Answers
Let's now answer number 1:
Momentum is mass x velocity
p = mv
Block 1 is 10.00kg and is moving at a speed of 4.50m/s. Just put in what you know to get the answer:
p= 10.00kg x 4.50 m/s = 45 kg.m/s
The momentum of block 1 is 45 kg.m/s.
2. In a collision if one object bumps into another object and they both travel the same direction, the scenario would be considered as a PERFECT inelastic collision.
We can solve for unknowns using this formula:
[tex]m_{1}v_{1i}+m_{2}v_{2i} = (m_{1}+m_{2})v_{f}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
v1i = velocity of object 1 before collision
v2i = velocity of object 2 before collision
So before we solve for what you need, let's list down what you know based on the problem.
m1 = 10.00kg (Block1)
m2 = 25.0kg (Block2)
v1i = 4.50 m /s (Block1)
v2i = 0 m/s (Block2)
You may be wondering why the velocity of object 2 is 0m/s. Well, the problem says that Block 2 was initially at rest, then that means it is not moving, so it's speed would be 0 m/s.
Now use the formula and put in what you know and derive what you do not know.
[tex]m_{1}v_{1i}+m_{2}v_{2i} = (m_{1}+m_{2})v_{f}[/tex]
[tex](10.00kg)(4.50m/s)+(25.0kg)(0m/s) = (10.00kg + 25.00kg)v_{f}[/tex]
[tex](45kg.m/s)+(0) = (35kg)v_{f}[/tex]
[tex](45kg.m/s)= (35kg)v_{f}[/tex]
[tex] \frac{45kg.m/s}{35kg} = v_{f} [/tex]
[tex]1.29m/s = v_{f}[/tex]
Final velocity or vf of both blocks after collision is 1.29m/s.
3. To get the momentum after collision,just keep in mind that momentum is conserved even after collision. So your answer would be 45kg.m/s. If it is necessary for you to solve for it, just solve for it using the equation on the right side, which is (m1+m2)vf.
(m1+m2)vf
=(10.00kg+25.0kg)(1.29m/s)
=(35kg)(1.29m/s)
=45.15kg.m/s or 45 kg.m/s
As for the next problem, a cannon being fired is also considered a collision and this type of collision is called explosion, where the momentum before and after collision is zero. Why? Because before firing, the ball is not moving and neither is the cannon.
So now that we know this, using the formula of explosion we can solve for what we need.
[tex]m_{1}v_{1}+m_{2}v_{2}=0[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
v1= velocity of object 1
v2 = velocity of object 2
[tex]m_{1}v_{1}+m_{2}v_{2}=0[/tex]
[tex](450kg)(v1) + (2.75kg)(23.2m/s)=0[/tex]
[tex](450kg)(v1) + (63.8kg.m/s)=0[/tex]
[tex](450kg)(v1) =0 - 63.8kg.m/s[/tex]
[tex](450kg)(v1) =- 63.8kg.m/s[/tex]
[tex]v1 = \frac{-63.8k.m/s}{450kg} [/tex]
[tex]v1 = -0.14 m/s[/tex]
The cannon travelled -0.14m/s.
Notice that the value is negative, this means that it went the opposite direction it initially traveled or it traveled backwards.
Related Questions
Wrap a fur coat around a thermometer. how does the temperature change?
Answers
Rocket engineers use newton's third law during launch. identify the action force.
A. exhaust gases push down on the earth
B. rocket travels upward
C. earth pushes back on the exhaust gases
Answers
The action force in this scenario is earth pushes back on the exhaust gases.
Explanation:The action force in this scenario is option C: earth pushes back on the exhaust gases.
Newton's third law states that for every action, there is an equal and opposite reaction. In this case, the action force is the exhaust gases pushing downward on the earth as the rocket launches. The reaction force is the earth pushing back on the exhaust gases with an equal force in the opposite direction.
So, while the rocket is traveling upward, the action force is the exhaust gases pushing downward on the earth and the reaction force is the earth pushing back on the exhaust gases.
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A fixed mass of an ideal gas is heated from 50 to 80℃ at a constant pressure of (a) 1 atm and (b) 3 atm. for which case do you think the energy required will be greater? why?
Answers
The energy required to heat a fixed mass of an ideal gas from 50 to 80℃ is the same at both 1 atm and 3 atm, as it depends on the gas's heat capacity and the temperature change, not pressure.
Explanation:The energy required to heat a fixed mass of an ideal gas from 50 to 80℃ would be the same for both cases of constant pressure at 1 atm and 3 atm. The reason behind this is that the amount of energy required to raise the temperature of an ideal gas is dependent on its heat capacity and the change in temperature, not the pressure at which it is heated. In both cases (a) and (b), the change in temperature is the same, so the energy required will also be the same.
A policeman's whistle has a _____. high pitch low amplitude low pitch
Answers
...................
A policeman's whistle has a _____.
high pitch
A forklift raises a 1020 N crate 3.50 m up to a shelf l. How much work is done by the forklift on the crate? The forklift does J work on the crate.
Answers
A forklift raises a 1,020 N crate 3.50 m up to a shelf. How much work is done by the forklift on the crate?
The forklift does
⇒ 3,570 J of work on the crate. the answer is 3570
Answer : Work done on the crate is 3570 J
Explanation :
Force acting on forklift due to its mass is 1020 N
Distance covered in lifting it, d = 3.5 m
Mathematically, the work done is defined as :
[tex]W=F\times d[/tex]
So, [tex]W=1020\ N\times 3.5\ m[/tex]
[tex]W=3570\ J[/tex]
The forklift does 3570 J work on the crate.
Hence, this is the required solution.
Suppose we are told that the acceleration a of a particle moving with uniform speed v in a circle of radius r is proportional to some power of r, say rn, and some power of v, say vm. Determine the values of n and m and write the simplest form of an equation for the acceleration.
Answers
[tex]a = r^nv^m[/tex]
The units for that equation must be:
[tex](\frac{m}{s^2}) = (m)^{-1} ( \frac{m}{s} )^2[/tex]
Answer:
Acceleration, [tex]a=k\dfrac{v^2}{r}[/tex]
Explanation:
It is given that, the acceleration a of a particle moving with uniform speed v in a circle of radius r is proportional to some power of r and some power of v. Mathematically, it can be written as :
[tex]a\propto r^nv^m[/tex]
or
[tex]a=r^nv^m[/tex]...........(1)
Dimensional formula of a = [tex][LT^{-2}][/tex]
Dimensional formula of r = [tex][L][/tex]
Dimensional formula of v = [tex][LT^{-1}][/tex]
Using dimensional analysis in equation (1) as :
[tex][LT^{-2}]=[L]^n[LT^{-1}]^m[/tex]
[tex][LT^{-2}]=[L]^{n+m}[T^{-m}][/tex]
Equation both sides of equation as :
n + m = 1, m = 2
This gives, n = -1
Use the value of m and n in equation (1) in order to get the formula :
[tex]a=kr^{-1}v^2[/tex]
[tex]a=k\dfrac{v^2}{r}[/tex]
Hence, this is the required solution.
The potential energy of a book on a shelf is 50 J. If the book is now on the floor (below the shelf), its potential energy is
Answers
If the book is now on the floor (below the shelf), its potential energy is 0 J.
Potential Energy is defined as the energy that is capable of generating work as a consequence of the location of the object.
When the book is on a shelf, it is capable of generating work by falling from the shelf onto the floor by the force of gravity. This is called gravitational potential energy.
When the book is on the floor, it is no longer capable of generating work by falling, and its potential energy is 0 as it can't fall anymore and generate work.
Have a nice day!
Answer:
shelf a is increase shelf b is stay the same and shelf c is decrease
Explanation:
i did it on edu
A torque applied to a flywheel causes it to accelerate uniformly from a speed of 161 rev/min to a speed of 853 rev/min in 5.0 seconds. determine the number of revolutions n through which the wheel turns during this interval. (suggestion: use revolutions and minutes for units in your calculations.)
Answers
[tex]60 s: 1 min = 5 s: x[/tex]
we find
[tex]\Delta t = \frac{5.0 s}{60 s/min}=0.083 min [/tex]
Then we can find the angular acceleration of the flywheel:
[tex]\alpha = \frac{\omega _f - \omega_i}{\Delta t}= \frac{853 rpm-161 rpm}{0.083 min}=8337 rev/min^2 [/tex]
At this point, we can use the law of motion of an uniformly accelerated rotational motion. The angular displacement after a time [tex]\Delta t[/tex] is given by
[tex]\theta (\Delta t)= \omega_i t + \frac{1}{2} \alpha t^2 = [/tex]
[tex]=(161 rpm)(0.083 min)+ \frac{1}{2}(8337 rev/min^2)(0.083 min)^2 =42.1 rev[/tex]
So, the flywheel covers 42.1 revolutions.
If electrons of energy 12.8 ev are incident on a gas of hydrogen atoms in their ground state, photons can be emitted by the excited gas. how many different photon energies could you possibly observe?
Answers
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Electrons with 12.8 eV energy can excite hydrogen atoms to several higher energy levels without ionizing them. Upon de-excitation, these atoms can emit a series of photons, each with a unique energy corresponding to the energy differences between these levels. Therefore, a variety of different photon energies could be observed, each corresponding to specific transitions between the energy levels.
When electrons of energy 12.8 eV are incident on hydrogen atoms in their ground state, the electrons can be excited to higher energy levels. To determine how many different photon energies can be observed, we must consider the energy levels that 12.8 eV can reach from the ground state. The ground state of hydrogen is -13.6 eV. An electron in this state can be excited to energy levels such as -3.4 eV (second energy level), -1.51 eV (third energy level), and -0.85 eV (fourth energy level), and so on, as long as the energy is less than 12.8 eV. However, an important point to note is that the energy required to excite an electron must match the energy difference between these levels precisely. Upon returning to the ground state or another lower energy state, these electrons will emit photons with energies corresponding to the differences in energies between these levels.
Which graphic design tools help you draw circles and rectangles?
Freehand tool
Geometric Shape tools
Vector Splines
Drawing tool
Answers
Geometric shape tools help you draw circles and rectangles. Option B is correct.
What is graphic design?Graphic design is the practice of using words, pictures, and other visual elements to communicate ideas to an audience, often in order to achieve a certain result.
In other words, graphic design serves as a tool for communicating ideas through imagery and design.
For those with imaginative thinking skills who appreciate art, technology, and communication, graphic design is a terrific job.
Every business has a need for design, therefore graphic designers have a lot of opportunities to work on a variety of brand-new, fascinating projects.
You can draw circles and rectangles using geometric form tools.
Hence, option B is correct.
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A 58.5-kg athlete leaps straight up into the air from a trampoline with an initial speed of 8.8 m/s. the goal of this problem is to find the maximum height she attains and her speed at half maximum height.
Answers
This is a uniformly accelerated motion with initial speed [tex]v_0 = 8.8 m/s[/tex] and acceleration [tex]a=g=-9.81 m/s^2[/tex] (the negative sign is required because the acceleration is directed downward, in the opposite direction of the motion, which is directed upward). The distance covered (S) in a uniformly accelerated motion is related to the acceleration and the initial and final velocity by the relationship
[tex]2aS=v_f^2-v_i^2[/tex]
At maximum height, S=h and the final velocity is zero: [tex]v_f =0[/tex]. So we can solve for h and find the maximum height:
[tex]2ah=-v_i^2[/tex]
[tex]h= \frac{-v_i^2}{g}= \frac{-(8.8 m/s)^2}{-9.81 m/s^2}=3.95 m [/tex]
2) Speed at half maximum height
Half maximum height corresponds to [tex] \frac{h}{2}= \frac{3.95 m}{2}=1.975 m [/tex]. To find the speed at this height, we can use the same relationship used in the previous step:
[tex]2a \frac{h}{2}=v_f^2-v_i^2 [/tex]
where [tex]v_f [/tex] is the speed at half maximum height.
Re-arranging and substituting numbers, we find
[tex]v_f = \sqrt{v_i^2+(2g \frac{h}{2}) }= \sqrt{(8.8m/s)^2+2(-9.81m/s^2)(1.975m)}=6.22m/s [/tex]
Using _________ permits scientists to temporarily enhance or depress activity in a specific area of the brain. A. TMS B. EEG C. MRI D. ESB
Answers
Using TMS permits scientists to temporarily enhance or depress activity in a specific area of the brain.
What is Transcranial magnetic stimulation ?
Transcranial magnetic stimulation (TMS) is a noninvasive procedure that uses magnetic fields to stimulate nerve cells in the brain to improve symptoms of depression. TMS is typically used when other depression treatments haven't been effective.
The electromagnet painlessly delivers a magnetic pulse that stimulates nerve cells in the region of your brain involved in mood control and depression. It's thought to activate regions of the brain that have decreased activity in depression.
a single Transcranial magnetic stimulation (TMS) pulse can cause disruption in the contralateral hand muscles for ∼200 ms. These different temporal windows of disruption across different brain regions
Transcranial magnetic stimulation targets the activity of nerve cells in your brain, which may alleviate depression symptoms. It could also have benefit for disorders like OCD, anxiety, and PTSD as well.
hence , correct option is A. TMS (Transcranial magnetic stimulation)
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which jet stream affects weather in south Africa
Answers
A property unique to a conducting substance that determines its resistance is called
Answers
Resistivity is a property of every substance that specifies how strongly that material opposes to the flow of electric current through it.
The resistance of a piece of wire of length L and cross-sectional area A is related to the resistivity of the material, [tex]\rho[/tex], by the formula
[tex]R= \frac{\rho L}{A} [/tex]
Answer:
Electrical Resistivity
Explanation:
As we know that all different type of conductors has its different unique resistivity due to which all conductors will show different resistance for same shape and size.
As we know that the resistance of a conductor is given as
[tex]R = \rho\frac{L}{A}[/tex]
here we know
[tex]\rho[/tex] = resistivity
L = length of conductor
A = crossectional area of conductor
so here for all conductors the resistivity is unique property due to which all will show different resistance
A 60-kg skier starts from rest from the top of a 50-m high slope. if the work done by friction is -6.0 kj, what is the speed of the skier on reaching the bottom of the slope?
Answers
Answer:
27.9 m/s
Explanation:
You want the speed of a 60 kg skier at the bottom of a 50 m high slope if 6 kJ of energy is lost to friction.
Potential energyThe potential energy of the skier at the top of the slope is ...
PE = mgh
PE = (60 kg)(9.8 m/s²)(50 m)
Kinetic energyThe kinetic energy of the skier at the bottom of the slope is this potential energy, less the energy lost due to friction.
KE = PE -6000 J
That is related to the skier's speed by ...
KE = 1/2mv²
So, the speed is ...
[tex]v^2=\dfrac{2\cdot KE}{m}=\dfrac{2(mgh-6000)}{m}=2\left(gh-\dfrac{6000}{m}\right)\\\\\\v^2=2\left(9.8\cdot50-\dfrac{6000}{60}\right)=780\\\\\\v=\sqrt{780}\approx27.9\quad\text{m/s}[/tex]
The speed of the skier at the bottom of the slope is about 27.9 m/s.
A spring with a spring constant of 95 n/m is compressed a distance of 0.45 m from its relaxed position. by how much does the spring\'s potential energy change?
Answers
The potential energy change of a spring with a spring constant of 95 N/m compressed by 0.45 m is approximately 9.62 J, calculated using the formula U = 1/2 kx².
Explanation:When a spring with a spring constant of 95 N/m is compressed a distance of 0.45 m from its relaxed position, the potential energy of the spring changes according to the formula for elastic potential energy, U = 1/2 kx², where 'k' is the spring constant and 'x' is the distance of compression or extension from the equilibrium position. In this case, the spring's potential energy change is calculated as U = 1/2 × 95 N/m × (0.45 m)².
By computing this, U = 1/2 × 95 × 0.45² = 0.5 × 95 × 0.2025 J. This results in U = 9.61875 J, so the potential energy of the spring changes by approximately 9.62 J.
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A satellite of mass 6500 kg orbits the earth in a circular orbit of radius of 7.5 106 m (this is above the earth's atmosphere).the mass of the earth is 6.0 1024 kg. what is the speed of the satellite?
Answers
The two forces, centripetal force and gravity are
equal
So, G M m / r^2 = (m V^2) / r
so sqrt (GM/r)= V
G is a gravitational constant which is G=6,67.10exp(-11)
Sqrt (6.67 x 10^-11) (6 x 10^24)/7.5 x 10^6
so V= 7.30479295e9 or 7305 m/s
Final answer:
To find the speed of a satellite in Earth orbit, we use the formula for orbital speed with the Earth's mass and the orbit's radius. After calculation, the satellite's speed is found to be approximately 7357.7 m/s.
Explanation:
The question asks for the speed of a satellite of mass 6500 kg orbiting the Earth in a circular orbit with a radius of 7.5 × 106 m. The mass of the Earth is given as 6.0 × 1024 kg. To find the speed of the satellite, we use the formula for the orbital speed:
v = √(GM/r)
where v is the orbital speed, G is the gravitational constant (6.674 × 10−12 Nm2/kg2), M is the mass of the Earth, and r is the radius of the orbit. Plugging in the given values:
v = √((6.674 × 10−12 × 6.0 × 1024) / 7.5 × 106)
After performing the calculation, we find that the speed of the satellite is approximately 7357.7 m/s.
A 2.03 kg book is placed on a flat desk. suppose the coefficient of static friction between the book and the desk is 0.522 and the coefficient of kinetic friction is 0.283. how much force is needed to begin moving the book?
Answers
[tex]F = \mu N [/tex]
μ static friction coefficient
N normal force
The normal force N on a flat desk:
[tex]N = mg[/tex]
m mass
g gravitational acceleration = 9.81 m/s²
If the force exerted on the block is not larger then the maximum friction force, the block stays put.
A 2.03 kg book is placed on a flat desk, with a coefficient of static friction between the book and the desk of 0.522 and a coefficient of kinetic friction of 0.283, requires a force of 10.4 N to start moving.
First, we have to calculate the Normal force (N), which, in a flat horizontal desk, has the same magnitude and opposite sense as the weight of the object (W). We can calculate its magnitude using the following expression.
[tex]|N| = |W| = m \times g = 2.03 kg \times \frac{9.81m}{s^{2} } = 19.9 N[/tex]
where,
m: mass of the objectg: Earth's gravityTo begin moving the book, we must overcome the highest static friction force (F), which can be calculated using the following expression.
[tex]F = \mu \times N = 0.522 \times 19.9 N = 10.4 N[/tex]
where,
μ: coefficient of static frictionA 2.03 kg book is placed on a flat desk, with a coefficient of static friction between the book and the desk of 0.522 and a coefficient of kinetic friction of 0.283, requires a force of 10.4 N to start moving.
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what was perphaps the greatest challenge of human space flight?
Answers
The second law of thermodynamics dictates that ____. 1 point low-quality energy becomes static some high-quality energy is always degraded the amount of energy in the universe is constantly changing low-quality energy is required to get high-quality energy
Answers
The second law of thermodynamics dictates that "Some high-quality energy is always degraded.
It is important to know that the "Thermodynamics" is defined as a branch of physics that studies the mechanical action of heat and the others forms of energy.
Final answer:
The second law of thermodynamics states that in any energy transfer, some high-quality energy is always degraded, leading to increased disorder or entropy in the system.
Explanation:
The second law of thermodynamics dictates that some high-quality energy is always degraded to a lower quality form during energy transfers. This law further implies that no energy transfer is completely efficient, thus resulting in an increase in entropy, or disorder, within a system. This is a fundamental concept in physics that puts an arrow on the transformations of matter and energy, signifying a one-way flow from usable to less-usable forms of energy. It is most commonly observed through heat loss, where energy spontaneously transfers from a hotter object to a cooler one, increasing the disorder of the system.
Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How far away is the storm?
Answers
That particular strike was very roughly 2.4 km (1.5 miles) away from them.
That's if you use 340 m/s (1120 ft/sec) for the speed of sound.
But the air in the region for several thousand feet around a thunderstorm
is doing weird things to sounds that pass through it, so you can't use any
exact number for the speed of sound in a stormy area.
The only thing you can be absolutely sure of is that Johnny and his friends
need to round up their equipment and get in the house. NOW !
2,317 meters on edg!!
The maximum kinetic energy of photoelectrons is 3.10 ev . when the wavelength of the light is increased by 50%, the maximum energy decreases to 1.50 ev . part a what is the work function of the cathode?
Answers
The work function of the cathode is found to be 0.10 eV, calculated by using the relationship between the maximum kinetic energy of photoelectrons, the photon energy, and the work function within the context of the photoelectric effect.
The question involves finding the work function of a cathode in a photoelectric effect scenario. We know that the maximum kinetic energy (KE) of photoelectrons is related to the photon energy (hf) and the work function (
W) as KE = hf - W. We were given that the kinetic energy decreased to 1.50 eV when the wavelength increased by 50%, which implies the initial wavelength corresponds to a photon energy that gives photoelectrons a kinetic energy of 3.10 eV. Let's express these energies in the equation form:
KE1 = hf1 - W, where KE1 = 3.10 eV
KE2 = hf2 - W, where KE2 = 1.50 eV and hf2 = hf1/1.5 (since the wavelength increased by 50%, energy decreases by the same factor)
By subtracting the second equation from the first, we eliminate W and can solve for hf1. Once we have hf1, we can solve for the work function using either of the equations:
3.10 eV - 1.50 eV = hf1 - hf1/1.5
1.60 eV = 0.5 * hf1
hf1 = 3.20 eV
Work function W = hf1 - KE1 = 3.20 eV - 3.10 eV = 0.10 eV
The work function of the cathode is therefore 0.10 eV.
What does it mean to say that science is a “systematic” process?
Answers
Science is a systematic process, which means it follows a careful method that involves observation and experimentation. Through experimentation, information is collected that supports or refutes a scientist’s hypothesis.
edginuity answer
how does a shovel make work easier for digging a hole?
Answers
The value for the index of refraction for any material must be
Answers
In fact, the index of refraction of a medium is the ratio between the speed of light in vacuum (c) and the speed of light in that medium (v):
[tex]n= \frac{c}{v} [/tex]
But the maximum speed the light can travel at is exactly c, the speed of light in vacuum: so v is always less (or equal, in case of vacuum) than c, and so n is always greater than 1.
The standard unit of work in the metric system is named after the scientist _____. 1 Albert Einstein 2 James Joule 3 Isaac Newton 4 James Watt
Answers
Hope it helped!
A volleyball is dropped from a cliff and a soccer ball is thrown upward from the same position. When each ball reaches the ground at the bottom of the cliff, the volleyball will hit the ground with greater velocity.
Answers
The answer if false.
Explanation:
It is exactly the opposite. The soccer ball will hit the ground with greater velocity.
Since the soccer ball is thrown upward, when it returns to the same heigth from which it was throwm it will have a velocity downward, which will make that the soocer ball reaches the ground at the bottom of the clif with greater velocity than the volleball.
The greater the velocity with which the soccer ball is thrown upward, the greater its velocity when reaches the same point from which it was thrown, and the greater the velocity with which it will hit the ground at the bottom of the clif.
KCl(aq) + AgF(aq) → AgCl(s) + KF(aq) If 0.45 moles of potassium chloride are consumed completely and we start with twice as much silver fluoride, how many moles of solid silver chloride will be produced?
Answers
Answer
0.45 moles of silver chloride will be produced
Explanation
The mole ratios for the reactions are 1 for all reactants and reactants. This means that 1 mol of potassium chloride will react with 1 mol of silver fluoride to produce 1 mol of silver chloride and 1 mol of potassium fluoride.
If only 0.45 mol of potassium chloride is available to react with 0.9 mol of silver fluoride, the potassium chloride will be the limiting reagent in this reaction. This means that only 0.45 mol of each of the product will be formed. This means that only 0.45 mol of silver chloride will be formed.
.
Estimate the first three standing-wave frequencies of the vocal tract. use v=344m/s. (the answers are only an estimate, since the position of lips and tongue affects the motion of air in the vocal tract.)
Answers
The fundamental frequency for a stopped pipe is given with the following formula:
[tex]f_0=\frac{v}{4L}[/tex]
Higher harmonics are simply:
[tex]f=nf_0; n=1,3,5,7,9...[/tex]
Keep in mind that the stopped pipe produces only odd harmonics.
Lenght of a human vocal tract is 17cm(for males, females have slightly shorter vocal tract). We can now calculate the answers.
[tex]f_0=\frac{344}{4\cdot 0.17}=505.88$Hz[/tex]
Now we can calculate higher harmonics:
[tex]f_3=3f_0=1517.64$Hz[/tex]
[tex]f_5=5f_0=2529.4$Hz[/tex]
What is the main reason why many nuclear power plants are located near bodies of water?
Answers
Hope this helps!:)
~Scarlett