find the weight density 1.00 qt. of liquid weighing 4.00 lb.​

Answer:by carbon and oder element

Explanation:

The Precambrian eon is different from the Phanerozoic eon due to the fact that the fossil present from the Precambrian eon was of mostly microorganisms which are single cellular organisms.

Explanation:

The Phanerozoic eon was marked with eon which had the multi cellular organism that is the level of cellularity was enhanced by this eon due to the evolutionary course taken for the organisms. Phanerozoic eon and Precambrian eon had a vast difference of cellular level of organization found in the fossil remains of both times.  

Precambrian eon had many primitive algae which existed mostly till the earliest Cambrian era only. Due to single cellularity of the organisms, the fossil of Precambrian eon was not much in abundance whereas the Phanerozoic eon had much abundant fossil remains.

Answer:

4.351968e+17 seconds

Explanation:

So I googled age of the universe and it says 13.8 billion years.

you'll have to do some conversions:

in one year, there are 365 days. in one day, there are 24 hours. in one hour, there are 3600 seconds.

[tex]\frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}[/tex]

so you have to add in the current age of the universe to that equation:

[tex]\frac{x seconds}{13.8 bil years} x \frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}[/tex]

arranged so that the proper "units" will read as "x seconds" at the end of the equation.

then you do the math to find x:

13.8 billion x 365 x 24 x 3600 = 4.351968e+17 seconds.

which would be 435,196,800,000,000,000 seconds

Hope this helps :)

Final answer:

The age of the universe is approximately 13.8 billion years, estimated using the Hubble constant. For a Hubble constant of 70 kilometers/second per million parsecs, the age of the universe is about 13.8 billion years. The age of the universe is approximately 13.799 billion years. Converting this into seconds, we get around 4.358 × 10^17 seconds with a margin of error due to uncertainty.

Explanation:

The student has asked for the age of the universe in seconds. To determine this, we use the currently accepted estimate for the age of the universe, which is approximately 13.799 billion years. To convert this age into seconds, we follow these steps:

First, convert the age in years to seconds by multiplying by the number of seconds in a year (31,536,000). Since there are ± 0.038 billion years of uncertainty, calculate the margin of error in seconds by multiplying 0.038 billion years by the number of seconds in a year. Performing the calculations, we find that the age of the universe in seconds is approximately 4.358 × 10^17 seconds, with an uncertainty of about 1.2 × 10^15 seconds. This answer provides an estimation based on the current understanding of astrophysics and cosmology.

Answer:

a) -1.14 rev/min²

b) 9900 rev

c) -9.92×10⁻⁴ m/s²

d) 30.8 m/s²

Explanation:

First, convert hours to minutes:

2.2 h × 60 min/h = 132 min

a) Angular acceleration is change in angular velocity over change in time.

α = (ω − ω₀) / t

α = (0 rev/min − 150 rev/min) / 132 min

α = -1.14 rev/min²

b) θ = θ₀ + ω₀ t + ½ αt²

θ = 0 rev + (150 rev/min) (132 min) + ½ (-1.14 rev/min²) (132 min)²

θ = 9900 rev

c) The tangential component of linear acceleration is:

a_t = αr

First,  convert α from rev/min² to rad/s²:

-1.14 rev/min² × (2π rad/rev) × (1 min / 60 s)² = -1.98×10⁻³ rad/s²

Therefore:

a_t = (-1.98×10⁻³ rad/s²) (0.50 m)

a_t = -9.92×10⁻⁴ m/s²

d) The magnitude of the net linear acceleration can be found from the tangential component and the radial component:

a² = (a_t)² + (a_r)²

The radial component is the centripetal acceleration:

a_r = v² / r

a_r = ω² r

First, convert 75 rev/min to rad/s:

75 rev/min × (2π rad/rev) × (1 min / 60 s) = 7.85 rad/s

Find the radial component:

a_r = (7.85 rad/s)² (0.50 m)

a_r = 30.8 m/s²

Now find the net linear acceleration:

a² = (-9.92×10⁻⁴ m/s²² + (30.8 m/s²)²

a = 30.8 m/s²

The angular acceleration of the flywheel is -1.14 rev/min². It makes 9,900 revolutions before stopping. The tangential component of the linear acceleration at 75 rev/min is 3.927 m/s² and the net linear acceleration is 31.08 m/s².

The following are the solutions to those physics problems (assuming no slip, only the deceleration is involved) :

https://brainly.com/question/32123193

#SPJ2

Answer:

Blind search

Explanation:

The blind search is a problem solving strategy which can be used to solve the problems of relatively simpler nature, and can only distinguish non-goal and goal state with no idea that which state is more promising.

In this example, blind search was used to reach the goal (Going up and down each isle).

Hope it helps!

[tex]a = \frac{v - u}{t} [/tex]

^^acceleration formula

[tex]s = \frac{1}{2} (u + v) \: t[/tex]

^^displacement formula

since the acceleration due to gravity is 9.8m/s^2 or 10m/s^2

9.8 = v-0/5

v = 49m/s

s= 1/2 (49m/s +0 m/s) 5

s= 122.5m

Explanation:

The first echo travels from the helicopter to the surface and back.  The second echo travels from the helicopter to the surface to the bottom of the lake and then back.

We know the difference in time is 0.24 s, so the time it takes the sound wave to travel through only the water is 0.24 s.  Since the sound wave covers the distance twice (first from the surface to the bottom, then the bottom to the surface), we only want half the time, 0.12 s.

The speed of sound in water at 20°C is 1481 m/s.  Therefore:

d = 1481 m/s × 0.12 s

d = 178 m

The depth of the lake is 178 meters (round as needed).

To calculate the depth of the lake, use the speed of sound at 20°C (343 m/s) and multiply it by the time difference (0.24s) between the echoes. This product gives the total distance sound traveled, which is twice the depth of the lake. The depth is found by dividing this distance by two, resulting in 41.16 meters.

The student is asking about determining the depth of a lake using sound waves from a hovering helicopter that are reflected from the surface of the water and the bottom of the lake. The time difference between the arrivals of the two echoes is given, and the speed of sound at 20°C needs to be used in the calculations. Since the speed of sound at this temperature is approximately 343 m/s, the total distance traveled by the sound waves is the speed of sound multiplied by the time difference between the echoes. This total distance is twice the depth of the lake, because the sound travels to the lake bottom and back up. Dividing this total distance by two gives the depth of the lake.

The formula to calculate the total distance traveled by the sound is:

Total distance = Speed of sound × Time difference

To find the depth, we divide the total distance by two:

Depth = (Speed of sound × Time difference) / 2

Depth calculation:

Total distance = 343 m/s × 0.24 s = 82.32 m
Depth = 82.32 m / 2 = 41.16 m

The depth of the lake is therefore 41.16 meters.

Answer:

1.Theimage will be located at -0.13m or -13 cm

2.The height of the image will be 0.052m or 5.2cm

Explanation:

Given that;

Height of object, h=20 cm = 0.2m

Object distance in front of convex mirror, o,= 50 cm =0.5m

Radius of curvature, r, =34 cm =0.34m

Let;

Image distance, i,=?

Image height, h'=?

You know that focal length,f, is half the radius of curvature,hence

f=r/2 = 0.34/2 = 0.17m ( this length is inside the mirror, in a virtual side, thus its is negative)

f= -0.17m

Apply the relationship that involves the focal length;

[tex]=\frac{1}{o} +\frac{1}{i} =\frac{1}{f}[/tex]

[tex]=\frac{1}{0.5} +\frac{1}{i} =-\frac{1}{0.17}[/tex]

Re-arrange to get i

[tex]\frac{1}{i} =-2-5.88\\\\\\\frac{1}{i} =-7.88\\\\i=-0.13m[/tex]

This is a virtual image formed at a negative distance produced through extension of drawing rays behind the mirror if you use rays to locate the image behind the mirror

Apply the magnification formula

magnification, m=height of image÷height of object

[tex]m=\frac{h'}{h} =-\frac{i}{o}[/tex]

substitute the values to get the height of image h'

[tex]\frac{h'}{0.20} =-\frac{-0.13}{0.5} \\\\\\h'=\frac{0.13*0.20}{0.5} \\\\\\h'=\frac{0.025}{0.5} =0.052m\\\\\\h'=5.2cm[/tex]

Explanation:

The density [tex]D[/tex] of the water is given by a relation between its mass [tex]m[/tex] and its volume [tex]V[/tex]:

[tex]D=\frac{m}{V}[/tex]

Isolating the volume:

[tex]V=\frac{m}{D}[/tex]

This means the volume of the water will depend on its mass and its density.

In this sense, the two factors that affect the volume of seawater are salinity level and temperature.

This is because the salinity (amount of salt in water) changes the its mass and its density, therefore its volume. The higher the salinity, the greater the volume.  

In the case of temperature, when it increases, the volume of water also increases and when the temperature decreases, the volume also decreases.

Answer:

D. Salinity level and temperature

Explanation:I took the test

Answer:

A. 60 Joule

Explanation:

First find the force given the pressure and area.

F = AP

F = 500 cm² × (1 m / 100 cm)² × 4000 N/m²

F = 200 N

Now find the work:

W = Fd

W = 200 N × 30 cm × (1 m / 100 cm)

W = 60 J

Explanation:

Pressure is the ratio of normal force to the area.

[tex]\texttt{Pressure = }\frac{\texttt{Normal force}}{\texttt{Area}}[/tex]

Force = Pressure x Area

Area = 500 cm² = 0.05 m²

Pressure = 4000 Pa

Force = 0.05 x 4000 = 200 N

We know that

                Work done = Force x Displacement

                 W = F x d

                 Displacement, d = 30 cm = 0.3 m

                 W = 200 x 0.3 = 60 Joules.

Option A is the correct answer.

Explanation:

Ohm's law describes the relationship between voltage, current, and resistance.

V = IR

where V is voltage, I is current, and R is resistance.

A. At the original voltage:

V₁ = I₁ R₁

When the voltage is doubled and resistance stays the same:

2V₁ = I₁' R₁

Dividing the two equations:

2V₁ / V₁ = (I₁' / I₁) (R₁ / R₁)

2 = I₁' / I₁

So the new current is double the original current.

B. At the original voltage and resistance:

V₂ = I₂ R₂

When both the voltage and resistance are increased by a factor of 2:

2V₂ = I₂' (2R₂)

Dividing the two equations:

(2V₂ / V₂) = (I₂' / I₂) (2R₂ / R₂)

2 = (I₂' / I₂) (2)

1 = I₂' / I₂

So the new current is the same as the original current.

Based on Ohm's Law, if voltage in an electric circuit is doubled, the current also doubles. However, if both voltage and resistance are doubled, the current remains the same.

The subject you're asking about is focused on how changes in voltage and resistance can affect current, according to Ohm's law. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. It can be represented by the formula I = V/R, where I is the current through the conductor, V is the voltage, and R is the resistance.

If the voltage is increased by a factor of 2, while the resistance remains constant, the current would also increase by a factor of 2. So the ratio Ifinal1/Iinitial1 would be 2/1 = 2.

If both the voltage and resistance are increased by a factor of 2, the current would remain the same, because the increase in voltage would be offset by the increase in resistance. Thus, the ratio Ifinal2/Iinitial2 would be 2/2 = 1.

https://brainly.com/question/36009177

#SPJ3

Answer:A)

Explanation:

Well It makes the Most sense. The momentum of the Cars were lessened due to the hit.

B is wrong because not only did the red car crash but so did the blue so the real answer should be both.

C makes no sense at all.

D The momentum is lost after collision so it is not the same, so this is false also.

HOPE THIS HELPS! :)

Answer:  The correct answer is :  Hues

Explanation:  The spectrum is made up of three primary light colors that are red, green and blue. For three secondary colors that are yellow, cyan and magenta. For six tertiary colors that are orange, lemon green, turquoise, light blue, violet and teal. The spectrum does not contain all the colors that human eyes and the brain can distinguish, for example magenta, pink and coffee are not in the visible spectrum because the mixing of several wavelengths, mainly dark reds, is required .

The visible spectrum includes the colors red, orange, yellow, green, blue, indigo, and violet, with specific wavelengths assigned to each. These colors are often observed in a rainbow. While indigo is sometimes included, the main colors are typically red, orange, yellow, green, blue, and violet.

The visible spectrum of light consists of colors that are produced by visible light of specific wavelengths. The primary colors that we see in a rainbow and that can be produced by narrow bands of wavelengths include:

Red (620 to 750 nm), Orange (590 to 620 nm), Yellow (570 to 590 nm), Green (495 to 570 nm), Blue (450 to 495 nm), Indigo (approx. 445 to 450 nm), Violet (380 to 445 nm). In total, these are the main colors of the visible light spectrum.

Answer:

B. 1.5:1

Explanation:

Let's take mercury(Hg) for an example.

Mercury have proton number of 80 and neutron number of 121.

To know the ration, you need to divide the neutron number with the proton number.

121/80

=1.5/1

Then, change the answer to ratio form=1.5:1

Answer:

A) The event horizon, singularity, and the chute located between the two.

Answer:

Black holes have three major parts that include A) The event horizon, singularity, and the chute located between the two.

Explanation:

A black hole is a celestial object that has an extremely important mass in a very small volume. They are cold remains of very old stars that contain a lot of matter in a compact space. Because of this, they have a great force of gravity.

Black holes are only formed by very massive stars. When they collapse on themselves forming a well in space: a black hole. If they are not so massive, the matter they are made of can stop the collapse and form a dying star that barely shines: a white dwarf or a neutron star.

Black holes have three main parts that include:

Answer:

588 N

Explanation:

Since the 60 kg is moving at a constant velocity there is no acceleration. In order for the system to be balanced, both the normal force and the force of gravity must be equal. In this case the man has a mass of 60 kg. So to find the force you multiply mass by gravitys constant (9.81). And you end up with an answer of 588.6 but I rounded to 588.

The reactive force acting on the man by the elevator is about 588 Newton

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\large {\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

mass of the man = 60 kg

velocity of the lift = 5 m/s

Unknown:

reactive force = N = ?

Solution:

We will use Newton's 2nd law formula for this problem.

[tex]\Sigma F = ma[/tex]

[tex]N - w = ma[/tex]

[tex]N - mg = ma[/tex]

[tex]N - 60(9.8) = 60(0)[/tex] → constant velocity ⇒ a = 0

[tex]N = 0 + 588[/tex]

[tex]N = 588 ~ Newton[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

Calculate the vertical component of the athlete's speed:

Vy = Vsin(θ)

Vy is the vertical component of the speed, V is the speed, and θ is the angle the athlete jumps off the ground at.

Given values:

V = 4m/s

θ = 23°

Plug in these values and solve for Vy:

Vy = 4sin(23°) = 1.563m/s

Let us use this kinematics equation for the athlete's vertical motion:

H = Vt + 0.5At²

H is the height, t is time, V is the initial vertical velocity, and A is acceleration.

Given values:

V = 1.563m/s

A = -9.81m/s² (acceleration due to gravity)

Plug in these values:

H = 1.563t - 4.905t²

We want to know the athlete's airtime, or when they reach the ground, ie calculate a time t when H = 0m. So let us substitute H = 0 and solve for t:

1.563t - 4.905t² = 0

t = 0.3187, 0

Reject t = 0s

t = 0.3187s

Choice A

The glass sphere will begin to float in glycerine when the glycerine's density decreases below that of the sphere's density of 1.30 g/cm³ upon heating. Using the coefficient of volume expansion, we can calculate the temperature at which this occurs.

To determine at what temperature the hollow glass sphere would begin to float in glycerine, we need to consider the density changes of glycerine with temperature. Since the sphere's density is 1.30 g/cm³ and the density of glycerine is 1.26 g/cm³ at 20°C, we look for the temperature at which the glycerine's density drops below that of the sphere. Using the formula ΔV = βV₀ΔT (where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion of glycerine, and ΔT is the change in temperature), we can calculate the new density of glycerine at different temperatures and find the point where it is equal to the sphere's density.

Since density is mass over volume, as volume increases due to temperature rise, density decreases. As glycerine warms up and expands, its density will decrease: Density_glycerine(T) = Density_glycerine(20°C) / (1 + βΔT). We set this equal to the sphere's density to solve for the temperature increase. When glycerine's density is just less than that of the glass sphere, the sphere will begin to float.

https://brainly.com/question/7103480

#SPJ3

Answer:

B. 12 m/s

Explanation:

Momentum is mass times velocity

p = mv

Given p = 72 kgm/s and m = 6 kg:

72 kgm/s = (6 kg) v

v = 12 m/s

Final answer:

The correct answer is B. 12 m/s.

Explanation:

The question provided is asking about finding the velocity of an object when its mass and momentum are known. The formula for momentum (p) is the product of mass (m) and velocity (v), which is expressed as p = m × v. Given that the momentum (p) is 72 kg·m/s and the mass (m) is 6 kg, we can solve for velocity (v) by rearranging the formula: v = p / m.

Plugging in the values, we get v = 72 kg·m/s divided by 6 kg, which simplifies to 12 m/s. Therefore, the correct answer is B. 12 m/s.

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{What s a successful result of science?}[/tex]

[tex]\huge\text{A discovery is a successfully result of science}[/tex]

[tex]\huge\text{Reason?}[/tex]

[tex]\huge\text{Well, because it known for the working or making}[/tex] [tex]\huge\text{'newer' discovers so it can tell us humans}[/tex] [tex]\huge\text{that something is theoretically correct}[/tex]

[tex]\boxed{\boxed{\huge\text{Thus the answer is A. a discovery}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{LoveYourselfFirst:)}[/tex]

Answer:

Both are electromagnetic waves

Explanation:

Both microwaves and light waves form a part of the electromagnetic spectrum. Electromagnetic waves are produced as a result of oscillating magnetic and electric fields. when arranged in order of frequencies and wavelengths they form the electromagnetic spectrum.

If an atom has 34 protons and 40 neutrons, the mass number is 74.

Explanation:

Mass number is related to the protons and neutrons. It is the product of the above two subatomic particles. Hence the mass number and the atomic number are dependent upon the subatomic particles of an atom. From the given data in the question, mass number of the atom is calculated as, 34 + 40 = 74.

Answer:

3.6×10⁶ m

Explanation:

Newton's law of universal gravitation states that the force between two masses is:

F = GMm / r²

where G is the universal constant of gravitation (6.67×10⁻¹¹ m³/kg/s²),

M is the mass of one object

m is the mass of the other object,

and r is the distance between the center of masses of the objects.

The force acting on the meteor is:

∑F = ma

GMm / r² = ma

GM / r² = a

Given M = 6×10²⁴ kg and a = 4 m/s²:

(6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / r² = 4 m/s²

r = 10⁷ m

The distance from the meteor to the center of the Earth is 10⁷ m.  We want to know what the height of the meteor is (distance to the surface of the Earth).  So we need to subtract the Earth's radius.

h = 10⁷ m − 6.4×10⁶ m

h = 3.6×10⁶ m

For vertical motion, use the following kinematics equation:

H(t) = X + Vt + 0.5At²

H(t) is the height of the ball at any point in time t for t ≥ 0s

X is the initial height

V is the initial vertical velocity

A is the constant vertical acceleration

Given values:

X = 1.4m

V = 0m/s (starting from free fall)

A = -9.81m/s² (downward acceleration due to gravity near the earth's surface)

Plug in these values to get H(t):

H(t) = 1.4 + 0t - 4.905t²

H(t) = 1.4 - 4.905t²

We want to calculate when the ball hits the ground, i.e. find a time t when H(t) = 0m, so let us substitute H(t) = 0 into the equation and solve for t:

1.4 - 4.905t² = 0

4.905t² = 1.4

t² = 0.2854

t = ±0.5342s

Reject t = -0.5342s because this doesn't make sense within the context of the problem (we only let t ≥ 0s for the ball's motion H(t))

t = 0.53s

Final answer:

In the Physics topic of projectile motion, it takes approximately 0.5345 seconds for a ball to reach the ground after rolling off a 1.4-meter high table horizontally at a speed of 4 m/s. This calculation is based on the free fall motion equation considering a gravitational acceleration of 9.8 m/s².

Explanation:

The subject of this question is Physics, particularly the topic of projectile motion. To determine how long it takes for a ball to reach the ground when it is rolled off a table, we need to use the equations of motion for objects in free fall. Since the horizontal motion and vertical motion are independent of each other, we only need to consider the vertical motion to answer this question.

Step-by-Step Calculation:

Identify the known variables: the height of the table (h) is 1.4 meters, and the acceleration due to gravity (g) is 9.8 m/s² (assuming earth's gravity).

The initial vertical velocity (vi) is 0 m/s since the ball is rolling off horizontally.

Use the equation for the vertical motion in free fall: h = vi * t + (1/2) * g * t², where t is the time in seconds.

Plugging in the known values, we get 1.4 = 0 * t + (1/2) * 9.8 * t².

Simplifying, we have 1.4 = 4.9 * t², which gives us t² = 1.4 / 4.9.

Calculating t², we find it equals approximately 0.2857.

Take the square root of both sides to find the time (t), which is roughly 0.5345 seconds.

Therefore, the ball takes approximately 0.5345 seconds to reach the ground after rolling off the table.

Answer:

The attraction of Br⁻ to H⁺ and Na⁺ to OH⁻

Explanation:

NaBr is an ionic compound and would easily be dissociated by water in solutions.

Water is a polar covalent molecule and with a partial dipole on it. The hydrogen ions have a positive charge and the hydroxyl ions are negatively charged.

In solutions with water, NaBr dissolves. This releases the sodium and bromide ion into the solution. The Bromide ion becomes hydrated and surrounded by the water molecules. The negatively charged end of the water molecule bonds with the Na ion and the positive end bonds with the negative part of the water molecule. This bonding provides the NaBr an ease of movement in its lattice structure.

This procedure leads to the solubility of NaBr in water.

Answer:

Not between significant digits.

Explanation:

A zero not significant when it's not between significant digits.

Answer:

Zero are not significant when indicating the decimal point position

Explanation:

The number zero has a special meaning with respect to its meaning, when it is placed to the right as a decimal, its meanings so precision measurements were made, for example 10 cm and 10.0 cm, the first one has an accuracy of one centimeter and the second has an accuracy of 0.1 cm.

In the case of being placed to the left of all numbers, the meaning is to indicate where the decimal point goes, but it does not give information about the accuracy of the measurement, in this second case the zeros are not significant, for example: 0.1 0.0001 in these two cases are not significant

Answer:

29.4 m/s

Explanation:

v = at + v₀

v = (9.8 m/s²) (3 s) + 0 m/s

v = 29.4 m/s

Answer:29.4 is correct

Explanation:

B. The electric potential energy of charge is [tex]1.9 \times 10^{-4} \ \mathrm{J}[/tex] if charge of [tex]24 \ \mu \mathrm{C}[/tex] is at a location where electric potential is 8.0 V.

The capacity required charge to move from a place to another is termed as electric potential energy.

The potential energy is given by the formula:

[tex]P E=q \Delta V[/tex]

Where,

PE is electric potential energy

q is charge

[tex]\Delta V[/tex] is electric potential

Given:

[tex]q=24 \ \mu \mathrm{C}=24 \times 10^{-6} \ \mathrm{C}[/tex]

[tex]\Delta V=8.0 \ \mathrm{V}[/tex]

Now,

[tex]\Rightarrow P E=24 \times 10^{-6} \times 8.0[/tex]

[tex]\therefore P E=1.92 \times 10^{-4} \ J[/tex]

Hence, we can say that [tex]1.92 \times 10^{-4} \ J[/tex] is electric potential energy for the given conditions.

Ek = 1/2 m v^2

Ek = 1/2 × 60 × 2^2

Ek = 1/2 × 60 × 4

Ek = 120 J

the kinectic energy is 120 J

Explanation:

Carbon-14 is a radioactive isotope of carbon and has a half-life of 5730 years. Due to its presence in all organic materials, this radioisotope is used in the dating of organic specimens.

However, this test is only useful for samples of thousands of years, for samples with ages of millions of years is not useful because the half-life of carbon-14 is lower.

In addition, there is a factor that negatively influences the accuracy of the test, the fact that the concentration of carbon-14 in the terrestrial atmosphere has not remained constant over time. This is due to changes in the flow of cosmic radiation and solar activity, changes in the intensity of the earth's magnetic field and the artificial production of this radiosotope between the 1950s and 1960s with the nuclear tests carried out.

Answer:

the answer is a

Explanation:

Answer:

Limited Resources

Answer:I’m sure it lime red resources

Explanation: