Answer:
[tex]F = 2\pi \dfrac{mMG}{L^2}}[/tex]
Explanation:
Assuming given,
Mass of wire be M
length of wire be L
small mass at center is = m
Radius of the wire be equal to = R = L/π
mass of small element of the wire
[tex]dM = \dfrac{M}{L}Rd\theta[/tex]
All the force are acting along y- direction
so, for force calculation
[tex]F = \int \dfrac{mdMG}{R^2} sin\theta [/tex]
[tex]F = \int_0^{\pi} \dfrac{m\dfrac{M}{L}RG}{R^2} sin\theta d\theta[/tex]
[tex]F = \int_0^{\pi} \dfrac{mMG}{L\dfrac{L}{\pi}} sin\theta d\theta[/tex]
[tex]F = \pi \dfrac{mMG}{L^2}}\int_0^{\pi}sin\theta d\theta[/tex]
[tex]F = \pi \dfrac{mMG}{L^2}}(-cos \theta)_0^{\pi}[/tex]
[tex]F = 2\pi \dfrac{mMG}{L^2}}[/tex]
The magnitude of the gravitational force is : [tex]2\pi \frac{mMG}{L^{2} }[/tex]
Given that :
mass of wire = M
length of wire = L
small mass at center = m
radius of wire = L / [tex]\pi[/tex]
Determine the magnitude of the gravitational force exerted by the wire on a pointFirst step : express the mass of small element of wire
dM = [tex]\frac{M}{L} Rd[/tex]∅
Since all forces act in the vertical direction the magnitude of the force exerted will be
F = [tex]\int\limits^\pi _o {\frac{m\frac{M}{L} RG}{R^2} } \, sin\beta d\beta[/tex]
[tex]F = \pi \frac{mMG}{L^2} \int\limits^\pi _0 {x} \, sin\beta d\beta[/tex]
Resolving equation above
Therefore F = [tex]2\pi \frac{mMG}{L^{2} }[/tex]
Hence we can conclude that The magnitude of the gravitational force is : [tex]2\pi \frac{mMG}{L^{2} }[/tex]
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Suppose a piece of dust finds itself on a CD. If the spin rate of the CD is 500 rpm, and the piece of dust is 4.3 cm from the center, what is the total distance traveled by the dust in 3 minutes? (Ignore accelerations due to getting the CD rotating.)
Answer:
405.3m
Explanation:
Since the CD spin rate is 500 rpm, or revolution per minutes, its angular speed in rad per second is
[tex]\omega = 500 rev/min * 2\pi rad/rev * 1/60 min/sec = 52.36 rad/s[/tex]
The dusk is 4.3 cm from center, so its velocity must be
[tex]v = R\omega = 4.3 * 52.36 = 225.14 cm/s[/tex]
Then the distance traveled by the dusk after 3 minutes, or 180 seconds is
[tex]d = v*t = 225.14 * 180 = 40526.54 cm[/tex] or 405.3m
Write the answer to this question. Energy is measured in units called joules(J). Suppose a roller coaster car starts with 78,000 J of potential energy. In a few seconds, it converts two-thirds of this energy into kinetic energy. As it takes a curve, the car doubles its kinetic energy. How much mechanical energy does the car now have?
The rollercoaster initially had 78,000 J of energy. It converted two-thirds of the energy into kinetic energy and later doubled it on a curve. Therefore, the coaster's new total mechanical energy is 182,000 J.
Explanation:In this energy problem, the roller coaster car starts out with 78,000 J of potential energy. It then converts two-thirds of its energy into kinetic energy, which is 2/3 * 78,000 J = 52,000 J. However, this isn't the end of the energy conversion. As the roller coaster car takes a curve, it doubles its kinetic energy to become 2 * 52,000 J = 104,000 J. Therefore, the new total mechanical energy of the car, considering both its remaining potential and newly gained kinetic energy, is its original potential energy (78,000 J) minus the potential energy converted to kinetic and then doubled (2/3 * 78,000 J * 2), which gives us 78,000 J - (2/3 * 78,000 J * 2) = 78,000 J - 104,000 J = -26,000 J. However, energy can't be negative, so it means the question might be flawed or we need to ignore the energy conservation law in this case and simply sum up potential and kinetic energies getting 78,000 J + 104,000 J = 182,000 J.
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To find the mechanical energy of the roller coaster car, we calculate the converted kinetic energy and then account for it being doubled during the ride. The car's total mechanical energy remains at 78,000 J due to conservation of energy.
The problem involves calculating the mechanical energy of a roller coaster car after it has converted some of its initial potential energy into kinetic energy and then doubled that kinetic energy. Initially, the car starts with 78,000 J of potential energy. As the problem states, the car converts two-thirds of this energy into kinetic energy. This conversion can be calculated as (2/3) × 78,000 J = 52,000 J of kinetic energy. Then, as the car takes a curve, it doubles this kinetic energy, resulting in 2 × 52,000 J = 104,000 J of kinetic energy. Due to the conservation of mechanical energy, and considering that no energy is lost to friction or other forces, the total mechanical energy of the car will be the same as the initial potential energy it had at the top of the first rise. Therefore, the car now has a total mechanical energy of 78,000 J.
Two technicians are discussing the need for the history of the vehicle. Technician A says that an accident could cause faults due to hidden damage. Technician B says that some faults could be related to a previous repair. Which technician is correct?a. Tech A onlyb. Tech B onlyc. Both a and bd. Neither a and b
Answer:
(C) both tech A and tech B
Explanation:
both technicians are correct because an accident could cause faults due to hidden damages which might not have been detected at the time of the accident and some faults could be related to previous repair probable due to human error from the repair man or even improper repair due to lack of adequate knowledge on the vehicle.
A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above Earth's surface (i.e. twice her normal distance from Earth's center). How much is her weight there? Group of answer choices
Answer:
100 N
Explanation:
Let us first find the mass of the person when they are on the earth's surface
[tex]F=G\frac{Mm}{r^{2} }\\[/tex]
Now let us see how F changes if the distance between two masses is doubled
[tex]F_{1} = G\frac{Mm}{(2r)^{2} } = \frac{1}{4} *G\frac{Mm}{r^{2} }[/tex]
So when the distance of separation is doubled, the force of gravity between the two masses decreases by a factor of four
Therefore her new weight = 400 N/4 = 100 N
Final answer:
The weight of the weight watcher on top of the tall ladder would be 1/4 of her normal weight due to the decrease in gravity with distance from Earth's center.
Explanation:
The weight of the weight watcher on top of a very tall ladder, twice her normal distance from Earth's center, would be 1/4 of her normal weight. This is because the gravitational force decreases with distance from the center of the Earth. When experiencing 1/4 the normal gravitational force, her weight would be 1/4 of the original weight.
A long pipe of outer radius ????1=3.50 cm and inner radius ????2=2.98 cm carries a uniform charge density of 9.22 mC/m3. Assuming that the pipe is sufficiently long to consider it infinitely long, use Gauss's law to calculate the electric field ???? at a distance ????=7.35 cm from the centerline of the pipe. Use ????0=8.85×10−12 C/N·m2 for the the permittivity of free space.
Answer:
2388078.86544 N/C
Explanation:
[tex]\rho[/tex] = Charge density = 9.22 mC/m³
r = Distance = 7.35 cm
[tex]r_o[/tex] = Outer radius = 3.5 cm
[tex]r_i[/tex] = Inner radius = 2.98 cm
l = Length of cylinder
[tex]\epsilon_0[/tex] = Permittivity of free space = [tex]8.85\times 10^{-12}\ F/m[/tex]
V = Volume
E = Electric field
Charge is given by
[tex]Q=\rho V\\\Rightarrow Q=\rho\pi l(r_o^2-r_i^2)[/tex]
Area
[tex]A=2\pi rl[/tex]
From Gauss law the flux through a cylindrical surface is given by
[tex]EA=\frac{Q}{\epsilon_0}\\\Rightarrow E=\frac{Q}{\epsilon_0A}\\\Rightarrow E=\frac{\rho\pi l(r_o^2-r_i^2)}{\epsilon_02\pi rl}\\\Rightarrow E=\frac{\rho(r_o^2-r_i^2)}{\epsilon_02r}\\\Rightarrow E=\frac{9.22\times 10^{-3}(0.035^2-0.0298^2)}{8.85\times 10^{-12}\times 2\times 0.0735}\\\Rightarrow E=2388078.86544\ N/C[/tex]
The electric at the given distance is 2388078.86544 N/C
name one situation in which you might notice the reflection of a wave
Answer:
A perfect example of wave reflection is an echo.
Explanation:
A wave reflection takes place when waves cannot pass through a surface and in turn they bounce back. It is not necessary that wave reflections can only happen with sound waves, they can also take place in light waves. Also, the waves which are reflected have the same frequency as the original wave, but their direction is different. When a wave strikes an object in the same angle, they bounce back straight but when they hit an object with different angle, their direction changes.
Why is it important to develop alternative energy sources
Answer:
The alternative energy sources are defined as those resources that are used in place of the natural and non-renewable resources. This resources plays an important role in the conservation of natural resources.
The fossil fuels are the resources on which the people are directly dependent. Burning up of these fossils leads to the emission of carbon, which has a direct impact on earth. A small increase in the amount of carbon dioxide can lead to the increase in the surface temperature of earth.
In addition to this, these fossil fuels such as coal, petroleum, oil and natural gases are found to be present in a limited proportion, and it is a very expensive process to obtain these resources, so sustainable development method must be adopted in order to save this natural resources for the future generation.
Some of the examples of alternative resources that are widely used in place of fossil fuels are wind energy, solar energy, tidal energy, biomass energy and bio-fuels.
Thus, it is very important to develop and use alternative resources.
Final answer:
Developing alternative energy sources is vital for mitigating climate change, reducing reliance on finite fossil fuels, and enhancing economic opportunity and security. Renewable energy such as solar, wind, and hydropower are crucial for the sustainable transition.
Explanation:
Developing alternative energy sources is crucial for a number of reasons. First, as renewable energy sources like solar and wind become more technically superior and cost-effective compared to fossil fuels, market forces will naturally encourage a transition away from non-renewable resources. This helps prevent dependency on finite resources that will eventually deplete.
Second, climate change concerns necessitate the development of alternative energy sources. Political measures may impose financial penalties on fossil fuel use to mitigate harmful ecological impacts, prompting a migration towards more sustainable energy choices.
Lastly, alternative energy sources like solar, wind, and hydropower can provide increased economic opportunity, job creation, and energy security. Especially in light of climate-related disasters that reveal the vulnerabilities of fossil-fuel-dependent energy systems, diversification is key. It is also critical to plan now for a transition to sustainable energy to avoid the potential "energy trap" where too much energy is consumed in building new infrastructure, leaving insufficient resources for society's needs.
The atoms in a sample of carbon must contain nuclei with the same number of
Answer:
Protons
Explanation:
All the atoms in the carbon sample will contain the same atomic number, represented by Z.
Also, the nucleus of an atom consists of protons and neutron and for the atomic number to be same, the number of protons in the atom must be same.
Therefore, the nucleus can have variation in the number of neutron but not proton for the same carbon sample giving rise to the isotopes of carbon.
Isotopes:
The elements that contains the same atomic number but their mass number is different.
Two pop cans are at rest on a stand. A firecracker is placed between the cans and lit. The firecracker explodes and exerts equal and opposite forces on the two cans. Assuming the system of two cans to be isolated, the post-explosion momentum of the system ____.
a. is dependent upon the mass and velocities of the two cans
b. is dependent upon the velocities of the two cans (but not their mass)
c. is typically a very large value
d. can be a positive, negative or zero value
e. is definitely zero
Answer:
e. is definitely zero
Explanation:
Given that
At initial condition the speed of the pop cans is zero.
We know that linear momentum
P = Mass x velocity
P = m v
At initial condition v = 0
P= 0
If there is no any external force then the linear momentum of the system will be conserve.And given that ,consider the system isolated.
Therefore the answer is e.
A skier of mass 71 kg is pulled up a slope by amotor-driven cable.The acceleration of gravity is 9.8 m/s2.How much work is required to pull him 62 mup a 31◦slope (assumed to be frictionless) ata constant speed of 2.58 m/s?Answer in units of kJ
Answer:
Work done will be 22216.894 J
Explanation:
We have given mass of the skier m = 71 kg
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Slop is given as [tex]\Theta =31^{\circ}[/tex]
Distance d = 62 m
So vertical distance [tex]d_y=dsin\Theta =62\times sin31^{\circ}=31.932m[/tex]
We know that work done is given by
[tex]W=mgh=mgd_y=71\times 9.8\times 31.93=22216.894J[/tex]
A platinum sphere with radius 1.21 cm is totally immersed in mercury. Find the weight of the sphere, the buoyant force acting on the sphere, and the sphere's apparent weight. The densities of platinum and mercury are 2.14 × 104 kg/m3 and 1.36 × 104 kg/m3, respectively.
Answer:
1.556 N , 0.989 N, 0.567 N
Explanation:
Radius of sphere, r = 1.21 cm = 0.0121 m
density of platinum , d = 2.14 x 10^4 kg/m^3
density of mercury, d' = 13.6 x 10^3 kg/m^3
Volume of sphere, [tex]\frac{4}{3}\pi \times r^{3}= \frac{4}{3}\times 1.34\times \left (0.0121 \right )^{3}[/tex]
V = 7.42 x 10^-6 m^3
Weight of sphere = volume of sphere x density of platinum x gravity
W = V x d x g = 7.42 x 10^-6 x 2.14 x 10^4 x 9.8 = 1.556 N
Buoyant force, B = Volume x density of mercury x gravity
B = 7.42 x 10^-6 x 13.6 x 10^3 x 9.8 = 0.989 N
Apparent weight = True weight - Buoyant force
Apparent weight = 1.556 - 0.989 = 0.567 N
To find the weight of the platinum sphere, calculate the mass of the sphere using its density and volume. Then, use the formula weight = mass × gravitational acceleration. The buoyant force acting on the sphere is equal to the weight of the fluid displaced, which in this case is the weight of an equivalent volume of mercury. The sphere's apparent weight can be calculated by subtracting the buoyant force from its actual weight.
Explanation:To find the weight of the platinum sphere, we can use the formula:
Weight = Mass × Gravitational acceleration
Given the density of platinum and the radius of the sphere, we can calculate the mass of the sphere using the formula:
Mass = Density × Volume
Using the volume of a sphere formula, we can determine the volume of the sphere. Once we have the mass, we can calculate the weight of the sphere.
The buoyant force acting on the sphere can be calculated using Archimedes' principle, which states that the buoyant force equals the weight of the fluid displaced. In this case, the fluid is mercury. Since the sphere is totally immersed in mercury, the buoyant force would be the weight of an equivalent volume of mercury.
The sphere's apparent weight can be calculated by subtracting the buoyant force from the weight of the sphere. This gives us the net force acting on the sphere when it is immersed in mercury.
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A 24-cm-diameter vertical cylinder is sealed at the top by a frictionless 15 kg piston. The piston is 90 cm above the bottom when the gas temperature is 315 ∘C. The air above the piston is at 1.00 atm pressure.
A) What is the gas pressure inside the cylinder?B) What will the height of the piston be if the temperature is lowered to18 ∘C?
Considering the gasses law and all the parameters, 1) the pressure inside the cylinder is 3249.4 Pa, 2) the height of the piston at 18ºC is 0.4452 m.
What is the Law of gasses?
The law of gasses is a group of chemical and physical laws that allows understanding the behavior of gasses in a close system.
The law of gasses considers different parameters, such as
Pressure, P: the amount of force applied on a surface. It is expressed in Pascals (Pa) or atmospheres (atm). 1 atm = 101325 Pa.
Volume, V: spaces occupied by a certain amount of mass. It is expressed in litters (L).
Temperature, T: it is a measure of the particles' internal agitation. It is expressed in kelvins (K). One centigrade = 1 + 273 kelvins.
When talking about standard conditions in gas, we refer to 1 atm pressure, 273 K of temperature (0ºC), and 22.4 L/mol of volume.
The different laws are,
Boyle law ⇒ P₁V₁ = P₂V₂ ⇒ P and V are inversely proportional. T is constant.Charles law ⇒ V₁/T₁ = V₂/T₂ ⇒ V and T are directily porportional. P is constant.Gay-Lussac law ⇒ P₁/T₁ = P₂/T₂ ⇒ T and P are directily porportional. V is constant.The relationship between these three laws and the variables is as follows,
(P₁V₁) / T₁ = (P₂V₂) / T₂
According to this framework, we can answer the questions in this porblem.
Available data:
D = 24-cm² = 0.0024 m²m = 15 kgh = 90 cm = 0.9 mT₀ = 315ºC ⇒ 315 + 273 = 588 K.Pair = 1atmA) What is the gas pressure inside the cylinder?
We know that P is defined by the relationship between force and area.
P = F/A
So, let us define Force and Area.
FORCE
F is the force applied by the piston. So we need to get the F of the piston.
To do it, we will use the following formula,
W = mg ⇒ Where m is mass (15 kg) and g is gravity (9.8m/s²)
Since W is a type of force, we can replace this value in the previous general formula,
P = F/A = W/A = mg/A
AREA
Area A is defined by the following formula
A = π r²
Where
- π = 3.1416
- r = D/2
Now, we can replace A in the general formula as follows,
P = mg/A = mg / π (D/2)²
The pressure inside the cylinder is,
P = mg / π (D/2)²
P = (15 x 9.8) / 3.1416 (12)²
P = 147 / 452.39
P = 0.32494
P = 3249.4 Pa
The gas pressure inside the cylinder 3249.4 Pa.
B) What will the height of the piston be if the temperature is lowered to 18 ∘C?
T₁ = 588 K
T₂ = 18 ºC ⇒ 18 + 273 = 291 K
Now, volume can be calculated as follows,
V = π r² h = A h
Where
- π = 3.1416
- r = D/2 = 12
- h₁ = 0.9 m
- A = 452.39 cm² = 0.4524 m²
Replacing,
V₁ = A h₁
V₁ = 0.4524 m² x 0.9 m
V₁ = 0.4071 m³
Now, we have the initial volume V₁, and the inicial and final temperatures, T₁ and T₂. We will use this values and the Charles law to get the final volume, V₂.
V₁/T₁ = V₂/T₂
V₂ = T₂ (V₁/T₁)
V₂ = 291 (0.4071/588)
V₂ = 291 (0.4071/588)
V₂ =0.2014
Now that we have the final volume, we can use this value to get the final height.
V₂ = A h₂
h = V₂/A
h₂ = 0.2014 m³ / 0.4524 m²
h₂ = 0.4452 m
The height of the piston when the temperature is lowered to 18ºC is 0.4452 m.
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Final answer:
Starting with Part A, the gas pressure inside the cylinder is calculated using the piston's weight and area of the cylinder's cross-section, plus atmospheric pressure. For Part B, the height of the piston at 18 °C is found using the combined gas law, with the final volume corresponding to the new height under constant pressure.
Explanation:
To answer the student's questions regarding the cylinder and piston system, we must use the principles of gas laws and mechanics.
Part A: Gas Pressure Inside the Cylinder
The pressure exerted by the piston onto the gas can be calculated using the formula P = F/A, where F is the force and A is the area. The force due to the piston's weight (F) is the mass of the piston times the gravitational acceleration (F = m * g). The area (A) is the cross-sectional area of the cylinder, which is πr² for a circle. Adding the atmospheric pressure above the piston gives us the total pressure exerted on the gas inside the cylinder.
Part B: Height of the Piston at 18 °C
Assuming the process is isobaric (constant pressure), the change in height can be found using the combined gas law which relates pressure, volume, and temperature of a gas. In this case, P1V1/T1 = P2V2/T2, where V1 and V2 are the initial and final volumes, respectively, determined by the product of the cross-sectional area and the height of the piston, P is pressure, and T is temperature in Kelvin. We are looking for the final volume, and thus the final height of the piston when the temperature is lowered.
The force required to stretch a Hooke’s-law spring varies from 0 N to 63.5 N as we stretch the spring by moving one end 5.31 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m. Find the work done in stretching the spring. Answer in units of J.
Answer:
Force constant will be 1195.85 N/m
Work done will be 1.6859 J
Explanation:
We have given the force, F = 63.5 N
Spring is stretched by 5.31 cm
So x = 0.0531 m
Force is given , F = 63.5 N
We know that force is given by [tex]F=kx[/tex]
So [tex]63.5=k\times 0.0531[/tex]
k = 1195.85 N/m
Now we have to find the work done
We know that work done is given by
[tex]W=\frac{1}{2}kx^2=\frac{1}{2}\times 1195.85\times 0.0531^2=1.6859J[/tex]
A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength.20 T. If the wire experiences a force of 0.60 N, what is themagnitude of the current moving through the wire?
A) 1A
B) 5A
C) 4A
D) 2A
E) 3A
Answer:
Current, I = 3 A
Explanation:
It is given that,
Length of the wire, l = 1 m
Magnetic field acting on the wire, B = 0.2 T
The magnetic force acting on the wire, F = 0.6 N
Let the current flowing through the wire is given by I. The magnetic force acting on an object in the uniform magnetic field is given by :
[tex]F=ILB\ sin\theta[/tex]
Here, [tex]\theta=90^{\circ}[/tex]
[tex]F=ILB[/tex]
[tex]I=\dfrac{F}{LB}[/tex]
[tex]I=\dfrac{0.6\ N}{1\ m\times 0.2\ T}[/tex]
I = 3 A
So, the current flowing through the rod 3 A.
A stamping machine begins turning out components that are out of tolerance. The manager removes the machine from service to ensure that more defective components are not produced and notifies maintenance to repair the machine. This is an example of ________. A. immediate corrective action B. benchmarking C. corporate governance D. disciplinary action E. basic corrective action
Answer:
Option A
Explanation:
Immediate corrective measure happens at the instant as it triggers a reaction according to a particular situation.
The time period of the solution is also on the same pattern and is not sustainable.
Thus the case where the stamping machine malfunctions and there is immediate removal of the machine from the service in order to reduce the production of the defective components is an example of immediate corrective measure.
A coin with a diameter of 2.11 cm is dropped onto a horizontal surface. The coin starts out with an initial angular speed of 19.0 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular deceleration of 1.26 rad/s2 , how far does the coin roll before coming to rest?
Answer:
9.49596 m
Explanation:
[tex]\omega_f[/tex] = Final angular velocity = 0
[tex]\omega_i[/tex] = Initial angular velocity = 19 rad/s
[tex]\alpha[/tex] = Angular acceleration = -1.26 rad/s²
[tex]\theta[/tex] = Angle of rotation
Equation of rotational motion
[tex]\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-19^2}{2\times -1.26}\\\Rightarrow \theta=143.25396\ rad[/tex]
Converting to m
[tex]143.25396\times \pi d=143.25396\times \pi\times 0.0211=9.49596\ m[/tex]
The distance the coin rolls before it stops is 9.49596 m
Suppose that two objects attract each other with a gravitational force of 16 units. if the mass of object one was doubled, and if the distance between the objects was tripled, then what would be the new force of attraction?
Answer: 3.5units
Explanation:
Gravitational force existing between the two masses is directly proportional to the product of their masses and inversely proportional to the square of the distances between the masses.
Mathematically, F = GMm/r^2
G is the gravitational constant
M and m are the masses
r is the distance between the masses.
If the force of attraction between the masses is 16units, it becomes,
16 = GMm/r^2... (1)
If the mass of object 1 is doubled and distance tripled, we will have
F= G(2M)m/(3r)^2
F=2GMm/9r^2... (2)
Solving eqn 1 and 2 to get the new Force
Dividing eqn 1 by 2, we have
16/F = GMm/r^2 ÷ 2GMm/9r^2
16/F = GMm×9r^2/r^2×2GMm
16/F = 9/2(upon cancelation)
Cross multiplying we have
9F=32
F= 32/9
F= 3.5units
Answer:
Answer: F = 4 units
Explanation:
If the distance is increased by a factor of 2, then force will be decreased by a factor of 4 (22). The new force is then 1/4 of the original 16 units.
F = (16 units ) / 4 = 4 units
Advantages of outsourcing project work may likely include all of the following EXCEPT:
a. Increased flexibility.
b. Higher level of expertise.
c. Shortened project duration.
d. Reduced costs.
e. Reduced conflict.
Answer:
e. Reduced conflict.
Explanation:
Outsourcing is a tool that allows you to hire a provider outside the company for the execution of secondary activities, such as cleaning or mail, or covering other areas of the company, such as financial or accounting systems or the human resources area
- Advantages of Outsourcing
- Cost reduction
- Focus on the main activity
- Transformation of fixed costs into variables
- Reduce risk
- Improve quality
- Productivity increase
- Improve innovation processes
- Greater flexibility
- Access to the latest technologies
- Increase in competitiveness
Advantages of outsourcing project work include increased flexibility, higher level of expertise, and reduced costs.
Explanation:The advantages of outsourcing project work may likely include increased flexibility because organizations can access a global talent pool and adapt to changing markets. Outsourcing can also provide a higher level of expertise as specialized firms or individuals with specific skills can be hired. Additionally, outsourcing can lead to reduced costs by eliminating the need for in-house resources and infrastructure.
However, one advantage that is unlikely to be associated with outsourcing project work is reduced conflict. When different parties are involved in a project, conflicts may arise due to differences in goals, perspectives, or communication barriers. Outsourcing does not automatically guarantee a reduction in conflict.
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Two waves are traveling in the same direction along a stretched string. The waves are 45.0° out of phase. Each wave has an amplitude of 9.00 cm. Find the amplitude of the resultant wave.
Answer:
Amplitude of the resultant wave = 15.72 cm
Explanation:
If two identical waves are traveling in the same direction, with the same frequency, wavelength and amplitude; BUT differ in phase the waves add together.
A = 9cm (amplitude)
φ = 45 (phase angle)
The two waves are y1 and y2
y = y1 + y2
where y1 = 9 sin (kx - ωt)
and y2 = 9 sin (kx - ωt + 45)
y = 9 sin(kx - ωt) + 9 sin(kx - ωt + 45) = 9 sin (a) + 9 sin (b)
where a = (kx - ωt)
abd b = (kx - ωt + 45)
Apply trig identity: sin a + sin b = 2 cos((a-b)/2) sin((a+b)/2)
A sin ( a ) + A sin ( b ) = 2A cos((a-b)/2) sin((a+b)/2)
We have that
9 sin ( a ) + 9 sin ( b ) = 2(9) cos((a-b)/2) sin((a+b)/2)
= 2(9) cos[(kx - wt -(kx - wt + 45))/2] sin[(kx - wt +(kx -wt +45)/2]
y = 2(9) cos (φ /2) sin (kx - ωt + 45/2)
The resultant sinusoidal wave has the same frequency and wavelength as the original waves, but the amplitude has changed:
Amplitude equals 2(9) cos (45/2) = 18 cos (22.5°) = 18 * -0.87330464009
= -15.7194835217 cm ≅ 15.72 cm
since amplitudes cannot be negative our answer is 15.72 cm
What would a plot of p versus 1/v look like for a fixed quantity of gas at a fixed temperature?
Answer:
Straight Line
Explanation:
For an ideal gas,
PV = nRT
For a fixed quantity ( constant number of moles) of a gas at fixed temperature
Right side of the equation will be constant
Thus,
PV = C
So, P = [tex]\frac{C}{V}[/tex] .
Thus P is directly related to [tex]\frac{1}{V}[/tex]
That's why plot between P and [tex]\frac{1}{V}[/tex] will be an straight line.
Water is flowing through a pipe whose cross sectional area at point A is larger than the cross sectional area at point B. The reading on a pressure gauge connected to the pipe at point A will be lower than the reading on a pressure gauge connected to the pipe at point B.
a.True
b.False
Answer:
a. True
Explanation:
Pressure is always inversely proportional to the cross section area
This can be proven from the equation P = F/A
Where P = Pressure, F = Force and A = Cross-sectional area
This can also be similarly proven from the continuity equation given as
A₁V₁ = A₂V₂
Where A₁ = Area in first part of pipe (point A)
A₂ = Area in second part of pipe (point B)
V₁ = Velocity of water in first part of pipe (point A)
V₂ = Velocity of water in second part of pipe (point B)
From the continuity equation we can have that
V₁/V₂ = A₂/A₁
Thus the velocity of the liquid at any point in the pipe is inversely proportional to the cross-sectional area of the pipe. The liquid will be moving slowly where the area is large and will be moving rapidly where the area is small, and since the velocity is directly proportional to the force (F = m × v/t)which id in turn directly proportional to the pressure (P = F/A), this proves my answer to be True!
A lift (elevator) is operated by an electric motor. It descends from the 10th floor to the 2nd floor at a constant speed. What is the main energy transformation during this journey?
#1
gravitational potential energy → kinetic energy.
#2
electrical energy → kinetic energy.
#3
kinetic energy → thermal energy.
#4
electrical energy → thermal energy.
Answer:
#4 Electrical energy to thermal energy
Explanation:
You clue there is constant speed, this means that the lift is not accelerating. So if that is the case, the lift is experiencing a resistive force against gravity. The one doing exerting the resistive force is the motor, which runs on electrical energy. Resistive force transforms into heat, so that makes it thermal energy. And so, the answer would be the last case.
In the two-slit experiment, for the condition of bright fringes, the value of m = +2 corresponds to a path difference of λ.
True or False?
Answer:
False
Explanation:
We know that if path difference is even multiple of wavelength then bright fringes are formed and if path difference is odd multiple of wavelength then dark fringes are formed .
For bright fringes
Path difference Δx = m λ
m = 0 , 2 , 4 , 6.......
If m = 2 then the path difference will be
Δx = 2 λ
therefore the above statement if false.
False
Tennis balls traveling at greater than 100 mph routinely bounce off tennis rackets. At some sufficiently high speed, however, the ball will break through the strings and keep going. The racket is a potential-energy barrier whose height is the energy of the slowest string-breaking ball. Suppose that a 100 g tennis ball traveling at 200 mph is just sufficient to break the 2.0-mm-thick strings. Estimate the probability that a 120 mph ball will tunnel through the racket without breaking the strings. Give your answer as a power of 10 rather than a power of e.
Answer:
Probability of tunneling is [tex]10^{- 1.17\times 10^{32}}[/tex]
Solution:
As per the question:
Velocity of the tennis ball, v = 120 mph = 54 m/s
Mass of the tennis ball, m = 100 g = 0.1 kg
Thickness of the tennis ball, t = 2.0 mm = [tex]2.0\times 10^{- 3}\ m[/tex]
Max velocity of the tennis ball, [tex]v_{m} = 200\ mph[/tex] = 89 m/s
Now,
The maximum kinetic energy of the tennis ball is given by:
[tex]KE = \frac{1}{2}mv_{m}^{2} = \frac{1}{2}\times 0.1\times 89^{2} = 396.05\ J[/tex]
Kinetic energy of the tennis ball, KE' = [tex]\frac{1}{2}mv^{2} = 0.5\times 0.1\times 54^{2} = 154.8\ m/s[/tex]
Now, the distance the ball can penetrate to is given by:
[tex]\eta = \frac{\bar{h}}{\sqrt{2m(KE - KE')}}[/tex]
[tex]\bar{h} = \frac{h}{2\pi} = \frac{6.626\times 10^{- 34}}{2\pi} = 1.0545\times 10^{- 34}\ Js[/tex]
Thus
[tex]\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}[/tex]
[tex]\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}[/tex]
[tex]\eta = 1.52\times 10^{-35}\ m[/tex]
Now,
We can calculate the tunneling probability as:
[tex]P(t) = e^{\frac{- 2t}{\eta}}[/tex]
[tex]P(t) = e^{\frac{- 2\times 2.0\times 10^{- 3}}{1.52\times 10^{-35}}} = e^{-2.63\times 10^{32}}[/tex]
[tex]P(t) = e^{-2.63\times 10^{32}}[/tex]
Taking log on both the sides:
[tex]logP(t) = -2.63\times 10^{32} loge[/tex]
[tex]P(t) = 10^{- 1.17\times 10^{32}}[/tex]
You are traveling on a narrow two-lane road and are approaching a child riding his bike on the right side of the road. A line of oncoming vehicles following a slow moving truck is approaching in the oncoming lane. You should flash your lights and tap your horn and:___________.
You are travelling on a narrow two-lane road and are approaching a child riding his bike on the right side of the road. A line of oncoming vehicles following a slow moving truck is approaching in the oncoming lane. You should flash your lights and tap your horn and: slow down and move closer to the truck
Explanation:
Change just a single lane at once. While switching to another lane to get ready for a turn, you should flag your goal to do as such at any rate 200 feet preceding evolving lanes or turning. Your sign separation must be in any event 300 feet before the turn in the event that you are working a vehicle in a speed zone of at any rate 50 miles for every hour.
Try not to zigzag all around lanes, which will significantly build your hazard of a mishap. On the thru-way, more slow vehicles should utilise the correct lane. Leave the left-hand lane for quicker moving or passing vehicles. Keep below principles when you are moving to another lane:
Make sure that there is no traffic in front of you in the lane you might want to enter Check your mirrors for any vehicles that are getting ready to pass you Briefly turn your head toward the lane that you are entering to ensure that there is no vehicle in your vulnerable side and that there is adequate space to move into the adjoining lane Use your blinker to caution different drivers of your goal to change lanesSmoothly move into the new driving laneYou should slow down and prepare to stop if necessary, yielding to the child on the bike. Flashing lights and honking the horn are not substitutes for cautious driving. Obey local traffic laws and be patient until it is safe to pass.
You are traveling on a narrow two-lane road and are approaching a child riding his bike on the right side of the road. A line of oncoming vehicles following a slow moving truck is approaching in the oncoming lane. To ensure safety, it's crucial not to rely solely on flashing your lights or tapping your horn. Your primary focus should be on slowing down and preparing to stop if necessary to yield to the child on the bike. Remember, flashing lights and using your horn can alert others, but they are not substitute for cautious driving. It's vital to exercise patience and wait until the oncoming traffic has passed and it is safe to overtake the child with a safe distance. Additionally, as a part of traffic safety, always be aware of and obey local laws regarding passing school buses with flashing lights, driving in school zones, and the general requirement to drive on the right hand side when encountering oncoming traffic.
A pair of alkaline D batteries can provide about 98000 J of electric energy at 3.0 V. If a current of 2 A flows through two D batteries while they’re in the circuit of a flashlight, how long will the batteries be able to provide power to the flashlight?
Answer:
4.53 hours
Explanation:
Energy, E = 98000 J
Voltage, V = 3 V
Current, i = 2 A
Let t be the time for which the batteries give the power.
Energy = V x i x t
98000 = 3 x 2 x t
t = 16333.33 seconds
t = 4.53 hours
A playground ride consists of a disk of mass M = 49 kg and radius R = 1.7 m mounted on a low-friction axle. A child of mass m = 29 kg runs at speed v = 2.6 m/s on a line tangential to the disk and jumps onto the outer edge of the disk.
Answer:
The angular speed is 0.83 rad/s.
Explanation:
Given that,
Mass of disk M=49 kg
Radius = 1.7 m
Mass of child m= 29 kg
Speed = 2.6 m/s
Suppose if the disk was initially at rest , now how fast is it rotating
We need to calculate the angular speed
Using conservation of momentum
[tex]m\omega_{i}=(mr^2+\dfrac{Mr^2}{2})\omega_{f}[/tex]
[tex]mvR=(mr^2+\dfrac{Mr^2}{2})\omega[/tex]
Put the value into the formula
[tex]29\times2.6\times1.7=(29\times1.7^2+\dfrac{49\times1.7^2}{2})\omega_{f}[/tex]
[tex]\omega_{f}=\dfrac{29\times2.6\times1.7}{(29\times1.7^2+\dfrac{49\times1.7^2}{2})}[/tex]
[tex]\omega_{f}=0.83\ rad/s[/tex]
Hence, The angular speed is 0.83 rad/s.
The angular speed is mathematically given as
wf=0.83rad/s
What is the angular speed?Question Parameter(s):
Generally, the equation for the conservation of momentum is mathematically given as
[tex]m\omega_{i}=(mr^2+\frac{Mr^2}{2})\omega_{f}[/tex]
Therefore
[tex]29\*2.6*1.7=(29\times1.7^2+\frac{49*1.7^2}{2})\omega_{f}[/tex]
wf=0.83rad/s
In conclusion, the angular speed is
wf=0.83rad/s
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A solid disk of mass 2 kg and radius 2 m is given a horizontal push of 20N at a point .3 m above its center. a. What is the minimum μs between the disk and the floor to allow rolling without slipping?
Answer:
[tex]\mu_s=1.0205[/tex]
Explanation:
Given:
mass of solid disk, [tex]m=2\ kg[/tex]radius of disk, [tex]r=2\ m[/tex]force of push applied to disk, [tex]F=20\ N[/tex]distance of application of force from the center, [tex]s=0.3\ m[/tex]For the condition of no slip the force of static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.
[tex]\therefore F<f_s[/tex]
where:
[tex]f_s[/tex] = static frictional force
[tex]\Rightarrow 20<\mu_s\times N[/tex]
[tex]\Rightarrow 20<\mu_s\times m.g[/tex]
[tex]\Rightarrow 20<\mu_s\times 2\times 9.8[/tex]
[tex]\mu_s>1.0204[/tex]
A 350-g air track cart on a horizontal air track is attached to a string that goes over a frictionless pulley with a moment of inertia of 6.00 × 10-6 kg ∙ m2 and a radius of 1.35 cm. If the string is pulled vertically downward by a force of 2.50 N,
(a) what is the magnitude of the acceleration of the cart?
(b) what is the tension in the horizontal string between the pulley and the cart?
The acceleration of the cart is 7.14 m/s^2. The tension in the string between the pulley and the cart is approximately 2.26 N.
Explanation:This physics problem involves the principles of dynamics and rotational motion.
(a) First, using Newton's second law, the acceleration a of the cart (mass, m) pulled by a force F is given by a = F/m. So, the acceleration is a = 2.50 N / 0.350 kg = 7.14 m/s^2.
(b) Considering the pulley, the torque τ exerted by the tension in the string is τ = r * T, r being the radius of the pulley. Given that τ = I * α and α = a/r (α being the angular acceleration), we can express the tension T as T = (I * a)/(r^2) = (6.00 × 10^-6 kg*m^2 * 7.14 m/s^2) / (0.0135 m)^2 = approximately 2.26 N.
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A pulley system is used to lift a 2,000 newton engine up a distance of 3 meters. The operator must apply a force of 250 newtons to the chain of the pulley system to lift the motor. To lift the engine 3 meters, the operator must pull a total of 30 meters of chain through the pulley system. What is the value of do?
To calculate the value of 'do' in the given pulley system, we need to know the efficiency.
Explanation:In order to calculate the value of 'do' in the given pulley system, we need to understand the concepts of actual mechanical advantage (AMA) and ideal mechanical advantage (IMA).
AMA is the ratio of the output force (load) to the input force (effort). In this case, the load is the engine with a weight of 2,000 newtons and the effort force is 250 newtons. So, AMA = Load/Effort = 2000 N/250 N = 8.
IMA is the theoretical mechanical advantage calculated by counting the number of ropes supporting the load. In this case, since there is only one rope supporting the load, IMA = 1.
The relationship between AMA and IMA is given by the equation: AMA = IMA x efficiency.
Since the efficiency is not provided in the question, we cannot directly calculate the value of 'do' without this information.