For the given pair of events A and​ B, complete parts​ (a) and​ (b) below. ​A: When a page is randomly selected and ripped from a 2424​-page document and​ destroyed, it is page 2020. ​B: When a different page is randomly selected and ripped from the​ document, it is page 1616. a. Determine whether events A and B are independent or dependent.​ (If two events are technically dependent but can be treated as if they are independent according to the​ 5% guideline, consider them to be​ independent.) b. Find​ P(A and​ B), the probability that events A and B both occur. a. Choose the correct answer below.

Answer:  B. We are 95% confident that the population parameter is between the lower confidence limit and upper confidence limit.

Step-by-step explanation:

In statistics, we know that the interpretation of [tex](1-\alpha)\%[/tex] level of confidence interval is that we are [tex](1-\alpha)\%[/tex] sure that the true population parameter lies in it.

Therefore, the proper interpretation of a 95% confidence interval is that we are 95% confident that the population parameter is between the lower confidence limit and upper confidence limit.

Final answer:

The correct interpretation of a 95% confidence interval is that we are 95% confident that the population parameter is within the interval. The confidence interval represents the range within which the true population parameter lies, with a certain level of confidence, not the prediction of sample means or point estimates.

Explanation:

The correct interpretation of a 95% confidence interval is B: We are 95% confident that the population parameter is between the lower confidence limit and upper confidence limit. This means that if we were to take many samples from the population and construct a confidence interval from each sample, we would expect about 95% of those intervals to contain the actual population parameter, such as the population mean. It's important to note that the confidence interval does not predict where individual point estimates or sample means will fall. Rather, it expresses the reliability of the estimate of the population parameter based on the sampled data.

Answer:

1.[tex]\frac{dy}{dt}=ky[/tex]

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

[tex]\frac{dy}{dt}[/tex]=Number of bacteria per unit time

[tex]\frac{dy}{dt}\proportional y[/tex]

[tex]\frac{dy}{dt}=ky[/tex]

Where k=Proportionality constant

2.[tex]\frac{dy}{y}=kdt[/tex],y'(0)=100

Integrating on both sides then, we get

[tex]lny=kt+C[/tex]

We have y(0)=200

Substitute the values then , we get

[tex]ln 200=k(0)+C[/tex]

[tex]C=ln 200[/tex]

Substitute the value of C then we get

[tex]ln y=kt+ln 200[/tex]

[tex]ln y-ln200=kt[/tex]

[tex]ln\frac{y}{200}=kt[/tex]

[tex]\frac{y}{200}=e^{kt}[/tex]

[tex]y=200e^{kt}[/tex]

Differentiate w.r.t

[tex]y'=200ke^{kt}[/tex]

Substitute the given condition then, we get

[tex]100=200ke^{0}=200 \;because \;e^0=1[/tex]

[tex]k=\frac{100}{200}=\frac{1}{2}[/tex]

[tex]y=200e^{\frac{t}{2}}[/tex]

Substitute t=2

Then, we get [tex]y=200e^{\frac{2}{2}}=200e[/tex]

[tex]y=200(2.718)=543.6=543.6[/tex]

e=2.718

Hence, the number of bacteria after 2 hours=543.6

Answer:

12,500 units

Step-by-step explanation:

Given:

Selling cost of the pump = $10

Variable cost of producing each unit = 60% of selling cost

or

Variable cost of producing each unit  = 0.60 × $10 = $6

Monthly fixed cost = $50,000

Now,

The profit per unit = Selling cost - Variable cost

or

The profit per unit = $10 - $6 = $4

Therefore,

The breakeven point = [tex]\frac{\textup{Fixed cost}}{\textup{Profit per unit}}[/tex]

or

the breakeven point = [tex]\frac{\textup{50,000}}{\textup{4}}[/tex]

or

the breakeven point = 12,500 units

Answer:

$175 = Cost of single dress

Step-by-step explanation:

It is provided that cost of dress is twice that of a skirt.

Let say, cost of skirt = x

Total things bought 3 dresses and 2 skirts.

Cost of single dress = 2x

Cost of all items = 3 [tex]\times[/tex] 2x + 2 [tex]\times[/tex] x = $1,000 - $300 = $700

6x + 2x = $700

x = 700/8 = $87.50

Cost of single dress = 2x = $87.50 [tex]\times[/tex] 2 = $175

Answer:

312

Step-by-step explanation:

Let the attendance before the drop be x

Now we are given that attendance dropped 4% this year

So new attendance = [tex]x-4\% \times x[/tex]

                               = [tex]x-\frac{4}{100} \times x[/tex]

                               = [tex]\frac{96x}{100}[/tex]

We are also given that attendance dropped 4% this year, to 300

So,  [tex]\frac{96x}{100}= 300[/tex]

[tex]x= 300 \times \frac{100}{96}[/tex]

[tex]x=312.5[/tex]

Hence the attendance before the drop was 312

The equations of the line are:

x = -4,

y = 0.5,

z = 5 + t

A line that is parallel to the z-axis lies in the xy-plane. Since it's parallel to the z-axis, its direction in the xy-plane is determined by the coefficients of x and y in its direction vector.

Let's first find the midpoint between the two given points:

Midpoint = [(x₁ + x₂) / 2, (y₁ + y₂) / 2, (z₁ + z₂) / 2]

Midpoint = [(-8 + 0) / 2, (5 - 4) / 2, (1 + 9) / 2]

Midpoint = [-4, 0.5, 5]

So, the midpoint is (-4, 0.5, 5).

Now, let's create a line that passes through the midpoint and is parallel to the z-axis. The equation of such a line in vector form is:

r(t) = Midpoint + t Direction

Where r(t) is the position vector of a point on the line, t is a scalar parameter, Midpoint is the midpoint we calculated, and Direction is the direction vector.

Since the line is parallel to the z-axis, its direction vector is (0, 0, 1). Thus, the equation of the line is:

r(t) = (-4, 0.5, 5) + t (0, 0, 1)

r(t) = (-4, 0.5, 5 + t)

In component form, the equations of the line are:

x = -4

y = 0.5

z = 5 + t

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The midpoint of the two points is (-4, 0.5, 5). The line parallel to the z-axis passing through this point has the equations: x=-4, y=0.5, z=t.

Firstly, we need to find out the midpoint between the two points (0, -4, 9) and (-8, 5, 1).

The formula to calculate the midpoint of two points in three dimensions is ((x1+x2)/2, (y1+y2)/2, (z1+z2)/2).

Applying this formula to our points, we get the midpoint as ((0-8)/2, (-4+5)/2, (9+1)/2) which is (-4, 0.5, 5).

Lines parallel to the z-axis in three-dimensional space have equations of the form x=a, y=b, z=t, where 'a' and 'b' are constants representing any particular point through which the line passes, and 't' represents a variable that can take any real value.

Since the line we want passes through the point (-4, 0.5, 5), our equations for the desired line become: x=-4, y=0.5, z=t.

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Answer: [tex]6.25\%[/tex]

Step-by-step explanation:

Given: A pharmacist attempts to weigh 0.375 g of morphine sulfate on a balance of dubious accuracy. When checked on a highly accurate balance, the weight is found to be 0.400 g.

i.e. Estimated weight =  0.375 g  and Actual weight = 0.400 g

Now, the percentage of error in the first weighing is given by :-

[tex]\%\text{ Error}=\dfrac{|\text{Estimate-Actual}|}{\text{Actual}}\times100\\\\=\dfrac{|0.375-0.400|}{0.400}\times100\\\\=\dfrac{|-0.025|}{0.400}\times100\\\\=\dfrac{0.025}{0.4}\times100\\\\=\dfrac{25\times10}{4\times1000}\times100=\dfrac{25}{4}=6.25\%[/tex]

Hence, the percentage of error in the first weighing = [tex]6.25\%[/tex]

Answer:

Minimize C =[tex]13x + 3y[/tex]

[tex]12x + 14y \geq  21[/tex]

[tex]15x + 20y \geq 37[/tex]

and x ≥ 0, y ≥ 0.

Plot the the lines on the graph and find the feasible region

[tex]12x + 14y \geq  21[/tex]  -- Blue

[tex]15x + 20y \geq  37[/tex] --- Green

So, the boundary points of feasible region are (-3.267,4.3) , (0,1.85) and (2.467,0)

Substitute the value in Minimize C

Minimize C =[tex]13x + 3y[/tex]

At (-3.267,4.3)

Minimize C =[tex]13(-3.267) + 3(4.3)[/tex]

Minimize C =[tex]-29.571[/tex]

At (0,1.85)

Minimize C =[tex]13(0) + 3(1.85)[/tex]

Minimize C =[tex]5.55[/tex]

At (2.467,0)

Minimize C =[tex]13(2.467) + 3(0)[/tex]

Minimize C =[tex]32.071[/tex]

So, the optimal value of x is -3.267

So, the optimal value of y is 4.3

So, the minimum value of the objective function is -29.571

Answer:

A)128

B)717

Step-by-step explanation:

In Roman numerals each letter have a numerical value in Hindu-Arabic numerals.

These values are:

I = 1

V = 5

X = 10

L = 50

C =100

D = 500

M = 1000

a) CXXVIII = 100+10+10+5+1+1+1 = 128

b) XCDCCCXXVII = 500+100+100+10+10+7-100-10 = 717

In this question we subtracted the value of XC(-100-10) because it was preceding or appeared before a larger value and hence, we subtract these values from the value of DCCCXXVII(500+100+100+100+10+10+7).

This could be understood with the help of following example: If we calculate the value of CD it would be (500-100) = 400. Now, XCD = (400-10) = 390.

Answer:

1 member took literature but not mathematics.

Step-by-step explanation:

We can draw a Venn diagram for the given question.

In a fraternity total number of members = 32

Number of members who took mathematics M = 18

Number of members who took both mathematics and literature (M∩L) = 5

And number of members who took neither mathematics nor literature = 8

Therefore, number of members who took literature but not mathematics

= 32 - [(18 + 5) + 8]

= 32 - [23 + 8]

= 32 - 31

= 1

Therefore, 1 member took literature but not mathematics.

Answer:

1 member took literature but not mathematics.

Step-by-step explanation:

Answer:

Yusuf got 19 toffees

Step-by-step explanation:

The problem tells us that if Yusuf counts his toffees in 4's, he has 3 left. Let's call the number of toffees "t", then we know that [tex]t[/tex]≡[tex]3(mod4)[/tex]

We also know that [tex]t[/tex]≡[tex]4(mod 5)[/tex]

Between 10 and 20, there are only 2 numbers t≡[tex]4(mod 5)[/tex], these numbers are 14 and 19.

However, 14≡[tex]2(mod 4)[/tex] so it doesn't add up.

On the other hand, 19 ≡3[tex](mod4)[/tex] and therefore, this is the answer.

Answer:

19 toffees.

Step-by-step explanation:

It is given that Yusuf has between 10 and 20 toffees.

Let n be the number of toffees.

If he counts his toffees in 4s, he has 3 left over.

[tex]n\equiv 3(mod4)[/tex]      ... (1)

So, the possible values of n between 10 and 20 are 11, 15 and 19.

If he counts his toffees in 5s, he has 4 left over.

[tex]n\equiv 4(mod5)[/tex]       ... (2)

So, the possible values of n between 10 and 20 are 14 and 19.

From (1) and (2) the possible value of n between 10 and 20 is 19.

Therefore, Yusuf has 19 toffees.

Answer:

  Part A:  13.2

  Part B:  see below

Step-by-step explanation:

Part A:

13.245 rounded to tenths is 13.2

Part B:

The rule is ...

  Add 1 in the number place you're rounding to if the digit to its right is 5 or more. Drop (or zero) all digits to the right of the place you're rounding to.

Here, the digit to the right of the tenths place is 4, so no action is taken other than dropping digits to the right of the tenths place.

Answer:

  r = -6

Step-by-step explanation:

We presume you want to find the value of r that satisfies the equation.

Subtract 6r+13 from both sides:

  (6r+7) -(6r+13) = (13 +7r) -(6r+13)

  -6 = r . . . . . simplify

_____

More detailed explanation

When we look at the equation we see the only variable is r, and that terms containing it appear on both sides of the equal sign. There is only one "r" term on each side, so we don't need to do any consolidation. We observe that the term with the smallest coefficient is 6r and that it is on the left side.

When we subtract 6r from the equation we will have the remaining "r" term on the right, but we will also have a constant there that we don't want. So, we can subtract that constant as well. That is why we choose to subtract 6r+13 from the equation. Doing so leaves the constants on the left and the "r" terms on the right.

As it happens, the difference between the "r" terms is plain "r", so we're done after we finish the subtraction.

__

When considering the "r" terms, we choose to subtract the term with the smallest coefficient so that the result has a positive coefficient for "r". This helps reduce mistakes in later steps, if there are any later steps.

___

Alternate "steps"

For a linear equation like this one, you can subtract one side from both sides. This might look like ...

  0 = 6+r . . . . . after subtracting 6r+7 (left side) from both sides

Then you can divide by the coefficient of r (which does nothing to this equation), and subtract the resulting constant (on the side with the variable). Here, that would give ...

  -6 = r

These three steps will work to solve any linear equation. Simplification steps may be required depending on the complexity. Again, it might be helpful, though is not essential, to subtract the side with the smallest coefficient of the variable.

___

Final note

The rules of equality say you can do anything you like to an equation, as long as you do the same thing to both sides. We can say "subtract the constant" because we are assured that you know it must be subtracted from both sides of the equation. Beware of any instruction that tells you to do something to one side of an equation and something different to the other side.

Answer:

The solution of this system is x=9/4, y=5/2, and z=-13/8

Step-by-step explanation:

1. Writing the equations in matrix form

The system of linear equations given can be written in matrix form as

[tex]\left[\begin{array}{ccc}1&0&2\\2&-1&0\\0&3&4\end{array}\right]\left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}-1&2&1\end{array}\right][/tex]

Writing

A = [tex]\left[\begin{array}{ccc}1&0&2\\2&-1&0\\0&3&4\end{array}\right][/tex]

X = [tex]\left[\begin{array}{c}x&y&z\end{array}\right][/tex]

B = [tex]\left[\begin{array}{c}-1&2&1\end{array}\right][/tex]

we have

AX=B

This is the matrix form of the simultaneous equations.

2. Solving the simultaneous equations

Given

AX=B

we can multiply both sides by the inverse of A

[tex]A^{-1}AX=A^{-1}B[/tex]

We know that [tex]A^{-1}A=I[/tex], the identity matrix, so

[tex]X=A^{-1}B[/tex]

All we need to do is calculate the inverse of the matrix of coefficients, and finally perform matrix multiplication.

3. Calculate the inverse of the matrix of coefficients

A = [tex]\left[\begin{array}{ccc}1&0&2\\2&-1&0\\0&3&4\end{array}\right][/tex]

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

[tex]\left[\begin{array}{ccc|ccc}1&0&2&1&0&0\\2&-1&0&0&1&0\\0&3&4&0&0&1\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc|ccc}1&0&2&1&0&0\\0&-1&-4&-2&1&0\\0&3&4&0&0&1\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc|ccc}1&0&2&1&0&0\\0&-1&-4&-2&1&0\\0&0&-8&-6&3&1\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc|ccc}1&0&2&1&0&0\\0&1&4&2&-1&0\\0&0&-8&-6&3&1\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc|ccc}1&0&2&1&0&0\\0&1&4&2&-1&0\\0&0&1&3/4&-3/8&-1/8\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc|ccc}1&0&0&-1/2&3/4&1/4\\0&1&4&2&-1&0\\0&0&1&3/4&-3/8&-1/8\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc|ccc}1&0&0&-1/2&3/4&1/4\\0&1&0&-1&1/2&1/2\\0&0&1&3/4&-3/8&-1/8\end{array}\right][/tex]

As can be seen, we have obtained the identity matrix to the left. So, we are done.

[tex]A^{-1} = \left[\begin{array}{ccc}-1/2&3/4&1/4\\-1&1/2&1/2\\3/4&-3/8&-1/8\end{array}\right][/tex]

4. Find the solution [tex]X=A^{-1}B[/tex]

[tex]X= \left[\begin{array}{ccc}-1/2&3/4&1/4\\-1&1/2&1/2\\3/4&-3/8&-1/8\end{array}\right]\cdot \left[\begin{array}{c}-1&2&1\end{array}\right] = \left[\begin{array}{c}9/4&5/2&-13/8\end{array}\right][/tex]

Answer:

a=2

Step-by-step explanation:

u=3b-2(2) or u=3b-4

Final answer:

To solve the equation for a, rearrange the terms and isolate 'a' by dividing by the coefficient.

Explanation:

Step 1: Start with the equation u + 3b - 2a + 2 = 0.

Step 2: Rearrange the terms to isolate 'a', which gives  -2a = -u - 3b - 2.

Step 3: Divide by -2 to solve for 'a', resulting in a = (u + 3b + 2) / 2.

Answer:

36.25 is equal to the 45.5% of 79.67

Step-by-step explanation:

To solve this you just have to find the value that represents the 100%.

To do this, you can use the Rule of Three that allows you to solve problems of proportions.

In this case, you know that the 45.5% of the magnitude X is 36.25, now you have to find the value which corresponds to the 100%.  

Mathematically it will be:

[tex]\frac{X}{36.25} =\frac{100}{45.5}[/tex]

Then you have to solve the equation to find X:

[tex]X=\frac{100}{45.5}*36.25[/tex]

And finally, the answer is:

[tex]X=79.67[/tex]

Answer:

l = 18 - L

Step-by-step explanation:

Since 18 feet board is cut into two pieces L and l.

L + l = 18

Subtracting both sides by L

l = 18 - L

Step-by-step explanation:

Consider the provided information.

For the condition statement [tex]p \rightarrow q[/tex] or equivalent "If p then q"

Part (A) If it snows tonight, then I will stay at home.

Here p is If it snows tonight, and q is I will stay at home.

Converse: If I will stay at home then it snows tonight.

[tex]q \rightarrow p[/tex]

Inverse: If it doesn't snows tonight, then I will not stay at home.

[tex]\sim p \rightarrow \sim q[/tex]

Contrapositive: If I will not stay at home then it doesn't snows tonight.

[tex]\sim q \rightarrow \sim p[/tex]

Part (B) I go to the beach whenever it is a sunny summer day.

Here p is I go to the beach, and q is it is a sunny summer day.

Converse: It is a sunny summer day whenever I go to the beach.

[tex]q \rightarrow p[/tex]

Inverse: I don't go to the beach whenever it is not a sunny summer day.

[tex]\sim p \rightarrow \sim q[/tex]

Contrapositive: It is not a sunny summer day whenever I don't go to the beach.

[tex]\sim q \rightarrow \sim p[/tex]

Part (C) When I stay up late, it is necessary that I sleep until noon.

P is I sleep until noon and q is I stay up late.

Converse: If I sleep until noon, then it is necessary that i stay up late.

[tex]q \rightarrow p[/tex]

Inverse: When I don't stay up late, it is necessary that I don't sleep until noon.

[tex]\sim p \rightarrow \sim q[/tex]

Contrapositive: If I don't sleep until noon, then it is not necessary that i stay up late.

[tex]\sim q \rightarrow \sim p[/tex]

The converse, contrapositive, and inverse of each of the specified conditional statements are shown below.

Suppose the conditional statement given is:

[tex]p \rightarrow q[/tex] or 'if p then q'

Then, we get:

For the listed conditional statements, finding their converse, contrapositive, and inverse statements:

This can be taken as: If it is a sunny summar day, then i go to the beach.

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Here are some possible answers

Answer:

  The scale factor is 2/3.

Step-by-step explanation:

When the dilation is about the origin, the ratio of image coordinates to original coordinates is the scale factor:

  4/5 = 6/9 = 2/3

The scale factor is 2/3.

Answer:

[tex]z= 5-2i[/tex]

Step-by-step explanation:

Start replacing!

[tex](x+iy) + 4i (x-iy) = -3+18i \\ x+iy +4ix -4i^2 y = -3 + 18i \\\\x + i (4x+y) +4y = -3 + 18i\\x+4y + (4x+y) i = -3 + 18i[/tex]

Now two complex numbers are equal if both the real and imaginary parts are equal, which gives you the system of equation [tex]\left \{x+4y=-3} \atop {4x+y=18} \right.[/tex]

Pick any method to solve it and you'll get [tex] x=5, y= -2 [/tex]

Answer:

  d)  one solution; (4, 1)

Step-by-step explanation:

It often works well to follow problem directions. A graph is attached, showing the one solution to be (4, 1).

_____

You know there will be one solution because the lines have different slopes. Each is in the form ...

  y = mx + b

where m is the slope and b is the y-intercept.

The first line has slope -1 and y-intercept +5; the second line has slope 1 and y-intercept -3. The slope is the number of units of "rise" for each unit of "run", so it can be convenient to graph these by starting at the y-intercept and plotting points with those rise and run from the point you know.

Answer:

(a) Sampling distribution

P(25) = 0,04

P(35) = 0.1 + 0.1 = 0,2

P(42,5) = 0.06 + 0.06 = 0,12

P(45) = 0,25

P(52,5) = 0.15 + 0.15 = 0,3

P(60) = 0,09

(b) E(X) = 45.5 oz

(c) E(X) = μ

Step-by-step explanation:

The variable we want to compute is

[tex]X=(X1+X2)/2[/tex]

For this we need to know all the possible combinations of X1 and X2 and the probability associated with them.

(a) Sampling distribution

Calculating all the 9 combinations (3 repeated, so we end up with 6 unique combinations):

P(25) = P(X1=25) * P(X2=25) = p25*p25 = 0.2 * 0.2 = 0,04

P(35) = p25*p45+p45*p25 = 0.2*0.5 + 0.5*0.2 = 0.1 + 0.1 = 0,2

P(42,5) = p25*p60 + p60*p25 = 0.2*0.3 + 0.3*0.2 = 0.06 + 0.06 = 0,12

P(45) = p45*p45 = 0.5 * 0.5 = 0,25

P(52,5) = p45*p60 + p60*p45 = 0.5*0.3 + 0.3*0.5 = 0.15 + 0.15 = 0,3

P(60) = p60*p60 = 0.3*0.3 = 0,09

(b) Using the sample distribution, E(X) can be expressed as:

[tex]E(X)=\sum_{i=1}^{6}P_{i}*X_{i}\\E(X)=0.04*25+0.2*35+0.12*42.5+0.3*52.5+0.09*60 = 45.5[/tex]

The value of E(X) is 45.5 oz.

(c) The value of μ can be calculated as

[tex]\mu=\sum_{i=1}^{3}P_{i}*X_{i}\\\mu=0.2*25+0.5*45+0.3*60=45.5[/tex]

We can conclude that E(X)=μ

We could have arrived to this conclusion by applying

[tex]E(X)=E((X1+X2)/2)=E(X1)/2+E(X2)/2\\\\\mu = E(X1)=E(X2)\\\\E(X)=\mu /2+ \mu /2 = \mu[/tex]

Answer:

The person has to invest $5000 at 9% and $7000 at 10%.

Step-by-step explanation:

As stated in the problem, we have an ammount C that the person invest at 9% and an ammount (C+2000) that it is invested at 10%.

To gain $1150 a year, the ammount C needs to satisfy this equation:

[tex]C*0.09+(C+2000)*0.10=1150[/tex]

Applying distributive property,

[tex]0.09C+0.10C+200=1150\\0.19C=1150-200[/tex]

[tex]C=950/0.19\\C=5000[/tex]

So the person has to invest C=$5000 at 9% and (C+2000)=$7000 at 10% to gain $1150 of interest yearly.

Answer:

the range of the relation is 3

Answer:

Let the growth function that shows the population in millions after x years,

[tex]P=P_0(1+r)^x[/tex]

Where,

[tex]P_0[/tex] = initial population,

r = growth rate per year,

Suppose the population is estimated since 1950,

Thus, if x = 0, P = 2560,

[tex]\implies 2560 = P_0 (1+r)^0\implies P_0 = 2560[/tex]

Now, if x = 10 ( that is, on 1960 ), P = 3040,

[tex]3040=2560(1+r)^{10}\implies r = 0.017[/tex]

Hence, the required function that shows the population after x years,

[tex]P=2560(1.017)^x[/tex]

If x = 42,

The population in 1992  would be,

[tex]P=2560(1.017)^{42}\approx 5196.608365\text{ millions}[/tex]

if x = 80,

The population in 2030 would be,

[tex]P=2560(1.017)^{80}\approx 9860.891929\text{ millions}[/tex]

Final answer:

The world population growth can be modeled using exponential growth with a relative growth rate calculated from given data. The relative growth rate, k, was found to be approximately 0.017355. Using this rate, we can estimate past and predict future populations; however, demographic trends show that actual growth rates are slowing.

Explanation:

To model the world population using a proportional growth rate, we employ the exponential growth model where dP/dt = kP. The world population was 2560 million in 1950 (P(0) = 2560) and 3040 million in 1960 (P(10) = 3040). We will use these data points to find the relative growth rate k.

Finding the Relative Growth Rate

The general solution of the differential equation is P(t) = P(0)e^(kt), where e is the base of the natural logarithm. Inserting our initial conditions:

P(0) = 2560, which implies C = 2560 where C is the initial population.

P(10) = 3040 yields 3040 = 2560e^(10k).

Dividing both sides by 2560 gives 3040/2560 = e^(10k), and then taking the natural logarithm of both sides we find ln(3040/2560) = 10k. Therefore, k ≈ ln(1.1875)/10. By calculating, k ≈ 0.017355 (rounded to six decimal places).

Estimating World Population for 1992 and Predicting for 2030

Using this growth rate, we can estimate the world population for any year t with P(t) = 2560e^(0.017355t):

For the year 1992 (t=42 years since 1950), P(42) ≈ 2560e^(0.017355*42).

For the year 2030 (t=80 years since 1950), P(80) ≈ 2560e^(0.017355*80).

Demographic trends suggest a slowing growth rate. Between 1965 and 1980, the annual rate was 2%, while predictions for 2005-2015 showed a decline to 1.1%. These numbers imply increasing doubling times and changing dynamics in world population growth.

Answer:

D = 170.6Km

Step-by-step explanation:

First of all, we set the reference (origin) at Grand Bahama.

Nw, from the first displacement of 3h we calculate the distance:

D1 = V1*t = 43.5 * 3 = 130.5 Km

The coordinates of this new location is given by:

r1 = ( -D1*cos(60°); D1*sin(60°)) = (-62.5; 158.835) Km

For the second displacement, the duration was of 1.95 hours (4.95 -3), so the distance traveled was:

D2 = V2*t = 23.5 * 1.95 = 45.825 Km

The coordinates of this new location is given by:

r2 = r1 + ( 0; D2) = (-62.25; 158.835) Km

Now we just need to calculate the magnitude of that vector to know the distance to Grand Bahama:

[tex]Dt = \sqrt{D_{2x}^{2}+D_{2y}^{2}}=170.6 Km[/tex]

Answer:

  (a) even: J, K, M, O; odd: L, N

  (b) L and O are connected to J

  (c) N is of degree 3

Step-by-step explanation:

Count the edge ends that intersect each vertex. You get ...

  J-2, K-2, L-3, M-2, N-3, O-4

These numbers are the degree of the vertex.

a) Vertices with even degree are J, K, M, O, since these have degrees of 2, 2, 2, and 4, respectively--all even numbers.

Vertices with odd degree are L and N, since these both have degree 3, an odd number.

__

b) The vertices that are adjacent to J are the ones at the other ends of the edges that intersect vertex J. One of those two edges connects to vertex L; the other to vertex O. J is adjacent to L and O.

__

c) When we counted edges in part (a), we found vertex N to be of degree 3.

Answer:

The correct option is A) [tex]3d+C[/tex].

Step-by-step explanation:

Consider the provided information.

Paco bought 3 CDs that cost d dollars each.

Let d is the cost of each CDs.

The cost of 3 CDs will be 3 times of d.

This can be written as:

[tex]3d[/tex]

He bought a pack of gum for C cent. Thus, we can say that the cost of pack of gum is C.

Now add the cost of gum in above expression.

[tex]3d+C[/tex]

Hence, the required expression is [tex]3d+C[/tex].

Thus, the correct option is A) [tex]3d+C[/tex].

Answer:

Units for parameter k would be [tex]minutes^{-1}[/tex].

Step-by-step explanation:

The concentration of CA0 is given in M (moles per liter), which is the unit for CA; if we show units inside parenthesis in the equation, it would be:

[tex]CA (M)=CA0 (M) *(1-e-k(?)*t(minutes))[/tex]

For the concentration units of CA0 not to be affected by the units of the factor (1-e-k*t), this factor would have to be a number without units.

Since 1 is a constant without units, for the constant e to be able to subtract from 1 it would have to be a number without units, which also applies to the factor k*t.

For the factor k*t to be a number without units, k must have units that can be canceled when multiplied by t, which is given in minutes, so k must have units of [tex]\frac{1}{minutes} =minutes^{-1}[/tex]

This can be confirmed by operating the equation using only its units (units of parameter k are noted by a question mark):

[tex]M=M(0-0-?*minutes)[/tex]

[tex]\frac{M}{M} =?*minutes[/tex]

[tex]1=?*minutes[/tex]

[tex]\frac{1}{minutes}=?[/tex]

[tex]minutes^{-1}=?[/tex]