[tex]A_r = 62.9296 \; \text{amu} \times 69.15 \% + 64.9278 \; \text{amu} \times 30.85 \%\\\phantom{A_r} = 63.5460 \; \text{amu}[/tex]
The idea is to sum up the product of atomic mass and abundance for each of the isotope- e.g. 62.9296 and 69.15% for X-63- to find the average of isotope atomic mass weighted regarding their abundance, which is by definition the relative atomic mass of the element.
Answer : The average atomic mass of an element X is, 63.546 amu
Solution : Given,
Mass of isotope X-63 = 62.9296 amu
% abundance of isotope X-63 = 69.15% = 0.6915
Mass of isotope X-64 = 64.9278 amu
% abundance of isotope X-64 = 30.85% = 0.3085
Formula used for average atomic mass of an element X :
[tex]\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})[/tex]
[tex]\text{ Average atomic mass of an element X}=\sum[(62.9296\times0.6915)+(64.9278\times 0.3085)][/tex]
[tex]\text{ Average atomic mass of an element X}=63.546amu[/tex]
Therefore, the average atomic mass of an element X is, 63.546 amu
Water (H2o) is composed of the same elements as hydrogen peroxide (H2o2) why do these substances have different properties
A.) The atoms are arranged differently in each molecule
B.) The molecules are the same
C.) The atoms are the same
D.) Water has more atoms than hydrogen peroxide
Option A is correct;
A.) The atoms are arranged differently in each molecule
Explanation:Water and hydrogen peroxide are made of the same elements: oxygen and hydrogen. However, hydrogen peroxide (H2O2) has 1 more oxygen than water (H2O).
Hydrogen peroxide is very unstable and breaks down readily into water and a single oxygen molecule.
And also the arrangement of atoms is different in each molecule.
Water (H2o) is composed of the same elements as hydrogen peroxide (H2o2) these substances have different properties because:
A.) The atoms are arranged differently in each molecule
The element of water which is made up of two hydrogen 2H and oxygen is of the same element with hydrogen peroxide.
However, we should note that H2O2 (hydrogen peroxide) has more number of oxygen than H2O (water).
As a result of this, even though they have the same element, they are of different particles because their atoms are arranged differently.
Therefore, the correct answer is option A
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Which is the best example of how electromagnetic energy is used in everyday life?
Answer:
The application of X-rays in the hospital.
Explanation:
An X-ray is a painless and brisk method generally used in order to generate inside images of the body. The X-rays are generally carried out in the X-ray departments in the hospital under the guidance of trained specialists known as radiographers, however, it can also be performed by other healthcare professionals.
Assume we have 25 mL of a 2.5 M HCl and a solution of NaOH of unkown concentration. The two react via the following equation.
HCl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l)
Select all that apply:
A. HCl is the titrant.
B. HCl is the analyte
C. NaOH is the titrant
D. NaOH is the analyte
My analysis: I would say that C would be the titrant as it is the unknown and the titrant would be HCl as it is the given? Is that correct?
Answer is A - HCl is the titrant and D-NaOH is the analyte.
In a titration process, the solution of unknown concentration considered is the analyte. During titration, a standard solution(titrant) is added to an analyte until the equivalence point is achieved.
So in this case as the concentration of NaOH is not known,NaOH is the analyte.
Titrant is the solution whose concentration is known to us and is added to an analyte until the equivalence point is reached. In this case since we know the concentration of HCl, HCl is the titrant.
A photon has a frequency of 7.3 × 10–17 Hz. Planck’s constant is 6.63 × 10–34 J•s. The energy of the photon, to the nearest tenths place, is _____ × 10–50 J.
Given:
E = 7.3 × 10–17 Hz
h= 6.63 × 10–34 J•s
Now E = hf
where E is the energy of the photon
h is the Planck's constant
f is the frequency of the photon
Substituting the values in the equation we get
E= 7.3 × 10^-17 × 6.63 × 10^-34
E= 4.8399 × 10^-50 J.
The energy of the photon, to the nearest tenths place, is 4.8399 × 10⁻⁵⁰ J.
How energy of photon is calculated?Energy of the photon can be calculated as :
E = hυ, where
E = energy of the photon = to find?
h = plank's constant = 6.63 × 10⁻³⁴ J•s (given)
and υ = frequency = 7.3 × 10⁻¹⁷ Hz
Now putting all these values in the above equation, we get
E = (6.63 × 10⁻³⁴) × (7.3 × 10⁻¹⁷)
E = 4.8399 × 10⁻⁵⁰ J.
Hence, 4.8399 × 10⁻⁵⁰ J is the energy of the photon.
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why is second ionization energy larger than first ionization energy
Hi!
Why is second ionization energy larger than first ionization energy?
The reason second ionization energy is larger is because it takes more energy to remove an electron from a poistively charged ion than it does from an neutral atom.
Ionization energy is the energy required to remove an electron from a neutral atom. When an electron is removed from an atom, the neutral atom becomes positively charged. When another electron is attempted to be removed from the same atom,this requires more energy than the first one, as the attractive force between the electrons and protons are greater owing to the presence of the extra proton. In order to break this force we need more energy to remove the second electron. Hence the second ionization energy is greater than the first ionization energy.
a student wants to remove the salt from a mixture of sand and salt in order to get only person he adds water to the mixture why it's the step help
copper has a density of 8.92 g/cm^3. a sample of copper occupies a volume of 25.8 mL. what is the mass of this sample of copper in milligrams?
Given:
Density:8.92g/cm3
Volume:25.8 mL
Now we know that
Mass = density X volume
Substituting the given values in the above equation we get:
Mass = 8.92 x 25.8= 230.136 g
= 230136 mg
Final answer:
To find the mass of a copper sample in milligrams, calculate the mass using density and volume (mass = density × volume), resulting in 230.016 g, and convert to milligrams to get 230016 mg.
Explanation:
The question asks to find the mass of a sample of copper in milligrams, given its density is 8.92 g/cm3 and it occupies a volume of 25.8 mL. First, we need to recall that density is defined as mass over volume (d = m/v), which means mass can be calculated as m = d × v. Given the density of copper (8.92 g/cm3) and the volume of the sample (25.8 mL, which is equal to 25.8 cm3 because 1 mL = 1 cm3), we can calculate the mass in grams and then convert it to milligrams.
To calculate the mass in grams: mass = 8.92 g/cm3 × 25.8 cm3 = 230.016 g. To convert this into milligrams (remembering that 1 g = 1000 mg), we multiply by 1000, resulting in 230016 mg.
Therefore, the mass of the copper sample is 230016 milligrams.
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Which has more Hydrogen atoms?
A) 2 moles of NH₃
B) 2 moles of CH₄
B. because the little number below the H stands for how many atoms there are, and b has 1 more Hydrogen atom than A does.
(I think)
ans is B) 2 moles of CH₄
because it has 4 Hydrogen atoms per molecule, 1 more than NH3 has.
Which of the following cations will hydrolyze to generate an acidic solution?
A. Na+
B. Ca+2
C. Sn+4
D. All of them
Answer:
C
Explanation:
Ca+2 and Na+ do not hydrolyze to form an acidic solution because they are obtained from an alkali.
Why does aluminum most often have an oxidation state of +3
Aluminium most often has an oxidation state of +3 because it has three valence electrons that are removed relatively easily.
Al is in Group 13, so it has three valence electrons.
To get a complete octet, it must either lose three electrons or gain five.
It is easier to remove three electrons, so Al most often has an oxidation state in its compounds.
Final answer:
Aluminum typically has a +3 oxidation state because it loses all three valence electrons in its outer shell during oxidation, forming an Al³+ ion. This oxidation state is maintained in both ionic and covalent aluminum compounds to achieve stability and comply with electrical neutrality in compounds like Al₂O₃.
Explanation:
Aluminum commonly exhibits an oxidation state of +3 because it has three valence electrons in its outer shell (ns²np¹ configuration). When aluminum atom is oxidized, it tends to lose all three of these electrons, resulting in an Al³+ ion with a +3 oxidation state. Transition metals, in comparison, have multiple oxidation states because they can lose electrons from both their s and d orbitals. This is not as straightforward for aluminum, which has only p orbital electrons to lose.
While in many compounds of aluminum, such as AlF3 and Al₂(SO₄)₃, the oxidation state is represented as ionic, some aluminum-containing compounds are covalent. However, in both cases, aluminum adopts a +3 oxidation state to achieve stability. In aqueous solutions, aluminum salts dissociate to release [Al(H₂O)₆]³+ cations, demonstrating aluminum's charge even when coordinated. Furthermore, during redox reactions, aluminum is oxidized by losing three electrons to give a +3 charge, which complies with the electrical neutrality essential in ionic compounds like Al₂O₃.
which two structures would provide a positive identification of an plant cell under a microscope?
A. Chloroplast, large central vacuole
B. Endoplasmic reticulum, chlorplast
C. Large central vacuole, flagellum
D. Cytoskeleton, cell wall
How many moles of carbon are in 3.0 moles of C6H12O6?
Hey there!:
1 mole of C6H12O6 ------------------ 6 moles of C
3.0 moles of C6H12O6 ------------- ??
3.0 *6 / 1 =>
18.0 moles of C
Hope that helps!
Answer:
18.0
Explanation:
Which of the characteristics below best describes organic compounds? produced by living organisms compounds of carbon and hydrogen limited to carbon compounds which are synthetic any compound containing carbon
Answer;
Compounds of carbon and hydrogen
Explanation;
An organic compound is any of a large class of chemical compounds in which one or more atoms of carbon are covalently linked to atoms of other elements, most commonly hydrogen, oxygen, or nitrogen.
The primary difference between organic compounds and inorganic compounds is that organic compounds always contain carbon while most inorganic compounds do not contain carbon. Additionally, nearly all organic compounds contain carbon-hydrogen or C-H bonds.
Organic compounds includes nucleic acids, fats, sugars, proteins, enzymes and hydrocarbon fuels. All organic molecules contain carbon, nearly all contain hydrogen, and many also contain oxygen.
Answer:
Compounds of carbon and hydrogen
Solid carbon is known to react with oxygen gas to produce carbon dioxide. If a mass of 1.2g of carbon is burned in oxygen, 4.4g of carbon dioxide is found to form. How many grams of oxygen gas reacted with carbon?
Now ,
C + O2 → CO2
According to above equation, 1 mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.Thus this implies that 12 g of carbon reacts with 32 g of O2 to produce 44 g of CO2.
No of moles = mass of the substance/molecular mass of the substance.
In this case 1.2 g of carbon reacts with "x "g of O2 to produce 4.4 g of CO2.
No of moles of carbon in this case = 1.2÷ 12 = 0.1 moles.
No of moles of carbon dioxide formed = 4.4÷44 =0.1 moles
Thus already discussed above, 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. Hence to produce 0.1 mole of CO2 ,0.1 mole of carbon needs to react with 0.1 mole of oxygen.
Also number of moles of O2 = mass of O2÷ molar mass of O2
Substituting number of moles of O2 as 0.1 we get
mass of O2(x) = Number of moles of O2 × Molar mass of O2
Mass of O2 (x) = 0.1 × 32= 3.2 g
Thus mass of 3.2 g O2 reacts with 1.2 g of CO2 to produce 4.4 g of CO2.
In the reaction between carbon and oxygen to form carbon dioxide, the amount of oxygen reacted can be calculated by subtracting the mass of carbon used from the mass of carbon dioxide formed. In this case, approximately 3.2 g of oxygen reacted with 1.2 g of carbon to produce 4.4 g of carbon dioxide.
Explanation:In the reaction between carbon and oxygen to form carbon dioxide, the amount of oxygen reacting can be calculated using stoichiometry. The balanced chemical equation for this reaction is C + O2 -> CO2. According to this equation, each mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.
Knowing that the molar mass of carbon is about 12.0 g/mol and carbon dioxide is approximately 44.0 g/mol, we can figure out the amount of oxygen that reacted. If the experiment has resulted in 4.4 g of carbon dioxide from 1.2 g of carbon, the amount of oxygen that participated may be calculated as follows: the difference between the mass of carbon dioxide formed (4.4 g) and the mass of carbon used (1.2 g) gives the mass of oxygen. Therefore, 4.4 g - 1.2 g equals 3.2 g of oxygen.
This shows that in the given reaction, approximately 3.2 g of oxygen reacted with 1.2 g of carbon to produce 4.4 g of carbon dioxide.
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How many grams of a 1000-gram radioactive sample are left after 3 half-lives? *
1 point
1000 grams
500 grams
250 grams
125 grams
2000 grams
The answer is 125 gms.
Answer:
first half of 1000gram=1000/2=500g
second half of 1000gram=500/2=250g
third half of 1000gram=250/2=125 g
Explanation:
in simple
third half of 1000 g=1000/(2³)=125gram
what is the mass of 0.28 moles of iron
1 mole has mass = 56 g
0.28 mol has mass = 56 x 0.28 = 15.68 g
Hope this helps!
Final answer:
To calculate the mass of 0.28 moles of iron, multiply the number of moles by the molar mass of iron, which is 55.85 g/mol, resulting in a mass of 15.638 grams.
Explanation:
To find the mass of 0.28 moles of iron, we need to use the molar mass of iron. The molar mass of iron (Fe) can be found on the periodic table and it is approximately 55.85 grams per mole.
Step 1: Molar Mass of Iron
First, we establish the molar mass of iron is 55.85 g/mol.
Step 2: Calculate the Mass
Next, we multiply the number of moles by the molar mass of iron to calculate the mass.
Mass = moles × molar mass
Mass = 0.28 moles × 55.85 g/mol
Mass = 15.638 grams
What is the name of the term that describes the conditions that are kept the same between all groups in an experiment?
Control or controlled group is the part of the experiment where conditions are kept the same.
Inertia is based only on an object’s Question 1 options: mass net force velocity weight
Answer: Inertia is based only on an object’s mass.
Explanation:
Any physical object's resistance towards any change in its velocity is known as inertia.
Therefore, more is the mass of an object, the more inertia will be there.
Thus, we can conclude that inertia is based only on an object’s mass and not on velocity.
The correct answer is option A which is mass.
Explanation:Inertia is terminology which is most commonly used in the physics. It is the measure of the resistance provided by the object in response to change in its speed or velocity.According to the first law of motion, an object remains in the rest or in continues motion state unless they experience a force on it.And every action has a reaction.So when a force is applied on the moving object, it resists to change its state. That resistance is inertia.Inertia of an object is directly proportional to mass of the object.Hence option A is correct one.98 points!! MUST SHOW YOUR WORK for Brainliest!
Which has more Carbon atoms:
A) 48 grams of CO₂
B) 12 grams of pure Carbon
48 grams of CO₂ contains approximately 6.56 x 10²³ carbon atoms, whereas 12 grams of pure carbon contains exactly 6.022 x 10²³ carbon atoms. Hence, 48 grams of CO₂ has more carbon atoms than 12 grams of pure carbon.
Comparing Carbon Content in CO₂ and Pure Carbon
To determine which sample contains more carbon atoms, we first need to consider their molar masses and the mass of carbon in each. The atomic mass of carbon is approximately 12 u, and one mole of a substance contains Avogadro's number of particles, which is roughly 6.022 x 10²³ particles/mole.
For CO₂ (molar mass approximately 44 g/mol), 48 grams corresponds to approximately 48 g / 44 g/mol = 1.09 moles of CO₂. Since each mole of CO₂ contains one mole of carbon atoms, there would be 1.09 moles of carbon atoms in 48 grams of CO₂.
For pure Carbon, 12 grams corresponds directly to 12 g / 12 g/mol = 1 mole of carbon since its molar mass is 12 g/mol. This equals 1 mole, or 6.022 x 10²³ carbon atoms.
Given that 1 mole of a substance contains 6.022 x 10²³ atoms:
48 grams of CO₂ has 1.09 moles x 6.022 x 10²³ atoms/mole = 6.56 x 10²³ carbon atoms.
12 grams of pure carbon has 1 mole x 6.022 x 10²³ atoms/mole = 6.022 x 10²³ carbon atoms.
Therefore, 48 grams of CO₂ has more carbon atoms than 12 grams of pure carbon.
If 23.7 g of Al(OH)3(s) are mixed with 29.5 g of H2SO4(s) and the reaction is run, answer the following questions:
(a) What is the limiting reagent?
(b) Assuming no side reactions, how much H2O(l) can be produced under these conditions?
(c) If 2.21 g of H2O(g) are produced in the lab under these conditions, what is the percent yield?
(d) How many grams of the reactant in excess remains at the end of the experiment?
Data: Atomic mass Al = 26.98, H = 1.008, O = 16.00, S = 32.07,
Aluminum hydroxide [tex]\text{Al}(\text{OH})_3[/tex] can behave as a base and neutralize sulfuric acid [tex]\text{H}_2\text{SO}_4[/tex] as in the following equation:
[tex]2\;\text{Al}(\text{OH})_3 \; (s) + 3\; \text{H}_2\text{SO}_4 \; (aq) \to \text{Al}_2(\text{SO}_4)_3 \; (aq) + 6 \; \text{H}_2\text{O} \; (l)[/tex] (Balanced)
(a)
[tex]n = m/M[/tex]. Thus the ratio between the number of moles of the two reactants available:
[tex]n(\text{Al}(\text{OH})_3, \text{supplied}) / n(\text{H}_2\text{SO}_4, \text{supplied})\\= [m(\text{Al}(\text{OH})_3)/ M(\text{Al}(\text{OH})_3)] / [n(\text{H}_2\text{SO}_4) / M(\text{H}_2\text{SO}_4)]\\= [23.7 / (26.98 + 3 \times(16.00 + 1.008))]/[29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00)]\\\approx 1.01[/tex]
The value of this ratio required to lead to a complete reaction is derived from coefficients found in the balanced equation:
[tex]n(\text{Al}(\text{OH})_3, \text{theoretical}) / n(\text{H}_2\text{SO}_4, \text{theoretical}) = 2/3 \approx 0.667[/tex]
The ratio for the complete reaction is smaller than that of the reactants available, indicating that the species represented on the numerator, [tex]\text{Al}(\text{OH})_3[/tex], is in excess while the one on the denominator, [tex]\text{H}_2\text{SO}_4[/tex], serves as the limiting reagent.
(b)
The quantity of water produced is dependent on the amount of limiting reactants available. [tex]29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00) = 0.301 \; \text{mol}[/tex] of sulfuric acid is supplied in this reaction as the limiting reagent. [tex]6[/tex] moles of water molecules are produced for every [tex]3[/tex] moles of sulfuric acid consumed. The reaction would thus give rise to [tex]0.301 \; \text{mol} \times 6/3 = 0.602 \; \text{mol}[/tex] of water molecules, which have a mass of [tex]0.602 \times (2 \times 1.008 + 16.00) = 10.8 \; \text{g}[/tex].
(c)
[tex]\text{Percentage Yield}\\= \text{Actual Yield} / \text{Theoretical Yield} \times 100 \; \%\\= 2.21 / 10.8 \times 100 \; \%\\= 20.4 \; \%[/tex]
(d)
The quantity of [tex]\text{Al}(\text{OH})_3[/tex], the reactant in excess, is dependent on the number of moles of this species consumed in the reaction and thus the quantity of the limiting reagent available. The consumption of every [tex]3[/tex] moles of sulfuric acid, the limiting reagent, removes [tex]2[/tex] moles of aluminum hydroxide [tex]\text{Al}(\text{OH})_3[/tex] from the solution. [tex]0.301 \; \text{mol}[/tex] of sulfuric acid is initially available as previously stated such that [tex]0.301 \; \text{mol} \times 2/3 = 0.201 \; \text{mol}[/tex], or [tex]0.201 \times (26.98 + 3 \time (16.00 + 1.008)) = 15.7 \; \text{g}[/tex], of [tex]\text{Al}(\text{OH})_3[/tex] would be eventually consumed.
[tex]23.7 - 15.7 = 8.0 \; \text{g}[/tex] of [tex]\text{Al}(\text{OH})_3[/tex] would thus be in excess by the end of the reaction process.
Aside from Earth, which of the following inner planets once had liquid water on its surface?
Aside from Earth, which inner planet once had liquid water on its surface? (Mars)
Aside from Earth, mars is one if the inner planets which once had liquid water on its surface.
What are planets?A planet is a large, rounded astronomical body that is neither a star nor its remnant. The best available theory of planet formation is the nebular hypothesis, which posits that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a protoplanetary disk. Planets grow in this disk by the gradual accumulation of material driven by gravity, a process called accretion.
The Solar System has at least eight planets: the terrestrial planets Mercury, Venus, Earth and Mars, and the giant planets Jupiter, Saturn, Uranus and Neptune. These planets each rotate around an axis tilted with respect to its orbital pole. All of them possess an atmosphere, although that of Mercury is tenuous, and some share such features as ice caps, seasons, volcanism, hurricanes, tectonics, and even hydrology.
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The main goal of developing technology is to___?
A)
learn about the universe and the laws of nature.
B)
design new scientific instruments.
C)
make new inventions and processes to benefit humans.
D)
make new scientific discoveries.
I believe the correct answer is C, but I'm 100% on this. Hope this helped though!
-TTL
Answer:
C
Explanation:
I did it and it is c
Hydrocarbons having the same formula but variations in structure are called _______. modified structures isomers saturated condensed structures
Hydrocarbons having the same formula but variations in structure are isomers.
The word “isomer” comes from the Greek words isos (= same or equal) and meros
(= share or part).
Thus, isomers have the same parts, but they are joined together in different ways.
A piece of wood has a density of 0.93 g/mL and a mass of 23 g what is the volume?
Given:
Density: 0.93 g/mL
Mass: 23 g
Volume = Density/Mass
Substituting the given values in this equation we get
Volume = 23 g ÷ 0.93 g/ mL
Volume = 24.73 mL
Physical and chemical changes occur during digestion. An example of a chemical change during digestion is. A:teeth chewing the food. B:the mouth swallowing food. C: the esophagus moving food. D: enzymes breaking down food.
It would be D. Enzymes breaking down the food. Enzymes are used to speed up chemical reactions
Answer: Option (D) is the correct answer.
Explanation:
A change that does not bring any difference in chemical composition of a substance are known as physical change.
For example, shape, size, mass, volume, density, etc of a substance are all physical properties.
Whereas a change that brings difference in chemical composition of a substance is known as chemical change.
For example, precipitation, reactivity, toxicity etc are chemical property.
During break down of food, salivary amylase breaks down starch into simple sugars. In stomach the enzyme pepsin converts protein into peptones in presence of acidic medium. Small intestine receives both intestinal and pancreatic juices (chemical substances) and the final digestion of fats, proteins and sugars occurs here.
Thus, we can conclude that example of a chemical change during digestion is enzymes breaking down food.
If one of the station models were to show that the barometric pressure was steadily dropping and the current weather condition showed a slight drizzle with the temperature of 65 degrees what would you expect the weather to be over the next 6 hours
The weather would be around the same maybe dropping 5 degrees.
What is barometric pressure?Barometric pressure is the measurement of air pressure in the atmosphere.
A barometer that has a high reading — meaning high pressure — and is stable, indicates good weather.
If one of the station models were to show that the barometric pressure was steadily dropping and the current weather condition showed a slight drizzle with the temperature of 65 degrees then would be around the same maybe dropping 5 degrees.
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As gaseous material condensed in the solar nebula, ice formed
1)
only far above or below the plane of the ecliptic
2)
only between the present orbits of Earth and Venus
3)
only inside the present orbit of Mars
4)
only far from the Sun
A student found the mass of the irregular solid to be 6.4 grams and the volume on the graduated cylinder rose from 6.8 mL to 7.7 mL. What is the identity of the substance? Question 4 options: Zinc Alcohol Aluminum Copper
Density, Volume and Mass
3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water
level rose to the 37.4 mL mark.
a) Calculate the density of the metal (in g/mL).
b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?
hat historical figure was responsible for developing the system for categorizing living things that is still used today? A) Sir Isaac Newton B) Carolus Linnaeus C) Benjamin Franklin D) Galileo
Carolus Linnaeus is responsible.
Understanding the high-temperature behavior of nitrogen oxides is essential for controlling pollution generated in automobile engines. The decomposition of nitric oxide (no) to n2 and o2 is second order with a rate constant of 0.0796 m−1⋅s−1 at 737∘c and 0.0815 m−1⋅s−1 at 947∘c. You may want to reference (page) section 14.5 while completing this problem. Part a calculate the activation energy for the reaction. Express the activation energy in kilojoules per mole to three significant digits.
We have that for the Question "Calculate the activation energy for the reaction" it can be said that The activation energy is
Ea=1.150KJ/molFrom the question we are told
Understanding the high-temperature behavior of nitrogen oxides is essential for controlling pollution generated in automobile engines. The decomposition of nitric oxide (no) to n2 and o2 is second order with a rate constant of 0.0796 m−1⋅s−1 at 737∘c and 0.0815 m−1⋅s−1 at 947∘cActivation energyGenerally the equation for the Activation energy is mathematically given as
[tex]10(\frac{kr}{ki})=\frac{Ea}{2.303R}(\frac{1}{t_1}-\frac{1}{t_2}})\\\\Therefore\\\\10(\frac{0.0815}{0.0796})=\frac{Ea}{2.303*8.314}(\frac{1}{1010}-\frac{1}{1220}})\\\\Ea=\frac{0.01024}{8.9*10^{-6}}/mol\\\\[/tex]
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The activation energy for the reaction is 96.8 kJ/mol.
Explanation:To calculate the activation energy for the reaction, we can use the Arrhenius equation: k = Ae-Ea/RT, where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin. We are given the rate constants at two different temperatures, so we can set up two equations:
k1 = A e-Ea/(R × T1)
k2 = A e-Ea/(R × T2)
Dividing the second equation by the first equation, we get:
(k2/k1) = (A e-Ea/(R ×T2))÷(A e-Ea/(R ×T1))
Simplifying, we get:
eEa/R = (k2/k1) ×(T2/T1)
Taking the natural logarithm of both sides, we can solve for the activation energy:
Ea = -R × ln((k2/k1) × (T2/T1))
Using the given values, we can plug in and calculate the activation energy:
Ea = -8.314 J/mol ×K × ln((0.0815 m-1 × s-1)/(0.0796 m-1 × s-1) × (947 + 273)/(737 + 273)) = 96.8 kJ/mol
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