Find the coordinates of point Q.

Find The Coordinates Of Point Q.

Answers

Answer 1

Answer:

Q(2, 6 )

Step-by-step explanation:

Using the midpoint formula

let the coordinates of Q = (x, y ), then

0.5(x + 10) = 6 ( multiply both sides by 2 )

x + 10 = 12 ( subtract 10 from both sides )

x = 2

and

0.5(y + 6) = 6 ( multiply both sides by 2 )

y + 6 = 12 ( subtract 6 from both sides )

y = 6

Coordinates of Q = (2, 6 )


Related Questions

Under fair value option, which of the following affects the income the investor recognizes from its ownership in the investee
A. The investees reported income adjusted for excess cost over book value amortization

B. Changes in the fair value of the investors ownership shares of the investee

C. Intra-equity profits from upstream sales

D. Extraordinary items reported by the investee

Answers

Answer:

B. Changes in the fair value of the investors ownership shares of the investee

Step-by-step explanation:

The fair value option is defined as the alternative for any business that helps them to record its financial instruments at their fair values.

The answer is : Changes in the fair-value of the investor's ownership in shares of the investee.

Rosa had 3 baskets. She had 35 plums. She put the same number of plums in each basket. Now she has 5 plums left over. How many plums did Rosa put in each basket?

Answers

Answer:

10 in each with 5 left over

Step-by-step explanation:

If she has five left over, that means she split 30 plums in three baskets. 30÷3 = 10. So there were 10 plums in each basket.

Linda and Juan went shopping. Linda spent $13 less than Juan. If we let z z represent how much Juan spent, write an algebraic expression for how much Linda spent. Preview

Answers

Answer:

L= z z -$13

Step-by-step explanation:

We will write "L" for Linda and" z z" for Juan.

As linda spent $13 less than Juan, It is that Linda spent $13 less than zz.

We must substract $13 to what zz spent to obtain what Linda spent. That is,

L = zz - $13

The algebraic expression for how much Linda spent is z - 13, where z represents how much Juan spent.

To represent how much Linda spent, we can use the algebraic expression z - 13.

We will write "L" for Linda and" z z" for Juan.

Since Linda spent $13 less than Juan,

we subtract 13 from the amount Juan spent to get the amount Linda spent.

As linda spent $13 less than Juan, It is that Linda spent $13 less than zz.

We must substract $13 to what zz spent to obtain what Linda spent. That is,

L = zz - $13

So the expression for how much Linda spent is z - 13.

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Which of the following functions is graphed below?

Answers

Answer:

C

Step-by-step explanation:

For this problem, the point where the line changes its slope is the focus point. The trick for this is to find the x point for the point. You have to look at he absolute value parenthesis, for this just put the opposite negative value of the number being added or subtracted inside the parenthesis. The "b" (y=mx+b) for the equation, isn't changed at all, so -2 would be the y value.

2. Which memory locations are assigned by the hashing function h(k) = k mod 101 to the records of insurance company customers with these Social Security numbers? a) 104578690 b) 432222187 c) 372201919 d) 501338753

Answers

Answer:

Memory Locations assigned

a) 58 b) 60 c) 52 d) 3  

Step-by-step explanation:

We are given that:

h(k) = k mod 101

To find the memory location, we need to evaluate the modulus value abbreviated as mod, k modulo n, which returns the value of remainder when k is divided by 101.

a) 104578690

104578690 mod 101 = 58

b) 432222187

432222187 mod 101 = 60

c) 372201919

372201919 mod 101 = 52

d) 501338753

501338753 mod 101 = 3

Final answer:

The memory locations assigned by the hashing function h(k) = k mod 101 to the Social Security numbers are: a) 81, b) 14, c) 15, and d) 38.

Explanation:

The hashing function h(k) = k mod 101 assigns memory locations to records based on the modulus operation. To find the memory locations assigned to the Social Security numbers given, we need to calculate the result of k mod 101 for each number.

For Social Security number 104578690, the result is 81.For Social Security number 432222187, the result is 14.For Social Security number 372201919, the result is 15.For Social Security number 501338753, the result is 38.

Therefore, the memory locations assigned to the records are:

a) 104578690 --> 81b) 432222187 --> 14c) 372201919 --> 15d) 501338753 --> 38

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The following data was collected in an experiment measuring the pressure of a gas (in atmospheres) as a function of temperature (in Kelvin). Temperature (K) Pressure (atm) 273.1 0.987 283.2 1.072 294.1 1.191 305.6 1.202 314.2 1.381 323.8 1.451 336.4 1.576 Plot this data in Excel with the independent variable on the x-axis and use Microsoft Excel to calculate the coefficient of determination (R2). Report the value of R2 here. Note: take care not to confuse the coefficient of determination R2 with R, the ideal gas constant. R2 is a statistical measure that we will include in graphs depicting linear relationships.

Answers

The coefficient of determination R2 calculated by Microsoft Excel is:

R2=0,974024991

Final answer:

To plot the given data in Excel, follow these steps: Create a scatter plot with temperature on the x-axis and pressure on the y-axis. To calculate R2 in Excel, add a trendline and check the 'Display R-squared value on chart' option.

Explanation:

To plot the given data in Excel, follow these steps:

Create a scatter plot in Excel with the temperature data on the x-axis and the pressure data on the y-axis.Enter the given data into two columns in an Excel spreadsheet.Select the data and choose the scatter plot option from the chart types.Format the chart as desired.

To calculate the coefficient of determination (R2) in Excel, follow these steps:

Add a trendline to the scatter plot.Right-click on the trendline and choose 'Format Trendline'.Check the 'Display R-squared value on chart' option.

The calculated coefficient of determination (R2) will be displayed on the chart.

Solve using synthetic division:
(x^5+2x^2+2x+1)/(x^2-1)

Answers

Answer:

  x^3 +x +2 +3/(x -1)

Step-by-step explanation:

Synthetic division can be done using a divisor with a power of the variable other than one, but the most straightforward application of it uses a binomial divisor with a variable coefficient of 1. Fortunately the divisor in this problem is the difference of squares, so can be factored into two divisors. We can make use of synthetic division to divide by one of them, then we can use it again with the other divisor.

  = ((x^5 +2x^2 +2x +1)/(x +1)) / (x -1)

  = (x^4 -x^3 +x^2 +x +1)/(x -1)

  = x^3 +x +2 + 3/(x -1)

The remainder from the second division is simplified by the fact that there is no remainder from the first division. If desired, the final remainder can be expressed over the original divisor as (3x +3)/(x^2 -1) by multiplying numerator and denominator by the first divisor, (x+1).

_____

The synthetic division tableaux are attached. First, we divide by (x+1), then that result is divided by (x-1).

We assume you've been shown how this works. If not, there are numerous web sites and videos that can explain better than is possible in this space.

Ms. Gooden feeds stray cats in the park every evening. She never knows how many cats will come to be fed. The food is always shared equally among the cats that are at the park. One evening, when 6 cups of cat food were shared, each cat received 2 3 cup of cat food. How many cats were fed that evening?

Answers

Answer:

9 cats were fed that evening.

Step-by-step explanation:

6 divided by 2/3 equals 9, so 9 cats were fed that evening.

Hope this helps! ☺

Answer:

There are 9 cats in total

Step-by-step explanation:

Let x be the no. of cats

Each cat received cup of food = [tex]\frac{2}{3}[/tex]

Caps received by x cats = [tex]\frac{2}{3}x[/tex]

We are given that 6 cups of cat food were shared

So, [tex]\frac{2}{3}x=6[/tex]

[tex]x=\frac{3}{2} \times 6 [/tex]

[tex]x=9 [/tex]

Hence there are 9 cats in total .

Can you help me with this please

Answers

Answer:

  see below

Step-by-step explanation:

If (x+5) is a factor of p(x), then the value x=-5 will make that factor be zero. The product p(x) of which it is a part will also be zero, so p(-5) = 0.

Since p(-5) = 0 at x=-5, there will be an x-intercept at x=-5.

Dividing something by a factor of that thing will always give a remainder of zero. So, p(x)/(x+5) has a remainder of 0.

"Events A1, A2 and A3 form a partiton of the sample space S with probabilities P(A1) = 0.3, P(A2) = 0.5, P(A3) = 0.2.If E is an event in S with P(E|A1) = 0.1, P(E|A2) = 0.6, P(E|A3) = 0.8, computeP(E) =P(A1|E) =P(A2|E) =P(A3|E) ="

Answers

Answer with Step-by-step explanation:

We are given that Events [tex]A_1,A_2 \;and\;A_3[/tex] form a partition of the sample space S .

[tex]P(A_1)=0.3,P(A_2)=0.5,P(A_3)=0.2[/tex]

If E is an event in S

[tex]P(E/A_1)=0.1,P(E/A_2)=0.6,P(E/A_3)=0.8[/tex]

[tex]P(E)=P(A_1)\cdot P(E/A_1)+P(A_2)\cdot P(E/A_2)+P(A_3)\cdot P(E/A_3)[/tex]

Substitute the values then we get

[tex]P(E)=(0.3)(0.1)+(0.5)(0.6)+(0.2)(0.8)=0.03+0.30+0.16=0.49[/tex]

[tex]P(E)=0.49[/tex]

Bayes theorem

[tex]P(E_i/A)=\frac{P(E_i)P(A/E_i)}{\sum_{i=1}^{n}P(E_i)P(A/E_i)}[/tex]

Now, using Bayes theorem

[tex]P(A_1/E)=\frac{P(A_1)\cdot P(E/A_1}{P(A_1)P(E/A_1)+P(A_2)P(E/A_2)+P(A_3)P(E/A_3)}[/tex]

Substitute the values then we get

[tex]P(A_1/E)=\frac{0.3\times 0.1}{(0.1)(0.3)+(0.5)(0.6)+(0.2)(0.8)}=\frac{0.03}{0.49}=\frac{3}{49}[/tex]

[tex]P(A_1/E)=\frac{3}{49}[/tex]

Similarly

[tex]P(A_2/E)=\frac{(0.5)(0.6)}{0.49}=\frac{0.30}{0.49}=\frac{30}{49}[/tex]

[tex]P(A_2/E)=\frac{30}{49}[/tex]

[tex]P(A_3/E)=\frac{(0.2)(0.8)}{0.49}=\frac{0.16}{0.49}=\frac{16}{49}[/tex]

[tex]P(A_3/E)=\frac{16}{49}[/tex]

You can use the Bayes' theorem and the law of total probability with chain rule to find the needed probabilities.

The needed probabilities are:

[tex]P(E) = 0.49[/tex][tex]P(A_1|E) = 0.0612[/tex][tex]P(A_2|E) = 0.612[/tex][tex]P(A_3|E) = 0.327[/tex]

What is Bayes' theorem?

Suppose that there are two events A and B. Then suppose the conditional probability are:

P(A|B) = probability of occurrence of A given B has already occurred.

P(B|A) = probability of occurrence of B given A has already occurred.

Then, according to Bayes' theorem, we have:

[tex]\rm P(A|B) = \dfrac{P(B|A)P(A)}{P(B)}[/tex]

(assuming the P(B) is not 0)

What is chain rule in probability?

For two events A and B, by chain rule, we have:

[tex]P(A \cap B) = P(B)P(A|B) = P(A)P(A|B)[/tex]

What is law of total probability?

Suppose that the sample space is divided in n mutual exclusive and exhaustive events tagged as [tex]B_i \: ; i \in \{1,2,3.., n\}[/tex]

Then, suppose there is event A in sample space.

Then probability of A's occurrence can be given as

[tex]P(A) = \sum_{i=1}^n P(A \cap B_i)[/tex]

Using the chain rule, we get

[tex]P(A) = \sum_{i=1}^n P(A \cap B_i) = \sum_{i=1}^n P(A)P(B_i|A) = \sum_{i=1}^nP(B_i)P(A|B_i)[/tex]

Using the above, rules, as we're already given that

[tex]A_1, A_2, A_3[/tex] are forming partition of the sample space (thus they're mutually exclusive and exhaustive events)

Also, its given that

[tex]P(A_1) = 0.3\\P(A_2) = 0.5\\P(A_3) = 0.2[/tex]

[tex]P(E|A_1) = 0.1\\P(E|A_2) = 0.6\\P(E|A_3) = 0.8[/tex]

Thus, by using the chain rule, we get:

[tex]P(E) = \sum_{i=1}^3P(A_i)P(E|A_i) = 0.3 \times 0.1 + 0.5 \times 0.6 + 0.2 \times 0.8 = 0.49\\\\P(E) = 0.49[/tex]

We have:

[tex]P(A_i \cap E) = P(A_i|E)P(E) = P(E|A_i)P(A_i)\\\\\rm P(A_i|E) = \dfrac{P(E|A_i)P(A_i)}{P(E)}[/tex]

Evaluating for i = 1, ,2, 3, we get:

Case 1: i = 1

[tex]\rm P(A_i|E) = \dfrac{P(E|A_i)P(A_i)}{P(E)}\\P(A_1|E) = \dfrac{0.1 \times 0.3}{0.49} \approx 0.0612[/tex]

Case 2: i = 2

[tex]\rm P(A_i|E) = \dfrac{P(E|A_i)P(A_i)}{P(E)}\\\\P(A_2|E) = \dfrac{0.6 \times 0.5}{0.49} \approx 0.612[/tex]

Case 3: i = 3

[tex]\rm P(A_i|E) = \dfrac{P(E|A_i)P(A_i)}{P(E)}\\P(A_3|E) = \dfrac{0.8 \times 0.2}{0.49} \approx 0.327[/tex]

Thus,

The needed probabilities are:

[tex]P(E) = 0.49[/tex][tex]P(A_1|E) = 0.0612[/tex][tex]P(A_2|E) = 0.612[/tex][tex]P(A_3|E) = 0.327[/tex]

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4. A number of whales were asked about things that they dislike
19 dislike giant squids
6 dislike giant squids and pollution and Captain Ahab
24 dislike Captain Ahab
1 dislike pollution but don't s dislike giant squids and don't dislike Captain Akab
11 dislike Captain Ahab and giant squids
3 dislike pollution and Captain Ahab but don't dislike giant squids
20 dislike pollution
5 have no dislikes
A How many whales were surveyed?
B. How many dislike at least one of those three tags?
C. How many dislike Captain Ahab but don't dislike giant squids?
D. How many dislike giant squids or pollution?
6. A number of classicists were asked to identify their favorite epic poets. The results

Answers

Final answer:

The question is solved by carefully analyzing the given figures and working step by step to avoid double counting of items. Adding numbers to find total whales and then subtracting or combining them as required gives the specific group numbers.

Explanation:

This question requires calculations around the given number of whales and their specific dislikes. Let's address each part of the question step by step:

A. To find out the total number of whales surveyed, we add all the mentioned whales together, including those with no dislikes.
B. To find out the number of whales disliking at least one thing, we subtract the whales with no dislikes from the total number of whales.
C. To find out the number of whales that dislike Captain Ahab but not giant squids, we need to remove the whales that dislike both these things.
D. To determine the number of whales that dislike either giant squids or pollution, we need to avoid counting the whales that dislike both twice.

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How can you express 1/4 as a percent?

Answers

Answer: 25%

Step-by-step explanation: To write a fraction as a percent, first remember that a percent is a ratio of a number to 100. If we want to write 1/4 as a percent, we need to find a fraction equivalent to 1/4 with a 100 in the denominator. We can do this by setting up a proportion.

[tex]\frac{1}{4}[/tex] = [tex]\frac{n}{100}[/tex]

Now, we can use cross products to find the missing value.

4n = 100

÷4     ÷4    ← divide by 4 on both sides

  n = 25

Therefore, 1/4 is equivalent to 25%.

Write the indicated conditional statements for the given statement.


Given Statement: Gerald bought his first car after saving up $5,000.


Conditional Statement:



Converse Statement:



Inverse Statement:



Contrapositive Statement:



Biconditional Statement:

Please help!!!

Answers

Explanation:

Given Statement: Gerald bought his first car after saving up $5,000.

The conditional conjunction after identifies the dependent clause, the one corresponding to the "if" statement in a conditional.

Conditional Statement:

If Gerald saved $5000, then he bought his first car.

__

Converse Statement:

If Gerald bought his first car, then he saved $5000.

__

Inverse Statement:

If Gerald did not save $5000, then he did not buy his first car.

__

Contrapositive Statement: (converse of the inverse)

If Gerald did not buy his first car, then he did not save $5000.

__

Biconditional Statement:

If and only if Gerald saved $5000, then he bought his first car.

given line ac with line ab=2x-4, bc=4x and ac=2x+12 find ac

Answers

Answer:

The answer to your question is: AC = 20

Step-by-step explanation:

Data

   AB = 2x - 4

   BC = 4x

   AC = 2x + 12

   AC = ?

            AB + BC = AC

        2x - 4 + 4x = 2x + 12

       6x - 4 = 2x + 12

       6x - 2x = 12 + 4

       4x = 16

       x = 16/4

       x = 4

AB = 2(4) - 4 = 8 - 4 = 4

BC = 4(4) = 16

AC = 2(4) + 12 = 8 + 12 = 20

         4 + 16 = 20

         20 = 20

Jane spent $40 on flowers. Each small flower cost $2, and each large flower cost $3. Write an equation that describes the relationship between cost and number of flowers purchased, where X is the number of small flowers and Y is the number of large flowers. Choose the best answer.

Answers

Answer: Our required equation describes the relationship between cost and number of flowers purchased is [tex]2X+3Y=40[/tex]

Step-by-step explanation:

Since we have given that

Total amount he spent on flowers = $40

Let the number of small flowers be 'X'.

Let the number of large flowers be 'Y'.

cost of small flowers = $2

cost of large flowers = $3

According to question, it becomes,

[tex]2X+3Y=40[/tex]

Hence, our required equation describes the relationship between cost and number of flowers purchased is [tex]2X+3Y=40[/tex]

The equation that describes this situation is.

2X + 3Y = 40

How to write the equation?

Let's define:

X = number of small flowers

Y = number of large flowers.

We know that Jane spent $40 on the flowers, and each small flower costs $2 and each large flower costs $3, then the total cost of the X and Y flowers is:

2*X + 3*Y

And that must be equal to 40, which is the amount she spent.

2X + 3Y = 40

That is the equation.

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In measuring reaction time, a psychologist estimates that a standard deviation is .05 seconds. How large a sample of measurements must he take in order to be 95% confident that the error in his estimate of mean reaction time will not exceed 0.01 seconds?

Answers

Answer:

97

Step-by-step explanation:

We are asked to find the size of sample to be 95% confident that the error in psychologist estimate of mean reaction time will not exceed 0.01 seconds.

We will use following formula to solve our given problem.

[tex]n\geq (\frac{z_{\alpha/2}\cdot\sigma}{E})^2[/tex], where,

[tex]\sigma=\text{Standard deviation}=0.05[/tex],

[tex]\alpha=\text{Significance level}=1-0.95=0.05[/tex],

[tex]z_{\alpha/2}=\text{Critical value}=z_{0.025}=1.96[/tex].

[tex]E=\text{Margin of error}[/tex]

[tex]n=\text{Sample size}[/tex]

Substitute given values:

[tex]n\geq (\frac{z_{0.025}\cdot\sigma}{E})^2[/tex]

[tex]n\geq (\frac{1.96\cdot0.05}{0.01})^2[/tex]

[tex]n\geq (\frac{0.098}{0.01})^2[/tex]

[tex]n\geq (9.8)^2[/tex]

[tex]n\geq 96.04[/tex]

Therefore, the sample size must be 97 in order to be 95% confident that the error in his estimate of mean reaction time will not exceed 0.01 seconds.

The commission earned on the sale of a car can be represented by the equation c(p)=250+0.02p where c represents the commission and p represents the purchase price of a car.

Jack sold two cars last weekend, one for $15,075 and the other for $21,640. Find his total commission.

If c(p)=745.80, find the purchase of the car.

Answers

Answer:

1) His total commission is $1,234.3

2) The purchase of the car is $24,790.

Step-by-step explanation:

1) 21640*0.02= 432.8+ 250= 682.8

15075*0.02= 301.5+ 250= 551.5

682.8+ 551.5= 1,234.3

2) 745.8- 250= 495.8/ 0.02= 24,790

Jack's total commission for selling two cars is $1234.3, and if

c(p) = 745.80, the purchase price of the car is $24,790.

We have,

Let's first find Jack's total commission for selling two cars, one for $15,075 and the other for $21,640.

For the car sold for $15,075:

c(p) = 250 + 0.02p

c(15075) = 250 + 0.02 * 15075

c(15075) = 250 + 301.5

c(15075) = 551.5

So, the commission for the car sold for $15,075 is $551.5.

For the car sold for $21,640:

c(p) = 250 + 0.02p

c(21640) = 250 + 0.02 * 21640

c(21640) = 250 + 432.8

c(21640) = 682.8

So, the commission for the car sold for $21,640 is $682.8.

Now, to find Jack's total commission, simply add the commissions for both cars:

Total Commission = Commission for first car + Commission for second car

Total Commission = $551.5 + $682.8

Total Commission = $1234.3

Jack's total commission for selling two cars is $1234.3.

Next, if c(p) = 745.80, we need to find the purchase price of the car (p). We can use the equation:

c(p) = 250 + 0.02p

Now, set c(p) equal to 745.80 and solve for p:

745.80 = 250 + 0.02p

Subtract 250 from both sides:

745.80 - 250 = 0.02p

495.80 = 0.02p

Now, divide both sides by 0.02 to isolate p:

p = 495.80 / 0.02

p = 24,790

Thus,

Jack's total commission for selling two cars is $1234.3, and if

c(p) = 745.80, the purchase price of the car is $24,790.

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The complement of 4 heads in the toss of 4 coins is

(Please explain)! Thanks!


Exactly one tail


At least one tail


All tails


Three heads

Answers

By using sample space we can say that complement of 4 heads in the toss of 4 coins is at least one tail .

What is sample space ?

set of all possible outcomes experiment is called sample space .

To find compliment of 4 heads we will first find sample space Sample space= S

= { HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH, TTTT }

Given case is 4 heads Say A= { HHHH}

Now we can calculate A complement as

A' = S-A

= { HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH,TTTT }- { HHHH}A'={ HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT TTHH, TTHT, TTTH,TTTT }

By using sample space we can say that complement of 4 heads in the toss of 4 coins is at least one tail .

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Final answer:

The complement of 4 heads in the toss of 4 coins is 'at least one tail', which includes any outcome where at least one coin lands on tails, encompassing all possibilities except for the exact outcome of 4 heads.

Explanation:

The student is asking about the concept of the complement in probability when flipping coins. Specifically, the complement of getting four heads in the flip of four coins. In probability, the complement of an event is all the possible outcomes that are not part of the event itself. In the case of flipping four coins, the event of getting four heads (HHHH) has a complement that consists of any outcome that does not have four heads. That includes outcomes with at least one tail.

Therefore, the complement of getting four heads is at least one tail, meaning any outcome where at least one coin lands on tails. All the outcomes with 0 heads and 4 tails, 1 head and 3 tails, 2 heads and 2 tails, or 3 heads and 1 tail would be part of this complement.

Since the question refers to the flip of four coins, only the following outcomes (macrostates) are possible: 0 heads (all tails), 1 head, 2 heads, 3 heads, or 4 heads (all heads). The complement of '4 heads' would comprise all outcomes except for '4 heads', reaffirming that the correct answer is at least one tail.

Jackson ran 5/7 of the distance around the school track Sarah around 4/5 of Jackson's distance what fraction of the total distance around the track did Sarah run

Answers

Answer:

2/3 of the track

Step-by-step explanation:

5/7 • 4/5 is 2/3 so Sarah ran 2/3 around the track.

Prove that quadrilateral ABCD with the vertices A (2,1), B (1,3), C (-5,0) D (-4,-2) is a rectangle. Graph the rectangle and then use appropriate formulas to justify / prove your answer.

Answers

Answer:

Just find the distance of the vertices of the quadrilateral ( such as : AB, BC, CD DA )by using distance formula...

Then if opposite sides of quadrilateral is equal then it is rectangle .....

hope you understand...

If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal places. Use the hyphen symbol, -, for negative values.

Answers

Answer:

y''=-1.26

Step-by-step explanation:

We are given that [tex]2x^2+y^2=17[/tex]

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

[tex]4x+2yy'=0[/tex]

[tex]2x+yy'=0[/tex]

[tex]yy'=-2x[/tex]

[tex]y'=-\frac{2x}{y}[/tex]

Again differentiate w.r.t.x

Then , we get

[tex]2+(y')^2+yy''=0[/tex] [tex](u\cdot v)'=u'v+v'u)[/tex]

[tex]2+(y')^2+yy''=0[/tex]

Using value of y'

[tex]yy''=-2-(-\frac{2x}{y})^2[/tex]

[tex]y''=-\frac{2+(-\frac{2x}{y})^2}{y}[/tex]

Substitute x=2 and y=3

Then, we get [tex]y''=-\frac{2+(\frac{4}{3})^2}{3}[/tex]

[tex]y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}[/tex]

Hence,y''=-1.26

WXY and YXZ are supplementary angles. m WXY=8x+12 m YXZ=2x+28. what is YXZ?

Answers

Answer:

YXZ= 56 degrees

Step-by-step explanation:

Add the angles and set them equal to 180. Then solve for x. then Pug it in 2x+28.

Answer: [tex]\angle{YXZ}=56^{\circ}[/tex]

Step-by-step explanation:

Given : ∠WXY and ∠YXZ are supplementary angles.

∠WXY= 8x+12   and   ∠YXZ = 2x+28

We know that the pair of supplementary angles are added up to 180°.

According to the question, we have

[tex]\angle{WXY}+\angle{YXZ}=180^{\circ}\\\\\Rightarrow\ 8x+12+2x+28=180\\\\\Rightarrow\ 10x+40=180\\\\\Rightarrow\ 10x=180-40\\\\\Rightarrow\ 10x=140\\\\\Rightarrow\ x=\dfrac{140}{10}=14[/tex]

Now, [tex]\angle{YXZ}=2(14)+28=56^{\circ}[/tex]

Hence, the measure of  [tex]\angle{YXZ}=56^{\circ}[/tex].

Every day, there are 3 times more likes on an internet video of a cat which is modeled by the function c(n) = (3)n − 1, where n is the number of days since the video posted. On the first day, there were 143 likes. What is the function that shows the number of likes each day?
A. c(n) = (3)(143)^{n-1}
B. c(n) = 143^{n-1}
C. c(n) = (3)143 − n
D.143(3)^{n-1}

Answers

The function that represents the number of likes each day is[tex]\(c(n) = 143(3)^{n-1}\)[/tex]. Therefore, the correct answer is option D.

The function [tex]\(c(n) = (3)n - 1\)[/tex] models the number of likes each day, where [tex]\(n\)[/tex] is the number of days since the video was posted.

On the first day, there were 143 likes.

To find the function that shows the number of likes each day, we need to substitute [tex]\(n = 1\)[/tex] into the given function and solve for the number of likes.

Substituting [tex]\(n = 1\) into \(c(n) = (3)n - 1\)[/tex], we get:

[tex]\[c(1) = (3)(1) - 1\][/tex]

[tex]\[c(1) = 3 - 1\][/tex]

[tex]\[c(1) = 2\][/tex]

So, on the first day[tex](\(n = 1\)),[/tex] there were 2 likes. Since the problem states that there were actually 143 likes on the first day, the correct function should take this into account. Therefore, the correct function is:

[tex]\[c(n) = 143(3)^{n - 1}\][/tex]

Thus, the correct option is:

[tex]D. \(143(3)^{n-1}\)[/tex]

The correct function modeling the number of likes each day with 143 initial likes and tripling daily is:  [tex]\[ c(n) = 143 \times 3^{n-1} \][/tex]

This aligns with the given exponential growth pattern.

To determine which function models the number of likes each day, let's consider the following:

- The initial number of likes is 143. This is the base case.

- The function is described as having 3 times more likes each day. This suggests an exponential growth pattern.

To derive the correct function, we need to incorporate this growth rate into the initial likes:

Given the base case (the first day) has 143 likes, and the number of likes triples each day, the correct function should start with the initial likes (143) and then account for the exponential increase by multiplying by the growth factor raised to the appropriate power.

This can be represented mathematically as:

[tex]\[ c(n) = 143 \times 3^{n-1}. \][/tex]

Let's break it down:

- Exponential Growth: Multiplying by 3 every day suggests exponential growth with a base of 3.

- Initial Value : The function starts with 143 likes.

- Days Since Posting : The exponent  n-1 accounts for the base case.

If  n = 1 , then [tex]\( 3^{n-1} = 3^{0} = 1,[/tex] which preserves the initial value of 143.

This leads us to option D , which correctly models the number of likes each day:

[tex]\[ c(n) = 143 \times 3^{n-1}.[/tex]  

Question :

Every day, there are 3 times more likes on an internet video of a cat which is modeled by the function c(n) = (3)n − 1, where n is the number of days since the video posted. On the first day, there were 143 likes. What is the function that shows the number of likes each day?

A. c(n) = (3)(143)^{n-1}

B. c(n) = 143^{n-1}

C. c(n) = (3)143 − n

D.143(3)^{n-1}

At union station, you notice that three subway lines just arrived at the same time. How long must you wait until all three lines arrive at Union Station at the same time again?

Answers

Answer:

You must wait 60 minutes for all three lines to arrive at Union Station at the same time again.

Step-by-step explanation:

The complete question in the attached figure

Step 1

Find the least common multiple (LCM) of the three numbers

List the prime factors of each number

[tex]10=(2)(5)\\12=(2^2)(3)\\15=(3)(5)[/tex]

Multiply each factor the greatest number of times it occurs in any of the numbers to find out the LCM

The LCM is equal to

[tex](2^2)(3)(5)=60[/tex]

therefore

You must wait 60 minutes for all three lines to arrive at Union Station at the same time again.

Kia has 2 1/4 pounds of peppermint candies. She wants to put them in small bags, each about 3/8 of a pound . How many small bags of candies can she make?

Answers

Answer:

Step-by-step explanation:

When I am dealing with fractions I put them in money wise so 2 1/4 would be like 2.25 and 3/8 would be like 0.75.

So that means you divide 2.25 by 0.75 and that will give you three.

Therefore Kia can make 3 small bags of candies.

have a nice day

please follow

Copy center prints black and white or colored copies. Yesterday, they printed 9 black and white copies for every 2 colored. If they printed 200 color copies then how many black and white copies where printed??

Answers

Answer:

The answer to your question is 900 black and white copies

Step-by-step explanation:

Data

9 black and white copies for every 2 colored

printed 200 color copies

black and white copies = ?

Process

                 This is a proportion exercise

                         BW : C ::  bw : c

                          9 : 2 ::  bw : 200

                         bw = 200(9) / 2

                         bw = 1800 / 2

                         bw = 900 copies


help fast thanks In the figure below, AB and CD

are straight line segments. Find the values of x and y.

Blank #1: value for x

Blank #2: value for y

Blank # 1

Blank # 2

Answers

Answer:

x = 20

y = 110

Step-by-step explanation:

5x + 45 + 3x - 25 = 180

those angles are supplementary (they make a straight angle in segment CD)

Solving that you get:

8x + 20 = 180

8x = 160

x = 20

Evaluating:

5(20) + 45 = 145

3(20) - 25 = 35

2(20) - 5 = 35

Now in segment AB:

y + (2x - 5) + (3x - 25) also sum 180, because they form a straight angle

y + 35 + 35 = 180

y = 110

A telephone pole is supported by a steel cable which extends from the top of the pole to a point on the ground 3 meters from its base. When Leah walks 2.5 meters from the base of the pole toward the point where the cable is attached to the ground, her head just touches the cable. Leah is 1.5 meters tall. How many meters tall is the pole?

Answers

We find that the telephone pole is 1.8 meters tall.

To figure out the height of the telephone pole, we can use similar triangles. Picture a right triangle formed by the telephone pole, the ground, and the wire, and another smaller triangle formed by Leah standing 2.5 meters from the pole, reaching the point where her head touches the wire 1.5 meters above the ground. Because these two triangles are similar, we can set up a proportion.

The large triangle's height is the height of the pole (H), and its base is 3 meters. The smaller triangle's height is Leah's height (1.5 meters), and its base is 2.5 meters. Using the similar triangles:

H (height of the pole) / 3 meters (distance from pole to cable ground attachment) = 1.5 meters (Leah's height) / 2.5 meters (Leah's distance from the pole)

H / 3 = 1.5 / 2.5

H = (1.5 / 2.5) * 3

H = 1.8 meters

Therefore, the telephone pole is 1.8 meters tall.

At the farmer's market, a bag of apples and 3 cartons of strawberries cost $18 total. If a bag of apples costs 50% more than a carton of strawberries, how much does a bag of apples cost?

Answers

Answer:

The answer to your question is: 1 bag of apples cost $6.

Step-by-step explanation:

We need to write an equation:

1 bag of apples + 3 cartons of strawberries = $18

but 1 bag of apples = 1.5 cartons of strawberries

So

1.5 cartons of strawberries + 3 cartons of strawberries = $18

simplify   4.5 cartons of strawberries = 18

                1 carton of strawberries = 18/ 4.5 = 4

finally         1 bag of apples = 1.5 (4) = 6

Answer:

$6.00

Step-by-step explanation:

Chelsea walked up a road that has 15% grade to get to her favorite store. That means the slope of the hill was 15/100. At what angle does the road come up from the ground ?

Answers

Answer:

[tex]8.53\°[/tex]

Step-by-step explanation:

we know that

The grade of a road can be thought of as rise/run, and you usually see it as a percentage.

So, a 15% grade is the same as a grade of 15/100; for every 15 units the road goes up vertically, it goes 100 units horizontally

see the attached figure to better understand the problem

Let

[tex]\theta[/tex] -----> angle does the road come up from the ground

The tangent of angle theta is equal to the ratio of the opposite side by the adjacent side

[tex]tan(\theta)=\frac{15}{100}[/tex]

[tex]\theta=tan^{-1}(\frac{15}{100})=8.53\°[/tex]

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