Answer:
C) nonmetal
Explanation:
Given;
The sample is in liquid state and do not conduct electricity.
We have given four types of classification.So for first,
A) Ionic
Ionic compounds are found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be ionic.
B)Metal
Metals are found in solid state at room temperature except mercury and it conducts electricity very well. Mercury also conducts electricity.So the sample is not a metal.
C)Nonmetal
Non metals are found in solid state except bromine which is in liquid state at room temperature and it does not conducts electricity.
Here the property of nonmetal matches with the sample, so the sample is a nonmetal and it could be Bromine.
D)Salt
Salt is an ionic compound found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be salt.
Answer:
C for k12
Explanation:
The rate of reaction for a hypothetical reaction was found to be 0.62 mol/L*s at 6°C. What would be the rate at 46°C?
Answer:
9.92 mol/L*s
Explanation:
Given data:
Rate of reaction = 0.62 mol/L*s
Temperature = 6°C
Rate of reaction at 46°C = ?
Solution:
There are 10 increase in four time of given temperature.
6+10 = 16
16+ 10 = 26
26+10 = 36
36=10 = 46
According to thumb rule,
By doubling the reaction four time the rate will be,
0.62 mol/L*s ×2⁴
0.62 mol/L*s × 16
9.92 mol/L*s
A red blood cell placed in distilled water will swell due to the diffusion of
Answer:
Osmosis
Explanation:
Particle in water move from low concentration to higher concentration in semi-permeable membrane. The particle of water would be less concentrated therefore the water would move into red blood cell therefore building in mass due to water and therefore swelling
A gas that exerts a pressure of 14 bar
in a container with a volume of 312 mL will exert a pressure of ______bar when transferred to a container with a volume of 652 mL.
Assume that the number of moles and the temperature remain constant.
Answer:
A gas that exerts a pressure of 14 bar in a container with a volume of 312 mL will exert a pressure of 6.7 bar when transferred to a container with a volume of 652 mL.
Explanation:
Given data;
Initial pressure = 14 bar
Initial volume = 312 mL
Final pressure = ?
Final volume = 652 mL
Solution:
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 14 bar 312 mL / 652 mL
P₂ = 4368 bar. mL /652 mL
P₂ = 6.7 bar
A gas that exerts a pressure of 14 bar in a container with a volume of 312 mL will exert a pressure of 6.7 bar when transferred to a container with a volume of 652 mL.
Answer:
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 14 bar 312 mL / 652 mL
P₂ = 4368 bar. mL /652 mL
P₂ = 6.7 bar
A gas that exerts a pressure of 14 bar in a container with a volume of 312 mL will exert a pressure of 6.7 bar when transferred to a container with a volume of 652 mL.
Explanation:
Convert 325 milliliters to liters.
A:0.325 liters
B:3.25 liters
C:32.5 liters
D:325 liters
Answer:
The Awnser Is A. 0.325 Liters
Explanation:
What is the total pressure of the two gases collected over water at 24 degrees Celsius if the pressure of hydrogen gas is 3.0KPa and the pressure of water vapor is 91.4KPa
Answer:
P(total) = 94.4 kpa
Explanation:
Given data:
Pressure of hydrogen gas = 3.0 kpa
Pressure of water vapors = 91.4 kpa
Total pressure =?
Solution:
According to Dalton law of partial pressure,
The total pressure exerted by mixture of gases is equal to the sum of partial pressure of the individual gas.
This expression can be written as,
P(total) = P₁ + P₂ + P₃ + ...... Pₙ
Now we will put the values in formula:
P(total) = P₁ + P₂
P(total) = 3.0 kpa + 91.4 kpa
P(total) = 94.4 kpa
what is the easiest way to separate hydrogen and oxygen out of a water molecule?
A.) Boil the water until the chemical bonds break
B.) They cannot be separated by using physical properties
C.) Filter the water using charcoal to break the chemical bonds
D.) Use a magnet to pull out the metallic bonds
For part one synthesis reactions The product of the reaction is MgO. Describe what you observed in the reaction then consider the general AB form of a synthesis reaction. Write the chemical reaction balancing the equation so that there are an equal number of atoms of each type in both reactants and the product
Answer:
[tex]2Mg+O_{2} \rightarrow 2MgO[/tex]
Explanation:
Synthesis reaction:
In the synthesis reaction, two reactants combined to form a single product.
For example,
"A" and "B" are two reactants then combined to form a "AB" product.
The chemical reaction is as follows.
[tex]A+B \rightarrow AB[/tex]
The product "MgO" is formed by magnesium reacts with oxygen to form Magnesium oxide.
The chemical reaction is as follows.
[tex]2Mg+O_{2} \rightarrow 2MgO[/tex]
In a synthesis reaction to create MgO, magnesium and oxygen combine, each molecule of magnesium combining with half a molecule of oxygen to produce a molecule of magnesium oxide. The MgO product is a white crystalline solid at room temperature. This follows the general AB form synthesis reaction.
Explanation:The synthesis reaction to create MgO from its elemental components is represented by the simple equation:
Mg (s) + 0.5O₂ (g) → MgO (s)
In this reaction, magnesium (Mg) combines with oxygen (O₂) to form magnesium oxide (MgO). To balance the equation, we use 0.5 moles of oxygen for every mole of magnesium. The principle of conservation of mass requires that the number of each type of atom is consistent on both sides of the equation.
The product, magnesium oxide, is a white crystalline solid at room temperature. When considering the general form of a synthesis reaction, AB, magnesium (A) and oxygen (B) come together to form magnesium oxide (AB).
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What do the elements in the oxygen family (Group 16) have in common?
O
A. They are all gases.
O
B. They tend not to react with other elements.
O
C. They are all nonmetals.
O
D. They tend to react in similar ways.
Answer:
D. They tend to react in similar ways.
Explanation:
A is not correct, as there is only one gas in Group 16--that being oxygen
B is not correct, as these elements actually tend to react a lot with others elements
C is not correct, as there is only three nonmetals in Group 16--those being oxygen, sulfur, and selenium
Therefore, by process of elimination, answer D. is correct
A 2.5 L sample of gases at STP (standard temperature and pressure is 273 k and 1.00 atm). When the temperature is raised to 273degrees Celsius and the pressure remains constant the new volume of the gas will be?
Answer:
x = 5.9
Explanation:
Using Charles' Law, the new volume of a 2.5 L sample of gas at STP when the temperature is raised to 273°C (546 K), keeping pressure constant, is found to be 5.0 L.
The subject of this question is Chemistry, specifically related to gases and their behavior under different conditions of temperature and pressure. The question is asking for the new volume of a gas when its temperature is raised from the standard temperature and pressure (STP), which is 0°C or 273 K and 1.00 atm, to 273°C, given that the pressure remains constant.
To solve this, we use the Charles' Law, which states that, assuming the amount of gas remains the same and the pressure is constant, the volume of the gas is directly proportional to its temperature in Kelvins. Mathematically, Charles' Law is expressed as:
V1/T1 = V2/T2
Here, V1 is the original volume, T1 is the original temperature, V2 is the new volume, and T2 is the new temperature. Substituting in the given values:
V1 = 2.5 L (original volume)
T1 = 273 K (original temperature in Kelvins, which is the same as 0°C)
T2 = 273°C + 273 = 546 K (we convert the new temperature to Kelvins by adding 273)
The pressure remains constant, so the only variable that changes is temperature. To find the new volume (V2), the equation is rearranged to solve for V2:
V2 = (V1 \\times T2) / T1
After calculating, we get:
V2 = (2.5 L \\times 546 K) / 273 K
V2 = 5.0 L
Thus, when the temperature of the gas is increased to 273°C at constant pressure, the new volume of the gas will be 5.0 liters.
Answer these in order
Answer:
Explanation:
Pure Substance: are those having same type of atoms or molecules.
Compound: one or more atoms of the element combine to form a compound.
Mixture: is combination of one or more substances mix together.
Homogeneous Mixture: are those which are not distinguish by naked eye but can be separated into its components by physical means
Heterogeneous mixture: are those which can be distinguished by naked eye and can be separated into its components by physical means.
The complete detail of your answer in attachment
help plz .....................................................................................
Answer:
D.
Explanation:
Energy is released after reaction, so this is exothermic reaction. D
Answer:
D
Explanation:
First of all, the reaction is exothermic. The equation is not normally written this way. The way it is written shows that energy is given off: the heat is a product. The only answer that is described is D
Exothermic (but oddly presented) and energy given off.
How many atoms of lead are contained in 0.532mol?
Answer:
3.2043 x 10²³
Explanation:
No. of Mole of lead (Pb) = 0.532 mol
No. of atoms of lead = ?
Solution:
Formula Used to calculate
no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number
Avogadro's no. = 6.023 x10²³
So,
The formula could be written as
no. of atoms of lead Pb = no. of moles x 6.023 x10²³
Put the values in above formula
no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³
no. of atoms of lead Pb = 3.2043 x 10²³
so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.
find the POH of a solution of H3PO4 having a concentration of 0.05M
Answer:
The pOH of the solution is 13.176
Explanation:
The concentration of [tex]H_{3}PO_{4}[/tex] solution is 0.05 M
[tex]H_{3}PO_{4}[/tex] produces [tex]3\:H^{+}\:ions\:[/tex].
[tex]H_{3}PO_{4}\longrightarrow3H^{+}+PO_{4}^{3-}[/tex]
If the concentration of [tex]H_{3}PO_{4}[/tex] is 0.05 M, then the concentration of [tex]H^{+}\:ions\:[/tex] is three times that of [tex]H_{3}PO_{4}[/tex].
[tex][H^{+}]=3\times0.05=0.15M[/tex]
pH =-㏒([tex][H^{+}][/tex])= -㏒(0.15) =0.824
pOH = 14 - pH = 13.176
How many moles are there in 50.5 atoms ba
8.386 × 10^-23 moles
Explanation:We are given;
Number of atoms of Ba is 50.5 atomsWe are required to determine the number of moles
We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's number, 6.022 × 10^23.Therefore, 1 mole of an element contains 6.022 × 10^23 atomsIn this case;
1 mole of Ba contains 6.022 × 10^23 atoms
Number of moles = 50.5 atoms ÷ 6.022 × 10^23 atoms
= 8.386 × 10^-23 moles
The number of moles in 50.5 atoms of Ba is 8.386 × 10^-23 moles
Why do different substances have different Odors?
Answer:
Substances generate a smell when their molecules land on so-called olfactory neurones in our noses (which, for some things, is a pretty unpleasant thought). ... But this fails to explain why some molecules with similar shapes can smell completely different, while others with quite different shapes can have a similar scent.
Explanation:
I took chemistry
Different substances have different odors because they release unique molecular compounds into the air that are detected by olfactory receptors in the nose. Humans can distinguish a vast number of scents due to the variety of olfactory receptors we possess. Our sense of smell, tightly linked to our sense of taste, is crucial for our interactions with the environment and can evoke strong emotional responses.
Explanation:Why Do Different Substances Have Different Odors?
Different substances have different odors because each releases unique molecules into the air, which interact with the olfactory receptors in the nose. Humans have approximately 350 olfactory receptor subtypes that combine to distinguish roughly 10,000 different odors. In contrast, animals like mice have around 1,300 receptor types, indicating a possibly broader range of detectable scents. When odor molecules, also known as odorants, enter the nose, they dissolve in the olfactory epithelium, stimulating the receptors, and send signals directly to the olfactory bulb of the brain. The complexity of the sense of smell is sophisticated enough that humans can differentiate an estimated 1.72 trillion different detectible smells according to research by Bushdid et al. (Science, 343, 2014).
Our sense of taste is also closely connected to our olfactory sense. Taste buds and odor receptors collaborate to create the perception of flavor, and when our ability to smell is inhibited, such as with congested nasal passages, our perception of taste is similarly diminished. Substances with different molecular structures stimulate different receptors, accounting for the wide array of smells we can detect, ranging from pleasant scents to the objectionable odors of thiols, such as those found in skunk spray. Odorants can evoke powerful emotional responses and memories, making our sense of smell an important aspect of our daily experiences and interactions with the world around us.
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5. Suppose the efficiency of illumination is defined as the
intensity of light absorbed by the plants divided by the
intensity of light provided to the plants. Based on the
data, would one be justified in concluding that the effi-
ciency of illumination was higher in Section 1 than in
the other sections?
A. Yes, because the illumination provided to the
plants was highest in Section 1.
B. Yes, because the amount of light not absorbed by
the plants was highest in Section 1.
C. No, because the amount of light absorbed by the
plants was lowest in Section 1.
D. No, because the information provided is insuffi-
cient to determine efficiency of illumination.
Hydrogen-3 has a half-life of 12.32 years. A sample of H-3 weighing 3.02 grams is left for 15.0 years. What will the final weight of the H-3 sample be?
Answer:
[tex]\large \boxed{\text{1.38 g}}[/tex]
Explanation:
Two important formulas in radioactive decay are
[tex](1) \qquad t_{\frac{1}{2}} = \dfrac{\ln 2}{k}\\\\(2) \qquad \ln \left(\dfrac{N_{0}}{N}\right) = kt[/tex]
1. Calculate the decay constant k
[tex]\begin{array}{rcl}t_{\frac{1}{2}} &=& \dfrac{\ln 2}{k}\\\\\text{12.32 yr} &= &\dfrac{\ln 2}{k}\\\\k & = & \dfrac{\ln 2}{\text{12.32 yr}}\\\\& = & \text{0.056 26 yr}^{-1}\\\end{array}[/tex]
2. Calculate the mass remaining
[tex]\begin{array}{rcl}\ln \left(\dfrac{A_{0}}{A}\right) &= &kt \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &\text{0.056 26 yr}^{-1}\times \text{15 yr} \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &0.8439 \\\\\dfrac{\text{3.20 g}}{A} &= &e^{0.8439} \\\\\dfrac{\text{3.20 g}}{A}&= &2.325 \\\\A &= &\dfrac{\text{3.20 g}}{2.325}\\\\&= & \textbf{1.38 g}\\\end{array}\\\text{The final mass of the sample will be $\large \boxed{\textbf{1.38 g}}$}[/tex]
Answer: n = 1.30g
Explanation:
Recall the pancake recipe: 1 cup flour + 2 eggs + ½ tsp baking powder → 5 pancakes Suppose there are 5 cups of flour, 12 eggs, and 4 tsp. of baking powder. How many pancakes can be made?
Answer:
25 pancakes can be made.
Explanation:
This is a question based on the concept on of limiting reagent or limiting factor.
The pancakes can be kept on making till one of the item gets exhausted.
Let's, check which item gets exhausted first-
5 cups of flours are sufficient for making- [tex]\frac{5}{1}[/tex] × 5 ie. 25 pancakes considering we have 5×2 ie. 10 eggs and 5×1/2 ie. e 2.5 tsp of baking powder.
We can see that, we have all the required material needed and only the flour gets exhausted first.
But, still for our satisfaction we can check once, 12 eggs will make [tex]\frac{12}{2}[/tex] × 5 ie. 30 pancakes, but we don't have flour for 30 of them.
Similarly, 4 tsp of baking powder will yield 40 pancakes but we neither have enough flour nor we have enough eggs for it.
Therefore, the maximum number of pancakes that can be made are is 25.
Final answer:
The maximum number of pancakes that can be created with 5 cups of flour, 12 eggs, and 4 teaspoons of baking powder is 25. Flour is the limiting ingredient in this scenario, determining the final count of pancakes.
Explanation:
When considering how many pancakes can be made with given amounts of ingredients, we must determine the limiting reactant, much like in a stoichiometric calculation in chemistry. The original pancake recipe calls for 1 cup of flour, 2 eggs, and rac{1}{2} teaspoon of baking powder to make 5 pancakes.
We are provided with 5 cups of flour, 12 eggs, and 4 teaspoons of baking powder. To find out the maximum number of pancakes we can make, we identify the ingredient that will run out first when making batches of 5 pancakes. Here are the calculations based on the recipe proportions:
Flour: 5 cups imes 5 pancakes = 25 pancakesEggs: 12 eggs imes rac{5}{2} pancakes per egg = 30 pancakesBaking powder: 4 teaspoons imes 10 pancakes per teaspoon = 40 pancakesThe ingredient that limits us here is the flour, which will only allow for the creation of 25 pancakes before it is used up. Therefore, the maximum number of pancakes that can be made with the ingredients on hand is 25.
A sample of metal with a mass of 350.0 g is heated to 100.0 ºC and dropped into 400.0 g of water at 21.4 ºC. The temperature of the water rises to 28.0 ºC. Assume there is no heat lost to the environment. Use the correct number of significant figures in your answer. What is the amount of heat gained by the water?
Answer:
1.1 x 10^4 J
Explanation:
Final answer:
The heat gained by the water when a metal sample is dropped into it can be determined using the formula q = mcΔT. For the given scenario, the water gains approximately 11000 J of heat.
Explanation:
To calculate the amount of heat gained by the water when a sample of metal is dropped into it, we can use the formula q = mcΔT, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
For water, the specific heat capacity (c) is typically 4.184 J/g°C.
In this case, the water's mass (m) is 400.0 g and the change in temperature (ΔT) is 28.0 °C - 21.4 °C = 6.6 °C.
Using the formula, we get q = 400.0 g × 4.184 J/g°C × 6.6 °C, which equals approximately 11016 J.
Since the question specifies to use the correct number of significant figures, we report the answer as 11000 J of heat gained by the water.
To whoever helps me thank you so much have a wonderful day!
Answer:
N and P
Explanation:
Anion:
When an atom gain the electrons anion is formed. The negative sign shows that atom gain electron because number of electron are greater than protons or we can say that negative charge becomes greater than positive charge.
Cation:
When atom lose electron cation is formed. The atom thus have positive charge because number of positive charge i.e protons are increased are greater than negative charge or electron.
In given problem N and phosphorus both can gain three electrons which means negative charge becomes greater that's why the extra electron gained by atoms are written as -3 and both form anion with charge -3.
while Al form cation with charge +3 Mg form cation with charge +2 and iodine and bromine both form anion with charge of -1.
Which of the following are lost or gained during a nuclear reaction? (5 points)
a Electrons and nucleus
b Electrons and neutrons
c Protons and electrons
d Protons and neutrons
D
Nuclear reaction involves the nuclei of atoms. The nucleus can either split (as is the case with fission) of fuse as is the case with nuclear fusion. Remember the main particles in the nucleus are protons and neutrons.
Explanation:
In nuclear fission, atomic nuclei split into lighter atoms through loss of protons and neutrons (such as through loos of a beta particles - 2 protons and 2 neutrons). In the case of fusion, two atomic nuclei fuse under pressure (hence adding neutrons and protons) to create heavier atoms (2 hydrogens can fuse to form a helium). Electrons are not involved in nuclear reactions. Electrons are mainly involved in chemical reactions.
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Temperature change affects the rate of a chemical reaction by changing the __________ of the colliding particle.
A) charge
B) concentration
C) size
D) speed
Answer:
D) speed
Explanation:
Reaction rates can be affected by several factors, including concentration, temperature, surface area and presence of a catalyst. Increasing concentration increases the number of effective collisions. Increasing temperature increases the kinetic energy of the particles, leading to more effective collisions
Answer:
D
Explanation:
Speed
Is the following nuclear equation balanced?
237 Np - He+233 AM
Answer:
Yes
Explanation:
Np²³⁷ → He⁴ + Am²³³
The given nuclear equation is balanced. Np²³⁷ undergoes alpha decay and produce alpha particle and Am²³³.
Properties of alpha radiation:
Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.
Alpha radiations can travel in a short distance.
These radiations can not penetrate into the skin or clothes.
These radiations can be harmful for the human if these are inhaled.
These radiations can be stopped by a piece of paper.
₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy
A(n)_____________________ can either amplify an electronic signal or switch a current on and off.
Transistors
A(n) transistor can either amplify an electronic signal or switch a current on and off.
Explanation:
The main component of a transistor is a semiconductor. A transistor has at least three terminals. Voltage application through a pair of terminals affects the voltage of the other terminal. In addition, the controlling voltage can be lower than the controlled voltage, hence the amplification (gain) property of transistors. This same principle can be applied to switch on and off larger currents. If a controlling current surpasses a particular saturation point –specific to that transistor-, then it switches on the larger currents (controlled currents).
Transistors have much application in the world from being significant components in the electric circuits for speakers, hearing aids, calculators, computers, and most other digital gadgets.
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1. A dining hall had a total of 25 tables-some long rectangular tables and some round
ones. Long tables can seat 8 people. Round tables can seat 6 people. On a busy
evening, all 190 seats at the tables are occupied.
How many long tables, x, and how many round tables, y, are there?
x = 20 long tables
y = 5 round table
Explanation:
We have the following system of equations:
x + y = 25
8x + 6y = 190
From the first equation we have:
x = 25 - y
And we replace x in the second equation:
8(25 - y) + 6y = 190
200 - 8y + 6y = 190
200 - 2y = 190
200 - 190 = 2y
10 = 2y
y = 5
Now we insert the value of y in the next equation:
x = 25 - y
x = 25 - 5
x = 20
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Given the total number of tables and the number of seats they provide, we can derive a system of linear equations to solve for the number of each type of table.
Explanation:This is a problem of linear algebra. Given that the total number of tables is 25 and each type of table seats a different number of people, we can set up the following system of equations:
Equation 1): x + y = 25 (This equation comes from the fact that there are 25 tables total, a sum of long rectangular tables, x, and round tables, y.)
Equation 2): 8x + 6y = 190 (This equation comes from the fact that all the seats at the tables are occupied and we know how many people each type of table can seat.) Solving these equations simultaneously will give us the values of x and y. This type of problem is common in Systems of Linear Equations in algebra.
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Part A
What is the mass of the water?
Express your answer to two significant figures and include the appropriate units.
The question focuses on calculating the mass of water using its density and volume, requiring an understanding of physics concepts and the correct application of significant figures and units.
Explanation:The question provided involves calculating the mass of water based on its density and volume, which is a fundamental concept in physics. To determine the mass of water, you use the formula mass = density × volume. The density of water is given as 1.000 ×10³ kg/m³, and various examples of volume calculations are provided, illustrating different contexts in which this calculation might be applied.
One specific calculation detailed is m = (1.000 × 10³ kg/m³) (2.00 × 10³ m³) = 1.00 × 10¸ kg, demonstrating how to apply the density-volume relationship. Another example provided is using a volume of 2.00 × 10¹ m³, resulting in a mass of 2.00 × 10±² kg. These calculations emphasize the importance of properly applying significant figures and units in physics problems.
The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).
4Al + 3O2 ----> 2Al2O3
The molar mass of O2 is 32.0 g/mol. What mass, in grams, of O2 must react to form 3.80 mol of Al2O3?
60.8
81.1
122
182
Answer:
D. 182
Explanation:
right on e2020
Answer:
182 grams of oxygen gas must react to form 3.80 mol of aluminum oxide.
Explanation:
[tex]4Al + 3O_2\rightarrow 2Al_2O_3[/tex]
Moles of aluminum oxide = 3.80 mole
According to reaction, 2 moles of aluminum oxide is obtained from 3 moles of oxygen gas.
Then 3.80 moles of aluminum oxide will be obtained from:
[tex]\frac{3}{2}\times 3.80 mol=5.7 mol[/tex] of oxygen gas.
Mass of 3.80 moles of oxygen = 5.7 mol × 32 g/mol = 182.4 g ≈ 182 g
182 grams of oxygen gas must react to form 3.80 mol of aluminum oxide.
If an element has 2+ valence electrons, does it transfer only one or more than one valence electrons
Answer:
element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.
Explanation:
Group IIA have 2+ valency and two electrons in its valance shell.Its Electropositivity is high and have the tendency to donate it two electrons.Element of IIA form ionic with most electronegative element.Examples:
Cu²⁺, Mg²⁺, Sr²⁺ are examples having 2+ valance electron
one of the following is examples of element that have 2+ valence electrons
MgCl₂
Atomic number of Magnesium (Mg) is 12
Electronic Configuration of Mg:
1s², 2s², 2p⁶, 3s²
or
K =2
L = 8
M = 2
So, it have to give its 2 electrons to form a stable compound.
Similarly
Chlorine atomic number is 17
Electronic Configuration of Chlorine:
1s², 2s², 2p⁶, 3s², 3p⁵
or
K =2
L = 8
M = 7
So, it have to gain one electrons to form a stable compound and complete its octet.
So,
Two chlorine atom as a molecule gain 2 electrons from Mg²⁺ atom
So one Mg²⁺ and 2 Cl⁻ atoms form an ionic bond
where in this ionic bond Mg²⁺ transfer its 2 valence electron completely and chlorine molecule accept 2 electrons.
Cl-----Mg------Cl
So the Answer is
element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.
What are the empirical formula and empirical formula mass for C10H30O10?
Empirical formula:
Empirical formula mass:
es
g/mol
Answer:
Empirical formula: CH₃O
Empirical formula mass = 31 g/mol
Explanation:
Data Given:
Molecular Formula = C₁₀H₃₀O₁₀
Empirical Formula = ?
Empirical Formula mass =
Solution
Empirical Formula:
Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.
So,
The ratio of the molecular formula should be divided by whole number to get the simplest ratio of molecule
As
C₁₀H₃₀O₁₀ Consist of 10 Carbon (C) atoms, 30 Hydrogen (H) atoms, and 10 Oxygen (O) atoms.
Now
Look at the ratio of these three atoms in the compound
C : H : O
10 : 30 : 10
Divide the ratio by two to get simplest ratio
C : H : O
10/10 : 30/10 : 10/10
1 : 3 : 1
So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1
So the empirical formula will be
Empirical formula of C₁₀H₃₀O₁₀ = CH₃O
Now
To find the empirical formula mass in g/mol
Formula mass:
Formula mass is the total sum of the atomic masses of all the atoms present in a formula unit.
**Note:
if we represent the molar mass of the empirical formula for one mol in grams then it is written as g/mol
So,
As the empirical formula of C₁₀H₃₀O₁₀ is CH₃O
Then Its empirical formula mass will be
CH₃O
Atomic Mass of C = 12
Atomic Mass of H = 3
Atomic Mass of O = 16
Total Molar mass of CH₃O
CH₃O = 12 + 3(1) + 16
CH₃O = 12 + 3 + 16
CH₃O = 31 g/mol
The empirical formula for C10H30O10 is C5H15O5 with an empirical formula mass of 151.15 g/mol.
Empirical formula: The empirical formula for C10H30O10 is C5H15O5.
Empirical formula mass: The empirical formula mass can be calculated by summing the atomic masses of the elements in the empirical formula: C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol. Therefore, the empirical formula mass is (5*12.01) + (15*1.008) + (5*16.00) = 151.15 g/mol.
You start with 12.94 g sample of a mixture containing SiO2, NaCl, and NH4Cl. If after subliming
away the NH4Cl, you have 2.17 grams of sample remaining, what was the mass percent of NH4CI
in the original sample? Show all work.
83.23 %
Explanation:We are given;
Mass of the sample mixture is 12.94 g Mass of the remaining mixture after sublimation is 2.17 gWe are required to get the mass percent of NH₄Cl in the original sample
Step 1 : Calculate mass of NH₄Cl in the original sample;Mass of NH₄Cl = Total mass of the mixture - remaining mass after sublimation
= 12.94 g - 2.17 g
= 10.77 g
Step 2: Percent by mass of NH₄Cl in the original sample% of NH₄Cl by mass =(Mass of NH₄Cl÷Total mass of original sample)×100
= (10.77 g ÷ 12.94 g) × 100
= 83.23 %
Therefore, the percent by mass of NH₄Cl in the original sample is 83.23%