Answers
Slope formula: [tex]\frac{y_{1}-y_{2}}{x_{1}-x_{2}}[/tex]
Given the two sets of coordinates (8,0) and (0,-2), plug them into the formula to find the slope. x1 is 8, x2 is 0, y1 is 0, y2 is -2.
[tex]\frac{0-(-2)}{8-0}[/tex]
[tex]\frac{0+2}{8-0}=\frac{2}{8}=\frac{1}{4}[/tex]
The slope is[tex]\frac{1}{4}[/tex].
I hope this helps :)
Related Questions
In the diagram shown, ∠a and ∠h are______. A) vertical angles B) linear pair angles C) corresponding angles D) alternate exterior angles
Answers
Answer:
The correct answer is D) Alternate Exterior Angles
Answer: D) Alternate Exterior Angles
Step-by-step explanation: Did it on USATP !
What are the steps for using a compass and straightedge to construct the bisector of ∠G? Two rays share a common endpoint labeled G, forming an obtuse angle. One ray is horizontal and points right. The second ray is inclined to horizontal in upward-left direction. Drag the steps and drop them in order from start to finish. Without changing the opening of the compass, place the point of the compass on point J and draw another arc in the interior of the angle.Use the straightedge to draw GK−→−.Place the point of the compass on point H and draw an arc in the interior of the angle.Label the intersection of the arcs in the interior of the angle as point K.Place the point of the compass on point G and draw an arc that intersects the sides of ∠G. Label the points of intersection as points H and J.
Answers
Answer:
The Quiz Was Updated This Is It Now
Step-by-step explanation:
DO IN ORDER!
Thee steps for using a compass and straightedge to construct the bisector of ∠G is given in the image attached.
How to construct the bisectorSo, the correct order of the steps from beginning is:
Place the point of the compass on point J and draw another arc in the interior of the angle.Use the straightedge to draw GK.Place the point of the compass on point H and draw an arc in the interior of the angle.Label the intersection of the arcs in the interior of the angle as point K.Place the point of the compass on point G and draw an arc that intersects the sides of ∠G.Label the points of intersection as points H and J.Learn more about bisector from
https://brainly.com/question/17526982
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For inequalities. Greater Than, >, and Less Than, <, mean the solution does NOT contain the number. So would you use and open circle or a closed circle to graph on a number line ___________________ For inequalities. Greater Than or Equal TO, >, and Less Than or Equal TO, <, mean the solution does contain the number. So would you use and open circle or a closed circle to graph on a number line?____________________
Answers
I need help with 23 please!!!
Answers
Answer:
28 questions
Step-by-step explanation:
In the first 10 mins she answered 2/5 of 40 which is 16. The remaining amount is 24 questions and half of that is 12. So she answered 12 questions in 15 mins. Finally you add them to get 28 questions in 25 minutes.
Find the product. -2 x ( x2 - 3) -2 x3 - 6 x -2 x3 + 6 x -2 x2 + 6 x 6 x3
Answers
[tex]-2x(x^2-3)\qquad|\text{use distributive property}\\\\=(-2x)(x^2)+(-2x)(-3)=-2x^3+6x[/tex]
True or False: The following relation is a function. {(−5,−7),(0,4),(−5,3),(9,4)}
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the answer is that it is false
In two weeks, your class collected more than 380 cans of food for the annual food drive. In the first week, 145 cans were collected. How many cans c of food were collected in the second week? Write and solve an inequality.
Answers
145 + c = 380
145 - 145 + c = 380 - 145 -Subtract 145 from both sides of the equation
c = 235
So, they collected 235 cans in the second week.
Hope this helps!
To find out how many cans of food were collected in the second week, subtract the number of cans collected in the first week from the total number of cans collected in two weeks. The inequality representing the problem is c + 145 > 380. Solving the inequality, we find that more than 235 cans were collected in the second week.
Explanation:To find out how many cans of food were collected in the second week, we can subtract the number of cans collected in the first week from the total number of cans collected in two weeks. Let's assign a variable, c, to represent the number of cans collected in the second week. The inequality that represents the problem is: c + 145 > 380. To solve this inequality, we need to isolate the variable by subtracting 145 from both sides: c > 380 - 145. Simplifying further, we get c > 235. So, more than 235 cans of food were collected in the second week.
Learn more about Inequality here:https://brainly.com/question/32625151
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algedratic expression for word phrase the quotient of y and 6
Answers
we are given
the quotient of y and 6
we always start from left to right order of operation
we know that
quotient means division
so, we can write as
the quotient of y and 6 is
[tex]\frac{y}{6}[/tex]...............Answer
What is the area of polygon IJKL?
A.
120 square units
B.
125 square units
C.
130 square units
D.
140 square units
E.
150 square units
Answers
ANSWER
The correct answer is E
EXPLANATION
Polygon IJKL is a rectangle.
The area is given by;
[tex]Area=l\times w[/tex]
The coordinates of I are [tex](5,8)[/tex] and L[tex](-5,8)[/tex].
This is a horizontal line so it will be faster using the absolute value method rather than the distance formula
The length is
[tex]|IL|=|5--5|[/tex]
[tex]|IL|=|5+5|[/tex]
[tex]|IL|=|10|[/tex]
[tex]|IL|=10[/tex]
units
The coordinates of K are [tex](-5,-7)[/tex] and L[tex](-5,8)[/tex].
The width is
[tex]|LK|=|8--7|[/tex]
[tex]|LK|=|8+7|[/tex]
[tex]|LK|=|15|[/tex]
[tex]|LK|=15[/tex]
units
Therefore
[tex]Area=10\times 15[/tex]
[tex]Area=150[/tex] square units
The coordinates of K are [tex](-5,-7)[/tex] and L[tex](-5,8)[/tex].
Answer:
The correct answer option is E. 150 square units.
Step-by-step explanation:
A polygon is figure with at least 3 straight or definite sides or typically 5 or more straight sides.
Here the polygon we are given is a rectangle.
We know that,
Area of a rectangle = l x w
so we need to measure the length and width of the rectangle to find its area.
If we look closely, we can see the length of the rectangle above the x-axis is 8 units and the length below the x-axis 7 units which makes a total og 15 units.
While the width is 10 units (5 units on each side of the y-axis).
Area of the rectangle = 15 x 10 = 150 square units.
Therefore, the area of the polygon is 150 square units.
3x567 estimate rounding?
Answers
567 would round out to 600. If you are also rounding the three, then that is one. The answer to that would be 600. If you aren't rounding the three, the answer would be 1800.
Answer:
1800
Step-by-step explanation:
567 = 600 rounded to nearest hundred
3 * 600 = 1800
I need help with this.
10 POINTS!
Answers
Augusta sells t-shirts at the school store. On Tuesday, Augusta sold 7 less than twice the number of t-shirts she sold on Monday. She sold 3 t-shirts on Tuesday. Write an algebraic equation to represent m, the number of t-shirts August sold on Monday.
Answers
Since it is true that 9=9, the answer x=2 works.
As equations get more complex it is important to use properties of equality to isolate the variable and solve the equation.
Here are the properties of equality you need to isolate terms and solve equations.
The Subtraction Property of Equality is used when you have an equation with addition in it. It states that you can subtract the same quantity from both sides of the equation without changing the equality.
The Addition Property of Equality is used when you have an equation with subtraction in it. It states that you can add the same quantity to both sides of the equation without changing the equality.
The Division Property of Equality is used when you have an equation with a variable multiplied by a number. It states that you can divide both sides of an equation by the same quantity (as long as that quantity is not equal to zero) without changing the equality.
The Multiplication Property of Equality is used when you have an equation with a variable divided by a number. It states that you can multiply both sides of an equation by the same quantity without changing the equality.
Let’s look at an example and use properties of equality to isolate the variable and solve the equation.
Mark me as brainliest anser
Antoni has read 147 pages of a book.He has completed 70% of the book.How many more pages does he need to read to finish the book
Answers
Will give brainliest. Some one please help your mans out please.
Identify the range of the function.
A)
R:{y| 0 ≤ y < 5}
B)
R:{y| 0 < y ≤ 5}
C)
R:{y| −4 ≤ y < 4}
D)
R:{y| −4 < y ≤ 4}
Answers
A)
R:{y| 0 ≤ y < 5}
Answer:
a) R: { y | 0 ≤ y < 5 }
Step-by-step explanation:
The lowest point on the graph (-4, 0) - point painted over ( ≤ ).
The highest point of the chart - close (4, 5) - point not painted over ( < ).
write 156x10^ -7 in standard form
Answers
.0000156
Hope I helped!
Good Luck!
Which is a true statement comparing the graphs of x^2/3^2 - y^2/4^2= 1 and y^2/3^2 - x^2/4^2 = 1?
The foci of both graphs are the same points.
The lengths of both transverse axes are the same.
The directrices of = 1 are horizontal while the directrices of = 1 are vertical.
The vertices of = 1 are on the y-axis while the vertices of = 1 are on the x-axis.
Answers
Answer: B) The lengths of both transverse axes are the same.
Step-by-step explanation: Given Hyperbola equations :
[tex]\frac{x^2}{3^2}-\frac{y^2}{4^2}=1[/tex] and
[tex]\frac{y^2}{3^2}-\frac{x^2}{4^2}=1[/tex]
First one : [tex]\frac{x^2}{3^2}-\frac{y^2}{4^2}=1[/tex] is a Horizontal Hyperbola.
a = 3 and 2a = 6.
Length of transverse axis = 6.
And second one : [tex]\frac{y^2}{3^2}-\frac{x^2}{4^2}=1[/tex] is a Vertical Hyperbola.
b=3 and 2b = 6
Length of transverse axis = 6.
The lengths of both transverse axes are the same.
Therefore, correct option is B option :
The lengths of both transverse axes are the same.Answer:
B
Step-by-step explanation:
You start at (8, 1). You move right 2 unit and left 3 units. Where do you end?
Answers
You should end around: (9,1) hope this helps!
if you move right 2 and left 3 one time you get 10.4, do it again you get 11.7 again 13.10
Pls help I don’t under stand this
Answers
Hello Queengirl0
Past tense:
Melissa has a full chocolate bar 8/8
At lunch:
Melissa ate 2/8 of the candy bar, 8/8 - 2/8 = 6/8
After school:
Melissa ate 3/8 of the candy bar, 6/8 - 3/8 = 3/8
Melissa has 3/8 of a chocolate bar left
:)
in a triangle, if the second angle is 2 times the first angle and the third angle is 3 times the first angle,find the angles of the triangle.
Answers
a + b + c = 180
b = 2a
c = 3a
a + 2a + 3a = 180
6a = 180
a = 30
b = 2(30)
b = 60
c = 3(30)
c = 90
Answer:
a = 30
b = 60
c = 90
PLEASE HELP!!
At 6:00 p.m. the temperature was -5*F outside. By midnight the temperature had dropped 12 degrees. What was the temperature at midnight?
A) -7*F
B) -17*F
C) 17*F
Answers
-5-12=-17 so it is b)
what is 7.08 as mixed number
Answers
7 8/100 or 7 2/25 in lowest terms
7 2/25 is your answer
your welcome
what is the sum: (1−5q)+2(2.5q+8)
Answers
The answer is seventeen
Convert decimal to fraction: .0167
Answers
We are to convert 0.0167 to fraction.
Trick 1: Count the number of decimal values in our number which is 4.
Trick 2: Write 1 followed by 4 zeros (the four you counted to above). This gives 10000 which is our denominator.
Trick 3: Retrieve our denominator by writing down the whole number which can be observed in 0.0167. That whole number is 167.
Trick 4: Now put your results in the fraction form. That is in numerator/denominator form.
This gives 167/10000
Trick 5: Try to simplify further. You can't! So the answer is:
[tex]\frac{167}{10000}[/tex]
Let g be the function given by g(x)=-3x^2-2x+3 evaluate g(-2)
Answers
g(x) = -3x² - 2x + 3
g(-2) = -3(-2)² - 2(-2) + 3
g(-2) = -12 + 4 + 3 = -5
Write an explicit formula for an arithmetic sequence whose common difference is -4.5
Answers
For this case we have:
The general formula of the arithmetic sequence is given by:
[tex]a_n = a_1 + (n-1) d\\[/tex]
Where
[tex]a_n[/tex]: Last term
[tex]a_1[/tex]: First term
n: Number of terms
d: Difference
Rewriting according to the given common difference, we have:
[tex]a_n = a_1 + (n-1) (- 4.5)[/tex]
Answer:
[tex]a_n = a_1 + (n-1) (- 4.5)[/tex]
The explicit formula for an arithmetic sequence whose common difference is -4.5 is:
[tex]a_n=a_1-4.5(n-1)[/tex]
Step-by-step explanation:Explicit formula--
Explicit formula is the formula which is used to find the nth term of a sequence.
We know that the explicit formula for an arithmetic sequence is given by:
[tex]a_n=a_1+(n-1)d[/tex]
where d is the common difference of the sequence and [tex]a_1[/tex] is the first term of the sequence.
We have: d= -4.5
Hence, the explicit formula is given by:
[tex]a_n=a_1-4.5(n-1)[/tex]
Lilliana’s hair was originally 48 inches long. She asked her hair dresser to cut 2/3 of her hair off. How long was her hair after her haircut.
Answers
—- • —- = —- 96/3 = 32 48-32 = 16
1 3 3
So her hair is 16 inches long now
Lilliana's hair was 48 inches long and she cut off 2/3 of it. After calculating 2/3 of 48, which is 32 inches, we subtract this from the original length. Lilliana's hair was 16 inches long after her haircut.
The student's question concerns the length of Lilliana's hair after she has asked her hairdresser to cut 2/3 of it off. If we know that Lilliana's hair was originally 48 inches long, we need to calculate 2/3 of this length and then subtract it from the original length to find the new length of her hair after the haircut.
Calculate 2/3 of 48 inches: (2/3) times 48 = 32 inches.
Subtract the amount cut from the original length: 48 inches - 32 inches = 16 inches.
Therefore, after Lilliana's haircut, her hair was 16 inches long.
Susan uses 15 rolls of ribbon to decorate 10 wedding baskets. Each roll of ribbon is
[tex]5 \frac{3}{8} [/tex]
yards long. After she decorates the baskets, she decides to cut off another
[tex] \frac{3}{4} [/tex]
yard from the ribbons of each basket. Write and simplify an expression to find out how much ribbon was used on the baskets.
Answers
Answer:
Amount of ribbon used = [tex]73 \frac{1}{8} yards[/tex] = 73.125 yards.
Explanation:
Number of ribbon rolls = 15
Number of wedding basket = 10
Length of 1 ribbon roll = [tex]5\frac{3}{8}=\frac{5*8+3}{8} =\frac{43}{8}[/tex] yards.
Total length of 15 ribbon roll = [tex]15*\frac{43}{8} =\frac{645}{8}[/tex]yards.
Length of ribbon cutting from each basket = [tex]\frac{3}{4}[/tex]yards.
Total length of ribbon cutting from 10 baskets = [tex]10*\frac{3}{4}=\frac{15}{2}[/tex] yards
Amount of ribbon used
[tex]=\frac{645}{8}-\frac{15}{2}=\frac{645}{8}-\frac{15*4}{2*4}=\frac{645}{8}-\frac{60}{8}\\ \\ =\frac{585}{8} =73 \frac{1}{8} yards[/tex]
Amount of ribbon used = [tex]73 \frac{1}{8} yards[/tex] = 73.125 yards.
I WILL GIVE BRAINLIEST!!! EASY POINTS
Drag an answer to each box to complete this paragraph proof.
Given: Triangle PQR with m∠P=(x)° , m∠Q=(3x)° , and m∠R=(5x)° .
Prove: x = 20
Answers
The answer for the first one is (x)°+(3x)°+(5x)°=180° and the answer for the second one is x=20. If you need me to explain how they got the answer, i'm here.
Answer:
Fill the blanks
1) (x)°+(3x)°+(5x)°=180°
2) x°=20°
Step-by-step explanation:
Consider the provided information.
Given: Triangle PQR with m∠P=(x)°, m∠Q=(3x)°, and m∠R=(5x)°.
We need to prove that x = 20
Consider the provided figure.
By the triangle sum theorem the sum of the angles in a triangle is equal to 180. Therefore using the give and triangle sum theorem,
m∠P+m∠Q+m∠R=180°
Now use substitution property.
(x)°+(3x)°+(5x)°=180°
Simplify the equation gets
9x°=180°
Finally, using the division property of equality.
9x°/9=180°/9
x°=20°
Hence proved
Can anyone help me please?? I’m so stuck
Answers
-60 -60
x=56 degrees
Explanation: Remote Triangles
∠DAB and ∠BAD form a linear pair, so ∠DAB + ∠BAD = 180°
116° + ∠BAD = 180° substituted
∠BAD = 64° subtracted 116° from both sides
ΔABC
∠A + ∠B + ∠C = 180° triangle angle sum theorem
64° + x + 60° = 180° substitution
x + 124° = 180° added like terms
x = 56° subtraction property
Answer: 56°
247x82 using in area model
Answers
247x82=534 5 go in the hundreads place 3 go in the tens place and 4 go in the ones place