find the perimeter of a triangle with side lengths of 16.3 CM 18.75 cm and 24.2 centimeters.​

Answer:

b=2

Step-by-step explanation:

1.1     Pull out like factors :

  4b - 8  =   4 • (b - 2)

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    4   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    b-2 = 0

Add  2  to both sides of the equation :

                     b = 2

One solution was found :

                  b = 2

Answer:

b = 2

Step-by-step explanation:

Equation: 4b - 2 = 6

Step 1: Use the addition property of equality by adding 2 on both sides to put x on one side. Now we have the equation 4b = 8.

Step 2: Use the division property of equality by dividing 4 on both sides to isolate x. Now we have the equation b = 2.

Step 3: Verify your answer by substituting 2 into the equation 4b - 2 = 6. Now we have 4(2) - 2 = 6, which is the same as 8 - 2 = 6. After simplifying, we get 6 = 6, which is a true statement. Therefore, the answer is b = 2

Answer:

y=2

Step-by-step explanation:

If I interpreted what you wrote correctly, the equations were 5x-4y=7 and x=5-y. Given these equations, we can substitute the x=5-y into the other equation due to it quite literally being equal to x. When you substitute the x-equation in, it reads 5(5-y)-4y=7. Distribute the 5 into the (5-y) to get 25-5y-4y=7. Combine like terms to get 25-9y=7. Next, subtract the 25 from each side to isolate the -9y. This leaves yoy with -9y= -18. Divide by -9 on each side to isolate and find y. This leaves you with y=2. You can check your work by substituting the y=2 into the second equation to find x and then use the x and y to check your solution in the first equation. :)

Answer:

36/23

Step-by-step explanation:

Answer:

y+4=-6(x+8)  point-slope form

y=-6x-52 slope-intercept form

6x+y=-52 standard form

Step-by-step explanation:

Slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.

Lines that are perpendicular have opposite reciprocal slopes.

So the slope of y=(1/6)x+3 is 1/6.

The opposite reciprocal of (1/6) is -6.

So the equation for the line we are looking for is in the form:

y=-6x+b         (Since the slope of our new line is -6)

Now we want our line to go through (-8,-4).

So plug that in:

-4=-6(-8)+b

-4=48+b

Subtract 48 on both sides:

-52=b

The equation for the line we are looking for is

y=-6x-52.

Now you could do other forms.

Another one is point-slope form.

We already know it goes through (-8,-4) and a slope of -6.

Point slope form is: y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

Plug in the information to get:

y-(-4)=-6(x-(-8))

y+4=-6(x+8)

I'm going to do one more form.

Standard form is ax+by=c where a,b,c are integers.

y=-6x-52

Add 6x on both sides:

6x+y=-52

Answer:

40

Step-by-step explanation:

a+b=c

a=girls

b= boys

c= total

the statement tell us:

4/5 of a class is girls:

a=(4/5)*c

boys=b=8

c=a+b

so we have:

c=(4/5)*c + 8

c-(4/5)*c=8

(5c-4c)/5 = 8

c/5=8

c=8*5

c=40

total=40

Final answer:

To solve the system of equations, use the method of substitution to find the values of x, y, and z.

Explanation:

To find the solution to the system, we can use the method of elimination or substitution. Let's use the method of substitution to solve this system.

From the first equation, we can isolate y in terms of x and z: y = 2x + 6z - 1.

Substitute this expression for y in the other two equations to eliminate the variable y. This will give you an equation with variables x and z.

Solve the resulting equation to find the values of x and z.

Substitute these values back into any of the original equations to solve for the remaining variable, y.

The solution to the system -2x + y + 6z = 1, 3x + 2y + 5z = 16, and 7x + 3y - 4z = 11 is x = 1, y = 2, and z = 3.

Answer:

Clockwise rotation of 90 degrees with the center of rotation being the origin or anti-clockwise rotation of 270 degrees with the center of rotation being the origin.

Step-by-step explanation:

Rotation is one of the examples of linear transformations in which a point or a group of points move at a given angle with the fixed length. This means that the initial points (pre-images) move along the arc of the circle. They can be transformed at any angle. The resultant of any transformation is called the image. The trapezoid 2 is the pre-image and the trapezoid 6 is the image. It can be clearly sensed that the trapezoid 2 is being rotated clockwise at the angle of 90 degrees with the center of rotation being the origin. However, further inspections show that trapezoid 2 can also be mapped/transformed on trapezoid 6 by the anti-clockwise rotation of 270 degrees, center of rotation being the origin. Rest of the trapezoids are either reflections or rotations of different angles!!!

Answer:

Rotation I think.

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

[tex](x-h)^{2} +(y-k)^{2}=r^{2}[/tex]

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

[tex](x+3)^{2} +(y-4)^{2}=r^{2}[/tex]

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

[tex]r=\sqrt{(2-4)^{2}+(-6+3)^{2}}[/tex]

[tex]r=\sqrt{(-2)^{2}+(-3)^{2}}[/tex]

[tex]r=\sqrt{13}\ units[/tex]

The equation of the circle is equal to

[tex](x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}[/tex]

[tex](x+3)^{2} +(y-4)^{2}=13[/tex]

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

[tex](10+3)^{2} +(4-4)^{2}=13[/tex]

[tex](13)^{2} +(0)^{2}=13[/tex]

[tex]169=13[/tex] -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

[tex](x-1)^{2} +(y-3)^{2}=r^{2}[/tex]

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

[tex]r=\sqrt{(6-3)^{2}+(2-1)^{2}}[/tex]

[tex]r=\sqrt{(3)^{2}+(1)^{2}}[/tex]

[tex]r=\sqrt{10}\ units[/tex]

The equation of the circle is equal to

[tex](x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}[/tex]

[tex](x-1)^{2} +(y-3)^{2}=10[/tex]

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

[tex](11-1)^{2} +(5-3)^{2}=10[/tex]

[tex](10)^{2} +(2)^{2}=10[/tex]

[tex]104=10[/tex] -----> is not true

therefore

The point is not on the circle

The statement is false

For this case we must evaluate the following expression:

14 + (- 8) ÷ 2 * -3

According to the method of algebraic resolution, called PEMDAS, the divisions and multiplications must be made from left to right, before the addition and subtraction, then:

14 + (- 4) * - 3 =

We eliminate the parenthesis keeping in mind that [tex]- * - = +[/tex]

[tex]14 + 12 =[/tex]

Equal signs are added and the same sign is placed:

[tex]14 + 12 = 26[/tex]

Answer:

26

Answer:

The value of x is 4

Step-by-step explanation:

we know that

The Intersecting Secants Theorem states that  When two secant lines intersect each other outside a circle, the products of their segments are equal

so

[tex](x-1+5)(5)=(x+2+4)(4)\\ (x+4)5=(x+6)4\\5x+20=4x+24\\5x-4x=24-20\\x=4[/tex]

Final answer:

To solve the equation (3x-9)+x+(x+28)=184, you combine like terms to get 5x + 19 = 184, subtract 19 from both sides to get 5x = 165, and then divide both sides by 5 to find that x = 33.

Explanation:

To solve the equation (3x-9)+x+(x+28)=184, we begin by combining like terms. This involves adding together the x terms and combining the constant numbers. The x terms (3x, x, and x) add up to 5x, and the constants (-9 and +28) add up to 19. Therefore, the equation simplifies to 5x + 19 = 184.

Next, we isolate the variable x. We do this by subtracting 19 from both sides of the equation, getting 5x = 165. Then, we divide both sides by 5 to find x. Dividing 165 by 5, we find that x = 33.

Thus, the solution to the equation is x = 33.

Answer:

16 -> 15/20 -> 0.65 -> -7/25

Step-by-step explanation:

Why?

Most of the numbers in the set are rational where there is only ONE nature number which is 16 and it's the greatest. Comes after is 15/20 which equals .75 and it's obviously larger than 0.65 which will come after. The negative number is the smallest so it goes last :)

Answer:

A) The Length Of Diagonal PS And Diagonal P'S' Are In The Ratio 1:3

Step-by-step explanation:

when a polygon is multiplied or scaled by k, a constant scalar number to form another polygon then these two polygons are similar. And similar polygons have proportional lengths of corresponding sides. Ratios within the polygons sides will be equal to the corresponding sides ratios of the other polygons.  The corresponding sides of image are scalar multiple of preimage

x'=kx

where x' is side in image

x is side in preimage

and k is scalar number

so the ratio between these two corresponding side will be 1:3

In given case as the scalar factor k is 3 so the ratio between corresponding sides will be 1:3.

Hence option A is correct:The Length Of Diagonal PS And Diagonal P'S' Are In The Ratio 1:3!

A statement about polygon PQRST and its image after dilation, polygon P'Q'R'S'T', that is correct include the following: A) The Length Of Diagonal PS And Diagonal P'S' Are In The Ratio 1:3.

In Mathematics and Geometry, the formula for calculating the scale factor of any geometric object or figure is represented by the following:

Scale factor = side length of image/side length of pre-image

Based on the graph, the length of diagonal P'S' is 5 units while the length of diagonal PS is 15 units. In this context, the length of segment A'B' can be calculated as follows;

Scale factor = P'S'/PS

Scale factor = 5/15

Scale factor = 1/3 ⇒ Ratio = 1 : 3.

In conclusion, we can logically deduce that the length of diagonal PS and diagonal P'S' are in the ratio 1 : 3, which implies that diagonal PS is three times as long as diagonal P'S'.

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Answer:

x = 13/k

Step-by-step explanation:

kx - 4 = 9

Add 4 to each side

kx - 4+4 = 9+4

kx = 13

Divide each side by k

kx/k = 13/k

x = 13/k

Answer:

x = 13/k

Step-by-step explanation:

1) Combine the constants, obtaining:

kx = 13

2) Divide both sides by k to isolate x:

x = 13/k

Answer:

The average power use in watts is 806.

Step-by-step explanation:

The month of May has 31 days and 1 day  is 24 hours. So May has:

31*24=744 hours

Now, we divide 600 kW-hr by the number of hours in the month (744 hrs) to get average power use:

600/744 = 0.80645161. kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

0.80645161 * 1000 = 806 Watts

"The average power use is 806 watts."

So, the event "rolling an even number on the die and drawing an even-numbered card" corresponds to exactly one outcome of the experiment.

In this experiment, there are six possible outcomes from rolling the die (1, 2, 3, 4, 5, or 6) and ten possible outcomes from drawing a card (1, 2, 3, 4, 5, 6, 7, 8, 9, or 10).

To find the total number of outcomes, we multiply the number of outcomes from rolling the die by the number of outcomes from drawing a card: [tex]6 (outcomes from the die) * 10 (outcomes from the card) = 60 possible outcomes.[/tex]

An event corresponds to a specific combination of rolling the die and drawing a card. For example, rolling a 1 on the die and drawing a card numbered 1 is one possible outcome.

Now, let's consider the definition of an event that corresponds to exactly one outcome of the experiment:

An event where the die shows an even number (2, 4, or 6) and the card drawn is also even (2, 4, 6, 8, or 10) would correspond to exactly one outcome of the experiment.

For example, if the die rolls a 2 and the card drawn is a 4, this combination uniquely identifies one outcome of the experiment.

Triangle GDO is the correct answer.

Although Triangle DOG seems like the exact same triangle, it's not (Ok, well technically it is, but when showing two congruent triangles, the points on the triangle should correspond to eachother).

Answer:

Always

Step-by-step explanation:

The Parallel Postulate:

When a line is already given, let's say the line is a, and the point be called A. If there is a point outside the line, only one line can be drawn through the point which doesn't intersect the line i.e. which is parallel to the given line. Hence, this statement is always true ..

Answer:

Always

Step-by-step explanation:

Given statement: Through a point not on a line, one and only one line can be drawn parallel to the given line.

Draw a line l.

Let point P not on the line l.

Slope of two parallel lines are same.

We need to draw a line which is passes through the point P and parallel to the line l.

Infinite number of lines having different slopes can pass through a single point.

That is two lines don't have same slope.

Hence only one line is possible, which is parallel to l and passes through the point P.

Therefore the given statement is always true.

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

[tex]y=ax^2+bx+c[/tex]

From the graph you can see that the curve passes through the points (2,4), (1,7) and (3,7), so

[tex]y(2)=4\Rightarrow 4=a\cdot 2^2+b\cdot 2+c\\ \\y(1)=7\Rightarrow 7=a\cdot 1^2+b\cdot 1+c\\ \\y(3)=7\Rightarrow 7=a\cdot 3^2+b\cdot 3+c[/tex]

We get the system of three equations:

[tex]\left\{\begin{array}{l}4a+2b+c=4\\ \\a+b+c=7\\ \\9a+3b+c=7\end{array}\right.[/tex]

Subtract these equations:

[tex]\left\{\begin{array}{l}4a+2b+c-a-b-c=4-7\\ \\9a+3b+c-a-b-c=7-7\end{array}\right.\Rightarrow \left\{\begin{array}{l}3a+b=-3\\ \\8a+2b=0\end{array}\right.[/tex]

From the second equation:

[tex]b=-4a[/tex]

Substitute it into the first equation:

[tex]3a-4a=-3\\ \\a=3[/tex]

So,

[tex]b=-4\cdot 3=-12[/tex]

and

[tex]3+(-12)+c=7\\ \\c=7+9=16[/tex]

The quadratic function is

[tex]y=3\cdot x^2-12x+16[/tex]

Answer:

Step-by-step explanation:

We only need two points to draw a graph of each equation.

2x + y = 6

Convert to the slope-intercept form y = mx + b:

2x + y = 6          subtract 2x from both sides

y = -2x + 6

for x = 0 → y = -2(0) + 6 = 0 + 6 = 6 → (0, 6)

for x = 3 → y = -2(3) + 6 = -6 + 6 = 0 → (3, 0)

6x + 3y = 12

Convert to the slope-intercept form:

6x + 3y = 12            subtract 6x from both sides

3y = -6x + 12          divide both sides by 3

y = -2x + 4

for x = 0 → y= -2(0) + 4 = 0 + 4 = 4 → (0, 4)

for x = 2 → y = -2(2) + 4 = -4 + 4 = 0 → (2, 0)

Mark given points in the coordinate system.

Draw the lines passing through these points.

Look at the picture.

The lines are parallel. The intersection of the line is not exist. Therefore the system of equations has no solution.

The graph of the given equation is Attached below.

An important math tool is graphing. It can be a straightforward method for introducing more general concepts like most and least, greater than, or less than. It can also be a great way to get your child interested in math and get them excited about it. Using graphs and charts, you can break down a lot of information into easy-to-understand formats that quickly and clearly convey key points.

Given equation 2x + y = 6 we can drive from this equation that at x = 0 y will be 6 and y =0 x will be 3 hence we have two points of the line (0,6) and (3,0)

From the Given equation (2) 6X + 3Y = 12 we can drive from this equation that at x = 0 y will be 4 and y =0 x will be 2 hence we have two points of the line (0,4) and (2,0).

Hence, we have two coordinates from both lines which is enough to draw a  line on an XY cartesian plan.

Learn more about graphs here:

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[tex]\bf y = \stackrel{\stackrel{monthly~fee}{\downarrow} }{10}~~\stackrel{\stackrel{month}{\downarrow }}{x}+\underset{y-intercept}{\stackrel{\stackrel{registration~fee}{\downarrow }}{30}}~\hfill \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

Answer: a. The y-intercept is 30. This is the cost of registration.

Step-by-step explanation:

The standard equation of line in intercept form is given by  :-

[tex]y=mx+c\ \ \ \ \ \ \ (i)[/tex], where m is the slope of the line and c is the y-intercept.

Given : Sara plotted the data and determined that the average gym costs consist of a one-time registration fee and a monthly fee modeled by the equation :-

[tex]y = 10x + 30[/tex]

By comparing it to the equation (i), we have

c=30 and m=10

i.e. The y-intercept is 30.

Also, y-intercept of any function shows the starting value of the function when x=0.

Thus, This is the cost of registration ( starting fee).

Answer:

An anti-clockwise rotation of 180 degrees about the origin.

Step-by-step explanation:

We can draw a straight line between A and A' going through (0, 0). Same with the other points. We also see that A'B'C'D' faces the opposite way  to ABCD which is characteristic of a rotation of 180 degrees.

Answer:

B - 0.18B

0.82B

Step-by-step explanation:

If B is the price of the board game, then the discount will be:

B * 18/100

= B * 0.18

= 0.18B

The expression for the cost Bo will pay for the game is:

B - 0.18B => Original price - discount

The expression can also be written as: (after solving)

0.82B ..

Answer:

A=0.82B

E=B−0.18B

hope this helps

Answer:

4th option

Step-by-step explanation:

i have answered ur question

Answer:

B

Step-by-step explanation:

150/100=2/3

2/3 of 100 = 66 2/3

A 100-pound person will burn 66 2/3 calories while sitting still for 1 hour.

To find out how many calories a 100-pound person will burn while sitting still for 1 hour, we can use the given ratio of 150-pound person: 100 calories = 1 hour. Since the ratio is constant, we can set up a proportion to solve for the unknown value:

150 pounds : 100 calories = 100 pounds : x calories

Coss-multiplying, we get:

150 pounds * x calories = 100 pounds * 100 calories

Simplifying, we have:

x = (100 pounds * 100 calories) / 150 pounds

Calculating the value of x, we find that a 100-pound person will burn 66 2/3 calories while sitting still for 1 hour.

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Answer:

The correct answer is third option 3 : 4

Step-by-step explanation:

It is given that,Jamaal has 20 models of planes and cars

Also he has  three times as many cars as planes

Let 'x' be the number planes.

Then number of cars = 3x

Total number of models = x + 3x = 4x

To find the ratio of his cars to total models

cars : total models = 3x : 4x

 = 3 : 4

Therefore the correct answer is third option 3 : 4

Answer:

3:4 is the answer and give the guy above me brainliest

Step-by-step explanation:

Answer:

11.33 in.  to the nearest hundredth.

Step-by-step explanation:

The perimeter of the shaded area =   length of the 2 straight lines + the length of the 2 arcs = 4 + length of the 2 arcs.

Calculate the length of the outer arc:

This equals (30 / 360) * perimeter of the largest circle

= 1/12 * 2 π * 8

= 4/3 π in.

The inner circle has a radius of  8 - 2 = 6 ins

so the length of the inner arc

= 1/12 * π * 2 * 6

= π in.

So the perimeter of the shaded region = 4 + 4/3 π + π

= 4 + 7π/3

=  11.33 in.

[tex]a_1=-3\\r=7\\a_n=a_{n-1}\cdot r\\\\ \boxed{a_n=7a_{n-1}}[/tex]

[tex]a_{n+1} =7a_{n}[/tex].

If we know the term [tex]n^{th}[/tex] and the common relation, r, of a geometric sequence, you can find the term [tex](n+1)^{th}[/tex] using the recursive formula [tex]a_{n+1} =a_{n}.r[/tex].

The first term of the geometric sequence is a₁ = -3.

The common relation we have to find the relationship between a term and the term that precedes it.

[tex]r=\frac{-21}{-3} = 7[/tex]

The recursive formula is:

[tex]a_{1} =-3[/tex]

[tex]a_{n+1} =7a_{n}[/tex]

Answer:

B

Step-by-step explanation:

The sequence is as follows:

7,19,31,43,55

Here:

a_1=7

d= 12

The standard formula for arithmetic sequence is:

[tex]a_n=a_1+(n-1)d\\a_n=7+(n-1)12[/tex]

By looking at the options we can see that

option B is correct ..

Answer: B a(n)=7+(n-1)*12

Step-by-step explanation:

A P E X

A graph is a function if it passes the vertical line test. The vertical line test is where you take a vertical (up and down) line and test all spots of the graph. If the graph intersects the vertical line more then once then it is not a function, it is a relation. If the vertical line only crosses the graph once then it is a function.

Look at the image below to see the vertical line test for this graph:

The vertical line crosses the graph twice, therefore this is not a function. It is a relation.

Hope this helped!

~Just a girl in love with Shawn Mendes