Final answer:
To design an application in which the number of days for each month in the year is stored in an array, create an array of integers representing the number of days in each month. Use a loop to display 12 sentences, each containing the month number and the corresponding number of days.
Explanation:
To design an application in which the number of days for each month in the year is stored in an array, you can create an array of integers representing the number of days in each month. Here's an example:
int[] daysInMonth = new int[]{31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
Then, you can use a loop to display 12 sentences, each containing the month number and the corresponding number of days. Here's an example:
for (int i = 0; i < 12; i++) {
System.out.println("Month " + (i + 1) + " has " + daysInMonth[i] + " days.");
}
Final answer:
To design the application, create an array with the number of days corresponding to each month and iterate through the array to display sentences for each month using the provided mnemonic or the knuckle mnemonic to remember the days.
Explanation:
To design an application that stores the number of days for each month in an array, we'll assume a non-leap year. We have the mnemonics "Thirty days hath September, April, June, and November. All the rest have thirty-one, save the second one alone, Which has four and twenty-four, till leap year gives it one day more". So, we'll create an array with the following values: 31 (January), 28 (February), 31 (March), 30 (April), 31 (May), 30 (June), 31 (July), 31 (August), 30 (September), 31 (October), 30 (November), 31 (December). Then, we can iterate through this array and display the sentences accordingly.
For example, the following pseudo-code can be used to display the sentences:Initialize an array daysInMonths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]For each index in the array representing a month (starting from 0 for January):Print "Month (index + 1) has (value at current index) days"
The knuckle mnemonic is a physical way to remember the number of days in each month, where months with 31 days are represented by the protruding knuckles and shorter months fall in the spots between the knuckles.
Design state machines to control the minutes and hours of a standard 24 hour clock. Your clock should include an AM/PM indicator light, 2-digit hours (1 – 12), 2-digit minutes (00 – 59). (There is no need to include seconds; if we wanted to display seconds, it would be the same state control unit as minutes.)
Answer:
1 Hz clock generator to produce 1 PPS (beat every second) sign to the seconds square.
SECONDS square - contains a partition by 10 circuit followed by a gap by 6 circuit. Will produce a 1 PPM (beat every moment) sign to the minutes square. The BCD yields associate with the BCD to Seven Segment circuit to show the seconds esteems.
MINUTES square - indistinguishable from the seconds square it contains 2 dividers; a partition by 10 followed by a separation by 6. Will produce a 1 PPH (beat every hour) sign to the HOURS square. The BCD yields interfaces with the BCD to Seven Segment circuit to show the minutes esteems.
HOURS square - relying upon whether it is a 12 or 24H clock, will have a partition 24 or separation by 12. For 24H, it will tally from 00 to 23. For 12H, it will tally from 00 to 11. The BCD yields associates with the BCD to Seven Segment circuit to show the hours esteems.
Note that: To rearrange the table, K is Q0 of IC1 (ones), G is Q0 of IC2 (tens, etc.
For the 12H clock, when the include in BCD comes to
0A, IC1 must be cleared (Y=1)
12, IC1 must be cleared (Y=1) and IC2 must be cleared (X=1)
Utilizing SOP (entirety of items), we get
Y = HJ + GJ where Y is the IC1 MR1, MR2 inputs associated together.
X = GJ where X is the IC2 MR1, MR2 inputs associated together.
Explanation:
Write syntactically correct Javascript code to sort an array of sub-arrays containing integers using the sort and reduce array functions as described below. You will sort the sub-arrays in ascending order by the maximum value found in each sub-array. Your solution would be executed in the following manner:
The question is incomplete. The complete question is:
Write syntactically correct Javascript code to sort an array of sub-arrays containing integers using the sort and reduce array functions as described below. You will sort the sub-arrays in ascending order by the maxium value found in each sub-array. Your solution would be executed in the following manner:
var x = [ [ 2 , 5 , 1 ], [ 1 , 23 ] , [ 3 ] , [ 22, 16, 8 ] ] ;
x.sort(compare);
will result in variable x containing [ 3 ] , [ 2, 5, 1], [ 22 , 16 , 8], [ 1 , 23 ] ]. The maximum value of each sub-array is shown here in bold. Your solution must be written so that when run with the code above, x will contain the sorted array.
Answer:
function compare(a , b) {
var max1 = Math.max(...a); //get the max in array a
var max2 = Math.max(...b); //get the max in array b
return max1 - max2;
}
var x = [ [ 2 , 5 , 1 ], [ 1 , 23 ] , [ 3 ] , [ 22, 16, 8 ] ] ;
x.sort(compare);
Explanation:
Given an array A positive integers, sort the array in ascending order such that element in given subarray which start and end indexes are input in unsorted array stay unmoved and all other elements are sorted.
An array is a special kind of object. With the square brackets, access to a property arr[0] actually come from the object syntax. This is essentially the same as obj[key], where arr is the object, while numbers are used as keys.
Therefore, sorting sub-array in ascending order by the maxium value found in each sub-array is done:
function compare(a , b) {
var max1 = Math.max(...a); //get the max in array a
var max2 = Math.max(...b); //get the max in array b
return max1 - max2;
}
var x = [ [ 2 , 5 , 1 ], [ 1 , 23 ] , [ 3 ] , [ 22, 16, 8 ] ] ;
x.sort(compare);
Given the following structure and variable definitions, struct customer { char lastName[ 15 ]; char firstName[ 15 ]; unsigned int customerNumber; struct { char phoneNumber[ 11 ]; char address[ 50 ]; char city[ 15 ]; char state[ 3 ]; char zipCode[ 6 ]; } personal; } customerRecord, *customerPtr; customerPtr = &customerRecord; write an expression that can be used to access the structure members in each of the following parts: a) Member lastName of structure customerRecord. b) Member lastName of the structure pointed to by customerPtr. c) Member firstName of structure customerRecord. d) Member firstName of the structure pointed to by customerPtr. e) Member customerNumber of structure customerRecord. f) Member customerNumber of the structure pointed to by customerPtr. g) Member phoneNumber of member personal of structure customerRecord. h) Member phoneNumber of member personal of the structure pointed to by customerPtr. i) Member address of member personal of structure customerRecord. j) Member address of member personal of the structure pointed to by customerPtr. k) Member city of member personal of structure customerRecord. l) Member city of member personal of the structure pointed to by customerPtr.
Answer:
see explaination
Explanation:
a)
customerRecord.lastName
b)
customerPtr->lastName or (*customerPtr).lastName
c)
customerRecord.firstName
d)
customerPtr->firstName or (*customerPtr).firstName
e)
customerRecord.customerNumber
f)
customerPtr->customerNumber or (*customerPtr).customerNumber
g)
customerRecord.personal.phoneNumber
h)
customerPtr->personal.phoneNumber or (*customerPtr).personal.phoneNumber
i)
customerRecord.personal.address
j)
customerPtr->personal.address or (*customerPtr).personal.address
k)
customerRecord.personal.city
l)
customerPtr->personal.city or (*customerPtr).personal.city
m)
customerRecord.personal.state
n)
customerPtr->personal.state or (*customerPtr).personal.state
o)
customerRecord.personal.zipCode
p)
customerPtr->personal.zipCode or (*customerPtr).personal.zipCode
To find all the prime numbers less than or equal to a given integer n by Eratosthenes' method: 1. Create a list of consecutive integers from two to n: (2, 3, 4, ..., n), 2. Initially, let p equal 2, the first prime number, 3. While enumerating all multiples of p starting from p2, strike them off from the original list, 4. Find the first number remaining on the list after p (it's the next prime); let p equal this number, 5. Repeat steps 3 and 4 until p2 is greater than n. 6. All the remaining numbers in the list are prime.
Answer:
I am writing a Python program:
def Eratosthenes(n):
primeNo = [True for i in range(n+1)] # this is a boolean array
p = 2 # the first prime number is initialized as 2
while (p * p <= n): # enumerates all multiples of p
if (primeNo[p] == True):
for i in range(p * p, n+1, p): #update multiples
primeNo[i] = False
p = p + 1
for p in range(2, n): #display all the prime numbers
if primeNo[p]:
print(p),
def main(): #to take value of n from user and display prime numbers #less than or equal to n by calling Eratosthenes method
n= int(input("Enter an integer n: "))
print("The prime numbers less than or equal to",n, "are: ")
Eratosthenes(n)
main()
Explanation:
The program contains a Boolean type array primeNo that is initialized by True which means that any value i in prime array will be true if i is a prime otherwise it will be false. The while loop keeps enumerating all multiples of p starting from 2, and striking them off from the original array list and for loops keep updating the multiples. This process will continue till the p is greater than n. The last for loop displays all the prime numbers less than or equal to n which is input by user. main() function prompts user to enter the value of integer n and then calls Eratosthenes() function to print all the prime numbers less than or equal to a given integer n.
2- There are many different design parameters that are important to a cache’s overall performance. Below are listed parameters for different direct-mapped cache designs. Cache Data Size: 32 KiB Cache Block Size: 2 words Cache Access Time: 1 cycle Calculate the total number of bits required for the cache listed above, assuming a 32-bit address. Given that total size, find the total size of the closest direct-mapped cache with 16-word blocks of equal size or greater. Explain why the second cache, despite its larger data size, might provide slower performance than the first cache. You must show your work
Answer:
1. 2588672 bits
2. 4308992 bits
3. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
Explanation:
1. Number of bits in the first cache
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^15 (1+14+(32*2^1)) = 2588672 bits
2. Number of bits in the Cache with 16 word blocks
Using the formula: (2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))
total bits = 2^13(1 +13+(32*2^4)) = 4308992 bits
3. Caches are used to help achieve good performance with slow main memories. However, due to architectural limitations of cache, larger data size of cache are not as effective than the smaller data size. A larger cache will have a lower miss rate and a higher delay. The larger the data size of the cache, the larger the area of memory you will need to "search" making the access time and performance slower than the a cache with a smaller data size.
The total number of bits required for the given cache is 335,872 bits. Despite the larger data size, the second cache with 16-word blocks might provide slower performance due to higher block transfer times and possible increased cache miss rates.
Given the cache parameters:
Cache Data Size: 32 KiBCache Block Size: 2 wordsCache Access Time: 1 cycleLet's calculate the total number of bits required for this cache. Assume a 32-bit address.
Calculate the number of blocks in the cache:To find the total size of the closest direct-mapped cache with 16-word blocks: A 16-word block = 16 × 4 bytes = 64 bytes. Number of blocks = 32768 bytes (32 KiB) / 64 bytes = 512 blocks.
Repeat the bit calculation with the new configuration:
Offset bits = log2(64) = 6 bitsIndex bits = log2(512) = 9 bitsTag bits = 32 - (Index bits + Offset bits) = 32 - 15 = 17 bitsTotal bits per block = 1 Valid bit + 17 Tag bits + 64 bytes × 8 bits/byte = 1 + 17 + 512 = 530 bits.Total bits for the new cache: 512 blocks × 530 bits/block = 271,360 bits.
Despite the larger data size, the second cache with 16-word blocks might provide slower performance due to higher block transfer times and possible increased cache miss rates. Larger blocks increase the penalty for cache misses and might not be fully utilized, leading to inefficiency.
Encryption Using Rotate Operations Write a procedure that performs simple encryption by rotating each plaintext byte a varying number of positions in different directions. For example, in the following array that represents the encryption key, a negative value indicates a rotation to the left and a positive value indicates a rotation to the right. The integer in each position indicates the magnitude of the rotation: key BYTE -2, 4, 1, 0, -3, 5, 2, -4, -4, 6
o implement simple encryption using rotate operations in assembly language, you can create a procedure that takes a plaintext byte and a key array as parameters. The key array represents the rotation values for each position. Here's an example of how you can write such a procedure in x86 assembly:
section .data key db -2, 4, 1, 0, -3, 5, 2, -4, -4, 6 section .text
global rotate_encrypt
rotate_encrypt:
; Input parameters:
; rdi: pointer to plaintext byte
; rsi: index in the key array
; Load the plaintext byte mov al, [rdi]
; Load the rotation value from the key array mov cl, [key + rsi]; Check if the rotation is positive or negative cmp cl, 0jge rotate_right jl rotate_left
rotate_right: ; Rotate right by the magnitude specified in clshr al, cljmp done
rotate_left: ; Rotate left by the magnitude specified in cl (convert to positive)neg clshl al, cl
done: ; Return the encrypted byte mov [rdi], alret
JAVA
In this exercise, you are given a word or phrase and you need to return that word or phrase with the word ‘like’ in front of it.
If the phrase already starts with like, you should not add another one, just return the phrase as is.
Example:
like("totally awesome") --> "like totally awesome"
like("like cool dude") --> "like cool dude"
like("I like you") -->"like I like you"
Answer:
Answer in the screenshot provided.
Explanation:
Check if the String starts with like. If it does not then prepend it.
Implement the simulation of a biased 6-sided die which takes the values 1,2,3,4,5,6 with probabilities 1/8,1/12,1/8,1/12,1/12,1/2. In [ ]: # WRITE YOUR OWN CODE HERE! FEEL FREE TO INSERT MORE CELLS! # ADD SOME COMMENTS TO YOUR CODE! Plot a histrogramm with 1,000,000 simulations to check if the relative counts of each number is approximately equal to the corresponding specified probabilities. Remark: Specify the bins of your histogram correctly.
Answer:
see explaination
Explanation:
import numpy as np
import matplotlib.pyplot as plt
a = [1, 2, 3, 4, 5, 6]
prob = [1.0/8.0, 1.0/12.0, 1.0/8.0, 1.0/12.0, 1.0/12.0, 1.0/2.0]
smls = 1000000
rolls = list(np.random.choice(a, smls, p=prob))
counts = [rolls.count(i) for i in a]
prob_exper = [float(counts[i])/1000000.0 for i in range(6)]
print("\nProbabilities from experiment : \n\n", prob_exper, end = "\n\n")
plt.hist(rolls)
plt.title("Histogram with counts")
plt.show()
check attachment output and histogram
To simulate a biased 6-sided die with specified probabilities, use the random.choices() function from the Python random module. Run the simulation for a large number of times and create a histogram to plot the relative counts of each number.
Explanation:To simulate a biased 6-sided die with specified probabilities, you can use the random.choices() function from the Python random module. You will need to provide the possible values and their corresponding probabilities as inputs to this function. Then, you can run the simulation for a large number of times, such as 1,000,000, and store the results in a list. Finally, you can create a histogram using the matplotlib.pyplot library to plot the relative counts of each number.
import random
import matplotlib.pyplot as plt
# Define the probabilities of each side of the die
probs = {
1: 0.1764,
2: 0.1764,
3: 0.1764,
4: 0.1764,
5: 0.1764,
6: 0.0972
}
# Define the number of times to simulate the die
num_simulations = 1000000
# Create a histogram of the relative counts of each number
die_hist = []
for i in range(num_simulations):
die_result = [random.choices(range(1, 7), k=1)[0] for _ in range(6)]
relative_count = len(die_result) / 6
die_hist.append(relative_count)
# Plot the histogram
plt.hist(die_hist, bins=20)
plt.xlabel('Number of times the die shows 1')
plt.ylabel('Relative count')
plt.show()
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1. Compare the similarities and differences between traditional computing and the computing clouds launched in recent years. Also discuss possible convergence of the two computing paradigms in the future.
2. An increasing number of organizations in industry and business adopt cloud systems. Answer the following questions regarding cloud computing:
a. List and describe the main characteristics of cloud computing systems.
b. Discuss key enabling technologies in cloud computing systems.
c. Discuss different ways for cloud service providers to maximize their revenues.
d. Characterize the three cloud computing models using suitable examples.
Answer and explanation:
(1)
Resilience and Elasticity
The information and applications hosted in the cloud are evenly distributed across all the servers, which are connected to work as one. Therefore, if one server fails, no data is lost and downtime is avoided. The cloud also offers more storage space and server resources, including better computing power. This means your software and applications will perform faster.
Flexibility and Scalability
Cloud hosting offers an enhanced level of flexibility and scalability in comparison to traditional data centres. The on-demand virtual space of cloud computing has unlimited storage space and more server resources. Cloud servers can scale up or down depending on the level of traffic your website receives, and you will have full control to install any software as and when you need to. This provides more flexibility for your business to grow.
Automation
A key difference between cloud computing and traditional IT infrastructure is how they are managed. Cloud hosting is managed by the storage provider who takes care of all the necessary hardware, ensures security measures are in place, and keeps it running smoothly. Traditional data centres require heavy administration in-house, which can be costly and time consuming for your business. Fully trained IT personnel may be needed to ensure regular monitoring and maintenance of your servers – such as upgrades, configuration problems, threat protection and installations.
Running Costs
Cloud computing is more cost effective than traditional IT infrastructure due to methods of payment for the data storage services. With cloud based services, you only pay for what is used – similarly to how you pay for utilities such as electricity. Furthermore, the decreased likelihood of downtime means improved workplace performance and increased profits in the long run.
Security
Cloud computing is an external form of data storage and software delivery, which can make it seem less secure than local data hosting. Anyone with access to the server can view and use the stored data and applications in the cloud, wherever internet connection is available. Choosing a cloud service provider that is completely transparent in its hosting of cloud platforms and ensures optimum security measures are in place is crucial when transitioning to the cloud.
2(a)The five main characteristics of cloud computing systems are given below:
On-demand self-service: That is used when needed
Broad network access: That is ubiquitous, that is, it is everywhere
Multi-tenancy and resource pooling: That is sharing of resources
Rapid elasticity and scalability : Deploy only the amount of resources needed at a time
Measured service: Pay for what you use
(b)The five key enabling technologies in cloud computing systems are given below:
Client server using Application Control Interfaces Server Virtualization : Allows platform independence sort of scenario. Aggregation of computers into server based data centers: I.e high availability of computing resources Storage technologies supporting logical shards: Replication and safety of data Network virtualization(c). The three different ways for cloud service providers to maximize their revenues:
Development : Here the revenue comes from subscriptions paid by the customers.These also testing a new market for development.
Reselling : Using a pre-developed service or a cloud-based application- if it works really well. Then it can be ported to an on-premises solution thus bringing is a large possibility of prospective consumers.These also testing a new market for deployment.
Hosting: Server hardware is very expensive thus cloud computing is marketed as a good solution for disaster recovery solutions for customer data and profits are made as per subscription or dynamic virtual resource renting approach
(d)The characteristics of three cloud computing models using suitable examples is given below:
IAAS: This provides virtualized computing resources over cloud i.e over the internet. Here the cloud provider will host the infrastructure components which are traditionally present in an on-premises data center, hardware,servers etc. For example: Google Compute Engine, Linode
PAAS: This usually provides a platform as a service which allows the customers to develop, run, and manage applications. The users do not have to undergo the the complexity of building and maintaining the infrastructure which is typically associated with developing and launching an app if they are using a PAAS. Examples are AWS Elastik beanstalk, Apache Stratos
SAAS:In this model model the customer is provided with access to application software which is often referred to as "on-demand software". For example Google Drive, PayPal etc
Similarities and differences in computing.
Computing is the goal, oriented activity that needs benefits from creating the computing machinery that helps is study and measuring the algorithms process of development. Traditional and cloud-based computing refers to the delivery of services through data and the program on the internet.
Thus the answer is technology, security, infrastructure.
The difference is related to the local servers and the cloud or internet system. The convergence of the two technologies show the dynamic possibilities for the future of the technology leads to enhanced security and information maintenance. The provision of further technology of switches and routers.The increase in the number of organizations and businesses over the recent years has led to the growth of cloud computing and many services related to the international domain.This has led to the growth of technology and infrastructure.
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The sum of the numbers 1 to n can be calculated recursively as follows: The sum from 1 to 1 is 1. The sum from 1 to n is n more than the sum from 1 to n-1 Write a function named sum that accepts a variable containing an integer value as its parameter and returns the sum of the numbers from 1 to to the parameter (calculated recursively).
Answer:
See explaination
Explanation:
The code
#function named sum that accepts a variable
#containing an integer value as its parameter
#returns the sum of the numbers from 1 to to the parameter
def sum(n):
if n == 0:
return 0
else:
#call the function recursively
return n + sum(n - 1)
#Test to find the sum()
#function with parameter 5.
print(sum(5))
A recursive function is simply a function that continues to execute itself until a condition is satisfied
The recursive function sum in Python, where comments are used to explain each line is as follows:
#This defines the sum function
def sum(n):
#The function returns n, when n is 1 or less
if n <= 1:
return n
#Otherwise, the sum is calculated recursively
else:
return n + sum(n - 1)
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Write a function "hailstone"that takes an int "n2"and prints the hailstone sequence. Hailstone Numbers:This sequence takes the name hailstone as the numbers generated bounce up and down. To generate the sequence, follow these rules:a.If the number isodd multiply it by 3 and add 1 b.If the number is even, divide by two.c.Repeat until you reach number 1.Sample Inputs & Outputsn2= 3-> 10, 5, 16, 8, 4, 2, 1 n2 =6-> 3, 10, 5, 16, 8, 4, 2, 1 n2 =7-> 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1
Answer:
Here is the C program
#include<iostream> //for input output functions
using namespace std; //to identify objects like cin cout
int Hailstone(int n2); //function declaration of function Hailstone
int main() { // start of main() function body
int num; // stores number entered by user
cout<<"Enter a number: "; // prompts user to enter a number
cin>>num; // reads the input number
while(num!=1) { // loop continues until the value of num becomes 1
num = Hailstone(num); // calls hailstone method and passes num to it
cout<<num<<"\n"; } } // prints the hailstone sequence
int Hailstone(int n2) { //function takes int n2 and prints hailstone sequence
if(n2 % 2 == 0) { // if the number is even
return n2 /=2; } // divide the n2 by 2 if n2 value is even
else { // if n2 is odd
return n2 = (3 * n2) + 1; } } // multiply n2 by 3 and add 1 if n2 is odd
Explanation:
The function Hailstone() takes as parameter an integer which is int type and is named is n2. This function prints the hailstone sequence. The function has an if statement that checks if the number n2 input by the user is even or odd. If the value of n2 is even which is found out by taking modulus of n2 by 2 and if the result is 0 this means that n2 is completely divisible by 2 and n2 is an even number. So if this condition evaluates to true then n2 is divided by 2. If the condition evaluates to false and the value of n2 is odd then n2 is multiplied by 3 and 1 is added.
In the main() function the user is prompted to enter a number and the Hailstone() function is called which keeps repeating until the value of n2 reaches 1.
The idea is to simulate random (x, y) points in a 2-D plane with domain as a square of side 1 unit. Imagine a circle inside the same domain with same diameter and inscribed into the square. We then calculate the ratio of number points that lied inside the circle and total number of generated points.
Answer:
For calculating Pi (π), the first and most obvious way is to measure the circumference and diameter.
π = Circumference / diameter
For the random points in the 2-D plane, we calculate the ratio of number points inside the circle and generate random pairs and then check
x² + y² < 1
If the given condition is true, then increment the points and used them. In randomized and simulation algorithms like Monte Carlo. In this case, if the number of the iteration is more then more accurate, the result is.
Explanation:
For simulating the random points in 2-D using Monte Carlo algorithms:
Monte Carlo
In this algorithm, we calculate the ratio of the number of points that lied in the circle. We do not need any graphics or simulations to generated points. In this, we generate random pairs and check x² + y² < 1.
π ≅ 4 × N inner / N total
The other way for calculating Pi (π) is to use Gregory-Leibniz Series.
Series which converges more quickly is Nilakangtha Series, which is developed in the 15th century. It is the other way to calculate Pi (π).
Server farms such as Google and Yahoo! provide enough compute capacity for the highest request rate of the day. Imagine that most of the time these servers operate at only 60% capacity. Assume further that the power does not scale linearly with the load; that is, when the servers are operating at 60% capacity, they consume 90% of maximum power. The servers could be turned off, but they would take too long to restart in response to more load. A new system has been proposed that allows for a quick restart but requires 20% of the maximum power while in this "barely alive" state. a. How much power savings would be achieved by turning off 60% of the servers? b. How much power savings would be achieved by placing 60% of the servers in the "barely alive" state? c. How much power savings would be achieved by reducing the voltage by 20% and frequency by 40%? d. How much power savings would be achieved by placing 30% of the servers in the "barely alive" state and 30% off?
Answer:
a) Power saving = 26.7%
b) power saving = 48%
c) Power saving = 61%
d) Power saving = 25.3%
Explanation:
Write a C++ program that reads students' names followed by their test scores. The program should output each students' name followed by the test scores and relevant grade. It should also find and print the highest test score and the name of the students having the highest test score. Student data should be stores in a struct variable of type studentType, which has four components: studentFName and studentLname of type string, testScore of type int (testScore is between 0 and 100), and and grade of type char. Suppose that the class has 20 students. Use an array of 20 components of type studentType.
Your Program must contain at least the following functions:
a. A function to read the students' data into the array.
b. A function to assign the relevant grade to each student.
c. A function to find the highest test score.
d. A function to print the names of the students having the highest test score.
Answer:
#include<iostream>
#include<conio.h>
using namespace std;
struct studentdata{
char Fname[50];
char Lname[50];
int marks;
char grade;
};
main()
{
studentdata s[20];
for (int i=0; i<20;i++)
{
cout<<"\nenter the First name of student";
cin>>s[i].Fname;
cout<<"\nenter the Last name of student";
cin>>s[i].Lname;
cout<<"\nenter the marks of student";
cin>>s[i].marks;
}
for (int j=0;j<20;j++)
{
if (s[j].marks>90)
{
s[j].grade ='A';
}
else if (s[j].marks>75 && s[j].marks<90)
{
s[j].grade ='B';
}
else if (s[j].marks>60 && s[j].marks<75)
{
s[j].grade ='C';
}
else
{
s[j].grade ='F';
}
}
int highest=0;
int z=0;
for (int k=0;k<20; k++)
{
if (highest<s[k].marks)
{
highest = s[k].marks;
z=k;
}
}
cout<<"\nStudents having highest marks"<<endl;
cout<<"Student Name"<< s[z].Fname<<s[z].Lname<<endl;
cout<<"Marks"<<s[z].marks<<endl;
cout<<"Grade"<<s[z].grade;
getch();
}
Explanation:
This program is used to enter the information of 20 students that includes, their first name, last name and marks obtained out of 100.
The program will compute the grades of the students that may be A,B, C, and F. If marks are greater than 90, grade is A, If marks are greater than 75 and less than 90, grade is B. For Mark from 60 to 75 the grade is C and below 60 grade is F.
The program will further found the highest marks and than display the First name, last name, marks and grade of student who have highest marks.
A C++ program prompts for student names and test scores, storing data in a structure. Functions assign grades, find the highest score, and print students with the highest score. It utilizes arrays and functions to manage student data effectively within the specified requirements.
Here's a C++ program that fulfills the requirements you specified:
```cpp
#include <iostream>
#include <string>
using namespace std;
struct studentType {
string studentFName;
string studentLName;
int testScore;
char grade;
};
const int MAX_STUDENTS = 20;
// Function prototypes
void readStudentData(studentType students[], int numStudents);
void assignGrades(studentType students[], int numStudents);
int findHighestScore(const studentType students[], int numStudents);
void printHighestScorers(const studentType students[], int numStudents, int highestScore);
int main() {
studentType students[MAX_STUDENTS];
int numStudents;
cout << "Enter the number of students (up to 20): ";
cin >> numStudents;
if (numStudents > MAX_STUDENTS || numStudents < 1) {
cout << "Invalid number of students. Exiting program.";
return 1;
}
readStudentData(students, numStudents);
assignGrades(students, numStudents);
int highestScore = findHighestScore(students, numStudents);
printHighestScorers(students, numStudents, highestScore);
return 0;
}
void readStudentData(studentType students[], int numStudents) {
for (int i = 0; i < numStudents; ++i) {
cout << "Enter student " << i + 1 << "'s first name: ";
cin >> students[i].studentFName;
cout << "Enter student " << i + 1 << "'s last name: ";
cin >> students[i].studentLName;
cout << "Enter student " << i + 1 << "'s test score: ";
cin >> students[i].testScore;
}
}
void assignGrades(studentType students[], int numStudents) {
for (int i = 0; i < numStudents; ++i) {
if (students[i].testScore >= 90)
students[i].grade = 'A';
else if (students[i].testScore >= 80)
students[i].grade = 'B';
else if (students[i].testScore >= 70)
students[i].grade = 'C';
else if (students[i].testScore >= 60)
students[i].grade = 'D';
else
students[i].grade = 'F';
}
}
int findHighestScore(const studentType students[], int numStudents) {
int highestScore = students[0].testScore;
for (int i = 1; i < numStudents; ++i) {
if (students[i].testScore > highestScore)
highestScore = students[i].testScore;
}
return highestScore;
}
void printHighestScorers(const studentType students[], int numStudents, int highestScore) {
cout << "Students with the highest score of " << highestScore << ":\n";
for (int i = 0; i < numStudents; ++i) {
if (students[i].testScore == highestScore)
cout << students[i].studentFName << " " << students[i].studentLName << endl;
}
}
```
This program reads student data, assigns grades, finds the highest test score, and prints the names of students with the highest score. It utilizes structures and functions as required.
What is required for real-time surveillance of a suspects computer activity?/p Group of answer choices a. Blocking data transmissions between a suspect’s computer and a network server. b. Poisoning data transmissions between a suspect’s computer and a network server. c. Preventing data transmissions between a suspect’s computer and a network server. d. Sniffing data transmissions between a suspect’s computer and a network server.
Answer:
c Preventing data transmissions between a suspect’s computer and a network server
Explanation:
What are the disadvantages of a Cessna 172?
Answer:
The 172 accounted for 17-percent of the active fleet and flew 16-percent of the hours flown while accounting for six-percent of the fatal accidents.
Explanation:
In a two-year period there was but one fatal 172 accident that was due to a mechanical failure. That was an engine failure related to a valve. There were no fatal accidents related to fuel exhaustion or starvation.
Despite the good record in that area, the 172 is probably involved in just as many forced landings as any like airplane. It just appears more adaptable to impromptu arrivals than some other airplanes. The low landing speed contributes to this. There is no available statistic on this, but I would bet that most 172 forced landings don’t result in what the NTSB classifies as an accident.
I looked at fatal 172 accidents that occurred during two more recent years (2012 and 2013) when virtually all the NTSB reports were final as opposed to preliminary. There were 25 such accidents in the 48 contiguous states. If the methodology I used years ago is applied to that number, the 172 safety record appears to have improved, maybe substantially.
A developer has the following class and trigger code:public class InsuranceRates {public static final Decimal smokerCharge = 0.01;}trigger ContactTrigger on Contact (before insert) {InsuranceRates rates = new InsuranceRates();Decimal baseCost = XXX;}Which code segment should a developer insert at the XXX to set the baseCost variable to the value of the class variable smokerCharge?
A. Rates.smokerCharge
B. Rates.getSmokerCharge()
C. ContactTrigger.InsuranceRates.smokerCharge
D. InsuranceRates.smokerCharge
Answer:
InsuranceRates.smokerCharge
Explanation:
To set the baseCost variable to the value of the class variable smokerCharge, the developer needs to replace
Decimal baseCost = XXX;
with
Decimal baseCost = InsuranceRates.smokerCharge;
This is done using the class reference type.
The smokerCharge should be declared in the InsuranceRates class, at first.
For example Ball b;
And then, a new instance of the object from the class is created, using the new keyword along with the class name: b = new Ball();
In comparing to the example I gave in the previous paragraph, the object reference in the program is:
InsuranceRates rates = new InsuranceRates();
Because the smokerCharge is coming from a different class, it can only be assigned to the variable baseCost via the InsuranceRates class to give:
Decimal baseCost = InsuranceRates.smokerCharge;
The correct code segment to set the baseCost variable to the value of the class variable smokerCharge is D. InsuranceRates.smokerCharge.
Explanation:The correct code segment to set the baseCost variable to the value of the class variable smokerCharge is D. InsuranceRates.smokerCharge.
In the given code, the smokerCharge variable is declared as a static final variable in the InsuranceRates class. This means that it can be accessed directly using the class name followed by the variable name.
Therefore, to set the baseCost variable to the value of smokerCharge, we use InsuranceRates.smokerCharge.
JAVA
Write a method that takes 2 parameters: a String[] array, and an int numRepeats representing the number of times to repeat each element in the array.
Return a new array with each element repeated numRepeats times.
For example:
repeatElements(new String[]{"hello", "world"}, 3)
Should return a new array with the elements:
["hello", "hello", "hello", "world", "world", "world"]
public String[] repeatElements(String[] array, int numRepeats){
}
Answer:
Answer is in the provided screenshot! This was a lot of fun to make!
Explanation:
We need to create a new Array which has to be the size of amount * original - as we now that we are going to have that many elements. Then we just iterate through all the values of the new array and set them equal to each of the elements in order.
Ignore the code in my main function, this was to print to the terminal the working code - as you can see from the output at the bottom!
Write programs for two MSP430 boards to do the following:
Board A: If the P1.1 button is pressed, send the message 0xAA via the UART at 9600 baud.
Board B: The red LED shall initially be off. However, if the Board B micro-controller receives a UART message of 0xAA at 9600 baud, turn on the Board B red LED.
Answer:
Explanation:
#include "msp430g2553.h"
#define TXLED BIT0
#define RXLED BIT6
#define TXD BIT2
#define RXD BIT1
const char string[] = { "Hello World\r\n" };
unsigned int i; //Counter
int main(void)
{
WDTCTL = WDTPW + WDTHOLD; // Stop WDT
DCOCTL = 0; // Select lowest DCOx and MODx settings
BCSCTL1 = CALBC1_1MHZ; // Set DCO
DCOCTL = CALDCO_1MHZ;
P2DIR |= 0xFF; // All P2.x outputs
P2OUT &= 0x00; // All P2.x reset
P1SEL |= RXD + TXD ; // P1.1 = RXD, P1.2=TXD
P1SEL2 |= RXD + TXD ; // P1.1 = RXD, P1.2=TXD
P1DIR |= RXLED + TXLED;
P1OUT &= 0x00;
UCA0CTL1 |= UCSSEL_2; // SMCLK
UCA0BR0 = 0x08; // 1MHz 115200
UCA0BR1 = 0x00; // 1MHz 115200
UCA0MCTL = UCBRS2 + UCBRS0; // Modulation UCBRSx = 5
UCA0CTL1 &= ~UCSWRST; // **Initialize USCI state machine**
UC0IE |= UCA0RXIE; // Enable USCI_A0 RX interrupt
__bis_SR_register(CPUOFF + GIE); // Enter LPM0 w/ int until Byte RXed
while (1)
{ }
}
#pragma vector=USCIAB0TX_VECTOR
__interrupt void USCI0TX_ISR(void)
{
P1OUT |= TXLED;
UCA0TXBUF = string[i++]; // TX next character
if (i == sizeof string - 1) // TX over?
UC0IE &= ~UCA0TXIE; // Disable USCI_A0 TX interrupt
P1OUT &= ~TXLED; }
#pragma vector=USCIAB0RX_VECTOR
__interrupt void USCI0RX_ISR(void)
{
P1OUT |= RXLED;
if (UCA0RXBUF == 'a') // 'a' received?
{
i = 0;
UC0IE |= UCA0TXIE; // Enable USCI_A0 TX interrupt
UCA0TXBUF = string[i++];
}
P1OUT &= ~RXLED;
}
During routine maintenance on your server, you discover that one of the hard drives on your RAID array is starting to go bad. After you replace the drive and rebuild the data, you run diagnostics on the RAID controller card with no problems, so you believe you fixed the problem. The next morning you arrive at work and discover that the RAID has completely failed. None of the disks are working. Your server is still running because you installed the OS on a non-RAID disk, but all the data is missing, and the server shows that none of your RAID disks are found.What might be the problem with your server? (Select all that apply.)asked Aug 13, 2019 in Computer Science & Information Technology by fili1001A. MotherboardB. CPUC. RAMD. RAID controllerE. Power supply
Answer:
RAID controller or Motherboard ie. A and D
Explanation:
From the explaination on the question the two most likely system parts that may be affecting the server are the Raid controller and the Motherboard.
The raid controller, this is because after the other drive has been replaced, the Raid still failed, it needs to be checked properly and replaced.
The motherboard, this is because it is the core centre of all boards.
Suppose that we have a set of activities to schedule among a large number of lecture halls, where any activity can take place in any lecture hall. We wish to schedule all the activities using as few lecture halls as possible. Give an efficient greedy algorithm to determine which activity should use which lecture hall.
Final answer:
An efficient greedy algorithm to determine which activity should use which lecture hall can be based on the number of conflicts between activities. This algorithm prioritizes activities based on their start time and assigns them to available lecture halls.
Explanation:
An efficient greedy algorithm to determine which activity should use which lecture hall can be based on the number of conflicts between activities. The algorithm can be implemented as follows:
Sort the activities based on their start time.Initialize an empty list to store the lecture halls.For each activity, check if there is a lecture hall available that doesn't conflict with any existing activities.If there is, assign the activity to that lecture hall. If not, create a new lecture hall and assign the activity to it.Continue this process for all activities.This algorithm will ensure that activities are scheduled in a way that minimizes the number of lecture halls required. By prioritizing activities based on their start time and assigning them to available lecture halls, conflicts can be reduced, leading to more efficient scheduling.
Write a function with local functions that calculates the volume, side areas, and total surface area of a box based on the lengths of the sides. It will have 3 inputs: the length, width, and height of the box. There will be no outputs since it will simply print the results to the screen.
Answer:
def calcBox(l, w, h): vol = l*w*h print("Volume is :" + str(vol)) sideArea1 = h*w sideArea2 = h*w sideArea3 = h*l sideArea4 = h*l sideArea5 = w*l sideArea6 = w*l print("Side Area 1: " + str(sideArea1)) print("Side Area 2: " + str(sideArea2)) print("Side Area 3: " + str(sideArea3)) print("Side Area 4: " + str(sideArea4)) print("Side Area 5: " + str(sideArea5)) print("Side Area 6: " + str(sideArea6)) surfAreas = 2*h*w + 2*h*l + 2*w*l print("Total surface areas is: " + str(surfAreas)) calcBox(5, 8, 12)Explanation:
Firstly, create a function calcBox that takes three inputs, l, w, and h which denote length, width and height, respectively.
Apply formula to calculate volume and print it out (Line 2-3).
Since there are six side areas of a box, and we define six variables to hold the calculated value of area for one side respectively (Line 5 - 10) and print them out (Line 11-16).
Apply formula to calculate surface areas and print it out (Line 18 - 19)
At last test the function (Line 21).
The Online Shopping system facilitates the customer to view the products, inquire about the product details, and product availability. It allows the customer to get register in order to purchase products. The customer can search products by browsing different product categories or by entering search keywords. Customer can place order and pay online. There are two acceptable payment methods. These are (1) pay by credit card and (2) pay by PayPal. The system provide service to seller to place the products for selling. The seller creates account to become the member and places his products under suitable product category. The systems allows the administrator to manage the products. It facilitates the administrator to modify the existing products categories or to add new products categories. The system facilitate site manager to view different reports including (1) order placed by customers, (2) products added by sellers, and (3) accounts created by users. Question 3.4.1 List software system actors. (10 points) Question 3.4.2 Write use cases associated with each stakeholder. (Note: each use case starts with an action word) (10 points)
Answer:
see explaination
Explanation:
We will consider the five Actors in the prearranged Online shopping software system:
Customer:
The scheme allows the customer to do below mention actions:
View goods and inquire about the niceties of products and their ease of use.
To create version to be able to purchase invention from the structure.
Browse crop through search category or shortest search alternative.
Place order for the necessary crop.
Make sum for the order(s) positioned.
Payment System:
Payment system allows client to pay using subsequent two methods:
Credit card.
PayPal.
Seller:
System allow seller to perform underneath actions:
Place the foodstuffs for selling under apposite product category.
Create account to happen to a member.
Administrator:
Following actions are perform by Admin:
Manage the goods posted in the system.
Modify existing manufactured goods categories or add novel categories for foodstuffs.
Site Manager:
System privileges Site director with the following role in the system:
View information on:
Orders Placed by customer
Products added by seller
Accounts created by users
check attachment
Write a program that will open a file named thisFile.txt and write every other line into the file thatFile.txt. Assume the input file (thisFile.txt) resides in the same directory as your code file, and that your output file (thatFile.txt) will reside in the same location. Do not attempt to read from or write to other locations.
Answer:
Check the explanation
Explanation:
The programmable code to solve the question above will be written in a python programming language (which is a high-level, interpreted, general-purpose programming language.)
f = open('thisFile.txt', 'r')
w = open('thatFile.txt', 'w')
count = 0
for line in f:
if count % 2 == 0:
w.write(line)
count += 1
w.close()
f.close()
5. Modify the file by allowing the owner to remove data from the file: a. Ask the owner to enter a description to remove b. If the description exists, remove the coffee name and the quantity c. If the description is not found, display the message: That item was not found in the file. 6. Modify the file by allowing the owner to delete data from the file: a. Ask the owner to enter a description to delete b. If the description exists, delete the coffee name and the quantity c. Replace the name and quantity of the coffee removed in step b by asking the user to enter a new coffee name and quantity d. If the description i
Answer:
Check the explanation
Explanation:
Code:
# 3------reading Coffe shop Inventory file
f = open('coffeeInventory.txt','r+')#opening file in reading mode
f1 = f.readlines()
numPounds = 0
for i in range(len(f1)):
print(f1[i].split('\n')[0])
if i!=0:
numPounds+=(int((f1[i].split('\n')[0]).split(';')[1]))
#Total pounds of coffee
print("Total pounds of Coffee:",numPounds)
f.close()#closing file
#4---------
f = open('coffeeInventory.txt','a+')#opening file in appending mode
#appending records
f.write('\nGuatemala Antigua;22')
f.write('\nHouse Blend;25')
f.write('\nDecaf House Blend;16')
f.close()#closing file
#5--------
#removing the record as per owner's description
Description = input("enter Description to remove:")
f = open('coffeeInventory.txt','r')#opening files in reading mode
f1 = f.readlines()
found = -1
for i in range(len(f1)):
line = f1[i].split('\n')[0]
des = line.split(';')[0]
if des==Description:
found = i
#storing the previous data
f2= open('coffeeInventory_pre.txt','w+')
f2.writelines(f1)
f2.close()
#removing the data if found
if found==-1:
print("The item was not found in the file")
else:
f1.remove(f1[found])
data_list = f1
f.close()
#modifying file after removing
modify_file = open('coffeeInventory.txt','w+')
for x in data_list:
modify_file.write(x)
modify_file.close()
f.close()
#6--------------
#deleting the record as per owner's description
Description = input("enter Description to delete:")
f = open('coffeeInventory.txt','r')#opening files in reading mode
f1 = f.readlines()
found = -1
for i in range(len(f1)):
line = f1[i].split('\n')[0]
des = line.split(';')[0]
if des==Description:
found = i
if i==-1:
print("The item was not found in the file")
else:
f1.remove(f1[found])
data_list = f1
f.close()
# deleting in the pre_Coffee_inventory file
#finding record
f2 = open('coffeeInventory_pre.txt','r')
f3 =f2.readlines()
found = -1
for i in range(len(f3)):
line = f3[i].split('\n')[0]
des = line.split(';')[0]
if des==Description:
found = i
if i==-1:
print("The item was not found in the file")
else:
f3.remove(f3[found])#deleting record
data_list1 = f3
f2.close()
#modifying pre file
f2 = open('coffeeInventory_pre.txt','w+')
f2.writelines(data_list1)
f2.close()
#opening file in writing mode
modify_file = open('coffeeInventory.txt','w+')
modify_file.writelines(data_list)
modify_file.close()
Answer:
See explaination
Explanation:
#5
#removing the record as per owner's description
Description = input("enter Description to remove:")
f = open('coffeeInventory.txt','r')#opening files in reading mode
f1 = f.readlines()
found = -1
for i in range(len(f1)):
line = f1[i].split('\n')[0]
des = line.split(';')[0]
if des==Description:
found = i
#storing the previous data
f2= open('coffeeInventory_pre.txt','w+')
f2.writelines(f1)
f2.close()
#removing the data if found
if found==-1:
print("The item was not found in the file")
else:
f1.remove(f1[found])
data_list = f1
f.close()
#modifying file after removing
modify_file = open('coffeeInventory.txt','w+')
for x in data_list:
modify_file.write(x)
modify_file.close()
f.close()
#6
#deleting the record as per owner's description
Description = input("enter Description to delete:")
f = open('coffeeInventory.txt','r')#opening files in reading mode
f1 = f.readlines()
found = -1
for i in range(len(f1)):
line = f1[i].split('\n')[0]
des = line.split(';')[0]
if des==Description:
found = i
if i==-1:
print("The item was not found in the file")
else:
f1.remove(f1[found])
data_list = f1
f.close()
# deleting in the pre_Coffee_inventory file
#finding record
f2 = open('coffeeInventory_pre.txt','r')
f3 =f2.readlines()
found = -1
for i in range(len(f3)):
line = f3[i].split('\n')[0]
des = line.split(';')[0]
if des==Description:
found = i
if i==-1:
print("The item was not found in the file")
else:
f3.remove(f3[found])#deleting record
data_list1 = f3
f2.close()
#modifying pre file
f2 = open('coffeeInventory_pre.txt','w+')
f2.writelines(data_list1)
f2.close()
#opening file in writing mode
modify_file = open('coffeeInventory.txt','w+')
modify_file.writelines(data_list)
modify_file.close()
Below is a sequence of 32-bit memory address references observed during the execution of an application, and given as word addresses.
3, 180, 43, 2, 191, 88, 190, 14, 181, 44, 186, 253
For each of these references, identify the binary address, the tag, and the index given a direct mapped cache with 16 one-word blocks. Also list if each reference is a hit or a miss, assuming the cache is initially empty
Answer:
a. 1 word
b. 2 words
Explanation:
We say that a computer has a 32-bit memory address when it allows 32-bit memory addresses. This entails that a byte-addressable 32-bit computer can address 232 = 4,294,967,296 bytes of memory, or 4 gibibytes (GiB). This allows one memory address to be efficiently stored in one word.
See attachment for the analysis on a table.
Each memory address results in a miss because the cache is initially empty. The address is broken down into tag, index, and the hit/miss status is determined. This process helps in understanding the functioning of a direct mapped cache.
Given a sequence of 32-bit memory address references and a direct mapped cache with 16 one-word blocks, let's analyze each memory address:
**Memory Address 3**:Since the cache is initially empty, all references result in a miss. For a 32-bit address, the index is derived from the next 4 bits (considering 16 blocks = 2^4), and the tag is derived from the remaining higher order bits.
Why MUST you request your DSO signed I-20 ship as soon as it is ready and who is responsible to request the I-20?
a. It is required you have an endorsed/signed I-20 when Customs and Border Patrol or police ask for it
b. We only keep an unsigned digital copy and cannot sign an I-20 after the fact
c. It is against U.S. regulations to send digital (signed or not) DS-2019s and must treat I-20s the same
d. You will need all signed original I-20s to make copies to apply for OPT, STEM and H-1B in the future, so get them now!
e. It is the student’s choice to request each term, however, we cannot go back retroactively to provide past copies
f. We can only provide a signed copy of current I-20 and if changes occur from previous semesters that information will not show
g. The original endorsed I-20 signed by a DSO will be destroyed after 30 days of issuance if not picked up, and it cannot be replicated
h. The cost to have I-20 shipped may go up at any time
i. All the above
Answer:
i. All the above
Explanation:
The correct answer is i. All the above
The given options are all correct
The cost of the shipped can increase and it is required to have l-20 signed however it is not signed after the fact, this DSO is destroyed after 30 days of its issuance if it is not being picked which is also not replaceable with the other.
There are different reasons to request DSO signed I-20 ship . They includes the option (All the above).
The I-20 is known to have a lot of purpose for its use as document. It is issued by a U.S. government, and it is also approved by them as a form of educational institution that certifies a student has been admitted to a full-time study program.The I-20 name is called “Certificate of Eligibility” as with it, one is allowed to apply for an F-1 student visa at a U.S. embassy. This document can be used in all situations highlighted above.
Learn more about Request from
https://brainly.com/question/24621985
If you want to prevent users from examining the SQL code that defines a procedure, function, or trigger, you code the CREATE statement with the ________________ option a. PRIVATE b. ENCRYPTION c. HIDE d. THROW
Answer:
b. ENCRYPTION
Explanation:
Encrypted data is commonly referred to as ciphertext, while unencrypted data is called plaintext.
Encryption is a process that encodes a message or file which makes it to be read by certain people only.
Encryption uses an algorithm to scramble, or encrypt, data and then uses a key for the receiving party to unscramble, or decrypt, the information.
Encryption is the option required to prevent users from examining the SQL code.
JAVA
Write a method that takes an int[] array and an int value and returns the first index at which value appears in the array.
If the value does not exist in the array, return -1
For example:
search(new int[]{10, 20, 30, 20}, 20)
Should return 1
Because 20 first appears at index 1 in the array.
search(new int[]{10, 20, 30, 20}, 40)
Should return -1
public int search(int[] array, int value)
{
}
Answer:
public static void main()
{
Scanner console = new Scanner(System.in);
System.out.println("Enter in a value");
int a = console.nextInt();
int[] array = {1,2,3,4,5};
int a1 = search(array, a);
System.out.println(a1);
}
public static int search(int[] array, int value)
{
boolean okay = true;
int b = 0;
for(b = 0; b<=array.length-1; b++)
{
if(value==array[0])
{
okay=true;
}
else
{
okay = false;
}
}
if(okay = true)
{
return b;
}
else
{
return -1;
}
}
Explanation:
Answer:
Answer is in the attached screenshot!
Explanation:
Just iterate through the values in the list - if the value at the index is equal to the one you are searching for, just return that index. If no value is returned then return with -1!
please identify three examples of how the United States is heteronormative
Final answer:
Heteronormativity in U.S. society is evident in legal recognition of heterosexual marriages, social expectations based on traditional gender roles, and media representations that prioritize heterosexual relationships.
Explanation:
Heteronormativity refers to the assumption that heterosexual orientation is the norm and other sexual orientations are considered abnormal. Here are three examples of how U.S. society is heteronormative:
Legal recognition: The U.S. government and many states have historically only recognized heterosexual marriages, excluding same-sex couples from legal recognition and benefits.Social expectations: Traditional gender roles and expectations often assume a heterosexual orientation, such as the expectation that a man and a woman will marry and have children.Media representations: Mainstream media tends to overwhelmingly portray heterosexual relationships as the default, downplaying or erasing the existence of LGBTQ+ relationships.These examples demonstrate how heteronormativity privileges and normalizes heterosexual orientations while marginalizing and stigmatizing non-heterosexual orientations.