For scuba dives below 150 ft, helium is often used to replace nitrogen in the scuba tank. If 15.2 g of He(g) and 30.6 g of O2(g) are added to a previously evacuated 5.00 L tank at 22° C, calculate the partial pressure of each gas present as well as the total pressure in the tank.

Answer:

THE ANSWER IS (D)

Explanation:

Answer:

it's D

Explanation:

Answer:

A. Fe2+

Explanation:

other answer was wrong

[tex]Fe^{2+}[/tex] is the most likely to be reduced. Hence, option A is correct.

Oxidation: The loss of electrons

Reduction: The gain of electrons

Oxidation number: the charge based on the number of electrons assigned to an atom as compared to the neutral atom.

[tex]Fe^{2+}[/tex] oxidize to [tex]Fe^{3+}[/tex] because removing the electron results in a half-filled d subshell.

Hence, option A is correct.

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Answer:

The answer is Flourine

The new volume of the balloon is approximately 2.33 liters when additional helium is added.

To find the new volume of the balloon, we can use Avogadro's Law, which states that the volume of a gas is directly proportional to the number of moles of gas, provided the temperature and pressure are constant. The formula for Avogadro's Law is:

[tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]

where:

We can rearrange the formula to solve for V2:

V2 = (V1 * n2) / n1

Substituting the values, we get:

[tex]V_2 = \frac{(1.90 \, \text{L} \times 0.1130 \, \text{mol})}{0.0920 \, \text{mol}}[/tex]

V2 ≈ 2.33 L

Therefore, the new volume of the balloon is approximately 2.33 liters.

Answer:

The correct answer is A

We'll have 2.0 moles of magnesium nitride produced  and and excess of 2.0 moles nitrogen gas

Explanation:

Step 1: Data given

Number of moles nitrogen gas (N2) = 4.0 moles

Number of moles magnesium = 6.0 moles

Step 2: The balanced equation

3Mg + N2 → Mg3N2

Step 3: Calculate the limiting reactant

For 3 molesmagnesium (Mg) we need 1 mol nitrogen gas  (N2) to react, to produce 1 mol magnesium nitride (Mg3N2)

Magnesium is the limiting reactant. It will completely be consumed 6.0 moles. Nitrogen is in excess. There will react 6.0 / 3 = 2.0 moles

There will remain 4.0 - 2.0 = 2.0 moles N2

Step4: Calculate moles Mg3N2

For 3 molesmagnesium (Mg) we need 1 mol nitrogen gas  (N2) to react, to produce 1 mol magnesium nitride (Mg3N2)

For 6.0 moles Mg we'll have 6.0 / 3 = 2.0 moles Mg3N2

The correct answer is A

We'll have 2.0 moles of magnesium nitride produced  and and excess of 2.0 moles nitrogen gas

The correct answer is a. 2.0 moles of magnesium nitride are formed when 6.0 moles of magnesium react with 4.0 moles of nitrogen, leaving 2.0 moles of nitrogen unreacted as excess.

The formation of magnesium nitride involves a reaction between magnesium metal and nitrogen gas. Magnesium forms a Mg2+ ion, which is a cation, by losing two electrons. Nitrogen, a non-metal, forms an anion with a charge of 3-. Therefore, the formula for magnesium nitride is Mg3N2, indicating that three magnesium ions react with two nitrogen ions to form one formula unit of magnesium nitride.

The balanced chemical equation for the formation of magnesium nitride is:

3Mg + N2 → Mg3N2

Given that 4.0 moles of nitrogen is reacted with 6.0 moles of magnesium, we can determine the limiting reactant and calculate the product formed. The molar ratio of Mg to N2 in the equation is 3:1, meaning three moles of Mg are required for every mole of N2. Therefore, 6.0 moles of Mg would completely react with 2.0 moles of N2 to produce magnesium nitride. Since we started with 4.0 moles of nitrogen, we have an excess of nitrogen, and magnesium is the limiting reactant.

The result is that all of the magnesium reacts and you would produce 2.0 moles of magnesium nitride with 2.0 moles of nitrogen left over as excess. Hence, the correct answer to the student's question is option a.

Answer : The final  pressure of the balloon will be, 1369.6 torr

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 923 torr

[tex]P_2[/tex] = final pressure = ?

[tex]V_1[/tex] = initial volume = 2.30 L

[tex]V_2[/tex] = final volume = 1.55 L

Now put all the given values in the above equation, we get:

[tex]923torr\times 2.30L=P_2\times 1.55L[/tex]

[tex]P_2=1369.6torr[/tex]

Thus, the final  pressure of the balloon will be, 1369.6 torr

Answer:

The answer to your question is C₂H₆O

Explanation:

Data

Molecular formula = C₆H₁₈O₃

Empirical formula = ?

Empirical formula is defined as the simplest ratio of the elements that form part of a molecule.

Process

To find the empirical formula find the greatest common factor of the subscripts.

                             6    18   3   2

                             3      9  3   3

                              1     3    1   3

                                     1

The GCF is 3, so factor 3 of the molecular formula

                         3 ( C₂H₆O)  

The result is the empirical formula C₂H₆O

Final answer:

The empirical formula for C6H18O3 is found by dividing the subscripts by their greatest common divisor, which in this case is 3. This yields C2H6O as the simplest whole-number ratio of the elements in the compound.

Explanation:

The empirical formula of a compound is the simplest whole-number ratio of atoms of each element in the compound. To determine the empirical formula for C6H18O3, we must find the greatest common divisor of the subscript numbers and divide them by that number. The greatest common divisor of 6, 18, and 3 is 3, so we divide each subscript by 3 to get the simplest ratio.

Dividing each subscript by 3, we get:

Carbon (C): 6 ÷ 3 = 2

Hydrogen (H): 18 ÷ 3 = 6

Oxygen (O): 3 ÷ 3 = 1

Therefore, the empirical formula is C2H6O.

Answer:

The answer to your question is a) N₂     b) 3.04 g of NH₃

Explanation:

Data

mass of H₂ = 2.5 g

mass of N₂ = 2.5 g

molar mass H₂ = 2.02 g

molar mass of N₂ = 28.02 g

molar mass of NH₃ = 17.04 g

Balanced chemical reaction

                3H₂  +  1 N₂   ⇒   2NH₃

A)

Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22

Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1

Conclusion

The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.

B)

             28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃

               2.5 g of N₂    --------------------   x

                            x = (2.5 x 2 x 17.04) / 28.02

                            x = 85.2 / 28.02

                           x = 3.04 g of NH₃

Answer:

[tex]Br_{4}F_{10}[/tex]

The prefix "Tetra" implies 4 Bromine atoms. The prefix "Deca" implies 10 fluorine atoms.

Answer:

C. Double Replacement

Explanation:

A. Wrong because SR uses a compound and element. This equation is a compound and compound.

B. Wrong because it does not have O2 in the formula. All combustion reactions must have O2.

C. Correct because it is a compound reacting with a compound.

D. Wrong because the reactants did not form a single product. ex. (x + y > xy)

E. Wrong because the equation did not start with a single compound and break down. ex. (xy > x + y)

The missing coefficients for the given chemical equation are found by balancing Al, SO₄, K, and OH groups, resulting in a balanced equation representing a double replacement reaction: Al₂(SO₄)₃(aq) + 6 KOH(aq)
ightarrow 2 Al(OH)₃(aq) + 3 K₂SO₄(aq).

The reaction in question is a classic example of a double replacement reaction, where the cations and anions of two ionic compounds switch places, forming two new compounds. To balance the skeleton equation, we should find the correct stoichiometric coefficients that maintain the conservation of mass for each element.

Start by writing the unbalanced equation with all reactants and products including their states:

Al₂(SO₄)₃(aq) + KOH(aq)
ightarrow Al(OH)₃(aq) + K₂SO₄(aq)

Now balance the elements step by step:

This yields the balanced chemical equation:

Al₂(SO₄)₃(aq) + 6 KOH(aq)
ightarrow 2 Al(OH)₃(aq) + 3 K₂SO₄(aq)

The type of reaction for the balance is option C, which is double replacement.

Answer:

takes place in the glomerulus

Explanation:

which is the vascular beginning of the nephron . Approximately one-fourth of the blood flow from cardiac output circulates through the kidney, the greatest rate of blood flow for any organ .

The filtration of the blood in the kidneys occurs in the glomerulus, where most solutes are filtered out by glomerular filtration.    

Filtration of the Blood in the Kidneys:

The filtration of the blood in the kidneys primarily occurs in the glomerulus. The glomerulus is a network of capillaries at the beginning of a nephron. When blood flows through the glomerulus, most solutes, except for proteins, are filtered out into the glomerulus by a process called glomerular filtration. The filtrate is then collected in the renal tubules, where it undergoes further processing to form urine.

This process begins with glomerular filtration, continues with tubular reabsorption in the proximal convoluted tubule (PCT), and ends with tubular secretion. Finally, the collecting ducts gather the filtrate, now called urine, which is passed on to the ureters and then eliminated from the body.

Answer:

for the water cycle

Explanation:

Answer:

1. H2 is the limiting reactant.

2. 56666.67g ( i.e 56.67kg) of NH3 is produced.

Explanation:

Step 1:

The equation for the reaction. This is given below:

N2 + H2 —> NH3

Step 2:

Balancing the equation.

N2 + H2 —> NH3

The above equation can be balanced as follow :

There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NH3 as shown below:

N2 + H2 —> 2NH3

There are 6 atoms of H on the right side and 2 atoms on the left side. It can be balance by putting 3 in front of H2 as shown below

N2 + 3H2 —> 2NH3

Now the equation is balanced.

Step 3:

Determination of the masses of N2 and H2 that reacted and the mass of NH3 produced from the balanced equation. This is illustrated below:

N2 + 3H2 —> 2NH3

Molar Mass of N2 = 2x14 = 28g/mol

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

From the balanced equation above,

28g of N2 reacted with 6g of H2 to produce 34g of NH3

Step 4:

Determination of the limiting reactant. This is illustrated below:

N2 + 3H2 —> 2NH3

Let us consider using all the 10kg (i.e 10000g) of H2 to see if there will be any left of for N2.

From the balanced equation above,

28g of N2 reacted with 6g of H2.

Therefore, Xg of N2 will react with 10000g of H2 i.e

Xg of N2 = (28 x 10000)/6

Xg of N2 = 46666.67g

We can see from the calculations above that there are leftover for N2 as only 46666.67g reacted out of 50kg ( i.e 50000g) that was given. Therefore, H2 is the limiting reactant.

Step 5:

Determination of the mass of NH3 produced during the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

6g of H2 reacted to produce 34g of NH3.

Therefore, 10000g of H2 will react to produce = ( 10000 x 34)/6 = 6g of 56666.67g of NH3.

Therefore, 56666.67g ( i.e 56.67kg) of NH3 is produced.

Answer:

H2 is the limiting reactant

56.2 kg of NH3 will be formed

Explanation:

Step 1: Data given

Mass of N2 = 50 kg = 50000 grams

Mass of H2 = 10 kg = 10000 grams

Molar mass of N2 = 28.0 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 50000 grams / 28.0 g/mol

Moles N2 = 1785.7 moles

Moles H2 = 10000 grams / 2.02 g/mol

Moles H2 = 4950.5 moles

Step 4: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

H2 is the limiting reactant.It will completely be consumed (4950.5 moles). Né is in excess. There will react 4950.5 / 3 = 1650.2 moles. There will remain 1785.7 - 1650.2 = 135.5 moles

Step 5: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 4950.5 moles H2 we'll have 2/3 * 4950.5 = 3300.3 moles

Step 6: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 3300.3 moles * 17.03 g/mol

Mass NH3 = 56204 grams = 56.2 kg

Answer:

It will have no effect

Explanation:

The loss of tin oxide to evaporation will have no effect on the empirical formula of a compound.

The empirical formula of any compound is the simplest formula of that compound by which the combining atoms can be represented.

This formula is not affect by physical changes.

According to the law of constant composition  "all pure samples of the same compound have the same element in the same proportion by mass".

Regardless of the mass loss or gain of any tin oxide compound, it will have the same empirical and molecular formula. The atoms are still combining in the ratio to give the product.

Answer:

PCI3

Mass ratio = 3:10

And Atomic ratio = 1:3

Hope it will help.

Final answer:

The total ionic equation for the neutralization reaction of ammonium hydroxide with hydrochloric acid expresses all components as ions and after removing spectator ions, the net ionic equation is OH⁻(aq) + H⁺(aq) → H₂O(l).

Explanation:

To write the total ionic equation for the neutralization reaction of ammonium hydroxide (NH₄OH) with hydrochloric acid (HCl), we need to express all soluble substances as ions. Ammonium hydroxide can be represented as NH₄⁺(aq) and OH⁻(aq) since it partially dissociates in solution. The hydrochloric acid fully dissociates into H⁺(aq) and Cl⁻(aq).

The total ionic equation is as follows:

NH₄⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq) → NH₄⁺(aq) + Cl⁻(aq) + 2H₂O(l)

The net ionic equation, which shows the actual chemical change, is produced by removing the spectator ions (NH₄⁺ and Cl-), resulting in: OH⁻(aq) + H⁺(aq) → H₂O(l)

Final answer:

The total ionic equation for the neutralization reaction between ammonium hydroxide and hydrochloric acid is NH4+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → NH4+(aq) + Cl-(aq) + H2O(l), with H+(aq) + OH-(aq) → H2O(l) as the net ionic equation.

Explanation:

The total ionic equation for the neutralization reaction of ammonium hydroxide (NH4OH) with hydrochloric acid (HCl) shows each species in its ionic form. The reactants ammonium hydroxide and hydrochloric acid dissociate in water to form NH4+ (aq), OH- (aq), H+ (aq), and Cl- (aq). In a complete ionic equation, all of the ions are shown as they exist in solution before and after the reaction:

NH4+ (aq) + OH- (aq) + H+ (aq) + Cl- (aq) → NH4+ (aq) + Cl- (aq) + H2O(l)

After the reaction, ammonium ions and chloride ions remain in solution while water is formed as the product. However, since ammonium ions (NH4+) are spectator ions in this reaction, they can be omitted to provide the net ionic equation:

H+ (aq) + OH- (aq) → H2O(l)

The net ionic equation indicates that the hydrogen ions (H+ from the hydrochloric acid) combine with the hydroxide ions (OH- from the ammonium hydroxide) to form water, which is a characteristic outcome of a neutralization reaction.

Answer:

decreased osmolality of extracellular fluids

Explanation:

When there is decreased osmolality of extracellular fluids, there will be Volume depletion, or extracellular fluid (ECF) volume contraction, which occurs as a result of loss of total body sodium. Causes include vomiting, excessive sweating, diarrhea, burns, diuretic use, and kidney failure. In this way, sodium loss always causes water loss.

Answer: C

Explanation: This is what my mastering said

16H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq)+2Mn2+(aq)+8H2O(l):

Ecell0 = +0.97 V.

The balanced equation is 16H⁺(aq)+2MnO₄⁻(aq)+10I⁻(aq)→5I₂(aq)+2Mn²⁺(aq)+8H₂O(l). The cell potential is Ecell0 = +0.97 V. The correct option is option C.

The potential difference of two half cells inside an electrochemical cell is measured by the cell potential, or Ecell. The capacity of electrons to go from one half cell to another is what determines the potential difference.

When one chemical is reduced and another is oxidized, a redox reaction takes place. The material loses one or maybe more electrons during oxidation, becoming positively charged as a result. In contrast, the material picks up electrons during reduction and then becomes negatively charged.

E cell = E° cathode -  E° anode

         = 1.51 - 0.54 V

          = 0.97 V

The balanced equation is 16H⁺(aq)+2MnO₄⁻(aq)+10I⁻(aq)→5I₂(aq)+2Mn²⁺(aq)+8H₂O(l).

Therefore, the correct option is option C.

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Answer:

the fraction of CO reacted is 0.76 or 76.0 %

Explanation:

Step 1: Data given

a new catalyst combines a 2.0 : 1.0 mole ratio mixture of carbon monoxide and oxygen gas

Volume = 2.45 L

Total pressure = 740 torr

Temperature = 552 °C = 825 K

Pressure decreases to 552 torr

Step 2: The balanced equation

2CO(g) + O2 (g) --> 2CO2(g)

Step 3: Calculate the percentage of the CO was converted to CO2

P1/n1 = P2/n2

⇒P1 = the initial pressure = 740 torr

⇒n1 = the initial number of moles = 2.0 moles CO and 1 mol of O2 = 3.0 moles

⇒P2 = the final pressure = 552 torr

⇒n2 = the final number of moles = TO BE DETERMINED

n2 = n1 * P2/P1

n2 =3.0 * 552 torr / 740 torr

n2 = 2.24 moles

Step 4: Calculate total moles of CO

Suppose X = the fraction of CO

final = 2*(x) + 3*(1-x)

2.24 = 2x + 3 - 3x

2.24 = -X + 3

-0.76 = -X

X = 0.76

This means the fraction of CO reacted is 0.76 or 76.0 %

The fraction or the percentage of the carbon monoxide converted to carbon dioxide is 76%.

Given:

Ratio of new catalyst to the mole ratio of carbon dioxide and oxygen  = 2:1

Volume = 2.45 L

Temperature = 825 K

Pressure = 740 torr

The reaction is:

2CO(g) + O₂ (g) [tex]\rightarrow[/tex] 2CO₂

From the reaction, the amount of CO converted into carbon dioxide is:

[tex]\dfrac{\text{P}_1}{\text n _1}&=\dfrac{\text{P}_2}{\text n _2}[/tex]

Where,

P₁ = initial pressure

n₁ = number of moles (initial)

P₂ = final pressure

n₂ = final number of moles

Now, calculating the n₂:

[tex]\text n_2 &= \dfrac{\text n_1 \times \text P_2}{\text P_1}[/tex]

[tex]\text n_2 &= \dfrac{3 \times 552}{740}[/tex]

n₂ = 2.24 moles.

Now, the total moles of carbon monoxide is:

2.24 = 2 x Y + 3 x (1 - Y)

2.24 = 2Y + 3 - 3Y

Y = 0.76

Thus, the number of a fraction of CO is 0.76.

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Answer:

The answer to your question is below

Explanation:

Electronegativity is a measure of how strongly atoms attract electrons to themselves.

Process

Look for the electronegativity of each element and compare.

a) Cl = 3.16   F = 3.98          Fluorine has a higher electronegativity

b) Se = 2.55 O = 3.44         Oxygen has a higher electronegativity

c) N = 3.04 As = 2.18         Nitrogen has a higher electronegativity

d) Na = 0.93 Mg = 1.31       Magnesium has a higher electronegativity

The more electronegative elements among the pairs are F (fluorine), O (oxygen), N (nitrogen), and Na (sodium). These are determined based on their positions in the periodic table, where electronegativity generally increases from left to right and decreases from top to bottom.

Electronegativity is a measure of the ability of an atom to attract a bonding pair of electrons. The Pauling scale is the most commonly used electronegativity scale and it ranges from 0 to 4.

Generally, electronegativity increases from left to right across a period and decreases moving down a group or column in the periodic table. Therefore, elements on the top right corner of the periodic table (excluding noble gases) are the most electronegative.

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Answer:

chemical reaction... that's because when they combine.. they form a salt and water only

Answer:

The mass of the air is 6920.71g

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Volume (V) = 5.0x10^3 L

Molar Mass of air (M) = 28.98 g/mol

Temperature (T) = 0.2°C

Pressure (P) = 1.07 atm

mass air (m) =?

Number of mole (n) =?

Recall:

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Conversion of celsius temperature to Kelvin temperature.

K = °C + 273

°C = 0.2°C

K = °C + 273

K = 0.2°C + 273

K = 273.2 K

Therefore, the temperature (T) = 273.2 K

Step 3:

Determination of the number of mole of air.

Applying the ideal gas equation PV = nRT, the number of mole n, can be obtained as follow:

PV = nRT

1.07 x 5.0x10^3 = n x 0.082 x 273.2

Divide both side by 0.082 x 273.2

n = (1.07 x 5.0x10^3)/(0.082 x 273.2)

n = 238.81 moles

Step 4:

Determination of the mass of air. This is illustrated below:

Number of mole of air = 238.81 moles

Molar Mass of air = 28.98 g/mol

Mass of air =.?

Mass = number of mole x molar Mass

Mass of air = 238.81 x 28.98

Mass of air = 6920.71g

Answer:

Chemical Change

Explanation:

It changes color and produces vapor when the foil is added to the solution.

Answer:

The answer to your question is Chemical change.

Explanation:

Process

Chemistry classifies changes in two types: physical and chemical changes.

Physical changes occur when matter changes its physical state. Examples are evaporation, condensation, solidification, etc.

Chemical changes occur when matter reacts with another substance and it changes its original composition, a new molecule is formed.

From the description given we conclude that is is a chemical change.

Answer:

The kid on the bike.

Explanation:

He has a physical form, whereas the shadow doesn't.

Answer:

the kid on the bicycle

Explanation:

matter is anything that takes up space and a shadow does not physically take up any space

Answer:

C2H5OH--- aqueous solution contains mostly molecules

Na2SO4---aqueous solution contains ions

HCN ---aqueous solution contains mostly molecules and a few ions

Explanation:

Only strong electrolytes dissociate completely in solution to form ions. Hence aqueous solutions of strong electrolytes comprises of ions which conduct electricity.

Weak electrolyte aqueous solutions contain mostly molecules since they ionize only to a very small extent in solution.

Nonelectrolytes remain molecular in solution and do not conduct electricity at all.

When dissolved in water, nonelectrolytes like ethanol produce primarily molecules, strong electrolytes like Na2SO4 generate only ions, and weak electrolytes like HCN result in a mix of mostly molecules with a few ions.

The type of substances present in a solution can be predicted based on the type of electrolyte. C2H5OH (ethanol), a nonelectrolyte, will mainly form molecules when dissolved in water as it does not ionize. Na2SO4, a strong electrolyte, will fully dissociate in water and produce only ions. HCN (hydrocyanic acid), a weak electrolyte, will produce mostly molecules with a few ions as it only partially ionizes in an aqueous solution.

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Answer:

The correct order of increasing standard molar entropy for the noble gases is He ≤ Ne ≤ Ar ≤ Kr

Explanation:

Entropy is the measure of degree of disorderliness or randomness of a substance. Entropy increases with increasing number of electron present in an atom due to increased repulsive force of the electrons. Therefore, the standard entropy of a substance increases with an increase in their atomic masses.

For the given noble gases in this question, Helium (He) has the least atomic mass while Krypton (Kr) has the highest atomic mass.

Thus, the correct order of increasing standard molar entropy for the noble gases is He ≤ Ne ≤ Ar ≤ Kr

Final answer:

The increasing standard molar entropy for noble gases is He ≤ Ne ≤ Ar ≤ Kr, due to growing atomic number and electronic complexity down the group.

Explanation:

The correct order of increasing standard molar entropy for the noble gases is He ≤ Ne ≤ Ar ≤ Kr. This is because entropy generally increases with atomic number due to increased electronic complexity and atomic mass. As you move down the group in the periodic table, noble gases have more electrons that can occupy a greater volume of space and therefore have higher entropy.

Answer:

One atom or more changes into atoms of another element.New subtances with different properties are formed.

Answer:

B. New substances with different properties are formed

C. Solids, Liquids, or gases may form

Explanation:

Edg 2020

Answer:

Somatotropin(Growth Hormone)

Explanation:

-Uncontrolled growth in a person is usually caused by the excessive secretion of growth hormone.

-This hormone is also known as Somatotropin.

-This hormone is produced  in the pituitary  gland.