Answer:
Flow; Impressed
Explanation:
The electric charge can be think of as the flow rate of electrons in a certain area or point. Voltage is a difference in electrical potential, it makes charges to move in the electrical conductor, therefore it is impressed across a circuit
You are pushing a rock along level ground and making the rock speed up. How does the size of the force you exert on the rock compare with the size of the force the rock exerts on you? The force you exert _______.
Final answer:
The force you exert on the rock is equal in magnitude but opposite in direction to the force the rock exerts on you, in accordance with Newton's Third Law of Motion.
Explanation:
When you push a rock along level ground and make it speed up, the force you exert compares with the force the rock exerts on you in accordance with Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. Therefore, the force you exert on the rock is equal in magnitude but opposite in direction to the force the rock exerts on you.
The concept can be understood by considering various scenarios where different forces are applied to objects of differing masses, resulting in different levels of acceleration. For example, pushing a basketball produces a noticeable acceleration due to the basketball's low mass, whereas pushing a stalled SUV with the same force results in a much smaller acceleration due to the SUV's greater mass.
Friction can also affect how much force is needed to move an object. When pushing a heavy crate, you must overcome static friction, which matches the force you apply up to the point where the crate begins to move. Once in motion, dynamic friction takes over, which is generally lower than static friction, making it easier to keep the object moving.
A body of mass 2.7 kg makes an elastic collision with another body at rest and continues to move in the original direction but with 1/3 of its original speed.
(a) What is the mass of the other body?
(b) What is the speed of the two-body center of mass id the initial speed of the 2.7kg body was 4.0 m/s?
Answer:
a)
1.35 kg
b)
2.67 ms⁻¹
Explanation:
a)
[tex]m_{1}[/tex] = mass of first body = 2.7 kg
[tex]m_{2}[/tex] = mass of second body = ?
[tex]v_{1i}[/tex] = initial velocity of the first body before collision = [tex]v[/tex]
[tex]v_{2i}[/tex] = initial velocity of the second body before collision = 0 m/s
[tex]v_{1f}[/tex] = final velocity of the first body after collision =
using conservation of momentum equation
[tex]m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}\\(2.7) v + m_{2} (0) = (2.7) (\frac{v}{3} ) + m_{2} v_{2f}\\(2.7) (\frac{2v}{3} ) = m_{2} v_{2f}\\v_{2f} = \frac{1.8v}{m_{2}}[/tex]
Using conservation of kinetic energy
[tex]m_{1} v_{1i}^{2}+ m_{2} v_{2i}^{2} = m_{1} v_{1f}^{2} + m_{2} v_{2f}^{2} \\(2.7) v^{2} + m_{2} (0)^{2} = (2.7) (\frac{v}{3} )^{2} + m_{2} (\frac{1.8v}{m_{2}})^{2} \\(2.7) = (0.3) + \frac{3.24}{m_{2}}\\m_{2} = 1.35[/tex]
b)
[tex]m_{1}[/tex] = mass of first body = 2.7 kg
[tex]m_{2}[/tex] = mass of second body = 1.35 kg
[tex]v_{1i}[/tex] = initial velocity of the first body before collision = 4 ms⁻¹
[tex]v_{2i}[/tex] = initial velocity of the second body before collision = 0 m/s
Speed of the center of mass of two-body system is given as
[tex]v_{cm} = \frac{(m_{1} v_{1i} + m_{2} v_{2i})}{(m_{1} + m_{2})}\\v_{cm} = \frac{((2.7) (4) + (1.35) (0))}{(2.7 + 1.35)}\\\\v_{cm} = 2.67[/tex] ms⁻¹
What would stars be like if hydrogen had the smallest mass per nuclear particle? What would stars be like if hydrogen had the smallest mass per nuclear particle? Stars would be brighter. All stars would be red giants. Nuclear fusion would not occur in stars of any mass.
Nuclear fusion would not occur in stars of any mass if hydrogen had the smallest mass per nuclear particle.
What is Nuclear fusion?This is the process in which nuclear reactions between light elements form heavier elements.
Hydrogen won't be able to undergo nuclear fusion in stars of any mass if hydrogen had the smallest mass per nuclear particle due to the sub=atomic particles not being favorable in this condition.
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A cylindrical container holds Fluid X (specific gravity 0.75) and Fluid Y (specific gravity 1.5). The two fluids are immiscible. The gauge pressure at the foot of the column is equal to what it would be if all the fluid in the column were water. Fluid X must therefore account for what fraction of the total fluid in the column?
Answer: 2/3 of the total volume
Explanation:
See attachment for details
What elements had to be made in a supernova explosion?
Answer:
Gold, Platinum and Uranium
Explanation:
A star is nothing but a huge ball of gas. Specifically, Hydrogen, the simplest element of nature. A star is in equilibrium because its immense mass causes it to collapse towards itself, squeezing those hydrogen nuclei or protons, and the union of the protons in its nucleus causes the star to explode, releasing energy. As long as these nuclear reactions exist (the same ones that human beings can cause with their hydrogen bombs), the star will remain in equilibrium.
Protons have a positive charge and tend to repel. But inside the stars they are so tight (there is a lot of pressure and temperature), that they can't avoid crashing. At that time, the electromagnetic force is defeated by what physicists call Strong Force, which holds together protons and neutrons forming more complex atoms. In a typical star, the protons join to form the next element in the periodic table: Helium, consisting of 2 protons and two neutrons. It is a rare element on Earth and was discovered in the Sun rather than on our planet. Hence his name, from the Greek Helios, the sun god.
However, the mass of the sum of the protons that bind to form Helium is less than the total mass of Helium. What happen? Are the laws of physics inside the stars not fulfilled? What happens is impossible to understand if one is born before Albert Einstein, but today it is very easy to explain. The mass that we lack, has actually become energy. The German physicist Albert Einstein (1879-1955) discovered that mass and energy are equivalent while formulating his Theory of Relativity. In fact, let me, for once, write a mathematical equation of an unparalleled beauty:
E = mc2
This equation tells us that the energy E is equal to the mass m times the square of a constant c; that constant c is the speed of light, approximately 300,000 km / s. That is, a very small mass, such as a proton, is equivalent to a very large energy, since the numerical factor by which the mass is multiplied is a very large number. And that energy is what the stars release, the one that our Sun emits and gives us life.
When Hydrogen is depleted, the star collapses until the pressure and temperature increase enough for Helium to fuse with itself; the cycle is repeated and the star ends up generating Carbon, Oxygen, Nitrogen, Silicon, Iron. As you can see, the stars are factories of atoms. When the star explodes, even heavier atoms are generated, such as Gold, Platinum, Uranium, elements that abound on our planet. And they abound, because the Sun is a second or third generation star: that is, it was born from the remains of other stars' explosions, along with the materials that make up our planet, the rest of the planets, the asteroids, the comets, the interstellar dust and ourselves.
Suzie (of mass 42 kg) is roller-blading down the sidewalk going 32 miles per hour. She notices a group of workers down the walkway who have unexpectedly blocked her path, and she makes a quick stop in 2.2 seconds.a) What is Suzie’s average acceleration? Answer in units of m/s 2 .b) What force in Newtons was exerted to stop Suzie? Answer in units of N.
Answer:
a) Suzie’s average acceleration = -6.46 m/s²
b) Force exerted to stop Suzie = 271.52 N
Explanation:
a) We have equation of motion, v = u + at
Final velocity, v = 0 m/s
Initial velocity, u = 32 mph = 14.22 m/s
Time, t =2.2 s
Substituting
0 = 14.22 + a x 2.2
a = -6.46 m/s²
Suzie’s average acceleration = -6.46 m/s²
b) Mass of Suzie = 42 kg
Force = Mass x Acceleration
F = Ma
F = 42 x -6.46 =-271.52 N
Force exerted to stop Suzie = 271.52 N
A roller coaster cart of mass m = 223 kg starts stationary at point A, where h1 = 26.8 m and a while later is at B, were h2 = 14.7 m. The acceleration of gravity is 9.8 m/s 2 . What is the speed of the cart at B, ignoring the effect of friction?
Answer:
vB = 15.4 m/s
Explanation:
Principle of conservation of energy:
Because there is no friction the mechanical energy is conserve
ΔE = 0
ΔE : mechanical energy change (J)
K : Kinetic energy (J)
U: Potential energy (J)
K = (1/2)mv²
U = m*g*h
Where :
m: mass (kg)
v : speed (m/s)
h : hight (m)
Ef - Ei = 0
(K+U)final - (K+U)initial =0
(K+U)final = (K+U)initial
((1/2)mv²+m*g*h)final = ((1/2)mv²+m*g*h)initial , We divided by m both sides of the equation:
((1/2)vB² + g*hB = (1/2 )vA²+ g*hA
(1/2) (vB)² + (9.8)*(14.7) = 0 + (9.8)(26.8 )
(1/2) (vB)² = (9.8)(26.8 ) - (9.8)*(14.7)
(vB)² = (2)(9.8)(26.8 - 14.7)
(vB)² = 237.16
[tex]v_{B} = \sqrt{237.16}[/tex]
vB = 15.4 m/s : speed of the cart at B
Answer:
the guy above me is correct
Explanation:
The presence of icicles hanging off the eaves of a wood-framed structure is most likely due to: heavy snow followed by a thaw. improper insulation in wall cavities. use of a poor-quality roof sheathing material. lack of proper roof ventilation. failure to install a radiant barrier above the roof insulation.
Answer:
Lack of proper roof ventilation
Explanation:
The icicles hanging off the eaves of a roof are due to lack of proper roof ventilation. This means after snowfalls the attic of the roof receives warm air which melts the snow above. This is caused because the upper part of roof is above 32⁰C (which melts the snow) and lower part of your roof is at a lower temperature which refreezes the snow dripping down to form icicles.
A 1,500 kg truck is towed sideways out of a mud-hole with a force of 15,000 N. How much acceleration is required for the tow truck to move this vehicle?
10 m/sec² acceleration is required for the tow truck to move this vehicle.
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
force = mass*acceleration
acceleration = force/mass
acceleration = 15000/1500
acceleration = 10 m/sec²
10 m/sec² acceleration is required for the tow truck to move this vehicle.
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Demand for a certain product is forecast to be 800 units per month, averaged over all 12 months of the year. The product follows a seasonal pattern, for which the January monthly index is 0.8. What is the seasonally-adjusted sales forecast for January?
Answer:
Adjusted forecast for January is 640
Explanation:
given,
Demand forecast of a certain product = 800 units
averaged over all months = 12 months
January monthly index = 0.8
We have to find seasonally-adjustment sales for January
Adjusted forecast = ( Demand ) x ( monthly index )
= 800 x 0.8
= 640
Adjusted forecast for January is 640
A heavy boy and a lightweight girl are balanced on a massless seesaw. If they both
move forward so that they are one-half their original distance from the pivot point,what will happen to the seesaw? Assume that both people are small enough compared to the length of the seesaw to be thought of as point masses.
A. It is impossible to say without knowing the masses.
B. It is impossible to say without knowing the distances.
C. The side the boy is sitting on will tilt downward.
D. Nothing will happen; the seesaw will still be balanced.
E. The side the girl is sitting on will tilt downward.
Answer:
D. Nothing will happen; the seesaw will still be balanced.
Explanation:
D. Nothing will happen; the seesaw will still be balanced. Since both toruqes or momentums respect to the center have changed in the same amount (one-half their original distance) the seesaw will remain balanced, if the children change distance in a different amount then it will be out of balance
D. Nothing will happen; the seesaw will still be balanced.
Further explanationThe force acting on a system with static equilibrium is 0
[tex] \large {\boxed {\bold {\sum F = 0}} [/tex]
(forces acting as translational motion only, not including rotational forces)
[tex] \displaystyle \sum F_x = 0 \\\\\ sum F_y = 0 [/tex]
For objects undergoing rotation, the equilibrium must be met
[tex] \large {\boxed {\bold {\sum \tau = 0}} [/tex]
A heavy boy (Hb) and a lightweight girl (Lg) are balanced on a mass-less seesaw
Because there is a balance of rotation, the torque equation:
Στ = 0
Hb.r1-Lg.r2 = 0
Hb.r1 = Lg.r2 (equation 1)
If they both move forward so that they are one-half their original distance from the pivot point, then the distance of the two children to the pivot point is reduced to half
Then the torque equation:
[tex]\rm Hb\times \dfrac{r_1}{2}= Lg\times \dfrac{r_2}{2}\\\\Hb\times r_1=Lg\times r_2[/tex]
This equation remains the same as equation 1, so the seesaw will still be balanced.
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A current I flows down a wire of radius a.
(a) If it is uniformly distributed over the surface, what is the surface current density K?
(b) If it is distributed in such a way that the volume current density is inversely.
Answer:
(a) [tex]K = \frac{I}{2\pi a}[/tex]
(b) [tex]J = \frac{I}{2\pi as}[/tex]
Explanation:
(a) The surface current density of a conductor is the current flowing per unit length of the conductor.
[tex]K = \frac{dI}{dL}[/tex]
Considering a wire, the current is uniformly distributed over the circumferenece of the wire.
[tex]dL = 2\pi r[/tex]
The radius of the wire = a
[tex]dL = 2\pi a[/tex]
The surface current density [tex]K = \frac{I}{2\pi a}[/tex]
(b) The current density is inversely proportional
[tex]J \alpha s^{-1}[/tex]
[tex]J = \frac{k}{s}[/tex] ......(1)
k is the constant of proportionality
[tex]I = \int\limits {J} \, dS[/tex]
[tex]I = J \int\limits \, dS[/tex] ........(2)
substituting (1) into (2)
[tex]I = \frac{k}{s} \int\limits\, dS[/tex]
[tex]I = k \int\limits^a_0 \frac{1}{s} {s} \, dS[/tex]
[tex]I = 2\pi k\int\limits\, dS[/tex]
[tex]I = 2\pi ka[/tex]
[tex]k = \frac{I}{2\pi a}[/tex]
substitute [tex]J = \frac{k}{s}[/tex]
[tex]J = \frac{I}{2\pi as}[/tex]
In a wire with current I and radius a, the surface current density K with uniform distribution is I/(2πaL). If volume current density varies inversely with the radius, the current is more dense at the center and less dense towards the surface, described by I/(πa²L).
Explanation:The subject here relates to the physical properties of the current flowing down a wire with a certain radius. (a) If the current I is uniformly distributed over the surface of the wire with a radius a, then the surface current density K can be given by the total current (I) divided by the surface area of the wire. In this context, the surface area of a cylindrical wire can be calculated by the formula 2π * a * L, where L is the length of the wire. Therefore, the surface current density K is I/(2πaL).
(b) If the current is distributed such that the volume current density J is inversely proportional to the radius, it implies that the current is more dense at the center of the wire and less dense as you approach the surface. The volume current density J can be described by the formula I/(πa²L). This complex distribution would likely require calculus to derive an exact relationship between current density and radius.
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A 5.20g bullet moving at 672 m/s strikes a 700g wooden block atrest on a frictionless surface. The bullet emerges, travelingin the same direction with its speed reduced to 428 m/s.
a. What is the resulting speed of the block?
b. What is the speed of the bullet-block center of mass?
Answer:
a) v=1.81 m/s; B) v=4.95 m/s
Explanation:
using momentum conservation
m1v1+m2v1=m1v2+m2v2
A)
5.2*672+700*0=5.2*428+700v2
The initial velocity of the block is 0, solving for v2
v2=1.81 m/s
B) Now both the bullet and the block travel together
m1v1+m2v1=(m1+m2)v2
5.2*672+700*0=(5.2+700)v
v=4.95 m/s
a. To find the resulting speed of the block after the bullet strikes it, we can use the law of conservation of momentum. b. The speed of the bullet-block center of mass can be found by calculating the weighted average of the speeds of the bullet and block.
Explanation:a. To find the resulting speed of the block, we can use the law of conservation of momentum. The momentum before the collision is equal to the momentum after the collision.
The initial momentum of the bullet is given by m1 * v1, and the final momentum is given by (m1 + m2) * vf, where m1 is the mass of the bullet, v1 is the initial velocity of the bullet, m2 is the mass of the block, and vf is the final velocity of the bullet and block combined.
Using these values, we can solve for vf and then find the resulting speed of the block.
b. The speed of the bullet-block center of mass can be found by calculating the weighted average of the speeds of the bullet and block. Since the mass of the bullet is much smaller than the mass of the block, the center of mass will be closer to the speed of the block.
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Which method is not a technique currently used by ocean scientists to map the topography of the ocean floor?
Answer:
Magnetometer
Explanation:
Magnetometer technique is not using by scientists for studying the ocean floor.The scientists currently is using SONAR ( sound navigation and ragging) technique for studying the ocean floor.SONAR is used sound waves sound waves for studying the ocean floor or we can say that SONAR is based on sound propagation.
Therefore answer is Magnetometer
Suppose you want to operate an ideal refrigerator with a cold temperature of − 15.5 °C , and you would like it to have a coefficient of performance of at least 8.25. What is the maximum hot reservoir temperature for such a refrigerator?
Answer:
15.65 °C
Explanation:
cold temperature (Tc) = -15.5 degree C = 273.15 - 15.5 = 257.65 kelvin
minimum coefficient of performance (η) = 8.25
find the maximum hot reservoir temperature of such a generator (Th)
η = \frac{Tc}{Th-Tc}
Th = Tc x (\frac{1}{η} + 1)
Th = 257.65 x (\frac{1}{8.25} + 1)
Th = 288.8 K
Th = 288.8 - 273.15 = 15.65 °C
The magnitude of displacements a and b are 3m and 4m, respectively, c=a+b. What is the magnitude of c if the angel between a and b is (a) 0 and (b) is 180?
Answer:
(a) 7 m
(b) 1 m
Explanation:
Given:
The magnitude of displacement vector 'a' is 3 m
The magnitude of displacement vector 'b' is 4 m.
The vector 'c' is the vector sum of vectors 'a' and 'b'.
(a)
Now, when the angle between the vectors is 0°, it means that the vectors are in the same direction. When vectors are in the same direction, then their resultant magnitude is simply the sum of their magnitudes.
So, magnitude of 'c' when 'a' and 'b' are in same direction is given as:
[tex]|\overrightarrow c|=|\overrightarrow a|+|\overrightarrow b|\\\\|\overrightarrow c|=3 + 4 = 7\ m[/tex]
Therefore, the magnitude of vector 'c' is 7 m when angle between 'a' and 'b' is 0°.
(b)
When the angle between the vectors is 180°, it means that the vectors are exactly in the opposite direction. When the vectors are in opposite direction, then their resultant magnitude is the subtraction of their magnitudes.
So, magnitude of 'c' when 'a' and 'b' are in opposite direction is:
[tex]|\overrightarrow c|=||\overrightarrow a|-|\overrightarrow b||\\\\|\overrightarrow c|=|3 - 4| = 1\ m[/tex]
Therefore, the magnitude of vector 'c' is 1 m when angle between 'a' and 'b' is 180°.
Jason launches a model rocket with a mass of 2.0 kg from his spring-powered rocket launcher with a spring constant of 800 N/m. He pulls it back .55 m. If Jason aims it straight up, what potential energy will the rocket have when it reaches its maximum height? What height will it reach?
Answer:
121 Joules
6.16717 m
Explanation:
m = Mass of the rocket = 2 kg
k = Spring constant = 800 N/m
x = Compression of spring = 0.55 m
Here, the kinetic energy of the spring and rocket will balance each other
[tex]\frac{1}{2}mu^2=\frac{1}{2}kx^2\\\Rightarrow u=\sqrt{\frac{kx^2}{m}}\\\Rightarrow u=\sqrt{\frac{800\times 0.55^2}{2}}\\\Rightarrow u=11\ m/s[/tex]
The initial velocity of the rocket is 11 m/s = u.
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² = g
[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11^2}{2\times -9.81}\\\Rightarrow s=6.16717\ m[/tex]
The maximum height of the rocket will be 6.16717 m
Potential energy is given by
[tex]P=mgh\\\Rightarrow P=2\times 9.81\times \frac{0^2-11^2}{2\times -9.81}\\\Rightarrow P=121\ J[/tex]
The potential energy of the rocket at the maximum height will be 121 Joules
Calculate the wavelengths of the first five members of the lyman series of spectral lines
Answer:
λ₂ = 1,219 10⁻⁷ m , λ₃ = 1.028 10⁻⁷ m , λ₄ = 0.9741 10⁻⁷ m , λ₅ = 0.9510 10⁻⁷ m and λ₆ = 0.9395 10⁻⁷ m
Explanation:
To calculate the lines of the hydrogen liman series, we can use the Bohr atom equation
En = -13.606 / n² [eV]
n En
1 -13,606
2 -13.606 / 4 = -3.4015
3 -13.606 / 9 = -1.5118
4 -13.606 / 16 = -0.8504
5 -13.606 / 25 = -0.5442
6 -13.606 / 36 = -0.3779
The lyma series are transitions where the state is fundamental (E1), let's calculate the first five transitions
State
initial final energy
6 1 -0.3779 - (- 13.606) = 13.23 eV
5 1 -0.5442 - (- 13.606) = 13.06 eV
4 1 -0.8504- (-13.606) = 12.76 eV
3 1 -1.5118 - (- 13.606) = 12.09 eV
2 1 -3.4015 - (- 13.606) = 10.20 eV
Let's use the relationship between the speed of light and the wavelength and the frequency
c = λ f
f = c / λ
Planck's relationship for energy
E = h f
E = h c / λ
λ = hc / E
We calculate for each energy
E = 10.20 eV
λ = 6.63 10⁻³⁴ 3 10⁸ / (10.20 1.6 10⁻¹⁹)
λ = 12.43 10⁻⁷ / 10.20
λ₂ = 1,219 10⁻⁷ m
E = 12.09 eV
λ₃ = 12.43 10⁻⁷ / 12.09
λ₃ = 1.028 10⁻⁷ m
E = 12.76 eV
λ₄ = 12.43 10⁻⁷ /12.76
λ₄ = 0.9741 10⁻⁷ m
E = 13.06 ev
λ₅= 12.43 10⁻⁷ /13.06
λ₅ = 0.9510 10⁻⁷ m
E = 13.23 eV
λ₆ = 12.43 10⁻⁷ / 13.23
λ₆ = 0.9395 10⁻⁷ m
What is the free-fall acceleration at the surface of the jupiter?
The free-fall acceleration at the surface of Jupiter is approximately 24.79 m/s², which is more than two and two thirds times the gravitational pull experienced on Earth. A person weighing 150 pounds on Earth would weigh around 400 pounds on Jupiter.
The free-fall acceleration at the surface of Jupiter is approximately 24.79 m/s². This value is derived from using Newton's Law of Universal Gravitation and considering Jupiter's mass and radius. Jupiter has a mass about 300 times that of Earth and a radius approximately 11 times larger. The gravitational acceleration (g) at a planet's surface is given by the formula:
g = G x (mass of the planet) / (radius of the planet)²,
where G is the gravitational constant. Since the mass of Jupiter is much greater than that of Earth, and despite its larger radius, the acceleration due to gravity would be significantly higher on Jupiter. Therefore, an astronaut entering Jupiter's atmosphere would fall faster compared to falling through the Earth's atmosphere. If an astronaut who weighs 150 pounds on Earth were to stand on a scale on Jupiter, she would weigh approximately 400 pounds, which is more than two and two thirds times her weight on Earth. However, this value may vary slightly depending on whether she is near Jupiter's pole or equator, due to its oblateness.
A model airplane with mass 0.741 kg is tethered to the ground by a wire so that it flies in a horizontal circle 30.5 m in radius. The airplane engine provides a net thrust of 0.804 N perpendicular to the tethering wire.
Find the magnitude of the torque the net thrust produces about the center of the circle.
Answer:
The magnitude of torque is τ = 24.522 N*m^2
Explanation:
To find the magnitude of the torque can use the equation of the force produce by the airplane so:
τ = F * d
τ = 0.804 N * 30.5 m
τ = 24.522 N*m
Check:
Find the acceleration
I = m*r^2=0.741kg*(30.5m)^2
I = 689.32 kg*m^2
τ = I*a_c
a_c = τ /I = 24.522 N*m^2 / 689.32 kg*m^2
a_c = 0.0355 m/s^2
τ = 0.0355 m/s^2 * 689.32 kg*m^2
τ = 24.522 N*m^2
A ball (mass 0.40 kg) is initially moving to the left at 30 m/s. After hitting the wall, the ball is moving to the right at 20 m/s. What is the impulse of the net force on the ball during its collision with the wall?
A) 20 kg. m/s to the right
B) 20 kg. m/s to the left
C) 4.0 kg. m/s to the right
D) 4.0 kg. m/s to the left
E) none of the above
Answer:
Option (a)
Explanation:
Impulse is defined as the change in momentum of the body. It is a vector quantity and its SI unit is Kg m/s.
mass of ball, m = 0.4 kg
initial velocity, u = - 30 m/s
Final velocity, v = + 20 m/s
Initial momentum, pi = mass x initial velocity = m u = 0.4 x (- 30) = - 12 kg m/ s
Final momentum, pf = mass x final velocity = mv = 0.4 x 20 = 8 Kg m /s
Change in momentum = final momentum - initial momentum = 8 - (- 12 )
So, impulse = 20 kg m /s right
Option (a) is correct
Final answer:
The impulse of the net force on the ball during its collision with the wall is the change in momentum, coming to 32 kg·m/s to the right, leading to option E) none of the above as the correct answer.
Explanation:
The impulse of the net force on a ball during its collision with the wall can be calculated using the change in momentum of the ball, which is equal to the impulse imparted to it. If the ball has a mass of 0.40 kg and changes its velocity from 30 m/s to the left (which we can consider as a negative direction) to 20 m/s to the right (a positive direction), we need to take into account the magnitude and the direction of this change.
The initial momentum of the ball is given by the product of its mass and its initial velocity, which is -0.40 kg × 30 m/s (the negative sign indicates the initial leftward direction). The final momentum after the collision is 0.40 kg × 20 m/s. The impulse is the difference between the final and initial momentum: (0.40 kg × 20 m/s) - (-0.40 kg × 30 m/s), which equals 20 kg·m/s + 12 kg·m/s or 32 kg·m/s to the right. Therefore, the correct answer is E) none of the above.
How much work is done when a vertical force acts on an object moving horizontally
Answer:
Zero work is done when a vertical force acts on an object moving horizontally
Explanation:
Word is the dot product of force and displacement.
W = F . s
W = Fs cosθ
θ is the angle between force and displacement,
We need to find how much work is done when a vertical force acts on an object moving horizontally.
That is angle between force and displacement = 90°
θ = = 90°
Substituting
W = Fs cos90 = Fs x 0 = 0
Zero work is done when a vertical force acts on an object moving horizontally
Sound waves are Sound waves are
(a) transverse waves characterized by the displacement of air molecules.
(b) longitudinal waves characterized by the displacement of air molecules.
(c) longitudinal waves characterized by pressure differences.
(d) Both (b) and (c). (e) (a), (b) and (c).
Sound waves in air and water are longitudinal waves characterized by pressure differences. Sound in solids can have both longitudinal and transverse components.
Explanation:Sound waves in air and water are longitudinal waves characterized by pressure differences. When sound waves propagate through a fluid like air or water, the disturbances are periodic variations in pressure, resulting in compressions (high-pressure regions) and rarefactions (low-pressure regions).
Fluids do not have appreciable shear strength, so the sound waves in them must be longitudinal or compressional. On the other hand, sound in solids can have both longitudinal and transverse components. For example, seismic waves generated by earthquakes have both longitudinal (compressional or P-waves) and transverse (shear or S-waves) components.
What principle is responsible for alternating light and dark bands when light passes through two or more narrow slits? What principle is responsible for alternating light and dark bands when light passes through two or more narrow slits? reflection refraction dispersion interference polarization
The interference principle is responsible for alternating light and dark bands when light passes through two or more narrow slits.
What is Interference?The phenomenon in which two or more waves combine to generate a new wave with a larger, smaller, or equal amplitude. It depends on the alignment of the peaks and troughs of the overlapping waves.
When two or more waves collide, this is known as interference. They may add up, or they may partially or completely cancel each other,
When two waves with the same frequency. We will see varying intensities of light at different points on the screen owing to their superposition.
Hence interference principle is responsible for alternating light and dark bands when light passes through two or more narrow slits.
To learn more about the interference refer to the link;
https://brainly.com/question/16098226
The air in this room consists of countless tiny, independent molecules. You can be sure that these air molecules won't all shift spontaneously to the other side of the room (leaving you in a vacuum) because that would
(A) violate Newton's laws of motion.
(B) be extremely unlikely and therefore violate the 2nd law of thermodynamics.
(C) violate Bernoulli's equation.
(D) not conserve energy and therefore violate the 1st law of thermodynamics.
Answer:
(B) be extremely unlikely and therefore violate the 2nd law of thermodynamics.
Explanation:
This process is highly unlikely and if happens would violet the 2nd law of thermodynamics.
The laws of motion do not rule out a move to one side of the room of all the air molecules. But it would be extremely unlikely to happen that. The second law of thermodynamics states that the universe responds to circumstances that become more and more likely, not improbable.
The speed of light in air 1. depends only on the frequency of the light. 2. depends on both the wavelength and the frequency of light. 3. depends only on the wavelength of light. 4. is independent of the wavelength and frequency of light.
Final answer:
The speed of light in air depends on both the wavelength and the frequency of light. Increasing or decreasing the frequency of light leads to changes in the amount of delay.
Explanation:
The speed of light in air depends on both the wavelength and the frequency of light. This relationship is defined by the equation c = fλ, where c is the speed of light, f is the frequency, and λ is the wavelength.
When the frequency of light increases, the wavelength decreases, and vice versa. This means that as you make the frequency higher or lower, there is a corresponding change in the amount of delay.
For example, if you increase the frequency, the wavelength becomes smaller, which leads to a shorter delay. On the other hand, if you decrease the frequency, the wavelength becomes larger, resulting in a longer delay.
A 0.0500-kg lead bullet of volume 5.00 × 10–6 m3 at 20.0 °C hits a block that is made of an ideal thermal insulator and comes to rest at its center. At that time, the temperature of the bullet is 327 °C.
a. How much heat was needed to raise the bullet to its final temperature?b. What is the volume of the bullet when it comes to rest?
c. What additional heat would be needed to melt the bullet?
Answer:
1964.8 J
[tex]5.12894\times 10^{-6}\ m^3[/tex]
1150 Joules
Explanation:
m = Mass of bullet = 0.5 kg
[tex]\Delta T[/tex] = Change in temperature = (327-20)
c = Specific heat of lead = 128 J/kg °C
[tex]\beta[/tex] = [tex]84\times 10^{-6}\ /^{\circ}C[/tex]
[tex]L_f[/tex] = Latent heat of fusion of lead = [tex]23000\ J/kg^{\circ}C[/tex]
(Values taken from properties of lead table)
Heat is given by
[tex]Q=mc\Delta T\\\Rightarrow Q=0.05\times 128\times (327-20)\\\Rightarrow Q=1964.8\ J[/tex]
The heat needed to raise the bullet to its final temperature is 1964.8 J
Change in volume is given by
[tex]\Delta V=V_0\beta \Delta T\\\Rightarrow \Delta V=5\times 10^{-6}\times 84\times 10^{-6}\times (327-20)\\\Rightarrow \Delta V=1.2894\times 10^{-7}\ m^3[/tex]
[tex]V=V_0+\Delta V\\\Rightarrow V=5\times 10^{-6}+1.2894\times 10^{-7}\\\Rightarrow V=5.12894\times 10^{-6}\ m^3[/tex]
The volume of the bullet when it comes to rest is [tex]5.12894\times 10^{-6}\ m^3[/tex]
Heat needed for melting
[tex]Q=mL_f\\\Rightarrow Q=0.05\times 23\times 10^3\\\Rightarrow Q=1150\ J[/tex]
The additional heat needed to melt the bullet is 1150 Joules
Final answer:
The calculation involves determining the heat required to increase the bullet's temperature, calculating the change in volume due to thermal expansion, and the additional heat required to melt the bullet, using the specific heat capacity, coefficient of thermal expansion, and latent heat of fusion for lead.
Explanation:
To solve this problem, we will use the specific heat capacity formula and the properties of lead to calculate the heat needed for temperature change and melting.
Heat required to raise the bullet's temperature: The heat (Q) needed can be calculated using the specific heat capacity equation Q = mcΔT, where 'm' is mass, 'c' is specific heat capacity, and ΔT is the change in temperature. For lead, the specific heat capacity (c) is approximately 128 J/(kg·°C).
Volume: To find the volume at the final temperature, we use the formula V = V_0(1+ αΔT), where V_0 is the initial volume, α is the coefficient of thermal expansion for lead, and ΔT is the change in temperature.
Additional heat to melt the bullet: To calculate the additional heat (Q_m) required to melt the bullet, we use the formula Q_m = mL_f, where 'm' is the mass of the bullet and L_f is the latent heat of fusion for lead.
To calculate these values, we also need the initial temperature (T_i), final temperature (T_f), and coefficient of thermal expansion for lead, which is 29.3 × 10⁻⁶ °C-1. For melting lead, the latent heat of fusion (L_f) is 24.7 kJ/kg.
The presently accepted value of the hubble constant gives an age of
Answer:
14 billion years
Explanation:
The Hubble – Lemaître law, previously called the Hubble law, is a law of physics that states that the redshift of a galaxy is proportional to the distance it is, which is the same as, the further one galaxy is found from another, more quickly it seems to move away from it.
The Hubble constant is the value that measures the rate at which the expansion speed of the Universe varies with distance, and is one of the fundamental parameters of the Universe and allows, in particular, to determine the age of the Universe as we will see.
A baseball is thrown at an angle of 29 relative to the ground at a speed of 24.3 m/s. The ball is caught 51.0463 m from the thrower. The acceleration due to gravity is 9.81 m/s2. How long is it in the air? Answer in units of s.
Answer:
T = 2.4 s
Explanation:
given,
angle at which ball is thrown = 29°
speed relative to ground = 24.3 m/s
ball is caught at a distance = 51.0463
acceleration due to gravity = 9.8 m/s²
time for which ball was in the air = ?
now,
velocity of ball in x-direction
V_x = v cos θ
V_x = 24.3 x cos 29°
V_x = 21.25 m/s
velocity in y direction
V_y = v sin θ
V_y = 24.3 x sin 29°
V_y = 11.78 m/s
distance on the ground when ball will reach maximum height
x = 51.0463/2 = 25.52 m
at top most point velocity is equal to zero
time for which the ball was in air
v = u + a t
0 = 11.78 - 9.8 t
[tex]t = \dfrac{11.78}{9.8}[/tex]
t = 1.20
this time is taken to travel half distance
total time = 2 x 1.20
T = 2.4 s
time for which ball was in air is T = 2.4 s
A 0.0026kg0.0026kg block is in a bowl whose lip is 1.0m1.0m above the ground. At the top, the block has a downward velocity and slides, without friction, down the sloped slide. At the bottom, it has a velocity of 6.0m/s6.0m/s. What is the block’s velocity at the top of the bowl?
Answer:
Vo = 4m/s
Explanation:
By conservation of energy:
[tex]1/2*m*Vf^2-1/2*m*Vo^2-m*g*h=0[/tex]
Solving for the initial speed:
[tex]Vo = \sqrt{2*(Vf^2/2-g*h)}[/tex]
[tex]Vo = \sqrt{2*(6^2/2-10*1)}[/tex]
Vo=4m/s