Early on in the story the narrator mentions the sound of wind through the wires strung overhead: "The wind in the wires took up the story . . ."Taking the plot's rising action at this point into account, which of the following literary devices is the author most likely using?
A.creative license
B.irony
C.extended metaphor
D.personification

Answer:

v = 2.29 m/s

Explanation:

As we know that the external force on the system of mass of boy + board is ZERO

So here we can use momentum conservation

now we have

[tex]m_1v_1 + m_2v_2 = (m_1 + m_2) v[/tex]

now we have

[tex]45 (2.5) + 4(0) = (45 + 4) v[/tex]

now we have

[tex]v = \frac{45}{49} (2.5)[/tex]

[tex]v = 2.29 m/s[/tex]

Answer:

V = 2.29 m/s

Explanation:

Given that,

Mass of the boy, [tex]m_1=45\ kg[/tex]

Mass of the skateboard, [tex]m_2=4\ kg[/tex]                            

Initial speed of the boy, v = 2.5 m/s

Let V is the final velocity of the boy and the board. The net momentum of the system remains constant. Using the conservation of linear momentum to find it as :

[tex]45\times 2.5=(45+4)V[/tex]

[tex]V=\dfrac{45\times 2.5}{(45+4)}[/tex]

V = 2.29 m/s

So, the velocity of the boat after Batman lands in it 2.29 m/s. Hence, this is the required solution.                                                                

The subsequent velocities of the satellite and the remains of the launcher can be calculated using the principle of conservation of momentum. The resultant velocities are approximately 8.70×10−² m/s and 81.5 m/s.

The subsequent velocities of the satellite and the remains of the launcher can be calculated using the principle of conservation of momentum. Since there are no external forces acting on the system, the initial momentum of the system is equal to the final momentum. Therefore, the final velocities of the satellite and the launcher can be calculated based on their masses and the kinetic energy supplied to them.

The mass of the satellite, m1 = 4800 kg, and the mass of the launcher, m2 = 1500 kg. The total initial kinetic energy supplied to the system is given as 5000 J. To calculate the velocities, we need to find the ratio of the kinetic energies of the satellite and the launcher.

Let v1 be the velocity of the satellite and v2 be the velocity of the launcher. According to the conservation of momentum, m1 * v1 + m2 * v2 = 0. Also, the total initial kinetic energy supplied to the system is given as 5000 J, where the kinetic energy of the satellite is (1/2) * m1 * v1^2 and the kinetic energy of the launcher is (1/2) * m2 * v2^2.

Using these equations, we can solve for v1 and v2. The subsequent velocities are approximately 8.70×10−² m/s in the direction of motion of the less massive satellite and 81.5 m/s, respectively.

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The satellite moves at approximately 0.704 m/s and the remains of the launcher move at approximately -2.253 m/s in the opposite direction.

To solve for the velocities of the satellite and the launcher remains after separation, we will use the principles of conservation of momentum and the given kinetic energy.

1. Conservation of Momentum

[tex]\[m_s v_s + m_l v_l = 0\][/tex]

Since the total momentum is zero:

[tex]\[4800 \, v_s + 1500 \, v_l = 0\][/tex]

Solving for one velocity in terms of the other:

[tex]\[v_l = - \frac{4800}{1500} v_s = -3.2 v_s\][/tex]

2. Conservation of Energy

The total kinetic energy provided to the system is 5000 J. The kinetic energy of the system is the sum of the kinetic energies of both parts:

[tex]\[\frac{1}{2} m_s v_s^2 + \frac{1}{2} m_l v_l^2 = 5000\][/tex]

Substituting [tex]\( v_l = -3.2 v_s \)[/tex]:

[tex]\[\frac{1}{2} (4800) v_s^2 + \frac{1}{2} (1500) (-3.2 v_s)^2 = 5000\][/tex]

[tex]\[2400 v_s^2 + 750 (10.24) v_s^2 = 5000\][/tex]

[tex]\[2400 v_s^2 + 7680 v_s^2 = 5000\][/tex]

[tex]\[10080 v_s^2 = 5000\][/tex]

Solving for [tex]\( v_s^2 \)[/tex]:

[tex]\[v_s^2 = \frac{5000}{10080} = 0.496 \, \text{m}^2/\text{s}^2\][/tex]

[tex]\[v_s = \sqrt{0.496} \approx 0.704 \, \text{m/s}\][/tex]

3. Determine [tex]\( v_l \)[/tex]

Using [tex]\( v_l = -3.2 v_s \)[/tex]:

[tex]\[v_l = -3.2 \times 0.704 \approx -2.253 \, \text{m/s}\][/tex]

The subsequent velocities of the satellite and the launcher remains after separation are:

- Velocity of the satellite: [tex]\( v_s \approx 0.704 \, \text{m/s} \)[/tex]

- Velocity of the launcher remains: [tex]\( v_l \approx -2.253 \, \text{m/s} \)[/tex]

Explanation:

From the first law of thermodynamics,

Δ[tex]Q[/tex]=Δ[tex]U[/tex]+[tex]W[/tex]

Where [tex]Q[/tex] is the heat given to the gas,

[tex]U[/tex] is the internal energy of the gas,

[tex]W[/tex] is the workdone by the gas.

When pressure is constant,

[tex]\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}[/tex]

[tex]V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}[/tex]

When pressure is constant,[tex]W=P[/tex]Δ[tex]V[/tex]

Where [tex]P[/tex] is pressure and [tex]V[/tex] is the volume of the gas.

Given [tex]P=1.5\times 10^{5}Pa[/tex]

Δ[tex]V=[/tex][tex]7.8-2.6=5.2m^{3}[/tex]

So,[tex]W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J[/tex]

Given that Δ[tex]U=6\times 10^{5}[/tex]

So,Δ[tex]Q=[/tex][tex]6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J[/tex]

By using the first law of thermodynamics, the ideal gas law, the given parameters and an additional calculation for the work done by the gas, we can calculate the total heat absorbed by the gas.

To calculate the heat absorbed by the gas, we use the first law of thermodynamics which states that the heat absorbed by a system is equal to the change in its internal energy plus the work done by the system on its surroundings, expressed as Q = ΔEint + W. The change in internal energy, ΔEint, is given as +6.0 × 10^5 J.

Since the pressure is constant, the work done by the gas, W, can be calculated using W = PΔV, where P is the pressure and ΔV is the change in volume. The change in volume can be determined using the ideal gas law before and after the change, PV = nRT, thus, ΔV = nR(ΔT)/P. Substituting the given pressure, temperature change from 300 K to 900 K, and ideal gas constant, we can find ΔV.

After plugging ΔV into the equation for work done, we then add this to the change in internal energy to find the heat absorbed.

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Answer:

The height of the bag will be 0.133 m

Explanation:

We have given gauge pressure [tex]P=1.33\times 10^3Pa=1330Pa[/tex]

Density of solution [tex]\rho =1.02\times 10^3=1020kg/m^3[/tex]

We have to find the height of the bag

We know that gauge pressure is given by P=\rho gh

[tex]1330=1020\times 9.8\times h[/tex]

h=0.133m

So the height of the bag will be 0.133 m

Final answer:

The minimum height of the bag should be 0.245 meters to infuse glucose into the vein.

Explanation:

In order for the fluid to enter the vein, its pressure at entry must exceed the blood pressure in the vein. To find the height of the fluid, we need to convert the blood pressure in mm Hg to SI units. Since 1.0 mm Hg = 133 Pa, the blood pressure in the vein is 18 mm Hg above atmospheric pressure, which is equivalent to (18 mm Hg)(133 Pa/mm Hg) = 2386 Pa.

Now we can calculate the height of the fluid using the formula:

h = P/(ρg)

Where:

Substituting the given values into the formula, we find:

h = (2386 Pa)/((1.02 x 10^3 kg/m^3)(9.8 m/s^2)) = 0.245 m

The minimum height of the bag should be 0.245 meters in order to infuse glucose into the vein.

The geologists use echo sounding for oil exploration, where they analyze the time taken by sound waves (created by explosives) to travel from the surface, reflect off oil deposits, and return. Given the speed of sound in granite (5000 m/s) and considering the travel time of the sound wave is two-way, we find the oil deposits to be approximately 2300m under the surface of the Lake Physics.

The question revolves around the concept of echo sounding used for oil exploration. Exploders use explosives to create sounds waves that travel down into the earth and reflect back when they hit a boundary between different materials like rock or oil. In this case, the echo was detected 0.920 seconds after the explosion.

To find out the depth of the oil deposit, we need to know the speed of sound in the medium. Sound travels at different speeds in different materials, and in granite, it's typically about 5000 m/s.

We can use the formula for distance in relation to speed and time: d = vt. The time we use in this equation should be the time for the sound to travel to the deposits and back, so we halve the given time to 0.460 s. Substituting the values into the equation, we get: d = 5000 m/s * 0.460 s = 2300 m.

This means that the oil deposits are approximately 2300 m below the surface of the lake.

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Answer:

Density of jacket will be [tex]680.4733kg/m^3[/tex]

Explanation:

We know that weight of water displaced= buoyant force=weight of man

Now volume of water displaced [tex]v=3.38\times 10^{-2}+6.42\times 10^{-2}=9.8\times 10^{-2}m^3[/tex]

Density of water [tex]d=100kg/m^3[/tex]

So weight of water displaced [tex]=9.8\times 10^{-2}\times 1000=98kg[/tex]

So weight of jacket = 98-75 = 23 kg

We have given volume of the jacket = [tex]3.38\times 10^{-2}m^3[/tex]

So density of jacket [tex]=\frac{mass}{volume}=\frac{23}{3.38\times 10^{-2}}=680.4733kg/m^3[/tex]

Answer:

High pressure inside the giant planet

Explanation:

As we move in the interior of the giant planet, the pressure and temperature in the interior of the planet increases. Since, the giant planets have hardly any solid surface and thus they are mostly constituted of atmosphere.

Also, the gravitational forces keep even the lightest of the matter bound in it contributing to the large mass of the planet.

If we look at the order of the magnitude of the temperature of these giant planets than nothing should be able to stay in liquid form but as the depth of the planet increases with the increase in temperature, pressure also increases which keeps the particle of the matter in compressed form.

Thus even at such high order of magnitude water is still found in liquid state in the interior of the planet.

Answer:

Strike-slip fault

Explanation:

Transform boundaries play the role of connecting the other plate boundary segments.

When the plates are rubbed against each other, they result in enormous amount of stresses which leads to the breaking of the part of a rock causing earthquakes. Places of occurrence of these breaks are termed as faults.

Strike slip faults results from compression which takes place horizontally, but but in this the rock displacement  releases energy and takes place in a horizontal direction which is parallel to the force of compression.

Transform boundaries are classified under Transform Faults, where plates slide past each other causing stress and earthquakes, such as at the San Andreas Fault.

Transform boundaries are classified under the type of fault known as Transform Faults. These happen at plate boundaries where the plates are not moving away or toward each other, but instead sliding past one another. This movement causes a huge amount of stress, leading to earthquakes. The most recognized transform fault is the San Andreas Fault in California, where the Pacific Plate and the North American Plate are sliding past each other.

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Answer:

V = 3.6385 m/s

θ = 47.46 degrees

Explanation:

the important data in the question is:

Skater 1:

[tex]M_1[/tex]= 39.6 kg

direction: south (axis y)

[tex]V_{1iy}[/tex] = 6.21 m/s

Skater 2:

[tex]M_2[/tex] = 52.1 kg

direction: east (axis x)

[tex]V_{2ix}[/tex] = 4.33 m/s

Now using the law of the conservation of linear momentum ( [tex]P_i = P_f[/tex] and knowing that the collision is inelastic we can do the next equations:

[tex]M_{1}V_{1ix}+M_2V_{2ix} = V_{sx}(M_1+M_2)[/tex]  (eq. 1)

[tex]M_{1}V_{1iy}+M_2V_{2iy} = V_{sy}(M_1+M_2)[/tex]  (eq. 2)

Where [tex]V_{sx}[/tex] and [tex]V_{sy}[/tex] is the velocity of the sistem in x and y after the collision.

Note: the conservation of the linear momentum have to be make once by each axis.

Now, in the (eq. 1) the skater 1 don't have velocity in the axis x, so we can replace [tex]V_{1ix}[/tex] by 0 in the equation and get:

[tex]M_2V_{2ix} = V_{sx}(M_1+M_2)[/tex]  (eq. 1)

also, in the (eq. 2) the skater 2 don't have velocity in the axis y, so we can replace [tex]V_{2iy}[/tex] by 0 in the equation and get:

[tex]M_{1}V_{1iy} = V_{sy}(M_1+M_2)[/tex]  (eq. 2)

Now, we just replace the data in both equations:

[tex](52.1)(4.33) = V_{sx}(39.6+52.1)[/tex]  (eq. 1)

[tex](39.6)(6.21) = V_{sy}(39.6+52.1)[/tex]  (eq. 2)

solving for [tex]V_{sx][/tex] and [tex]V_{sy}[/tex] we have:

[tex]V_{sx][/tex] = 2.46 m/s

[tex]V_{sy][/tex] = 2.681 m/s

using the pythagoras theorem we can find the magnitude of the velocity as:

V = [tex]\sqrt{2.46^2+2.681^2}[/tex]

V = 3.6385 m/s

For find the direction we just need to do this;

θ = [tex]tan^{-1}(\frac{2.681}{1.46})[/tex]

θ = 47.46 degrees

Answer:

15.825 m

Explanation:

t = Time taken = 2.5 s

u = Initial velocity = 6.75 m/s

v = Final velocity = 5.91 m/s

s = Displacement

a = Acceleration

Equation of motion

[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{5.91-6.75}{2.5}\\\Rightarrow a=-0.336\ m/s^2[/tex]

[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{5.91^2-6.75^2}{2\times -0.336}\\\Rightarrow s=15.825\ m[/tex]

The distance Rickey slides across the ground before touching the base is 15.825 m

Answer:

θ₀ = 67.79°

Explanation:

Given info

we know that

Ymax = v₀y² / (2g)

v = v₀x  (when Y = Ymax)

when the projectile was at half its maximum height (Y')

v' = 2v = 2*v₀x

we can use the equations

(v')²= v'x² + v'y²   ⇒  (2*v₀x)² = (v₀x)² + v'y²   ⇒   v'y² = 3*(v₀x)²   (I)

if we know that

v'y² = v₀y² - 2*g*(y')  

y' = Ymax /2 = (v₀y² / (2g)) / 2 = v₀y² / (4g)

then

v'y² = v₀y² - 2*g*(v₀y² / (4g)) = v₀y² - (v₀y² / 2) = v₀y² / 2

⇒ v'y² = v₀y² / 2       (II)

we can say that (I) = (II)

3*(v₀x)² = v₀y² / 2   ⇒   v₀y = √6*v₀x

Finally we apply

tan θ₀ = v₀y / v₀x

⇒  tan θ₀ = √6*v₀x / v₀x = √6

⇒  θ₀ = tan⁻¹ (√6) = 67.79°

Answer:

option (c)

Explanation:

In the game of tug of war, the Newton's third law is obeyed.

One team pulls the rope in one direction and the other team pulls the rope in another direction.

As the mass of one team is more, so it is harder to pull the rope by the another team.

So, it depends on the total mass of the team.

Option (c) is correct.

Answer:

The best answer would be C. Total mass of the team.

Explanation:

C would be the best answer because when looking in the formula of force then the 2 factors that are inputted are mass and acceleration but in this case acceleration would most likely not have much have an effect so that leaves the factor of mass.

Hope this helped!

Answer:

m1/m2 = 0.51

Explanation:

First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:

V = √F/u

This is the equation that describes the relation between speed of a pulse and a force exerted on it.

the value of "u" is:

u = m/L

Where m is the mass of the rod, and L the length.

Now, for the rod 1:

V1 = √F/u1 (1)

rod 2:

V2 = √F/u2 (2)

Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:

1.4V2 = √F/u1 (3)

Replacing (2) in (3):

1.4(√F/u2) = √F/u1 (4)

Now, let's solve the equation 4:

[1.4(√F/u2)]² = F/u1

1.96(F/u2) =F/u1

1.96F = F*u2/u1

1.96 = u2/u1 (5)

Now, replacing the expression of u into (5) we have the following:

1.96 = m2/L / m1/L

1.96 = m2/m1 (6)

But we need m1/m2 so:

1.96m1 = m2

m1/m2 = 1/1.96

m1/m2 = 0.51

The ratio of the masses of the two ropes, given that the speed of a pulse on rope 1 is 1.4 times the speed on rope 2, is approximately 1:2. This conclusion is attained by applying the concept of pulse velocity in a string or rope, which is governed by the tension and the linear mass density of the material.

The principle guiding the speed of a pulse on a rope or string is tied to the tension and linear density of the rope. The velocity of a pulse in a string or rope is given as v = √(T/μ), where T represents tension, and μ represents linear mass density (mass/length).

In the context of this question, if the speeds of pulses on two ropes are different but the tensions are the same (since the ropes are stretched the same way), the difference in speed must be due to a difference in linear mass density. Specifically, the speed of a pulse is inversely proportional to the square root of the rope's mass per unit length.

Given that the speed of the pulse on rope 1 is 1.4 times the speed on rope 2, the ratio of the masses of the two ropes (m1/m2) will be the square of the inverse ratio of the speeds. Hence, m1/m2 = (1/1.4)² = 0.51 or approximately 1:2.

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Answer:

ground state

Explanation:

  Lets take  

n=3 ,n=2 ,n=1 are the energy level.

Energy level n=1 is the ground energy level.

The energy from 3 to 1 = hν

The energy from 3 to 2 = hν₁

The energy from 2 to 1 = hν₂

We can say that

hν = hν₁ +  hν₂

If the electron were de-excitation from the third level to ground level then the sum of emitted frequency will be equal to the frequency of a single electron.

Therefore the answer is ground state.

Answer:

E. The wheel with spokes has about twice the KE.

See explanation in: https://quizlet.com/100717504/physics-8-mc-flash-cards/

Answer:

Explanation:

We have to consider how the location of the mass affects the moment of inertia.

For a solid cylinder, I = mR²

For a hollow cylinder, I = 1/2mR²

Where

I ist the moment of inertia,

m is their masses,

R is the radius of rotation.

Since they have the same mass and radius, it can be seen that a hollow cylinder has twice the moment of inertia as a solid cylinder of the same mass and radius.

We know that the rotational kinetic energy is proportional to the moment of inertia. From;

Rotational KE = 1/2IW²

Where W is the angular speed.

so that at the same angular speed, the wheel with the spokes will have about double the kinetic energy as the solid cylinder. Take note that some of the mass is in the spokes so the moment of inertia is not exactly double.

Answer:

0.2s

Explanation:

SO for the dolphin to hear its echo, the sound wave must travel a distance twice as much as the displacement between the dolphin and the ocean floor. So d = 154 * 2 = 308 m

Since the speed of sound in ocean floor is v = 1533m/s we can find out the time by dividing the distance d by the speed of sound

t = d / v = 308 / 1533 = 0.2s

[tex](t = d / v )[/tex]The time passes before it hears an echo is 0.3secs

A sound wave  servers patterns of disturbance caused by the movement of energy traveling through a medium.

The speed of sound in ocean floor was given as [tex]( v = 1533m/s)[/tex]

To find the time, we can make use if the formula

[tex](t = d / v )[/tex]

Where t= time

v= velocity

d= distance

Then substitute ,we have

[tex]= 308 / 1533 = 0.2s[/tex]

Learn more about sound wave at;

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Answer: Newton's law of gravity theory disagrees with Einstein's theory. The last one were named Theory of General Relativity and was discovered and proposed by the physicist Einstein in the year of 1915.

Explanation: Until the beginning of 20 century, the physics were ruled by Isaac Newton's ideas. He believed that the gravity was a force caused by the objects mass on the space, made them to be draw towards each other. Newton thought that the greater the mass of the object, the more intense was its attraction, which would justify the planet's moovements around the sun and how the gravity between them maintain the planets on solar orbit. Concluding, he believed gravity was a immediate force of action, regardless of the distance of the bodies.

Contrary to Newton's law of gravity, in 1915, the physicist Einstein created the Theory of General Relativity, wich discovered that gravity was, in fact, the deformation caused by the attraction of massive celestial bodies. This deformation, related to the Sun, for example, creates a curvature on the space-time and this curvature are followed by the other planets.

So, we can conclude that Newton's law of gravity disagree's with the Theory of General Relativity, once the first believes that light force of attraction are transmitted instantly and, as Einstein already prooved, the gravity influency propagates in the speed of light.

Answer:

V = -0.8 m/s

Explanation:

given,

mass of the child (m)= 25 Kg

mass of the boat(M) = 30 Kg

velocity of boat = ?

Assuming Boys throws package of mass(m₁) 6 Kg at the horizontal speed of       10 m/s

using conservation of momentum

(M + m + m₁) V = (M+ m)V + m₁ v

initial velocity V = 0 m/s

(M + m + m₁) x 0 = (M+ m)V + m₁ v

0 = (25+50)V + 6  x 1 0

75 V = -60

V = -0.8 m/s

negative direction shows that velocity in the direction opposite to the motion of package.

Final answer:

The velocity of the boat immediately after, assuming it was initially at rest, is 15.8 m/s.

Explanation:

To calculate the velocity of the boat, we can use vector addition. The boat's velocity relative to the water is perpendicular to the river's velocity. We can use the Pythagorean theorem to find the magnitude of the boat's velocity:

Vboat = sqrt((Vriver)2 + (Vboat)2)

Substituting the given values, we get:

Vboat = sqrt((5.0 m/s)2 + (15.0 m/s)2) = 15.8 m/s

Therefore, the velocity of the boat immediately after is 15.8 m/s.

Answer:

Energy, E = 178.36 J

Explanation:

It is given that,

Mass 1, [tex]m_1=4\ kg[/tex]

Mass 2, [tex]m_2=4\ kg[/tex]

Mass 3, [tex]m_3=6\ kg[/tex]

Height from which they are dropped, h = 1.3 m

Let m is the energy used by the clock in a week. The energy is equal to the gravitational potential energy. It is given by :

[tex]E=(m_1+m_2+m_3)gh[/tex]

[tex]E=(4+4+6)\times 9.8\times 1.3[/tex]

E = 178.36 J

So, the energy used by the clock in a week is 178.36 Joules. Hence, this is the required solution.

Radiation refers to the transfer of energy by electromagnetic waves, a process that can take place with no medium, such as the heat from the sun reaching Earth.

The transfer of energy by electromagnetic waves is known as radiation. This process does not require a medium; the energy is carried by photons in the electromagnetic waves. Examples of this process include the heat produced by the sun, which reaches the Earth via the transfer of radiant energy, and microwaves heating food through radiation.

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Answer:

a) h=10.701m

b) No. On this case a liquid like wine is not good as the mercury, because the wine is composed of water, alcohol and other elements, but specially the alcohol evaporates much easier than the mercury, and that will cause malfunction in the vacuum of the baroemter used for the experiment.

Explanation:

The Torricelli's experiment "was invented by the Italian scientist Evangelista Torricelli and the most important purpose of this experiment was to prove that the source of vacuum comes from atmospheric pressure"

Pressure is defined as "the force that is applied on any object in the direction perpendicular to the surface of the object in the unit area is known as the pressure. There are various types of pressure".

Part a

We have the density for the red Bordeaux wine given [tex]\rho=965\frac{kg}{m^3}[/tex], the atmospheric pressure on the Toriccelli's barometer is given by:

[tex]P_{atm}=\rho g h[/tex]

Solving for the height of wine in the column we have this:

[tex]h=\frac{P_{atm}}{\rho g}[/tex]

And replacing we have:

[tex]h=\frac{101300Pa}{965\frac{kg}{m^3} 9.81\frac{m}{s^2}}=10.701 m[/tex]

So the height of the red Bordeaux wine would be h=10.701m. A very high value on this case if we compare with the usual values for this variable.

Part b

No. On this case a liquid like wine is not good as the mercury, because the wine is composed of water, alcohol and other elements, but specially the alcohol evaporates much easier than the mercury, and that will cause malfunction in the vacuum of the baroemter used for the experiment.

The height of the wine column for normal atmospheric pressure can be calculated using the equation P = ρgh. The vacuum above the column in the wine barometer would not be as good as that for mercury. The correct answer is No (B).

The height h of the wine column for normal atmospheric pressure can be calculated using the equation P = ρgh, where P is the atmospheric pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the column. The atmospheric pressure can be taken as P = 101325 Pa and the acceleration due to gravity is approximately g = 9.8 m/s^2. Plugging in these values and the density of the wine, ρ = 965 kg/m^3, we can solve for h. Hence, h = P / (ρg).

To compare the vacuum above the column in the wine barometer with that of a mercury barometer, it is important to note that the height of the liquid column in a barometer is determined by the atmospheric pressure pushing down on the liquid. Since both the wine and mercury barometers are subjected to the same atmospheric pressure, the height of the columns will be the same if the densities of the liquids are the same. However, since the density of wine is less than that of mercury, the height of the wine column will be greater than that of the mercury column. Therefore, No (B) is the correct answer.

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Answer:

C) the Fahrenheit thermometer is incorrect

Explanation:

Since

1) K = °C + 273

2) °F = 9/5 °C + 32

for 0 °C

1) K = 0°C + 273 = 273 K

2) °F = 9/5 * 0°C + 32 = 32 °F

Thus the Kelvin thermometer measurement coincides with the Celsius measurement but not with the °F . On the other hand, if the Fahrenheit measurement is right, the Celsius thermometer and the Kelvin one should be wrong.

Therefore is more reasonable to assume that one thermometer failed (the one of Fahrenheit and both Kelvin and Celsius are right ) that 2 thermometers ( Celsius and Kelvin thermometers fail and the one of Fahrenheit is right)

For the three thermometers, we see that one thermometer failed and 2 are right,, Hence the Fahrenheit thermometer is incorrect

Option C is correct

What is ?

Generally, the equation for finding Kelvin is mathematically given as

K = °C + 273

Where

°F = 9/5 °C + 32

In conclusion, The Kelvin thermometer measurement relates with Celsius measurement but has no direct link with  Fahrenheit  F,  the Fahrenheit thermometer is incorrect

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Answer:

Time period between the successive beats will be 0.1703 sec

Explanation:

We have given speed of the sound v = 349 m/sec

Wavelength of piano [tex]A\lambda _A=0.766m[/tex]

Wavelength of piano  [tex]B\lambda _B=0.776m[/tex]

So frequency of piano A [tex]f_1=\frac{v}{\lambda _1}=\frac{349}{0.766}=455.61Hz[/tex]

Frequency of piano B [tex]f_2=\frac{v}{\lambda _1}=\frac{349}{0.776}=449.74Hz[/tex]

So beat frequency f = 455.61 - 449.74 = 5.87 Hz

So time period [tex]T=\frac{1}{f}=\frac{1}{5.87}=0.1703sec[/tex]

So time period between the successive beats will be 0.1703 sec

Yes, the voltage across a capacitor in an RLC series circuit with AC can be greater than the source voltage, especially at resonance where the capacitive and inductive reactances cancel each other out and energy oscillates between the capacitor and inductor.

In an RLC series circuit with alternating current (AC), it is indeed possible for the voltage amplitude across the capacitor to be greater than the voltage amplitude across the source. This phenomenon occurs due to resonance in the circuit, where the capacitive and inductive reactances can cancel each other out at a certain frequency, known as the resonant frequency. When the circuit is at resonance, the voltages across the capacitor and inductor can be much greater than the source voltage because of the energy oscillating between the electric field of the capacitor and the magnetic field of the inductor.

According to the equation Vc = Q/C, where Q is the charge and C is the capacitance, we see that the voltage across the capacitor (Vc) is directly proportional to the amount of charge stored and inversely proportional to the capacitance. In an AC RLC circuit at resonance, the charge can oscillate at amplitudes resulting in voltages across the capacitor that exceed the source voltage.

The same can be true for the voltage across the inductor. If the circuit is driven at or near its resonant frequency, the inductive reactance and capacitive reactance can become equal in magnitude but opposite in phase, leading to a situation where the voltage across the inductor also exceeds the source voltage due to the energy stored in its magnetic field.

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The velocity after 3 s is 12 m/s rightward

Explanation:

The motion of the rocket is a motion at constant acceleration, therefore we can apply suvat equations:

[tex]v=u+at[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time interval

For the rocket in this problem:

u = 0 (the rocket starts from rest)

t = 3 s

[tex]a=4 m/s^2[/tex] rightward is the acceleration

Solving for v, we find the final velocity:

[tex]v=0+(4)(3)=12 m/s[/tex] (rightward)

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Answer: C

Explanation:

Production is expected that it will almost double by the end of the year is the answer because production in this context relates to a numerical quantity which is a function of time.

Therefore the probability there is on whether production will almost double to provide enough electricity and not if production will occur.

Windmills account for about 2,500 megawatts of electrical power nationwide, and the production is expected to almost double by the end of the year, providing enough electricity for 1.3 million households.

Windmills account for about 2,500 megawatts of electrical power nationwide, and the production is expected to almost double by the end of the year. This doubling of production would provide enough electricity for 1.3 million households.

The correct answer choice is c. expected that it will almost double by the end of the year to provide because it accurately represents the expectation of the doubling of production and the purpose of providing enough electricity for households.

Answer:

[tex]p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant[/tex]

Explanation:

first write the newtons second law:

F[tex]_{s}[/tex]=δma[tex]_{s}[/tex]

Applying bernoulli,s equation as follows:

∑[tex]δp+\frac{1}{2} ρδV^{2} +δγz=0\\[/tex]

Where, [tex]δp[/tex] is the pressure change across the streamline and [tex]V[/tex] is the fluid particle velocity

substitute [tex]ρg[/tex] for {tex]γ[/tex] and [tex]g_{0}-cz[/tex] for [tex]g[/tex]

[tex]dp+d(\frac{1}{2}V^{2}+ρ(g_{0}-cz)dz=0[/tex]

integrating the above equation using limits 1 and 2.

[tex]\int\limits^2_1  \, dp +\int\limits^2_1 {(\frac{1}{2}ρV^{2} )} \, +ρ \int\limits^2_1 {(g_{0}-cz )} \,dz=0\\p_{1}^{2}+\frac{1}{2}ρ(V^{2})_{1}^{2}+ρg_{0}z_{1}^{2}-ρc(\frac{z^{2}}{2})_{1}^{2}=0\\p_{2}-p_{1}+\frac{1}{2}ρ(V^{2}_{2}-V^{2}_{1})+ρg_{0}(z_{2}-z_{1})-\frac{1}{2}ρc(z^{2}_{2}-z^{2}_{1})=0\\p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant[/tex]

there the bernoulli equation for this flow is [tex]p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant[/tex]

note: [tex]ρ[/tex]=density(ρ) in some parts and change(δ) in other parts of this equation. it just doesn't show up as that in formular

Answer:

Displacement = 0.707A

Explanation:

To solve for the displacement we know that

Potential energy PE = 1/2Total energy (Etotal)

Therefore 1/2kx^2 = 1/2(1/2KA^2)

Solving for x we have

x^2 = √A^2/2

x = A/√2

x= 0.707A

Answer:

Criminal Law

Explanation:

Criminal Law is the body of law that codifies what a state defines as legal and/or illegal as well as the punishments for the violations of the laws. Examples of Criminal laws are murder, assault, theft, or drunken driving. Under criminal comes that procedure of prosecution of individual who  commit crime. It is different from the civil law.

Answer:

Criminal Law is the body of law that codifies what a state defines as legal and/or illegal as well as the punishments for the violations of the laws. Examples of Criminal laws are murder, assault, theft, or drunken driving. Under criminal comes that procedure of prosecution of individual who  commit crime. It is different from the civil law.

Answer:

Gravity

Explanation:

While a star is on the main sequence, its equilibrium is the result of the outward pressure of hot gas and the inward pressure of GRAVITY.

Gravity is a property of mass of objects. Pressure gravity is the resultant force felt by a particular mass object.

As gravity contact the star surface, density gradient is set up.

Pressure of gravity is a gravitational compression which increases the objects density, compresses the mass of objects and reduces the object's size.

A star might leave the sequence if the star run out of fuel for nuclear fusion in its core.