Determine the solution of the following system of equations: *
Captionless Image
No solution
(3, 1)
( 1 , -3 )
Infinite Solutions

Answer:

D

Explanation:

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, the correct option is option D.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter.  Chemical property is a characteristic of matter that describes its ability to change into a different substance.

Therefore, the correct option is option D.

To learn more about matter, here:

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Answer:

There are 0.100 moles chlorine ions (Cl-) involved

Explanation:

Step 1: Data given

Volume of CaCl2 = 25.0 mL = 0.025 L

Molarity of CaCl2 = 2.00 M

Step 2: The balanced equation

CaCl2 (aq) + 2AgNO3 (aq) ⇆ Ca(NO3)2 (aq) + 2AgCI (s)

CaCl2 → Ca^2+ + 2Cl-

Step 3: Calculate moles CaCl2

Moles CaCl2 = molarity CaCl* volume

Moles CaCl2 = 2.00 M * 0.025 L

Moles CaCl2 = 0.050 moles

Step 4: Calculate moles chloride ions

CaCl2 → Ca^2+ + 2Cl-

For 1 mol CaCl2 we have 1 mol Ca^2+ and 2 moles Cl-

Moles Cl- ions = 2*0.050 moles

Moles Cl- ions = 0.100 moles

There are 0.100 moles chlorine ions (Cl-) involved

The reaction of 25.0 mL of a 2.00 M CaCl2 solution provides 0.100 moles of chloride ions for the reaction, based on the stoichiometry that shows each mole of CaCl2 gives two moles of chloride ions.

To calculate how many moles of chloride ions were involved in the reaction where 25.0 mL of a 2.00 M CaCl2 solution is used, we must first understand the stoichiometry of the reaction:

CaCl2(aq) + 2AgNO3(aq) → Ca(NO3)2(aq) + 2AgCl(s)

From the balanced equation, we see that each mole of CaCl2 provides two moles of Cl− ions. To find the moles of CaCl2, we use the concentration and volume of the solution:

(2.00 moles/L) × (0.025 L) = 0.050 moles of CaCl2

Since there are two moles of Cl− for every mole of CaCl2, we multiply the moles of CaCl2 by 2:

0.050 moles × 2 = 0.100 moles of chloride ions

Answer : The partial pressure of [tex]H_2[/tex] at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of [tex]HBr[/tex] = [tex]1.0\times 10^{-2}atm[/tex]

The partial pressure of [tex]H_2[/tex] = [tex]2.0\times 10^{-4}atm[/tex]

The partial pressure of [tex]Br_2[/tex] = [tex]2.0\times 10^{-4}atm[/tex]

[tex]K_p=4.2\times 10^{-9}[/tex]

The balanced equilibrium reaction is,

                                [tex]2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)[/tex]

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant [tex]K_p[/tex] for the reaction will be:

[tex]K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}[/tex]

Now put all the values in this expression, we get :

[tex]4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}[/tex]

[tex]p=-1.99\times 10^{-4}[/tex]

The partial pressure of [tex]H_2[/tex] at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of [tex]H_2[/tex] at equilibrium is, 1.0 × 10⁻⁶

Answer : The pH of the solution will be less than 7.

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

Mathematically,

[tex]pH=-\log [H^+][/tex]

As per question, if there is a high concentration of hydrogen ions then its pH become less than 7 and the solution will be acidic.

Hence, the pH of the solution will be less than 7.

Answer:

low

Explanation:

Answer:

a

Explanation:

0.75

Answer:

the answer is a

Explanation:

Answer:

The new pressure on the gas P2 = 0.10atm

Explanation:

Data;

V1 = 0.084L

P1 = 1.0atm

V2 = 0.785L

P2 = ?

This question is a practical problem where Boyle's law is applied.

According to Boyle's law, the pressure of a fixed mass of gas is inversely proportional to its volume provided that the temperature on the gas remains constant

Mathematically

P = k / v, k = PV

P1*V1 = P2*V2 = P3*V3..........Pn*Vn

P1 * V1 = P2 * V2

Solving for P2,

P2 = (P1 * V1 ) / V2

P2 = (0.084 * 1) / (0.785)

P2 = 0.10atm

The new pressure of the gas is 0.10atm

Final answer:

Using Boyle's Law, we can determine that the pressure inside the vacuum chamber is approximately 0.107 atm when a marshmallow expands from 0.084 L to 0.785 L at constant temperature.

Explanation:

To determine the pressure inside the vacuum chamber where a marshmallow has expanded from 0.084 L to 0.785 L at constant temperature, we can use the gas laws. According to Boyle's Law, at constant temperature for a given mass, the volume of a gas is inversely proportional to the pressure. The formula for Boyle's Law is P1V1 = P2V2, where P denotes pressure and V denotes volume. Using this law, we calculate as follows:

P1V1 = P2V2

1.0 atm × 0.084 L = P2 × 0.785 L

P2 = (1.0 atm × 0.084 L) / 0.785 L

P2 = 0.084 atm / 0.785

P2 = 0.107 atm

Thus, the pressure inside the vacuum chamber is approximately 0.107 atm when the volume of the marshmallow is 0.785 L.

Answer:

a) ΔG = 1688.5 J/mol = 1.7  kJ/mol

b) ΔG = 21673.3  J/mol = 21.7  kJ/mol

Explanation:

Step 1: Data given

Temperature = 20.0 °C = 293 K

Initial temperature = 1.0 bar = 0.986923 atm

Final temperature = 2.0 bar = 1.97385 atm

Step 2: Calculate

ΔG = RT * ln (Pt / Pi)

⇒with R = 8.314 J/K* mol

⇒with T = 293K

⇒with Pt = final pressure = 1.97385 atm

⇒with Pi = the initial pressure = 0.986923 atm

ΔG = 8.314 J/mol*K *293 K * ln (1.97385/0.986923)

ΔG = 8.314 J/mol*K *293 K * 0.693

ΔG = 1688.5 J/mol = 1.7  kJ/mol

(b) 0.000 27 atm

Step 3:

ΔG = RT * ln (Pt / Pi)

⇒with R = 8.314 J/K* mol

⇒with T = 293K

⇒with Pt = final pressure = 1.97385 atm

⇒with Pi = the initial pressure = 0.00027 atm

ΔG = 8.314 J/mol*K *293 K * ln (1.97385/0.00027)

ΔG = 8.314 J/mol*K *293 K * 8.897

ΔG = 21673.3  J/mol = 21.7  kJ/mol

The molar Gibbs energy change of carbon dioxide at 20°C when its pressure is changed from 1.0 bar to 2.0 bar is 4.08 kJ/mol, and when changed from 1.0 bar to 0.00027 atm is -34.65 kJ/mol.

The molar Gibbs energy change of a substance can be calculated using the equation ΔG = RT ln(Pf/Pi), where ΔG is the change in molar Gibbs energy, R is the universal gas constant, T is the absolute temperature, Pf is the final pressure, and Pi is the initial pressure.

Given that temperature (T) is 20°C or 293.15 K, R is 8.314 J/K/mol (universal gas constant), Pi is 1.0 bar, and the pressures Pf are (a) 2.0 bar and (b) 0.00027 atm respectively. We also note that 1 bar is roughly equivalent to 0.986923 atm.

(a) When Pf is 2.0 bar, ΔG = (8.314 J/K/mol)*293.15 K*ln(2.0/1.0) = 4.08 kJ/mol.

(b) When Pf is 0.00027 atm, ΔG = (8.314 J/K/mol)*293.15 K*ln(0.00027/0.986923) = -34.65 kJ/mol.

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Answer:

plz mark as brainliest

Explanation:

OZONE

Earth keeps a nearly steady temperature, because it makes heat in its interior. In other words, Earth has been losing heat since it formed, billions of years ago. But it’s producing almost as much heat as it’s losing. The process by which Earth makes heat is called radioactive decay.

Answer:

what is the English translation, id like to help

Explanation:

Answer: Sufficient amount of energy and appropriate orientation.

Explanation:

A chemical reaction is most likely to occur when reactant particles collide with sufficient amount of energy needed to break bonds and

appropriate orientation .

Answer: an air compressor and desk chair.

Explanation:

Final answer:

Two fluid technologies that make use of air are the Bunsen burner and the atomizer, both operating based on entrainment principles to achieve proper combustion or to create a fine mist spray.

Explanation:

The use of air in fluid technologies is demonstrated through various devices that rely on fluid dynamics. Two specific technologies that utilize air are the Bunsen burner and the atomizer. The Bunsen burner uses an adjustable gas nozzle to entrain air, which is necessary for proper combustion. Atomizers employ a squeeze bulb to create a jet of air that entrains small droplets, such as drops of perfume, allowing them to be sprayed as a fine mist.

These technological applications are significant in daily practices and across several industries. The principle at work in both the Bunsen burner and atomizer is the creation of low-pressure areas through increased fluid speed, causing air to be entrained with another fluid or gas for a particular purpose.

Answer:

Nuclear energy

Explanation:

hope this helps

Answer:

Surface area of the reactants

Explanation:

If the reactants say Cu is in the powdered form, it reacts very quickly, otherwise the reaction will be delayed

Answer:

Surface Area and concentration

Explanation:

One of the most important factors that affect the rate of chemical reaction is the surface area of reactants. Surface area of reactants has to do with the number of particles of reactants exposed for reaction. In the reaction;

2AgNO3(aq) + Cu(s) -------> Cu(NO3)2(aq) + 2Ag(s), the most important factors affecting the rate of reaction are surface area of the solid copper metal and the concentration of the silver nitrate solution.

If copper turnings are used, the reaction will proceed faster than when a lump of copper is used. This is the effect of surface area in rate of reaction.

The higher the concentration of the solve nitrate solution, the faster the rate of reaction also. Hence the answer.

Answer:

if multiple choice e. d. a. if not e.

Explanation:

Answer:

-0.6⁰c

Explanation:

find the solution below

Answer:

pH = 4.17

Explanation:

According to the molar concentration you stated, pH of the solution is: 4.17

Remember that pH = - log [H⁺]

and [H⁺] = 10^-pH

When:

pH > 7 →  Basic solution

pH = 7 → Neutral solution

pH < 7 → Acid solution

Answer:

It is higher than that of water

Explanation:

Because we now know that through experimentation, the new compound has a higher and stronger hydrogen bonds than water, the specific heat capacity will be higher.

Specific heat capacity is the amount of heat needed to raise the temperature of a unit mass of as substance by 1°C.

Answer:

It is higher than that of water

Explanation:

i just finnished the quiz

The properties of elements and compounds.

2. A compound is either molecular or ionic in nature.

3. Most molecular compounds are composed of two or more atoms.

4. Molecules consisting of two atoms are diatomic molecules.

5. The chemical formula of a molecular compound is a molecular formula.

6. Molecular compounds tend to have low melting and boiling points.

7. Ionic compounds tend to have high melting and boiling points.

8. A molecular formula shows how many atoms of each element a molecular contains, but it does not indicate the structure of the molecule.

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Answer:

Power plants.

Explanation:

When power plants start the burning coal process, the chemical bonds carrying its carbon atoms are brake down and releasing energy also carrying heavy metals such as lead, mercury, and cadmium into the atmosphere.

When the sulfur which is present in coal reacts with oxygen it produces sulfur dioxide and they the ability to combines with other lethal toxic molecules that are found in the atmosphere and form small, acidic particulates that can cause several diseases in humans.

Final answer:

Isotopes are versions of an element with the same number of protons but different numbers of neutrons, such as carbon-12 and carbon-14. To find the number of protons, neutrons, and electrons in an atom, you need the atomic number and mass number. Radioactive isotopes decay to more stable forms, releasing particles and energy.

Explanation:

Isotopes are different forms of an element that have the same number of protons but a different number of neutrons. For example, whereas carbon-12 has six protons and six neutrons, carbon-14 has six protons and eight neutrons. Both isotopes of carbon have six electrons since the number of electrons is defined by the number of protons to maintain a neutral charge. Radioactive isotopes, or radioisotopes, may emit particles and energy, transforming into more stable forms and losing potential energy in the process.

To determine the number of protons, neutrons, and electrons in an atom with a given mass number, you first need to know the element's atomic number (number of protons) and mass number. The atomic number is equal to the number of protons and electrons (in a neutral atom). The number of neutrons can be found by subtracting the atomic number from the atomic mass number. For instance, carbon-14, with an atomic number of 6 and a mass number of 14, has 6 protons, 8 neutrons (14 - 6), and 6 electrons.

Answer : The value of the rate constant for the forward reaction at 700 K is, [tex]4.70\times 10^6[/tex]

Explanation :

The given chemical equilibrium reaction is:

[tex]NO(g)+O_2(g)\rightleftharpoons NO_2(g)[/tex]

The expression for equilibrium constant is:

[tex]K_c=\frac{[NO_2]}{[NO][O_2]}[/tex]

The expression for rate of forward and backward reaction is:

[tex]R_f=K_f[NO][O_2][/tex]

and,

[tex]R_b=K_b[NO_2][/tex]

As we know that at equilibrium rate of forward reaction is equal to rate of backward reaction.

[tex]R_f=R_b[/tex]

[tex]K_f[NO][O_2]=K_b[NO_2][/tex]

[tex]\frac{K_f}{K_b}=\frac{[NO_2]}{[NO][O_2]}[/tex]

[tex]\frac{K_f}{K_b}=K_c[/tex]

Given:

[tex]K_c=8.7\times 10^6[/tex]

[tex]K_b=0.54M^{-1}s^{-1}[/tex]

Now put all the given values in the above expression we get:

[tex]\frac{K_f}{K_b}=K_c[/tex]

[tex]\frac{K_f}{0.54}=8.7\times 10^6[/tex]

[tex]K_f=4.70\times 10^6[/tex]

Therefore, the value of the rate constant for the forward reaction at 700 K is, [tex]4.70\times 10^6[/tex]

Final answer:

The rate constant for the forward reaction of NO with O2 forming NO2 at 700 K, given the equilibrium constant and the reverse reaction rate, is calculated to be 4.698 × 10^6 M⁻¹s⁻¹.

Explanation:

The question asks for the rate constant for the forward reaction of NO(g) reacting with O₂(g) to form NO₂(g) at 700 K, given the equilibrium constant (KC) and the rate constant for the reverse reaction. To find the rate constant for the forward reaction (kf), we use the relationship between the equilibrium constant and the rate constants of the forward and reverse reactions, which is KC = kf / kr. Given KC = 8.7 × 106 and the reverse rate constant (kr = 0.54 M⁻¹s⁻¹), we can rearrange the formula to solve for kf: kf = KC × kr. Substituting the given values yields kf = 8.7 × 106 × 0.54 M⁻¹s⁻¹ = 4.698 × 106 M⁻¹s⁻¹.

Answer:

1. iron(III) oxide

2. 8

3. 8

Explanation:

Know the naming rules

Reactants on left side products on right side

The first reactant is Fe2O3, with 5 total atoms on both sides.

The first reactant in the equation Fe2O3 + 3C —> 2Fe + 3CO is Fe2O3, which represents iron(III) oxide.

On the reactant side, there are a total of 5 atoms (2 Fe atoms and 3 O atoms from Fe2O3, and 3 C atoms).

On the product side, there are a total of 5 atoms (2 Fe atoms from 2Fe and 3 C atoms from 3CO).

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There are approximately 0.0105 grams of methylamine in 100.0 mL of the solution.

To solve this problem, we need to follow these steps:

**1. Calculate the hydroxide ion concentration:**

* pH = 10.68

* pOH = 14 - pH = 3.32

* [OH-] = 10^(-pOH) = 10^(-3.32) = 4.74 x 10^-4 M

**2. Calculate the Kb of methylamine:**

* Ka = 2.5 x 10^-11 (pKa = 10.60)

* Since methylamine is a weak base, Kb = 1/Ka = 4.0 x 10^-4

* Kb = [CH3NH3+][OH-] / [CH3NH2]

**3. Express the concentration of CH3NH2 in terms of the remaining concentration:**

* Let x be the initial concentration of CH3NH2 (in M).

* At equilibrium, some CH3NH2 will react with water, forming CH3NH3+ and OH-.

* The remaining concentration of CH3NH2 will be x - [OH-].

**4. Substitute concentrations and solve for x:**

* Kb = [CH3NH3+][OH-] / [CH3NH2]

* Kb = ((x - [OH-]) * [OH-]) / (x - [OH-])

* 4.0 x 10^-4 = (x * 4.74 x 10^-4) / (x - 4.74 x 10^-4)

* Solving this equation for x gives x = 0.0034 M

**5. Calculate the moles and grams of methylamine:**

* Moles of CH3NH2 = (0.0034 M) * (0.1 L) = 0.00034 mol

* Molar mass of CH3NH2 = 31.05 g/mol

* Mass of CH3NH2 = (0.00034 mol) * (31.05 g/mol) = 0.0105 g

Therefore, there are approximately 0.0105 grams of methylamine in 100.0 mL of the solution.

Answer:hope we can be friends

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Imagine an enormous cloud of gas and dust many light-years across. Gravity, as it always does, tries to pull the materials together. A few grains of dust collect a few more, then a few more, then more still. Eventually, enough gas and dust has been collected into a giant ball that, at the center of the ball, the temperature (from all the gas and dust bumping into each other under the great pressure of the surrounding material) reaches 15 million degrees or so. A wondrous event occurs.... nuclear fusion begins and the ball of gas and dust starts to glow. A new star has begun its life in our Universe. So what is this magical thing called "nuclear fusion" and why does it start happening inside the ball of gas and dust? It happens like this..... As the contraction of the gas and dust progresses and the temperature reaches 15 million degrees or so, the pressure at the center of the ball becomes enormous. The electrons are stripped off of their parent atoms, creating a plasma. The contraction continues and the nuclei in the plasma start moving faster and faster. Eventually, they approach each other so fast that they overcome the electrical repulsion that exists between their protons. The nuclei crash into each other so hard that they stick together, or fuse. In doing so, they give off a great deal of energy. This energy from fusion pours out from the core, setting up an outward pressure in the gas around it that balances the inward pull of gravity.

Explanation:

Producers would die, and if producers died, consumers would die too. ... food chains show energy being transferred and food webs show organisms linked to each other.

Answer:

Your question is incomplete.

But what I can help you with is once a redox reaction occurs, one element oxidizes and another is reduced, generating the equilibrium of the reaction.

On the other hand, it is important to clarify all the redox reactions, reactions of reducing factors (positive protons) and oxygen that oxidize.

Explanation:

example:

Reduction half-reaction: {2 e ^ - + Cu ^ 2 + -> Cu} {2 e ^ - + Cu ^ 2 + -> Cu}

Half oxidation reaction: {Fe -> Fe ^ 2 + + 2 e ^ -} {Fe -> Fe ^ 2 + + 2 e ^ -}

or more frequently, also called general equation:

{Fe + Cu ^ 2 + -> Fe ^ 2 + + Cu} {Fe + Cu ^ 2 + -> Fe ^ 2 + + Cu}

Answer:

D. second order, 1/[A]t versus t

Explanation:

Since the power of the concentration is 2 in the rate law, it is a second order reaction. Also, for a second order reaction, the variables that would yield a straight line when graphed are 1/[A]t versus t

Final answer:

The overall order of the reaction is 2 (second-order). A plot of 1/[A]t versus t will give a straight line for this reaction.

Explanation:

The overall order of the reaction is 2, which means it is a second-order reaction. This is because the rate law is rate = k[A]2, indicating that the reaction rate is proportional to the square of the concentration of A.

A plot of 1/[A]t versus t will give a straight line for this reaction. This is because the integrated rate law for second-order reactions has the form of the equation of a straight line: kt + [A]o = 1/[A]t. If the plot of 1/[A]t versus t is not a straight line, the reaction is not second order.

Answer:

At the time of Rutherford's experiment, the accepted model for the atom was the Thomson plum-pudding model of the atom, in which the atom consists of a "sphere" of positive charge distributed all over the sphere, with tiny negative particles (the electrons) inside this sphere.

In his experiment, Rutherford shot alpha particles towards a very thin sheet of gold foil. He observed the following things:

1- Most of the alpha particles went undeflected, but

2- Some of them were scattered at very large angles

3- A few of them were even reflected back to their original directions

Observations 2) and 3) were incompatible with Thomson model of the atom: in fact, if this model was true, all the alpha particle should have gone undeflected, or scattered at very small angles. Instead, due to observations 2) and 3), it was clear that:

- The positive charge of the atom was all concentred in a tiny nucleus

- Most of the mass of the atom was also concentrated in the nucleus

So, Rutherford experiment lead to a change in the atomic model of the atom, as it was clear that the plum-pudding model was no longer adequate to describe the results of Rutherford's experiment.

Final answer:

Rutherford's gold foil experiment disproved the plum pudding model by showing that alpha particles were deflected by a dense nucleus within the atom. This discovery led to a new atomic model where a central nucleus is orbited by electrons.

Explanation:

In 1911, Ernest Rutherford's gold foil experiment challenged the then-accepted plum pudding model of the atom. The plum pudding model hypothesized that an atom's mass and charge were uniformly distributed throughout the atom. This model suggested that alpha particles, which are helium nuclei, would pass through a gold foil with little or no deflection. However, Rutherford's experiment revealed that while most particles passed through the foil, a small percentage (approximately 1 in 8000) were deflected at large angles, and some even bounced back toward the source. This suggested that the atom's mass and positive charge were not evenly distributed, but rather concentrated in a small, central nucleus, leading to the development of the nuclear model of the atom.

Rutherford's findings fundamentally altered the scientific understanding of the atomic structure. The dramatic deflections and backscatterings indicated the existence of a compact, positively-charged atomic nucleus, around which the electrons orbited. This discovery was instrumental in moving away from the plum pudding model to one that reflected the modern view of the atom, where a dense nucleus contains most of the atom's mass and positive charge, with electrons residing in the surrounding empty space.

Using Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin with constant pressure, the new volume of gas when temperature is decreased from 1500 K to 750 K is 5.0 liters.

This question is related to the Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming that the pressure and the amount of gas remain constant. To solve this problem, we can use the formula V₁/T₁= V₂/T₂ , where V₁ and V₂ are the initial and final volumes, and T₁ and T₂ are the initial and final temperatures in Kelvin, respectively.

Given: V₁ = 10.0 liters, T₁ = 1500 K, T₂ = 750 K
We are solving for V₂.

Using Charles's Law:
V₁/T₁= V₂/T₂
(10.0 L) / (1500 K) = V2 / (750 K)
V₂ = (10.0 L) / 2
V₂= 5.0 liters

The correct answer is that the new volume of the gas when the temperature is decreased to 750 K is 5.0 liters.

Answer: Radioactivity

Explanation: