Explain why the function f(x)=x^2 is not invertible
Answers
When you reflect the curve across the line y=x, it becomes multiple-valued, hence its inverse is not a function.
Related Questions
I need help plz, i dont understand it, its english class, i dont like english class
Answers
Round the answer to the nearest cent.
A 30% discount on $47.50 is $
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Answer:
14. 25
Step-by-step explanation:
Sharon and Jacob started at the same place. Jacob walked 3 m north and then 4 m west. Sharon walked 5 m south and 12 m east. How far apart are Jacob and Sharon now?
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Drawing this on a coordinate plane gives us coordinates for Jacob (-4, 3) and coordinates for Sharon (12, -5).
The distance formula is:
[tex] \sqrt{( x_{2}-x_{1})^{2} +(y_{2}-y_{1})^2 } [/tex]
Substituting our values for Jacob and Sharon in we get:
[tex]\sqrt{(-4-12)^2+(3--5)^2} \\ \sqrt{(-16)^2 + (3+5)^2} \\ \sqrt{256+(8)^2} \\ \sqrt{256+64} \\ \sqrt{320}=17.89[/tex]
They are now 17.89 m apart.
Answer:
17.89
Step-by-step explanation:
7. What is the solution to the proportion below?
Captionless Image
y = 6/7
y = 18
y = 4.5
y = 24
Answers
Cross multiplying, we get:
[tex]4(2y-9) = 6y \\ \\ 8y-36=6y \\ \\ 8y-6y=36 \\ \\ 2y=36 \\ \\ y=18[/tex]
Thus the value of y for given proportion is 18.
The quotient property of radicals requires the indices of the radicals to be the same. Does this mean that it is not possible to write es002-1.jpg as a single radical? Explain.
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The radicands are powers of the same base, so they can be written using rational exponents.
Simplify the quotient of the exponential expressions by getting a common denominator and subtracting exponents.
The simplified expression is the 4th root of y
The expression can be written as a single radical by covertong the expression to a rational format such that both the denominator and numerator have the same base as y¼
Numerator = The 4th root of y³ = y¾Denominator = squareroot of y = y½Using indices :
Division sign signifies the powers should be subtracted[tex] \frac{y¾}{y½} = y^{¾ - ½} = y¼[/tex]
Therefore, the expression can be written as a single radical thus y¼
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I need help please Brainliest
Answers
2. A
3. A
4. D
Hope i helped plz tell me how i did thanks
Find the distance between the two points. Round to the nearest tenth if necessary. (10, –4), (5, 8)
169
7
13
16
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If you ask this question may be you do not know the formula of the distance between two points or you do not know how to use it, so I am going to explain you both.
1) Formula of the distance betweer two points:
Say the point A has coordinates (x1, y1) and the point B has coordinates (x2, y2), the distance, d, between the points A and B is given by the formula:
[tex]d^2= (x_1-x_2)^2+(y_1+y_2)^2} = d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} [/tex]
2) So, to apply that formula you need the coordinates of the two points.
In this case the coordinates of the point (10,-4) are: x = 10, y = -4
The coordinates of the point (5,8) are: x = 5, y = 8.
3) This is the application:
[tex]d= \sqrt{(10-5)^2+(-4-8)^2}= \sqrt{(5)^2+(-12)^2}= \sqrt{25+144} d= \sqrt{169}=13 [/tex]
So, the answer is 13.
Look at the picture below // 50 points // PLEASEE HELPP
Answers
so answer is C. steeper
Hey, I have some questions on some math problems for Algebra 2. Think you can help? Here's the first one :)
Some investments in the stock market have gained 10% annually. the total value of the investment, A, and this rate can be found using A= P(1.10)^n where P is the initial value of this investment, and N is the number of years the money is invested. if $1,000 is invested in the stock market at this annual rate of return, what is the expected total value after 18 years?
1. $4,054.47
2. $5,559.92
3. $18,700.00
4. $19,800.00
I originally thought it was $18,700.00 but I don't know
Answers
A=P(1.10)^N
P=$1000
N=18
A=1000 (1.10)^18
A = 1000 * 5.55991731349
A=5559.91731349
Rounding off to the nearest hundredths, we get
A = $5559.92
The expected total value after 18 years is $5,559.92
Solve 3x+11= k for x.
A. x=3k-11
B. x=k-11
C. k+11
x=———
3
D. k-11
x= ———
3
What’s the answer?
Answers
None of the answers listed are correct.
3x + 11 = k
SUBTRACT 11 from both sides:
3x + 11 = k
-11 -11
You are then left with:
3x = k-11
DIVIDE 3 by both sides:
3x/3 = k-11/3
You are then left with:
x= k-11/3
The value of x for the equation 3x + 11 = k is [tex]\frac{k-11}{3}[/tex].
What is linear equation in one variable?
The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.
According to the given question.
We have a linear equation in one variable
[tex]3x + 11 = k[/tex]
For the above equation the value of x is given by
[tex]3x + 11 = k[/tex]
⇒[tex]3x = k -11[/tex] ( subtracting 11 from both the sides)
⇒[tex]x = \frac{k-11}{3}[/tex] ( dividing both the sides by 3)
Hence, the value of x for the equation 3x + 11 = k is [tex]\frac{k-11}{3}[/tex].
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if y varies directly as x, and y=6 as x=-1, find y for the x-value of 5
Answers
Answer:
[tex]y=-30[/tex]
Step-by-step explanation:
we are given
y varies directly as x
so, we can write equation as
[tex]y=kx[/tex]
where
k is constant of proportionality
We have
at x=-1 , y=6
so, we can use it to find k
[tex]6=k(-1)[/tex]
so, we get
[tex]k=-6[/tex]
now, we can plug it back
[tex]y=-6x[/tex]
now, we can plug x=5
and we get
[tex]y=-6\times 5[/tex]
[tex]y=-30[/tex]
Which step in the construction of copying a line segment ensures that the new line segment has the same length as the original line segment
Answers
Answer:
Using a compass.Step-by-step explanation:
Using a compass ensures that the new segment has the same length as the original one. Taking a pivot point and then drawing a arc, this distance is the copy.
factor by grouping 5x^2+2x+40x+16
Answers
5 x^2 + 40 x + 2 x + 16
2 x + 40 x = 42 x:
5 x^2 + 42 x + 16
Factor the quadratic 5 x^2 + 42 x + 16. The coefficient of x^2 is 5 and the constant term is 16. The product of 5 and 16 is 80. The factors of 80 which sum to 42 are 2 and 40. So 5 x^2 + 42 x + 16 = 5 x^2 + 40 x + 2 x + 16 = 8 (5 x + 2) + x (5 x + 2):
8 (5 x + 2) + x (5 x + 2)
Factor 5 x + 2 from 8 (5 x + 2) + x (5 x + 2):
Answer: (5 x + 2) (x + 8)
What is the best estimation of mean for this data set.
Answers
5 is correct I did this quiz
5 is the best estimation of mean for the given data set.
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
In the given data, the number of sites ae given in y axis and number of shield daters on x axis.
From the given dart let us construct a table
Number of sites Number of shield darters
2 3
3 1
4 4
6 2
7 3
8 1
9 1
By using the mean formula we get the mean as 5
Hence, 5 is the best estimation of mean for the given data set.
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There is 30\100 of a liter of orange juice on one container and 5\10 of a liter of pineapple juice in another container. If Mrs. Morales combines the two juices ,how much orange-pineapple juice will she ? Explain how you found your answer.
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Mrs. Morales will have 4/5 of a liter of juice.
_____
The total quantity was found by adding the quantities of individual kinds of juice. The addition was performed by expressing each fraction using the common denominator of 10, then reducing the final result.
a rock is thrown from the top of a tall building. the distance, in feet, between the rock and the ground x seconds after it is thrown is given by f(x)=-16x62-4x+382 How long after the rock is thrown does it hit the ground
Answers
We have then:
f (x) = - 16x ^ 2-4x + 382
The moment the rock hits the ground we have f (x) = 0
0 = -16x ^ 2-4x + 382
We solve the polynomial looking for its roots which are:
x1 = -5.012803699004288
x2 = 4.762803699004288
We ignore the negative root. The solution is:
x = 4.76
Answer:
it hits the ground 4.76 s after is thrown
It takes approximately 5.0 seconds for the rock to hit the ground after it is thrown.
Explanation:To find the time when the rock hits the ground, we need to find the value of x when the distance between the rock and the ground is 0. In the given equation, f(x) = -16x^2 - 4x + 382, where f(x) represents the distance between the rock and the ground. We can set this equation equal to 0 and solve for x:
-16x^2 - 4x + 382 = 0
This is a quadratic equation. We can use the quadratic formula to solve for x:
x = (-b ± sqrt(b^2 - 4ac)) / (2a)
Plugging in the values from the equation, we get:
x = (-(-4) ± sqrt((-4)^2 - 4(-16)(382))) / (2(-16))
This simplifies to:
x = (4 ± sqrt(16 + 24512)) / (-32)
x = (4 ± sqrt(24528)) / (-32)
x ≈ (-4 ± 156.49) / (-32)
Since we're dealing with time, the negative value doesn't make sense in this context. So, we take the positive root:
x ≈ (4 + 156.49) / (-32)
x ≈ 160.49 / (-32)
x ≈ -5.0
Therefore, it takes approximately 5.0 seconds for the rock to hit the ground after it is thrown.
Alex is installing wooden flooring in his room. The room is rectangular in shape with length of 12 feet and width of 10 feet.
If the total cost of the wooden flooring is $600, what is the unit price of the flooring per square foot?
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Then you take your $600 and divide it by your entire room size (120)
This will give you the amount per square foot.
Your answer will be $5.00 per square foot
find the roots of the polynomial equation x^3-x^2+x+39=0
Answers
x^2-4x+4=-9,
(x-2)^2=-9
x-2=+-3i,
x=2+3i or 2-3i.
The roots are -3, 2+3i, 2-3i.
Triangle ABC is similar to triangle DEF. The length of AC---- is 12 cm. The length of EF--- is 15 cm. The length of DF---- is 9cm.
What is the length of BC----?
Enter your answer in the box
____ cm
Answers
____________________________________________________
Explanation:
____________________________________________________
[AC] / [DF] = 12 cm / 9 cm ;
[BC] / [EF] = x / 15 cm ;
12 / 9 = x / 15 ; Solve for "x" ; {Note: "x" is the length of BC (in cm) ;
Simplify the " (12/9) " ;
→ " 12 / 9 = (12 ÷ 3) / (9 ÷ 3) " ;
= 4 / 3 ;
And rewrite:
→ 4 / 3 = x / 15 ; Solve for "x" ;
_____________________________________________________
Note: Cross-multiply:
Given: "(a/b)" = (c/d)" ; { b[tex] \neq [/tex]0 ; d[tex] \neq [/tex]0 } ;
" a*d = b*c " .
_____________________________________________________
As such:
→ 3x = 15 * 4 ;
→ 3x = 60 ;
Divide EACH SIDE of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
__________________________________________________
→ 3x / 3 = 60 / 3 ;
→ x = 20 .
____________________________________________________
Answer: The length of BC is: " 20 cm " .
____________________________________________________
The triangle ABC and triangle DEF are similar so the value of the length of BC is 20 cm and this can be determined by using the properties of a similar triangle.
Given :
Triangle ABC is similar to triangle DEF.The length of AC is 12 cm. The length of EF is 15 cm. The length of DF is 9cm.The following steps can be used to determine the length of BC:
Step 1 - According to the given data, triangle ABC is similar to triangle DEF.
Step 2 - So, according to step 1:
[tex]\rm \dfrac{AC}{DF} = \dfrac{BC}{EF}[/tex]
Step 3 - Substitute the values of length AC, DF, and EF in the above equation.
[tex]\rm \dfrac{12}{9} = \dfrac{BC}{15}[/tex]
Step 4 - Multiply 15 on both sides in the above expression.
[tex]\rm \dfrac{12}{9}\times 15 = BC[/tex]
Step 5 - Simplify the above expression in order to get the value of the length BC.
BC = 20 cm
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Combine like terms to simlify the expression: 2/5k—3/5+1/10k
Answers
(5/10)k - 3/5
(1/2)k - 3/5 is the answer to the question
THen
4/10K - 3/5 + 1/10k = 5/10k - 3/5
Simplify 5/10k
1/2k - 3/5 is your answer
There are twenty-three red marbles and two blue marbles in a box. a marble is randomly chosen from the box, its color noted, then put back in the box. this process is repeated. what is the probability that (a) the first marble is blue? (b) the first four marbles are red? (c) the first four marbles are red and the fifth is blue?
Answers
B. 4/25
C. 6/25
I'm sure about the first one, not so much about the last 2 though...
Two boats on opposite banks of a river start moving towards each other. They first pass each other 1400 meters from one bank. They each continue to the opposite bank, immediately turn around and start back to the other bank. When they pass each other a second time, they are 600 meters from the other bank. We assume that each boat travels at a constant speed all along the journey. Find the width of the river?
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Let xx be the width of the river. It is given that, when they have met the first time, boat11 has travelled 14001400 m and boat22, (1400−x)(1400−x) metres.
When they meet for the second time, boat11 has travelled 600+(x−1400)=(x−800)600+(x−1400)=(x−800) m, and boat22, 1400+(x−600)=(x+800)1400+(x−600)=(x+800) m.
Note that, the relationship of the distances each traveled, is the same to both meetings. Thus,
14001400−x=x−800x+80014001400−x=x−800x+800⇒x=?⇒x=?Hope you can take it from here.MEDAL PLEASE HELP
A compact disc is designed to last an average of 4 years with a standard deviation of 0.9 years. What is the probability that a CD will last less than 3 years?
1.11%
13.35%
86.65%
100%
Answers
Find the perimeter and the area of the polygon with the given vertices. J (1,2), K (7,2), L (7,8), M (1,8)
Answers
recall, the perimeter is all sides summed up, and the area is just length * width.
Answer : The perimeter and the area of the polygon with the given vertices is, 24 unit and 36 unit² respectively.
Step-by-step explanation :
First we have to calculate the distance of JK, KL, LM and MJ.
Using distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where,
d = distance between the two coordinates
x and y are the coordinates.
To calculate the distance of JK:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(7-1)^2+(2-2)^2}[/tex]
[tex]d=\sqrt{(6)^2+(0)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
To calculate the distance of KL:
[tex]d=\sqrt{(x_3-x_2)^2+(y_3-y_2)^2}[/tex]
[tex]d=\sqrt{(7-7)^2+(8-2)^2}[/tex]
[tex]d=\sqrt{(0)^2+(6)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
To calculate the distance of LM:
[tex]d=\sqrt{(x_4-x_3)^2+(y_4-y_3)^2}[/tex]
[tex]d=\sqrt{(1-7)^2+(8-8)^2}[/tex]
[tex]d=\sqrt{(-6)^2+(0)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
To calculate the distance of MJ:
[tex]d=\sqrt{(x_4-x_1)^2+(y_4-y_1)^2}[/tex]
[tex]d=\sqrt{(1-1)^2+(8-2)^2}[/tex]
[tex]d=\sqrt{(0)^2+(6)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
The distance of JK, KL, LM and MJ is, 6, 6, 6 and 6.
Now we have to calculate the perimeter of the polygon.
Perimeter of polygon = JK + KL + LM + MJ
Perimeter of polygon = 6 + 6 + 6 + 6
Perimeter of polygon = 24 unit.
Now we have to calculate the area of polygon.
As the distance between the coordinates are equal that means the geometry will be square because in square the all four sides are equal.
Now we have to calculate the area of polygon by using area of square formula.
Area of polygon = Area of square = (side)²
Given: Side = 6
Area of polygon = Area of square = (6)²
Area of polygon = Area of square = 36 unit²
Thus, the area of polygon is, 36 unit²
please help ASAP
the vertices of pqr are p(-3, 8), q(-6, -4), and r(1, 1). if you reflect pqr across the x-axis, what will be the coordinates of the vertices of the image p'q'r'?
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Solve for all values of r 3r/r-5 - 2/r+3=r/r+3
Answers
(3r)(r+3)=(r-5)(r+2)
3r^2 +9r= r^2-3r-10
2r^2+12r+10=0
2(r^2+6r+5)=0
2(r+5)(r+1)=0
r=-1 or r=-5
Graph a system of equations to solve log (−5.6x + 1.3) = −1 − x. Round to the nearest tenth. From the least to the greatest, the solutions are:
ANSWER IS ::::: (-2.1)⇒0.2
Answers
Answer:
From least to the greatest, the solutions are: (-2.1) to (0.2)
Step-by-step explanation:
Given : Equation -[tex]log (-5.6x + 1.3) = -1-x[/tex]
To Solve : The equation
Step1 : Write the equation :
[tex]log (-5.6x + 1.3) = -1-x[/tex]
Step 2 : To solve the equation we plot the graph,
when we plot the graph the points where y=0 for value of x
Step 3: Points where y=0,x=-2.12 and 0.221 (shown in the attached graph)
Therefore, (x+2.12) and (x-0.221) are the solutions of the equation.
Round to nearest tenth x= -2.1 and 0.2
From least to the greatest, the solutions are: (-2.1) to (0.2)
I need some help with this math question. Please see attachment.
Answers
II. The interquartile range is the difference between the coordinates of the ends of the box: 13 -6 = 7. It is FALSE that the interquartile range is 6.
III. The median is Q2, the line in the middle of the box. It is 8. It is FALSE that the median is 10.
Selection A is appropriate.
please help me help!!!!!!!!!!!!
Answers
( -2*(-3*3)=16 )
bx - 5 = 16/-2
bx - 5 = -8
bx = -8+5
bx = -3
x = -3/b ← in the first box
when b=3
x = -3/b
x = -3/3
x = -1 ← in the second box
(Please Help For Examination) A sweet stall was placing order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger dimensions 15cmx12cmx5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs.4 for 1000cm(square), Find the cost of cardboard required for supplying 250 boxes of each kind.
Answers
Explanation:
1) The statement is incomplete. The complete statement contains the information of the dimensions of both bigger and smaller cardboard boxes.
2) The dimesions of bigger cardboard boxes are 25cm * 20 cm * 5 cm
3) The dimensions of smaller cardboard boxes are 15 cm * 12 cm * 5cm
4) For bigger cardboard boxes:
length, l = 25 cm
width, w = 20 cm
height, h = 5 cm
surface of each bigger carboard box = 2 [ l*w + l*h + w*h] = 2 [25*20 + 25*5 + 20*5] cm^2 = 1450 cm^2
total surface of 250 bigger cardboard boxes = 250 * 1450 cm^2 = 3625,500 cm^2
5% of the total surface area extra = 362,500cm^2 * 5 / 100 = 18,125 cm^2
Total area for bigger cardboard boxes= 362,500 cm^2 + 18,125 cm^2 = 380,625 cm^2
5) Smaller cardboard boxes
length, l = 15 cm
width, w = 12 cm
height, h = 5 cm
surface of each smaller cardboard box = 2 [l*w + l*h + w*h] = 2 [ 15*12 + 15 * 5 + 12 * 5] cm^2 = 630 cm^2
total surface of 250 smaller cardboard boxes = 250 * 630 cm^2 = 157,500 cm^2
5 % extra = 157,500 cm^2 * 5 / 100 = 7,875 cm^2
total area for smaller cardboard boxes = 157,500 cm^2 + 7,875 cm^2 = 165,375 cm^2
6) total area of cardboard required = 380,625 cm^2 + 165,375 cm^2 = 546,000 cm^2
7) Cost of cardboard required
unit cost per area * total area = (Rs 4 / 1000cm^2) * 546,000 cm^2 = Rs 2,184.
Answer: Rs 2,184