Domain -1,4,5,3,-5 Range n,w,y,n,w is this a function

Answers

Answer 1

Short answer yes.
If you apply the vertical line test, none of the xs have 2 ys. It does not matter if 2 xs have the same y value.

Related Questions

2.
How can you tell when a quadratic equation has two identical, rational solutions? (1 point)

when the radicand is negative
when b in the quadratic formula is greater than the radicand
when the radicand equals zero
when the radicand is not a perfect square,

Answers

The general formula for the solutions of a quadratic equation
ax² + bx + c = 0

are given by:

x₁₂ = [- b +- √(b²-4ac) ] / 2a

You have three cases:

1) the radicand is positive: you then have two dinstinct soutions, one with the root added to (-b) and then divided by 2a, and the other one with the root subtracted to (-b) and then divided by 2a.

2) the radicand is negative: you then have no solutions, because the root can't be performed. This case means that the given polynomial is never equal to zero.

3) the radicand is equal to zero: you then have the same value for both the solutions, which is -b/(2a).

Therefore your answer should be: C) when the radicand is equals to zero.

Write an equation in slope intercept form for the line that passes through (-2,3) and is parellel to the line whose equation 3x+2y=6

Answers

Parallel lines refers to a pair of straight lines that never intercept or touch each other. The slopes of this lines is the same one.

On this exercise is given the equation of a line and a point, and is asked to find the equation of a line in slope-intercept form that is parallel to the given one, and that passes through the given point.

3x+2y=6 Subtract 3x in both sides
2y=-3x+6 Divide by two in both sides to isolate y
y=-3/2x+3

The slope of the given line is -3/2, which means that the slope of a line parallel to this one, have to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the slope-intercept form y=mx+b, where letter m represents the slope.

y=mx+b Substitute the values of the given point and slope
3=(-3/2)-2+b Combine like terms
3=3+b Subtract 3 in both sides
0=b

The equation in slope intercept form for the line that passes through the point (-2,3) and is parallel to the line whose equation is 3x+2y=6 is y=-3/2x or y=-3/2x+0.

Six times a number decreased by 10 is eight

Answers

If you're looking for an expression then it will be:

6n - 10 = 8

6x - 10 = 8
Six times a number decreased by 10 is 8

Your equation is
6x - 10 = 8

Now solve for x
6x - 10 = 8

Add 10 to each side
6x - 10 + 10 = 8 + 10
6x = 18

Divide each side by 6
6x ÷ 6 = 18 ÷ 6
x = 3

Solve this problem, and identify the percent, amount, and base.
What percent of 60 is 45?

Answers

27% of 60 = 45

hope this helps
- Ashley

Answer:

45 is 75% of 60

Step-by-step explanation:

If we want to know what percentage of 60 is 45, our 100% will be 60.

to find out what percentage is 45 we apply a simple rule of three

[tex]60 \longrightarrow 100\\ 45\longrightarrow x\\ x=\frac{45(100)}{60}= 75[/tex]

Which of the following polynomials corresponds to the product of the multivariate polynomials 4x - 3y + 5 and x + 2y - -3?

Answers

Final answer:

The product of the multivariate polynomials 4x - 3y + 5 and x + 2y - -3 is 4x^2 + 5x + 5xy - 16y^2 + 19y - 27.

Explanation:

The product of two multivariate polynomials can be found by multiplying each term in the first polynomial by each term in the second polynomial and then combining like terms. In this case, we have:

(4x - 3y + 5)(x + 2y - -3) = 4x(x + 2y - -3) - 3y(x + 2y - -3) + 5(x + 2y - -3)

Using the distributive property, we can simplify this to:

4x^2 + 8xy - 12x - 3xy - 6y^2 + 9y + 5x + 10y - -15

Combining like terms:

4x^2 + 5x + 5xy - 16y^2 + 19y - 27

PLEASE HELP
8.08, part 2

11. Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

A) y squared over 45 minus x squared over 36 = 1
B) y squared over 81 minus x squared over 36 = 1
C) y squared over 36 minus x squared over 81 = 1
D) y squared over 36 minus x squared over 45 = 1

12. Find an equation in standard form for the hyperbola with vertices at (0, ±4) and asymptotes at y = ± 1 divided by 4. x.

A) y squared over 16 minus x squared over 64 = 1
B) y squared over 16 minus x squared over 256 = 1
C) y squared over 256 minus x squared over 16 = 1
D) y squared over 64 minus x squared over 4 = 1

13. Eliminate the parameter.
x = t - 3, y = t2 + 5

A) y = x2 + 6x + 14
B) y = x2 - 14
C) y = x2 - 6x - 14
D) y = x2 + 14

14. Find the rectangular coordinates of the point with the polar coordinates.
ordered pair 3 comma 2 pi divided by 3

A) ordered pair negative 3 divided by 2 comma 3 square root 3 divided by 2
B) ordered pair 3 square root 3 divided by 2 comma negative 3 divided by 2
C) ordered pair negative 3 divided by 2 comma 3 divided by 2
D) ordered pair 3 divided by 2 comma negative 3 divided by 2

15. Find all polar coordinates of point P where P = negative pi divided by 6 .

A) (1, negative pi divided by 6 + (2n + 1)π) or (-1, negative pi divided by 6 + 2nπ)
B) (1, negative pi divided by 6 + 2nπ) or (-1, negative pi divided by 6 + 2nπ)
C) (1, negative pi divided by 6 + 2nπ) or (1, pi divided by 6 + (2n + 1)π)
D) (1, negative pi divided by 6 + 2nπ) or (-1, negative pi divided by 6 + (2n + 1)π)

16. Determine two pairs of polar coordinates for the point (4, 4) with 0° ≤ θ < 360°.

A) (4 square root 2 , 135°), (-4 square root 2 , 315°)
B) (4 square root 2 , 45°), (-4 square root 2 , 225°)
C) (4 square root 2 , 315°), (-4 square root 2 , 135°)
D) (4 square root 2 , 225°), (-4 square root 2 , 45°)

17. The graph of a limacon curve is given. Without using your graphing calculator, determine which equation is correct for the graph.
a circular graph with an inner loop on the left

[-5, 5] by [-5, 5] (5 points)

A) r = 3 + 2 cos θ
B) r = 2 + 3 cos θ
C) r = 2 + 2 cos θ
D) r = 4 + cos θ

18. Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
r = -2 + 3 cos θ

A) No symmetry
B) y-axis only
C) x-axis only
D) Origin only

19. A railroad tunnel is shaped like a semiellipse, as shown below.
A semiellipse is shown on the coordinate plane with vertices on the x axis and one point of intersection with the positive y axis.

The height of the tunnel at the center is 54 ft, and the vertical clearance must be 18 ft at a point 8 ft from the center. Find an equation for the ellipse.

20. Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
r = 2 cos 3θ

Answers

11. Ans: (D)

Since all the vertices and the foci lie along the y axis, therefore, we would need the following equation for vertical hyperbola:

[tex] \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 [/tex]

Since (h,k) = (0,0)
Therefore, the above equation becomes,
[tex] \frac{(y)^2}{a^2} - \frac{(x)^2}{b^2} = 1 [/tex]

Now the distance between the vertices is:
2a = 12
=> a = 6

And the distance between the foci is:
2c = 18
=> c = 9

Since,
[tex]c^2 = a^2 + b^2[/tex]

=> [tex]b^2 = 45[/tex]

Hence, the equation becomes,
[tex]\frac{(y)^2}{36} - \frac{(x)^2}{45} = 1[/tex] (Option D:y squared over 36 minus x squared over 45 = 1)

12. Ans: (B)
The hyperbola's standard form is(as it is a vertical):
[tex] \frac{y^2}{16} - \frac{x^2}{b^2} = 1 [/tex] -- (X)

=> [tex]y^2 = ( \frac{16}{b^2})*(b^2 + x^2) [/tex]

=> y = ± [tex]( \frac{4}{b} ).x[/tex] --- (A)
Since asymptotes at y = ± [tex]( \frac{1}{4} ).x[/tex]. --- (B)
Compare (A) and (B), you would get,
[tex] \frac{4}{b} = \frac{1}{4}[/tex]

=> b=16

The equation (X) would become:
[tex] \frac{y^2}{16} - \frac{x^2}{256} = 1 [/tex] (Option-B)

13. Ans: (A) [tex]y = x^{2} + 6x + 14[/tex]
Equations given:
x = t - 3 --- (equation-1)
y = [tex]t^{2}[/tex] + 5 --- (equation-2)

From equation-1,
t = x + 3

Put the value of t in (equation-2),
[tex]y = (x+3)^{2} + 5[/tex]
[tex]y = x^2 + 9 + 6x + 5[/tex]
[tex]y = x^2 + 6x + 14[/tex]

Hence, the correct option is (A)

14. Ans: (A)

The polar coordinates given: [tex](3, \frac{2 \pi }{3} )[/tex] = (r, θ)
Since,
x = r*cosθ,
y = r*sinθ

Plug-in the values of r, and θ in the above equations:
x = (3) * cos(120°); since [tex]\frac{2 \pi }{3}[/tex] = 120°
=> x = [tex]- \frac{3}{2} [/tex]

y = (3) * sin(120°);
=> y = [tex] \frac{3 \sqrt{3} }{2} [/tex]

Ans: (x,y) = [tex](- \frac{3}{2} ,\frac{3 \sqrt{3} }{2})[/tex] (Option A)

15. Ans: (D)
The general forms of finding all the polar coordinates are:
1) When r >= 0(meaning positive): (r, θ + 2n [tex] \pi [/tex]) where, n = integer
2) When r < 0(meaning negative): (-r, θ + (2n+1) [tex] \pi [/tex]) where, n = integer

Since r is not mentioned in the question, but in options every r slot has the value r=1, therefore, I would take r = +1, -1(plus minus 1)

θ(given) = [tex] \frac{- \pi }{6} [/tex]

When r = +1(r>0):
(1, [tex] \frac{- \pi }{6} [/tex] + 2n[tex] \pi [/tex])

When r = -1(r<0):
(-1, [tex] \frac{- \pi }{6} [/tex] + (2n+1)[tex] \pi [/tex])

Therefore, the correct option is (D): (1, negative pi divided by 6 + 2nπ) or (-1, negative pi divided by 6 + (2n + 1)π)

16. Ans: (B)
In polar coordinates,
[tex]r = \sqrt{x^{2} + y^{2}} [/tex]

Since x = 4, y=4; therefore,
[tex]r = \sqrt{16 + 16} = 4 \sqrt{2} [/tex]

To find the angle,
tanθ = y/x = 4/4 = 1

=> θ = 45° (when [tex]r =4 \sqrt{2} [/tex])
If r = -[tex]r =4 \sqrt{2} [/tex], then,

θ = 45° + 180° = 225°
Therefore, the correct option is (B) (4 square root 2 , 45°), (-4 square root 2 , 225°)

17. Ans: (B)

(Question-17 missing Image is attached below) The general form of the limacon curve is:
r = b + a cosθ

If b < a, the curve would have inner loop. As you can see in the image attached(labeled Question-17), the limacon curve graph has the inner loop. Therefore, the correct option is (B) r = 2 + 3 cosθ, since b = 2, and a = 3; and the condition b < a (2 < 3) is met.

18. Ans: (C)
Let's find out!
1. If we replace θ with -θ, we would get:
r = -2 + 3*cos(-θ )
Since, cos(-θ) = +cosθ, therefore,
r = -2 + 3*cos(θ)

Same as the original, therefore, graph is symmetric to x-axis.

2. If we replace r with -r, we would get:
-r = -2 + 3*cos(θ )
r = 2 - 3*cos(θ)

NOT same as original, therefore, graph is NOT symmetric to its origin.

3. If we replace θ with -θ and r with -r, we would get:
-r = -2 + 3*cos(-θ )
Since, cos(-θ) = +cosθ, therefore,
r = 2 - 3*cos(3θ)

NOT same as original, therefore, graph is NOT symmetric to y-axis.

Ans: The graph is symmetric to: x-axis only!

19. (Image is attached below) As the question suggests that it is a horizontal ellipse, therefore, the equation for the horizontal ellipse is:

[tex] \frac{x^{2}}{a^{2}} + \frac{y_{2}}{b_{2}} = 1 [/tex] -- (A)

Since, x = 8f,
y = 18ft,
b = 54ft,
[tex]a^{2}[/tex] = ?

Plug-in the values in equation (A),
(A)=> [tex] \frac{64}{a^{2}} + \frac{324}{2916} = 1 [/tex]

=> [tex]a^{2}[/tex] = 72

Therefore, the equation becomes,
Ans: [tex] \frac{x^{2}}{72} + \frac{y_{2}}{2916} = 1 [/tex]

20. Ans: x-axis only
Let's find out!

1. If we replace θ with -θ, we would get:
r = 2*cos(-3θ )
Since, cos(-θ) = +cosθ, therefore,
r = +2*cos(3θ) = Same as original

Therefore, graph is symmetric to x-axis.

2. If we replace r with -r, we would get:
-r = 2*cos(3θ )
r = -2*cos(3θ) = Not same

3. If we replace θ with -θ and r with -r, we would get:
-r = 2*cos(-3θ )
Since, cos(-θ) = +cosθ, therefore,
r = -2*cos(3θ) = Not Same

Ans: The graph is symmetric to: x-axis only!

Final answer:

To find the equations of the axes, asymptotes, and conjugate hyperbola of a given hyperbola in general form, algebraic manipulation including finding the hyperbola's center, complementing squares for x and y, and determining the asymptote slopes is necessary.

Explanation:

When encountering the equation of a hyperbola in the general form ax² + 2hxy + by² + 2gx + 2fy + c = 0, finding the axes, asymptotes, and equation of the conjugate hyperbola requires a series of steps and some algebraic manipulation. Here's an outline how you would typically approach it:

First, find the center of the hyperbola by solving the system of equations derived from the partial derivatives with respect to x and y set to zero.

Transform the equation by completing the square for both x and y terms to determine the values of the semi-major and semi-minor axes.

To find the slopes of the asymptotes, you'd use the equation derived from the general form by setting the constant term such that only the x and y squared terms remain.

Lastly, the conjugate hyperbola can be determined by changing the signs associated with the squared terms.

As an example, an original hyperbola's equation might look like 8x² + 10xy - 3y² - 2x - 4y - 2 = 0. After required algebraic manipulations, which include centering the hyperbola and finding the orientation of the axes, the equations to the asymptotes are derived by setting the constant term to create the equation 8x² + 10xy - 3y² = 0 and solving for y in terms of x. Meanwhile, the conjugate hyperbola is found by negating the sign of the y squared term in the transformed equation of the original hyperbola.

PLEASE HELP!!!!!! MEDAL TO RIGHT ANSWER! Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
A rocket is launched from atop a 76-foot cliff with an initial velocity of 135 ft/s.
A.) Substitute the values into the vertical motion formula h=-16t^2+vt+c. Let h=0
B.) Use the quadratic formula find out how long the rocket will take to hit the ground after it is launched. Round to the nearest tenth of a second.
1.)0= -16t^2 + 135t + 76; 0.5 s
2.)0= -16t^2 + 135t + 76; 9 s,

Answers

After substitution your equation should be: 0= -16t^2+135t+76 and your answer to {A} would be {135 goes as V, 76 goes as C}. Question B is answered by soling the quadratic equation -16t^2+135t+76 = 0 Answer: 9.0s {the other solution is a negative }

The regular price of a child's entry ticket to a water park is $6 less than that for an adult's. The park offers half off all entry tickets during the off-peak season. The Sandlers paid a total of $78 for 1 adult ticket and 2 child's tickets to the water park during the off-peak season. 78 = one-half x + (x − 6) What is the regular price of a child's ticket?

Answers

c=a-6
0.5(a + 2c) = 78
0.5(a + a -6)=78
0.5(2a-6)=78
a-3=78
a=81

c=a-6
c=81-6
c=75

The more surface area an ice cube has, the more quickly it melts to cool a beverage. mark states that the ideal ice cube would be a prism that is a perfect cube of dimensions 2 by 2 by 2. denise thinks that the prism should be more flat, with dimensions of 1 by 2 by 4. which rectangular prism gives the greatest surface area, making for a better ice cube?

Answers

Answer: D

Step-by-step explanation:

Denise Rectangular prism gives the greatest surface area, making for a better ice cube.

What is Three dimensional shape?

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

The surface area of a rectangular prism can be calculated by adding up the areas of all six faces.

The surface area of a prism with dimensions l, w, and h is given by:

A = 2lw + 2lh + 2wh

For Mark's prism (2 by 2 by 2), the surface area is:

A = 2(2 × 2) + 2(2 × 2) + 2(2 × 2)= 24

For Denise's prism (1 by 2 by 4), the surface area is:

A = 2 (1 × 2) + 2 (1 × 4)+ 2 (2 × 4)= 28

So both prisms have the different surface area of 24 square units and 28 square units.

Hence, Denise rectangular prism gives the greatest surface area, making for a better ice cube

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Find the GCF of the monomials 118a^2 and 121b^2.

Answers

Factor both monomials
118a^2 = 2 * 59 * a * a
121b^2 = 11 * 11 * b * b

The greatest common factor is 1. Nothing else is common

What is the rate and unit rate of 16 dollars for 9 books?

Answers

the rate is 16 dollars for 9 books and the unit rate is $1.777777778 per book.

the equation Y= -16t2 + 120 can be used to represent the fruit's height above the ground, where t represents time, in seconds, after she threw the apple. How long did it take the apple to hit the ground? Round your answer to the neares hundreth.

Answers

y = -16t^2 + 120

Let y = 0

Solve for t.

0 = -16t^2 + 120

-120 = -16t^2

-120/-16 = t^2

7.5 = t^2

sqrt{7.5} = sqrt{t^2}

2.7386127875 = t

We now round to the nearest hundredths, which means to 2 decimal places.

Answer: t = 2.74 seconds

someone help a sister out

Answers

x= 14 for the top
x= -2 for the bottom

Elliot got some new trading cards.He has 4 packs with 20 cards each. Another pack has only 8 cards which equation show a way to find how much cards Elliot has in all?
A.c=(4×8)+20
B.c=4+20+8
C.c=(4×20)+8

Answers

C.c=(4x20)+8 is the correct one

C.c=(4x8)+20 because the 4 and 20 are first in the sentence and the 8 is being added

@ganeshie8

Which of the following would appear in the Credits column of a bank statement for a checking account?

A. An online bill payment
B. Interest earned
C. Bank fees
D. An ATM withdrawal

Answers

It is letter B or the interest earned. It is considered credit since it current asset or an income earned from the deposits or your account. This means that the banks pays the interest you've earned from the money in your account, it goes the same with your saving account.

Answer:

Interest earned

Step-by-step explanation:

(APEX)

A segment can have more than one bisector.
True
False

Answers

Can a Segment have more than one bisector. Yes A segment can have more than one bisector. For every line segment, there is one perpendicular bisector that passes through the midpoint. There are infinitely many bisectors, but only one perpendicular bisector for any segment.

Helppp!!! Will fan and Medal!!!
suppose n is an integer. select all statements below that are true:

n^2 + n is always an even integer
n^2 + n is always an even integer when n is even
n^2 + n is always an even integer when n is odd
n^2 + n is never an even integer when n is odd
n^2 + n is never an even integer
n^2 + n is sometimes an even integer

Answers

Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers

Can someone please explain how to find this answer? thanks

Answers

I would start with the standard form equation of the parallel line.
.. 5x -2y = 5(-2) -2(3) = -16
Then solve for y.
.. 2y = 5x +16 . . . add 2y+16; then divide by 2 for the next equation
.. y = (5/2)x +8 . . . . . . . corresponds to selection (B)

so, a line that is parallel to 5x-2y = -12, will have the same exact slope as that equation's, so what is it anyway?

[tex]\bf 5x-2y=-12\implies 5x+12=2y\implies \cfrac{5x+12}{2}=y \\\\\\ \cfrac{5x}{2}+\cfrac{12}{2}=y\implies \stackrel{slope}{\cfrac{5}{2}}x+6=y[/tex]

so, notice, from the slope-intercept form, it happens that the slope is 5/2, well, the line will have the same slope.

so we're looking for the equation of a line whose slope is 5/2 and runs through -2,3

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ &&(~ -2 &,& 3~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{5}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=\cfrac{5}{2}[x-(-2)] \\\\\\ y-3=\cfrac{5}{2}(x+2)\implies y-3=\cfrac{5}{2}x+5\implies y=\cfrac{5}{2}x+8[/tex]

f(5)= 3.14r^{2}

pls help

Answers

If you have
.. F(r) = πr^2
and you want to evaluate it for r=5, you put 5 in place of every instance of r, then do the arithmetic.
.. F(5) = π*5^2
.. F(5) = 3.14*25 = 78.5

Determine whether the statement is always, sometimes, or never true. Complete the explanation. In parallelogram MNPQ, the diagonals MP and NQ meet at R with MR = 7 cm and RP = 5 cm. ; diagonals of a parallelogram each other.

Answers

This is never true. In a parallelogram, the diagonals will always bisect each other. Thus, each of these segments would always have to be equal.

Final answer:

In a parallelogram, the diagonals bisect each other, meaning that they divide each other into two equal parts. Therefore, the statement is always true.

Explanation:

The statement is always true. In a parallelogram, the diagonals bisect each other, meaning that they divide each other into two equal parts. Therefore, if MR = 7 cm and RP = 5 cm, then NR = 7 cm and RQ = 5 cm. The diagonals MP and NQ meet at point R, so we have MR = NR and RP = RQ, confirming that the statement is always true.

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A) what is the value such that 50% or more of the students studied longer than that value?
a. 2 hours
b. 9 hours
c. 15 hours
d. 18 hours
e. 29 hours

Answers

c.15 hours i wish its right

What’s is the value of the digit 5 in the number 57,634?
5,000
1,000
50,000
10,000

Answers

This would be known to be the (tenth) thousands.

(5)7,,634= The 5 would equal the ten thousands because first, once the number would have it's (first) comma, this would be in the thousands. And also, this number has (2) numbers in it's thousands, and not just 1. But if it were to have 3, this would be another story, and from this, it would clearly explain to be your (option (b)).

Factor. 25m^100 - 121n^16

Answers

This is a difference of squares. Difference of squares factor like this.
a^2 - b^2 = (a + b)(a - b)
In your question all 4 factors must be perfect squares in order to use this property.

25 = 5*5
m^100 = m^50 * m^50
121 = 11 * 11
n^16 = n^8 * n*8

All four parts are perfect squares as required.
a = 5m^50
b = 11n^8

a^2 - b^2 = (5m^50 - 11n^8)(5m^50 + 11n^8)

Sophie did an anyonymous survey and collected her friends' credit scores. the scores she found are listed in the table below. what is the mean credit score in this group? (round to the nearest whole point, if applicable.) 682 601 744 674 701 790 676 638 773
a. 698
b. 695
c. 676
d. 701

Answers

To find the mean of the data, you will combine all values together and then spread them all out evenly to create one value that represents the data.

In math this involves adding the data together and then dividing the sum by how many pieces of data there are.

682 + 601 + 744 + 674 + 701 + 790 + 676 + 638 + 773 = 6279

6279/9 = 697.66...

The rounded credit score is 698 (Choice A).

Using the mean concept, it is found that the mean credit score in this group is given by:

a. 698

What is the mean?

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

In this problem, there are 9 observations, which are:

682 601 744 674 701 790 676 638 773

Hence, the mean is given by:

[tex]M = \frac{682 + 601 + 744 + 674 + 701 + 790 + 676 + 638 + 773}{9} = 698[/tex]

Hence option a is correct.

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a painter needs to cover a triangular region 60 meters by 68 meters by 71 meters. a can of can cover 70 square meters.. how many cans will be needed??,

Answers

When we know all 3 sides of a triangle, we can calculate area by using Heron's Formula. (see attached). Where s is the SEMI-PERIMETER
perimeter = 60 + 68 +71 = 199
SEMI-Perimeter = 199/2 = 99.5
Area = sq root (99.5 * (99.5-60) * (99.5-68) * (99.5-71)
Area = sq root (99.5 * 39.5 * 31.5 * 28.5)
Area = sq root ( 3,528,381.94 )
Area = 1,878.4 square meters
1,878.4 / 70 sq mtr per can means you will need
26.83 cans OR 27 cans

Final answer:

To cover the triangular region, the painter will need approximately 29 cans of paint.

Explanation:

To find the number of cans needed to cover the triangular region, we first need to calculate the total area of the region. We can do this by using the formula for the area of a triangle: A = (1/2) * base * height. Assuming the 60 meters side is the base, we can use the formula to find the area: A = (1/2) * 60 * 68. The area of the triangular region is 2040 square meters. Since each can covers 70 square meters, we can divide the total area by the area covered by each can: 2040 / 70 = 29.14.

Therefore, the painter will need approximately 29 cans of paint to cover the triangular region.

Learn more about Calculating the number of paint cans needed for a triangular region here:

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∠ RQS and ∠ TQS are a linear pair where m∠ RQS = 2x + 4 and m∠ TQS = 6x + 20
1. Solve for x.
2. Find m∠ RQS and m∠ TQS
3. Show how you can check your answer
I want help to understand how to solve the problem because I have others to solve also.,

Answers

Since the given angles are a linear pair, that means that they add up to 180 degrees (straight line). So we know that:
m∠ RQS + m∠ TQS = 180

Now let's answer the questions.
1. Solve for x
m∠ RQS + m∠ TQS = 180
2x + 4 + 6x + 20 = 180
2x + 6x + 4 + 20 = 180
(2 + 6)x + 24 = 180
8x + 24 = 180
8x = 156
x = 19.5

2. Find m∠ RQS and m∠ TQS
m∠ RQS = 2x + 4
m∠ RQS = 2*19.5 + 4
m∠ RQS = 39 + 4
m∠ RQS = 43

m∠ TQS = 6x + 20
m∠ TQS = 6*19.5 + 20
m∠ TQS = 117 + 20
m∠ TQS = 137

3. Show how you can check your answer.Verify that they do add up to 180.
So 43 + 137 = 180
This demonstrates that they do make up a linear pair.

Answer:

∠RQSangle r q s and ∠TQSangle t q s are supplementary angles, so the sum of the angles should equal 180.

Step-by-step explanation:

if point P lies on segment AB with endpoints at A(-5,11) and B(1,5) such that AP:PB = 1:1 then p must have coordinates of?

Answers

That means P is the midpoint:

[tex]P=\left(\frac{x_1+x_2}{2}\;,\; \frac{y_1+y_2}{2} \right) \\ \\ P=\left(\frac{-5+1}{2}\;,\; \frac{11+5}{2} \right)=\left(\frac{-4}{2}\;,\; \frac{16}{2} \right) \\ \\ P=(-2\;,\;8)[/tex]

If the ratio is 1:1 then the point must be a mid-point. Then the coordinate of the mid-point P is (–2, 8).

What is coordinate geometry?

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of line, etc.

If point P lies on segment AB with endpoints at A(-5,11) and B(1,5) such that AP:PB = 1:1.

We know that if the ratio is 1:1 then the point must be a mid-point.

Let the coordinate of point P be (x, y)

Then we have

[tex]\rm (x,y) = ( \dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})\\\\(x,y) = (\dfrac{-5+1}{2}, \dfrac{11+5}{2})\\\\(x,y) = (\dfrac{-4}{2} , \dfrac{16}{2})\\\\(x,y) =(-2, 8)[/tex]

The coordinate of the mid-point P is (–2, 8).

More about the coordinate geometry link is given below.

https://brainly.com/question/1601567

What is the first step in solving 12 (9+5) - 6 (3)?

Answers

Use BEDMAS the order of operations and solve the Brackets first.

Alisha has a $15,000 car loan with a 6 percent interest rate that is compounded annually. How much will she have paid at the end of the five-year loan term?
total amount = P (1 + i)t
$19,500.25
$15,900.50
$20,073.50

Answers

Use the attached formula.
r = 6 / 1,200 = .005
Principal = 15,000
n = number of payments = 5 yrs * 12 months = 60
TOTAL Loan Cost = (.005 * 15,000 * 60) / 1 -(1.005^-60)
TOTAL Loan Cost = 4,500 / (1 - 0.7413721962)
TOTAL Loan Cost = 4,500 / 0.2586278038
TOTAL Loan Cost = 17,399.52
Although it is NOT one of the choices, I think my answer of 17,399.52 is correct. Using a monthly loan payment calculator, I get 289.99 for the monthly payment. 290*60 months = 17,400 so that seems correct.
I do not think that formula you posted is correct. (Compare it to the one I posted.)

Answer:

20,073.50

Step-by-step explanation:

i used the formula

Can someone help me with 2-5?

Answers

Problem 2

Let's say there are 1000 people at the game
0.27*1000 = 270 of them are students
0.06*1000 = 60 are students who didn't buy a program
60/270 = 0.222 = 22.2% of the students will not buy a program

So the answer is roughly 22% when rounded to one decimal place

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Problem 3

Like with problem 2, we'll assume 1000 people at the game
0.73*1000 = 730 adults
0.42*1000 = 420 adults buy a program
approximately 420/730 = 0.5753 = 57.53% of the adults bought a program which rounds to 58%

Answer: 58%

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Problem 4

The answer here is simply 63% since this is the percent form of 0.63

The value 0.63 is the total for the "Yes" column

You already found this value by adding up the values in the "yes" column from the original table: 0.42+0.21 = 0.63

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Problem 5

x = total number of students and adults combined

look in the "students" row and "no" column. The value of 0.06 is found there.

0.06*x = 35
0.06*x/0.06 = 35/0.06
x = 583.333
which rounds to 583

So there are 583 people.

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