Find the​ point, P, at which the line intersects the plane. x equals negative 3 minus 8 tx=−3−8t​, y equals negative 6 plus 5 ty=−6+5t​, z equals negative 6 minus 6 tz=−6−6t​; negative 7 x plus 2 y plus 8 z equals negative 4−7x+2y+8z=−4 The​ point, P, at which the line intersects the plane is left parenthesis nothing comma nothing comma nothing right parenthesis,,. ​(Simplify your answer. Type an ordered​ triple.)

Answers

Answer 1

Answer:

  P = (-18 5/9, 3 13/18, -17 2/3)

Step-by-step explanation:

The given point must satisfy both the equation of the line and that of the plane. We can substitute for x, y, and z in the plane's equation to get ...

  -7(-3-8t) +2(-6+5t) +8(-6-6t) = -4

  21 +56t -12 +10t -48 -48t = -4

  18t -39 = -4 . . . collect terms

  18t = 35 . . . . . . add 39

  t = 35/18 . . . . . .divide by the coefficient of t

The point is ...

  (x, y, z) = (-3-8(35/18), -6+5(35/18), -6-6(35/18))

  P = (x, y, z) = (-18 5/9, 3 13/18, -17 2/3)


Related Questions

In 1912, the RMS Titanic, a British passenger ship, sank in the North Atlantic Ocean after colliding with an iceberg. Historians do not know the exact passenger list, so the death toll is estimated. Here is data from the 2201 passengers on board, by cabin class. First Class Second Class Third Class Crew Row Totals Died 122 167 528 673 1490 Survived 203 118 178 212 711 Col Totals 325 285 706 885 2201 Source: Wikipedia, RMS Titanic (2015) If we randomly select a passenger who survived the Titanic, what is the probability that this passenger is in a second class cabin?

Answers

Final answer:

The probability that a randomly selected survivor was in second class is calculated by dividing the number of second class passengers who survived (118) by the total number of survivors (711), resulting in a probability of 16.6%.

Explanation:

The subject of this question is probability. To calculate the probability that a randomly selected survival was in the second class cabin, we need to consider the number of second class passengers who survived compared to the total number of survivors. From the data provided, we can see that 118 passengers in second class survived the incident. The total number of survivors is 711.

Therefore, the probability (P) is calculated as follows:
P = Number of successful outcomes / Total number of outcomes.
Hence, P = 118 / 711 = 0.166.

This means that there is a 16.6% chance that a passenger who survived was from the second-class cabin.

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Final answer:

The probability that a randomly selected survivor is from the second-class cabin is approximately 0.166, or 17% when rounded to the nearest percent.

Explanation:

Any calculation of probability involves dividing the number of favorable outcomes by the total number of outcomes. In this case, you want to find the probability that a randomly selected passenger who survived the Titanic was in a second-class cabin.

From the chart, we can see that 118 second-class passengers survived. The total number of survivors is 711. Hence, the probability of a survivor being from the second-class cabin is given by the formula:

Probability = favorable outcomes / total outcomes = number of second class survivors / total number of survivors.

Substituting these values into the formula we get: Probability = 118 / 711 = 0.166, or around 17% when rounded to the nearest percent.

So, if we randomly select a passenger who survived the Titanic, there is a 17% probability that this passenger is in a second-class cabin.

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Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg

Answers

Answer:

The potential energy associated with the given mass equals 1814.98 kilo Joules.

Step-by-step explanation:

We know that for a object of mass 'm' standing at a height of 'h' meters above the surface of earth the potential energy associated with the object is given by

[tex]P.E=mass\times g\times h[/tex]

where

'g' is acceleration due to gravity.

Since it is given that mass of 1 cubic meter of water is 1000 kilograms that the mass associated with given quantity of water is also 1000 kilograms since the volume is 1 cubic meter.

The height is given as 607 feet = [tex]{607}\times 0.3048=185.0136[/tex]meters

Applying the values in the above equation we get

[tex]P.E=1000\times 9.81\times 185.0136=1814.98kJ[/tex]  

Replacement times for CD players are normally distributed
with=5.5
years (66 months) and
= 1.5 years (18 months). Find the probabilitythat a randomly
selected CD player will have a replacement time orMORE THAN 7
YEARS.

Answers

Answer:

0.04

Step-by-step explanation:

X~N(μ=14.2; σ=0.9), a=7

[tex]P(X>7)=1-P(X\leq 7)[/tex]

[tex]P(0\leq X\leq a)=P(\frac{0-\mu}{\sigma} \leq \frac{X-\mu}{\sigma}\leq \frac{a-\mu}{\sigma}), Z= \frac{X-\mu}{\sigma}=P(0\leq X\leq a)=P(\frac{0-\mu}{\sigma} \leq \frac{X-\mu}{\sigma}\leq \frac{a-\mu}{\sigma}), Z= \frac{X-\mu}{\sigma}[/tex]

[tex]P(0\leq X\leq 7) = P(\frac{0-5.5}{1.5} \leq Z\leq \frac{7-5.5}{1.5}) = \Phi(1.66)-\Phi(-3.66) = \Phi(1.66) -(1-\Phi(3.66)) = 0.95-(1-0.99)=0.96[/tex]

P(X>7)=1-0.96=0.04

use completeling the square to solve for x in the equation (x-12)(x+4)=9

Answers

Answer:

x= [tex]4\pm \sqrt{73}[/tex]

Step-by-step explanation:

First step. Solve the binomial product from the left side of the equation:

[tex](x-12)(x+4)=9[/tex]

[tex]x^2+4x-12x-48=9[/tex]

Second step. Simplify and move independent terms to the right side of the equation:

[tex]x^2-8x=57[/tex]

Third step. Find a number that multiplied by two gives -8, then square this number and sum it on both sides of the equation:

[tex]x^2-8x+16=57+16[/tex]

Fourth step. Write the left side of the equation as a squared binomial:

[tex](x-4)^2=73[/tex]

Fifth step. First, take the square root and then add 4 to both sides of the equation to solve for x:

[tex](x-4)=\pm \sqrt{73}[/tex]

[tex]x= 4\pm \sqrt{73}[/tex]

How many grams are 2.7x10-^4 grams

Answers

Answer:

0,00027 grams!

Step-by-step explanation:

This is a scientific notation problem.

When a number is followed by a [tex]10^{-1}[/tex], it means that said number has one zero at the beginning.

In this case, the number is followed by [tex]10^{-4}[/tex], so that means that 2.7 has four zeros at the beginning. So, 2.7x[tex]10^{-4}[/tex] grams is equal to 0,00027 grams! (always the comma goes after the first zero).

The expression "2.7x10^-4 grams" is already given in grams, using scientific notation, and does not require a unit conversion since it is already in the unit we are interested in (grams). To understand what this quantity represents in standard decimal form, let's break down the scientific notation:

Scientific notation is a way of expressing very large or very small numbers in a compact form. The notation "2.7x10^-4" means that you take the number 2.7 and multiply it by 10 raised to the power of -4.

The term "10^-4" means "1 divided by 10 to the 4th power," which is the same as 0.0001 (1 followed by 4 zeros in the denominator).

To convert "2.7x10^-4" to its decimal form, you would perform the multiplication:

2.7 × 0.0001 = 0.00027

So, "2.7x10^-4 grams" is equal to 0.00027 grams in standard decimal notation.

Use Gaussian Elimination to find an equation of a polynomial that passes through points A(-5,-3), B(-2,3). C(3,3), D(6,19). Indicates row operations with the R notation. Leave coefficients in fraction form, do not report in decimals.

Answers

Answer:

The polynomial equation that passes through the points is [tex]2-\frac{2}{3}x+\frac{1}{12}x^{2}+\frac{1}{12}x^{3}[/tex]

Step-by-step explanation:

Suppose you have a function y = f(x) which goes through these points

A(-5,-3), B(-2,3). C(3,3), D(6,19)

there is a polynomial P(x) of degree 3 which goes through these point.

We use the fact that four distinct points will determine a cubic function.

P(x) is the degree 3 polynomial through the 4 points, a standard way to write it is

[tex]P(x) = a+bx+cx^2+dx^3[/tex]

Next replace the given points one by one, which leads to a system of 4 equations and 4 variables (namely a,b,c,d)

[tex]-3=a+b\cdot-5+c\cdot -5^2+d\cdot -5^3\\3=a+b\cdot-2+c\cdot -2^2+d\cdot -2^3\\3=a+b\cdot 3+c\cdot 3^2+d\cdot 3^3\\19=a+b\cdot 6+c\cdot 6^2+d\cdot 6^3[/tex]

We can rewrite this system as follows:

[tex]-3=a-5\cdot b+25\cdot c-125\cdot d\\3=a-2\cdot b+4\cdot c-8\cdot d\\3=a+3\cdot b+9\cdot c+27\cdot d\\19=a+6\cdot b+36\cdot c+216\cdot d[/tex]

To use the Gaussian Elimination we need to express the system of linear equations in matrix form (the matrix equation Ax=b).

The coefficient matrix (A) for the above system is

[tex]\left[\begin{array}{cccc}1&-5&25&-125\\1&-2&4&-8\\1&3&9&27\\1&6&36&216\end{array}\right][/tex]

the variable matrix (x) is

[tex]\left[\begin{array}{c}a&b&c&d\end{array}\right][/tex]

and the constant matrix (b) is

[tex]\left[\begin{array}{c}-3&3&3&19\end{array}\right][/tex]

We also need the augmented matrix, it is obtained by appending the columns of the coefficient matrix and the constant matrix.

[tex]\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\1&-2&4&-8&3\\1&3&9&27&3\\1&6&36&216&19\end{array}\right][/tex]

To transform the augmented matrix to the reduced row echelon form we need to follow these steps:

Subtract row 1 from row 2 [tex]\left(R_2=R_2-R_1\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&3&-21&117&6\\1&3&9&27&3\\1&6&36&216&19\end{array}\right][/tex]

Subtract row 1 from row 3 [tex]\left(R_3=R_3-R_1\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&3&-21&117&6\\0&8&-16&152&6\\1&6&36&216&19\end{array}\right][/tex]

Subtract row 1 from row 4 [tex]\left(R_4=R_4-R_1\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&3&-21&117&6\\0&8&-16&152&6\\0&11&11&341&22\end{array}\right][/tex]

Divide row 2 by 3 [tex]\left(R_2=\frac{R_2}{3}\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&1&-7&39&2\\0&8&-16&152&6\\0&11&11&341&22\end{array}\right][/tex]

Add row 2 multiplied by 5 to row 1 [tex]\left(R_1=R_1+\left(5\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&8&-16&152&6\\0&11&11&341&22\end{array}\right][/tex]

Subtract row 2 multiplied by 8 from row 3 [tex]\left(R_3=R_3-\left(8\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&0&40&-160&-10\\0&11&11&341&22\end{array}\right][/tex]

Subtract row 2 multiplied by 11 from row 4 [tex]\left(R_4=R_4-\left(11\right)R_2\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&0&40&-160&-10\\0&0&88&-88&0\end{array}\right][/tex]

Divide row 3 by 40 [tex]\left(R_3=\frac{R_3}{40}\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&0&1&-4&-1/4\\0&0&88&-88&0\end{array}\right][/tex]

Add row 3 multiplied by 10 to row 1 [tex]\left(R_1=R_1+\left(10\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&-7&39&2\\0&0&1&-4&-1/4\\0&0&88&-88&0\end{array}\right][/tex]

Add row 3 multiplied by 7 to row 2 [tex]\left(R_2=R_2+\left(7\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&88&-88&0\end{array}\right][/tex]

Subtract row 3 multiplied by 88 from row 4 [tex]\left(R_4=R_4-\left(88\right)R_3\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&0&264&22\end{array}\right][/tex]

Divide row 4 by 264 [tex]\left(R_4=\frac{R_4}{264}\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&0&1&1/12\end{array}\right][/tex]

Subtract row 4 multiplied by 30 from row 1 [tex]\left(R_1=R_1-\left(30\right)R_4\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&0&2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&0&1&1/12\end{array}\right][/tex]

Subtract row 4 multiplied by 11 from row 2 [tex]\left(R_2=R_2-\left(11\right)R_4\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&0&2\\0&1&0&0&-2/3\\0&0&1&-4&-1/4\\0&0&0&1&1/12\end{array}\right][/tex]

Add row 4 multiplied by 4 to row 3 [tex]\left(R_3=R_3+\left(4\right)R_4\right)[/tex]

[tex]\left[\begin{array}{cccc|c}1&0&0&0&2\\0&1&0&0&-2/3\\0&0&1&0&1/12\\0&0&0&1&1/12\end{array}\right][/tex]

From the reduced row-echelon form the solutions are:

[tex]\left[\begin{array}{c}a=2&b=-2/3&c=1/12&d=1/12\end{array}\right][/tex]

The polynomial P(x) is:

[tex]2-\frac{2}{3}x+\frac{1}{12}x^{2}+\frac{1}{12}x^{3}[/tex]

We can check our solution plotting the polynomial and checking that it passes through the points.

find cardinality of set B

B = {∅, {1}, {1, 2}, {1, 2,3}, · · · , {1, 2, · · · , m}}

Answers

Answer:

m + 1

Step-by-step explanation:

Given set,

B = {∅, {1}, {1, 2}, {1, 2,3}, · · · , {1, 2, · · · , m}},

Since, the elements of S are,

{} , {1}, {1, 2}, {1, 2, 3}....... {1, 2,.....m }

Thus, every next set contains one more succeeding natural number than the previous set.

So, if the last set contains m natural numbers.

Then there are 'm + 1' sets in B ( m sets included ∅ )

Hence, the number of elements in B is 'm+1'

I.e. Cardinality of B is m + 1.

Assistance in understanding and solving this example on Elementary Number Theory with the details of the solution to better understand, thanks.

a) Find all solutions to 3x+4y=60 in positive integers.

b) A roadside stand bought 11 large baskets of eggs from a farmer and sold 39 small baskets of eggs, which hold fewer than a dozen. There were 19 eggs left over. How many eggs does a large basket hold?

Answers

Answer:

a)

x  |  y

==========

16  |  3

12  |  6

8   |  9

4   |  12

b) A large basket contains 23 eggs

Step-by-step explanation:

a) Isolating 3x, we get

3x = 60-4y

This means that 60-4y is a multiple of 3.

Besides, as x is a positive integer, then x = 60-4y has to be greater than zero

60-4y>0

Solving the inequality for y

60>4y

60/4 > y

15>y (or y<15, which is the same)

The multiples of 3 which are smaller than 15 are 3,6,9 and 12

Now we draw a table for these values of y and found the value of x by replacing in the equation 3x = 60-4y---> x = (60-4y)/3

x  |  y

=======

16  |  3

12  |  6

8   |  9

4   |  12

And these are all the solutions in positive integers.

b) This problem is pretty much like problem a)

Let's call x the number of eggs contained in the large baskets and y the number of eggs contained in the small baskets.

Then

Number of eggs bought - number of eggs sold = number of eggs left over.

In this case

11x-39y = 19

But we also know that 0<y<12 because the small baskets hols fewer than a dozen.

Isolating x in the equation 11x-39y + 19, we get

x=(19+39y)/11

Now we make a table with these values of x and y remembering that y is a positive integer smaller than 12

x   | y

=======

5.2  | 1

8.8  | 2

12.4 | 3

15.9 | 4

19.5 | 5

23   | 6

26.6 | 7

30.1 | 8

33.6 | 9

37.2 |10

40.7 |11

From this table we see that the only integer solution for x is 23, so a large basket contains 23 eggs.

John sells hot dogs from a cart outside an office building 5 days a week. If the price of a hot dog is $3, what is John’s weekly revenue from hot dogs if he sells 47 each day.

Answers

Answer:

John’s weekly revenue from hot dogs = [tex]\$705[/tex]

Step-by-step explanation:

John  sells hot dogs from a cart outside an office building 5 days a week .

Price of a hot dog = [tex]\$3[/tex]

Number of hot dogs sold each day = 47

So, total number of hot dogs sold on 5 days = 5 × Number of hot dogs sold each day = 5 × 47 = [tex]235[/tex]

We need to find John’s weekly revenue from hot dogs if he sells 47 each day.

John’s weekly revenue from hot dogs = Price of a hot dog × total number of hot dogs sold on 5 days = 3 × 235 = [tex]\$705[/tex]

Rewrite using necessary or sufficient condition, as appropriate: "if the oven is hot then you may put the cake in."

Answers

Answer:

Answered

Step-by-step explanation:

"if the oven is hot then you may put the cake in". This the premise.

Now, The necessary condition will be "If the oven is hot" meaning the cake can be put inside the oven only when the oven is hot and not otherwise. So, here the hotness of the oven becomes the necessary condition.

"Oven is hot" is the necessary condition "to put the cake in"

Solve the following circle graph problems.

If savings are represented by 45° on a circle graph showing all expenses, and the total expenses are $1440, how much go into savings?

Select one:

a. $240

b. $120

c. $180

d. $300

Answers

Answer:

$180 go into savings

Step-by-step explanation:

Given : Savings are represented by 45° on a circle graph showing all expenses.

Total expenses are $1440

To Find : How much go into savings?

Solution:

Total angle of expense = 360°

Savings = [tex]\frac{\text{Saving angle}}{\text{Total angle}} \times 1440[/tex]

            = [tex]\frac{45}{360} \times 1440[/tex]

            = [tex]180[/tex]

Hence $180 go into savings

Percents

George's stock went down 12.6% since yesterday. The closing price for this
stock yesterday was $80.74

1. How much money did each share lose?​

2. How much is each share of stock worth today?

Answers

Answer:

$10.17$70.57

Step-by-step explanation:

1. The change in value was 12.6% of $80.74, calculated as ...

  0.126×$80.74 = $10.17324 ≈ $10.17

__

2. The new price is lower than the price yesterday by that amount, so is ...

  $80.74 -10.17 = $70.57

_____

Note on percents

A percent should be no mystery. The word "per cent" literally means "per hundred", or "/100" in symbols. The symbol "%" is a shorthand way to write "/100". So 12.6% means 12.6/100 = 126/1000 = 0.126.

When written as a decimal, the units digit of a percent is placed in the hundredths digit of the decimal number, as you can see in the example above. (The "2" in "12.6" is in the hundredths place in 0.126.)

Generally percentages are used to express ratios. They are usually a "pure number" with no units attached. Since they are a ratio, they are generally useless unless you know what the numbers involved in the ratio are. Here, the denominator of the ratio, the "base" or "reference", is yesterday's stock price. The percentage is described as the drop in price since yesterday, so it is the ratio ...

  (drop in price since yesterday)/(yesterday's price)

Both of these values have units of dollars, so the numerator units cancel the denominator units and what is left is a pure number. The ratio is 0.126, so to express it as a percentage, we multiply it by 100%. Of course, 100% = 100/100 = 1, so we haven't changed the value; we've only changed the way it is presented. That is ...

  0.126 = 0.126 × 100% = 12.6%

_____

Additional note on decimals and percents

You may hear that to convert a decimal to a percent, you multiply it by 100. That is only partly right. Multiplying anything by 100 changes its value by that factor. When you change a decimal to a percentage, the goal is not to change the value, merely the form. What you actually want to do is multiply by 100% = 100/100. In the example we're using here, this looks like ...

  0.126 × 100/100 = 12.6/100 = 12.6% . . . . . . remember that % means /100.

One of the interior angles of a triangle is equal to 30°, and one of the exterior angles is equal to 40°. Find the remaining interior angles of this triangle.

Answers

Answer:

The remaining interior angles of this triangle are 140º and 10º

Step-by-step explanation:

The sum of the interior angles of a triangle is always 180º.

A triangle has 3 angles. In this problem, we have one of them, that i am going to call A1 = 30º.

The sum of a interior angle with it's respective exterior angle is also always 180º.

We have that one of the exterior angles is equal to 40°. So it's respective interior angle is

40º + A2 = 180º

A2 = 180º - 40º

A2 = 140º

Now we have two interior angles, and we know that the sum of the 3 interior angles is 180º. So:

A1 + A2 + A3 = 180º

A3 = 180º - A1 - A2

A3 = 180º - 30º - 140º

A3 = 180º - 170º

A3 = 10º

Answer:

140 and 10

Step-by-step explanation:

Prove that an integer is odd if and only if it is the sum of two consecutive integers.

Answers

Answer:

A proof can be as follows:

Step-by-step explanation:

Remember that an odd interger is of the form [tex]2p+1[/tex] where [tex]p[/tex] is a integer and remember that two consecutive integer are two numbers of the form [tex]p, p+1[/tex]

[tex](\Rightarrow)[/tex] Suppose the [tex]n[/tex] is an odd integer.

Then [tex]n-1[/tex] must be an even integer and hence divisible by 2. Then we define

[tex]p=\dfrac{n-1}{2}\\q=\dfrac{n-1}{2}+1[/tex]

Then we have that

[tex]p+q=\dfrac{n-1}{2}+\dfrac{n-1}{2}+1=\frac{(n-1)+(n-1)}{2}+1=\frac{2(n-1)}{2}+1=n-1+1=n[/tex]

The converse is as follows:

[tex](\Leftarrow)[/tex] Let [tex]p[/tex] an integer, then[tex]p,p+1[/tex]  are two consecutive integers. Then

[tex]n=p+(p+1)=2p+1[/tex] is an odd integer.

Consider the quadratic function f(x) = -x^2 + 1x + 12. Determine the following: (enter all numerical answers as integers, fractions, or decimals): The smallest -intercept is 2 = The largest x-intercept is z = The y-intercept is y = The vertex is ( The line of symmetry has the equation Preview

Answers

Answer and Explanation:

Given : The quadratic function [tex]f(x)=-x^2+x+12[/tex]

To find : Determine the following ?

Solution :

The x -intercept are where f(x)=0,

So, [tex]-x^2+x+12=0[/tex]

Applying middle term split,

[tex]-x^2+4x-3x+12=0[/tex]

[tex]-x(x-4)-3(x-4)=0[/tex]

[tex](x-4)(-x-3)=0[/tex]

[tex]x=4,-3[/tex]

The x-intercepts are (4,0) and (-3,0).

The smallest x-intercept is x=-3

The largest x-intercept is x=4

The y -intercept are where x=0,

So, [tex]f(0)=-(0)^2+0+12[/tex]

[tex]f(0)=12[/tex]

The y-intercept is y=12.

The quadratic function is in the form, [tex]y=ax^2+bx+c[/tex]

On comparing, a=-1 , b=1 and c=1 2

The vertex of the graph is denote by (h,k) and the formula to find the vertex is

For h, The x-coordinate of the vertex is given by,

[tex]h=-\frac{b}{2a}[/tex]

[tex]h=-\frac{1}{2(-1)}[/tex]

[tex]h=\frac{1}{2}[/tex]

For k, The y-coordinate of the vertex is given by,

[tex]k=f(h)[/tex]

[tex]k=-h^2+h+12[/tex]

[tex]k=-(\frac{1}{2})^2+\frac{1}{2}+12[/tex]

[tex]k=-\frac{1}{4}+\frac{1}{2}+12[/tex]

[tex]k=\frac{-1+2+48}{4}[/tex]

[tex]k=\frac{49}{4}[/tex]

The vertex of the function is [tex](h,k)=(\frac{1}{2},\frac{49}{4})[/tex]

The x-coordinate of the vertex i.e. [tex]x=-\frac{b}{2a}[/tex] is the axis of symmetry,

So, [tex]x=-\frac{b}{2a}=\frac{1}{2}[/tex] (solved above)

The axis of symmetry is [tex]x=\frac{1}{2}[/tex].

If P and Q are predicates over some domain, and if it is true that Vx(P(x)V Q(x)), must VxP(x) v VæQ(x) also be true? Explain.

Answers

Answer:

It is not true

Step-by-step explanation:

Suppose your domain is the integer numbers. Define

P(x)="x is even"

Q(x)="x is odd"

So we have that the predicate [tex]\forall x(P(x) \vee Q(x))[/tex] is always true because the integers are always even or odd. But the predicate [tex]\forall x P(x) \vee \forall x Q(x)[/tex] means that all the integer numbers are even or all the integer numbers are odd, which is false. So we can't deduce [tex]\forall x P(x) \vee \forall x Q(x)[/tex] from [tex]\forall x(P(x) \vee Q(x))[/tex].

You are asked to bake muffins for a breakfast meeting. Just as you are about to start making them, you get a call saying that the number of people coming to the meeting has doubled! Your original recipe called for three eggs. How many eggs do you need to make twice as many muffins?

Answers

Answer:  6

Step-by-step explanation:

Given : The number of eggs required to make the current muffin receipe = 3

If the number of people coming to the meeting has doubled, then we need twice of as many eggs .

i.e. the number of eggs required to make twice of muffin =[tex]2\times3=6[/tex]

Hence, the number of people coming to the meeting has doubled = 6

A number multiplied by a negative three is 12.
(Can somebody please help me write this into an expression??) :(

Answers

In order to find the answer to this question you will have to find the missing number in the given numbers we have then fill in the blank to make your expression and your answer.

[tex]-3 = 12[/tex]

[tex]-4 \times -3 = 12[/tex]

[tex]= -4[/tex]

Therefore your answer is "-4 * -3 = 12."

Hope this helps.

Suppose that Jane borrows $8400 from a bank on April 9 at an annual rate of 9.2% simple interest. How much does she owe on August 20 of the same year?

Answers

Answer:

274.576 + 8400 = $8674.576

Step-by-step explanation:

Here, Number of days = 21 + 31 +30 +31 +20 = 123

We know that,

[tex]Simple Interest = \frac{P\timesT\timesR}{100}[/tex]

where, P = Principle = 8400

T = time = 123 ÷ 365

R = Rate = 9.2

⇒ [tex]Simple Interest = \frac{8400\times123\times9.2}{365\times100}[/tex]

⇒ Simple Interest = 274.576

Thus, total amount Jane has on 20 August = 274.576 + 8400 = $8674.576

State whether the following statement is true or​ false, and explain why. If the statement is​ false, state the true change. A high school reports that its​ students' SAT scores were down by 12​% in one year. The next​ year, however, the test scores rose by 20​%. The high school principal​ announces, "Overall, test scores have improved by 8​% over the past two​ years."

Answers

False. The high school principal's claim of an overall improvement of 8% is incorrect; the actual improvement is 5.6% over the two years.

Initial SAT scores were down by 12%.

Next year, the scores rose by 20%.

Let's assume the initial SAT score was 100 (just for simplicity):

After the 12% decrease: 100 - 12% of 100

= 88.

After the 20% increase on 88:

88 + 20% of 88

= 105.6.

So, in this scenario, the scores have actually increased from 100 to 105.6, which is an increase of 5.6%, not 8%.

Hence, the high school principal's claim of an overall improvement of 8% is incorrect. The true change is an increase of 5.6% over the two years.

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Final answer:

The principal's statement is false because percentage change does not simply add and subtract, but rather it compounds. After the changes, the scores have increased by 5.6% of the original scores, not 8%.

Explanation:

The statement given by the principal is false. It's a common misconception that you can add and subtract percentages like usual numbers.

Let's say the original score was 100%. A 12% decrease would leave the scores at 88% of their original. The next year, when the scores rose by 20%, it didn't rise by 20% of the original 100%, but 20% of the new 88%, that is, 17.6%, making the new score 105.6% of the original scores.

So, over the two years, the scores did not increase by 8%, but rather, they increased by 5.6% of the original scores. The principal does not correctly understand the mathematical concept of percentage change.

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Use a proof by contradiction to prove that the sum of two odd integers is even CM

Answers

Answer:

The sum of two odd integers is even

Step-by-step explanation:

Proof by contradiction:

We are going to assume that the sum of two odd integers is odd.

An odd integer is written as 2p+1 where p is an integer and an even integer is written as 2p where p is an integer

So, if the sum of two odd integers is odd we would have

[tex](2k+1) + (2p+1) = 2r+1\\2k+1+2p+1=2r+1\\2k+2p+2=2r+1\\2(k+p+1)=2r+1[/tex]

The left side of the equation is clearly an even number while the right side of the equation is odd. Therefore, our hypothesis is wrong and we can conclude that the sum of two odd integers is even.

Keith has 40-pound bags of mulch in his truck that weigh a total of 3600 pounds. His Owner’s Manual lists the truck’s capacity as at most 3000 pounds. How many bags does Keith need to remove in order to meet the weight requirements?
Please show step by step explanation

Answers

Final answer:

Keith is 600 pounds over the weight limit of his truck. Given that each bag of mulch weighs 40 pounds, Keith needs to remove 15 bags of mulch to be within the truck's weight capacity.

Explanation:

This is a straightforward math problem involving subtraction and division. First, let's find out how much weight is over the truck's capacity. Keith's truck is currently carrying 3600 pounds of mulch, but his truck's capacity is only 3000 pounds. So, he is over by 3600 - 3000 = 600 pounds.

Each bag of mulch weighs 40 pounds, so to find out how many bags Keith needs to remove, we simply divide the total excess weight by the weight of each bag: 600 / 40 = 15 bags. Therefore, Keith needs to remove 15 bags of mulch from his truck to meet the weight requirements.

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Final answer:

Keith needs to remove 15 bags of mulch to meet the weight requirements.

Explanation:

To find out how many bags Keith needs to remove, we need to determine the weight of one bag of mulch. If he has 40-pound bags and a total weight of 3600 pounds, we can divide the total weight by the weight of one bag:

Number of bags = Total weight / weight of one bag = 3600 pounds / 40 pounds = 90 bags

Since the truck's capacity is at most 3000 pounds, Keith needs to remove the excess weight:

Excess weight = Total weight - Truck's capacity = 3600 pounds - 3000 pounds = 600 pounds

Now, we can calculate how many bags he needs to remove using the weight of one bag:

Bags to remove = Excess weight / weight of one bag = 600 pounds / 40 pounds = 15 bags

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Find an equation of a line with the x- and y-intercepts below. Use exact fractions when necessary.

x-intercept 7; y-intercept -5

Answers

Answer:

The line with the x- and y-intercepts below has the following equation:

[tex]f(x) = \frac{5x}{7} - 5[/tex]

Step-by-step explanation:

The equation of the line has the following format:

[tex]f(x) = ax + b[/tex]

We are given two points, we are going to substitute them into the above equation, and find the equation of the line given the conditions.

Solution

Starting from the y-intercept makes the solution easier, since the term a is multiplied by 0

y-intercept -5

This means that when [tex]x = 0, y = f(x) = -5[/tex], so:

[tex]f(x) = ax + b[/tex]

[tex]-5 = a(0) + b[/tex]

[tex]b = -5[/tex]

For now, the line has the following equation:

[tex]f(x) = ax - 5[/tex]

x-intercept 7

This means that when [tex]y = f(x) = 0,x = 7[/tex], so:

[tex]f(x) = ax - 5[/tex]

[tex]0 = 7(a) - 5[/tex]

[tex]7a = 5[/tex]

[tex]a = \frac{5}{7}[/tex]

So, the line with the x- and y-intercepts below has the following equation:

[tex]f(x) = \frac{5x}{7} - 5[/tex]

Determine whether p ∧ (p → q) and p ∧ q are logically equivalent.

Answers

Answer:

Yes they are logically equivalent

p∧(p→q)≡p∧q

Step-by-step explanation:

The statements are logically equivalent if they have the same truth tables. So let´s use truth tables in order to determine if they are logically equivalent or not:

The picture that I attached you shows the truth table for each case. As you can see, p∧(p→q) has exactly the same truth values as p∧q. So we can conclude that they are logically equivalent.

Subtract : 8,878-2,314

5.4 from 12 ( the difference is.....

Answers

Answer:

1st question : 6564

2nd question : 6.6

Step-by-step explanation:

We have to subtract 8,878-2,314.

We will subtract the smaller number from greater number.

So, the answer will be = 6564

We also have to subtract 5.4 from 12 .

Hence, the difference will be = 6.6

Quadratic Functions Put the equationy = x^2 + 14a + 40 into the form y = (x - h )^2 + k: Answer: y Preview Get help: Video Poins

Answers

Answer:

The required form is [tex]y=(x+7)^2-9[/tex].

Step-by-step explanation:

Consider the provided quadratic function.

[tex]y=x^2 + 14x + 40[/tex]

We need to put the equation into the form [tex]y = (x - h )^2 + k[/tex]

Add and subtract 49 in order to make the above function a perfect square.

[tex]y=x^2 + 14x+49-49 + 40[/tex]

[tex]y=x^2 + 14x+7^2-49 + 40[/tex]

[tex]y=(x+7)^2-49 + 40[/tex]

[tex]y=(x+7)^2-9[/tex]

Hence, the required form is [tex]y=(x+7)^2-9[/tex].

A vial contains 80 mg of drug in 2 mL of injection. How many milliliters of the injection should be administered to obtain 0.02 g of the drug?

Answers

Answer:

0.5mL of the injection should be administered to obtain 0.02 g of the drug.

Step-by-step explanation:

First step: The first step of this problem is the conversion of 0.02g to mg.

Each gram has 1000 miligrams. So:

1g - 1000mg

0.02g - xmg

x = 1000*0.02

x = 20mg

Final step:

A vial contains 80 mg of drug in 2 mL of injection. How many mL should be administered to obtain 0.02 g = 20mg of the drug.

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

In this step, as the dose of the injection increases, so the quantity of the drug. So the relationship between the measures is direct. So:

80 mg - 2mL

20 mg - xmL

80x = 40

[tex]x = \frac{40}{80}[/tex]

x = 0.5mL

0.5mL of the injection should be administered to obtain 0.02 g of the drug.

Final answer:

To obtain 0.02 grams of the drug, the required volume to administer from the vial containing 80 mg in 2 mL is 0.5 mL.

Explanation:

To solve this problem, we need to determine how many milliliters contain 0.02 grams of the drug. First, convert the amount we want from grams to milligrams since our given concentration is in milligrams: 0.02 grams is equal to 20 milligrams.

Given that the vial contains 80 mg of drug in 2 mL, we can calculate the volume required for 20 mg. The formula we will use is:

(desired dose / concentration of vial) × volume of vial = required volume

(20 mg / 80 mg) × 2 mL = 0.5 mL

Therefore, to obtain 0.02 grams (20 mg) of the drug, the required volume to administer would be 0.5 mL.

Find all values of m so that the function y = xm is a solution of the given differential equation. (Enter your answers as a comma-separated list.)

x^2y'' − 14xy' + 54y = 0

m =

Answers

Answer:

m = 6,9  

Step-by-step explanation:

We are given that [tex]y = x^m[/tex] is a solution to given differential equation.

[tex]x^2y'' - 14xy' + 54y = 0[/tex]  

First we 3evaluate the value of:

[tex]y'' = m(m-1)x^{(m-2)}[/tex]

[tex]y' = mx^{(m-1)}[/tex]

Putting these value in the above differential equation, we get,

[tex]x^2m(m-1)x^{(m-2)} + 14xmx^{(m-1)} + 54x^m = 0[/tex]

[tex]x^m[m(m-1) -14m + 54] = 0[/tex]

[tex]x^m(m^2 - 15m + 54) = 0[/tex]

[tex](m^2 - 15m + 54) = 0[/tex]

[tex](m-9)(m-6) = 0[/tex]

[tex]m = 9,6[/tex]

Thus, for m = 9,6 , the function [tex]y = x^m[/tex] is a solution of given differential equation.

Values of m so that the function [tex]y = x^m[/tex] is a solution of the given differential equation are 6 and 9 and this can be determined by differentiating the [tex]y = x^m[/tex].

Given :

[tex]y = x^m[/tex][tex]x^2y"-14xy'+54y = 0[/tex]   ------ (1)

The following calculations can be used to determine the value of 'm':

[tex]y = x^m[/tex]  ---- (2)

Now, differentiate the above equation with respect to 'x'.

[tex]\dfrac{dy}{dx}=\dfrac{d}{dx}(x^m)[/tex]

[tex]y' = mx^{m-1}[/tex]   ----- (3)

Now, differentiate equation (2) with respect to 'x'.

[tex]\dfrac{d^2y}{dx^2}=\dfrac{d}{dx}(mx^{m-1})[/tex]

[tex]y" = m(m-1)x^{m-2}[/tex]    ----- (4)

Now, put the values of y, y', and y" in equation (1).

[tex]x^2\times m(m-1)x^{m-2}-14x(mx^{m-1})+54x^m=0[/tex]

[tex]x^m(m(m-1)-14m+54)=0[/tex]

[tex]x^m(m^2-15m+54)=0[/tex]

(m - 9)(m - 6) = 0

m = 9 , 6

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In Exercises 15-22, change the number given as a percent to a decimal number. 15. 7% 0.07 18, 0.75% 0.0075 212 135.9% 1.359 17, 5.15% 00515 16.39% 0.39 19, %00025 22, 298.7% 2.987 20. % 0.00375 27.

Answers

Step-by-step explanation:

We are asked to convert given percent to a decimal number.

We know to convert a number to decimal, we divide given percent by 100 as percent means per hundred.

We also know that to divide a number by hundred, we need to move decimal to two digits to left.

(15). [tex]7\%[/tex]

[tex]7\%=\frac{7}{100}=0.07[/tex]

(16). [tex]39\%[/tex]

[tex]39\%=\frac{39}{100}=0.39[/tex]

(17). [tex]5.15\%[/tex]

[tex]5.15\%=\frac{5.15}{100}=0.0515[/tex]

(18). [tex]0.75\%[/tex]

[tex]0.75\%=\frac{0.75}{100}=0.0075[/tex]

(19). [tex]\frac{1}{4}\%[/tex]

[tex]\frac{1}{4}\%=\frac{\frac{1}{4}}{100}=\frac{1}{4*100}=\frac{1}{400}=0.0025[/tex]

(20). [tex]\frac{3}{8}\%[/tex]

[tex]\frac{3}{8}\%=\frac{\frac{3}{8}}{100}=\frac{1}{8*100}=\frac{3}{800}=0.00375[/tex]

(21). [tex]135.9\%[/tex]

[tex]135.9\%=\frac{135.9}{100}=1.359[/tex]

(22). [tex]298.7\%[/tex]

[tex]298.7\%=\frac{298.7}{100}=2.987[/tex]

A patient is ordered 60 mg/kg/day of an antibiotic to be divided in 3 doses per day. The patient weighs 60 kg. How many mg of drug should they receive per dose and how many mg of drug should they receive per day Round answers to the nearest tenth and DO NOT include units

Answers

Answer:

3600 mg of drug per day.

[tex]\text{The amount of drug per dosage}=\text{1200 mg}[/tex]

Step-by-step explanation:

We have been given that a patient is ordered 60 mg/kg/day of an antibiotic.

Since the weight of the patient is 60 kg, so the dosage of drug per day would be 60 mg times 60.

[tex]\text{The dosage of drug per day}=\frac{\text{60 mg}}{\text{ kg}}\times 60\text{ kg}[/tex]

[tex]\text{The dosage of drug per day}=\text{60 mg}\times 60[/tex]

[tex]\text{The dosage of drug per day}=\text{3600 mg}[/tex]

Therefore, the patient should receive 3600 mg of drug per day.

Since the patient gets 3 doses per day, so dosage of drug per dosage would be amount of drug per day divided by 3.

[tex]\text{The amount of drug per dosage}=\frac{\text{3600 mg}}{3}[/tex]

[tex]\text{The amount of drug per dosage}=\text{1200 mg}[/tex]

Therefore, the amount of drug per dosage would be 1200 mg.

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