-8 hope it helps i just took the test
"which of newton's laws could we have used to predict that the forces in parts a and b are equal and opposite?"
Newton's third law of motion, stating every action has an equal and opposite reaction, allows us to predict equal and opposite forces in different parts of a system. The interaction of these forces depends on the chosen system of interest and whether the forces are internal or external to that system.
The Newton's third law of motion is the principle we could use to predict that the forces in parts a and b are equal and opposite.
This law states that for every action there is an equal and opposite reaction, which means that whenever one body exerts a force on another, the second body exerts a force that is equal in magnitude but opposite in direction on the first body.
The choice of the "system of interest" is crucial as it affects whether the action-reaction forces are internal and cancel each other out, or if they are external and do not cancel. If both bodies are included in the system, the forces are internal and cancel because they are equal and opposite.
However, if only one body is chosen as the system of interest, the force exerted by the other body is considered external, and therefore, it does not cancel out within the system being analyzed.
How many Neutrons does this atom have?
4
6
10
14
As we can see in the given figure there are four spheres of blue color which are having + sign
They represents protons inside the nucleus
And the other red spheres have no sign so these are the neutral one which we say as neutrons
SO here in this figure the atom must have 6 neutrons
so correct answer will be
N = 6
Compare and contrast the dark zone of the ocean with the forest floor of a tropical rain forest.What living or nonliving factors affect these areas?
Understandably, the ocean floor receives very little sunlight, because of how far down it is and the way that water molecules scatter and absorb light. As a result, the organisms have many adaptations to help them survive even this harsh climate.
Similarly to the ocean floor, the bottom of a rain forest doesn't receive much sunlight either. The plants there have adapted to have huge leaves, so that they can get as much sunlight for photosynthesis as possible.
An element
is made up of compounds
is a homogenous mixture
can be divided by physical
cannot be divided into smaller substances by chemical means
A lens collects light and focuses it into a small spot. this increases the ________ of the light wave. w
How many cells must be connected in series to give the 350 v a large catfish can produce?
Final answer:
Approximately 2333 electro plaques, or biological cells, would be needed to be connected in series to produce 350 V, given that each cell produces 0.15 V.
Explanation:
To calculate the number of cells required to produce a voltage of 350 V, similar to what a large catfish can produce, we must understand that when cells are connected in series, the total voltage is the sum of the individual voltages of each cell. If each cell, similar to those in an electric eel, produces an electromotive force (emf) of 0.15 V, then the number of cells required to reach 350 V would be the total voltage desired divided by the voltage of one cell.
(350 V) / (0.15 V per cell) = 2333.33 cells
Therefore, approximately 2333 cells would need to be connected in series to produce 350 V. This figure is derived by understanding that the potential difference across each cell adds up when they are connected in a series circuit, a principle that is crucial in the functioning of biological cells called electro plaques in electric fish.
The interior of earth consists almost entirely of _____ rock. felsic molten solid sedimentary
What force causes static cling? What two types of charges does this force have?
You're using a wedge to split a log. you are hitting the wedge with a large hammer to drive it into the log. it takes a force of 1900 n to push the wedge into the wood. if the wedge moves 0.23 m into the log, how much work have you done on the wedge?
Answer: 437 J
Work done can be defined as the product of force and displacement. It is the work required to move an object to certain distance using a certain force.
[tex]work=force\times displacement[/tex]
It is given that:
[tex]Force=1900 N[/tex]
[tex]Displacement=0.23 m[/tex]
Then, [tex] work=1900N\times 0.23m = 437 N-m=437J [/tex]
Hence, the work done on the wedge to drive it into log is 437 J
The image illustrates that as the distance between two objects increases, the force of gravity ____________. A) decreases. B) increases. C) remains the same. D) increases then decreases.
B; Decreases
Because,
The image illustrates that as the distance between two objects increases, the force of gravity decrease. The strength of gravity is affected by the distance between two objects as well as their masses
What is the weight of a 45 kg box?
Final answer:
The weight of a 45 kg box, assuming standard Earth gravity, would be 441.45 Newtons, which is calculated by multiplying the mass by the acceleration due to gravity.
Explanation:
The weight of an object is the force due to gravity acting on its mass. It is calculated using the equation Weight = Mass × Gravity. The mass of the box is given as 45 kg, and assuming standard Earth gravity which is approximately 9.81 m/s2, the weight can be calculated as follows:
Weight = 45 kg × 9.81 m/s2 = 441.45 Newtons (N)
Therefore, the weight of a 45 kg box would be 441.45 Newtons under Earth's gravity.
You swing a bat and hit a heavy box with a force of 1500 n. the force the box exerts on the bat is
The equation for gear ratio
justin and his friends are on the football team. they consider skateboarders at their school to be an out-group. what does this mean?
Explanation:
Justine and his friends feel superior of themselves to the skateboarders team as they have a negative feeling about the skateboarders team. They always isolate and out group the skateboarders team in the school. They feel that football is the only superior sport and all has to play and support football and not skateboarding as a sport.
Thus they have a negative feeling towards the skateboarders team.
Airbags will deploy in a head-on collision, but not in a collision that occurs from an angle.
Final answer:
The question focuses on why airbags deploy in head-on collisions but may not in angled collisions. Airbags are meant to minimize injuries by increasing the deceleration time of a passenger's head, decreasing the force experienced. They are triggered by vehicle sensors that detect significant changes in velocity.
Explanation:
Airbags are designed to deploy upon impact to minimize serious injuries. They accomplish this by increasing the time it takes for a passenger's head to come to rest, which in turn decreases the force on the head. A head-on collision triggers the airbags due to significant changes in velocity, while an angled collision might not trigger them if the sensors do not detect a sufficient impact.
The airbag system's sensors are calibrated to respond to certain types of impacts to ensure that airbags deploy when most effective. In angled collision, the angle of impact might not meet the criteria for airbag deployment because the force might be distributed differently and the sensors may not detect impact as severe enough to trigger airbag deployment.
The angle and severity of the collision plays a significant role in determining whether the airbag will deploy or not.
Without inertia, how would an object that is experiencing a centripetal force behave?
It would move in a line away from the circle’s center.
It would move in a line toward the circle’s center.
It would move in a curved, circular path.
It would move in a line tangent to the circular path.
B. It would move in a line toward the circle’s center.
Explanation:
got it right on edge 2022
When a puddle dries up what are the particles really doing
Final answer:
When a puddle dries up, water undergoes evaporation, where the particles change from liquid to gas and eventually disperse into the atmosphere as invisible water vapor. The rate of evaporation increases with temperature, and sediment particles in the puddle settle down due to gravity.
Explanation:
Understanding Evaporation of Puddles
When a puddle dries up, the water particles are undergoing a phase change from liquid to gas, known as evaporation. On a warm day after it has rained, the increase in temperature causes the water in mud puddles to evaporate more quickly. This is because warmer air can hold more moisture. During the process of evaporation, the liquid water particles gain energy and transition into the gaseous state, becoming invisible water vapor in the air.
Similarly, on a cold, dry day, ice can sublimate, which means it changes directly from solid to gas without going through the liquid phase, also leaving no water behind. In both cases, the particles that were once part of the puddle are now dispersed into the atmosphere as water vapor. Dust and other sediment particles in the puddle settle down due to gravity, unless they are colloidal in size, which can stay suspended because of Brownian motion.
A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal component of 30 m/s. using g = 9.8 m/s2 , the distance from launching to landing points is:
For a projectile, the distance of travel is determined by the horizontal velocity and the time spent in the air, which is dictated by the vertical velocity and gravity. We calculate the time from the equation t = (2*V0y)/g and then find the range from x = V0x * t.
Explanation:The distance from launching to landing for a projectile is determined by the horizontal motion because vertical motions regulate the time the projectile spends in the air but not the distance covered. Using the given initial vertical velocity (20 m/s) and horizontal velocity (30 m/s), and considering that the acceleration due to gravity, g, is -9.8 m/s2, the time in the air (t) can be calculated from the motion equation: t = (2*V0y)/g, where V0y is the initial vertical component of the velocity. Then, the range, or horizontal distance covered, x, can be found by multiplying this time by the horizontal component of the initial velocity, V0x: x = V0x * t, leading to the total distance the projectile traveled.
Learn more about Projectile Motion here:https://brainly.com/question/29545516
#SPJ11
A negatively charged object is located in a region of space where the electric field is uniform and points due north. the object may move a set distance d to the north, east, or south. rank the three possible movements by the change in electric potential energy (ue) of the object. rank from greatest increase to decrease in ue.
(a) There will be an increase in the potential energy when the charge moves North.
(b) The variation of potential energy will be zero when the charge is moving to the east.
(c)There is a loss in potential energy when a charge moves to the South.
What will be the potential energy of the charge at different directions?(a) The largest increase in potential energy occurs when the charge is moving north. This is because the charge is negative,
so it acquires potential energy when moving in the same direction of the field (vice versa, a positive charge when moving in the direction of the field loses potential energy converting it into kinetic energy).
The amount of potential energy gained is equal to the product of the charge and the distance covered:
[tex]\rm \Delta PE=qD[/tex]
(b) The second-largest increase is when the charge is moving east. In this case, actually, the variation of potential energy is zero.
This is because the charge is moving perpendicular to the field, and so it is moving along points with the same potential. Therefore, in this case, the variation of potential energy is zero:
[tex]\rm \Delta PE=0[/tex]
(c) Finally, when the charge is moving south, it loses potential energy. This is because it is moving against the electric field,
since it is a negative charge, in this direction it loses potential energy converting it into kinetic energy. Therefore, in this case
[tex]\rm \Delta PE=-qD[/tex]
Thus
(a) There will be an increase in the potential energy when the charge moves North.
(b) The variation of potential energy will be zero when the charge is moving to the east.
(c)There is a loss in potential energy when a charge moves to the South.
To know more about Energy of the Charge follow
https://brainly.com/question/874116
When a temperature of a pot in a kiln is 1 , 200 ∘ 1,200∘f, an artist turns off the heat and leaves the pot to cool at a controlled rate of 81 ∘ 81∘f per hour. express the temperature of the pot in degrees celsius as a function of the time t t (in hours) since the kiln was turned off?
Final answer:
The temperature of the pot in Celsius as a function of time since the kiln was turned off is given by the linear equation T(t) = 648.89 - 45t.
Explanation:
When a temperature of a pot in a kiln is 1,200°F, and the artist turns off the heat, allowing the pot to cool at a controlled rate of 81°F per hour, the temperature of the pot in degrees Celsius as a function of the time t (in hours) can be calculated using two steps. First, convert the starting temperature from Fahrenheit to Celsius using the formula C = °(F - 32) ÷ 1.8. For 1,200°F, this converts to approximately 648.89°C. Second, since the cooling rate is 81°F per hour, which equals 45°C per hour (using the conversion factor 1°F = 5/9°C), the temperature as a function of time t in Celsius is given by the linear equation T(t) = 648.89 - 45t.
Which statement about work and power correctly describes an automobile race?
The car do different amount of work depending on how fast they finish.
The car that finishes last has the lowest
Power
The car with the greatest power travels the greatest distance
The car do different amounts of work depending on their power.
Answer: "The car that finishes last has the lowest power."
Describe how the amount of heat released or absorbed related to specific heat capacity and amount of it? A) Amount of heat absorbed or released is doubled if quantity is doubled. If a different substance with half the specific heat capacity is used, the amount of heat absorbed or released is doubled. B) Amount of heat absorbed or released is doubled if quantity is cut in half. If a different substance with half the specific heat capacity is used, the amount of heat absorbed or released is doubled. C) Amount of heat absorbed or released is doubled if quantity is doubled. If a different substance with half the specific heat capacity is used, the amount of heat absorbed or released is cut in half. D) Amount of heat absorbed or released is doubled if quantity is cut in half. If a different substance with half the specific heat capacity is used, the amount of heat absorbed or released is cut in half.
Answer:
The answer is C).
Explanation:
I just did this on USATestprep
When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What type of learning is Ian demonstrating?
Answer: observational learning and modeling
Explanation:
To get an spaceship into orbit, it has to move
about as fast as the speed of sound
about as fast as the speed of light
about 18,000 miles per hour
there is no minimum speed for orbital motion
How much heat energy, in kilojoules, is required to convert 76.0 g of ice at −18.0 ∘c to water at 25.0 ∘c ?
The total heat energy required to convert 76.0 g of ice at -18.0°C to water at 25.0°C is 35.184 kJ. This includes the energy to heat the ice to 0°C, melt the ice, and heat the water to 25°C.
Explanation:To calculate the heat energy required, we need to account for three processes: heating the ice to 0°C, melting the ice, and then heating the water to 25°C.
For the first process, we use the formula Q=mcΔT, where m is mass, c is specific heat, and ΔT is the temperature change. Ice has a specific heat of 2.09 J/g°C. So Q = 76.0 g * 2.09 J/g°C * 18°C = 2854.56 J.
For the second part, we use the formula Q = mLf, where m is mass and Lf is heat of fusion. For ice, Lf = 334 kJ/kg or 334 J/g. So Q = 76.0 g * 334 J/g = 25384 J.
For the last process, we once again use Q=mcΔT, this time with the specific heat of water, 4.184 J/g°C. So Q = 76.0 g * 4.184 J/g°C * 25°C = 7946 J.
To get the total heat energy required, we add these three quantities together and convert from joules to kilojoules. Q_total = (2854.56 J + 25384 J + 7946 J) / 1000 = 35.184 kJ. So, it requires 35.184 kJ of heat energy to convert 76.0 g of ice at -18.0°C to water at 25.0°C.
Learn more about Heat Energy here:https://brainly.com/question/25384702
#SPJ11
what are the inner planets relative distance from the sun
The position vector r describes the path of an object moving in the xy-plane. position vector point r(t) = ti + (ât2 + 7)j (1, 6) (a) find the velocity vector, speed, and acceleration vector of the object.
The velocity vector is v(t) = i + 2âtj, the speed is |v| = sqrt(1 + 4a^2t^2), and the acceleration vector is a(t) = 2âj.
Explanation:To find the velocity vector of the object, we need to take the derivative of the position vector with respect to time. The velocity vector is given by v(t) = dr/dt = i + 2âtj.
To find the speed of the object, we can calculate the magnitude of the velocity vector. The speed is given by the formula |v| = sqrt((i + 2âtj) dot (i + 2âtj)) = sqrt(1 + 4a^2t^2).
To find the acceleration vector of the object, we need to take the derivative of the velocity vector with respect to time. The acceleration vector is given by a(t) = dv/dt = 2âj.
You walk into an elevator, step onto a scale, and push the "up" button. you recall that your normal weight is 639 n . when the elevator has an upward acceleration of magnitude 2.90 m/s2 , what does the scale read?
This question deals with the concepts of the actual weight and apparent weight.
The apparent weight of the person is "827.9 N".
APPARENT WEIGHTThe apparent weight of an object is the reaction of the elevator floor on the person while the elevator is in accelerated motion. It is not the actual weight but the weight felt by the person for that time. In this case the elevator is moving up. Hence the apparent weight will be:
[tex]W_a=m(g+a)=mg+ma\\W_a=W+ma[/tex]
where,
W = actual weight = 639 Nm = mass = [tex]\frac{W}{g}=\frac{639\ N}{9.81\ m/s^2}[/tex] = 65.14 kga = acceleration = 2.9 m/s²[tex]W_a[/tex] = apparent weight = ?Therefore,
[tex]W_a=639\ N + (65.14\ kg)(2.9\ m/s^s)[/tex]
[tex]W_a=827.9\ N[/tex]
Learn more about apparent weight here:
https://brainly.com/question/26393265
The scale reading in an elevator accelerating upwards will display an increased weight due to the additional force of acceleration. When an elevator accelerates with a magnitude of 2.90 m/s^2, the scale will show a higher value than the normal weight, calculated by the sum of gravitational force and force of acceleration.
Explanation:When you step onto a scale in an elevator that is accelerating upwards with a magnitude of 2.90 m/s2, the scale reading will be higher than your normal weight due to the additional force required to accelerate you upwards. Given that your normal weight is 639 N, we can calculate the new scale reading by incorporating the effects of the elevator's acceleration using Newton's second law of motion.
To find the new scale reading, we first determine the apparent weight. The apparent weight is the sum of the true weight (gravitational force) and the force of acceleration (ma).
Apparent weight = True weight (W) + Force of acceleration (ma)
Where the true weight W = mg (mass times gravity), and a is the acceleration of the elevator.
Assuming Earth's gravity to be 9.81 m/s2, we can calculate the apparent weight as follows:
Apparent weight = mg + ma
Now, we need to find the mass (m) from the given weight (639 N), which is m = W/g = 639 N / 9.81 m/s2.
Then plug the mass and the given acceleration into the equation for apparent weight.
The scale reading in an accelerating elevator is directly proportional to the acceleration; it increases as the elevator accelerates upwards. However, once the elevator reaches a constant velocity, the scale reading will return to your normal weight, 639 N, because there will be no additional force from acceleration (a = 0).
If we mechanically squeeze a gas into a smaller volume, what happens to the pressure and temperature?
(A) The pressure and temperature both increase, but we can't predict how much each one will change.
(B) The pressure increases and the temperature decreases
(C) Only the pressure increases
If we mechanically squeeze a gas into smaller volume, the pressure and temperature both will increase, but we can't predict how much each one will change.
Answer: B
Explanation:
According to kinetic theory of gases, the pressure of a gas is inversely proportional to the volume of the gas. So as the volume is decreased, the pressure of the gas tends to increase.
As there is an increase in the pressure due to compression of volume by an external force, the temperature of the gas also increases as the external force or the work done will transfer its energy to the gas molecules leading to the increase in temperature.
The best example for this is heating of the mechanical air pumping machine for cycle Tyre.
During filling of air in cycle Tyre, we have to give extra mechanical energy in the pumping piston to compress the volume of air in the pumping machine and that gas get transferred to the Tyre.
But while pumping, the mechanical pumping machine gets heated up due to the mechanical work done on the piston.
This work done is transferred as heat to the molecules of gas thus increasing the gas temperature on decreasing the volume and also the pressure will be increased when volume is compressed mechanically.
Brad is working on a speed problem in physics class. The problem tells him that a girl runs from her house to the park 0.05 km away in 10 s. Brad calculates that her speed is 0.005 m/s. Is he correct? If not, explain the flaw or flaws in his problem solving process.
Answer:
He is incorrect! Her speed was 5m/s.
Explanation:
For calculating the speed, first we shall remember that:
[tex]v=\dfrac{d}{t}[/tex]
Where [tex]v[/tex] is the speed, [tex]d[/tex] is the distance travelled and, [tex]t[/tex] is the time it takes to travel distance [tex]d[/tex].
So one migth think that velocity can be easely compute:
[tex]v=\dfrac{0.05}{10}[/tex]
[tex]v=0.005\dfrac{m}{s}[/tex]
Be carefull, he does not make a proper dimensional analisis!
Before computing the speed we must know in what dimensions our values are.
[tex]d=0.05km[/tex], distances is measure in Kilometers.
[tex]t=10s[/tex], time is measure in seconds.
If we want our speed to be in [tex]m/s[/tex], first we need to be sure that our values are expressed in meters and seconds.
Time is already expressed in seconds, distance is not in Kilometers.
So
[tex]0.05Km=50m[/tex],
now we can compute the speed:
[tex]v=\dfrac{d}{t}[/tex]
[tex]v=\dfrac{50m}{10s}[/tex]
[tex]v=\5dfrac{m}{s}[/tex]