find an explicit formula for the arithmetic sequence -45,-30,-15,0...

Answer:

6x^2 - 10x  inches ^2

Step-by-step explanation:

The area of a rectangle is

A = l*w

    = (3x-5) * (2x)

    = 6x^2 - 10x

Answer:

The area of the rectangle is 6x^2(squared)-10x

Step-by-step explanation:

To find the area of rectangles, you must multiply the length by the width. The formst for this is A=LxW. When you substitute each part of the equation in, it becomes 2x(3x-5). When you have parentheses, distribute the number on the outside to each number(or variable) on the inside. First, multiply 2x by 3x. This leaves you with 6x^2(squared). Then, multiply the 2x by the -5. This leaves you with -10x. Combine each part to get 6x^2(squared)-10x. :)

Answer:

39

Step-by-step explanation:

134 + 167 = 301

301/7=43

301+430= 344

344/9 = 38.2  so you would need 39 tables

Answer:

The equation x+3=9 is true if and only if x=6.

Not enough information.

Step-by-step explanation:

We are looking for a if and only if statement for a bioconditional.

There is only one such choice:

The equation x+3=9 is true if and only if x=6.

We only know information about the triangle's angles, and nothing about their sides.  AAA (angle-angle-angle) is not enough information to conclude congruence.  It is enough for proving it to be similar.  

volume of a cylinder = pi×r^2×h

Answer:

I can increase r and decrease h, or I can decrease r and increase h.

Step-by-step explanation:

answer given in edmentum

The correct option is B.

The sum of the lengths of the diagonals in the given parallelogram is 12 miles. This value was derived by first identifying the values of the segments in relation to 'y', calculating for 'y', then using the property of the parallelogram where the diagonals bisect each other.

To solve for this geometry problem involving a parallelogram, we need to equate the given values and solve for 'y'. The values given stipulate that DE = EB; therefore, we get:

y+2 = 3y-4

y-3y = -4-2

-2y = -6

y = 3

Solving for y, we obtain y = 3.

Next is to solve AE, which is given as CE = AE and substituting the calculated value of y, we get:

AE = 2y - 3 = 2(3) - 3 = 3 miles.

In this parallelogram, it is a property that the diagonals bisect each other. Hence, DE = EB, and AE = EC. Therefore, AC equals 2 * AE = 2 * 3 miles = 6 miles.

Similarly, DB equals 2 * DE = 2 * 3 miles = 6 miles.

Thus, the sum of the lengths of the two trails, AC and BD, is 6 miles + 6 miles = 12 miles.

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The complete question is given below:

The parallelogram shown represents a map of the boundaries of a natural preserve. Walking trails run from points A to C and from points B to D. The measurements shown represent miles.

What is the sum of the lengths of the two trails?

A. 6 miles

B. 12 miles

C. 16 miles

D. 36 miles

Answer:

{-4,3,5,8}

Step-by-step explanation:

The function is in (a,b) form. Always remember that range comes after domain. So here a represents the domain and b represents the range.

In the given function:

{(-1,5),(2,8),(5,3),(13,-4)}

The range will be {5,8,3,-4}

We will write it in ascending order

{-4,3,5,8} ....

Answer:

Part 1)  3 --------> [tex]3\frac{3}{7}[/tex] ÷ [tex]1\frac{1}{7}[/tex]

Part 2) -3 -------> [tex]-2\frac{2}{5}[/tex] ÷ [tex]\frac{4}{5}[/tex]

Part 3) 2 --------> [tex]-12.2[/tex] ÷ [tex]-6.1[/tex]

Part 4) -2 -------> [tex]-16[/tex] ÷ [tex]8[/tex]

Step-by-step explanation:

Part 1) we have

[tex]3\frac{3}{7}[/tex] ÷ [tex]1\frac{1}{7}[/tex]

Convert mixed number to an improper fraction

[tex]3\frac{3}{7}=\frac{3*7+3}{7}=\frac{24}{7}[/tex]

[tex]1\frac{1}{7}=\frac{1*7+1}{7}=\frac{8}{7}[/tex]

Substitute

The quotient is equal to

[tex](\frac{24}{7})/(\frac{8}{7})=\frac{24}{8}=3[/tex]

Part 2)

we have

[tex]-2\frac{2}{5}[/tex] ÷ [tex]\frac{4}{5}[/tex]

Convert mixed number to an improper fraction

[tex]-2\frac{2}{5}=-\frac{2*5+2}{5}=-\frac{12}{5}[/tex]

Substitute

The quotient is equal to

[tex](-\frac{12}{5})/(\frac{4}{5})=-\frac{12}{4}=-3[/tex]

Part 3) we have

[tex]-12.2[/tex] ÷ [tex]-6.1[/tex]

Convert decimal number to an improper fraction

[tex]-12.2=(-12.2)*\frac{10}{10}=-\frac{122}{10}[/tex]

[tex]-6.1=(-6.1)*\frac{10}{10}=-\frac{61}{10}[/tex]

Substitute

The quotient is equal to

[tex](-\frac{122}{10})/(-\frac{61}{10})=\frac{122}{61}=2[/tex]

Part 4)  we have

[tex]-16[/tex] ÷ [tex]8[/tex]

Remember that

[tex]-16=-8*2[/tex]

Substitute

The quotient is equal to

[tex](-8*2)/(8)=-2[/tex]

Answer:

the guy above me got it and i needed the points sorry lol

Step-by-step explanation:

Answer:

Satish will pay $64.8

Step-by-step explanation:

Kilometres when Satish is alone

150 kilometres in the beginning

150 kilometres in the end

Total: 300 kilometres

Kilometres when Satish is with friends

Total km: 2100

Satish Travelled alone: 300

Kilometres when Satish is with friends: 2100-300 = 1800 km

Litres of gas when Satish is alone

6 litres of gas per 100 kilometres

6 x 3 for 300 kilometres = 18 litres

Litres of gas when Satish is with friends

6 litres of gas per 100 kilometres

6 x 18 for 1800 kilometres = 108 litres

Cost of gas when Satish is alone

$1.2 per litre

18 x 1.2 = $21.6

Cost of gas when Satish is with friends

$1.2 per litre

108 x 1.2 = $129.6

Cost for each friend = $129.6/3 = $43.2

Satish will pay: Cost when travelled with friends + Cost when travelled alone

=$43.2+ $21.6

=$64.8

So, Satish will pay $64.8

Answer:

He will pay $ 64.8

Step-by-step explanation:

Given,

The total distance of the trip = 2100 km,

∵ Sathish pick up his 2 friends 150 kilometers after he begins the trip and drop off when there are 150 kilometer remaining.

So, the number of kilometres for which he and his friends pay the costs = 2100 - (150+150)

= 2100 - 300

= 1800 km,

Now, the quantity of gas for 100 km = 6 liters,

So, the quantity of gas for 1800 km = 18 × 6 = 108 liters,

If the cost of gas is $ 1.20 per liters,

Then the total cost paid by them ( when satish is not alone )  

[tex]=\text{gas consumed in liters}\times \text{cost per liters}[/tex]

[tex]=108\times 1.2[/tex]

[tex]=\$ 129.6[/tex]

∵ they split this cost evenly,

So, the share of satish ( when he is with his friend ) = [tex]\frac{129.6}{3}[/tex] = $ 43.2

For the remaining 300 km, he paid the cost of gas,

Again, the quantity of gas for 100 km = 6 liters

⇒ The quantity of gas for 300 km = 18 liters,

Thus, the cost he paid when he was alone = 18 × cost of gas for 1 liter

= 18 × 1.2

= $ 21.6

Hence, the total amount paid by satish = $ 43.2 + $ 21.6 = $ 64.8

Answer:

Step-by-step explanation:

<, > - dotted line

≤, ≥ - solid line

x ≤ a or x < a - the region below the horizontal line x = a

x ≥ a or x > a - the region above the horizontal line x = a

y ≤ a or y < a - the region on the left side of the vertical line y = a

y ≥ a or y > a - the region to the right of the vertical line y = a

=========================================

We have dotted line (<, >).

The vertical line (y).

The region on the left side of the vertical dotted line y = -3

The ":" is actually a division, a fraction.

So part a is therefore,

[tex]\dfrac{w}{100}=\dfrac{12}{25}[/tex]

Here we use cross multiplication,

[tex]\dfrac{a}{b}=\dfrac{c}{d}\Longleftrightarrow ad=bc[/tex]

And we have,

[tex]

25w=12\cdot100 \\

w=\dfrac{12\cdot100}{25}=\dfrac{1200}{25}=\boxed{48}

[/tex]

Now part b.

First convert 2m to cm. 1m = 100cm therefore 2m is 200cm.

Now we have simplified to,

[tex]\dfrac{180}{200}=\dfrac{1.8}{2}=\dfrac{\dfrac{18}{10}}{2}=\dfrac{\dfrac{9}{5}}{2}=\boxed{\dfrac{9}{10}=9:10}

[/tex]

Hope this helps.

r3t40

Answer:

0

Step-by-step explanation:

0 would be the individual function because 0 is only one number so if you were to multiply 0x(x) then it would be 0x.

Answer:

4

Step-by-step explanation:

if we see the table as being a numerical representation of a graph in the x-y plane, the first column will represent the x-values (i.e the domain) and the second column will represent the y-values (i.e the range).

That is to say, the x-values are the inputs into the function that will spit out the y-values as outputs.

By observation, we can see that when x = 0 (i.e the initial value of the input), that the resulting function output is y =4 (i.e the initial value of the output).

Hence the initial value of the function (i.e the output) is 4

Answer:

rhombus, rectangle

Step-by-step explanation:

All parallelograms have two pairs of parallel sides.

A rhombus is a parallelogram. A rectangle is a parallelogram.

A trapezoid is not a parallelogram.

Answer: rhombus, rectangle

Answer:

AB is longer than FD.

Step-by-step explanation:

This is an SAS triangle problem.

According to the law of cosines,

c^2 = a^2 + b^2 - 2abcosC

In triangle ABC, a = BC, b = AC, and c = AB

In triangle FDE, a = DE, b = FE, and c = FD.

The only difference is that C is 72° in one triangle and 65° in the other.

We know that cos0° = 1 and cos 90° = 0, so cos72° < cos65°.

In triangle ABC, cosC is smaller, so you are subtracting a smaller number from a^2 + b^2.

c^2 is larger, so c is larger.

AB is longer than FD.

That makes sense because, as you widen the angle between your outstretched arms, the distance between your hands increases.

The statement which correctly compares AB and FD is AB is longer than FD.

A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.

Sum of the interior angles of a triangle is 180 degrees.

Given two triangles, ABC and DEF.

We have to find the relationship between the sides AB and FD.

Given that,

Sides AC and FE are congruent.

Sides BC and DE are congruent.

Included angles, ∠C = 72° and ∠E = 65°

The side opposite to larger angle will be larger.

So AB is longer than FD.

Hence AB is longer than FD.

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Answer: [tex]27p^{26}[/tex]

Step-by-step explanation:

In this case, you need to use the Power of a power property, which states that:

[tex](a^m)^n=a^{mn}[/tex]

And the Product of powers property, which states that:

[tex](a^m)(a^n)=a^{(m+n)}[/tex]

Then, applying this, we get the following product:

[tex](3p^4)^3*(p^2)^7=27p^{(4)(3)}*p^{(2)(7)}=27p^{12}*p^{14}=27p^{(12+14)}=27p^{26}[/tex]

Answer: 3.

Hassan is incorrect because StartRoot 0.15 EndRoot is less than 0.4.    

Step-by-step explanation:

Hassan used the iterative process to locate StartRoot 0.15 EndRoot on the number line.

A number line going from 0 to 0.9 in increments of 0.1. A point is between 0.4 and 0.5.

Which best describes Hassan’s estimation?

Hassan is correct because StartRoot 0.15 EndRoot almost-equals 0.4

Hassan is correct because the point is on the middle of the number line.

Hassan is incorrect because StartRoot 0.15 EndRoot is less than 0.4.    

Hassan is incorrect because the point should be located between 0.1 and 0.2.

Answer:

Domain [-5,3)

Range [0,2]

Step-by-step explanation:

Domain is where the function exists for the x's.

The graph starts at x=-5 and ends at x=3. The graph includes what happened at x=-5 but not at x=3. Since there are no breaks in the graph, the graph exists for x values bigger that or equal to -5 but less than 3.

The domain is [-5,3) in interval notation.

Range is very similar except it is for the y values. So the graph starts at y=0 and stops at y=2. It includes something happening at both and there are no breaks between y=0 and y=2.

The range in interval notation is [0,2].

The values are (x = -5) and (x = 3). But the graph includes what happened at (x = -5) but not (x = 3), therefore, the domain is [-5,0). The values are (y = 0) and (y = 2) and the graph includes what happened at (y = 0) and (y = 2), therefore, the range is [0,2].

Domain is nothing but the value of x in the equation (y = f(x)) and range is nothing but the value of y in the equation (y = f(x)).

So, from the given graph there are two values of 'x' at which the graph of the function gets started and ends.

The values are (x = -5) and (x = 3). But the graph includes what happened at (x = -5) but not (x = 3). Therefore, the domain of the given graph is:

[tex]x\; \epsilon\;[-5,3)[/tex]

Similarly, there are two values of 'y' at which the graph of the function gets started and ends.

The values are (y = 0) and (y = 2) and the graph includes what happened at (y = 0) and (y = 2). Therefore, the range of the given graph is:

[tex]y\; \epsilon\;[0,2][/tex]

For more information, refer to the link given below:

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Answer:

C is the correct option

Step-by-step explanation:

To find the probability of P(a or b) we will use  the formula:

P(a or b)= P(a)+ P(b) - P(a-b)

Now put the given values in the formula:

P(a or b)= 0.60+0.25-0.15

P(a or b)=0.85 - 0.15

P(a or b)= 0.70

Thus the correct option is C....

Answer: Option C

[tex]P (A\ or\ B) = 0.70[/tex]

Step-by-step explanation:

If A and B are events that are not mutually exciting, then it is true that:

[tex]P (A\ or\ B) = P (A) + P (B) - P (A\ and\ B)[/tex]

In this case we know [tex]P(A)[/tex], [tex]P(B)[/tex] and we also know [tex]P (A\ and\ B)[/tex]

[tex]P(A)=0.60[/tex]

[tex]P(B) = 0.25[/tex]

[tex]P(A\ and\ B)=0.15[/tex]

Therefore we have that:

[tex]P (A\ or\ B) = 0.60 + 0.25 - 0.15[/tex]

[tex]P (A\ or\ B) = 0.60 + 0.1[/tex]

[tex]P (A\ or\ B) = 0.70[/tex]

Out of those 80 counters, 20 counters may have a white dab on them.

Total number of counters in the bag = 200

counters that have a white dab = 50

counters that are now taken out of the bag = 80

Let's first take the ratio of counters that have a white dab to the total number of counters in the bag.

[tex]\rm{=\dfrac{counters\ that\ have\ a\ white\ dab}{Total\ number\ of\ counters\ in\ the\ bag}[/tex]

[tex]=\dfrac{50}{200} = \dfrac{1}{4} = 0.25[/tex]

Therefore, the ratio of counters that have a white dab to the total number of counters in the bag is 0.25.

As the bag is given  a good shake to ensure even distribution of the marked counters.

Those 80 counters will follow the same ratio of the bag, so, the number of tokens with white dab will be,

Number of tokens taken out x ratio of the bag

= 80 x 0.25

= 20

Hence, out of those 80 counters, 20 counters may have a white dab on them.

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You need a picture deficiencies did that for 20 characters

first, lets solve by factoring:

Let's solve your equation step-by-step.

2x2+14x−4=−x2+3x

Step 1: Subtract -x^2+3x from both sides.

2x2+14x−4−(−x2+3x)=−x2+3x−(−x2+3x)

3x2+11x−4=0

Step 2: Factor left side of equation.

(3x−1)(x+4)=0

Step 3: Set factors equal to 0.

3x−1=0 or x+4=0

x=

1

3

or x=−4

we can also solve using the quadratic formula:

2x2+14x−4=−x2+3x

Step 1: Subtract -x^2+3x from both sides.

2x2+14x−4−(−x2+3x)=−x2+3x−(−x2+3x)

3x2+11x−4=0

Step 2: Use quadratic formula with a=3, b=11, c=-4.

x=

−b±√b2−4ac

2a

x=

−(11)±√(11)2−4(3)(−4)

2(3)

x=

−11±√169

6

x=

1

3

or x=−4

lastly, we can complete the square.

2x2+14x−4=−x2+3x

Step 1: Add x^2 to both sides.

2x2+14x−4+x2=−x2+3x+x2

3x2+14x−4=3x

Step 2: Subtract 3x from both sides.

3x2+14x−4−3x=3x−3x

3x2+11x−4=0

Step 3: Add 4 to both sides.

3x2+11x−4+4=0+4

3x2+11x=4

Step 4: Since the coefficient of 3x^2 is 3, divide both sides by 3.

3x2+11x

3

=

4

3

x2+

11

3

x=

4

3

Step 5: The coefficient of 11/3x is 11/3. Let b=11/3.

Then we need to add (b/2)^2=121/36 to both sides to complete the square.

Add 121/36 to both sides.

x2+

11

3

x+

121

36

=

4

3

+

121

36

x2+

11

3

x+

121

36

=

169

36

Step 6: Factor left side.

(x+

11

6

)2=

169

36

Step 7: Take square root.

x+

11

6

=±√

169

36

Step 8: Add (-11)/6 to both sides.

x+

11

6

+

−11

6

=

−11

6

±√

169

36

x=

−11

6

±√

169

36

x=

1

3

or x=−4

Answer:

x=

1

3

or x=−4

Final answer:

The equation [tex]2x^2 + 14x - 4 = -x^2 + 3x[/tex] is a quadratic equation, which can be solved by standard methods such as factoring, completing the square, or applying the quadratic formula and then validated by substituting the solutions back into the original equation.

Explanation:

To solve the quadratic equation, [tex]2x^2 + 14x - 4 = -x^2 + 3x[/tex], first combine like terms by getting all terms on one side of the equation, resulting in [tex]3x^2 + 11x - 4[/tex] = 0. This is a standardized quadratic equation [tex]ax^2[/tex] + bx + c = 0. To find the solutions for this equation, you can either factorize it, complete the square or use the quadratic formula, (-b ± √([tex]b^2[/tex] - 4ac)) / (2a). After finding the roots (values for x), verify them by plugging them back into the original equation to ensure they satisfy it.

Answer:

p = 650 – v and 4p + 9v = 2,925 , Its B

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Answer:

b

Step-by-step explanation:

Answer:

(1, 3)

(2, 2)

(3, 1)

Step-by-step explanation:

Substitute x and y with the numbers given

2(1) + 2(3) = 8

2(2) + 2(2) = 8

2(3) + 2(1) = 8

Answer

(1, 3)

(2, 2)

(3, 1)

Answer:

B. 3x3+6x−2

Step-by-step explanation:

When you divide 3x3+6x−2 by x+1 we get a remainder of -11.

Answer:

x+6y=150

Step-by-step explanation:

If you add 6y to both sides of the equation, it becomes this, making it equal.

Answer:

x+6y = 150 (B)

Step-by-step explanation:

Given the equation x = 150-6y

The equation is also equivalent to

x+6y = 150.

This is gotten simply by taking -6y to the other side of the equation but note that if a function or constant is crossing an 'equal to' sign in an equation, it changes the sign. Considering this equation, -6y changed to +6y upon crossing the equal to sign to give is x+6y = 150 which is the required answer.

Answer:

1

Step-by-step explanation:

We are to find the value of the following:

[tex] log _ 3 5 \times log _ { 2 5 } 9 [/tex]

[tex] \log _ { 3 } 5 \times \log _ { 2 5 } 9 =\dfrac{1}{\log_{5}3}\times\log_{25}9=\dfrac{1}{\log_{5}3}\times\log_{5^2}9=\dfrac{1}{\log_{5}3}\times\dfrac{1}{2}\log_{5}9[/tex]

[tex] \dfrac { 1 } { \log _ { 5 } 3 } \times \dfrac { 1 } { 2 } \log_ { 5 } 9 = \dfrac{1}{\log_{5}3}\cdot\dfrac{1}{2}\log_{5}3^2=\dfrac{1}{\log_{5}3}\cdot\dfrac{2}{2}\log_{5}3=\dfrac{1}{\log_{5}3}\cdot\log_{5}3=\dfrac{\log_{5}3}{\log_{5}3}=[/tex] 1

Answer:

The value is: 1

Step-by-step explanation:

Use the Change of base formula. This is:

[tex]log_a(x)=\frac{log_b(x)}{log_b(a)}[/tex]

Using base 10:

[tex]log_3(5)*log_{25}(9)=\frac{log(5)}{log(3)}*\frac{log(9)}{log(25)}[/tex]

We know that:

[tex]9=3^2\\25=5^2[/tex]

And according to the logarithms properties:

[tex]log(x)^n=nlog(x)[/tex]

Then, we can simplify the expression:

[tex]=\frac{log(5)}{log(3)}*\frac{log(3)^2}{log(5)^2}=\frac{log(5)}{log(3)}*\frac{2log(3)}{2log(5)}=\frac{log(5)}{log(3)}*\frac{log(3)}{log(5)}=\frac{log(5)*log(3)}{log(3)*log(5)}=1[/tex]

Answer:

The zeros of the quadratic polynomial are

[tex]x=\frac{15\sqrt{5}}{10}[/tex]  and [tex]x=-\frac{3\sqrt{5}}{10}[/tex]

The relationship between its zeroes and coefficients in the procedure

Step-by-step explanation:

step 1

Find the zeros

we know that

The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]4\sqrt{5}x^{2}-24x-9\sqrt{5}=0[/tex]

so

[tex]a=4\sqrt{5}\\b=-24\\c=-9\sqrt{5}[/tex]

substitute in the formula

[tex]x=\frac{-(-24)(+/-)\sqrt{-24^{2}-4(4\sqrt{5})(-9\sqrt{5})}} {2(4\sqrt{5})}[/tex]

[tex]x=\frac{24(+/-)\sqrt{-24^{2}-4(4\sqrt{5})(-9\sqrt{5})}} {8\sqrt{5}}[/tex]

[tex]x=\frac{24(+/-)\sqrt{1,296}} {8\sqrt{5}}[/tex]

[tex]x=\frac{24(+/-)36} {8\sqrt{5}}[/tex]

[tex]x=\frac{24(+)36} {8\sqrt{5}}=\frac{15\sqrt{5}}{10}[/tex]

[tex]x=\frac{24(-)36} {8\sqrt{5}}=-\frac{3\sqrt{5}}{10}[/tex]

step 2

Find the sum of the zeros and the product of the zeros

Sum of the zeros

[tex](\frac{15\sqrt{5}}{10})+(-\frac{3\sqrt{5}}{10})=\frac{12\sqrt{5}}{10}=\frac{6\sqrt{5}}{5}[/tex]

Product of the zeros

[tex](\frac{15\sqrt{5}}{10})*(-\frac{3\sqrt{5}}{10})=-\frac{9}{4}[/tex]

step 3

Verify that

Sum of the zeros= -Coefficient x/Coefficient x²

Coefficient x=-24

Coefficient x²=4√5

substitute

[tex]\frac{6\sqrt{5}}{5}=-(-24)/4\sqrt{5}\\ \\\frac{6\sqrt{5}}{5}=\frac{6\sqrt{5}}{5}[/tex]

therefore

the relationship is verified

step 4

Verify that

Product of the zeros= Constant term/Coefficient x²

Constant term=-9√5

Coefficient x²=4√5

substitute

[tex]-\frac{9}{4}=(-9\sqrt{5})/4\sqrt{5}\\ \\-\frac{9}{4}=-\frac{9}{4}[/tex]

therefore

the relationship is verified    

Step-by-step explanation:

1 1-5 Measuring Segments Find the distance between two points using the Ruler Postulate Determine the length of a segment using the Segment Addition Postulate.

Answer:

26.

Step-by-step explanation:

We are asked to find the distance between -18 and 8  using the ruler postulate.

The ruler postulate states that the distance between two pints on a ruler is the absolute value of the difference between the numbers shown on ruler.

So the distance between -18 and 8 would be [tex]|-18-8|=|-26|=26[/tex].

Therefore, the distance between -18 and 8 is 26.

Answer:

$ 134,628

Step-by-step explanation:

1. make 3.8 into a percent round decimal to the right 2 times

2.multiply the total with the percent

3.solve

4.take answer and subtracted from the total

5.solve

6. subtract the number you got from the first solution problem from the last problen solution

7.solve

Answer: $21,316.1

Step-by-step explanation:

Given :  For every house you sell you earn 3.8% commission.

Which can be written as 0.038.

This month you sold 2 houses that had a combined total of $560,950

Then, the amount of commission you will earn is given by :-

[tex]\$560,950\times0.038=\$21,316.1[/tex]

Therefore, the you will earn $21,316.1 as commission.

[tex]\huge{\boxed{-\frac{1}{2}}}[/tex]

We can find the slope with [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are both points.

Plug in the values. [tex]\frac{1-(-3)}{-4-4}[/tex]

Simplify. [tex]\frac{1+3}{-4-4}[/tex]

Add/subtract. [tex]\frac{4}{-8}[/tex]

Simplify. [tex]\boxed{-\frac{1}{2}}[/tex]

Answer:

No.

The slope of the line is -1/2.

Step-by-step explanation:

I'll give you a hint, to solve slope of the line use [tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex].

[tex]\displaystyle \frac{1-(-3)}{(-4)-4}=\frac{4}{-8}=\frac{4\div4}{-8\div4}=\frac{1}{-2}=-\frac{1}{2}[/tex]

The slope of the line is -1/2, which is our answer.

I hope this helps!