here is not 3/4 then point (-3,3) is not on the line.

Taking a point (-1,-6)

Slope = (-6 - 0 ) ÷ (-1 - 7) = -6/-8 = 3/4

The point (-1,-6) is on the line.

Taking a point (7,0):

This point is the x - intercept and so its on the line.

Taking a point (11,3):

Slope = (3 - 0) ÷ (11 - 7) = 3/4

Therefore the point (11,3) is on the line.

Answer:

wut that dude said is correct i verified it

Step-by-step explanation:

[tex]\frac{11}{18}[/tex]

let n represent the number to be found

simplify the ratio on the right by multiplying both parts by 3

we now have

[tex]\frac{n}{11}[/tex] = [tex]\frac{1}{18}[/tex] ( cross-multiply )

18n = 11 ( divide both sides by 18 )

n = [tex]\frac{11}{18}[/tex]

The complete ratio for __:11= 1/3 :6   is   [tex]\frac{11}{18} : 11 = \frac{1}{3} : 6[/tex]

The given equivalent ratio expression is:

__:11= 1/3 :6

This can be re-written as:

[tex]x : 11 = \frac{1}{3}:6[/tex]

Rewrite the ratio in fraction form:

[tex]\frac{x}{11} = \frac{1}{3} \div 6[/tex]

Change the division sign on the right to multiplication, and 6 to 1/6

[tex]\frac{x}{11} = \frac{1}{3} \times \frac{1}{6} \\\\\frac{x}{11} = \frac{1}{18}[/tex]

Cross multiply:

18x   =  11

Divide both sides bu 18

[tex]\frac{18x}{18} = \frac{11}{18} \\\\x = \frac{11}{18}[/tex]

Therefore, the equivalent ratio is [tex]\frac{11}{18} : 11 = \frac{1}{3} : 6[/tex]

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The equation of the given line, y = 3x - 2, is written in slope-intercept form:

... y = mx + b

where m represents the slope and b is the y-intercept.

Matching the form to the given equation, you see m = 3, and b = -2. The slope of the given line is 3.

The slope of a line perpendicular to it will be the negative reciprocal of this value

... slope of perpendicular line = -1/m = -1/3

For some new value of b, the equation of the perpendicular line can be written

... y = (-1/3)x + b

Filling in the values of the point coordinates, we can find the appropriate value of b.

... 4 = (-1/3)(3) +b

... 4 = -1 + b . . . . . . . simplify

... 5 = b . . . . . . . . . . add 1

Then the equation you want is ...

... y = (-1/3)x + 5

We are given table

Month :         1     2        3         4         5

Shoppers:   50  250   1250   6250  3250

so, we have

first term =50

[tex]a_1=50[/tex]

Second term =250

[tex]a_2=250[/tex]

Third term =1250

[tex]a_3=1250[/tex]

[tex]a_4=6250[/tex]

[tex]a_5=31250[/tex]

now, we can find ratios

[tex]\frac{a_2}{a_1} =\frac{a_3}{a_2}=\frac{a_4}{a_3}=\frac{a_5}{a_4}=5[/tex]

we can see that all ratios are same and 5

so, this is exponential

so, option-D..........Answer

The table below shows the number of shoppers at Jacob's store over a period of five months:  

Month 1 2 3 4 5  

Shoppers 50 250 1,250 6,250 31,250  

Did the number of people at Jacob's store increase linearly or exponentially?

Answer:

D.Exponentially, because the table shows the number of shoppers increases by an equal factor for an equal increase in months

I believe you only need to know one angle.

For example, if you know angle 1, you can calculate angle 3. Angle 2 = angle 3 and angle 4 = angle 1.

Also, Angle 5= angle 1 and so on...

That would be four times 88 passengers:  352 passengers per day.

Answer: 352

Step-by-step explanation:

88x4

The answer is (-5,-6)

Answer:

Option D is correct.

(-5, -6)

Step-by-step explanation:

Ordered pair states that a pair of number that is locate a point on a coordinate plane i.,e (x, y)

Given the line: [tex]2x-3y = 8[/tex]              .....[1]

Option A:

(12, -73)

Substitute the value of x = 12 and y = -73 in [1] we have;

2(12) - 3(-73) = 8

24 + 219 = 8

243 = 8        False.

Similarly for;

Option B

(-2, 4)

2(-2) - 3(4) = 8

-4 -12 = 8

-20 = 8        False.

Option C

(2, 43)

2(2) - 3(43) = 8

4-129= 8

-125= 8        False.

Option D

(-5, -6)

2(-5) - 3(-6) = 8

-10 +18 = 8

8 = 8      True.

Therefore, only (-5, -6) ordered pair is on the line 2x-3y = 8

How does the $100 gift card affect the measure of center of the data?

It increases the mean value of the prizes.

It decreases the mean value of the prizes.

It increases the median value of the prizes.

It decreases the median value of the prizes.

A number and its absolute value are not equal when the number is less than zero. Since subtracting 2 makes the number less than zero, we know ...

... the number is a non-negative number less than 2. (0 ≤ n < 2)

(1)

since both equations express y in terms of x, equate the right sides

- 2x = - 4x + 10 ( subtract 4x from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

substitute x = 5 into y = - 2x → y = - 10

solution is : (x, y ) → (5, - 10 )

(2)

equate the right sides of both equations

3x = 2x - 7 ( subtract 2x from both sides )

x = - 7

substitute x = - 7 into y = 3x → y = - 21

solution is : (x, y) → (- 7, - 21)

(3)

substitute y = - 8 into the other equation

- 8 = 6x + 22 ( subtract 22 from both sides )

- 30 = 6x ( divide both sides by 6 )

x = - 5

solution is : (x, y ) → (- 5, - 8 )

SOH CAH TOA tells you ...

... Tan(θ) = Opposite/Adjacent

You have ...

... Tan(θ) = (3)/(4)

Matching parts of the two expressions, we see ...

... Adjacent = (4)

_____

In the context of this problem we might reasonably assume that the adjacent side length is 4 units. In any other context, the best we might say is that it is 4/3 times the length of the opposite side.

slope = - [tex]\frac{2}{3}[/tex]

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = - 12 into this form

subtract 2x from both sides

3y = - 2x - 12 ( divide all terms by 3 )

y = - [tex]\frac{2}{3}[/tex] x - 4 ← in slope- intercept form

with slope m = - [tex]\frac{2}{3}[/tex]

[tex]\text{The slope-intercept form:}\ y=mx+b\\m-slope,\ b-y-intercept\\\\2x+3y=-12\qquad|\text{subtract 2x from both sides}\\\\3y=-2x-12\qquad|\text{divide both sides by 3}\\\\y=-\dfrac{2}{3}x-4\\\\Answer:\ \boxed{m=-\dfrac{2}{3}}[/tex]

n = 28

to evaluate the expression, perform the multiplications before subtraction

( 5 × 28 ) - ( 3 × 4 ) = 140 - 12 = 128

Angle BEC is the unmarked angle in the middle of the figure. Its value is the difference between straight angle AED (180°) and the two marked angles, 57° and 33°. That difference is ...

... 180° - 57° -33° = 90°

∠BEC is a right angle.

Answer:

Right angle

Step-by-step explanation:

We are given that

Angle AEB=[tex]57^{\circ}[/tex]

Angle CED=[tex]33^{\circ}[/tex]

We have to find  the classification of angle BEC

We know linear sum =[tex]180^{\circ][/tex]

Angle AEB +Angle BEC+Angle CED=180

Substitute the values then we get

[tex]57+33+\angle BEC=180^{\circ}[/tex]

[tex]90+\angle BEC=180[/tex]

[tex]\angle BEC=180-90[/tex]

[tex]\angle BEC=90^{\circ}[/tex]

Hence, the angle BEC is right angle

As can be clearly seen from the graph provided, the line of the linear regression passes through the point (2006, 1200). Thus, we can easily say, using linear regression, to predict the number of reported robberies that occurred during 2006 will be 1200.

Therefore, out of the given options, Option B is the correct option.

________________________________________________________
                Linear Regression - Line of Best Fit Quick Check
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1. The city of Harmonville created a scatter plot to illustrate the number of robberies that have been reported there over the past several years. Use linear regression to predict the number of reported robberies that occurred during 2006.

Answer:
B. 1,200
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2. Find the equation of the line of best fit for the points (−4, 10), (−1, 5), (2, −1), (3, −6), and (5, −7).

Answer:
A. y = -2x + 2
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3. What is the significance of a correlation coefficient of -0.97?

Answer:
A. The points all lie very close to the line of best fir, and the line is decreasing.
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These are all 100% correct. You're Welcome!
________________________________________________________

Put your number into the half-angle formula and simplify.

[tex]\displaystyle\sin{\frac{\theta}{2}}=\pm\sqrt{\frac{1-\cos{\theta}}{2}}=\sqrt{\frac{1-\frac{1}{3}}{2}}\\\\=\sqrt{\frac{1}{3}}=\sqrt{\frac{3}{9}}\\\\=\frac{\sqrt{3}}{3}[/tex]

The appropriate selection is ...

[tex]A)\quad\dfrac{\sqrt{3}}{3}[/tex]

A=h/2(a+b) solver for h

2A=h(a+b)

2A/(a+b)=h   (Solution)

Answer: The equation is of line "b"

Step-by-step explanation:

First we find the slope of the given line by using slope intercept form.

Converting the equation into slope intercept form

[tex] 5y=-2x+10 [/tex]

Divide both side by 5 we get

[tex] y= \frac{-2}{5} x+ 2 [/tex]

On comparing with

[tex] y =mx+c [/tex]

We get slope [tex] m=\frac{-2}{5} [/tex]

as the slope of line is negative therefore the line will be either line "b" or line "d"

As line "b" pass from (0,2)

On putting point [tex] x=0 &y=2[/tex] in given equation we get

[tex] 2(0)+5(2)=0+10=10 [/tex]

Which is equal to RHS of the line

Therefore the given equation is of line "b"

Now putting point (0,-2)

We get [tex] 2(0)+5(-2)=-10 [/tex]

Which is not equal to RHS and therefore line "d" is not the required line

Therefore the given equation is of line "b"

Answer:

Step-by-step explanation:

Any equation with a product of variables, or with a variable in an exponent or denominator, is not a linear equation. Here, "product of variables" includes powers and roots—any expression with an exponent other than 1, or a total of exponents other than 1.

The equations x^2 + y = 4 and x/2 - y^3 = 1 are not linear equations because they contain terms with variables raised to powers other than one, whereas - x - y = 2 and x = 5 are linear.

The question involves identifying which equations from the given list are not linear equations. Linear equations are of the form y = mx + b, where m and b are constants. Non-linear equations can include terms with variables raised to powers other than one, variables in the denominator, or variables under a radical.

The given equations are - x - y = 2, x^2 + y = 4, x/2 - y^3 = 1, and x = 5. The second equation, x^2 + y = 4, is not linear because it has a term x squared. The third equation, x/2 - y^3 = 1, is also not linear due to the term y cubed. Both of these equations contain expressions that disqualify them from being linear, as linear equations cannot have variables with exponents other than one. Therefore, these two are examples of a non-linear system of equations.

On the other hand, the first equation - x-y = 2 and the fourth equation, x = 5 are both linear. The first is in the standard linear form after being rearranged, and the fourth represents a vertical line in the xy-plane, which is a special case of a linear equation.

To simplify the expression 12 - 3 * 12 * 10 * 120, follow the order of operations: Multiply 3 * 12, then 36 * 10, then 360 * 120, and finally subtract 12 from the result to get 43,188.

To simplify the expression 12 - 3 * 12 * 10 * 120, you need to follow the order of operations, which is Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

Multiply 3 * 12 = 36

Multiply 36 * 10 = 360

Multiply 360 * 120 = 43,200

Finally, subtract 12 from 43,200 to get 43,188.

1 and a half is the correct answer (1 1/2) for the first one, for the second one it is D, and for the third one it is A.

Let's add both of the fractions together. They at 2 slices of pumpkin pie, and 3 slices of pecan pie. The fractions of these is 2/8 and 3/8. Added together, this is 5/8, so I believe this is your answer.

For this one, we can simply multiply the total acres by the cost per acre. 1240*52 is 64,480, so your land is worth a total of $64,480.

For this question, all we need to do is multiply the number of gallons Shelly's car can hold by the price per gallon. 14*3.56 is 49.84, so she'll be spending $49.84 to fill up her tank.

It is 6561 because 3^12 is 531441 and 3^4 is 81 so when you divide you get 6561.

A. 12 sandwiches. He can buy 12 because 6*12=72. He already has the chips at 15.00. So 72+15=87. Close to the amount of $90.00

f(x)=4x^3 - 6x^2 + 2x - 5

f(-2)

Replace X with -2:

4(-2)^3 - 6(-2)^2 + 2(-2) - 5 =

Calulate the powers:

4(-8) - 6(4) +(-4) -5=

Multiply:

-32 - 24 -4 -5=

Subtract

-65

The lateral area of the prism is the area of the three rectangles in the middle of the net. (The two triangles are the bases of the prism, which don't count toward lateral area.) The total length of the three rectangular prism faces is (8 +15 +17) cm = 40 cm. The width of those rectangles is 11 cm. The lateral area will be the product of this length and width:

... lateral area = (40 cm)(11 cm) = 440 cm²

Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.

Explanation:

From the given information,

Initial population = 1000

Increasing rate or growth rate = 30% every hour.

No of population increase in every hour is,

[tex]1000\times \frac{30}{100} =1000\times 0.3[/tex]

Total population after h hours is,

[tex]1000(1+0.3)^h[/tex]

It is in the form of,

[tex]P(t)=P_0(t)(1+r)^t[/tex]

Where [tex]P_0(t)[/tex] is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex]  is the growth factor after time t.

In the above equation 1000 is the initial population and [tex](1+0.3)^h[/tex] is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.

Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.

Answer:

the answer should be A

Step-by-step explanation:

We are given that

point C lies on AB

Let's assume AC=x

we know that

CB=AB-AC

[tex]CB=30-x[/tex]

Point C is 1.5 times farther from point A than from point B

so, we get

[tex]\frac{AC}{CB} =1.5[/tex]

now, we can plug values

[tex]\frac{x}{30-x} =1.5[/tex]

now, we can solve for x

[tex]x=1.5\left(30-x\right)[/tex]

[tex]x=18[/tex]

so, we get

[tex]AC=18[/tex]

now, we can find CB

[tex]CB=30-18[/tex]

[tex]CB=12[/tex]

so, we get

[tex]AC=18[/tex]

[tex]CB=12[/tex]...............Answer

The sum of the given expressions will be 6x-18.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression is (2x−6)+4(x−3). The summation will be calculated as

Sum = (2x-6)+4(x-3)

Sum = (2x-6)+4x-12

Then we combine like terms.

Sum = (2x-6)+4x-12

Sum = 6x-6-12

Sum = 6x-18

Therefore, the sum of the given expressions will be 6x-18.

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ANSWER

The correct answer is B

EXPLANATION

The first function is

[tex]x^2-2x+y-3=0[/tex]

We make y the subject to obtain;

[tex]y=-x^2+2x+3[/tex]

Let us quickly write this in the vertex form.

[tex]y=-(x^2-2x)+3[/tex]

[tex]y=-(x^2-2x+(-1)^2)+3+(-1)^2[/tex]

[tex]y=-(x-1)^2+4[/tex]

Since the [tex]a[/tex] is negative, the graph opens up.

The vertex is at [tex](1,4)[/tex]

The y-intercept is [tex]-3[/tex]

The x-intercept is found by equating the function to zero.

[tex]-(x-1)^2+4=0[/tex]

[tex]\Rightarrow (x-1)^2=4[/tex]

[tex]\Rightarrow (x-1)=\pm 2[/tex]

[tex]\Rightarrow x=1 \pm2[/tex]

[tex]\Rightarrow x=-1,3[/tex]

With these information we can quickly sketch the graph as shown in the attachment(the red graph).

For the second function,

[tex]x^2+y=0[/tex]

we again make y the subject to obtain,

[tex]y=-x^2[/tex]

This is a basic quadratic function that can be graphed easily. Note that it is also a maximum graph.

From the graph the solution to the two functions is

[tex](-1.5,-2.25)[/tex]

Answer:

B.(–1.5, –2.25)

Step-by-step explanation: