Answer:
Explanation:
The contributions of water properties in Thermoregulation in endotherms and in the plasma membrane structure.
A) Thermoregulation in endotherms: Water contributes to thermoregulation by its property of High specific heat. Water's high specific heat acts as a heat buffer, it is much harder to cool down/heat up, therefore, it will make warmer than the cold environment around it or colder than the hot environment around it. Thermoregulation works in humansas well. Recall Homeostasis which is the body's way of regulating our temperature.
B) Plasma membrane structure:
The property of water, polarity, contributes to the plasma membrane because it creates the arrangement of phospholipids making it a semi-permeable membrane.
Recall that the Plasma Membrane has a hydrophilic end on the outside that is charged and likes water and a hydrophobic end on the inside that has no charge and doesn't like water.
The membrane that separates the interior of the cell from the external environment is known as the plasma membrane, sometimes known as the cell membrane, and it is present in all cells. A cell wall is affixed to the plasma membrane on the exterior of bacterial and plant cells.
What is transpiration?Like all other living things, plants need an excretory system to remove extra water from their bodies. Transpiration is the term for this process of removing extra water from the body of the plant. Typically, it is the evaporation of water from the leaf surface.
Now, according to the question :
(A) Thermoregulation in endotherms :
Water helps regulate body temperature since it has a high specific heat. Due to its high specific heat, which acts as a heat buffer, water will either make an area warmer than the surrounding cold environment or colder than the surrounding hot environment. Humans are capable of thermoregulation as well. Remember that the body uses homeostasis to control our body temperature.
(B) Plasma membrane structure:
Because it forms the arrangement of phospholipids that makes the plasma membrane a semi-permeable membrane, water's polarity contributes to the plasma membrane.
Remember that the Plasma Membrane has an exterior hydrophilic end that is charged and prefers water, and an interior hydrophobic end that is uncharged and dislikes water.
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In the picture, what can you say about the indices of refraction n1 and n2? (1 point)
n1 < n2
n1 > n2
n1 = n2
Not enough information to tell
Answer:
(c) n1 = n2
Explanation:
You want to know what can be said about the indices of refraction when a light ray continues on a straight path from one medium to another.
RefractionWhen a wave passes through media where the index of refraction changes, its path will be bent in accordance with Snell's law. When the index of refraction does not change, the path will remain unbent.
The figure shows the path of the ray is a straight line, so we can conclude ...
n1 = n2 . . . . . choice C
__
Additional comment
Even if the indices are different, the path will remain straight if the angle of incidence is 0—the path is normal to the interface between media. Here, the path is not shown as normal to the interface.
Degeneracy pressure stops the crush of gravity in all the following except
Answer:
A very massive main- sequence star
Explanation:
Degeneracy pressure refers to pressure expend by dense material , which is composed of fermions, which is an example of electrons in a white dwarf star. According to Pauli exclusion principle, which states that no two fermions can exist in the same quantum state, actually give details about the pressure.
When there is stellar masses that is less than about 1.44 of that of solar masses, there will be gravitational fall in the energy , and the energy will not be sufficient to produce the neutrons of a neutron star, therefore, the fall is abstruptly stopped through the electron degeneracy to form white dwarfs.this result to the creation of an effective pressure that further prevents gravitational fall.
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. find the speed v of the particle at t=5.00 seconds?
Answer:
43 m/s
Explanation:
Mass, m = 5 kg
Force, F(t) = 6t² - 4t + 3
To find the speed, we first need to get the acceleration, a.
Force is the product of mass and acceleration. It is given as:
F = ma
Therefore, acceleration is:
a(t) = F(t)/m
a(t) = (6t² - 4t + 3) / 5
a(t) = 1.2t² - 0.8t + 0.6
Acceleration is the differentiation of velocity with respect to time, t. Therefore, to get velocity, v, we integrate a(t):
a(t) = dv(t) / dt
=> v(t) = (1.2/3)t³ - (0.8/2)t² + 0.6t
v(t) = 0.4t³ - 0.4t² + 0.6t
Therefore, at time t = 5secs, velocity is:
v(5) = 0.4 * (5³) - 0.4 * (5²) + 0.6 * 5
v(5) = 50 - 10 + 3
v(5) = 43 m/s
The velocity at time, t = 5 secs is 43 m/s
On a merry-go-round, animals at the edge are located 4 times farther from the axis of rotation than the animals near the center. The animals near the center has a rotational speed of 3 RPM and a tangential speed of 2 m/sec.
What is the rotational speed of the animals near the edge?
a 3 RPM
b 12 RPM
c 2 RPM
d 6 RPM
Answer:
12 RPM
Explanation:
I would calculate the distance from the edge to the center, and then multiple that by 3RPM with 2 m/sec
Light refracts when traveling from air into glass because light
Answer:
Speed of light changes
Explanation:
Since glass is denser than air so the speed of light in glass is less than in air so light rays bend i.e. refract.
Light refracts when traveling from air into glass due to a change in speed caused by differences in optical density. The process, governed by Snell's Law, results in the bending of light towards the normal line as it enters the denser medium.
Explanation:Light refracts when traveling from air into glass because light waves undergo a change in speed when they pass from one medium to another. This process is known as refraction. Refraction occurs because there is a change in light's propagation speed due to the difference in optical density between air and glass. When light rays propagate from air (less optically dense) into glass (more optically dense), they bend towards the normal line—a line perpendicular to the boundary between the two media. This bending happens according to Snell's Law, which relates the angle of incidence to the angle of refraction, taking into account the refractive indices of the two media.
How does atmospheric pressure affect the boiling point of a liquid
Answer:
The atmospheric pressure and boiling point are directly proportional
Increasing atmospheric pressure increases the boiling point also
Explanation:
The atmosphere contain molecules that are in constant motion. They exert a downward force on a liquid’s surface. The higher the air pressure, the harder it is for the liquid to evaporate. Therefore, the boiling point of a solvent or liquid is affected by the atmospheric pressure and boiling point is raised.
A liquid in a high pressure environment boils at a higher temperature.
When placed in a lower pressure environment it boils at a lower temperature.
A force F acts in the forward direction on a cart of mass m. A friction force ff opposes this motion. Part A Use Newton's second law and express the acceleration of the cart. Express your answer in terms of the variables F, f, and m.
The acceleration of the cart can be calculated using the equation a = (F - f) / m, where F is the applied force, f is the friction force, and m is the mass of the cart.
Explanation:The acceleration of the cart can be expressed using Newton's second law, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Therefore, the acceleration (a) of the cart can be calculated using the equation:
a = (F - f) / m
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Compute the quantity of heat released by 25.0 g of steam initially at 100.0oC, when it is cooled to 34.0°C and by 25.0 g of water initially at 100.0 oC, when it is cooled to 34.0°C.
Answer:
For steam, heat released E = 15.26KJ
For water, heat released E2 = 6.91KJ
Explanation:
Given;
Mass(steam) ms = 25g
Mass (water) mw = 25g
Change in temperature of both steam and water ∆T = 100-34= 66°C
Specific heat of water C = 4.186 J/g.°C
Specific Latent heat L = 334J/g
For steam;
Heat released E = msL + msC∆T
E = (25×334) + (25×4.186×66)
E = 15256.9J
E = 15.26KJ
For water;
Heat released E2 = mwC∆T
E2 = 25×4.186×66
E2 = 6906.9J
E2 = 6.91KJ
A glass flask whose volume is 1000 cm3 at a temperature of 1.00 ∘C is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52.0 ∘C , a volume of 8.25 cm3 of mercury overflows the flask.If the coefficient of volume expansion of mercury is 18.0×10−5K−118.0×10 compute the coefficient of volume expansion of the glass.
Answer:
[tex]1.8\times 10^{-5}/K[/tex]
Explanation:
Volume of glass flask,[tex]V_0=1000 cm^3[/tex]
[tex]T_1=1.00^{\circ} C[/tex]
[tex]T_2=52.0^{\circ} C[/tex]
Over flow[tex]\Delta V=8.25 cm^3[/tex]
Coefficient of mercury=[tex]\beta_{Hg}=18.0\times 10^{-5}/K[/tex]
[tex]\Delta V_{Hg}=\beta_{Hg}V_0(T_2-T_1)=18\times 10^{-5}\times 1000\times (52-1)[/tex]
[tex]\Delta V_{Hg}=9.18 cm^3[/tex]
[tex]\Delta_{gass}=\Delta V-\Delta_{Hg}=9.18-8.25=0.93 cm^3[/tex]
[tex]\beta_{gass}=\frac{\Delta V_{gass}}{V_0(T_2-T_1)}[/tex]
[tex]\beta_{gass}=\frac{0.93}{1000\times (52-1)}[/tex]
[tex]\beta_{gass}=1.8\times 10^{-5}/K[/tex]
Hence, the coefficient of volume expansion of the glass=[tex]1.8\times 10^{-5}/^{\circ} C[/tex]
The coefficient of volume expansion of the glass [tex]\bold { 1.8 x 10^-^5\ K^-^ 1}[/tex]
Given here,
Volume of the glass flask = 1000[tex]\bold {cm^3}[/tex]
Initial temperature = 1[tex]\bold{^oC}[/tex]
Final temperature = 52 [tex]\bold{^oC}[/tex]
[tex]\bold{ \Delta V = V_0 \beta \Delta T}[/tex]
Where,
[tex]\bold {\Delta V}[/tex] - Change in volume
[tex]\bold{V_0}[/tex] - initial volume = 1000cm
[tex]\bold {\beta }[/tex] - coefficient of volume expansion
[tex]\bold{\Delta T }[/tex] - temperature [tex]\bold { = T_2- T_1}[/tex]
Put the values in the formula
[tex]\bold {\Delta V_H_g = 18\times 10^-^5 \times 1000\times 51}\\\\\bold {\Delta V_H_g = 9.18 cm^3}[/tex]
[tex]\bold {\Delta Vglass = \Delta V_H_g - \Delta _H_g}\\\\\bold {\Delta Vglass = 9.18 -8.25 }\\\\\bold {\Delta Vglass = 0.93 cm^3}[/tex]
So, coefficient of volume expansion for gas,
[tex]\bold {\beta glass = \dfrac {0.93 }{1000 \times 51}}\\\\\bold {\beta glass = 1.8 x 10^-^5\ K^-^ 1}[/tex]
The coefficient of volume expansion of the glass [tex]\bold { 1.8 x 10^-^5\ K^-^ 1}[/tex]
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If an electronin an electron beam experiences a downward force of 2.0x10^-14N while traveling in a magnetic field of 8.3x10^-2T west, what is the direction and the magnitude of the velocity?
Answer:
Explanation:
Given that,
Force is downward I.e negative y-axis
F = -2 × 10^-14 •j N
Magnetic field is westward, +x direction
B = 8.3 × 10^-2 •i T
Charge of an electron
q = 1.6 × 10^-19C
Velocity and it direction?
Force in a magnetic field is given as
F = q(V×B)
Angle between V and B is 270, check attachment
The cross product of velocity and magnetic field
F =qVB•Sin270
2 × 10^-14 = 1.6 × 10^-19 × V × 8.3 × 10^-2
Then,
v = 2 × 10^-14 / (1.6 × 10^-19 × 8.3 × 10^-2)
v = 1.51 × 10^6 m/s
Direction of the force
Let x be the direction of v
-F•j = v•x × B•i
From cross product
We know that
i×j = k, j×i = -k
j×k =i, k×j = -i
k×i = j, i×k = -j OR -k×i = -j
Comparing -k×i = -j to given problem
We notice that
-F•j = q ( -V•k × B×i)
So, the direction of V is negative z- direction
V = -1.51 × 10^6 •k m/s
Ultrasound with a frequency of 4.257 MHz can be used to produce images of the human body. If the speed of sound in the body is the same (1.06 km/s) as in salt water, what is the wavelength in the body? Answer in units of m.
The wavelength of an ultrasound with a frequency of 4.257 MHz in the human body is approximately 0.000249 meters or 0.249 mm, calculated using the formula
λ = v/f with the given speed of sound (1060 m/s) and the frequency.
The question is asking to calculate the wavelength of an ultrasound with a frequency of 4.257 MHz in the human body, given the speed of sound in the body is 1.06 km/s. To find the wavelength, we use the formula λ = v/f, where λ is the wavelength, v is the speed of sound, and f is the frequency.
First, we convert the speed of sound from km/s to m/s: 1.06 km/s = 1060 m/s. Then we use the given frequency (f) of 4.257 MHz, which we also convert to Hz: 4.257 MHz = 4.257 x 106 Hz. Now we can calculate the wavelength:
λ = v/f
λ = 1060 m/s / 4.257 x 106 Hz
λ ≈ 0.000249 m
Therefore, the wavelength of the ultrasound in the body is approximately 0.000249 meters or 0.249 mm.
The wavelength of 4.257 MHz ultrasound in the human body, using the speed of sound of 1.06 km/s, is approximately 0.249 mm.
To determine the wavelength of ultrasound in the body given the frequency and the speed of sound, we can use the formula:
lambda = v / f, where
lambda is the wavelength,
v is the speed of sound, and
f is the frequency of the ultrasound wave. The speed of sound in the body is given as 1.06 km/s, which is equivalent to 1060 m/s. The frequency of the ultrasound is 4.257 MHz, or 4.257 x 106 Hz. Plugging these values into the formula:
lambda = 1060 m/s / 4.257 x 106 Hz
The result will yield the wavelength of ultrasound in the human body, measured in meters.
Performing the calculation:
lambda = 1060 / 4.257 x 106
lambda = 0.000249 m or approximately 0.249 mm
The wavelength of 4.257 MHz ultrasound in the human body is therefore about 0.249 mm.
A sound wave (a periodic longitudinal wave) from a loudspeaker travels from air into water. The frequency of the wave does not change, because the loudspeaker producing the sound determines the frequency. The speed of sound in air is 343 m/s, whereas the speed in fresh water is 1482 m/s. When the sound wave enters the water, does its wavelength increase, decrease, or remain the same
Answer:
When the sound wave enters the water its wavelength increase.
Explanation:
Given:
Speed of sound in air [tex]v = 343 \frac{m}{s}[/tex]
Speed of sound in fresh water [tex]v' = 1482 \frac{m}{s}[/tex]
We know that when wave travel into one medium to another medium frequency doesn't change.
Velocity is given by,
[tex]v = f \lambda[/tex]
In above equation frequency is constant,
So when sound wave enters the water wavelength increase because speed sound is increase in water as compare to air.
Therefore, when the sound wave enters the water its wavelength increase.
Will water flow more easily through a wide pipe or a narrow pipe? Will current flow more easily through a thick wire or a thin wire?
Answer:
Explained below.
Explanation:
The water will flow more easily through a wide pipe, because as we know that if the diameter of the pipe is wider than the flow of water will be more.
And same case will be applied with the electric current, if the is wire thicker then the flow of the current will be more easy and the charge will also flow easily.
Suppose you are 3.3km away from a rifle range where someone is practicing shooting. How long would it take you to hear the sound of a shot fired by him?
Can you guys answer quickly, its urgent.
Answer:9.5 seconds(approx.)
Explanation:time=distance/speed
here,
distance=3.3 km= 3300 m
standard speed of sound=344 m/s
so, time=3300/344
time=9.5(approx.)
Final answer:
It would take approximately 9.71 seconds for the sound of a shot to travel 3.3 km and reach you, using the speed of sound of 340 m/s.
Explanation:
To calculate how long it would take for you to hear the sound of a shot fired from 3.3 km away, we need to use the speed of sound. In general, the speed of sound is approximately 340 meters per second (m/s) at sea level under normal conditions. Therefore, we can use the formula:
Time = Distance / Speed of Sound.
Now we simply plugin the values to get:
Time = 3300 meters / 340 m/s = 9.71 seconds
Therefore, it would take approximately 9.71 seconds for the sound of the shot to travel 3.3 km and reach you.
Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 1515 grams and velocity of 77 centimeters per second has a kinetic energy of 147147 ergs. Find the kinetic energy for a mass of 1010 grams and velocity of 99 centimeters per second?
Answer:
The second kinetic energy is 162 J.
Explanation:
Given that,
Mass, [tex]m_1=15\ g[/tex]
Velocity, [tex]v_1=7\ cm/s[/tex]
Kinetic energy, [tex]K_1=147\ ergs[/tex]
Mass, [tex]m_2=10\ g[/tex]
Velocity, [tex]v_2=9\ cm/s[/tex]
We need to find kinetic energy [tex]K_2[/tex]. Kinetic energy is given by :
[tex]K=\dfrac{1}{2}mv^2[/tex]
So,
[tex]\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J[/tex]
So, the second kinetic energy is 162 J.
Sound waves are converted into mechanical movements by the
Answer:
a.auditory ossicles
b.oval window
c.Round window
d.tympanic membrane
Answer is tympanic membrane
Explanation:
The tympanic membrane otherwise called the ear drum is a membrane shaped like a cone,it connects the outside to the inner ear,it serves to convert vibration from air into fluid membrane vibration a good example of mechanical waves for onwatd transmission into the cochlea of the inner ear through the oval window
Sound waves are converted into mechanical movements by the ear, specifically through structures in the middle and inner ear. The eardrum, ossicles, and cochlea play significant roles in this process, with the final conversion to electrical signals occurring in the cochlea.
Explanation:Sound waves are converted into mechanical movements by the ear, specifically the structures within the middle and inner ear.
When sound waves enter the ear, they strike the eardrum or tympanic membrane in the middle ear, causing it to vibrate. These vibrations are then transferred to three tiny bones in the middle ear called the ossicles, consisting of the malleus, incus, and stapes. The vibrations move these bones, with the stapes pushing into the oval window of the cochlea in the inner ear.
The cochlea is filled with fluid and lined with tiny hair-like structures called stereocilia. The mechanical movement from the ossicles creates waves in this fluid, which cause the stereocilia to move. This movement is converted into electrical signals that the brain interprets as sound.
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The incoming infrared radiation from the Sun as it travels towards Earth is _____. mostly reflected back out into space mostly absorbed and transmitted toward Earth's surface equally absorbed and reflected completely blocked and reflected by the upper atmosphere
Answer:
Mostly absorbed and transmitted toward Earth's surface
Explanation:
Infrared radiation from the sun reaches the Earth's surface and warms the Earth's surface. It emits some infrared radiation, some absorbed by gases such as carbon dioxide in the atmosphere. This is known as the greenhouse effect. and If it don't, radiation from the earth is powerful enough to burn the skin.
so correct answer is Mostly absorbed and transmitted toward Earth's surface
Answer:
mostly absorbed and transmitted toward Earth's surface
Explanation:
veronicas velocity was measured as 4.3 m/s. She displaced 20 meters in 4.7 seconds. Which piece of information is missing for the correct calculation of velocity?
Answer: B
Explanation:
Why do you think the combined wave is more powerful than either the transverse or longitudinal wave with the same amplitude
Answer:
Explanation:
The combined wave only end up been more powerful than the Longitudinal wave. This means, the transverse wave is more powerful than the combined wave. In transverse wave, the oscillation is perpendicular to the direction of the wave, while in longitudinal wave, the motion of the movement of the object is parallel to the movement of the wave. And in combined wave, the movement of the medium is in a circular manner,
Convection
A) is energy similar to radiant heat from the sun.
B) is the result of conductive heat loss to the air that overlies the surface of the body.
C) is the direct transfer of energy through physical contact.
D) changes a liquid to a vapor.
Answer:
A) energy similar to radiant heat from the sun
Write down the (real) electric and magnetic fields for a monochromatic plane wave of amplitude E0 , frequency w, and phase angle zero that is (a) traveling in the negative x direction and polarized in the z direction; (b) traveling in the direction from the origin to the point (1, 1, 1), with polarization parallel to the xz plane. In each case, sketch the wave, and give the explicit Cartesian components ofk and ii.
Answer:
a) the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis
b) the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)
Explanation:
a) the polarization the determined wave oscillates the electric field, which is the z axis
As the wave travels on the negative x-axis and the magnetic field is perpendicular, this field goes on the positive y-axis
the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis
be) in the case of a polarization in the xi plane the magnetic field must go in the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)
The top and bottom surfaces of a metal block each have an area of A = 0.030 m 2, and the height of the block is d = 0.11 m. At the top surface of the block, a force F1 is applied to the right, while at the bottom surface of the block, a force F2 is applied to the left, causing a shear in the metal block. If F1 = F2 = 30 ⨯ 106 N and the displacement between the two edges due to the shear is 1.12 10-3 m, what is the shear modulus of the metal
Answer:
Shear modulus is equal to [tex]9.82\times 10^{10}N/m^2[/tex]
Explanation:
We have given area [tex]A=0.030m^2[/tex]
Force is given [tex]F_1=F_2=30\times 10^6N[/tex]
Height of the block d = 0.11 m
Change in height of the block [tex]\Delta d=1.12\times 10^{-3}m[/tex]
Stress is given by
[tex]stress=\frac{force}{area}[/tex]
[tex]stress=\frac{30\times 10^6}{0.030}=10^9N/m^2[/tex]
Strain is equal to
[tex]strain=\frac{\Delta d}{d}[/tex]
[tex]strain=\frac{1.12\times 10^{-3}}{0.11}=10.18\times 10^{-3}[/tex]
Shear modulus is equal to
Shear modulus [tex]=\frac{stress}{strain}[/tex]
[tex]=\frac{10^9}{10.18\times 10^{-3}}=9.82\times 10^{10}N/m^2[/tex]
A block of mass = 4.00 kg is supported by a spring scale with unit of measure of Newtons. This spring scale is attached to top of an elevator. The elevator accelerates upward with a = 3.00 m/sec2. What is the reading on the spring scale to 3 significant figures?
Answer:
118 N
Explanation:
Given mass of the block, m = 4.00kg.
The acceleration of the elevator, a = 3.0 m/s^2.
As elevotar attaced with spring scale and accelerating upward
(block and elevator), so total force
[tex]F_N-mg=ma[/tex]
Here, mg is the weight of the block downward direction.
or
[tex]F_N=ma+mg=m(g+a)[/tex]
substitute the given value, we get
[tex]F_N=4kg(9.8m/s^2+3m/s^2)[/tex]
= 117.6 N = 118 N.
Thus, the reading on the spring scale to 3 significant figures is 118 N.
In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following pressure p, in atm, as a function of volume V, in liters: p = p0 V-6/5. Here p0 is a constant of units atm⋅L6/5. show answer Incorrect Answer 50% Part (a) Write an expression for the work W done on the gas when the gas is compressed from a volume Vi to a volume Vf.
The work done on the gas during an adiabatic compression process is calculated by integrating the pressure as a function of volume from the initial volume to the final volume. In this case, the integral ∫from V(i) to V(f) p₀ V^(-6/5) dV provides the value for the work done.
Explanation:In an adiabatic process, the work done W on the gas when it's compressed from a volume V(i) to a volume V(f) can be calculated by integrating the pressure-volume equation over the given volume range.
Given the pressure equation p = p₀ V^(-6/5), the work done on the gas (W) can be computed by the integral formula for work: W = ∫p dV = ∫from Vi to Vf p₀ V^(-6/5) dV. Evaluating this integral gives the work done on the gas during the compression process in the adiabatic process.
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What is the equivalent resistance in this circuit?
Ω
What is the current in this circuit?
A
Answer:
6.0?
Explanation:
What is the current in this circuit?
A
Hold on, our servers are swamped. Wait for your answer to fully load.
Answer:
The first one is 15.
The second one is 3.0.
Explanation:
You add up all the sides accept the voltage. 2+3+4+6= 15
For the second one you divide the voltage by all the resisters. 45/15=3
The electric power consumed by a circuit with one light bulb is 24 W. The voltage of the battery is 3 V. What is the current in the circuit?
Answer:
8 ampere
Explanation:
P= V x I
so
I = P/V
I= 24 /3
I = 8 A
Kinect energy is expressed using the unit
Answer:
joule
Explanation:
every unit for Energy is joule J
The starting conditions of an oscillator are characterized by the
Answer:
The phase constant
Explanation:
The phase constant tells how much a signal is shifted along the x-axis. A phase constant of ϕ means that each value of the signal happens ϕ amount of time earlier. If the signal has a beginning, then a phase constant of ϕ means the signal occurs that much sooner.
The starting conditions of an oscillator are characterized by the phase constant. Option B is correct.
Phase Constant:
This represents the number of oscillation per cycle of wave. It is denoted by [tex]\bold {\phi}[/tex]. It is also known as Propagation constant. The phase constant can be calculated using the formula.
[tex]\bold {\phi = \dfrac {2\pi }{\lambda}}[/tex]
Where, lambda is wavelength.
Frequency is the number of waves passing from a point per unit time.Amplitude is the height of the wave from its mid point.Therefore, option B is correct. The starting conditions of an oscillator are characterized by the phase constant.
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El vector a tiene componented ax= 2.70 cm, ay=2.25 cm; y el vector b tiene componentes bx= 0.30 cm, by= 1.75 cm. Calcular las componentes de la resultante a+b
Answer:
Explanation:
Given that,
A vector A has x component to be 2.7cm and y component to be 2.25cm
Then,
A = 2.7•i + 2.25•j
A vector B has x component of 0.30cm and y component of 1.75cm
B = 0.3•i + 1.75•j
So, we want to find A+B
Addition of vectors
Generally
(a•i + b•j) + (c•i + d•j) = (a+c)•i +(b+d)•j
Vectors are added component wise.
So,
A + B = (2.7•i + 2.25•j) + (0.3•i + 1.75•j)
A + B = (2.7 + 0.3)•i + (2.25 + 1.75)•j
A + B = 3•i + 4•j
We can also find it magnitude and direction
Generally,
A = a•i + b•j
|A| = √(a²+b²)
<A = arctan(b/a)
So,
|A+B| = √(3²+4²) = √9+16 = √25
|A+B| = 5
And it's direction
< = arctan(y/x)
< = arctan(4/3)
< = 53.13°
A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.814 rad/s2.What is the mass of the wheel?
Answer:
The mass of the wheel is 2159.045 kg
Explanation:
Given:
Radius [tex]r = 0.330[/tex]
m
Force [tex]F = 290[/tex] N
Angular acceleration [tex]\alpha = 0.814 \frac{rad}{s^{2} }[/tex]
From the formula of torque,
Γ [tex]= I\alpha[/tex] (1)
Γ [tex]= rF[/tex] (2)
[tex]rF = I \alpha[/tex]
Find momentum of inertia [tex]I[/tex] from above equation,
[tex]I = \frac{rF}{\alpha }[/tex]
[tex]I = \frac{0.330 \times 290}{0.814}[/tex]
[tex]I = 117.56[/tex] [tex]Kg. m^{2}[/tex]
Find the momentum inertia of disk,
[tex]I = \frac{1}{2} Mr^{2}[/tex]
[tex]M = \frac{2I}{r^{2} }[/tex]
[tex]M = \frac{2 \times 117.56}{(0.330)^{2} }[/tex]
[tex]M = 2159.045[/tex] Kg
Therefore, the mass of the wheel is 2159.045 kg