Unpaired electron is the electron, that occupies the a place in orbital without the pair of electron. The number of unpaired electron in 3d sub shell of octahedral coordination complex [tex][FeX_6]^{2-}[/tex] is 3.
The given octahedral coordination complex in the problem is [tex]{FeX_6]^{2-}[/tex]
Here, [tex]X[/tex] is the halogen.
What is unpaired electron?Unpaired electron is the electron, that occupies the a place in orbital without the pair of electron.
In the given complex ion +3 oxidation state [tex]F[/tex] (iron) represents in,
[tex]_{26}F^{3+}=1s^2, 2s^2 2p^6, 3s^23p^63d^6,4s^2\\[/tex]
[tex]F^{3+}=1s^2, 2s^2 2p^6, 3s^23p^63d^6[/tex]
As the unpaired electron in 3d sub shell is 3.
Hence the number of unpaired electron in 3d sub shell of octahedral coordination complex [tex][FeX_6]^{2-}[/tex] is 3.
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Final answer:
The [FeX₆]³− octahedral complex, with iron in a d5 configuration and halides as weak field ligands, will have five unpaired electrons due to the high-spin configuration created by the ligands.
Explanation:
To determine the number of unpaired electrons in the octahedral coordination complex [FeX₆]³−, where X represents any halide, we will apply crystal field theory (CFT). First, we note that iron in this complex exists in a +3 oxidation state, which gives it a d5 electron configuration since the neutral iron atom has 8 valence electrons (3d6 4s2).
For any halide as a weak field ligand in an octahedral complex, the crystal field splitting is not sufficient to overcome the electron pairing energy. This results in a high-spin complex for iron (III), where all the d-orbitals initially receive one electron each before any pairing occurs.
Thus, the [FeX₆]³− complex will have five unpaired electrons, one in each of the 3d orbitals, as halides create a high-spin configuration for a d5 metal ion like iron (III).
Choose the statement about nuclear fusion that is always correct?
A) Very little energy is released in fusion processes.
B) Due to its instability, 56Fe readily undergoes fusion.
C) Nuclear fusion is an energetically favorable process for lighter atoms.
D) In fusion reactions, a proton and an electron combine to create a neutron.
EDIT: THE ANSWER IS (C)
A person on earth would weigh a lot more on the sun due to increased ________________. gravity mass atoms energy
Emily finds a rock with crystals 2 cm large. Her rock _____.
Assume that you have two objects, one with a mass of 6 kg and the other with a mass of 17 kg, each with a charge of −0.027 c and separated by a distance of 3 m. what is the electric force that these objects exert on one another? answer in units of n. what is the gravitational force between them? answer in units of n.
Electric force is the attractive or reflective force of interception between two charged object.
A) The electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.B) The gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.Given information-
The mass of first object is 6 kg.
The mass of second object is 17 kg.
The charge on both the object is 0.027 C.
The distance between the two object is 3 m.
What is electric force?Electric force is the attractive or reflective force of interception between two charged object. It can be calculated using the Coulomb's law as,
[tex]F=k_e\dfrac{q_1\q_2}{r^2}[/tex]
Here, [tex]q[/tex] is the charge on the object and [tex]r[/tex] is the distance between the objects. [tex]k_e[/tex] is coulombs constant [tex](8.987\times 10^9)[/tex] N-m squared per C squared.
A) Electric force that these objects exert on one another-Put the values in above formula to find out the electric force between given objects-
[tex]F=8.987\times10^9\dfrac{(-0.027)\times(-0.027)}{3^2}\\F=7.28\times 10^5[/tex]
Hence the electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.
B) Gravitational force between them-Gravitational force between two object with mass [tex]m_1[/tex] and [tex]m2[/tex] can be given as,
[tex]F_g=G\dfrac{m_1m_2}{r^2}[/tex]
Here [tex]G=6.67\times 10^{-11}[/tex] N-m squared per kg squared.
Put the values,
[tex]F_g=6.67\times 10^{-11}\times\dfrac{6\times17}{3^2}\\F_g=7.56\times10^{-10}[/tex]
Thus, the gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.
Hence,
The electric force that these objects exert on one another is [tex]7.28\times 10^5[/tex] N.The gravitational force between them is [tex]7.56\times10^{-10}[/tex] N.Learn more about the electric force here;
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Final answer:
The electric force and gravitational force between two objects can be calculated using specific laws involving charge, mass, and distance.
Explanation:
The electric force between two objects can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The gravitational force between the two objects can be determined using Newton's Law of Universal Gravitation, where the force is proportional to the product of the masses and inversely proportional to the square of the distance between them.
what is showed in the diagram /Users/jacinta/Desktop/NNNNNN.png
What is the acceleration of a skateboarder of mass 46 kg who is being pushed forward with a force 120N?
Answer:
The acceleration of this skateboarder is 2.61 m/s^2.
Explanation:
120=46*a
/46 /46
2.61 m/s^2=a
How many electrons must be removed from an electrically neutral silver dollar to give it a charge of +2.4 μC?
The total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.
Charge and ElectronA charge can be defined as a property of any matter that causes it to experience a force when it's placed in an electric or magnetic field. The electron is negatively charged. The value of an electron charge is [tex]1.6\times 10^{-19}\;\rm C[/tex]
Given that the neutral silver dollar has a charge [tex]q = +2.4 \mu \rm C[/tex] .
The charge can be given as,
[tex]q=ne[/tex]
Where n is the number of electrons. Thus,
[tex]n =\dfrac { q}{e}[/tex]
[tex]n = \dfrac {+2.4 \times 10 ^{-6}}{1.6\times 10^{-19}}[/tex]
[tex]n = 1.5 \times 10^{13}[/tex]
Hence we can conclude that the total number of electrons removed from the neutral silver dollar is [tex]1.5 \times 10^{13}[/tex] electrons.
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Which color in the visible spectrum has the highest frequency?
Violet waves have the most energy of the visible spectrum.
Remember: c=fλ
Therefore: f=c/λ
Here c is the speed of light in a vacuum.
So:
As wavelength decreases, frequency increases and, as E=hf, where h is constant (Planck's constant), so does the energy that the waves carry. Waves with a short wavelength have the most energy.
Red waves have a relatively long wavelength (in the 700 nm range), and violet waves are much shorter - roughly half that.Violet is the color in the visible spectrum that has the highest frequency. (option b)
The visible spectrum consists of various colors that we can see with our eyes, ranging from red to violet. Each color corresponds to a specific wavelength of light. Wavelength is the distance between consecutive peaks (or troughs) of a wave. The frequency of a wave, on the other hand, refers to how many waves pass a particular point in space per unit of time.
The relationship between frequency (f), wavelength (λ), and the speed of light (c) can be described by the equation:
c = f × λ
where c is the speed of light in a vacuum (approximately 3 × 10^8 meters per second), f is the frequency, and λ is the wavelength.
As per this equation, the higher the frequency of light, the shorter the wavelength. Conversely, the lower the frequency, the longer the wavelength.
Hence the correct option is (b),
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Complete Question:
Which color in the visible spectrum has the highest frequency?
a) Blue
b) Violet
c) Green
d) Red
How is the size of a planet related to the thickness of its atmosphere?
An electron has kinetic energy 3.00 ev. find its wavelength.
In the absence of air resistance and friction, what will happen to the velocity of an object going at 20 m/s E?
Light of wavelength 520 nm passes through a slit of width 0.220 mm. (a) the width of the central maximum on a screen is 8.30 mm. how far is the screen from the slit?
What would the potential of a standard hydrogen electrode (s.h.e.) be under the given conditions? [h+]=0.70 mph2=2.4 atmt=298 k?
A monochromatic laser is exciting hydrogen atoms from the n=2 state to the n=5 state. part a what is the wavelength λ of the laser?
help asap please!! An aluminum block of mass 12.00 kg is heated from 20 C to 118 C. If the specific heat of aluminum is 913 J-1 kg K-1 then how much energy is required?
A. 10.956 kJ
B. 1073.688 kJ
C. 64.640 kJ
D. 7456.167 kJ
a star with an original mass of 8 to 25 solar masses will ultimately become a ?
a) red giant
b)white dwarf
c) neutron star
d)main sequence star
A diver 40 m deep in 10∘C fresh water exhales a 1.0-cm-diameter bubble.
What is the bubble's diameter just as it reaches the surface of the lake, where the water temperature is 20∘C? Assume that the air bubble is always in thermal equilibrium with the surrounding water.
Express your answer to two significant figures and include the appropriate units.
The diameter of the air bubble when it reaches the surface is about 1.7 cm
[tex]\texttt{ }[/tex]
Further explanationThe basic formula of pressure that needs to be recalled is:
Pressure = Force / Cross-sectional Area
or symbolized:
[tex]\large {\boxed {P = F \div A} }[/tex]
P = Pressure (Pa)
F = Force (N)
A = Cross-sectional Area (m²)
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
In this problem , we will use Ideal Gas Law as follows:
Given:
initial diameter of bubble = d₁ = 1.0 cm
initial depth of the diver = h = 40 m
initial temperature = T₁ = 10 + 273 = 283 K
atmospheric pressure = Po = 1.0 atm = 10⁵ Pa
final temperature = T₂ = 20 + 273 = 293 K
density of water = ρ = 1000 kg/m³
Unknown:
final diameter of bubble = d₂ = ?
Solution:
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
[tex]\frac{P_1 (\frac{1}{6} \pi (d_1)^3)}{T_1} = \frac{P_2(\frac{1}{6} \pi (d_2)^3)}{T_2}[/tex]
[tex]\frac{P_1 (d_1)^3}{T_1} = \frac{P_2 (d_2)^3}{T_2}[/tex]
[tex]\frac{(P_o + \rho g h ) (d_1)^3}{T_1} = \frac{P_o (d_2)^3}{T_2}[/tex]
[tex]\frac{(10^5 + 1000(9.8)(40) ) (1.0)^3}{283} = \frac{10^5(d_2)^3}{293}[/tex]
[tex]\frac{(492000 ) (1.0)^3}{283} = \frac{10^5(d_2)^3}{293}[/tex]
[tex]d_2 \approx 1.7 \texttt{ cm}[/tex]
[tex]\texttt{ }[/tex]
Learn moreMinimum Coefficient of Static Friction : https://brainly.com/question/5884009The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Pressure
By applying the ideal gas law, we find the diameter at the surface to be approximately 1.7 cm.
To determine the bubble's diameter when it reaches the surface, we use the ideal gas law. Since temperature and volume are directly proportional under constant pressure, we can express this relationship as:
(V₁/T₁) = (V₂/T₂)
where,
V₁ = initial volume of the bubble T₁ = initial temperature of the water (10°C = 283 K)V₂ = final volume of the bubbleT₂ = final temperature of the water (20°C = 293 K)Given that V₁ is π(0.005 m)² * h (since the volume of a sphere is directly proportional to the radius cubed), we know the final volume V₂ will change due to both temperature and the reduction in pressure as the bubble rises.
Hydrostatic pressure P₁ at 40 meters depth is given by:
P₁ = P₀ + ρgh
P₀ = atmospheric pressure = 1 atmρ = density of water ≈ 1000 kg/m³g = 9.8 m/s²h = 40 mP₁ ≈ 1 + (1000 * 9.8 * 40) / 101325 ≈ 4.93 atm
At the surface, the only pressure is P₀ (1 atm).
Using the combined gas law P₁V₁/T₁ = P₂V₂/T₂:
4.93V₁/283 = 1V₂/293
Solving for V₂ we get:
V₂ = 4.93 * V₁ * 293 / 283
V₂ ≈ 5.09 * V₁
Since the volume ratio (D₂/D₁)³ = 5.09, taking the cube root:
D₂ ≈ 1.71 * D₁
So, if initial diameter D₁ is 1.0 cm:
D₂ = 1.71 * 1.0 cm ≈ 1.7 cm
Therefore, the bubble's diameter at the surface is approximately 1.7 cm.
If a spaceship of proper length 40 m is measured to have a length 30 m, how fast is it moving?
Conventionally, the field strength around a charged object is the direction of the force acting on a .
Answer:
Field Strength:Any charged body has the capacity to effect any test charge that comes inside its field or region. It can be also defined as,
"The total amount or magnitude of force,F or intensity felt by any unit test charge when it enters an electromagnetic or electric field."
For an electric field its unit will be, volt per meter or simply V/m.Explanation:
A unit test charge inside an electric field:
When a unit test charge enters a given parameters or area set by the charged particle then it will surely experience a force,F equal to the magnitude of that charge body and it will be different as it continues to move closer or far inside the field.
As, we have, "E=F/q",(where "F" is the field strength and "q" is the unit test charge placed inside the field).how have increased carbon dioxide levels and temperatures affected living organisms
Answer:
Carbon dioxide is a greenhouse gas that traps heat on eath increasing the global average temperature. This for example is melting the arctic ice faster and more than usual. This is leading many arctic species to loose their habitats.
Answer:
Carbon dioxide is a greenhouse gas that traps heat on eath increasing the global average temperature. This for example is melting the arctic ice faster and more than usual. This is leading many arctic species to loose their habitats
Explanation:
twas correct ed2022
What set of simple machines would be needed to create the complex machine shown here?
a brick is suspended above the ground at a height of 6.6 m. it has a mass of 5.3 kg. what is the potential energy of the brick
A mechanical high-speed bat is flying along a path perpendicular to a wall. it emits a sound with a frequency f0 . the night is clear and the air is still. let the speed of sound waves in the still air be vs . the bat hears a sound wave reflected from the wall with a frequency fnew . from this information one can determine the speed vbat at which the bat is flying. install a detector at the wall. 0 bat f v what is the detected frequency? 1. f1 = vs + vbat vs f0 2. f1 = vs vs − vbat f0 3. f1 = vs vs + vbat f0 4. f1 = vs + vbat vs − vbat f0 5. f1 = 2 vs vs − vbat f0 6. f1 = vs − vbat vs f0 7. f1 = vs − vbat vs + vbat f0 8. f1 = f0 9. f1 = 2 vs vs + vbat f0
The detected frequency f1 can be calculated using the Doppler effect formula, which leads to the conclusion that option 3 is the correct answer (f1 = vs / (vs + vbat) * f0). This equation allows to determine the actual speed of the bat.
Explanation:This question can be addressed using the Doppler effect principle, which describes how the frequency of sound changes for an observer moving in relation to a sound source.
Given that the bat is moving perpendicular to the wall with the speed vbat and since the night is clear and air is still (meaning no additional obstructions in the sound path), the detected frequency f1 can be calculated using the Doppler effect formula:
f1 = vs / (vs + vbat) * f0.
Therefore, option 3 is the correct answer. To measure the actual speed of the bat, you can install a detector on the wall and make use of the fact that frequencies f0 and f1 are known and the speed of sound vs is also known or can be easily determined from the conditions (e.g., air temperature).
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The question pertains to the Doppler Effect, and the formula for the detected frequency of the bat's echo, considering the bat's speed, is f1 = vs / (vs + vbat) * f0.
Explanation:The question deals with the concept of the Doppler Effect in physics. This effect relates to the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. In this specific scenario, a mechanical bat emits a sound with a frequency of f0 and moves towards a wall. The sound wave reflects off the wall and returns to the bat. The frequency that the bat hears is affected by its own velocity (vbat) and the speed of sound (vs) in the air around it.
Based on the formulas listed, the correct one is number 3, f1 = vs / (vs + vbat) * f0, based on the standard equation for Doppler Effect when the observer (in this case, the bat) is moving towards a stationary source (in this case, the reflected sound wave). When this happens, the observed frequency increases, since the bat is chasing the sound wave that it emitted.
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The cathode ray tube uses which of the following to direct electron beams...
A) electric fields
B) bar magnets
C) magnetic fields
D) gravitational field
Also...what did the cathode ray tube allow J.J. Thomson to do?
A) study static charges in electric fields
B) study and discover the positively charged nucleus
C) study moving electrons in the presence of a magnetic field
D) study the shapes of magnetic fields around solenoids.
Thanks! :)
A metallic object is given a positive charge by the process of induction, as illustrated in Figure 18.8. (a) Does the mass of the object increase, decrease, or remain the same? Why? (b) What happens to the mass of the object if it is given a negative charge by induction? Explain.
What is the frequency of a photon that has the same momentum as a neutron moving with a speed of 1.90 × 103 m/s?
The frequency of a photon can be determined by relating its momentum to the speed of a neutron. The resulting frequency is 4.8 × 10¹4 Hz.
The frequency of a photon can be calculated using the relation between momentum and speed. Given that the speed of a neutron is 1.90 × 103 m/s, the frequency of the photon with the same momentum would be 4.8 × 10¹4 Hz.
A teacher pushed a 98 newton desk across a floor for a distance of 5 meter he exerted a horizontal force of 20 newton for four seconds
The work done by the teacher in pushing the desk is calculated by multiplying the force exerted (20 newtons) by the distance covered (5 meters), which gives a total work done of 100 joules.
Explanation:To calculate the amount of work done in moving an object, we use the formula: Work = Force x Distance.
In this case, the teacher exerted a force of 20 newtons across a distance of 5 meters. Therefore the work is calculated as: 20N x 5m = 100 joules.
To summarise, the teacher did 100 joules of work on the desk when pushing it through a 5 meter distance.
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The complete question is here:
A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. She exerted a horizontal force
of 20 newtons. How much work was done?
Why does the sound of something moving away from you seem to change to a lower and lower pitch?
A) As the source moves away, the increased distance creates more interference; so the pitch drops.
B) As the source moves away, the frequency of the sound waves is being compressed, so the pitch drops.
C) As the source moves away, the sound waves speed up to reach the observer; this causes the pitch to drop.
D) As the source moves away, the sound waves stretches out relative to the person standing still; so the pitch drops.
What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 8.0 nc ?
The calculation of escape speed from a charged glass sphere involves principles from electrostatics and classical mechanics, requiring an understanding of how kinetic and electric potential energies equate as an electron moves away from the sphere. Unfortunately, without detailed formulae specific to this electrostatic scenario, a precise answer cannot be provided here.
Explanation:The question involves calculating the escape speed of an electron from a charged glass sphere, which is a task that falls under the domain of electrostatics and classical mechanics in physics. Generally, the escape speed from a celestial body like Earth is determined by its mass and the gravitational forces involved. However, in this electrostatic context, the key forces are electrical, not gravitational. The escape speed in this scenario would depend on the electric potential energy and kinetic energy equivalence. Given the unique nature of the question which combines concepts from electrostatics with classical escape velocity calculations, a straightforward formula application from physics textbooks might not directly apply without considering the electric force on the electron due to the charged sphere. Nonetheless, the principle remains that to calculate escape speed, one would need to equate the kinetic energy of the electron with the work done against the electric force as it moves to infinity (where the electrical potential energy becomes zero).
The escape speed of an electron from the surface of a charged sphere can be found using the formula, yielding approximately 162 meters per second. This is derived considering the charge of the sphere, its radius, and Coulomb's constant.
To find the escape speed of an electron from a charged sphere, you need to use the concept of electric potential energy and kinetic energy. The escape speed, vesc, is given by:
vesc = √((2 * k * Q) / r)where Q is the charge of the sphere, r is the radius of the sphere, and k is Coulomb's constant (k = 8.99 × [tex]10^9[/tex] N [tex]m^2[/tex]/[tex]C^2[/tex]).
Given:
Diameter of the sphere = 1.1 cm → radius, r = 0.55 cm = 0.0055 mCharge of the sphere, Q = 8.0 nC = 8.0 × [tex]10^{-9}[/tex] CUsing the formula:
vesc = √((2 * 8.99 × [tex]10^9[/tex] N [tex]m^2[/tex]/[tex]C^2[/tex] * 8.0 × [tex]10^{-9}[/tex] C) / 0.0055 m)vesc = √((1.4384 × [tex]10^2[/tex] ) / 0.0055 m)vesc ≈ √(2.6145 × [tex]10^4[/tex])vesc ≈ 162 m/sThus, the escape speed of the electron from the surface of the charged sphere is approximately 162 meters per second.
A vertical polarizing filter is used on the lens of a camera. Which waves do not strike the lens?