Find the missing lengths of the sides

Find The Missing Lengths Of The Sides

Answers

Answer 1
That's a 30-60-90 triangle, so the hypotenuse will always be 2x, the shorter leg will be x and the longer leg will be x√3. In this case, we are given the longer leg and we can deduce that x = 9. So, a = x = 9 and c = 2x = 18. Your answer is A, a = 9 yd, c = 18 yd.
Answer 2

Answer:

a) a = 9d, c = 18 yd

Step-by-step explanation:

The given triangle is a 30-60-90 triangle. The ratio of the sides of the triangle is 1x: 2x: √3x.

Here the hypotenuse is 2x, the shorter leg is x and the longer leg is √3x.

In given figure, we are given the longer leg.

√3x = 9√3

From this we can find the value of x, which is the shorter leg.

Dividing both sides by √3, we get

x = 9

The shorter side, a = 9 yd

Now let's find the hypotenuse.

Plug in x = 9, in 2x, we get

= 2*9

= 18 yd

The hypotenuse "c" = 18 yd.

So the answer is a) a = 9d, c = 18 yd


Related Questions

Bc¯¯¯¯¯ is parallel to de¯¯¯¯¯. what is ab? enter your answer in the box.

Answers

this can help you to understand it

Daniel is planning to go camping, but he lost the pole that supports the middle point of the tent. A cross-section of the tent is shown below. The base of the tent measures 96 inches wide, and the length from the top point of the tent to the corners of the base is 102 inches.

Answers

96/2 = 48

102^2 = 10404

48^2 = 2304

10404 - 2304 = 8100

 squareroot(8100) = 90

 the pole needs to be 90 inches high

helpppppppppppppppppppppppppp

Answers

Answer:
perimeter = 6 + 3√2 ft

Explanation:
The triangle given is an isosceles right-angled triangle.
This means that two of its legs are equal = 3 ft
Now, we will get the length of the third leg which is the hypotenuse using the Pythagorean theorem as follows:
(third leg)^2 = (3)^2 + (3)^2
(third leg)^2 = 18
third leg = sqrt(18) = 3√2 ft

Finally, we will get the perimeter as follows:
perimeter = 3 + 3 + 3√2 
perimeter = 6 + 3√2 ft

Hope this helps :)

Is 11p-7q polynomial

Answers

Answer:  Yes; this is polynomial.

Specifically, it is a "polynomial EXPRESSION" ; but not a "polynomial equation" ; because it is not an "equation.

There are more than one variables/variable expressions, so it is a polynomial.

Jennifer recorded the temperature of water samples and the time it took 50g of salt to dissolve in the samples. Jennifer's data models a direct variation. Which table contains Jennifer's data?

Answers

the answer is c. it look like this 
80°32 
83°33.2 
84°33.6 
90°36

Answer:

The answer is C.

Step-by-step explanation:

I know  that its c because i literatly just tried it and it said corect it was on USA. test prep

In 1992, only 275 people owned cellphones in Metropolis. Each year, cell phone use has continuously grown by 82%. How many cellphone users were there in 2000?

Answers

For this case we have the following equation of the potential type:
 y = A (b) ^ t
 Where,
 y: number of people with cell phones
 A: initial number of people with cell phones
 b: growth rate
 t: time
 Substituting values:
 y = 275 * (1.82) ^ t
 For the year 2000 we have t = 8.
 Substituting:
 y = 275 * (1.82) ^ 8
 y = 33105.77794
 nearest whole integer:
 y = 33105
 Answer:
 there were 33105 cellphone users in 2000

Please help! 15 points!

Btw, you cannot answer in the file.....that's just a pic.....

Answers

You can find the value of x using the trigonometric function of cosine.

cos x = adj/hyp
cos 49 = x/55
55(cos 49) = x 
36.083 = x 

Hope I am right :)

20 POINTS! What is the distance between the points (2, 3) and (5, -4)?

Answers

Use the distance formula.

The distance, d, between points [tex] (x_1, y_1) [/tex]
and [tex] (x_2, y_2) [/tex] is given by the distance formula below.

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Now we can apply the formula to your points.

Let Point 1 be (2, 3) and Point 2 be (5, -4).

Then you have

[tex] x_1 = 2~~~~y_1 = 3~~~~x_2 = 5~~~~y_2 = -4 [/tex]

[tex] d = \sqrt{(5 - 2)^2 + (-4 - 3)^2} [/tex]

[tex] d = \sqrt{(3)^2 + (-7)^2} [/tex]

[tex] d = \sqrt{9 + 49} [/tex]

[tex] d = \sqrt{58} [/tex]

Answer: the distance is sqrt(58)

Jade buys a blouse and a skirt for 34 of their original price. Jade pays a total of $31.50 for the two items. If the original price of the blouse is $18, what is the original price of the skirt? Enter your answer in the box.

Answers

The original cost of the skirt was $39.71.

This can be found by first calculating what the total cost of the items was originally. Since you spent $31.50 on items at 34% of their original price, the total cost can be found by dividing the new total by the percentage.

$31.50/.34 = $92.65.

Now we need to find the original price of the blouse. We repeat the same action with the $18 and the percentage.

$18/.34 = $52.94.

Now we can subtract the original cost of the blouse from the original cost of both items.

$92.65-$52.94 = $31.71.

Answer:

The original price of the skirt is $24

Step-by-step explanation:

The question must be 3/4 of their original price. So, I will solve this using 3/4 as 34 is unclear and does not suit the question.

Lets assume that the price of the blouse be = x

Lets say the price of the skirt is = y

Now, given is that 3/4 of the price together for both items is $31.5 0

This means,

[tex]\frac{3}{4}(x+y)=31.50[/tex]  ..... (1)

The original price of the blouse is $18 so, x= 18 .............(2)

Putting x=18 in equation (1)

[tex]\frac{3}{4}(18+y)=31.50[/tex]

[tex]3(18+y)=31.50*4[/tex]

[tex]3y+54=126[/tex]

[tex]3y=72[/tex]

y=24

Hence, the original price of the skirt is = $24.

Check:

Original price of both items = [tex]18+24=42[/tex]

And 3/4 of 42 is [tex]\frac{3}{4}*42= 31.50[/tex]

So, the correct answer is $24.

The price of a 250 dollar coat increased 7% last year. The coat is now on sale for one half off. What is the sale price?

Answers

start: 250increase: 250(1 + 0.07), 250(1.07)sale: 0.5(250(1.07)

Cora arrived at school at 7:55 am She left for 1 hour for a doctors appointment. She was dismissed from school at 3:15 pm. How long was Cora at school?

Answers

add 7:55 and 1:00 and subtract that from 3:15

Ramon spends 2/5 of his monthly income on rent ,1/5 of his income on utilities and 3/4 of the amount remaining on food and recreation.He saves 193.50 a month,What is Ramon’s monthly income?

Answers

Let x = income
Then: 
Rent: [tex] \frac{2}{5} x[/tex]
Utilities:  [tex] \frac{1}{5} x[/tex]
Food and Recreation:  [tex] \frac{3}{4}(x-( \frac{2}{5} x+\frac{1}{5} x))= \frac{3}{10} x[/tex]

Now adding all the expenses: [tex] \frac{2}{5} x+ \frac{1}{5} x+ \frac{3}{10} x= \frac{9}{10} x[/tex]
We see that the expenses are 90% of the income, so the savings must be 10% of the income.
[tex] \frac{1}{10} x=193.5[/tex]
x=1935.0  this is your income  
Hope this helps...

How much is in the account after year 6 ??

Answers

i think the answer is c 
its actually 1155 but that the closest answer to it
hope it helps

Which sequence of transformations creates a similar, but not congruent, triangle? ((will medal for correct answer))

Dilation and rotation
Rotation and translation
Reflection and rotation
Translation and reflection,

Answers

Dilation and rotation

You need to have a password with 4 letters followed by 2 even digits between 0 and 9, inclusive. if the characters and digits cannot be used more than once, how many choices do you have for your password?

Answers

Final answer:

The total number of possible passwords, considering the conditions that no letters or digits can be reused, and only even digits 0-9 can be used, would be 7,893,600.

Explanation:

This is a question of combinations and permutations. Firstly, consider the four letters. There are 26 letters in the English alphabet. Since you have four letters and none of them can be the same, the number of possibilities is 26 * 25 * 24 * 23. Next, consider the two numbers. Since we can only choose even numbers between 0 and 9 (which gives us 5 possible selections), and they cannot be the same, the number of possibilities is 5 * 4. Therefore, to find the total number of possible passwords, you multiply the possibilities for letters and numbers together. So, the number of

possible passwords would be 26 * 25 * 24 * 23 * 5 * 4, which equals to 7,893,600.

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A rectangular note card has a perimeter of 18 inches and an area of 20 square inches. What are the dimensions of the note card?

Answers

5 by 4

4 x 5 = 20

5 + 5 + 4 + 4 = 18
The dimensions are 5 by 4,
hope I helped (:

prove that an isosceles trapezium is always cyclic

Answers

Since the opposite angles are supplementary, an isosceles trapezium is a cyclic quadrilateral. Thus, ABCD is a rectangle as each internal angle is 90°. 8. If the non-parallel sides of a trapezium are equal, prove that it is cyclic.


i don't have time but to prove that an isosceles trapezium is always cyclic, you have to prove that if you add the opposite angles, you will get 180 degrees.

Hope this helps !

Photon

Find the area of the triangle that has a base of 4.2 mm and a height of 1.5 mm.

Answers

6.3 is your answer
I hope this helps

6.3 is the final answer

A rectangular deck
is 12 ft by 14 ft. When the length and width are increased by the same amount very becomes 280 squares ft. By how much were the dimensions increased ?

Answers

Both dimensions were increased by 127.

The other response seems more complex so probably ignore mine. I probably misinterpreted the question.

Original length: 14 ft. New length x + 14.
Original width: 12 ft. New width x + 12.

New area:

[tex] A = LW [/tex]  or [tex] LW = A [/tex]

[tex] (x + 14)(x + 12) = 280 [/tex]

[tex] x^2 + 14x + 12x + 168 = 280 [/tex]

[tex] x^2 + 26x - 112 = 0 [/tex]

[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]

[tex] x = \dfrac{-26 \pm \sqrt{26^2 - 4(1)(-112)}}{2(1)} [/tex]

[tex] x = \dfrac{-26 \pm \sqrt{676 + 448}}{2} [/tex]

[tex] x = \dfrac{-26 \pm \sqrt{1124}}{2} [/tex]

[tex] x = \dfrac{-26 \pm 2\sqrt{281}}{2} [/tex]

[tex] x = -13 \pm \sqrt{281} [/tex]

[tex] x \approx -29.76 [/tex]   or   [tex] x \approx 3.76 [/tex]

We discard the negative answer.

Answer:

Exact:
[tex] (-13 + \sqrt{281})~ ft [/tex]

Approximate:
[tex] 3.76 ~ft [/tex]

Please help, what effect does doubling the radius of a cone's base have on the cone's volume? Thank you! :),

Answers

This it the formula for the volume of a cone: V = (π)(r^2)(h/3) r is the radius (measured from the center of the cone base to the edge of the base) h is the height of the cone from the center of the base to the top If the radius is doubled, the equation becomes: V = (π)((2r)^2)(h/3) This can be simplified to V = (π)(4r^2)(h/3), so the new volume will be 4 times the original volume.

At the end of the first round in a quiz show, Jeremy has at most negative 20 points. Write an inequality that means “at most negative 20.”

Answers

The inequality would be x < -20 points, where x represents his number of points. The words "at most "mean that he can have up to and including -20 points.  If we read this inequality, it tells us that the number of points he has is less or equal to -20 which is the same thing as saying "at the most" -20 points.

7. Given the vertices of ∆ABC are A (2,-5), B (-4,6) and C (3,1), find the vertices following each of the transformations FROM THE ORIGINAL vertices: a. Rx = 3 b. T<3,-6> c. r(90◦, o)

Answers

Q1)
Rx = 3
in this reflection, the image has been reflected along the x = 3 line. then all the points on the image are reflected along this vertical line. the distance between each point and the vertical line is noted and by that same distance its moved to the opposite side of the vertical line, while the y coordinates stay the same.
A(2,-5)- x coordinate is 2, its 1 unit away from x=3, it should move by 1 unit to the other side of x = 3, then x = 4. y stays as it is.
A' - (4,-5)

B(-4,6) - distance from x = 3, is (-4-+3) is seven units, moves by 7 units to the other side
B' (10,6)

C(3,1) = distance from 3 = 0, therefore the point stays at is,
C' (3,1)

Q2)
next is a translation, in translation the size nor shape changes, each point in the original image moves the same distance in the same direction.
T (3,-6) (x,y) = this means that the x coordinates move by +3 points to the right and y coordinates move downwards by 6 units
A (2,-5) ---> (2+3,-5-6)
A' (5,-11)
B (-4,6) ---> (-4+3,6-6)
B' (-1,0)
C (3,1) ---> (3 + 3, 1-6)
C' (6,-5)

Q3)
r(90°,0)
this is a rotation done in the clockwise direction. then the image takes a rotation to the right direction around the origin. 
then the x, y coordinates of the preimage become ;
(x,y) = (y,-x)
A(2,-5) --> A' = (-5,-2)
B(-4,6) ---> B' = (6,4)
C(3,1)  ---> C' = (1,-3)

Help? Will mark Brainliest! TYSM!

Answers

1 3 5 is the answer mark me if u want to please
#1, 3, 5 are your answers.

#2, 4, and 6 cancel out because they are not included with the bisect

Hope this helped!

It has 3 more vertices than a triangle

Answers

Well, a triangle has 3 vertices, and 3 + 3 would be 6 vertices. So it is a hexagon.
The answer would be a hexagon. 

A vertice is simple a corner of a shape. A triangle has 3 corners, so it has three vertices. A hexagon has 6 corners, so it had 6 vertices!

helppppppppppppppppppp

Answers

we have that
g(x)=(3^x)-2
f(x)=(3^x)

using a graph tool
see the attached figure

the answer is  the option D
the graphic of G(x) is a translation of f(x) 2 units down

The sin 215° is ____
●A positive value
●0
●A negative value

Answers

The sin 215° is ____

●A positive value

The sin 215 degrees is a positive value. (Soh Cah Toa - Sin Cos Tan)


Answer: A positive value




believe; live


what should you do first to simplify the expression (43 + 9) ÷ 76 + 5

Answers

Hi there!

You should always find the value inside the parenthesis first when simplifying an equation. 
Tell me if you need help solving the equation!

Hope this helps!
always find the value inside the parenthesis first when simplifying an equation.

expression (43 + 9) ÷ 76 + 5


 43+9  =52     52 ÷  76 + 5

Which absolute value function has a graph that is wider than the parent function when graphed represents the parent function f(x)=|x| reflected over the x-axis and translated 1 unit to the right

A. F(x) = -|x|+1
B. F(x) = -|x-1|
C. F(x) =|-x|+1
D. F(x) =|-x-1|

Answers

The answer to this is B

Answer:

B.[tex]F(x)=-\mid{x-1}\mid[/tex]

Step-by-step explanation:

We are given that a function

[tex]f(x)=\mid x\mid[/tex]

We have to find absolute value of function when parent function reflected over the x- axis and translated 1 unit to the right.

The transformation rule when the point (x,y) is reflected over x- axis is given by

[tex](x,y)\rightarrow (x,-y)[/tex]

Apply the reflection on function  over x- axis then, we get

[tex]g(x)=-\mid x\mid[/tex]

Transformation rule when the point (x,y) is shifted a units  towards right is given by

[tex](x,y)\rightarrow (x-a,y)[/tex]

When the graph is translated 1 units towards right then , obtained function is given by

[tex]F(x)=-\mid{x-1}\mid[/tex]

What is the solution of the equation (x – 5)2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

Answers

(x – 5)² + 3(x – 5) + 9 = 0

x² - 10x + 25 + 3x - 15 + 9 = 0

x² - 7x - 16 = 0

[tex]x = \frac{7 + \sqrt{(-7)^2-4(1)(-16)} }{2} [/tex] or [tex]x = \frac{7 - \sqrt{(-7)^2-4(1)(-16)} }{2} [/tex] 

[tex] x = \frac{7 + 3i \sqrt{3} }{2} [/tex] or [tex] x = \frac{7 - 3i \sqrt{3} }{2} [/tex] 

(Answer B)

Answer: [tex]x=\frac{7\pm 3i\sqrt{3}}{2}[/tex]

Explanation:

Since, given quadratic function, [tex](x-5)^2 + 3(x-5) + 9 = 0[/tex] -----(1)

let us consider,[tex]x-5=p[/tex] -----(2)

Put this value in equation (1),

We get, [tex]p^2+3 p+9=0[/tex], which is also a quadratic equation.

Since, quadratic formula for finding the root of quadratic equation of type [tex]ax^2+bx+c=0[/tex] is,  [tex]x=\frac{-b\pm\sqrt{b^2-4ac}} {2a}[/tex]

Here, a=1, b=3  and c=9, so, [tex]p=\frac{-3\pm\sqrt{3^2-4\times1 \times9}} {2\times1}[/tex]

Thus,  [tex]p=\frac{-3\pm3\sqrt{-3}} {2}[/tex] ⇒ [tex]p=\frac{-3\pm3i\sqrt{3}} {2}[/tex]   (because √-1=i)

Now, from equation(2) [tex]x-5=\frac{-3\pm3i\sqrt{3}} {2}[/tex]

⇒[tex]x=\frac{-3\pm3i\sqrt{3}} {2}+5=\frac{7\pm 3i\sqrt{3}}{2}[/tex]

[tex]x=\frac{7\pm 3i\sqrt{3}}{2}[/tex]

A street promotion worker gets paid $0.10 for each flyer he hands out. His goal is to make $15 an hour. How many flyers must he hand out each hour?

A. 45
B. 1500
C. 150
D. 15

Answers

C.150 is the answer. I hope this helps :)
Final answer:

The street promotion worker must hand out 150 flyers each hour to make $15.

Explanation:

To determine how many flyers the street promotion worker must hand out each hour to make $15, we need to use the equation:

Number of flyers × Payment per flyer = Total payment

Since the worker wants to make $15 an hour, the equation becomes:

Number of flyers × $0.10 = $15

To solve for the number of flyers, we divide both sides of the equation by $0.10:

Number of flyers = $15 ÷ $0.10

Number of flyers = 150

Therefore, the street promotion worker must hand out 150 flyers each hour to make $15.

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