(ENVIRONMENTAL SCIENCE NOT PHYSICS)
7. gradually taking over farmland over a long period of time is known as commodities. True or False
8. The 2002 farm bill gives money to farmers who grow crops like wheat and soybeans but not to fruit and vegetable farmers. True or False
9. some farmers have been selling their land to developers because it is more cost efficient to do so than to grow crops. True or False
10. The FBI regulates the use of pesticides in agricultural crops. True or False

Answers

Answer 1
1) False
2) True
3) True
4) True
5) False
6) True
7) False
8) True
9) True
10) False

100% : just took this :)

Related Questions

A woman falls to the ground while wearing a parachute. The air resistance on the parachute of the parachute is 500N. If the woman falls at a constant rate of 5m/s, then the gravitational force on her is

Answers

The fact that the woman falls at a constant velocity means its acceleration is zero. 
For Newton's second law, the resultant of the forces acting on a body is equal to the product between the mass m of the body and its acceleration a:
[tex]\sum F = ma[/tex]
In our problem, the acceleration is zero, so the resultant of the forces should be zero as well.

Only two forces are acting on the woman: the air resistance R (upward, 500 N) and the weight W (downward). The resultant of these two forces is zero, so
[tex]R-W=0[/tex]
[tex]W=R[/tex]
and since the air resistance R is 500 N, then the weight (the gravitational force) of the woman is 500 N as well.

Answer:

The correct answer is A.

Explanation:

You see a marble sign. Its letters are too worn to read. What caused this?

Answers

The worn letters on a marble sign are the result of weathering and erosion from natural elements, human activities, and pollution, which cause the marble to deteriorate over time.

If you see a marble sign with letters too worn to read, it's likely that the sign has been subjected to various forms of weathering and erosion. Over time, natural elements like rain, wind, temperature changes, and possibly even the growth of lichens or moss can cause the marble to wear down. This process can gradually erase the inscriptions on the sign.

Additionally, human activities such as touching or rubbing the sign can accelerate the erosion of marble, further contributing to the letters becoming unreadable. Moreover, pollution can also have a corrosive effect on marble, causing the inscriptions to fade more quickly.

Overall, the combined effects of natural weathering, human interference, and environmental pollutants are responsible for the deterioration of marble signs and their inscriptions.

Tom and his little sister are enjoying an afternoon at the ice rink. they playfully place their hands together and push against each other. tom's mass is 61 kg and his little sister's mass is 15 kg. if the sister's acceleration is 2.1 m/s2 in magnitude, what is the magnitude of tom's acceleration?

Answers

Newton's third law says:
"For every action, there is an equal and opposite reaction. ".

So, the force that Tom does on the sister is equal to force the sister applies on Tom:
[tex]F_t = F_s[/tex]
where the label "t" means "on Tom", while the label "s" means "on the sister".

From Newton's second law, we also know
[tex]F=ma[/tex]
where m is the mass and a the acceleration. so we can rewrite the first equation as
[tex]m_t a_t = m_s a_s[/tex]
And find Tom's acceleration:
[tex]a_t = \frac{m_s}{m_t} a_s = \frac{15 kg}{61 kg} (2.1 m/s^2) =0.52 m/s^2[/tex]
Final answer:

Under the principle of conservation of momentum, Tom and his sister exert equal and opposite forces on each other when they push, leading to equal and opposite accelerations. Tom's acceleration is given by the force his sister exerts (her mass times her acceleration) divided by his mass. Thus, his acceleration is calculated to be 0.516 m/s².

Explanation:

This problem involves the principle of conservation of momentum in physics. When Tom and his sister push against each other, they exert equal and opposite forces, leading to equal and opposite accelerations because acceleration = force/mass. The sister's acceleration (2.1 m/s²), as given in the problem, is directed away from Tom. To find Tom's acceleration, we need to use the equation: force = mass * acceleration (from Newton's 2nd law), solve this equation for Tom assuming that the force exerted by Tom and his sister on each other is the same.

Assuming that his sister's mass (15 kg) times her acceleration (2.1 m/s²) gives the force they exert on each other, we get 15 kg * 2.1 m/s² = 31.5 N. Then we divide this force by Tom's mass (61 kg) to get his acceleration: 31.5 N / 61 kg = 0.516 m/s². Therefore, Tom's acceleration is 0.516 m/s² away from his sister.

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What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.
1.1 × 10–17 J 
1.1 × 10–16 J
8.3 × 10–16 J
8.3 × 10–15 J

Answers

The energy carried by a single photon is given by
[tex]E=hf[/tex]
where h is the Planck's constant and f is the frequency of the photon.

The photon of our exercise has a frequency of [tex]f=1.7 \cdot 10^{17} Hz[/tex], therefore its energy is
[tex]E=hf=(6.63 \cdot 10^{-34}Js)(1.7 \cdot 10^{17} Hz)=1.1 \cdot 10^{-16} J[/tex]

Answer:

The correct answer is B.

Explanation:

Got a 100% on the Exam

At what separation will two charges, each of magnitude 6.0fYC,exert a force of 1.4N on each other?

a.0.48m

b.2.0m

c.5.1*10^6m

d.0.23m

e.40m

Answers

I assume that "fYC" is just a writing mistake and the two charges have magnitude [tex]q=6 \mu C=6 \cdot 10^{-6}C[/tex].
The electrostatic force between the two charges is
[tex]F=k_e \frac{q^2}{d^2} [/tex]
where [tex]k_e = 8.99 \cdot 10^9 Nm^2C^{-2}[/tex] is the Coulomb's constant, q is the magnitude of the two charges, and d is the separation between them.

We know the value of the force, F=0.14 N, so re-arranging the formula and using these data we can solve to find the value of d:
[tex]d= \sqrt{ \frac{k_e q^2}{F} } =0.48 m[/tex]

So, the separation between the two charges is 0.48 m.

This question involves the concept of Colomb's Law and electrostatic force.

The separation between charges will be "a. 0.48 m".

COLOMB'S LAW

According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

where,

F = electrostatic force = 1.4 Nk = Colomb's constant = 9 x 10⁹ N.m²/C²q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ Cq₂ = magnitude of second charge = 6 μC = 6 x 10⁻⁶ Cr = distance between charges = ?

Therefore,

[tex]1.4 N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{r^2}\\\\r=\sqrt{\frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{1.4\ N}}[/tex]

r = 0.48 m

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A ball is thrown at a height of 1.2m above the ground with an initial speed of 20 m/s at an angle 60 degrees above the horizontal. find a vector valued function r(t) describing the position of the ball

Answers

just try your best best friend everyone

A 17 kg box sitting on a shelf has a potential energy of 350 J. How high is the shelf? Round your answer to the nearest whole number. The shelf ism high

Answers

Hello!

Here we can use PE=mgh

So with your givens we have

Mass=17kg
PE= 350J
g=9.80m/s^2

So we have

350J = 17kg * 9.80m/s^2 * h

Now we just solve for our height! So we have

350J/(17kg*9.80m/s^2) = 2.10m is the height of the shelf. So rounded to nearest whole number, the shelf is 2meters high.

Hope this help. Any questions please just ask. Thank you so much!

The shelf is 2.10 m high. If rounded for nearest whole number the height of shelf is 2 meter.

From the formula of potential energy,

PE = mgh

Where,

PE- potential energy = 350J

m - mass = 17 kg

g - gravitational acceleration = 9.8 m/s²

h - height = ?

Put the values in the formula and solve it for h    

350J = 17kg  x 9.80m/s^2 x  h

h =  2.10 m

Therefore, the shelf is 2.10 m high. If rounded for nearest whole number the height of shelf is 2 meter.

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which vector best represents the net force acting on the -3 C charge in the diagram

w
x
y
z

Answers

Vector ' W ' best represents the net force acting on the -3 C charge in the diagram.

Answer:

 W is the correct answer.

Explanation:

   Since the charges are negative the forces acting is repulsive.

   The left -4C charge repulse -3C, the force is shown in figure given as F2

   The right -4C charge repulse -3C, the force is shown in figure given as F1

    Since the charge magnitudes are same the magnitude of F1 and F2 are same, but their direction is different. From second figure we can see the angle between forces and W is 30⁰.

  On resolving vectors the force along Z = F1 sin 30 and force along X = F2 sin 30

  Since magnitudes are same they cancel each other.

   Force along W = F1 cos 30 + F2 cos30 = 2Fcos 30 (Say F1 = F2 = F)

So net force is directed towards Z.

Waves transfer heat by the process of ______________.

convection

radiation

Answers

radiation transfers heat by electromagnetic waves

Answer: Radiation

Explanation: Waves (electromagnetic waves) transfer heat by the process of radiation, where radiation means the emission or transmission of energy by waves or particles, and heat is a form of energy, so this has sense.

In the other hand, convection means the heat transfer done by the bulk movement of particles inside gases or liquids, for example, if you heat a pot with water inside, first the water near the bottom is heated, and then by convection, this heated water moves and gives heat to the surrounding water.

If an object that enters the Earth’s atmosphere does not completely disintegrate, its remains can impact the Earth true or flase

Answers

true, when entering earths atmosphere there are stages. also known as the Thermosphere. stage 3. Where tempatures are hotter then any other stage. but do not burn all the way. mainly like a "shooting star".

Why does a clear stream always appear to be shallower than it actually is?

Answers

Because you see the base of the steam from the surface of the water. This creates the effect of the stream bed being elevated to the surface. This happens in water because light travels slower in water than in a vacuum.

Clear streams apparently look shallower than actual stream due to refraction of light.

What is refraction of light?

Refraction is the redirection of a wave as it passes from one medium to another medium. The redirection can be because of the wave's change in speed or by a change in the medium.

The refracted light coming from water always bends away from the normal at the surface. The refracted light coming from rarer to denser medium always bends towards normal at the surface.

When some one see the base of the steam from the top of water, stream base appears elevated to the surface. This happens in water as light travels slower in water than in a vacuum.

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Tai ran from his home to a position 300 m south of his home in 100 seconds. What was his velocity? A.0.33 m/s south B.0.33 m/s north C.3 m/s north D.3 m/s south

Answers

[tex]velocity = distance / time = 300m/100s = 3m/s [/tex]

Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of 50 kilograms. What can Paul do to increase the bike’s kinetic energy?

A. He can let Ivan off at the next stop.
B. He can pedal harder to increase the rate to 10 meters/second.
C. He can reduce the speed to 3 meters/second.
D. He can pick up a third rider.

Answers

The formula is Ke = 1/2 m v^2
The two of them together have a Ke of mv^2. So you either increase m or v. That's what makes the problem difficult. He can do D or B. We have to choose.

A is no solution. The Ke goes down because Paul loses Ivan's mass.
C is out of the question 3 meters/sec is a big reduction from 5 m/s. So now what do we do about B and D?

The question is what does the third person add. The tandoms I've peddled only allow for 1 or 2 people to add to the motion. So the third person only adds mass. He does not have a v that he is contributing to. To say that he is going 5m/s is true, but he's not contributing anything to that motion.

I pick B, but it is one of those questions that the correctness of it is in the head of the proposer. Be prepared to get it wrong. Argue the point politely if you agree with me, but back off as soon as you have presented your case.

B <<<<====== answer. 

Answer: The correct answer is option C.

Explanation:

Kinetic energy is the energy possessed by the an object due to its motion.An its calculated by:

[tex]K.E.=\frac{1}{2}mass\times (velocity)^2[/tex]

Kinetic energy depends upon the mass and velocity of the an object.

So, Paul can increase the bike's kinetic energy by increasing the velocity of its bike. Hence, the correct answer is option C.

Increasing the mass will also increase the kinetic energy . But according to option (D) he has to stop the bike first by applying brakes which will reduce the kinetic energy of the bike.And then again have to perform the work to bring the bike in motion

Why aren’t organisms on the sea floor crushed by water pressure

Answers

Their internal pressure is balanced out with the external pressure of the water.
For exactly the same reason that you don't get crushed by air pressure.
Your body is built with exactly enough pressure inside, pushing out.

A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box

Answers

The formula for Force is F = MA

 F = 128N.
M = 35.2kg.128 
= 35.2A

Divide both sides by 35.2

A = ~3.636
So the answer is 3.636 m/s².

When a man pushes a 35.2 kg box across a frictionless floor with a force of 128 N, then the acceleration of the box would be 3.6363 meters/second².

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows

F = ma

As given in the problem if a man pushes a 35.2 kg box across a frictionless floor with a force of 128 N, we have to calculate the acceleration of the box

Force = mass ×acceleration

128 = 35.2 × acceleration

acceleration = 128/35.2

                    = 3.6363 meters/second².

Thus, the acceleration of the box would be 3.6363 meters/second².

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5. Amy and Josh are coasting on their bicycles down a 10° slope at 15 m/s through still air. The mass of Amy and her bicycle is 60 kg. The mass of Josh and his bicycle is 90 kg. The cross-sectional area of Amy and her bicycle is 0.45, while the cross-sectional area of Josh and his bicycle is 0.60. The drag coefficient for both cyclists is 0.70. Other than gravity and air resistance, the external forces acting on the two bicycle and rider systems are the same. Which cyclist is more affected by air resistance? The Answer is Amy but what is the math invovled, Please Show Work and Help!

Answers

Forces in the x-direction:

[tex]ma = mg*sin \theta - cA v^{2} [/tex]

The acceleration:
[tex]a = g*sin \theta - \frac{cA}{m} v^2[/tex]

The first term is independent of mass, only the second term depends on mass m:
[tex]\frac{cA}{m} v^2 [/tex]
Amy:
[tex]\frac{0.45 * 0.7}{60} v^2 = 0.00525v^2[/tex]
Josh:
[tex] \frac{0.6 * 0.7}{90} v^2 = 0.00467v^2[/tex]

The negative impact on Amy is larger than on Josh.
Final answer:

Amy experiences less air resistance due to her smaller cross-sectional area compared to Josh, but as she has a lower mass, the air resistance has a more significant effect on her, making her more affected by air resistance.

Explanation:

To determine which cyclist, Amy or Josh, is more affected by air resistance, we can examine the force due to air resistance, which can be calculated using the formula:

Fd = (1/2)ρCdAv2

where Fd is the force of drag (air resistance), ρ is the air density (which we'll assume to be constant for both cyclists), Cd is the drag coefficient, A is the cross-sectional area, and v is the velocity.

Given that both cyclists have the same drag coefficient (Cd = 0.70) and are traveling at the same velocity (v = 15 m/s), the only variables that differ between the two are their cross-sectional areas. Since Amy has a smaller mass and a smaller cross-sectional area (A = 0.45 m2), the force of air resistance will be smaller in magnitude compared to Josh's due to his larger cross-sectional area (A = 0.60 m2).

However, air resistance's impact on an object is also related to the object's mass. A smaller force applied to a smaller mass can have a more significant effect than the same force applied to a larger mass. Therefore, even if the force of air resistance is absolutely higher for Josh, Amy, with her lower mass, would be more affected by it, as it would constitute a more substantial proportion of her total mass.

A raft is made of a plastic block with a density of 650 kg/m 3 , and its dimensions are 2.00 m à 3.00 m à 5.00 m. 1. what is the volume of the raft? _________________________________________________________________ 2. what is its mass? _________________________________________________________________ 3. what is its weight? _________________________________________________________________ 4. what is the raft's ap parent weight in water? (hint: density of water = 1.00 à 10 3 kg/m 3 ) _________________________________________________________________ 5. what is the buoyant force on the raft in water? _________________________________________________________________ 6. what is the mass of the displaced water? _________________________________________________________________ 7. what is the volume of the displaced water? _________________________________________________________________ 8. how much of the raft's volume is below water? how much is above? _________________________________________________________________ 9. answer items 5 â 8 using ethanol (density = 0.806 à 10 3 kg/m 3 ) instead of water.

Answers

1) The volume of the raft is the product between the lenghts of its three dimensions:
[tex]V = (2.00 m)(3.00m)(5.00m)=30 m^3[/tex]

2) The mass of the raft is the product between its density, d, and its volume, V:
[tex]m=dV=(650 kg/m^3)(30 m^3)=19500 kg[/tex]

3) The weight of the raft is the product between its mass m and the gravitational acceleration, [tex]g=9.81 m/s^2[/tex]:
[tex]W=mg=(19500 kg)(9.81 m/s^2)=1.91 \cdot 10^5 N[/tex]

4) The apparent weight is equal to the difference between the weight of the raft and the buoyancy (the weight of the displaced fluid):
[tex]W_a = W- \rho_W V_{disp} g[/tex]
where [tex]\rho _W = 1000 kg/m^3[/tex] is the water density and [tex]V_{disp}[/tex] is the volume of displaced fluid.
The density of the raft ([tex]650 kg/m^3[/tex]) is smaller than the water density ([tex]1000 kg/m^3[/tex]), this means that initially the buoyancy (which has upward direction) is larger than the weight (downward direction) and so the raft is pushed upward, until it reaches a condition of equilibrium and it floats. At equilibrium, the weight and the buoyancy are equal and opposite in sign:
[tex]W=B=\rho _W V_{disp} g[/tex]
and therefore, the apparent weight will be zero:
[tex]W_a = W-B=W-W=0[/tex]

5) The buoyant force B is the weight of the displaced fluid, as said in step 4):
[tex]B=\rho_W V_{disp} g[/tex]
When the raft is completely immersed in the water, the volume of fluid displaced [tex]V_{disp}[/tex] is equal to the volume of the raft, [tex]V_{disp}=V[/tex]. Therefore the buoyancy in this situation is
[tex]B= \rho_W V g = (1000 kg/m^3)(30 m^3)(9.81 m/s^2)=2.94 \cdot 10^5 N[/tex]
However, as we said in point 4), the raft is pushed upward until it reaches equilibrium and it floats. At equilibrium, the buoyancy will be equal to the weight of the raft (because the raft is in equilibrium), so:
[tex]B=W=1.91 \cdot 10^5 N[/tex]

6) At equilibrium, the mass of the displaced water is equal to the mass of the object. In fact, at equilibrium we have W=B, and this can be rewritten as
[tex]mg = m_{disp} g[/tex]
where [tex]m_{disp}= \rho_W V_{disp}[/tex] is the mass of the displaced water. From the previous equation, we obtain that [tex]m_{disp}=m=19500 kg[/tex].

7) Since we know that the mass of displaced water is equal to the mass of the raft, using the relationship [tex]m=dV[/tex] we can rewrite [tex]m=m_{disp}[/tex] as:
[tex]d V =d_W V_{disp}[/tex]
and so
[tex]V_{disp}= \frac{d V}{d_W}= \frac{(650 kg/m^3)(30m^3)}{1000kg/m^3}= 19.5 m^3 [/tex]

8) The volume of water displaced is (point 7) [tex]19.5 m^3[/tex]. This volume is now "filled" with part of the volume of the raft, therefore [tex]19.5 m^3[/tex] is also the volume of the raft below the water level. We can calculate the fraction of raft's volume below water level, with respect to the total volume of the raft, [tex]30 m^3[/tex]:
[tex] \frac{19.5 m^3}{30 m^3}\cdot 100= 65 \% [/tex]
Viceversa, the volume of raft above the water level is [tex]30 m^3-19.5 m^3 = 10.5 m^3[/tex]. Therefore, the fraction of volume of the raft above water level is
[tex] \frac{10.5 m^3}{30 m^3}\cdot 100 = 35 \% [/tex]

9) Let's repeat steps 5-8 replacing [tex]\rho _W[/tex], the water density, with [tex]\rho_E=806 kg/m^3[/tex], the ethanol density.

9-5) The buoyant force is given by:
[tex]B=\rho _E V_{disp} g = (806 kg/m^3)(30 m^3)(9.81 m/s^2)=2.37 \cdot 10^5 N[/tex]
when the raft is completely submerged. Then it goes upward until it reaches equilibrium and it floats: in this condition, B=W, so the buoyancy is equal to the weight of the raft.

9-6) Similarly as in point 6), the mass of the displaced ethanol is equal to the mass of the raft: 
[tex]m_E = m = 19500 kg[/tex]

9-7) Using the relationship [tex]d= \frac{m}{V} [/tex], we can find the volume of displaced ethanol:
[tex]V_E = \frac{m}{d_E} = \frac{19500 kg}{806 kg/m^3}=24.2 m^3 [/tex]

9-8) The volume of raft below the ethanol level is equal to the volume of ethanol displaced: [tex]24.2 m^3[/tex]. Therefore, the fraction of raft's volume below the ethanol level is 
[tex] \frac{24.2 m^3}{30 m^3}\cdot 100 = 81 \% [/tex]
Consequently, the raft's volume above the ethanol level is 
[tex]30 m^3 - 24.2 m^3 = 5.8 m^3[/tex]
and the fraction of volume above the ethanol level is
[tex] \frac{5.8 m^3}{30 m^3}\cdot 100 = 19 \% [/tex]

Physical changes (2 points)

are only caused through burning a material

cannot be detected by the naked eye

do not change the identity of the substance

change the identity of a substance

Answers

Physical changes do not change the identity of the substance. Heat causes chemical reactions. You cannot see chemical changes with the naked eye. The identity of a substance changes like when you burn paper, from paper it turns into ash and produces smoke, which are products from the chemical reactions. 

rapid energy transfer between ____ and ____ energy make roller coasters thrilling

Answers

Hello there!

The answer is the following:

Rapid energy transfer between Potential and Kinetic energy makes roller coasters thrilling. 

Potential Energy is the energy related to the vertical position of the roller coaster cart. When it is at the highest point, the Potential Energy is at a maximum. 

Kinetic Energy is the energy related to the speed of the roller coaster cart. When the cart is at the highest point, the kinetic energy is at a minimum, but as it begins to go down, the Potential Energy is transformed into Kinetic Energy, making the cart to increase its speed and making it a thrilling experience. 

24 g of water is heated from 25 c to 35
c. how much heat energy was required

Answers

If you were to rase to temperature 10c and the heat energy required to rase it 1 c is 4190 j/(kg C). 24g • 4190 j/(kg C) • (35-25)C 24 • 4190 • 10= 1,005,600 j or 1.5 MJ

The heat energy required is approximately 1000 calories (or 4184 joules).

To calculate the heat energy required, we can use the formula:

Q = mcΔT

where:

Q = heat energy (in calories or joules)

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in cal/g°C or J/g°C)

ΔT = change in temperature (in °C)

For water, the specific heat capacity is approximately 1 cal/g°C or 4.184 J/g°C.

Given that the mass of water (m) is 24 grams, and the change in temperature (ΔT) is 35°C - 25°C = 10°C, we can plug the values into the formula:

Q = (24 g) * (1 cal/g°C) * (10°C)

Q ≈ 240 calories

Since 1 calorie is approximately 4.184 joules, the heat energy required in joules is:

Q ≈ 240 calories * 4.184 J/cal

Q ≈ 1004.16 joules

So, approximately 1000 calories (or 1004.16 joules) of heat energy were required to heat 24 grams of water from 25°C to 35°C.

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14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?

Answers

The relationship between resistance R and resistivity [tex]\rho[/tex] is
[tex]R= \frac{\rho L}{A} [/tex]
where L is the length of the wire and A its cross section.

The radius of the wire is half the diameter:
[tex]r= \frac{d}{2}= \frac{1.6 mm}{2}=0.8 mm=8\cdot 10^{-4} m [/tex]
and the cross section is
[tex]A=\pi r^2 = \pi (8\cdot 10^{-4} m)^2=2.01\cdot 10^{-6} m^2[/tex]

From the first equation, we can then find the length of the wire when [tex]R=4.8 \Omega[/tex] (copper resistivity: [tex]\rho = 1.724 \cdot 10^{-8} \Omega m[/tex])
[tex]L= \frac{AR}{\rho}= \frac{(2.01\cdot 10^{-6} m^2)(1.724 \cdot 10^{-8} \Omega m)}{4.8 \Omega}=7.21 \cdot 10^{-15} m [/tex]

A proton is fired from far away toward the nucleus of a mercury atom. mercury is element number 80, and the diameter of the nucleus is 14.0 fm. part a if the proton is fired at a speed of 3.4×107 m/s , what is its closest approach to the surface of the nucleus? assume the nucleus remains at rest. express your answer to two significant figures and include the appropriate units.

Answers

The initial kinetic energy of the proton is given by:
[tex]K= \frac{1}{2} mv^2[/tex]
where [tex]m=1.67\cdot 10^{-27}kg[/tex] is the proton mass and [tex]v=3.4\cdot 10^7 m/s[/tex] is the initial speed.

As the proton approaches the nucleus, it decelerates because of the repulsive electric field and its kinetic energy converts into electric potential energy. The proton will stop at a distance r from the center of the nucleus, and its potential energy at this distance will be:
[tex]U=k_e \frac{(80e)(e)}{r} [/tex]
where [tex]k_e = 8.99\cdot 10^9 N m^2 C^{-2}[/tex], 80e is the charge of the nucleus of mercury (which contains 80 protons), and [tex]e=1.6\cdot 10^{-19}C[/tex] is the proton charge.

For the conservation of energy,
[tex]K=U[/tex]
Rewriting it, we find
[tex]r=2k_e \frac{(80e)(e)}{mv^2}=3.4 \cdot 10^{-15} m =34 fm [/tex]

This is not the final answer, however, because this is the distance reached by the proton with respect to the center of the nucleus. So, to find the distance from the surface, we should subtract the radius of the nucleus, which is half the diameter: 14/2=7 fm. So
[tex]d=r-r_0=34 fm-7 fm=27 fm =2.7 \cdot 10^{-15 } m[/tex]

Answer:

[tex]27fm[/tex]

Explanation:

Kinetic Energy of proton

[tex]Kinetic Energy (K)=\frac{1}{2}mV^{2}[/tex]

[tex]m=Mass of proton[/tex]

[tex]V=Velocity of proton[/tex]

[tex]m=1.67\times 10^{-27} kg[/tex]

[tex]V=3.4\times 10^{7}ms^{-1}[/tex]

[tex]K=\frac{1}{2}\times 1.67\times 10^{-27}kg\times \left (3.4\times 10^{7}ms^{-1}  \right )^2[/tex]

[tex]K=\frac{19.305}{2}\times 10^{-13}J[/tex]

[tex]K=9.65\times 10^{-13}J[/tex]

For conservation of energy;

[tex]Kinetic Energy=Potential energy[/tex]

[tex]K= U[/tex]

So,

[tex]U= 9.65\times 10^{-13}J[/tex]

Here,

[tex]U=Potential Energy[/tex]

[tex]U=k_{e}\frac{q_{1}q_{2}}{r}[/tex]

Here,

[tex]k_{e}=Coulomb's law constant[/tex]

[tex]k_{e}=8.99\times 10^{9}Nm^{2}C^{-2}[/tex]

[tex]q_{1}=80e[/tex]

[tex]q_{2}=e[/tex]

[tex]e=1.602\times 10^{-19}C[/tex]

[tex]r=The distance that proton will stop from the center of the nucleus[/tex]

[tex]U=k_{e}\frac{80e\times e}{r}[/tex]

[tex]9.65\times 10^{-13}J=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{r}[/tex]

[tex]r=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{9.65\times 10^{-13}J}[/tex]

[tex]34fm[/tex]

[tex]r_{0}=Radius of the atom[/tex]

[tex]Radius\left ( r_{0} \right )=\frac{diameter\left ( d \right )}{2}[/tex]

[tex]Diameter of the nucleus of mercury atom=14fm[/tex]

[tex]Radius of atom =\frac{14fm}{2}[/tex]

[tex]r=7fm[/tex]

[tex]d=r-r_{0}[/tex]

[tex]d=34fm-7fm[/tex]

[tex]d=27fm[/tex]

Further Explanation:

When a proton approaches a nucleus, it decelerates. Because the repulsive electric field and its kinetic energy converts into electric potential energy.  

Then due to this, the proton will stop at a distance “r” from the center of the nucleus.  

To find the distance from the surface where the proton hits, we have to subtract the radius of the nucleus.  

Learn more:

1. Kinetic energy https://brainly.com/question/1621817 (answer by skyp)

2. Potential energy https://brainly.com/question/12489105 (answer by nitrotype2000)

3. Conservation of energy https://brainly.com/question/11911812 (answer by hrishisup)

Keywords:

Kinetic energy, potential energy, conservation of energy.  

A uniform rod XY of weight 10.0N is freely hinged to a wall at X. It is held horizontal by a force F acting from Y at an angle 30° to the horizontal, as shown.

What is the value of F?
A- 5.0 N B- 8.7cm C- 10.0cm D-20.0cm

Answers

In order to solve the problem, we must require the equilibrium of all the torques acting on the rod. The fixed point is in X, so we have:
- The weight of the rod (mg) acting at the center of the rod (so, at a distance L/2 from X, where L is the length of the rod). So, the torque is 
[tex]T_W = mg \frac{L}{2} [/tex]
- The vertical component of F (so, [tex]F \sin 30^{\circ}[/tex]) applied in Y, so at a distance L from X. Its torque is
[tex]F \sin 30^{\circ} L[/tex]

The weight points downwards (so, the torque is clockwise), while the torque of F points anti-clockwise, so the equilibrium of torques is
[tex]F \sin 30^{\circ} L = mg \frac{L}{2} [/tex]
and since the weight is mg=10 N, re-arranging the equation we find
[tex]F = \frac{10 N}{2 sin 30^{\circ}} = 10 N[/tex]

The value of the horizontal force acting on the rod is 10 N. Therefore option (C) is correct.:

Given data:

The weight of rod is, W = 10.0 N.

The angle made by force with respect to horizontal is, [tex]\theta = 30^\circ[/tex].

To maintain the steady position (equilibrium condition), the vertical component of force F must be balanced by the moment of force due to weight.

Therefore,

[tex](Fsin\theta) \times L = W \times \dfrac{L}{2} \\\\(F \times sin30^{\circ}) = \dfrac{10}{2} \\F = 10 \;\rm N[/tex]

Thus, the value of the horizontal force acting on the rod is 10 N. And option (C) is correct.

Learn more about the equilibrium of forces here:

https://brainly.com/question/3876381?referrer=searchResults

A piston-cylinder system contains of 3 kg of saturated mixture of water at 160 kpa. initially, water is in liquid phase. heat is now transferred to the water and the piston, which is at the stop, start moving when the pressure reaches 500 kpa. heat transfer continues until the total volume increases by %20. determine,
a.the initial and final temperature,
b.the mass of liquid when the piston first starts moving, and
c.the work done during this proce

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - https://brainly.com/question/1581851#readmore

13) A branch falling from a tree is to gravity as a car driving on the road is to A) a driver's foot off of the accelerator, coasting. B) a driver's foot off the accelerator and on the break pedal. C) a driver's foot on the accelerator pressed down to maintain speed. D) a driver's foot on the accelerator and pressed down gradually more and more.

Answers

a driver's foot off the accelerator and on the break pedal. C

Its D: A driver's foot on the accelerator and pressed down gradually more and more.

Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a)if a sample of gold with a mass of 7.583 g, is pressed into a leaf of 3.061 μm thickness, what is the area (in m2) of the leaf? (b)if, instead, the gold is drawn out into a cylindrical fiber of radius 2.500 μm, what is the length (in m) of the fiber?

Answers

(a) First of all, let's convert the gold's density into appropriate units:
[tex]d=19.32 g/cm^3 = 19320 kg/m^3[/tex]
and the mass as well:
[tex]m=7.583 g=7.583 \cdot 10^{-3} kg[/tex]
From density and mass, we can find the volume of the leaf, V:
[tex]V= \frac{m}{d}= \frac{7.583 \cdot 10^{-3} kg}{19320 kg/m^3} =3.9\cdot 10^{-7}m^3[/tex]
We know that the thickness is [tex]d=3.061 \mu m=3.061 \cdot 10^{-6} m[/tex], and the volume is the product between the thickness and the area: [tex]V=A d[/tex], so we can find the area:
[tex]A= \frac{V}{d}= \frac{3.9\cdot 10^{-7}m^3}{3.061 \cdot 10^{-6} m} =0.127 m^2[/tex]

(b) The radius of the cylinder is [tex]r=2.5 \mu m=2.5 \cdot 10^{-6} m[/tex], therefore its area is
[tex]A=\pi r^2 = 1.96\cdot 10^{-11} m^2[/tex]
For a cylinder, the volume is the product between the length L and the area A: V=AL, therefore we can find the length L (the volume is the one calculated at the previous step):
[tex]L= \frac{V}{A} = \frac{3.9\cdot 10^{-7}m^3}{1.96\cdot 10^{-11} m^2} =1.99\cdot 10^4 m[/tex]

Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.

Answers

Let's call [tex]C_{eq}[/tex] the equivalent capacitance of the circuit. The relationship between the  capacitance, the charge Q in the circuit and the potential difference V applied on the capacitor is
[tex]C_{eq}= \frac{Q}{V} [/tex]
Using [tex]Q=3.5 \cdot 10^{-4}C[/tex] and [tex]V=5.55 V[/tex], we find
[tex]C_{eq}= \frac{3.5 \cdot 10^{-4}C}{5.5 V} =6.4 \cdot 10^{-5}F[/tex]

In reality, the circuit consists of 3 capacitors in parallel, each one having same capacitance C. When 3 capacitors are connected in parallel, their equivalent capacitance is:
[tex]C_{eq}=C+C+C=3C[/tex]
We know [tex]C_{eq}[/tex], so we can find C:
[tex]C= \frac{C_{eq}}{3}= \frac{6.4 \cdot 10^{-5}F}{3} =2.1 \cdot 10^{-5}F [/tex]

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

The capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].

What is equivalent capacitance of parallel series?

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

It can be given as,

[tex]C_{eq}=\dfrac{Q}{V}[/tex]

Here, [tex]Q[/tex] is the charge and [tex]V[/tex] is the voltage.

Given information-

The voltage of the battery is 5.55 V.

The value of charge is [tex]3.45\times10^{-4}[/tex] C.

Put the values in the above formula as,

[tex]C_{eq}=\dfrac{3.45\times10^{-4}}{5.55}\\C_{eq}=6.4\times10^{-4}\rm F[/tex]

Given that the three uncharged capacitors with equal capacitance are combined in parallel.

For the parallel connection of the capacitance the equivalent capacitance can be given as,

[tex]C_{eq}=C+C+C[/tex]

Here, [tex]C[/tex] is the capacitance of each capacitors. Put the values,

[tex]6.4\times10^{-4}\rm =3C\\C=2.1\times10^{-5}\rm F[/tex]

Hence the capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].

Learn more about the equivalent capacitance here;

https://brainly.com/question/5626146

When photons with a wavelength of 310 nm strike a magnesium plate the maximum velocity of the ejected electrons is 3.45*10^5 m/s. calculate the binding?

Answers

Given that the work function for sodium metal is 1.82 eV, what is the threshold frequency? 0. 1. 1. 0. 1. 1. 34. • When photons with a wavelength of 310 nm strike a magnesium plate, the maximum velocity of the ejected electrons is 3.45x10. 5 m/s. Calculate the binding energy of electrons to the magnesiumsurface. 1. 2. 2 +. 1.

A brick is dropped from 100m up. Find it's impact velocity and air time.

Answers

the airtime is 9.8
the velocity is 0

This back-and-forth movement of electrons is called . In contrast, the movement of electrons in one direction in a battery circuit is called .

Answers

the back-and-forth movement of electrons is called alternating current. Electrons go back and forth, the direction of their path alternates from one direction to another.

the movement of electrons in one direction is called direct current. The electrons move in a direct, single path without changing directions.

Final answer:

The back-and-forth movement of electrons is called alternating current (AC), and the unidirectional flow in a battery circuit is known as direct current (DC). DC moves from the negative to the positive terminal of a battery, driven by the terminal voltage. The concept of conventional current assumes the flow of positive charges from positive to negative terminal.

Explanation:

The back-and-forth movement of electrons is called alternating current (AC). In contrast, the movement of electrons in one direction in a battery circuit is called direct current (DC).

When electrons move from a low-potential terminal (negative end) through a conductor, such as a wire, and enter a high-potential terminal (positive end) of a battery, this consistent unidirectional flow forms a DC. This is differ from AC, where the movement of electric charge periodically reverses direction. Electricity produced by batteries is a form of DC, and this is why it has definite positive and negative terminals.

The terminal voltage or electromotive force (emf) of a battery drives the flow of electrons, producing electric current. In metal wires, conventional current is carried by the flow of electrons which are negatively charged. However, conventional current is treated as if positive charges move from the positive to the negative terminal, reflecting historical conventions established before the discovery of the electron.

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