Dan is calculating the volume of two cylinders. Cylinder A has a radius of 2 feet and a height of 4 feet. Cylinder B also has a height of 4 feet, but the radius has been doubled. Which statement best describes the relationship between the volumes of the two cylinders? A) When the radius is doubled, the resulting volume is half the original volume. B) When the radius is doubled, the resulting volume is 2 times the original volume. C) When the radius is doubled, the resulting volume is 4 times the original volume. D) When the radius is doubled, the resulting volume is 8 times the original volume.

Answers

Answer 1
we have that
Cylinder A has a radius of 2 feet and a height of 4 feet
so
volume of the cylinder A=pi*r²*h-----> pi*2²*4-----> 16*pi ft³

Cylinder B also has a height of 4 feet, but the radius has been doubled
h=4 ft
r=2*2---> 4 ft
so
volume of the cylinder B=pi*r²*h-----> pi*4²*4-----> 64*pi ft³

volume cylinder B/volume cylinder A=64*pi/(16*pi)----> 4

therefore 
the answer is the option
C) When the radius is doubled, the resulting volume is 4 times the original volume.


Related Questions

PLEASE PLEASE HELP ASAP

Answers

We will use the concept of similar triangles to solve this problem. We will use two triangles: ΔABC and ΔCBD. Next we will establish relations between them. Given that:

BC = m
AC = 18
AD = 11
DC = 7

We will name the some angles as follows:

∠ACB = ∠DCB = β

So the following relations from the triangles are equal to:

(1) [tex]cos( \beta )= \frac{7}{m}[/tex]
(2) [tex]cos( \beta )= \frac{m}{18}[/tex]

So, matching these equations:

[tex] \frac{7}{m}= \frac{m}{18} [/tex]

Solving for m:

[tex]m^{2} = 18x7 = 126[/tex]
∴ [tex] m = \sqrt{126}[/tex]

Mr. Morris left work at 5:53 P.M. and drove 47 minutes to his home. What time did he arrive?

Answers

Hi there!

First, we know that the remaining time until 6 PM is 7 minutes. So, we can subtract 7 minutes from 47 and now we have 40 minutes left to add and it is 6 PM. Next, since 40 is not more than 60 minutes, we'll add 40 minutes to 6 PM. This leaves us with the time 6:40.

ANSWER:
He arrived at 6:40


Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

Answer:

6:40

Step-by-step explanation:

BRAINLIEST!!!

Which statement about a dilation with a scale factor of 3 is true?

Answers

The picture shows a scale factor of 3/2, not 3. The only equation that makes any sense is the first one:
  3/2 = 6/4

_____
The others are just plain false.
Answer:

The statement which is true about the dilation is:

                        [tex]\dfrac{3}{2}=\dfrac{6}{4}[/tex]    

Step-by-step explanation:

We know that the dilation transformation changes the size of the original figure but the shape is preserved.

The dilation transformation either reduces the size of the original figure i.e. the scale factor is less than 1 or enlarges the size of the original figure i.e. the scale factor is greater than 1.

The ratio of the corresponding sides of the two figure are equal.

i.e.

                 [tex]\dfrac{3}{2}=\dfrac{6}{4}[/tex]

What is the change in temperature between -8°c and 3°c ?

Answers

11 degrees Celsius. Because -8 to 0 is 8. Then 0 to 3 is 3. So if you add the 3 and the 8 together, you get your answer 11 degrees. So 11 degrees Celsius is your change.

What is the null hypothesis if we want to test the hypothesis that the mean score on campus 1 is higher than on campus 2? h0: µ1 = 0?

Answers

μ1 <= μ2
____________

No, the null hypothesis will be, there is no difference between the mean scores of campus 1 and campus 2.

Therefore, the null hypothesis would be:

H₀: µ₁ - µ₂ = 0

where µ₁ is the population mean score of campus 1 and µ₂ is the population mean score of campus 2.

What is mean by Subtraction?

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Now, We test this null hypothesis against the alternative hypothesis that the mean score on campus 1 is higher than on campus 2:

Hₐ: µ₁ > µ₂

Hence, if there is sufficient evidence to reject the null hypothesis and conclude that there is a significant difference between the mean scores of campus 1 and campus 2.

Thus, No, the null hypothesis will be, there is no difference between the mean scores of campus 1 and campus 2.

Therefore, the null hypothesis would be:

H₀: µ₁ - µ₂ = 0

where µ₁ is the population mean score of campus 1 and µ₂ is the population mean score of campus 2.

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The exponential function y = 2(3)x grows by a factor of 9 between x = 1 and x = 3. What factor does it grow by between x = 5 and x = 7?

Answers

Given the function y=2(3)^x
the growth factor between x=1 and x=3 is given by:
[2(3)^3]/[2(3)^1]
=54/6
=9
thus the growth factor between x=5 and x=7 will be as follows:
[2(3)^7]/[2(3)^5]
simplifying the above we get:
=[3^7]/[3^5]
=3^(7-5)
=3^2
=9

Answer:

9

Step-by-step explanation:

A cirlce with a radius of 8 cm rotates 30 degrees in one second. Determine the angle of rotation in radians.
Angle:___ w:___ v:___

Answers

same as before, since 180° is π, how much is 30° in radians?

[tex]\bf \begin{array}{ccll} de grees&radians\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 180&\pi \\\\ 30&x \end{array}\implies \cfrac{180}{30}=\cfrac{\pi }{x}\implies x=\cfrac{30\pi }{180}\implies x=\cfrac{\pi }{6}\\\\ -------------------------------\\\\ \stackrel{angular~velocity}{w}=\cfrac{\stackrel{central~angle}{\frac{\pi }{6}}}{\stackrel{time}{1~s}}\implies w=\cfrac{\pi }{6}~\frac{radians}{seconds}[/tex]

[tex]\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=8\\ \theta =\frac{\pi }{6} \end{cases}\implies s=8\cdot \cfrac{\pi }{6}\implies s=\cfrac{4\pi }{3} \\\\\\ \stackrel{linear~velocity}{v}=\cfrac{\stackrel{arc's~length}{\frac{4\pi }{3}}}{\stackrel{time}{1~s}}\implies v=\cfrac{4\pi }{3}~\frac{cm}{seconds}[/tex]

Yanis fires pottery in a kiln. He decides to measure the rate of change of temperature of the pottery over time. What would be an appropriate unit for Yanis's purpose?

Answers

degrees celcius/ hour

Answer with explanation:

Pottery is on a Kiln.

Unit of temperature can be Kelvin(°K) or Degree Celsius(°C) or Fahrenheit(°F).

Unit of time is second, minute and hour.

Rate of change of temperature of the pottery over time can be written as

     [tex]1.=\frac{\text{Degree Celsius}}{\text{Second}}\\\\2.=\frac{\text{Degree Celsius}}{\text{Minute}}[/tex]

Internationally , Kelvin is used as S.I unit of Temperature.

So,Yanin can use

  [tex]1.=\frac{\text{Kelvin}}{\text{Second}}\\\\2.=\frac{\text{Kelvin}}{\text{Minute}}[/tex]

 as Rate of change of temperature of the pottery over time.

Q10 Q6.) Find a set of parametric equations for the line that passes through the given points

Answers

Hello there!


See picture below for the answer!

The correct answer is option A

Unsaved If you are studying the effects of UV rays on eyesight and you group 10 people together and make them wear sunglasses for 10 weeks and see if their eyesight is affected and then take another group and do not give them sunglasses and test their vision after 10 weeks, what is the treatment ? note this is not an ethical study.

sunglasses.
10 weeks.
eyesight.
vision test.

Answers

In a statistical experiment, a treatment is the factor or the independent variable which is under the control of experimenter. Experimenter can change the conditions of this factor according to his will and according to needs of experiment.

In the given example, the experimenter make 10 people wear sunglasses and check their eyesight after 10 weeks. To another group he does not give sunglasses and check their eyesight after 10 weeks.

So, sunglasses are such a factor which are under the control of experimenter. So the treatment in this case is sunglasses.

Hence 1st option is the correct answer.

Answer:

Sunglasses

Step-by-step explanation:

Experts/ace/geniuses helppp asapp

Answers

The slope is the ratio of the change in y to the change in x. If the line is horizontal, the change in y is zero and the slope is zero (last choice).

The table shows the number of boys and girls that have black, blonde, brown, or red hair color. What is the probability that a student is a boy with red hair? (round to nearest hundredth)

Hair Color Boys Girls
Black 4 5
Blonde 4 6
Brown 10 8
Red 2 1

Answers

2 of the 40 students are boys with red hair. If one is chosen at random, ...
  the probability that the student is a boy with red hair is 2/40 = 0.05.

Answer:

0.05

Step-by-step explanation:

Given :

Hair Color Boys Girls

Black          4                 5

Blonde          4                  6

Brown          10                 8

Red                  2                   1

Solution :

Since ware required to find the probability that a student is a boy with red hair.

Total no. of boys with red hair = 2

Total no. of students = 4+4+10+2+5+6+8+1=40

Thus the probability  that a student is a boy with red hair = [tex]\frac{\text{No. of boys with red hair }}{\text{total no. of students }}[/tex]

⇒[tex]\frac{2}{40}[/tex]

⇒[tex]\frac{1}{20}[/tex]

⇒[tex]0.05[/tex]

Hence the probability that a student is a boy with red hair is 0.05

help me out with this

Answers

The process is similar to (and easier* than) adding three 4-digit numbers. Add the numbers in each column.

The sum is ...
  (2+1-3)x³ +(-4+6+2)x² +(6-8-4)x +(-3+12-7)
  = 0x³ +4x² -6x +2

The sum is 4x² -6x +2


_____
* The process is easier because there are no "carry" operations from one column to another as there may be when adding multi-digit numbers.

Graph the parabola 3x^2+6x-24

Answers

We have the following function:
 F (x) = 3x ^ 2 + 6x-24
 We observe that it is a quadratic equation.
 The graph is therefore a parabola.
 Its cut points are:
 (-4, 0)
 (2, 0)
 Answer:
 
See attached image to see graph of the function

I had 42 ounces of rice. On Monday I bought 58 more ounces of rice. Then I divided all the rice into 10 equal-sized portions for dinner with friends. How many ounces of rice were in each portion? ounces

Answers

First, I had 42 ounces of rice. Then, I got 58 ounces more.
---------------------------↑-----------------------------------
                               42 + 58
                                  100

                         100 ÷ 10 = 10

                      Answer = 10 ounces 

Hope this helped☺☺
Final answer:

The student initially had 42 ounces of rice, bought 58 more for a total of 100 ounces. These were divided into 10 portions, so each portion will contain 10 ounces of rice.

Explanation:

This problem is a basic arithmetic question. The student starts with 42 ounces of rice and then adds 58 more ounces, for a total of 100 ounces. She then divides these 100 ounces into 10 equal portions. The key here is to understand the concept of division, which basically means splitting up a total amount (100 ounces) evenly into a certain number of parts (10 portions). To do this, simply use the operation of division: 100 divided by 10 equals 10. Thus, each portion will contain 10 ounces of rice.

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what is The desired outcomes of a specified event.

Answers

What do you mean by this

Answer:

Favorable Outcomes

Step-by-step explanation:

A drink contains 20% cranberry juice and the rest is apple juice. What is the ratio of cranberry juice to apple juice? A.1:20 B.1:4 C.4:1 D.20:1

Answers

20% of the juice is cranberry
80% of the juice is apple
Our ratio would be 20:80
We can simplify it and it will become
1:4

So your answer would be B. 1:4

I hope this helps :)

Write an equation of the line with the given​ slope, m, and​ y-intercept (0,b) m=-3/5 b=7/10

Answers

y=-3/5x+7/10 is the correct answer. y=mx+b
Final answer:

The equation of the line with a slope of -3/5 and a y-intercept of 7/10 is y = (-3/5)x + (7/10).

Explanation:

To write an equation of a line with a given slope (m) and y-intercept (0,b), we use the slope-intercept form of a linear equation which is y = mx + b. In this case, the slope is -3/5 and the y-intercept is 7/10.

Substituting these values into the slope-intercept formula, the equation of the line is y = (-3/5)x + (7/10).

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What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

Answers

[tex]2x^{2} +16x - 9 = 0 2(x + 4)^{2} - 41 = 0 (x + 4)^{2} = \frac{41}{2} x + 4 = \pm \sqrt{\frac{41}{2}} x = -4 \pm \sqrt{\frac{41}{2}}[/tex]

Answer:

The zeros to the quadratic equation are:

[tex]x= -4+\sqrt{\frac{41}{2}}\\\\x= -4-\sqrt{\frac{41}{2}}[/tex]

Step-by-step explanation:

A quadratic function is one of the form [tex]f(x) = ax^2 + bx + c[/tex], where a, b, and c are numbers with a not equal to zero.

The zeros of a quadratic function are the two values of x when [tex]f(x) = 0[/tex] or [tex]ax^2 + bx +c = 0[/tex].

To find the zeros of the quadratic function [tex]f(x)= 2x^2 + 16x -9[/tex] , we set [tex]f(x) = 0[/tex], and solve the equation.

[tex]2x^2+16x\:-9=0[/tex]

[tex]\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]\mathrm{For\:}\quad a=2,\:b=16,\:c=-9:\quad x_{1,\:2}=\frac{-16\pm \sqrt{16^2-4\cdot \:2\left(-9\right)}}{2\cdot \:2}\\\\x=\frac{-16+\sqrt{16^2-4\cdot \:2\left(-9\right)}}{2\cdot \:2}= -4+\sqrt{\frac{41}{2}}\\\\x=\frac{-16-\sqrt{16^2-4\cdot \:2\left(-9\right)}}{2\cdot \:2}= -4-\sqrt{\frac{41}{2}}[/tex]

If you have 2500 to invest at 6 interest compounded quarterly. For how many years will the money need to be invested for that amount to triple?

Answers

For this case we have the following equation:
 P (t) = P * (1 + r / n) ^ (n * t)
 Where,
 P: initial investment
 r: interest rate
 n: periods
 Substituting values:
 3 * 2500 = 2500 * (1 + 0.06 / 4) ^ (4 * t)
 Rewriting:
 3 = (1,015) ^ (4 * t)
 Clearing t:
 log1.015 (3) = log1.015 ((1.015) ^ (4 * t))
 4 * t = log1.015 (3)
 t = (1/4) * log1.015 (3)
 t = 18.45 years
 Answer:
 
the money will need to be invested 18.45 years for that amount to triple

please help with this word problem

Answers

Comment
There is no exact answer to this. It will have to shown in terms of the width. Also we need to use the Pythagorean Formula

Givens
L = 10 * W
W = W

Formula
L^2 + W^2 = C^2

Solution
(10W)^2 + (W^2) = C^2
C^2 = 100W^2 +W^2
C^2 = 101W^2                   Now take the square root.
C = sqrt(101W^2)
C=  W*sqrt(101)                <<<<< Answer. I think this is what they mean

Experts/ace/geniuses helppp asapp

Answers

The answer is D. The bottom most choice.
The answer to it is D.-4000m+39000
To check you just sub in the numbers for m
ex. -4000(2)+39000=31000
-4000(3)+39000=27000
-4000(4)+39000=23000

For a test of upper h 0h0​: pequals=​0.50, the sample proportion is 0.470.47 based on a sample size of 100. use this information to complete parts ​(a) through ​(c) below.

Answers

(a) Calculate the standard error of the sample proportion.

(b) Determine the z-score for the sample proportion.

(c) Find the p-value for the given z-score.

To find the standard error, z-score, and P-value for the given test, follow these steps:

(a) Calculate the standard error using the formula:

[tex]\[ \text{Standard error} = \sqrt{\frac{p \times (1 - p)}{n}} \][/tex]

Given [tex]\( p = 0.50 \) (the population proportion) and \( n = 100 \) (the sample size), substitute these values into the formula:[/tex]

[tex]\[ \text{Standard error} = \sqrt{\frac{0.50 \times (1 - 0.50)}{100}} \]\[ = \sqrt{\frac{0.50 \times 0.50}{100}} \]\[ = \sqrt{\frac{0.25}{100}} \]\[ = \sqrt{0.0025} \]\[ = 0.05 \][/tex]

(b) Calculate the z-score using the formula:

[tex]\[ \text{z-score} = \frac{\text{sample proportion} - \text{population proportion}}{\text{standard error}} \]Given that the sample proportion is \( 0.47 \), substitute this value along with the previously calculated standard error into the formula:\[ \text{z-score} = \frac{0.47 - 0.50}{0.05} \]\[ = \frac{-0.03}{0.05} \]\[ = -0.6 \][/tex]

(c) Finally, find the P-value using a z-table or statistical software corresponding to the calculated z-score. The P-value represents the probability of observing a sample proportion at least as extreme as the one obtained, assuming the null hypothesis is true.

On Sunday, 370 people bought tickets to the county fair. Tickets cost $7 for adults and $3 for children. The total revenue from ticket sales on Sunday was $1750. The system of equations below represents the number of people and total sales for the county fair on Sunday, where x represents the number of child tickets and y represents the number of adult tickets.

Answers

Number of child tickets: x
Number of adult tickets: y

1) x+y=370
2) 3x+7y=1750

Using the method of substitution
a) Isolating y in the first equation:
1) x+y=370→x+y-x=370-x→y=370-x

b) Replacing y=370-x in the second equation:
2) 3x+7y=1750→3x+7(370-x)=1750

c) Solving for x: Distributive property:
3x+7(370)-7x=1750
3x+2590-7x=1750

Adding similar terms:
-4x+2590=1750

-4x+2590-2590=1750-2590
-4x=-840

Dividing both sides of the equation by -4:
-4x/(-4)=-840/(-4)
x=210

Replacing x=210 in the first equation:
1) y=370-x→y=370-210→y=160

Answer:
The number of child tickets was 210 and
the number of adult tickets was 160

A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. Part B: Solve 3x^2 + 5x − 8 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Answers

These are two questions and two answers:

Question 1:

A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work.

Answer: The negative value of the radicand means that the equation does not have real solutions.

Explanation:

1) With radicand the statement means the disciminant of the quadratic function.

2) The discriminant is: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation: ax² + bx + c

3) Then, for 3x² - 15x + 20, a = 3, b = - 15, and c = 20

and the discriminant (radicand) is: (-15)² - 4(3)(20) = 225 - 240 = - 15.

4) The negative value of the radicand means that the equation does not have real solutions.

Question 2:

Part B: Solve 3x^2 + 5x − 8 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Answer:
two solutions x = 1 and x = - 8/3x

Explanation:

1) I choose factoring (you may use the quadratic formula if you prefer)

2) Factoring

Given: 3x² + 5x − 8 = 0

Make 5x = 8x - 3x: 3x² + 8x - 3x - 8 = 0

Group: (3x² - 3x) + (8x - 8) = 0

Common factors for each group: 3x(x -1) + 8(x - 1) = 0

Coomon factor x - 1: (x - 1) (3x + 8) = 0

The two solutions are for each factor equal to zero:

x - 1 = 0 ⇒ x = 1
3x + 8 = 0 ⇒ x = -8/3

Those are the two solutions. x = 1 and x = - 8/3

The quadratic equation 3x² − 15x + 20 = 0 has a radicand of -15, indicating no real solutions. The equation 3x² + 5x − 8 = 0 can be solved using the quadratic formula, yielding solutions of x = 1 and x = -8/3.

For the quadratic equation 3x² − 15x + 20 = 0, the radicand can be found as part of the quadratic formula process, which is b^2 - 4ac. Here, a=3, b= -15, and c=20. Substituting these values in, we get the radicand as (-15)² - 4(3)(20) = 225 - 240 = -15. Since the radicand is negative, this indicates that the equation has no real solutions; the solutions are complex numbers.

To solve the equation 3x² + 5x − 8 = 0, we will use the quadratic formula, x = −b ± √(b^2 - 4ac) / (2a), since we have a quadratic with a, b, and c all non-zero. Substituting a=3, b=5, and c= -8, we find the radicand to be (5)² - 4(3)(-8) = 25 + 96 = 121. Calculating further, x = (-5 ± √121) / 6, which simplifies to x = (-5 ± 11) / 6. Thus, we have two solutions: x = (11 - 5) / 6 = 1 and x = (-5 - 11) / 6 = -16/6 = -8/3.

The period if a function is 4pi
How many cycles of the function occur in a horizontal length of 12pi?
(answer was 3)
QUESTION: Which type of transformation of the parent function would be shown by the graph?

Answers

The answer is horizontal stretch

Answer:

She's right the answer is a horizontal stretch.

Determine the number of possible solutions for a triangle with A= 30 a=20 and b=16

Answers

There is a unique solution for a triangle with A=30 degrees, a=20 units, and b=16 units. By using the Law of Sines, sin(B) is computed as 0.4. Since there is no obtuse angle with the same sine, there is only one possible angle B, leading to one possible triangle.

To determine the number of possible solutions for a triangle with A=30 degrees, a=20 units (side opposite angle A), and b=16 units (another side), we need to apply the Law of Sines and explore the possible cases. According to the Law of Sines:

a/sin(A) = b/sin(B)

For the given values, we have:

20/sin(30 degrees) = 16/sin(B)

Calculating sin(B) gives us:

sin(B) = 16 * sin(30 degrees) / 20 = 8/20 = 0.4

Now, if sin(B) is less than 1, which it is in our case, there are two possible scenarios:

B is acute: There will be one solution for B, meaning B could be angle whose sine is 0.4.

B is obtuse: We must also check if there is a possible obtuse angle that also has a sine of 0.4. However, since the sine function is positive and less than or equal to 1 for angles between 0 and 180 degrees and it's symmetric with respect to 90 degrees, there can't be an obtuse angle with the same sine value as an acute angle.

Therefore, we only have one possible angle B, which implies we have a unique solution for the triangle.

Additionally, we should check whether side b is larger than the altitude from A; otherwise, there would be no solution for the triangle. To do this, we can use the extended Law of Sines to calculate the diameter (D) of the triangle's circumcircle:

D = a / sin(A)

And thus, the altitude (h) from A would be:

h = D * sin(B)

If b > h, we have a valid triangle and a unique solution.

There is exactly one possible solution for a triangle with the given side lengths a = 20, b = 16, and angle A = 30°.

To determine the number of possible solutions for a triangle given the side lengths a, b, and the angle A, we can use the Law of Sines. The Law of Sines states:

[tex]\[\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}\][/tex]

where:

a, b, c - side lengths of the triangle

A, B, C - angles opposite to the respective sides

Given:

A = 30°

a = 20

b = 16

We can find the angle B using the Law of Sines:

[tex]\[\frac{a}{\sin(A)} = \frac{b}{\sin(B)}\][/tex]

[tex]\[\frac{20}{\sin(30^\circ)} = \frac{16}{\sin(B)}\][/tex]

sin (B) = [tex]\frac{16 \times \sin(30^\circ)}{20}[/tex]

         = [tex]\frac{16 \times 0.5}{20}[/tex]sin

         = [tex]\frac{8}{20}[/tex]

         = 0.4

To find the angle B, we take the inverse sine:

B = [tex]\sin^{-1}(0.4)[/tex]

B = 23.58°

Now, we can find angle C since the sum of angles in a triangle is 180°:

C = 180° - A - B

C = 180° - 30° - 23.58°

C = 126.42°

Now, let's check if the side lengths satisfy the triangle inequality theorem:

a + b > c

20 + 16 >

36 > c

Since 36 is greater than c, the triangle inequality theorem is satisfied.

So, there is exactly one possible solution for a triangle with the given side lengths a = 20, b = 16, and angle A = 30°.

Two events are independent when the following is true:

a. the outcome of one event determines the outcome of the other event

b. there is no correlation between the two events

c. the outcome of one event does NOT determine the outcome of the other event

d. The outcome of the event is determined by the theoretical probability of the event

Answers

Solution:

Independent Events:

Consider an experiment of Rolling a die, then getting an even number and multiple of 3.

Total favorable outcome = {1,2,3,4,5,6}=6

A=Even number = {2,4,6}

B=Multiple of 3 = {3,6}

A ∩ B={6}

P(A)=[tex]\frac{3}{6}=\frac{1}{2}[/tex], P(B)= [tex]\frac{2}{6}=\frac{1}{3}[/tex]

P(A ∩ B)=[tex]\frac{1}{6}[/tex]

So, P(A)× P( B)=[tex]\frac{1}{2}\times\frac{1}{3}=\frac{1}{6}[/tex]=P(A ∩ B)

Hence two events A and B are independent.

Option (c). the outcome of one event does NOT determine the outcome of the other event



Answer:

C on edge or the outcome of one event does NOT determine the outcome of the other event

Step-by-step explanation:

A die is tossed. find the odds against rolling a number greater than 11.

Answers

0% The # can be no greater than 6

Use synthetic division and the Remainder Theorem to find P(a)

P(x)=x^4+3x^3-6x^2-10x+8 ; a=2


28


–16


2


4

Answers

x=a=2→P(2)=(2)^4+3(2)^3-6(2)^2-10(2)+8
P(2)=16+3(8)-6(4)-20+8
P(2)=16+24-24-20+8
P(2)=4

P(a)=4

Answer: Fourth option. 4

Using synthetic division and the Remainder Theorem, we find that P(a) for P(x) when a=2 is P(2)=4, which is the remainder of the synthetic division.

To find P(a) for the given polynomial P(x)=x⁴+3x³-6x²-10x+8 when a=2, we can use synthetic division. The Remainder Theorem states that the remainder of the division of a polynomial by a linear divisor (x - a) is equal to P(a).

Let's perform the synthetic division:

Write down the coefficients of P(x): 1, 3, -6, -10, 8.Write the value of a below the synthetic division bar: 2.Bring down the leading coefficient: 1.Multiply this coefficient by a and write the result below the next coefficient: 1 * 2 = 2. Add this to the next coefficient: 3 + 2 = 5.Repeat this process for all coefficients.

The synthetic division should look like this:

 2  |  1   3  -6  -10   8
     |      2  10    8  -4
     |_____________________
        1   5   4   -2   4

The final number in the bottom row is the remainder, which is also P(2). So, P(2)=4.

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