Answer:
990 pounds
Step-by-step explanation:
If one troop eats 11 pounds and there are 90 troops, you only need to multiply 90 by 11.
what is the slope of 2x+3y=15
Note that the slope-intercept form is: y = mx + b
First, set the equation as such
2x (-2x) + 3y = (- 2x) + 15
3y = -2x + 15
Isolate the y. Divide 3 from both sides
(3y)/3 = (-2x + 15)/3
y = (-2/3)x + 5
-2/3 is your slope
hope this helps
"Sketch a possible graph for a negative Quintic polynomial with one real zero." Can anyone explain how this is done? And if possible provide a graph?
quintic means degree of 5.
a negative quintic would be: f(x) = -x⁵ +
an example with one real zero could be: -x⁵ + x³ + x + 3 (see attachment)
Well let's start with y = -x^5 and y = - x^5 +1
The graph looks like the one on the right for these two. The red one is y = - x^5 and the blue one is y = - x^5 + 1
See below on the right
You can tell that these two are correct because there is only 1 x axis intercept for each of them. That means there is only 1 real solution which is what you are calling for.
Another one could be something like
y = -(x - 5)(x^2 + 2)(x^2 + 3)
The graph of that is on the left.
Is 109 an prime nor composite number
Hi!
Answer is Yes!
Explanation: This question is super easy for me. 109 is a prime number because it has not possible to factorize it. By the other words, 109 it can only divided by the 1. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie
If an object is said to be moving at 10 m/s due north. The measurement 10 m/s north would be best described as
A) a speed.
B) a velocity.
C) neither a speed or velocity.
D) either a speed or a velocity.
Remark
Velocity is speed that has a direction. So the answer excludes both being true. C and D are both incorrect for the same reason: you cannot have both together when a direction is given.
Speed has no direction.
Answer: B Velocity has direction and a magnitude of speed.
−3r+10=15r−8 solve for R
Answer,
R = 1
Explanation,
Subtract 10 from both sides,
-3r + 10 - 10 = 15r - 8 - 10
Simplify,
-3r = 15r - 18
Subtract 15r from both sides,
-3r - 10 = 15r - 18 - 15r
Simplify,
-18r = -18
Divide both sides by -18,
-18r/-18 = -18/-18
Simplify,
R = 1
Hope this helps :-)
To solve the equation −3r+10=15r−8 for r, we first move all r terms to one side and constant terms to the other to get -18r = -18. We then divide both sides by -18 to find that r = 1.
Explanation:The question is asking us to solve the equation −3r+10=15r−8 for the variable r. To do this, we first combine all terms involving r on one side of the equation and constant terms on the other side. Therefore, the equation becomes:
−3r - 15r = -8 - 10
which simplifies to:
-18r = -18.
We then divide both sides of the equation by -18 to solve for r:
r = 1.
Learn more about Algebraic Equations here:https://brainly.com/question/31303181
#SPJ2
How Would You Guys Describe A "Function Notation"?
Hey there!
When you write an equation in function notation, one side of the equation is, "f(x)".
You can replace x with another variable such as n if you are using a different one.
f(x) takes the place of y in an equation.
For example, the equation y = 3x + 2 in function notation is f(x) = 3x + 2.
Hope this helps!
Gabby drove 124 miles in 150 minutes. Find Gabby's speed in kilometers per hour. (HELP FOR TEST TMRRW PLZ 15 POINTS!!!)
First, you need to convert the minutes into hours, to do this you divide the minutes by 60 (the amount of minutes in an hour). Once you've gotten the value (which is 2.5), you divide that by the amount of miles drove, then you get the unit rate, or in other words the kilometers per hour, which equals 49.6 km/h
an investigation is currently worth 1.2 X10^7 dollars twenty years ago the investment was worth 9.6X10^5 dollars how many times greater in the value of the investment today than the value of the investment twenty years ago A. 0.125 B. 12.5 C. 125 D. 12,500
As given,
Current value = [tex]1.2\times10^{7}[/tex] dollars
Twenty years ago value was = [tex]9.6\times10^{5}[/tex] dollars
suppose x times the investment has increased, so,
[tex]9.6\times10^{5}[/tex]*x=[tex]1.2\times10^{7}[/tex]
x = [tex]\frac{1.2\times10^{7}} {9.6\times10^{5}}[/tex]
this gives x = 12.5 times.
Hence, option B is the correct answer.
At a restaurant 42 people had breakfast on Saturday morning. 1/7 ate eggs only 2/3 ate both pancakes and eggs the remaining ate pancakes only. How many people ate pancakes
i need help with this problem
simplify 7(2y+1)+3y
the answer is 17y + 7
distribute 14y+7+3y
add like terms 17y +7
Let x = number of games played. Equation: 37.50 – .5x = 42.75 – .75x Step 1: 37.50 – 1.25x = 42.75 Step 2: – 1.25x = 5.25 Step 3: – 4.2 = x Sandor knows his answer is incorrect because a negative number of games cannot be played. What was Sandor’s mistake?
Answer:
Answer you are looking for would be C. I just finished the quiz.
Answer:
(c)
Step-by-step explanation:
In step 1, he should have added .75x to both sides.
What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?
-4x/5+8.8. I think that's it, and if it isn't, i don't know.
Find the equation of the line in slope-intercept form with slope of 3/5 and (0,-2)
slope-intercept form: y = mx + b where m = slope and b = y intercept
Given: slope m = 3/5 and y intercept b = -2
So equation
y = 3/5 x - 2
btw i dont think your allowed to leak that according to RSM's policy fyi
WHAT IS THE SUM OF 5(17)² / 10³ =
289/200
OR
1.445
OR
1 89/200
Radical expression for the exponential expression above
The answer is
[tex]\sqrt{x}[/tex]
because,
[tex]a^{x/n} = \sqrt[n]{x}[/tex]
A particle moving along the x axis so that it’s position at t is greater than or equal to 0 is given by s(t)=(t)ln(3t). Find the acceleration of the particle when the velocity is first zero.
We are given
equation of position
[tex]s(t)=(t)ln(3t)[/tex]
Calculation of velocity:
we can find derivative
[tex]s'(t)=1*ln(3t)+t*\frac{3}{3t}[/tex]
[tex]s'(t)=ln(3t)+1[/tex]
so, velocity is
[tex]v(t)=ln(3t)+1[/tex]
now, we can set it to 0
and then we can solve for t
[tex]v(t)=ln(3t)+1=0[/tex]
[tex]t=\frac{1}{3e}[/tex]
Calculation of acceleration:
we can find derivative again
[tex]v'(t)=\frac{3}{3t} +0[/tex]
[tex]v'(t)=\frac{1}{t} [/tex]
so, acceleration is
[tex]a(t)=\frac{1}{t} [/tex]
now, we can plug value of t
[tex]a(\frac{1}{3e})=\frac{1}{\frac{1}{3e}} [/tex]
[tex]a(\frac{1}{3e})=3e [/tex]..................Answer
which line is parallel to the line whose equation is 4x+3y=7 and also passes through the point (-5,2)?
Final answer:
The line that is parallel to 4x+3y=7 and passes through (-5,2) has the equation y=(-4/3)x-14/3.
Explanation:
The line that is parallel to the line with the equation 4x+3y=7 and passes through the point (-5,2) will have the same slope as the given line. To find the slope, we need to rearrange the equation into slope-intercept form (y=mx+b), where m is the slope. In this case, we get 3y=-4x+7, which can be simplified to y=-(4/3)x+7/3. So the slope is -4/3.
Now that we know the slope, we can use the point-slope formula y-y1=m(x-x1) to find the equation of the line that passes through (-5,2).
Using y-2=(-4/3)(x-(-5)), we can simplify to y-2=(-4/3)(x+5). Expanding and rearranging, we get y=(-4/3)x-14/3.
The equation of the parallel line is: [tex]\[\boxed{4x + 3y = -14}\][/tex]
To find the equation of a line parallel to the given line 4x + 3y = 7 and passing through the point (-5, 2), follow these steps:
1. Determine the slope of the given line:
The given line's equation is in standard form: Ax + By = C. To find its slope, we can rewrite it in slope-intercept form y = mx + b, where m is the slope.
Starting with the given equation:
4x + 3y = 7
Solve for y:
[tex]\[3y = -4x + 7\]\[y = -\frac{4}{3}x + \frac{7}{3}\][/tex]
The slope m of the given line is [tex]\(-\frac{4}{3}\).[/tex]
2. Use the slope of the parallel line:
Since parallel lines have the same slope, the line we are looking for also has a slope of [tex]\(-\frac{4}{3}\).[/tex]
3. Use the point-slope form to find the equation of the new line:
The point-slope form of a line's equation is given by:
[tex]\[y - y_1 = m(x - x_1)\][/tex]
where [tex]\((x_1, y_1)\)[/tex] is a point on the line, and m is the slope.
Here, the point (-5, 2) and slope [tex]\(m = -\frac{4}{3}\):[/tex]
[tex]\(-\frac{4}{3}\).[/tex]
[tex]\[y - 2 = -\frac{4}{3}(x + 5)\][/tex]
Simplify the equation:
[tex]\[y - 2 = -\frac{4}{3}x - \frac{4}{3} \cdot 5\]\[y - 2 = -\frac{4}{3}x - \frac{20}{3}\][/tex]
Add 2 (or [tex]\(\frac{6}{3}\))[/tex] to both sides:
[tex]\[y = -\frac{4}{3}x - \frac{20}{3} + \frac{6}{3}\]\[y = -\frac{4}{3}x - \frac{14}{3}\][/tex]
The equation of the line parallel to 4x + 3y = 7 and passing through (-5, 2) is:
[tex]\[y = -\frac{4}{3}x - \frac{14}{3}\][/tex]
Converting back to standard form for consistency:
[tex]\[3y = -4x - 14\]\[4x + 3y = -14\][/tex]
Therefore, the equation of the parallel line is:
[tex]\[\boxed{4x + 3y = -14}\][/tex]
#34. Find the value of x for the rectangle.
(How did u do it/what did u do)
Hey, CadenClough! For this, it's best to use algebra. We know that rectangles have two of each measure: two lengths and two widths. This means the formula to find the complete perimeter of the rectangle is 2l + 2w = p.
Now let's look at the problem. For length, we have x + 3 and for width we have 2x - 6. First off, fill in the values for length and width in the perimeter equation like this:
[tex]2(x + 3) + 2(2x - 6) = 26[/tex]
Now distribute the 2:
[tex]--> 2x + 6 + 4x - 12 = 26[/tex]
Combine like terms:
[tex]2x + 4x + 6 - 12 = 26[/tex]
Simplify:
[tex]6x - 6 = 26[/tex]
Isolate x:
[tex]6x = 26 + 6[/tex]
--> [tex]x = \frac{32}{6}[/tex]
Now plug in the value of x:
[tex]2(\frac{32}{6} + 3) + 2(2 * \frac{32}{6} - 6)[/tex]
= 64/3 - 12 + 32/3 + 6
= 26
So x = [tex]\frac{32}{6}[/tex] or 16/3.
d+(−5.004)=2.826
I am so confused. What do I do?
Okayyy, so the answer is 7.830. Adding a negative number is the same as subtracting a positive number so you can rewrite it as d-5.004=2.826, then you will add 5.004 to 2.826 and for your answer you will get 7.830.
Answer:
d=7.83
Step-by-step explanation:
Do the following
d +(-5.004)=2.826
1) To eliminate the Parenthesis we're going to operate the plus times -5.004:
What gives us:
d - 5.004 = 2.826
2) Let's add 5.004 to both sides to leave d alone, on ther first member:
d-5.004 +5.004= 2.826+5.004
d+0=7.830
d=7.83
NEED HELP!!!!!!!!
George is building a fence around a rectangular dog run. He is using his house as one side of the run. The area of the dog run will be 240 square feet. The length of the run is 30 feet, and the width is (30-x) feet. The diagram below shows his plan.
Recall the formulas for area and perimeter: A = lw and P = 2l + 2w.
How many feet of fencing will George need for the dog run?
22 feet
68 feet
76 feet
82 feet
Answer:
68 feet
Step-by-step explanation:
30 x (30-x) = 240
30-x = 8
-x = -22
x = 22
Therefore width is 30-22 = 8 feet
8+8+30+30 = 76 total for all 4 sides.
George would need 76 feet of fencing for the dog run IF he was not using his house as one side of the run. Therefore, taking the 76 total feet that would be required to go around all 4 sides and subtracting the feet of one width (8 feet), gives a total of 68 feet.
Answer:
b
Step-by-step explanation:
68
Evaluate. 2⋅(5^8/5^5)
350
250
225
125
Hello there!
The answer should be the second option B. 250
[tex]2*(5^8/5^5)[/tex]
Explanation:
↓↓↓↓↓↓↓↓↓↓↓↓
[tex]2*(5^8/5^5)[/tex]
First you had to remove parenthesis.
[tex]2*\frac{5^8}{5^5}[/tex]
[tex]\frac{5^8}{5^5}=5^3[/tex]
[tex]5^3*2[/tex]
[tex]5^3=125[/tex]
[tex]2*125[/tex]
Then multiply by the numbers and it should be the correct answer.
[tex]2*125=250[/tex]
[tex]=250[/tex]
Answer⇒⇒⇒⇒⇒=250
Hope this helps!
Thank you for posting your question at here on Brainly.
Have a great day!
-Charlie
The correct answer is b) 250.
Evaluate the exponent in the denominator:
[tex]\frac{5^8}{5^5}=5^{8-5}=5^3[/tex]
The subtraction of exponents arises from the rule that when you divide two terms with the same base, you subtract the exponents.
Substitute the result back into the original expression:
[tex]2 \cdot 5^3[/tex]
Calculate the final result:
[tex]2 \cdot 5^3=2 \cdot(5 \cdot 5 \cdot 5)=2 \cdot 125=250[/tex]
So, [tex]2 \cdot \frac{5^8}{5^5}[/tex] simplifies to 250. The key step is understanding how to handle the exponents when you divide terms with the same base. In this case, it simplifies to [tex]5^{3}[/tex] , and then you can evaluate the expression further to get the final result of 250.
Question:
Evaluate: [tex]2 \cdot \frac{5^8}{5^5}[/tex]
a) 350
b) 250
c) 225
d) 125
convert the following improper fraction to a whole or mixed number 112/7
16 should be your answer, because 112 divided by 7 equals 16!
When you convert this improper fraction 112/7 to a whole number is just 16.
How many lines of symmetry does the shape below appear to have?
Answer:
There is no shape
Step-by-step explanation:
There is no shape below.
the sum of 3 numbers is 13. the second number is 3 subtracted from 3 times the first. the third number is 4 times the first. what is the number
x + y + z = 13
y = 3x - 3
z = 4x
Because we have values for y and z, we can plug them into the original equation to find the value of x.
x + 3x - 3 + 4x = 13
Combine like terms.
8x - 3 = 13
Add 3 to both sides.
8x = 16
Divide both sides by 8.
x = 2
The value of x is 2.
Because we have the exact value of x, we can insert this into each x value to find the values of y and z.
y = 3(2) - 3
y = 3
z = 4(2)
z = 8
2 + 3 + 8 = 13
ken grew 4/5 of an inch last year.sang grew 3/8of an inch.who grew more and by how much
4/5 = .8 inches
3/8 = .375 inches
So subtract .8-.375 = .425
Ken grew more by .425 inch or 17/40
Darryl has $7 left in his pocket. He spent $9 on a book, $12 on a compact disc, and $4 on a magazine. How much money did he have at the beginning of the day?
He has 7 dollars left so...
We can add 7+9+12+4 to get the amount in the beginning
32$ to start with
Final answer:
To determine how much money Darryl had at the beginning of the day, we add the amounts he spent on a book, compact disc, and magazine to the money he has left, which totals $32.
Explanation:
The question involves solving a simple arithmetic problem regarding the total amount of money Darryl had at the beginning of the day, based on his expenditures throughout the day. To find out how much money Darryl had initially, we need to add up the amounts he spent on various items and then add the money he has left.
Darryl spent:
$9 on a book$12 on a compact disc$4 on a magazineand he has $7 left.
To find the total amount Darryl had at the beginning of the day, we add up all the expenditures and the remaining amount:
$9 (book) + $12 (compact disc) + $4 (magazine) + $7 (remaining) = $32
So, Darryl had $32 at the beginning of the day.
Which expression represents "five less than three times x"?
A: 3x-5
B: 3-5x
C: 5x-3
D: 5-3x
A
three times x = 3 × x = 3x
less 5 means subtract 5 from 3x, hence
3x - 5 → A
Answer:
[tex]3x-5[/tex]
Step-by-step explanation:
"five less than three times x"
The unknown number is x
Three times x means we multiply 3 with x
So the expression becomes 3x
5 less than 3x means we subtract 5 from 3x
To get the expression we use variables and operators like +,- . x or divide
So the final expression becomes
[tex]3x-5[/tex]
(6.4+0.92 , 15.74 -2.64)
Alright, let's break this down:
1. First, we will solve the addition problem on the left, which is 6.4 plus 0.92. When you add these two numbers together, you will get 7.32.
2. Secondly, we will solve the subtraction problem on the right, which is 15.74 minus 2.64. When you subtract these two numbers, you will find that the result is 13.1.
So the answer to our problem is (7.32, 13.1).
Solve the following inequality. |3n-2|-2<1
Answer: [tex]\frac{-1}{3}[/tex] < n < [tex]\frac{5}{3}[/tex]
Step-by-step explanation:
| 3n - 2 | - 2 < 1
+2 +2
| 3n - 2 | < 3
3n - 2 < 3 and 3n - 2 > -3
+2 +2 +2 +2
3n < 5 and 3n > -1
n < [tex]\frac{5}{3}[/tex] and n > [tex]\frac{-1}{3}[/tex]
[tex]\frac{-1}{3}[/tex] < n < [tex]\frac{5}{3}[/tex]
Interval Notation: [tex](\frac{-1}{3},[/tex][tex]\frac{5}{3})[/tex]
Graph: [tex]\frac{-1}{3}[/tex] o--------------------o [tex]\frac{5}{3}[/tex]
[tex]|3n-2|-2<1\\\\|3n-2|<3\\\\3n-2<3 \wedge 3n-2>-3\\\\3n<5 \wedge 3n>-1\\\\n<\dfrac{5}{3} \wedge n>-\dfrac{1}{3}\\\\n\in \left(-\dfrac{1}{3},\dfrac{5}{3}\right)[/tex]
Expressed as a product of its prime factors in index form, a number N is
N=3 X 5^2 X x^3
Express 5N^2 as a product of prime factors in index form.
Give your answer in terms of x.
ANSWER
[tex]5N^2=3^{2} \times 5^{5} \times x^{6}[/tex]
EXPLANATION
[tex]N=3\times5^2 \times x^3[/tex].
[tex]5N^2=5(3\times5^2 \times x^3)^2[/tex]
Recall this property of exponents;
[tex](a^m)^2=a^{m} \times a^m[/tex]
So our product becomes;
[tex]5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)[/tex]
[tex]5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3[/tex]
[tex]5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3[/tex]
Recall this law of exponents:
[tex]a^m \times a^n =a ^{m+n}[/tex]
[tex]5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}[/tex]
[tex]5N^2=3^{2} \times 5^{5} \times x^{6}[/tex]