Evaluate 10m + n2/4 when m = 5 and n = 4

Answers

Answer 1

Answer:

[tex]54[/tex]

Step-by-step explanation:

we have

[tex]10m+\frac{n^{2}}{4}[/tex]

For [tex]m=5.n=4[/tex]

substitute the values of m and the value of n in the equation

so

[tex]10(5)+\frac{4^{2}}{4}[/tex]

[tex]50+4[/tex]

[tex]54[/tex]

Answer 2

Answer:54

Step-by-step explanation:


Related Questions

line L1, L2 and L3 are in the same plane, L1 is perpendicular to L2, and L3 is parallel to L1. which of the following statement must be true?

1. L3 is parallel to L2
2.L3 is perpendicular to L2
3.L3 intersects L2

Answers

Only Statement 2 is surely correct.
because there maybe chances that the line L1 and L3 lies above the line L2 and they can also fulfill the condition of perpendicularity so we can't be sure about statement 3 & statement 1 is clearly incorrect

The true statement will be

1. ''L3 is perpendicular to L2''

What is Parallel lines?

Parallel lines are straight lines that do not intersect at any point.

Given that;

Line L1, L2 and L3 are in the same plane,

L1 is perpendicular to L2, and L3 is parallel to L1.

Now,

Line L1 is perpendicular to L2.

And, L3 is parallel to L1.

Then, Line L3 is perpendicular to line L2

Thus, The true statements will be

1. ''L3 is perpendicular to L2'' and

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Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.
PLEASE HELP ASAP!! NEED NOW! THANKS!

Answers

y=-4/3x+300  i  hope this helps you

y=-4/3x+300  i  hope this helps you


Find the distance between the points (
-
10,12) and (15,12).

Answers

The distance formula is:

[tex]d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} [/tex]

We are given two points in the form (x,y), so plug in the values to the distance formula:

[tex]d= \sqrt{(-10-15)^2-(12-12)^2} [/tex]

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

[tex]d= \sqrt{(-25)^2} [/tex]

The square and square root cancel each other out leaving us with 25.

The answer is 25.


select true statements. (-10x^(2)+5x+3)/(2x^(2)+4)

Answers are
The numerator has 3 terms
The denominator includes a coefficient of 4
The denominator includes a coefficient of 2
The numerator has 2 terms
The numerator includes a coefficient of 3

Answers

The correct answers for the exercise shown above, are:

 - The numerator has 3 terms:

 the first term is:-10x^2
 the second term is: 5x
 the third term is: 3

 - The denominator includes a coefficient of 4:

 2x^2+4

 - The denominator includes a coefficient of 2:

  2x^2+4

 - The numerator includes a coefficient of 3:

 -10x^2+5x+3

Answer: True statements::    The numerator has 3 terms; The denominator includes a coefficient of 2.


Step-by-step explanation:


What is the probability of flipping a coin and it coming up heads four times in a row

Answers

In a single toss, the probability that the result of the toss is head is 1/2:
[tex]P_1 (head) = \frac{1}{2} [/tex]

For 2 tosses in a row, the probability that the result is head in both tosses is
[tex]P_2 = P_1 \cdot P_1 = ( \frac{1}{2} )( \frac{1}{2} )= \frac{1}{4} [/tex]

If we continue, we find that the probability to have 4 heads in 4 consecutive tosses is given by
[tex]P_4 = ( P_1 (head) )^4 = ( \frac{1}{2} )^4 = \frac{1}{16} [/tex]

Lisa drove 40 3/5 miles in one hour. At the same speed in how many hours could she drive in 121 4/5

Answers

She would drive c 3 hours
Hello!

[tex]\bf Answer:[/tex]

Lisa can drive 121 4/5 miles in [tex]\boxed{ \rm C.~3~hours}[/tex].

40 3/5 = 40.6

121 4/5 = 121.8

121.8 ÷ 40.6 = 3

Toysrus is having a 38% off sale. If a backpack normally costs $22, how much will it cost on sale

Answers

it will be 13.64. it is bc 38% of 22 is 8.36 and 22-8.36=13.64

The backpack will cost $13.64 during the 38% off sale at Toysrus, calculated by subtracting the discount ($8.36) from the original price ($22).

To calculate the discount amount, we multiply the original price by the discount percentage:

$22 * 0.38 = $8.36

Now, to get the sale price, we subtract the discount amount from the original price:

$22 - $8.36 = $13.64

Therefore, the backpack will cost $13.64 on sale.

Find the first term, a1, of an arithmetic sequence if a12 = 38 and a45 = 170.
–6

132/33

–5

6

Answers

Standard formula for arithmetic sequence:
an = a0 + d(n-1)

if we use the two terms given, setting a12 as starting term and a45 as the end term an.

170 = 38 + 33d 
170 - 38 = 33d
132 = 33d

132/33 = d
This is the common difference, use it to find the first term.

38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0

The starting term is -6

The solution is: The starting term is -6

What is Arithmetic progression?

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Standard formula for arithmetic sequence:

an = a0 + d(n-1)

if we use the two terms given, setting a12 as starting term and a45 as the end term an.

170 = 38 + 33d 

170 - 38 = 33d

132 = 33d

132/33 = d

This is the common difference, use it to find the first term.

38 = a0 + (132/33)(12-1)

38 = a0 + (132/33)(11)

38 = a0 + 132/3

38 - 132/3 = a0

38 - 44 = a0

-6 = a0

The starting term is -6

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use similar triangles to solve. a person who is 5 feet tall is standing 140 ft from the base of a tree and the tree cast a 154 foot shadow. the person's Shadow is 14 ft in length what is the height of the tree

Answers

For this case we have the following relationship using similarity of triangles:
 (x / 154) = (5/14)
 Clearing the value of x we have:
 x = (5/14) * (154)
 Rewriting we have:
 x = 55 feet
 Answer:
 
the height of the tree is:
 
x = 55 feet
To find the height of the tree, you can create a proportion with the information that is given and solve for the height.

Heights:                x              5 feet
Base Lengths:    154 feet      14 feet

14x = 770
14       14
x = 55 feet

The height of the tree is 55 feet.

describe the steps you would use to factor 2x ^ 3 + 5x ^ 2 - 8x - 20 completely then State the factored form. this isn't multiple choice btw

Answers

Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0

You see that the term will be 0 for x = 2

(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0

You can use the abc-formula to solve the quadratic equation.

x = -2.5 ∨ x = -2

So the factored form will be

2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0


You see that the term will be 0 for x = 2


(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0


You can use the abc-formula to solve the quadratic equation.


x = -2.5 ∨ x = -2


So the factored form will be


2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


This is a function whose domain is a set of consecutive integers. They are finite and infinite.

Answers

The set of consecutive integers are:

[tex]z = \{...,-3, -2, -1, 0, +1, +2, +3,...\}[/tex]

If the function is finite, then there are two values [tex]a[/tex] and [tex]b[/tex], being [tex]a\ \textless \ b[/tex], in which this function is valid, then:

[tex]f(x) = x[/tex]
being [tex]x [/tex] the set of integers in the interval defined by [tex](a,b)[/tex]

If the function is infinite, the function is valid in the set of all integers then:

[tex]f(x) = x[/tex]
And -∞[tex]<x<[/tex]+∞ 

Answer:

the answer is sequence (usa test prep)

Step-by-step explanation:

What is the slant height x of this square pyramid? The figure shows a square pyramid. The slant height is shown as a dashed line perpendicular to the base edge and is labeled as x. The length of the lateral edge is 4 meters. The lateral edge makes a 60 degree angle with the base edge. Enter your answer in the box. Express your answer in radical form.

Answers

The side adjacent to the 60° angle in the right triangle consisting of x, the lateral edge, and half the base edge is half the base edge, 2 m. The side opposite that angle is x. Thus you have
  tan(60°) = x/(2 m)
  (2 m)*tan(60°) = x = 2√3 m

The slant height is 2√3 meters.

Based on the information given, it should be noted that the slant height will be 2✓3 meters.

From the information given, the slant height is shown as a dashed line perpendicular to the base edge and is labeled as x as the length of the lateral edge is 4 meters and the lateral edge makes a 60 degree angle with the base edge.

Therefore, the calculation of the slant height goes thus:

Tan 60° = x/2

x = 2 × tan 60°

x = 2 × ✓3

x = 2✓3

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helppppp picture included

Answers

They dont represent proportional relationship!
but what are the drop down answers?

The home of Russell Slater is assessed at $140,000. The tax rate is 11.8 mills. The actual amount of tax on Russell's home is:


$1,652


$1,462


$1,362


None of these


$1,562

Answers

number 3 is right i think

you have a part-time job that pays $4.75 an hour with tips allergy $4 and fifty an hour your deductions are fic a 7.65% federal tax withholding 12.5% in state tax withholding 6.85 % you work 20 hours per week you want to save $40 a week how much left in your discretionary income per week soon that all the income from your part time job is discretionary and the next one is

You decide to save 15% of your realized income how much do you save per month?

Answers

I do believe that the answer is 27.75 if I have the correct definition of what the realized income is.

if 7 out of 8 people use crust toothpaste, how many use this product in a city with a population of 40,000?

Answers

Since 7 out of 8 people use crust toothpaste, in a city with the population of 40,000, 87.5% of the people use crust. so 40,000*87.5%= 35,000. 

If output per worker is now nearly $120,000 per year, how much will the average worker produce 5 years from now if productivity improves by (use the compounding formula below to answer the question): fv1 = p(1 + r), fv2 = p(1 + r)(1 + r), fv3 = p(1 + r)(1 + r)(1 + r)… instructions: enter your responses rounded to two decimal places. (a) 2 percent per year? $ (b) 3 percent per year? $

Answers

 It takes Jane 1 hour to make a necklace and 45 minutes to make a bracelet. As If output per worker is now nearly $120,000 per year, how much will the average worker produce 5 years from now if productivity improves by (use the compounding formula below to answer the question) answer.

priority question

The dot plots below show the test scores of sixth- and seventh-grade students: Dot plot for Grade 6 shows 6 dots on score 70, 4 dots on score 80, 6 dots on score 90, and 4 dots on score 100. Dot plot for Grade 7 shows 5 dots on score 50, 7 dots on score 60, 4 dots on score 70, and 4 dots on score 80. Based on visual inspection of the dot plots, which grade, if any, appears to have the higher mean score? Grade 6 Grade 7 Both groups show about the same mean score. No conclusion about mean score can be made from the data.

Answers

Sixth grade:
7 | x x x x x x
8 | x x x x
9 |x x x x x x
A | x x x x . . . . . . . . where "A" is used to represent 10 tens (100)

7th grade:
5 | x x x x x
6 | x x x x x x x
7 | x x x x
8 | x x x x

The range (low, high) and median of the 6th grade scores are all higher than those of the 7th grade scores.

Based on visual inspection, Grade 6 appears to have the higher mean score.

Answer:

Grade 6 i think

Consider the differential equation dy/dx = 1/3x(y-2)^2.

(a) A slope field for the given differential equation is shown below. Sketch the solution curve that passes through the point (0, 2), and sketch the solution curve that passes through the point (1, 0).

(b) Let y = f(x) be the particular solution to the given differential equation with initial condition f(1) = 0. Write an equation for the line tangent to the graph of y = f(x) at x = 1. Use your equation to approximate f(0.7).

(c) Find the particular solution y = f(x) to the given differential equation with initial condition f(1) = 0.

(This was on the no-calculator section of the recently-released AP Calculus AB 2018 exam so I appreciate it if you tried to limit calculator usage)

Answers

a) Judging by the slope field, it would appear the solution passing through (0, 2) would just be the line [tex]y=2[/tex]. This holds up for the given ODE, since if [tex]y(x)=2[/tex], then both sides of the ODE reduce to 0.

Since we can surmise that [tex]y=2[/tex] is an equilibrium for this ODE (that is, the derivative along this line is 0 everywhere), and the slope at (1, 0) is positive, we know that as [tex]x\to+\infty[/tex], the function [tex]y(x)[/tex] will converge to 2. In other words, as [tex]x[/tex] gets larger, the slope field suggests that the solution curve through (1, 0) will start to plateau and steadily approach [tex]y=2[/tex]. On the other hand, as [tex]x\to-\infty[/tex], the slope field tells us that the curve would rapidly diverge off to [tex]-\infty[/tex]. (When you actually draw the solution, you would end up with something resembling the plot of [tex]-e^{-x}[/tex].)

b) The tangent line to [tex]y=f(x)[/tex] at [tex]x=1[/tex], given that [tex]f(1)=0[/tex], takes the form

[tex]\ell(x)=f(1)+f'(1)(x-1)[/tex]
[tex]\ell(x)=f'(1)(x-1)[/tex]

When [tex]x=1[/tex], we have [tex]y=0[/tex], so

[tex]f'(1)=\dfrac13\cdot1\cdot(0-2)^2=\dfrac43[/tex]

and so the tangent line to [tex]f(x)[/tex] at [tex]x=1[/tex] is

[tex]\ell(x)=\dfrac43(x-1)[/tex]

Using the tangent line as an approximation, we would find

[tex]f(0.7)\approx\ell(0.7)=\dfrac43\left(\dfrac7{10}-1\right)=-\dfrac4{10}=-0.4[/tex]

c) The ODE is separable, so we can write

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac13x(y-2)^2\iff\dfrac{\mathrm dy}{(y-2)^2}=\dfrac x3\,\mathrm dx[/tex]

Integrating both sides gives us

[tex]-\dfrac1{y-2}=\dfrac{x^2}6+C[/tex]

Given that [tex]y(1)=0[/tex], we get

[tex]-\dfrac1{0-2}=\dfrac{1^2}6+C\implies C=\dfrac13[/tex]

so the particular solution is

[tex]-\dfrac1{y-2}=\dfrac{x^2}6+\dfrac13[/tex]

You're asked to find the solution in the form [tex]y=f(x)[/tex], so you should solve for [tex]y[/tex]. You would end up with

[tex]y=-\dfrac6{x^2+2}+2=\dfrac{2(x^2-1)}{x^2+2}[/tex]
Final answer:

To sketch the solution curves passing through (0, 2) and (1, 0), we can use the slope field provided. The tangent line to y = f(x) at x = 1 can be found by taking the derivative of f(x) and substituting x = 1. We can find the particular solution to the differential equation by integrating it with the given initial condition f(1) = 0.

Explanation:(a) Solution curves through (0, 2) and (1, 0)

To sketch the solution curves, we can use the slope field provided. For the point (0, 2), the slope is 1/3(0)(2-2)^2 = 0. Thus, at (0, 2) the solution curve is horizontal. For the point (1, 0), the slope is 1/3(1)(0-2)^2 = 8/3. Thus, at (1, 0) the solution curve is directed upwards with a slope of 8/3.

(b) Tangent line at (1, 0) and f(0.7)

Since f(1) = 0, we already know that the point (1, 0) lies on the graph of y = f(x). The equation of the tangent line to y = f(x) at x = 1 can be found by finding the derivative of f(x) and substituting x = 1. In this case, the derivative is dy/dx = 1/3x(y-2)^2, so at x = 1, we have dy/dx = 1/3(1)(0-2)^2 = -8/3. Therefore, the equation of the tangent line is y - 0 = (-8/3)(x - 1), which simplifies to y = -8/3(x-1). To approximate f(0.7), we can substitute x = 0.7 into the equation of the tangent line to get y = -8/3(0.7 - 1) = -8/3(0.3) = -8/10 = -0.8.

(c) Find the particular solution with f(1) = 0

To find the particular solution, we can integrate the differential equation with the given initial condition. Starting with dy/dx = 1/3x(y-2)^2, we can rewrite it as (y-2)^(-2)dy = 1/3xdx. Integrating both sides will give us the equation of the particular solution.

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Mike is looking for a loan. He is willing to pay no more than an effective rate of 8.000% annually. Which, if any, of the following loans meet Mike’s criteria? Loan X: 7.815% nominal rate, compounded semiannually Loan Y: 7.724% nominal rate, compounded monthly Loan Z: 7.698% nominal rate, compounded weekly a. Y only b. X and Z c. Y and Z d. None of these meet Mike’s criteria.

Answers

If Mike is willing to pay no more than an effective rate of 8.000% annually, the loans that meet his criteria are loan X and loan Z. Of those two, the lowest would be loan X.  I hope the answer will help you :)

Answer:

b. X and Z

Step-by-step explanation:

Since, the effective rate is,

[tex]r=(1+\frac{i}{n})^i-1[/tex]

Where, i is the nominal rate,

n is the number of compounding periods,

For loan X,

i = 7.815 % = 0.07815,

n = 2, ( 1 year = 2 semiannual )

Thus, the effective rate would be,

[tex]r=(1+\frac{0.07815}{2})^2-1[/tex]

[tex]=0.079676855625[/tex]

[tex]=7.9676855625\%\approx 7.968\%[/tex]

Since, 7.968 % < 8.000 %,

Loan X meets Mike's criteria,

For loan Y,

i = 7.724 % = 0.07724,

n = 12 ( 1 year = 12 months ),

Thus, the effective rate would be,

[tex]r = ( 1+\frac{0.07724}{12})^{12}-1[/tex]

[tex]=0.0800339518197[/tex]

[tex]=8.00339518197\% \approx 8.003\%[/tex]

Since, 8.003 % > 8.000 %,

Loan Y does not meet his criteria,

For loan Z,

i = 7.698 % = 0.07698,

n = 52 ( 1 year = 52 weeks ),

Thus, the effective rate would be,

[tex]r = (1+\frac{0.07698}{52})^{52}-1[/tex]

[tex]=0.0799589986135[/tex]

[tex]=7.99589986135\%[/tex]

[tex]\approx 7.996\%[/tex]

Since, 7.996 % < 8.000 %,

Loan Z meets his criteria.

Therefore, Option 'b' is correct.

PLEASE HELP!!! REWRITE THE FOLLOWING LINEAR EQUATION IN SLOPE INTERCEPT FORM??

Answers

y=-2x-2 That is the answer
y=-2x-2 you want to use the distributive property on the right side before subtracting four from both sides
y+4=-2(x-1)
y+4=-2x+2
y(-4)=-2x+2(-4)
y=-2x-2

A bag contains 7 blue, 12 red, and 6 orange marbles. Find each probability if you draw one marble at random from the bag. Write as a fraction. a) P (purple)
b) P (red or orange) Please
c)P(not blue) Help

Answers

Total = 7 + 12 + 6 = 25

Purple = 0
Red = 12/25
Orange = 6/25
Blue = 7/25

a. Since there is 0 purple, the answer is 0.
b. 18/25 ( 12/25 + 6/25)
c. 18/25 (Not blue = 25 - 7 = 18)

Hope this helped☺☺

What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point (15, –5)?

Answers

The slope of the perpendicular line is the negative reciprocal of that of the given line, so is
  -1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
  y = (-5/3)(x -15) -5
  y = (-5/3)x +20

The y-intercept of the perpendicular line is y=20.

To win at lotto in a certain state, one must correctly select 6 numbers from a collection of 50 numbers (one through 50). the order in which the selections is made does not matter. how many different selections are possible?

Answers

Number of different selection = 50C6
Number of different selection = 50 x 49 x 48 x 47 x 46 x 45
Number of different selection = 15 890 700

Answer: 15 890 700
The number of possible selections is
  C(50, 6) = 50!/(6!*44!) = 15,890,700

REALY NEED HELP Find an equation of the line passing through the pair of points. Write the equation in the form Ax+By=C. (4,8) and (3,5)

Answers

let
A (4,8) and B (3,5)

step 1
find the slope m
m=(y2-y1)/(x2-x1)---------> m=(5-8)/(3-4)----> m=-3/-1----> m=3

step 2
with m=3 and point B (3,5) find the equation of the line
y-y1=m*(x-x1)-----> y-5=3*(x-3)----> y-5=3x-9----> 3x-y=4

the answer is
the equation in the form Ax+By=C is
 3x-y=4

see the attached figure

the radius of a glass is 1.25 inches. What circumference? use 3.14 for pi

Answers

C=2×3.14×1.25

Answer= 7.85
I think this is the answer.

Find f. f ''(x) = 4 + 6x + 36x2, f(0) = 2, f (1) = 10

Answers

It has been a while since I have done differnetial equations but I think here you only need to integrate twice. 
4 + 6x + 36x^2=  2*(2+3x+18x^2) 

Integrate 2+3x+18x^2 to get 2x+3/2x^2+18/3x^3 +C = 2x +3/2x^2+6x^3 + C
Integrate again now this: 2x +3/2x^2+6x^3 + C to get x^2 + 1/2x^3+3/2x^4 +Cx +D 
Now multiply by two (as I have taken out 2 earlier) 
2x^2+x^3+3x^4+2Cx+D

Now use the initial conditions. 
f(0)=2 
D=2 
f(1)=10
2+1+3+2C+2=10
C=1

So the solution is: (ordered by power, as neat mathematicans would do) 
f(x)= 3x^4 + x^3 + 2x^2 + 2x +2

The function [tex]\( f(x) \)[/tex] is: [tex]\[ f(x) = 2x^2 + x^3 + 3x^4 + 5x + 4 \][/tex]

Given:

[tex]\[ f''(x) = 4 + 6x + 36x^2 \][/tex]

[tex]\[ f(0) = 2 \][/tex]

[tex]\[ f(1) = 10 \][/tex]

1. Integrate [tex]\( f''(x) \)[/tex] to find [tex]\( f'(x) \)[/tex]:

[tex]\[ f'(x) = \int (4 + 6x + 36x^2) \, dx = 4x + 3x^2 + 12x^3 + C_1 \][/tex]

2. Integrate [tex]\( f'(x) \)[/tex] to find [tex]\( f(x) \)[/tex]:

[tex]\[ f(x) = \int (4x + 3x^2 + 12x^3 + C_1) \, dx = 2x^2 + x^3 + 3x^4 + C_1x + C_2 \][/tex]

3. Use the initial condition [tex]\( f(0) = 2 \)[/tex] to find [tex]\( C_2 \)[/tex]:

[tex]\[ 2x^2 + x^3 + 3x^4 + C_1x + C_2 \text{ at } x=0 \][/tex]

[tex]\[ 2 = C_2 \][/tex]

[tex]\[ C_2 = 2 \][/tex]

4. Use the initial condition [tex]\( f(1) = 10 \)[/tex] to find [tex]\( C_1 \)[/tex]:

[tex]\[ f(1) = 2(1)^2 + (1)^3 + 3(1)^4 + C_1(1) + 2 = 10 \][/tex]

[tex]\[ 2 + 1 + 3 + C_1 + 2 = 10 \][/tex]

[tex]\[ 8 + C_1 = 10 \][/tex]

[tex]\[ C_1 = 2 \][/tex]

Thus, the function [tex]\( f(x) \)[/tex] is:

[tex]\[ f(x) = 2x^2 + x^3 + 3x^4 + 5x + 4 \][/tex]

The complete question is:

Find f(x). f ''(x) = 4 + 6x + 36x2, f(0) = 2, f (1) = 10

5.6 times what equals 19.04

Answers

You would have to multiply 5.6 by 3.4 to get 19.04

If the total income generated from gasoline for AER was $408 million how much would be the cost for a barrel of gasoline, gasoline 34% kerosene 14% 60 million barrels total production crude oil

Answers

The problem statement appears to be trying to tell you that 60 million barrels of crude were processed, resulting in 34% of that volume being turned into gasoline, which was then sold for a total of $408 million. You are asked for the revenue associated with 1 barrel of gasoline.

($408·10^6)/(60·10^6 bbl × 0.34) = $408/(20.4 bbl) = $20/bbl

The income from one barrel of gasoline is $20.00.

The correct answer is: $20

Explanation:

As we are interested in finding the cost for a barrel of gasoline, we need to read the percentage of gasoline from the pie-chart first—which is 34%.

Now number of barrels containing gasoline = 34% of 60 million barrels = [tex] \frac{34}{100} * 60 = 20.4 [/tex] million barrels

For all the barrels, the total income is $408 million; therefore, in order to find the per-barrel cost, we need to divide $408 by 20.4:

[tex] \frac{408}{20.4} = \$20 [/tex]

Hence the correct answer is $20.

Eve is replacing the soil in her plant containers. How many cubic inches of soil will Eve need for the two rectangular containers? 
A.45 
B.216
C.648
D.864

Answers

The answer is B, 216in 3.
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