Cosmic microwave background radiation is classified as a form of electromagnetic energy because it

Answer:

I think the answer is C

Explanation:

When you look at the table, two designs used a 9-volt battery, but the second design lifted more wait because the amount of wire they had wrapped around the magnetic core was more.

Group #2's electromagnet was stronger due to the use of a 9-volt battery, longer wire, and a double-nail core.

The strength of Group #2's electromagnet can be attributed to several aspects of their design:

By combining these aspects, Group #2 was able to create a stronger electromagnet compared to other groups.

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Answer:

[tex]s = 1.472\,m[/tex]

Explanation:

The heat require to melt the ice formed in the rear window is:

[tex]Q = m_{ice}\cdot L_{f}[/tex]

[tex]Q = \rho_{ice}\cdot V_{ice}\cdot L_{f}[/tex]

[tex]Q = \rho_{ice}\cdot A_{w}\cdot s \cdot L_{f}[/tex]

The heat transfer rate given by the defroster is:

[tex]\dot Q = \epsilon\cdot i[/tex]

But:

[tex]\epsilon \cdot i \cdot \Delta t = \rho_{ice}\cdot A_{w}\cdot s \cdot L_{f}[/tex]

The maximum thickness of ice that can be melt is:

[tex]s = \frac{\epsilon \cdot i \cdot \Delta t}{\rho_{ice}\cdot A_{w}\cdot L_{f}}[/tex]

[tex]s = \frac{(12\,V)\cdot (29\,A)\cdot (3.8\,min)\cdot (\frac{60\,s}{1\,min} )}{(917\,\frac{kg}{m^{3}} )\cdot (0.56\,m^{2})\cdot (105\,\frac{J}{kg} )}[/tex]

[tex]s = 1.472\,m[/tex]

Answer:

Max thickness; h = 4.61 x 10^(-4) m

Explanation:

We are given;

Current; I = 29A

Voltage; V = 12 V

Time; t = 3.8 minutes = 228 seconds

Density;ρ = 917 kg/m³

latent heat of fusion of water; L = 3.35 x 10^(5) J/kg

Area; A = 0.56 m²

We know that volume = Area x Height.

Thus, V = Ah and h = V/A

We also know that density is given by;

ρ = mass/volume = m/V

Amd V = m/ρ

Thus, h can be written as;

h = (m/ρ)/A - - - - - (eq1)

Now, we know that;

The specific latent heat (L) of a material is a measure of the heat energy (Q) per mass (m) released or absorbed during a phase change.

It is defined through the formula

Q = mL

Thus, m = Q/L

So, putting Q/L for m in eq 1,we have; h = (Q/Lρ)/A = Q/LρA

Now, power(P) is; Q/t where Q is energy dissipated and t is time.

Thus, P = Q/t and thus, Q = Pt

Thus, h = Pt/LρA - - - - (eq2)

We also know that Power = IV

Thus, power = 29 x 12 = 348 W

Thus, plugging in the relevant values into eq(2),we have;

h = (348 x 228)/(3.35 x 10^(5) x 917 x 0.56)

h = 79344/(1720.292 x 10^(5))

h = 4.61 x 10^(-4) m

Answer:

Explanation:

Incomplete question but for understanding.

We want to find the electrical force between two charges, then you can use the coulombs law which states that the force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of their distance apart,

So,

F = kq1•q2 / r²

Where k is a constant and it is given as

K = 8.99 × 10^9 Nm²/C²

q1 and q2 are the charges and in this question it is not given, so the question is incomplete. Let assume that,

q1 = - 1.609 × 10^-19 C electron

q2 = 1.609 × 10^-19 C proton

Since unlike charges attract, then it is force of attraction

Also, r is the distance apart and it is not given, let assume the distance between the two charges is 2 × 10^-5m

Then,

F = kq1•q2 / r²

F = 8.99 × 10^9 × 1.609 × 10^-19 × 1.609 × 10^-19 / (2 × 10^-5)²

F = 5.82 × 10^-19 N

Answer:

c –5.4 × 1010 N on edge

Explanation:

Answer:

F = 0.332 N in the east direction

Explanation:

Length, L = 7.7 cm = 7.7 * 0.01 = 0.077 m(along the north south)

Current, I = 3.45 A (northwards)

Magnetic field, B = 1.25 T (vertically upwards)

The magnitude of the force is given by, F = ILBsin90

F = 3.45 * 0.077 * 1.25 * 1

F = 0.332 N

The direction of the force is calculated using the Right Hand Thumb Rule:

It states that "Hold the wire carrying current in your right hand so that the thumb points along the wire in the direction of the current, then the fingers will encircle the wire in the direction of the lines of magnetic force."

Based on the Right Hand Thumb Rule, the magnetic force will act in the east direction

Answer:

According to me, v=w×f is the correct formula...

Explanation:

v=w×f :-

The velocity of a wave can be found by multiplying the wavelength of the wave by its frequency.

The velocity of a wave can be found by multiplying the wavelength of the wave by its frequency. The formula for wave speed is v = λf, where v is the velocity, λ is the wavelength, and f is the frequency. For example, if the wavelength of a wave is 2 meters and its frequency is 5 Hz, the velocity of the wave would be 10 m/s. It's important to note that the velocity of a wave is determined by the medium through which it is traveling and not by the amplitude of the wave.

This is an inelastic collision. The equation for an inelastic collision is: [tex]m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = (m_{1} + m_{2})v_{f}[/tex]

(110)(6) + (150)(-4) = (110 + 150)(vf)

660 - 600 = 260vf

60 = 260vf

vf = 0.2308 m/s

They will travel in the positive direction, right, and their combined velocity will be 0.2308 m/s.

Hope this helps!! :)

a) Constant

b) Constant

Explanation:

a)

We can answer this question by using the equivalent of Newton's second law of motion of rotational motion, which can be written as:

[tex]\tau_{net} = I \alpha[/tex] (1)

where

[tex]\tau_{net}[/tex] is the net torque acting on the object in rotation

I is the moment of inertia of the object

[tex]\alpha[/tex] is the angular acceleration

The angular acceleration is the rate of change of the angular velocity, so it can be written as

[tex]\alpha = \frac{\Delta \omega}{\Delta t}[/tex]

where

[tex]\Delta \omega[/tex] is the change in angular velocity

[tex]\Delta t[/tex] is the time interval

So we can rewrite eq.(1) as

[tex]\tau_{net}=I\frac{\Delta \omega}{\Delta t}[/tex]

In this problem, we are told that at a given instant, the object has an angular acceleration due to the presence of torques, so there is a non-zero change in angular velocity.

Then, additional torques are applied, so that the net torque suddenly equal to zero, so:

[tex]\tau_{net}=0[/tex]

From the previous equation, this implies that

[tex]\Delta \omega =0[/tex]

Which means that the angular velocity at that instant does not change anymore.

b)

In this second case instead, all the torques are suddenly removed.

This also means that the net torque becomes zero as well:

[tex]\tau_{net}=0[/tex]

Therefore, this means that

[tex]\Delta \omega =0[/tex]

So also in this case, there is no change in angular velocity: this means that the angular velocity of the object will remain constant.

So cases (a) and (b) are basically the same situation, as the net torque is zero in both cases, so the object acts in the same way.

Answer:

Its natural frequency

Explanation:

Resonance occurs when a force causes an object to vibrate. The object has a higher probability of doing so at a specific rate called the object's natural frequency or resonant.

The frequency is dependent on the size, shape, and composition and properties of the object involved.

Answer:

Resonance occurs when a force causes an object to vibrate at

its own natural frequency

Explanation:

What is resonance .

This is a phenomenon in which an external force or a vibrating system forces another system around it to vibrate with greater amplitude at a specified frequency of operation.

When an object is forced to vibrate at its natural frequency, resonance occurs. Sound can travel through solids, liquids, gases, and even a vacuum. In order for sound from a speaker to reach a listener, air near the speaker must travel to the listener

What is a forced vibration?

Forced vibration is a type of vibration in which a force is repeatedly applied to a mechanical system.

Forced vibration is when an alternating force or motion is applied to a mechanical system.

Answer:

The charged particle follows a spiral path in a magnetic field.

Explanation:

A charge immersed in a region with an electric field experiences a force that acts along the same direction of the electric field. In particular:

- The force has the same  direction as the electric field if the charge is positive

- The force has the opposite direction as the electric field if the charge is negative

Therefore, a charge moving in an electric field is accelerated along the direction of the electric field.

On the other hand, a charge in motion in a region with a magnetic field experiences a force that acts perpendicular to the direction of the field. This means that a charge in motion in a magnetic field will acquire a circular motion in the plane perpendicular to the direction of the magnetic field.

As a result, if the particle has also a original motion outside this plane, its final motion will consist of:

- A uniform motion along that direction, +

- A circular motion along the plane perpendicular to the field

So, the resultant motion of the particle will be a spiral path. So the correct answer is

The charged particle follows a spiral path in a magnetic field.

Final answer:

The motion of charged particles differs significantly in electric versus magnetic fields. In magnetic fields, particles exhibit circular or spiral motions, and in electric fields, the motion is linear. This difference allows for the clear distinction between the two types of fields based on the particle's path.

Explanation:

The motion of a charged particle can be a revealing indicator of the presence and type of field it is moving through. When examining the behavior of charged particles, we see distinct patterns emerge in magnetic and electric fields. For magnetic fields, the motion is characterized by circular or spiral paths due to the magnetic force acting perpendicular to the particle's velocity. This is starkly different in an electric field, where the charged particle tends to move in a linear path along the direction of the field.

Magnetic fields cause a charged particle to follow a circular or helical path, with the nature of this motion being dependent on the angle between the velocity of the particle and the magnetic field lines. Technologies such as cyclotrons and mass spectrometers exploit this principle, utilizing magnetic fields to guide charged particles along desired paths.

In contrast, in an electric field, charged particles move linearly, aligning with the electric field lines. This linear motion is a result of the electric force acting along the direction of the field, guiding the particles in a straightforward path. The distinction between these two types of motion provides a clear method for distinguishing between magnetic and electric fields based on the observed path of a charged particle.

Answer:

The angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .

Explanation:

Given :

Mass of pulley , m = 2 kg .

Radius of pulley , R = 0.1 m .

Angular velocity of pulley , [tex]\omega=2\ rad/s[/tex] .

We need to find the angular momentum

We know , angular momentum of a rigid body is given by :

[tex]L=I\omega[/tex]       ......( 1 )

Here , I is the angular momentum of cylindrical pulley and is given by :

[tex]I=\dfrac{MR^2}{2}\\\\I=\dfrac{2\times 0.1^2}{2}\\\\I=0.01\ kg \ m^2[/tex]

Putting value of I and [tex]\omega[/tex] in equation 1 .

We get :

[tex]L=0.01\times 2\ kg\ m^2\ rad /s\\\\L=0.02 \ kg\ m^2\ rad /s\\[/tex]

Therefore , the angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .

The angular momentum of the cylinder pulley can be determined by first calculating the moment of inertia using the mass and the radius of the pulley, and then substituting the obtained values and the given angular velocity into the formula for angular momentum. The calculated angular momentum for this cylinder pulley is 0.02 kg.m²/s.

The angular momentum of a rotating object, such as a cylinder pulley, is calculated by the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. The moment of inertia of a cylinder is I = 0.5mr², where m is the mass and r is the radius of the cylinder.

First, we calculate the moment of inertia for our cylinder pulley: I = 0.5 x 2 kg x (0.1 m)² = 0.01 kg.m². Now, we can determine the angular momentum: L = 0.01 kg.m² x 2 rad/s = 0.02 kg.m²/s.

Therefore, the angular momentum of a 2 kg cylinder pulley with radius 0.1 m rotating at a constant angular speed of 2 rad/s is 0.02 kg.m²/s.

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Answer:

radial artery and carotid artery

Explanation:

Answer:

[tex]5.38\cdot 10^5 V/m[/tex]

Explanation:

At first, the 6Li ions are accelerated by the potential difference, so their gain in kinetic energy is equal to the change in electric potential energy; so we can write:

[tex]q\Delta V=\frac{1}{2}mv^2[/tex]

where

[tex]q=+e=+1.6\cdot 10^{-19}C[/tex] is the charge of one 6Li ion

[tex]\Delta V=9.2 kV=9200 V[/tex] is the potential difference through which they are accelerated

[tex]m=9.99\cdot 10^{-27}kg[/tex] is the mass of each ion

v is the final speed reached by the ions

Solving for v, we find:

[tex]v=\sqrt{\frac{2q\Delta V}{m}}=\sqrt{\frac{2(1.6\cdot 10^{-19})(9200)}{9.99\cdot 10^{-27}}}=5.43\cdot 10^5 m/s[/tex]

After that, the ions pass into a region with a uniform magnetic field of strength

[tex]B=0.99 T[/tex]

The magnetic field exerts  a force perpendicular to the direction of motion of the ions, and this force is given by

[tex]F=qvB[/tex]

In order to make the ions passing through undeflected, there should be an electric force balancing this magnetic force. The electric force is given by

[tex]F=qE[/tex]

where E is the strength of the electric field.

Since the two forces must be balanced,

[tex]qE=qvB[/tex]

From which we get

[tex]E=vB[/tex]

So the strength of the electric field must be

[tex]E=(5.43\cdot 10^5)(0.99)=5.38\cdot 10^5 V/m[/tex]

Answer:

The noun agony means acute pain — either mental or physical, but people often use the word hyperbolically: "This paper cut is agony." The noun agony is also used in the common phrase "the thrill of victory and the agony of defeat," which has been the tag-line of ABC's Wide World of Sports for decades.

Explanation:

Answer:

400k

Explanation:

Answer:

Stress is the force applied to an object. In geology, stress is the force per unit area that is placed on a rock. Four types of stresses act on materials.

A deeply buried rock is pushed down by the weight of all the material above it. Since the rock cannot move, it cannot deform. This is called confining stress.

Compression squeezes rocks together, causing rocks to fold or fracture (break) (Figure below). Compression is the most common stress at convergent plate boundaries.

Explanation:

Answer:

[tex]2.9\cdot 10^{-7} J[/tex]

Explanation:

The energy density associated to a magnetic field is:

[tex]u=\frac{B^2}{2\mu_0}[/tex] (1)

where

B is the strength of the magnetic field

[tex]\mu_0[/tex] is the vacuum permeability

The magnetic field produced by a current-carrying wire is

[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]

where

I is the current in the wire

r is the distance from the wire at which the field is calculated

Substituting into (1),

[tex]u=\frac{\mu_0 I^2}{8\pi^2 r^2}[/tex] (2)

Since this is the energy density, the total energy stored in a certain element of volume [tex]dV[/tex] will be

[tex]U=u\cdot dV=\frac{\mu_0I^2}{8\pi^2 r^2}dV[/tex] (3)

Here the field strength changes as we move farther from the wire radially, so we can write dV as

[tex]dV=2\pi h r dr[/tex]

where

h is the height of the cylinder

r is the distance from the wire

So eq(3) becomes:

[tex]dU=\frac{\mu_0I^2}{8\pi^2 r^2} \cdot 2 \pi h r dr = \frac{\mu_0 I^2 h}{4\pi}\frac{1}{r}dr[/tex]

Now we have to integrate this expression to find the total energy stored in the cylindrical volume. We have:

h = 50 mm = 0.050 m is the height of the cylinder

I = 4.9 A is the current in the wire

[tex]b=2.1 mm = 0.0021 m[/tex] is the internal radius of the cylinder (the radius of the wire)

[tex]a=24 mm=0.024 m[/tex] is the external radius of the cylinder

So,

[tex]U=\int\limits^a_b {dU} =\frac{\mu_0 I^2 h}{4\pi} \int\limits^{0.024}_{0.0021} \frac{1}{r}dr = \frac{\mu_0 I^2 h}{4\pi} [ln(a)-ln(b)]=\\=\frac{(4\pi \cdot 10^{-7})(4.9)^2(0.050)}{4\pi}[ln(0.024)-ln(0.0021)]=2.9\cdot 10^{-7} J[/tex]

Answer:

varn=n1+1ehvkT–1

Explanation:

This is Einstein's equation.

Answer:

speed, direction, or both

Explanation:

If forces acting on an object are unbalanced, the object could experience a change in speed, direction, or both.

When the forces operating on an item are imbalanced, it signifies that the object's net force is not zero.

This causes the item to accelerate in the direction of the net force. As a result, depending on the direction of the net force, the object's speed may change, causing it to either accelerate or decelerate.

Due to the uneven forces, the item may potentially change its direction of travel.

The magnitude and direction of the unbalanced forces acting on the item will determine the degree of the changes in speed and direction.

Thus, unbalanced forces can thus induce a range of changes, including changes in speed, direction, or both.

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Answer:

Both A and B

Explanation:

Normally, the direct current through motor is controlled and directed by the control switches. Also, most of the available power windows and power locks in the market utilize the reversible permanent and in-built circuit breakers. Therefore, both technicians are correct.

Answer:

Explanation:

Givent that,

The required force to pull the peddle is

F = 14N,

The peddle has a mass of

m = 0.08kg

To a distance of 0.1m

d = 0.1m

Using conservation of energy

The workdone by pulling the peddle to a certain distance is equal to the kinectic energy of the peddle

Work done = K.E

F × d = ½ mv²

14 × 0.1 = ½ × 0.08 × v²

1.4 = 0.04 v²

v² = 1.4 / 0.04

v² = 35

v = √35

v = 5.92 m/s

The velocity of the peddle is 5.92 m/s

Answer:

Explanation:

Acceleration =  a change in velocity / a change in time

Acceleration = ( final velocity - initial velocity) / a change in time

Acceleration = (6m/s - 35 m/s ) / 5 s

                     = (-29 m/s) /( 5 s)

                     = - 5.8 m/s^^2  

Remember Significant Figures  

- 6 m/s^2

P.S I have no idea why the answers say m/s because acceleration is m/s^2.

:)

Answer:

Reflection

Explanation:

The wave phenomenon that allows the DVD player to work is REFLECTION.

Reflection is defined as the repropagation of incident light striking a plane surface.

The light ray striking the surface is incident ray while the repropagated light ray is the reflected ray. The DVD was able to play because the laser light that hits the surface of the disk was able to reflect back and returns to the detector. The detector senses the light and cause the DVD to play. If the laser light didn't reflect, assuming it was absorbed by the surface of the disk, the detector wouldn't have detected the light and the DVD wouldn't have played.

Answer:

C. Reflection

Explanation:

Edge 2020

Answer:

[tex]27.164 lb/in^2[/tex]

Explanation:

We are given that

Gauge pressure at 3.4 degree Celsius,P=[tex]24lb/in^2[/tex]

We have to find the gauge pressure in tire when the temperature rises to 26 degree Celsius.

Atmospheric pressure=[tex]14.7lb/in^2[/tex]

[tex]P_1=P+14.7=24+14.7=38.7lb/in^2[/tex]

K=273+Degree Celsius

[tex]T_1=3.4+273=276.4 K[/tex]

[tex]T_2=26+273=299K[/tex]

[tex]P_2=\frac{P_1T_2}{T_1}[/tex]

[tex]P_2=\frac{38.7\times 299}{276.4}[/tex]

[tex]P_2=41.864 lb/in^2[/tex]

Gauge pressure in tire when the temperature rises to 26 degree Celsius.=[tex]41.864-14.7=27.164lb/in^2[/tex]

Answer:

27.16 lb/in²

Explanation:

initial temperature, T1 = 3.4 °C = 276.4 K

initial gauge pressure, P1 = 24 lb/in²

atmospheric pressure, Po = 14.7 lb/in²

initial absolute pressure, P1' = Po + P1 = 14.7 + 24 = 38.7 lb/in²

final temperature, T2 = 26 °C = 299 K

Let the final gauge pressure is P2.

use the ideal gas equation and the volume is constant.

[tex]\frac{P_{1}'}{T_{1}}=\frac{P_{2}'}{T_{2}}[/tex]

[tex]\frac{38.7}{276.4}=\frac{P_{2}'}{299}[/tex]

P2' = 41.86 lb/in²

Now the gauge pressure, P2 = P2' - Po = 41.86 - 14.7 = 27.16 lb/in²

Thus, the new gauge pressure is 27.16 lb/in².

Answer:

its the 3rd one with the hand and the beam on light shining through it

Explanation:

Answer:

3rd choice

Explanation:

glass of water is refraction

cat/mirror is reflection

an example of diffraction is if you have a screen w/ a slit in it and you shined a light on one side of it, so based on that, I would go with the 3rd choice with the hand and the light coming through between the fingers

Answer:

C. are often metals

and

D. have high conductivity

Answer:

19.2J

Explanation:

For a string-mass system the elastic potential energy is given by:

[tex]U=\frac{1}{2}kx^2[/tex]

k: spring's constant = 240N/m

x: compression = 0.40m

by replacing the values of k and x you obtain:

[tex]U=\frac{1}{2}(240N/m)(0.40m)^2=19.2J[/tex]

hence, the elastic potential energy is 19.2J

Answer:

19.2j I took the assessment and got it right :)

Explanation:

Answer:it the tendon

Explanation:

Answer: The answer would be bone... I mean organ

Explanation:

Look in the defenition In edunuity

Answer:

The length of the antenna would be L = 1056 km

Explanation:

Given:-

- The frequency of ELF, f = 71 Hz

- The speed of EM wave, c = 3.00 *10^8 m/s

Find:-

Calculate the length of a quarter-wavelength antenna for a transmitter generating ELF waves

Solution:-

- We will first determine the wavelength (λ) of the ELF waves with frequency (f) generated by the transmitter. The relationship that holds true for all types of EM waves is:

                            λ = c / f

                            λ = (3.00*10^8 m/s) / ( 71 Hz )

                            λ = 4225352.11267 m

- The antenna of the transmitter is to be designed such that its length (L) is 1/4-wavelength of ELF generated. So:

                            L = 0.25*λ

                            L = 0.25*4225352.11267

                            L = 1056 km          

Answer:

Electric power is the rate at which work is done or energy is transformed in an electrical circuit.

P = W/t

Explanation

Where  P is Power,

             W is work

             t = Time passed