Find the area of the following circle. (Round answer to the nearest hundredth.)
d = 15 in
area = _____ square inches
circumference = ______ inches

Final answer:

The rate of change in the linear equation y=16500-1500x is -1500, indicating that y decreases by 1500 for each increase in x by one unit. This represents the slope of the line and shows a direct relationship between x and y in a regression line context.

Explanation:

In the equation y=16500-1500x, the rate of change is represented by the coefficient of x, which is -1500. This means that for each unit increase in x, the value of y decreases by 1500. Contrary to the provided reference which mistakenly lists the slope as -105,000/1, the actual rate of change in this linear equation is -1500. Such linear equations are often used to describe a regression line, which showcases the average relationship between the variables x and y in a scatter diagram.

The slope of a line in a linear equation like this one is crucial for understanding how changes in one variable affect another. This linear model is straightforward and does not change across different values of x, unlike in nonlinear models where the rate of change can vary.

Answer:

1) Option B-  $728

2) Kara's annual premium is $62.5.

Step-by-step explanation:

1) Given : Daniel, a 37-year-old male, bought a $160,000, 10-year life insurance policy.

To find : What is Daniel's annual premium?

Solution :

In the table given,

Annual premium is per $1000 of coverage.

Daniel's life insurance policy buy is $160,000  

Annual premium per $1000 coverage Daniel buy at $160

37 year old male 10 year cost is $4.55

(marked in the attached table below)

Daniel's annual premium is [tex]4.55\times 160[/tex]

[tex]=\frac{455}{100}\times 160[/tex]

[tex]=728[/tex]

Daniel's annual premium is $728

Therefore, Option B is correct.

2) Given : Kara, a 25-year-old female, bought a $50,000, 10-year life insurance policy through her employer. Kara is paid semimonthly.

To find : How much is deducted from each of her paychecks for life insurance?

Solution :

In the table given,

Annual premium is per $1000 of coverage.

Kara's life insurance policy buy is $50,000  

Annual premium per $1000 coverage Kara buy at $50

25 year old female 10 year cost is $2.50

(marked in the attached table below)

Kara is paid semimonthly

So, cost is[tex]\frac{2.50}{2}=1.25[/tex]

Kara's annual premium is [tex]1.25\times 50[/tex]

[tex]=\frac{1.25}{100}\times 50[/tex]

[tex]=62.5[/tex]

Kara's annual premium is $62.5.

The transformation that could NOT have been applied to the original figure to create an image with the same area is:

C. Dilation by a scale factor of 0.5.

To determine which transformation could NOT have been applied to the original figure to create the image with the same area, let's analyze each option:

A. Rotation of 90 degrees: When a figure is rotated by 90 degrees, the area remains the same.

This transformation is possible.

B. Reflection across a horizontal line: A reflection across a horizontal line (a horizontal flip) preserves the area of the figure.

This transformation is possible.

C. Dilation by a scale factor of 0.5: Dilation involves scaling a figure by a certain factor.

If a figure is dilated by a scale factor of 0.5, both its length and width are reduced to half, which means the area is reduced to one-fourth of the original area.

This transformation is not possible because it changes the area.

D. Translation down 4 and then right 1: A translation moves a figure without changing its size or shape. A translation down 4 and then right 1 would not change the area of the figure, as it simply shifts the figure's position.

This transformation is possible.

So, the transformation that could NOT have been applied to the original figure to create an image with the same area is:

C. Dilation by a scale factor of 0.5

Dilation by a scale factor of 0.5 would change the area, making it incompatible with the condition that the areas of the original figure and its image are the same.

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Answer:

- 1/2

Step-by-step explanation:

I just did it

Answer:

Option a )  $19,925

Step-by-step explanation:

$15,000 was invested for 9 years and then $4,000 was withdrawn after 2 years.

So, $11,000 was invested for entire 9 years and $4,000 was invested for 2 years.

Interest on $11,000 for 9 years @ 8.5 % = 11,000 X 9 X 8.5 % = $8,415

Interest on $4,000 for 2 years @ 8.5 % = 4,000 X 2 X 8.5 % = $680

Penalty for withdrawing $4,000 = 4000 X 8.5 % X 0.5 = $170

Total amount that Rachel will get on maturity = $11,000 + total interest - penalty = $11,000 + $8,415 + $680 - $170 = $19,925

Hope it helps.

Thank you !!

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

[tex]5x^2+14x-3[/tex]

As we know "Split the middle term":

[tex]5x^2+15x-x-3\\\\=5x(x+3)-1(x+3)\\\\=(5x-1)(x+3)[/tex]

Since it is quadratic equation so, it has 2 roots.

So, the roots are (x+3) and (5x-1).

Hence, Option 'B' is correct.

C is the correct choice.

Given that Jeff volunteers his time by working at an animal shelter, and each year he works for a total of 240 hours, and so far this year, he has worked 97 hours, to determine which equation will solve for how many more hours (h ) Jeff will volunteer for, the following calculation must be performed:

Therefore, C is the correct choice.

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Let assume that [tex]\sqrt7[/tex] is a rational number. Therefore it can be expressed as a fraction [tex]\dfrac{a}{b}[/tex] where[tex]a,b\in\mathbb{Z}[/tex] and [tex]\text{gcd}(a,b)=1[/tex].

[tex]\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2[/tex]

This means that [tex]a^2[/tex] is divisible by 7, and therefore also [tex]a[/tex] is divisible by 7.

So, [tex]a=7k[/tex] where [tex]k\in\mathbb{Z}[/tex]

[tex](7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2[/tex]

Analogically to [tex]a^2=7b^2[/tex] ------- [tex]b^2[/tex] is divisible by 7 and therefore so is [tex]b[/tex].

But if both numbers [tex]a[/tex] and [tex]b[/tex] are divisible by 7, then [tex]\text{gcd}(a,b)=7[/tex] which contradicts our earlier assumption that [tex]\text{gcd}(a,b)=1[/tex].

Therefore [tex]\sqrt7[/tex] is an irrational number.

Final answer:

To prove that √7 is irrational, we assume the opposite and show that it leads to a contradiction. We start by assuming that √7 is rational and can be expressed as a fraction. By squaring both sides of the equation and simplifying, we get an equation that leads to p and q being divisible by 7, which contradicts our initial assumption. Therefore, √7 must be irrational.

Explanation:

To prove that √7 is irrational using the method of contradiction, we assume the opposite, which is that √7 is rational. This means that it can be expressed as a fraction p/q, where p and q are integers with no common factors other than 1. We can then square both sides of the equation (√7)² = (p/q)² and simplify to get the equation 7 = p²/q². Rearranging, we have p²= 7q².

From this equation, we can deduce that p² is divisible by 7, which means p must also be divisible by 7. Let's represent p as 7r, where r is another integer. Substituting back into the equation, we get (7r)² = 7q², which simplifies to 49r² = 7q². Dividing both sides by 7, we have 7r² = q². This implies that q² is also divisible by 7, so q must also be divisible by 7.

However, if both p and q are divisible by 7, this contradicts our initial assumption that p/q has no common factors other than 1. Therefore, our assumption that √7 is rational must be false, and hence √7 is irrational.

Answer: D. yes; y = –3.3x

Step-by-step explanation:

Answer:

$66.97 is his first payment went toward reduction.

Step-by-step explanation:

Given : Jesse took out a 30-year loan for $85,000 at 7.2% interest, compounded monthly. If his monthly payment on the loan is $576.97.

To find : How much of his first payment went toward note reduction(reducing principal)?  

Solution :

First we find the interest of 1 month on a loan of $85,000 at 7.2% interest.

[tex]I=85000\times \frac{7.2}{12\times 100}[/tex]

[tex]I=85000\times 0.006[/tex]

[tex]I=510[/tex]

Interest of 1 month is $510.

Monthly payment = $576.97

Now, first payment or reducing principal is given by

F= monthly payment - interest of 1 month

F=$576.97- $510

F=$66.97

Therefore, $66.97 is his first payment went toward reduction.

The degree of any given polynomial is said to be the highest power in the exponent of variables given in the polynomial.

For example, quadratic equations like (4x² + 4x + 1) have degree 2.

Here given polynomial is (a⁴ + b³ - 2a·b + c), this polynomial is a multivariable expression.

It is clearly visible that the highest power in the exponent of its variables is 4.

So, the degree of the given polynomial is 4.

The apothem (a), radius (r), and perimeter (p) of a regular figure are defined as follows: the apothem is the perpendicular distance from the center of the figure to one of its sides, the radius is the distance from the center of the figure to any point on its circumference, and the perimeter is the total length of all its sides.

The apothem (a) of a regular figure is the perpendicular distance from the center of the figure to one of its sides.

The radius (r) of a regular figure is the distance from the center of the figure to any point on its circumference.

The perimeter (p) of a regular figure is the total length of all its sides.

Answer:

B.) $1198.40

Step-by-step explanation:

Given,

The original price of the bed = $ 1600,

Since, in sale, he got 30 % off,

The price of bed in sale = The original price of the bed - 30 % of the original price of the bed

[tex]= 1600 - 30\% \text{ of } 1600[/tex]

[tex]=1600-\frac{30\times 1600}{100}[/tex]

[tex]=1600-\frac{48000}{100}[/tex]

[tex]=1600-480=\$ 1120[/tex]

Also, there is a sales tax of 7 % ,

Thus, the final price of the bed = The price of bed in sale  + 7 % of the price of bed in sale

[tex]=1120+\frac{7\times 1120}{100}[/tex]

[tex]=1120+\frac{7840}{100}[/tex]

[tex]=1120+78.40=\$1198.40[/tex]

Hence, he paid $ 1198.40.

Point P is on the unit circle U. The values of trigonometric functions at t are [tex]sin\theta=\dfrac{8}{17},\;cos\theta=-\dfrac{15}{17}[/tex][tex],tan\theta=-\dfrac{8}{15},\;cot \theta=-\dfrac{15}{8},\;cosec\theta=\dfrac{17}{8},\;sec\theta=-\dfrac{17}{15}[/tex].

Given:

From the given figure, the coordinate of point P is [tex](-\dfrac{15}{17}, \dfrac{8}{17})[/tex].

The point P is present on a unit circle U. So, in general, the coordinates of a point on the circle will be [tex](x,y)\equiv (cos\theta, sin\theta)[/tex].

By comparing the given coordinate with the general expression, the value sine and cosine function will be,

[tex]sin\theta=\dfrac{8}{17}\\cos\theta=-\dfrac{15}{17}[/tex]

Now, the other trigonometric functions will be,

[tex]tan\theta=\dfrac{sin\theta}{cos\theta}\\tan\theta=-\dfrac{8}{15}\\cot \theta=-\dfrac{15}{8}\\cosec\theta=1/sin\theta=\dfrac{17}{8}\\sec\theta=1/cos\theta=-\dfrac{17}{15}[/tex]

Therefore, the values of trigonometric functions at t are [tex]sin\theta=\dfrac{8}{17},\;cos\theta=-\dfrac{15}{17}[/tex][tex],tan\theta=-\dfrac{8}{15},\;cot \theta=-\dfrac{15}{8},\;cosec\theta=\dfrac{17}{8},\;sec\theta=-\dfrac{17}{15}[/tex].

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Using translation concepts, it is found that the equation of the resulting graph is given by:

[tex]y = \sqrt[3]{x + 4} - 5[/tex]

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the changes are given as follows:

Hence the equation of the resulting graph is given by:

[tex]y = \sqrt[3]{x + 4} - 5[/tex]

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The equation of the graph \\sqrt[3]{x} shifted down by 5 units and to the left by 4 units is \\sqrt[3]{x + 4} - 5.

The transformation of the graph of y = \\sqrt[3]{x} down by 5 units and to the left by 4 units is represented by the function y = \\sqrt[3]{x + 4} - 5. When a graph is shifted to the left by 'a' units, we replace 'x' in the equation with (x + a). Similarly, when a graph is shifted down by 'b' units, we subtract 'b' from the function, resulting in f(x) - b. Therefore, incorporating both transformations into the original function, we get y = \\sqrt[3]{x + 4} - 5.

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