find two consecutive odd integers whose product is 1443

1: Thirty subtracted from four times a number is greater than the opposite of ten.

Let the number be x, so equation becomes : [tex]30-4x>-10[/tex]

2: Given equation is  [tex]27-2b\leq-6[/tex] this states that the result of 27-2b is less than equal to opposite of six.

Correct answer is option(2).

Isaac can add the ordered pair (1, 3) to the set to keep it a function.

A function is a relation where each input (or domain element) is associated with exactly one output (or range element).

This means that in the set of ordered pairs representing a function, no two pairs can have the same first element (input) but different second elements (outputs).

Given the function defined as : {(0,1),(2,3),(5,8),(7,2)},

we need to add one more ordered pair without violating the property that each input maps to exactly one output.

Let's examine each option:

1.) (0, 2) : This pair has the same first element as (0, 1). Adding (0, 2) would imply that the input 0 maps to both 1 and 2, which is not allowed in a function because each input must map to exactly one output.

2.) (1, 3) : This pair has a first element of 1, which is not present in the original set of ordered pairs. Therefore, adding (1, 3) does not create any conflicts. The input 1 is not repeated, so each input still maps to exactly one output. This maintains the function property.

3.) (5, 3) : This pair has the same first element as (5, 8). Adding (5, 3) would imply that the input 5 maps to both 8 and 3, which violates the definition of a function.

4.) (7, 0) : This pair has the same first element as (7, 2). Adding (7, 0) would imply that the input 7 maps to both 2 and 0, which also violates the definition of a function.

Therfore , Only the pair (1,3) can be added to the set without violating the function property. This pair introduces a new input that does not conflict with the existing inputs in the set.

Let the nuber be x

According to question

3(x +4) = 18+ x

3x+ 12=18+x

3x-x=18-12

2x = 6

x =6/2

x = 3

[tex]|x-2|-5 <-2 \\\\|x-2|<3\\\\x-2<3 \wedge x-2>-3\\\\x<5 \wedge x>-1\\\\x\in(-1,5)[/tex]

Answer: 2/9

Step-by-step explanation:

lt

2

7

×

7

9

=

2 × 7

7 × 9

=

14

63

=

14 ÷ 7

63 ÷ 7

=

2/9

−1/8*(1/8) =

-(1/8)² =

-1/64

(a) Lily: 5 * 2 - 12 + 3 = 1 pt

(b) Rose: -3 * 2 -1 + 6 + 7 = 6 pts

(c) Rose

x+9=18+-2x

divide 2x from both sides

which makes it 3x+9=18

subtract 9 from the 18

which is 3x=9

divide 3 from both sides

which gives you x=3

x+9=18+(-2x) add the 2x to the x and you should get 3x+9=18. Then you would subtract the 9 from the 18 and should get 3x=9. Then just divide the 9 by the 3 and get x=3 which is your answer. Hope this helps!

Product is multiplication.

Let the number = x

3 *( X+7) = -36

Use distributive property:

3x +21 = -36

Subtract 21 from each side:

3x = -57

Divide both sides by 3:

x = -57 /3

x = -19

Check: 3 * (-19 +7) = 3 * -12 = -36

The number is -19

To round 39,189 to the nearest thousand, we need to look at the digit in the hundreds place. If the digit in the hundreds place is 5 or greater, we round up, if it is less than 5, we round down. In this case, 1 is less than 5, so we round 39,189 down to 39,000.

To round 39,189 to the nearest thousand, we need to look at the digit in the hundreds place. In this case, it is 1. If the digit in the hundreds place is 5 or greater, we round up to the next thousand. If it is less than 5, we round down to the current thousand. Since 1 is less than 5, we round 39,189 down to 39,000.

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Given that a student works no more than 25 hours per week, and that work is performed every day of a 7-day week, the maximum number of hours they can work per day is approximately 3.57, making it fair to say they can work up to 3 hours each day. This scenario can be represented by the inequality h ≤ 3.

To answer your question, we need to find an inequality that represents how many hours the student can work each day given they work no more than 25 hours every week.
If we assume a typical week encompasses 7 days, and the student works every day of the week, then we should distribute the maximum hours worked per week over these seven days.
This results in 25 hours ÷ 7 days ≈ 3.57 hours/day. However, since you can't work a fraction of an hour, the student can work up to 3 hours a day.
The inequality representing this scenario would be h ≤ 3, where 'h' represents the number of hours the student can work each day.

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To convert 1.8499 × 10^9 by moving the decimal nine places to the right, you get 1,849,900,000. This is achieved by shifting the decimal point and adding zeros as needed.

To move the decimal nine places to the right for the number 1.8499 × 10^9, you follow these steps:

Thus, 1.8499 × 10^9 in standard notation becomes 1,849,900,000.

Answer:

Consider two adjacent rectangular rooms having Length=L, and, Breadth = B

Now Suppose the wall which is in between two rooms has a height or length =H.

Breadth of wall = B [ if the wall doesn't exceed the breadth of room]

Considering two rooms to be identical,

Area of each room= L × B square unit

Area of each tile = 1×1=1 square unit

Number of tiles required= L B ÷ 1= LB tiles( product of length and breadth of room is number of tiles required)

Suppose if,LB= N

B= N/L  .................(1)

Area of wall(W) = B×H= B H square unit

B =W/H ......................(2)

Equating (1) and (2)

⇒N/L = W/ H

⇒H =[tex]\frac{WL}{N}[/tex]

⇒H =[tex]\frac{WL}{LB}[/tex]

⇒H = W/B

 ⇒  H =[tex]\frac {\text{ Area of Wall}}{\text{Breadth of room or wall}}[/tex]

No equation is given .

The answer would be -30.75 hope this helps !!

You can draw a triangle or a quadrilateral since they have at least three angles. For the second part, any angle can be named with three letters. After naming each corner/angle of the figure, name an angle so that the actual angle letter is the middle letter, surrounded by the letters of the corners that is just next to it.

There are Infinite number of figure , that contains at least three angles and requires three letters to name each angle

1.Any of the Triangle, either Acute, Obtuse, Right, Scalene, Isosceles, or Equilateral.

2. Any of the Quadrilateral, Parallelogram,Rectangle, Square, Trapezoid, and Kite.

→Or In General

Any of the Polygon whether it is Regular or Irregular.

→Because, A polygon is defined as ,a simple closed figure made up of three or more line segment.

the answer is a add -19w and dont forget to do it on each side

You should put brainliest to the other person that answered this question.

24 cans in total is your answer

6 times 4

6 · 4 = 24

24 cans in total

Jordan and Sharla are saving money to go on a study abroad trip. They must provide a down payment of $650 to sign up for the trip, and they can pay the remaining balance later. Jordan raises money by mowing lawns in his neighborhood and charges $25 per lawn. Sharla raises money by selling handmade necklaces for $15 each. Sharla raises less money than Jordan does because Sharla 3. only has enough materials to make 40 necklaces. (A) write two constraints to model the problem. Let x represent the number of lawns Jordan mows and y represent the number of necklaces Sharla sells. (B) can Sharla afford the down payment with the money she earns selling her necklaces? Explain your answer    

this is the wrong subject

A) 25x+15y=650

25x+15(40)=650

Or it could be 25x=650 and 15y=650

B) No because she makes $15 for every necklace which she only has 40 necklaces 15x40=600

The answer would be 108 because you multiply the 9 and the 12 together and get 108. I hope this helps.

This is fast and easy, hope this helps :)

The quotient of 4 divided by 28 is 0.142857.

To perform long division for 4 divided by 28, follow these steps:

1. Write 4 as the dividend and 28 as the divisor.

        ___

28 | 4

2. Determine how many times 28 can be divided into 4 without exceeding it. In this case, 28 cannot be divided into 4, so we write 0 above the division line.

        0

        ___

28 | 4

3. Multiply the divisor (28) by the quotient (0), and write the product below the dividend.

        0

        ___

28 | 4

        0

4. Subtract the product from the dividend. In this case, 4 minus 0 is 4.

        0

        ___

28 | 4

        0

       ----

        4

5. Bring down the next digit from the dividend, which is 0.

        0

        ___

28 | 4

        0

       ----

        40

6. In this case, 28 can be divided into 40 once, so we write 1 above the division line.

        01

        ___

28 | 4

        0

       ----

        40

7. Multiply the divisor (28) by the quotient (1), and write the product below the 40.

        01

        ___

28 | 4

        0

       ----

        40

       28

8. Subtract the product (28) from the 40.

        01

        ___

28 | 4

        0

       ----

        40

       28

       ----

        12

9. The final quotient is 0.142857.

Therefore, 4 divided by 28 equals 0.142857.

Learn more about Long Division here:

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 (x - 4)(x - 3) + (2 - x)(x - 1)

= x² - 3x - 4x + 12 + 2x - 2 - x² + x

= x² - x²     -3x - 4x + 2x + x     +12 - 2  

=     0                   -4x                    +10

Answer: -4x + 10

Answer:

[tex]408\frac{miles}{hour}[/tex]

Step-by-step explanation:

we know that

To find the speed divide the total distance by the time

so

[tex]\frac{34}{(1/12)}=34*12=408\frac{miles}{hour}[/tex]

To answer this question, we know that 1km equals 1000m

and 1 hour is equal to 60 minutes. In the same way 1 minute equals 60 sec onds

So we have to change the units of elephant speed to km per hour.

For this we do the following procedure:

1) we multiply 6.9 m / s by the conversion factor from meters to kilometers (1 km / 1000m)

[tex]6.9 \frac{m}{s} *\frac{1 km}{1000 m}=0.0069\frac{km}{s} \\[/tex]

2) The result obtained is multiplied by the conversion factor from seconds to minutes (60s / 1min)

[tex]0.0069 \frac{km}{s} *\frac{60 s}{1 min}=0.414 \frac{km}{min}\\[/tex]

3) The result obtained is multiplied by the conversion factor from minutes to hours (60min / 1hr)

[tex]0.414\frac{km}{min}*\frac{60 min}{1 h}= 24.84\frac{km}{h} \\[/tex]

The answer is 24.84 km / h

 You can skip step 2) multiplying 0.0069 km / s by the conversion factor from seconds to hours (3600 s / 1h)

Answer:

Diameter of circle while measuring vertically=3.5 cm

Diameter of circle while measuring Horizontally=3.6 cm

As you have not written by which instrument from geometry box you have measured the length of diameter.

1. By Scale i.e ruler 2. By Divider  Or 3. By mere Observation i.e by comparing length

1.If you have done measurement by simply observation there are maximum possibility of having error.  

2. Then if you have measured these lengths by scale or ruler there is very less chances of getting error in measurement of length because sometimes divison in scale varies i.e if a point lies between 4.5 to 4.6 we can't say exactly whether it is 4.5 or 4.6.

3. So it is better to compare line segments by Divider.There is no chances of getting error.

Most probably you have measured Diameter by ruler, Due to that you have faced the problem.  

Answer:

The possible reasons are shown below:

Step-by-step explanation:

Consider the provided information.

lin measured the diameter of a circle in two different directions. Measuring vertically, she got 3.5 cm, and measuring horizontally, she got 3.6 cm.

The diameters of a circle should have the same length, If the length are not same then the reasons can be:

0.214285714

Hope this helps! :)

P.S- can you help me with my problem? LOL it's just that no one will help me! It's on planets. Hopefully, you know those stuff. :(

given 4y = 2x - 10 and y = 6, then

2x - 10 = 24 ( add 10 to both sides )

2x = 34 ( divide both sides by 2 )

x = [tex]\frac{34}{2}[/tex] = 17

The correct expressions are as follows:

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Equivalent [tex]343[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Not Equivalent [tex]49[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Equivalent [tex]7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Not Equivalent [tex]49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}[/tex]

[tex]\texttt{ }[/tex]

Let's recall following formula about Exponents and Surds:

[tex]\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }[/tex]

[tex]\boxed { (a ^ b) ^ c = a ^ { b . c } } [/tex]

[tex]\boxed {a ^ b \div a ^ c = a ^ { b - c } }[/tex]

[tex]\boxed {\log a + \log b = \log (a \times b) }[/tex]

[tex]\boxed {\log a - \log b = \log (a \div b) }[/tex]

Let us tackle the problem!

[tex]\texttt{ }[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}[/tex]

[tex]\texttt{ }[/tex]

From the results above, it can be concluded that the correct statements are:

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Equivalent [tex]343[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Not Equivalent [tex]49[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Equivalent [tex]7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}[/tex]

[tex]7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}[/tex] Not Equivalent [tex]49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

Answer:

equivalent

not equivalent

equivalent

not equivalent

-step explanation: