Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the milky way galaxy (which is around 300km/s). suppose the star was actually moving toward the earth at a more reasonable 300km/s. what wavelength λ would the 656.46-nm line move to? use 299,792km/s for the speed of light. express your answer in nanometers to five significant figures.

Answers

Answer 1
According to Doppler Effect, an observer at rest will perceive a shift in the wavelength or frequency of the radiation emitted by a source in movement.This shift is given by the formula:
[tex] \frac{ \lambda - \lambda_{0} }{ \lambda_{0} } = \frac{-v}{c} [/tex]

where:
[tex] \lambda[/tex] = observed wavelength
[tex] \lambda_{0}[/tex] = wavelength at rest
v = speed of source (positive if towards the observer, negative if away from the observer)
c = speed of light

Therefore, we can solve for the observed wavelength:
[tex]\lambda = \lambda_{0} (\frac{-v}{c}) + \lambda_{0} \\ \lambda = \lambda_{0} (1 - \frac{v}{c})[/tex]

Substituting the given data:
[tex]\lambda = 656.46 (1 - \frac{300}{299792})[/tex]
= 655.80 nm

Hence, the observed wavelength of the line would be 655.80 nm. Note that this value is smaller than the one at rest, which means that we have a blue-shift, as expected for an approaching source.
Answer 2

The hydrogen line at 656.46 nm shifts to about 655.80 nm if a star is traveling 300 km/s toward Earth.

Using the Doppler Effect to Determine the Wavelength Shift

First, note the speed of light: c = 299,792 km/s.Original wavelength of the hydrogen line: λ₀ = 656.46 nm.Star's velocity towards Earth: v = -300 km/s (negative because the star is approaching).

Use the Doppler shift formula for wavelengths:

[tex]\[\lambda = \lambda_0 \sqrt{\frac{c - v}{c + v}}\][/tex]

Plugging in the values:

[tex]\[\lambda = 656.46 \, \text{nm} \sqrt{\frac{299,792 - 300}{299,792 + 300}}\][/tex]

Calculate the ratio:

Ratio = √(299,492 / 300,092) ≈ √(0.998)

Evaluate the square root:

[tex]\[\frac{299,492}{300,092} \approx 0.998\][/tex][tex]\[\sqrt{0.998} \approx 0.999\][/tex]

Compute the shifted wavelength:

[tex]\[\lambda \approx 656.46 \, \text{nm} \times 0.999\][/tex] ≈ 655.80 nm

The 656.46-nm line would shift to approximately 655.80 nm if the star were moving towards Earth at 300 km/s.

Complete question:

Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm. Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the Milky Way galaxy (which is around 300 km/s). Suppose the star was actually moving toward the earth at a more reasonable 300 km/s. What wavelength I would the 656.46-nm line move to? Use 299, 792 km/s for the speed of light. Express your answer in nanometers to five significant figures.


Related Questions

When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is 9.90 cm wide on a screen that is 2.53 m away. how wide is the slit?

Answers

Final answer:

The width of the slit when violet light of 415 nm wavelength creates a central diffraction peak of 9.90 cm on a screen 2.53 m away is approximately 10.6 μm.

Explanation:

The wavelength of violet light is given as 415 nm, and it produces a diffraction pattern with a central peak width of 9.90 cm on a screen 2.53 meters away. We can find the width of the slit using the formula for single-slit diffraction:

Δy = λL/a

where Δy is the width of the central peak, λ is the wavelength, L is the distance to the screen, and a is the width of the slit. Rearranging the formula to solve for a, we have:

a = λL/Δy

Substituting the provided values:

a = (415 x 10^-9 m)(2.53 m) / (9.90 x 10^-2 m)

After calculating, we find that the width of the slit (a) is approximately:

a ≈ 1.06 x 10^-5 m or 10.6 μm

Using the single-slit diffraction formula and given values, we calculate the width of the slit to be 21.1 μm.

To solve this problem, we'll use the formula for the width of the central peak in a single-slit diffraction pattern:

w = 2Lλ / a

Where:

w = width of the central peak (9.90 cm = 0.099 m)L = distance from the slit to the screen (2.53 m)λ = wavelength of violet light (415 nm = 415 x 10⁻⁹ m)a = width of the slit (what we need to find)

Rearranging the formula to solve for a:

a = 2Lλ / w

Substituting the given values:

a = (2 * 2.53 m * 415 x 10⁻⁹ m) / 0.099 m

Now, calculate:

a = 2.11 x 10⁻⁵ m or 21.1 μm

Therefore, the width of the slit is 21.1 μm.

Picturing the way a volcano erupts to remember how a volcano functions is called a. Visualizing c. Keywording b. Categorizing d. All of these

Answers

the answer is A visual 

Making a mental picture of the way a volcano erupts to remember how a volcano functions is called visualization.

What is visualization?

Visualization is the process whereby a person makes or forms a mental picture of a particular situation or occurrence in order to better understand that occurrence.

Picturing the way a volcano erupts to remember how a volcano functions is a process of visualization.

A mental picture of the volcano is made by the individual.

Therefore, Picturing the way a volcano erupts to remember how a volcano functions is called visualization.

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A light source emits a beam of photons, each of which has a momentum of 2.7 × 10-29 kg·m/s. (a) what is the frequency of the photons? (b) to what region of the electromagnetic spectrum do the photons belong?

Answers

The frequency of the photons is equal to 1.22 ×10¹³ Hz and lies in the infrared region of the electromagnetic spectrum.

What is the frequency?

The frequency of the photons or light can be described as the number of oscillations in one second. The frequency possesses S.I. units per second or Hertz.

The relationship between momentum (p), frequency (ν), and speed of light (c) is:

p = hν/c

ν = pc/h

Given, the momentum of the photons, p = 2.7 ×10⁻²⁹ Kg.m/s

The speed of light, c = 3×10⁸ m/s

The plank's constant, h = 6.626 ×10⁻³⁴ Js

The frequency of the photons can determine from the above-mentioned relationship:

ν = (2.7 × 10⁻²⁹).( 3 × 10⁸)/ 6.626 × 10⁻³⁴

ν = 1.22 × 10¹³ Hz

Therefore, the frequency of the photons is 1.22 × 10¹³ Hz and lies in the infrared region of the spectrum.

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Marie notices that most of her friends have MP3 players that are all made by a certain brand. She wants one, too, but not just any MP3 player. Marie wants to buy the exact same brand that her friends have. She thinks this is the way to fit in. Which term describes why Marie only wants a certain brand of MP3 player

Answers

the term is conformity

What potential increase vac must an electron be accelerated through if the most energetic photon it can emit will scatter off of a stationary electron at an angle ϕ=60∘ with wavelength 8.4×10−12m?express your answer in kilovolts to two significant digits?

Answers

Referring to Compton scattering 
Δλ = h/m₀c (I- cos Ф)
λ' =λ = (0,0242×10⁻¹⁰) (1- cos 60°)
λ= λ' -(0.0242 × 10⁻¹⁰) (1- cos 60°)

7.19 ˣ 10⁻¹²m

The increased potential is given by 
Vₐc = hc/eλ = 6.625 × 10 ⁻³⁴ J,s) ( 3× 10⁸ m/s ( 1.6 ˣ 10 ⁻¹⁰C)
(7.19 ˣ 10⁻¹²m)

173kV.

The pressure exerted by a phonograph needle on a record is surprisingly large. if the equivalent of 1.00 g is supported by a needle, the tip of which is a circle 0.210 mm in radius, what pressure is exerted on the record in n/m2?

Answers

Pressure, P = Force, F/ Surface Area, A

In the current scenario,
Force, F = Weight = mg = 1/1000*9.81 = 9.81*10^-3 N
Surface area, A = πr^2 = π*(0.210/1000)^2 = 1.385*10^-7 m^2

Therefore,
P = F/A = (9.81*10^-3)/(1.385*10^-7) = 70,807.71 N/m^2
Final answer:

The pressure exerted by a phonograph needle on a record, if the equivalent of 1g is supported by the needle with a radius of 0.210 mm, is approximately 7.05*10^7 Pa or N/m².

Explanation:

The pressure exerted by a phonograph needle on a record is calculated using the formula for pressure: P = F / A . To obtain the force (F), we multiply the mass of the needle (1g or 0.001 kg) by the acceleration due to gravity (9.8 m/s²). This yields a force of 0.0098 N. The area (A) is calculated using the formula for the area of a circle, A=πr², where r is the radius of the needle tip (0.210 mm or 0.00021 m). So, the area amounts to roughly 0.000000139 m². The resulting pressure (P), when calculated comes out to be approximately 7.05*10^7 Pa or N/m².

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A steam turbine operates at a boiler temperature of 450 k and an exhaust temperature of 300 k. what is the maximum theoretical efficiency of this system?

Answers

The maximum theoretical efficiency of the system is the one corresponding to the efficiency of a Carnot cycle operating between the same temperatures of the system:
[tex]\eta=1- \frac{T_c}{T_h} [/tex]
where [tex]T_c[/tex] and [tex]T_h[/tex] are the cold and hot temperatures, respectively.
In our problem, [tex]T_c=300 K[/tex] and [tex]T_h=450 K[/tex], therefore the maximum theoretical efficiency is
[tex]\eta=1- \frac{300 K}{450 K}=0.33 [/tex]
So, 33%.
Final answer:

The maximum theoretical efficiency of a steam turbine operating at a boiler temperature of 450 K and an exhaust temperature of 300 K, as calculated by the Carnot efficiency, is approximately 33%.

Explanation:

The efficiency of a heat engine like a steam turbine can be evaluated using the Carnot efficiency formula. The Carnot efficiency formula is 1 - Tc/Th where Tc is the cold reservoir temperature (exhaust temperature) and Th is the hot reservoir temperature (boiler temperature). Given in the problem, Tc=300K and Th=450K:

Efficiency = 1 - Tc/Th

= 1 - 300 K / 450 K = 1 - 0.67 approximately

So, the maximum theoretical efficiency of the steam turbine would be about 33% according to the Carnot efficiency.

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A 10 µf capacitor is charged to 108 v and is then connected across a 328 ω resistor. what is the initial charge on the capacitor? answer in units of µc.

Answers

The capacitance is defined as the maximum charge stored in a capacitor, Q, divided by the voltage applied, V:
[tex]C= \frac{Q}{V} [/tex]

The capacitor is initially charged with the battery of 108 V, so the the initial charge on the capacitor can be found by re-arranging the previous formula:
[tex]Q=CV=(10 \mu F)(108 V)=1080 \mu C[/tex]

A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. calculate the time in which the ball will reach the ground.

Answers

The ball moves by uniformly accelerated motion, and its vertical position at time t is described by the following law
[tex]y(t) = h+v_0t - \frac{1}{2}gt^2 [/tex]
where
[tex]h=4.21 m[/tex] is the initial height from which the ball starts its motion
[tex]v_0=1.53 m/s[/tex] is the initial velocity of the ball
[tex]g=9.81 m/s^2[/tex] is the gravitational acceleration

The time in which the ball reaches the ground is the time t at which the vertical position y(t) becomes zero:
[tex]0= h + v_0 t - \frac{1}{2}gt^2[/tex]
Which means
[tex]0=4.21 + 1.53 t - 4.9 t^2 [/tex]

whose solutions are:
[tex]t=-0.78 s[/tex]
[tex]t=1.10 s[/tex]
Neglecting the negative solution (since it has no physical meaning), we can say that the ball reaches the ground after 1.10 s.

The time in which the ball will reach the ground is about 1.10 s

Further explanation

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Kinematics.

We will solve it in the following way

Given:

initial speed = u = 1.53 m/s

initial height = H = 4.21 m

Unknown:

time taken = t = ?

Solution:

[tex]H = ut - \frac{1}{2}gt^2[/tex]

[tex]-4.21 = 1.53t - \frac{1}{2}(9.8)t^2[/tex]

[tex]-4.21 = 1.53t - 4.9t^2[/tex]

[tex]4.9t^2 - 1.53t - 4.21 = 0[/tex]

We will solve the above equation using the following quadratic function formula:

[tex]t = \frac{1.53 + \sqrt{1.53^2 - 4(4.9)(-4.21)}}{2(4.9)}[/tex]

[tex]t \approx 1.10 ~ s[/tex]

Learn moreVelocity of Runner : https://brainly.com/question/3813437Kinetic Energy : https://brainly.com/question/692781Acceleration : https://brainly.com/question/2283922The Speed of Car : https://brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

If a muon is traveling at 70% of the speed of light, how long does it take to decay in the observer's rest frame (i.e., what is the observed lifetime τμ of the muon)? express your answer in microseconds to two significant figures.

Answers

The muon lifetime in the muon reference frame is
[tex]\tau_0 = 2.2 \mu s[/tex]

In the observer's rest frame, the muon lifetime is instead given by
[tex]\tau = \gamma \tau_0[/tex]
where
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } } [/tex] is the relativistic factor, with v being the muon speed and c the speed of light.

Since the muon is traveling at 70 % of the speed of light, 
[tex]v=0.70 c[/tex]
and the relativistic factor is
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{(0.70 c)^2}{c^2} } }=1.4 [/tex]

Therefore, the muon lifetime in the observer's rest frame is
[tex]\tau = \gamma \tau_0 = (1.4)(2.2 \mu s)=3.1 \mu s[/tex]

Answer:

Observed lifetime [tex]= 3.0\mu s[/tex]

Explanation:

The lifetime of muon in the muon’s reference frame.

[tex]t^{_{0}}=2.2\mu s[/tex]

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

Here the  

[tex]\gamma =\dfrac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

[tex]\gamma[/tex] is the relativistic factor.  

V = Speed of muon

C = Speed of light

The muon’s speed of 70% of light speed.  

Hence,

[tex]V=\dfrac{70}{100}C[/tex]

V = 0.7C

[tex]=\dfrac{1}{\sqrt{1-\frac{(0.7C)^2}{C^2}}}[/tex]

[tex]=\dfrac{1}{\sqrt{1-0.49}}[/tex]

[tex]=\dfrac{1}{\sqrt{0.51}}[/tex]

[tex]=\dfrac{1}{0.71}[/tex]

= 1.4

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

[tex]t=1.4\times 2.2\mu s[/tex]

[tex]t=3.0\mu s[/tex]

Further explanation:

The muon is a lepton which decays to form an electron or positron. The lifetime of the muon is 2.20 microseconds. The muon lifetime in the muon reference frame is .  

But the observed lifetime [tex]= \gamma =\frac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

Learn more:

1. Speed of muon https://brainly.com/question/10048817 (answer by skyluke89)

2. Muon https://brainly.com/question/13198853 answer by skyluke89 )

Keywords: Muon, Speed of light, life time.

you drop a glass on the floor and it shattters chemical or physical change ?

Answers

This describes a physical change. The glass shattering changes its physical shape and appearance only, as it retains its chemical composition.
This is Physical change.

Hope this helps!

Find the kinetic energy of an electron whose de broglie wavelength is 34.0 nm.

Answers

The De Broglie wavelength of the electron is
[tex]\lambda=34.0 nm=34 \cdot 10^{-9} m[/tex]
And we can use De Broglie's relationship to find its momentum:
[tex]p= \frac{h}{\lambda}= \frac{6.6 \cdot 10^{-34} Js}{34 \cdot 10^{-9} m}=1.94 \cdot 10^{-26} kg m/s [/tex]

Given [tex]p=mv[/tex], with m being the electron mass and v its velocity, we can find the electron's velocity:
[tex]v= \frac{p}{m}= \frac{1.94 \cdot 10^{-26} kgm/s}{9.1 \cdot 10^{-31} kg}= 2.13 \cdot 10^4 m/s[/tex]

This velocity is quite small compared to the speed of light, so the electron is non-relativistic and we can find its kinetic energy by using the non-relativistic formula:
[tex]K= \frac{1}{2}mv^2= \frac{1}{2}(9.1 \cdot 10^{-31} kg)(2.13 \cdot 10^4 m/s)^2=2.06 \cdot 10^{-22} J [/tex]

Kinetic energy is a property of a moving item that is affected by both mass and velocity. The electron's kinetic energy with a de-Broglie wavelength of 34nm is 2.06 × [tex]10^-^2^2[/tex]J.

First, we have to convert de Broglie wavelength in m to satisfy the dimensions.

λ = 34.0nm =34×[tex]10^-^9[/tex].

To find  kinetic energy we need to find velocity and for that, we need to find momentum by using the formulae:

P= h/λ  = 6.6×[tex]10^-^3^4[/tex]/34×[tex]10^-^9[/tex] = 1.94×[tex]10^-^2^6[/tex] kgm/s.

After getting momentum we need to find the velocity

V=p/m = 1.94×[tex]10^-^2^6[/tex] / 9.1×[tex]10^-^3^1[/tex]= 2.13×[tex]10^4[/tex] m/s.

Now we have the value of velocity and by applying it  [tex]k=1/2mv^2[/tex], we can find easily find the kinetic energy

[tex]k=1/2mv^2[/tex] = 1/2 (9.1×[tex]10^-^3^1[/tex] kg)×(2.13×[tex]10^4[/tex] m/s[tex])^2[/tex] = 2.06×[tex]10^-^2^2[/tex]J.

Therefore, the kinetic energy of the particle is 2.06×[tex]10^-^2^2[/tex]J.

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A crying baby emits sound with an intensity of 8.0 × 10-8 w/m2. calculate a reasonable estimate for the intensity level from a set of quintuplets (five babies), all crying simultaneously at the same place? the lowest detectable intensity is 1.0 × 10-12 w/m2.

Answers

Sound intensity of 1 baby, I = 8*10^-8 W/m^2

The sound heard should be higher by:

10*log (n) where for 5 babies, n = 5. Then
10*log (n) = 10*log (5) ≈ 7 dB

Also give is the reference sound, Io = 1.0*10^-12 W/m^2

Therefore,
Sound intensity, L1 = 10*log (I/I1) = 10*log [(8*10^-8)/(1*10^-12)] ≈ 49 dB
Therefore, total intensity for the five babies is:

Total intensity = 49+7 = 56 dB

The intensity level from a set of quintuplets (five babies) : 56 dB

Further explanation

Wave intensity is the power of a wave that is moved through a plane of one unit that is perpendicular to the direction of the wave

Can be formulated

[tex]\rm I=\dfrac{P}{A}[/tex]

I = intensity, W m⁻²

P = power, watt

A = area, m²

The farther the distance from the sound source, the smaller the intensity

[tex]\rm \dfrac{I_2}{I_1}=\dfrac{(r_1)^2}{(r_2)^2}[/tex]

So the intensity is inversely proportional to the square of the distance from the source

[tex]\rm I\approx \dfrac{1}{r^2}[/tex]

Intensity level (LI) can be formulated

[tex]\rm LI=10\:log\dfrac{I}{I_o}[/tex]

Io = 10⁻¹²

For the level of intensity of several sound sources as many as n pieces can be formulated:

LIn = LI1 + 10 log n

The intensity level of 1 baby is

[tex]\rm LI=10\:log\dfrac{8.10^{-8}}{10^{-12}}[/tex]

LI = 10 log 8.10⁴

LI = 49

The intensity level of 5 babies :

LI5 = LI + 10 log n

LI5 = 49 + 10 log 5

LI5 = 49 + 7

LI5 = 56

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Apply: what will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors? test your answers with the gizmo.

Answers

1) Total resistance

the total resistance of a circuit with n resistors in parallel is given by
[tex] \frac{1}{R_{eq}} = \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} [/tex]
where [tex]R_i[/tex] are the single resistances.

In our circuit, we have 3 resistors of [tex]10.0 \Omega[/tex] each, so the total resistance of the circuit is given by
[tex] \frac{1}{R_{eq}}= \frac{1}{10 \Omega}+ \frac{1}{10 \Omega}+ \frac{1}{10 \Omega}= \frac{3}{10 \Omega} [/tex]
which means a total resistance of
[tex]R_{Eq} = \frac{10 \Omega}{3}=3.33 \Omega [/tex]

2) Current in the circuit

The current in the circuit can be found by using Ohm's law:
[tex]I= \frac{V}{R_{Eq}} [/tex]
where V is the voltage of the battery and Req is the total resistance we found before. By using V=15 V, we find
[tex]I= \frac{15 V}{3.33 \Omega}=4.5 A [/tex]

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

To calculate the total resistance in a parallel circuit with three resistors of 10 ohms each, we use the formula for parallel resistance:

[tex]\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}[/tex]

Substituting the values:

1/Rtotal = 1/10 + 1/10 + 1/10

1/Rtotal = 3/10

Therefore, Rtotal = 10/3 = 3.33 ohms

Next, we calculate the total current using Ohm's Law:

I = V/Rtotal

Given the battery voltage is 15 volts:

I = 15/3.33 ≈ 4.50 amps

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

Calculate the magnitude of the angular momentum of the earth in a circular orbit around the sun. mastering

Answers

The angular momentum of the Earth around the Sun is given by:
[tex]L=m \omega r^2[/tex]
where 
m is the Earth's mass
[tex]\omega[/tex] is the Earth's angular velocity
r is the average distance of the Earth from the Sun

The Earth takes 365 days to make a complete revolution around the Sun, which corresponds to
[tex]t=365 d \cdot 24 \cdot 60 \cdot 60 =3.15 \cdot 10^7 s[/tex]
A complete revolution corresponds to [tex]2 \pi rad[/tex], therefore the Earth's angular velocity is
[tex]\omega = \frac{2 \pi rad}{3.15 \cdot 10^7 s}=1.99 \cdot 10^{-7} rad/s [/tex]

The average distance of Earth from the Sun is 149.6 million km:
[tex]r=149.6 Mkm = 149.6 \cdot 10^9 m[/tex]

And the Earth's mass is [tex]m=5.97 \cdot 10^{24} kg[/tex], therefore its angular momentum is
[tex]L=m \omega r^2 =(5.97 \cdot 10^{24} kg)(1.99 \cdot 10^{-7} rad/s)(149.6 \cdot 10^9 m)^2=[/tex]
[tex]=2.66 \cdot 10^{40} kg m^2/s[/tex]

What is the resistance of a 1500 w ( 120 v) hair dryer?
b. what is the current in the hair dryer when it is used?

Answers

a) power = IV
From ohms law. I =V/R
So, Power = VV/R

  Therefore, R (resistance) = VV ÷ Power

     R = (120×120) ÷ 1500
        = 9.6 ohs.

b) From ohm's law, V=IR
    So, I = V/R
            = 120 ÷ 9.6
            = 12.5 A 

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

(a) The resistance of the hairdryer will be 9.6 ohms.

(b)the current in the hairdryer will be 12.5 A.

When all physical parameters and temperature are constant,

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law

V=IR

(a)

The following data are given as

P = 1500 w

v = 120 v

The power generated in the hairdryer

[tex]\rm{P = vI}\\\\I=\frac{P}{v} \\\\I=\frac{1500}{120}\\\\I=12.5 A}[/tex]

To obtained the resistance

[tex]\rm R=\frac{v}{I} \\\\\rm R=\frac{120}{12.5} \\\\R= 9.6 ohm}[/tex]

Hence the resistance of the hairdryer will be 9.6 ohms.

(b)

The Equation of Ohm's Law

V=IR

[tex]\rm I =\frac{V}{R} \\\\\rm I =\frac{120}{9.6}\\\\\ I= 12.5 A[/tex]

Hence the current in the hairdryer will be 12.5 A.

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Calculate the weight ofa 58 kg astronaut on the moon where g=1.6 m/s2

Answers

weight = (mass) x (gravity)

On the moon, gravity = 1.6 m/s² .

The astronaut, with his mass of 58 kg, weighs

(58 kg) x (1.6 m/s²) = 92.8 newtons (about 21.1 pounds)


On the Earth, gravity = 9.8 m/s² .

The astronaut, with his mass of 58 kg, weighs

(58 kg) x (9.8 m/s²) = 568.4 newtons (about 127.9 pounds)

Discuss five ways human activity has accelerated soil erosion

Answers

Answer:

road erosion, house construction, steep slope cultivation, tourism development, and animal trampling.

Explanation:

Two moles of an ideal gas are compressed in a cylinder at a constant temperature of 80.0 ∘c until the original pressure has tripled. calculate the amount of work done by gas.

Answers

The work done by a gas during an isothermal process is given by:
[tex]W=nRT ln \frac{V_f}{V_i} [/tex] (1)
where
n is the number of moles of the gas
R is the gas constant
T is the absolute temperature of the gas
[tex] \frac{V_f}{V_i} [/tex] is the ratio between the final volume and the initial volume of the gas

We need to calculate this ratio, and we can do it by using the gas pressure. In fact, for an isothermal process, Boyle's law states that the product between pressure and volume of the gas is constant:
[tex] pV=k [/tex]
which can be rewritten as
[tex] p_i V_i= p_f V_f[/tex]
which is equivalent to
[tex] \frac{V_f}{V_i}= \frac{p_i}{p_f} [/tex]
The problem says that the pressure of the gas is tripled, therefore the ratio between final and initial volume is:
[tex] \frac{V_f}{V_i} = \frac{p_i}{3 p_i} = \frac{1}{3} [/tex]

Now we can use eq.(1) to calculate the work done by the gas. The absolute temperature is
[tex]T=80.0^{\circ}C+273 = 353 K[/tex]
The number of moles is n=2, therefore the work done is
[tex]W=nRT ln \frac{V_f}{V_i}=(2 mol)(8.31 J/mol K) (353 K) \ln \frac{1}{3}= -6445 J[/tex]
And the work is negative, because it is done by the environment on the gas (the gas is compressed)

Final answer:

The work done by two moles of an ideal gas compressed isothermally in a cylinder can be calculated using the formula W = nRT ln(V1/V2). The work is generally negative as the gas does work on its surroundings during the process.

Explanation:

When an ideal gas is compressed in a cylinder, the work done by the gas can be calculated using the principles of thermodynamics. Specifically, if the gas is compressed isothermally (at a constant temperature), the work done by the gas during this process can be calculated using the formula W = nRT ln(V1/V2), where n represents the number of moles of gas, R is the universal gas constant, T is the temperature in Kelvin, and V1 and V2 are the initial and final volumes of the gas respectively.

In the scenario presented, we have 2 moles of gas, a temperature of 80.0°C, and the original pressure being tripled during the compression. This tripling of pressure corresponds to reduction in volume to one third. From these values, we can calculate the work done by the gas during compression. However, we do not have specific information about the volumes or pressures, so we cannot calculate a numerical value. In general, though, we can say the work done by the gas during an isothermal process is negative, as it is compressed and does work on its surroundings.

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The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

Answers

C)a powerful magnet.

Answer:

C) a powerful magnet

Explanation:

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

when current is pass to the coil, an electromagnetic force field is produced. The electromagnetic force field produced then have an impact on the magnet which drives the shaft to move

Jupiter‘s great red spot is believed to be a

Answers

The Great Red Spot is an anticyclonic (high pressure) storm that rotates around the planet at about 22°. 

Cyclonic storm -gradpoint

A camera with a 50.0-mm focal length lens is being used to photograph a person standing 3.00 m away. if the film is 36.0 mm high, what fraction of a 1.75-m-tall person will fit on it?

Answers

f = 50.0mm = 5.0cm
d₀ = 3.00m = 3.00cm
1/f = 1/d₀ + 1/di
= 1/di = 1/5 - 1/325 = 5.078 cm
m= hi/h₀ = di/d₀ = 5.078/300
hi/h₀ = 169.29
hi = 1692.9 cm

If a hydrogen atom in the ground state absorbs a photon of energy 12.09 ev, to which state will the electron make a transition?

Answers

The energy levels of the hydrogen atom are given by
[tex]E_n = -13.6 \frac{1}{n^2} [eV][/tex] (1)
where n is the level number. Therefore, the ground state has energy of
[tex]E_1 = -13.6 \frac{1}{1^2} eV = -13.6 eV[/tex]

If the atom absorbs a photon of energy [tex]E=12.09 eV[/tex], the final energy of the hydrogen atom is
[tex]E_f = E_1 + E = -13.6 eV + 12.09 eV =-1.51 eV[/tex]

And we can use eq.(1) to find the corresponding level number:
[tex]n= \sqrt{ \frac{-13.6 eV}{E_f} } = \sqrt{ \frac{-13.6 eV}{-1.51 eV}}= \sqrt{9}=3 [/tex]
So, the electron made a transition to the n=3 level.

Thermodynamics is the study of the relationship between thermal energy and mass. other forms of energy. types of engines. temperature.

Answers

Thermodynamics is a branch of physics concerned with heat and temperature and their relation to other forms of energy and work. The behavior of these quantities is governed by the four laws of thermodynamics, irrespective of the composition or specific properties of the material or system in question. The laws of thermodynamics are explained in terms of microscopic constituents by statistical mechanics. Thermodynamics applies to a wide variety of topics in science and engineering, especially physical chemistry, chemical engineering and mechanical engineering.

Other forms of energy.

1) A substance has a half life of 20 years. what percentage would be left after 40 years?

2)After 4 half lifes of uranium, 10 grams of the uranium remains. how much uranium did you start with?

Answers

1) The half-life is the time required for a substance to reduce to half its initial value. In formulas:
[tex] \frac{m(t)}{m_0} = ( \frac{1}{2} )^{t/t_{1/2}}[/tex] (1)
where
m(t) is the amount of substance left at time t
m0 is the initial mass
[tex]t_{1/2}[/tex] is the half-life

In this problem, the half-life of the substance is 20 years:
[tex]t_{1/2} = 20 y[/tex]
therefore, the fraction of sample left after t=40 years will be
[tex] \frac{m(t)}{m_0}=( \frac{1}{2})^ \frac{40 y}{20 y} = ( \frac{1}{2})^2 = \frac{1}{4} [/tex]

So, only 1/4 of the original sample will be left, which corresponds to 25%.

2) We can use again formula (1), by re-arranging it:
[tex]m_0 = \frac{m(t)} {( \frac{1}{2} )^{ \frac{t}{t_{1/2} }}}[/tex]
If we use m(t)=10 g (mass of uranium left at time t), and [tex]t=4 t_{1/2}[/tex] (the time is equal to 4 half lifes), we get
[tex]m_0 = \frac{10 g}{ (\frac{1}{2})^4 } =16 \cdot 10 g = 160 g[/tex]
So, the initial sample of uranium was 160 g.

In a typical lightning strike, 2.9 c flows from cloud to ground in 0.18 ms. what is the current during the strike?

Answers

Current = (charge) / (time)

= (2.9 C) / (0.18 ms)

= (2.9 C) / (0.00018 sec)

16,111 Amperes !  (but it doesn't last long)


The absolute (or total) pressure at the bottom of a cylindrical container with a cross-sectional area of 47.0 cm2 and holding a fluid of density 560 kg/m3 is 115 kpa. (a) determine the depth of the fluid.

Answers

Final answer:

The fluid's depth in the cylinder can be determined using the equation for fluid pressure, h = P / (pg), and plugging in given values, resulting in an approximated depth of 20.9 meters.

Explanation:

The total absolute pressure at a point in a fluid is the sum of the atmospheric pressure and the pressure due to the fluid above the point of reference. The latter is given by the equation P = pgh, where p is the density of the fluid, g is the acceleration due to gravity and h is the height (or depth) of the fluid column above the point of reference. In this scenario, we know P (absolute pressure, 115 kPa), p (density, 560 kg/m3), and g (standard gravity, roughly 9.81 m/s2), and we want to find h.

To find h, we can rearrange our equation: h = P / (pxg) . Plugging the given values we have h=115000Pa/(560kg/m3*9.8m/s2), which gives h = 20.9 m.

This means the depth of the fluid in the cylinder is approximately 20.9 meters.

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If a chromosome on unfolds itself how is transcription enhanced

Answers

Sorry that I'm late the answer is the DNA region is easily accessible

Which forces tend to slow down an object

Answers

The answer is "friction and air resistance" gravity does some of the work by keeping the object from floating away, but friction and air resistance does the biggest part. Friction is how rough the ground it meaning on tile, dirt, grass, etc... that would slow down the object and air resistance is the gravity pushing on the object also making it stop. 

Hope this helps!

The measurement of an exoplanet's radius is measured in units compared to ________.

the Sun's radius
planet Earth's radius
planet Jupiter's radius
the moon's radius

Answers

the eaths radius is the correct answer, if you need proof look at nasa's website 

Planet Earth's radius
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