Answer and Explanation:
cross: BbTt x bbTt
Cross for B gene
Parental ) Bb x bb
Gametes) B b b b
Punnet square) B b
b Bb bb
b Bb bb
F1) Genotypic proportion: 2/4=1/2 Bb : 2/4=1/2 bb
Genotypic ratio 1:1
Phenotypic proportion: 2/4=1/2 B- : 2/4=1/2 bb
Phenotypic ratio 1:1
Cross for T gene
Parental ) Tt x Tt
Gametes) T t T t
Punnet square) T t
T TT Tt
t Tt tt
F1) Genotypic proportion 1/4 TT
2/4 Tt
1/4 tt
Genotypic ratio 1 : 2 : 1
Phenotypic proportion: 3/4 T-
1/4 tt
Phenotypic ratio 3 : 1
What are some similarities between nerves and hormones?
Answer:
The biggest difference between the two is that the nervous system uses electrical impulses to send signals through neurons, whereas the hormonal system uses chemical messengers transported into blood plasma to target cells. While endocrine system is slow, nervous impulse is immediate/rapid. Hormones are transported chemically through blood, nervous impulses are transported electrochemically through nerve fibres. Hormones affect different organs of the body and has a widespread effect, while nervous impulses afeect only a particular part of the body. Hormonal effect is long lasting whereas nervous effect is short lived. Hormones can bring about a metabolic change but nervous impulse impulses cannot bring about a metabolic change.
A child's pituitary gland does not release enough hormones. What is the most
likely cause of this?
A. The child has no ovaries.
B. The child has no adrenal hormones.
C. The child's blood glucose level is too high.
D. The child's hypothalamus is not working correctly.
Answer: im not sure but i think its b
Explanation:
A child's pituitary gland does not release enough hormones, the most
likely cause of this - D. The child's hypothalamus is not working correctly.
Hypothalamic dysfunction is a problem with a part of the brain called the hypothalamus. The hypothalamus helps control the pituitary gland and regulates many body processes with help of hormones.
The following changes would take place due if the hypothalamus is not working correctly -
If the hypothalamus is not working correctly which leads to many issues such as blurred vision and weight loss.The hypothalamus dysfunction regulates the pituitary gland that releases many essential hormones such as growth hormones which cause poor intellectual and body growth.homeostasis will also be affected.Thus, The correct choice is - D.
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Which growth model would you expect to see in a stable population
Stage 4 of the age structure diagrams is likely to represent a population in decline, as it follows the stages of rapid growth, slow growth, and stable population respectively. Declining populations typically show fewer young individuals and an aging overall population.
Explanation:The age structure diagrams described in stages 1 through 3 indicate different patterns of population growth: stage 1 shows rapid growth, stage 2 shows slow growth, and stage 3 shows a stable population. In stable populations, the logistic growth model is a more realistic representation of population dynamics than exponential growth. This is because the logistic growth model accounts for resource limitations that impact reproductive growth as population size increases.
Considering the provided descriptions, stage 4 in an age structure diagram would typically represent a population that is either declining or contracting. This is inferred from the fact that stable populations have nearly equal numbers across age groups, while declining populations would show fewer younger individuals and potentially a bulging at older age groups, indicating that less offspring are being produced and the overall population is aging.
Although the direct reduction of CoQ to CoQH2 is thermodynamically possible, this reaction is not a direct part of the electron transport chain via complexes I, III, and IV. Instead NADH reduces an FMN cofactor in complex I and the reduced FMNH2 kick-starts electron transport in the membrane.
Why is this electron handoff from NADH to FMN, as opposed to direct reduction of CoQ by NADH, a critical component of the electron transport chain?
Answer:
This electron handoff from NADH to FMN, as opposed to direct reduction of CoQ by NADH, a critical component of the electron transport chain is important for Signaling Transduction and Metabolomics
Explanation:
The NADH-CoQ reductase reaction is catalyzed by Complex I. In this course of activity, following events takes place-
a) FNM (NADH dehydrogenase flavoprotein) is reduced by the NADH to FMNH2 through following reactions –
NADH+H++E-FMN↔NAD++E-FMNH2
b) In the next phase coenzyme Q receives electron from FMNH2 through the the iron–sulfur centers of the NADH-CoQ reductase
c) The iron atom undergoes oxidation–reduction cycles to conserve mitochondrial protein as lataxin and hence transport protons from the matrix to the intermembranal space thereby Signaling Transduction and Metabolomics
Explain the characteristics scientists use when observing organisms and placing them in the six kingdoms.
Answer:
Classification of organisms is done while considering many factors such as:
Cell type- whether the organism is prokaryotic or eukaryotic
Cell structure- This includes both the presence and composition of the cell wall
Body type- whether the organism is multicellular or unicellular
Mode of nutrition- the method through which the organism achieves its nutritional requirement, by consuming other organisms (heterotroph) or making its own food (autotroph)
Darius is observing a family of geese, which includes a male goose, female goose, and several goslings. When a dog approaches the geese, the male goose hisses at the dog and flaps its wings threateningly.
Is the behavior of the male goose an example of an adaptation?
A. Yes, because the behavior is inherited and helps the goose and its offspring survive.
B. Yes, because the behavior is a response to another animal.
C. No, because adaptations are body structures, not behaviors.
D. Maybe, depending on whether or not the dog attacks the geese.
Answer:
A. Yes, its an inherited behaviour that helps the goose and its offspring to survive.
Explanation:
Adaptation could be a trait with a functional role in an individual or animal that is maintained and has also evolved as a result of natural selection.
The male goose hissing and wing flapping is an adaptive trait of scaring away predators.
Answer:
Yes
Explanation:
In animals the sensory capabilities evolved over hundreds of millions of years. It is therefore not surprising that different sensory aspects use similar transduction mechanisms. In terms of transduction (i.e., the way energy or chemicals are sensed and transduced into an electrical signal), which distinct human sensory systems use the same molecular mechanisms? Please list two pairs of systems and explain the similarity.
Answer:
Visual framework:
In visual framework, sensory cells replace physical vitality of light signals into electrical motivations that movement to the mind. Tangible cells in visual framework are bar cells and cone cells. The light creates a conformational changes in rhodopsin. This change brings about a decrease of the electro-chemical inclination of the photo-receptor which brings about decrease of electrical signs setting off to the cerebrum.
Aulfactory framework:
In the olfactory framework the atoms that giving smell stuck the bodily fluid tough situation to G protein receptors on olfactory cells. The G protein does initiates a downstream flagging course that causes progressively level of cyclic AMP which causes synapse discharge
Starch is a polymer of glucose molecules in plants with a role analogous to that of glycogen in animals. Starch synthesis requires ADP‑glucose generated by ADP‑glucose pyrophosphorylase. The biochemical mechanism of ADP‑glucose pyrophosphorylase catalysis is similar to that of UDP‑glucose pyrophosphorylase. What is the driving force for the ADP‑glucose pyrophosphorylase reaction?
a. production of ADP‑glucose
b. hydrolysis of ADP‑glucose
c. production of pyrophosphate
d. hydrolysis of pyrophosphate
The driving force for the ADP-glucose pyrophosphorylase reaction is hydrolysis of pyrophosphate.
Explanation:The driving force for the ADP‑glucose pyrophosphorylase reaction is d. hydrolysis of pyrophosphate.
Here's why:
The reaction is:
ATP + glucose-1-phosphate + pyrophosphate <=> ADP-glucose + phosphate
The hydrolysis of pyrophosphate (PPi) into two inorganic phosphates releases a significant amount of free energy (approximately -30 kJ/mol). This free energy release drives the reaction forward, even though the difference in free energy between ADP-glucose and ATP is small.
The production of ADP-glucose (a readily usable sugar precursor) is important for starch synthesis, but it is the hydrolysis of PPi that provides the necessary energy for the reaction to occur.
Therefore, option d is the correct answer.The driving force for the ADP‑glucose pyrophosphorylase reaction is production of ADP-glucose.
Which of the following statements about membrane-enclosed organelles is TRUE? Other than the nucleus, most organelles are small and thus, in a typical cell, only about 10% of a cell’s volume is occupied by membrane-enclosed organelles; the other 90% of the cell volume is the cytosol. The nucleus is the only organelle that is surrounded by a double membrane. In a typical cell, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane. The nucleus is the only organelle that contains DNA.
Answer:
The correct answer is: "In a typical cell, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane".
Explanation:
The endoplasmic reticulum (ER) is a membranous organelle that is in charge of the synthesis and transport of certain molecules. This organelle is composed of a folded lipidic bilayer that branches into interconnected tubules enclosing the lumen. This lumen occupies about 10% of the cell total volume.
More than half of the total membrane of eukaryotic cells is found in the ER. The ER´s membrane size also exceeds the total size of the plasmatic membrane.
The membrane of the endoplasmatic reticulum allows the selection of molecules that need to be transported from the cytoplasm to the organelle´s lumen. It is also a connection channel between the nucleus and the cytoplasm.
Answer:
The third option is the correct answer: In a typical cell, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane.
Explanation:
Eucaryotic cells contain intracellular membranes that enclose nearly half the cell's total volume in separate intracellular compartments called organelles.
Membrane-enclosed organelles are those that are bound by a phospholipid bilayer (the membrane), thereby allowing the organelles within the cell to control what goes in or out of it using a semi-permeable membrane.
The main types of membrane-enclosed organelles present in all eucaryotic cells are the endoplasmic reticulum, Golgi apparatus, nucleus, mitochondria, lysosomes, endosomes, and peroxisomes.
The ER encompasses approximately half of the total membrane area of an animal cell, thus, the area of the endoplasmic reticulum membrane far exceeds the area of plasma membrane.
In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give genotypic and phenotypic ratios of offspring.
Answer:
Total four genotypes and its frequency
SsWw – 4/16
ssWw- 4/16
Ssww - 4/16
ssww - 4/16
Phenotype –
SsWw – Heterozygous Spotted skin and heterozygous wooled hair
ssWw - Homozygous non-spotted skin and heterozygous wooled hair
Ssww - Heterozygous Spotted skin and Homozygous non -wooled hair
ssww - Homozygous non-spotted skin and Homozygous non -wooled hair
Explanation:
Given -
Allele for spotted skin is "S"
Allele for non-spotted skin is "s"
Allele for Wooly hair is "W"
Allele for non-wooly hair is "w"
Allele "S" is dominant over "s"
And Allele "W" is dominant over "w"
Cross is carried out between heterozygous spotted, non-wooly man and heterozygous wooly-haired, non-spotted woman
Genotype of heterozygous spotted, non-wooly man - Ssww
Genotype of heterozygous wooly-haired, non-spotted woman - ssWw
Ssww * ssWw
Sw Sw sw sw
sW SsWw SsWw ssWw ssWw
sw Ssww Ssww ssww ssww
sW SsWw SsWw ssWw ssWw
sw Ssww Ssww ssww ssww
Total four genotypes and its frequency
SsWw – 4/16
ssWw- 4/16
Ssww - 4/16
ssww - 4/16
Phenotype –
SsWw – Heterozygous Spotted skin and heterozygous wooled hair
ssWw - Homozygous non-spotted skin and heterozygous wooled hair
Ssww - Heterozygous Spotted skin and Homozygous non -wooled hair
ssww - Homozygous non-spotted skin and Homozygous non -wooled hair
The branch of science which deals with the gene and inheritance is called genetics.
The correct answer is 1:2:1 and 3:1
The cross between two characters is called a dihybrid cross.
According to the question, the parent's genes are Ss and Ww.
The gamete formed during the gametogenesis is S and s for one parent and W and w for another.
This gamete and fused with any of the gametes to increase the variation.
After the cross the result is
SW, Sw, sW, and sw.
Hence the genotype ratio is 1:1:1:1 but the phenotype ratio is spotted skin: nonspotted skin is 2:2.
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Explain what is “acid rain.” In your explanation, tell how it affects plants and the environment and the steps society can take to help reduce its effects.
Answer:
Acid rain: Rainfall made so acidic by atmospheric pollution that it causes environmental harm, chiefly to forests and lakes. The main cause is the industrial burning of coal and other fossil fuels.
Alternative fuels is an excellent way to prevent acid rain and to stop using nonrenewable fuels and switch over to renewable sources of energy, such as solar, wind and water energy.
Answer:
Acid rain comes from Gaseous Sulfur evaporating into the air. When it goes into the clouds, it reacts with the water vapor to make sulfuric acid. Then, when the cloud turns into water droplets, it brings the sulfuric acid down with it, typically in low concentrations. This will erode any substance with Calcite a mineral in it. Since Limestone and marble have this mineral, many buildings, statues, and surfaces are affected by acid rain. However, this affect will only be significantly felt by long term exposure. The way to help decrease the likelihood of acid rain is to reduce the amount of electricity because most electricity in the United States comes from burning coal, which produces sulfur dioxide. Burning any fossil fuel for energy production, including oil and natural gas, releases nitrogen oxides. Or reduce vehicle exhaust that also produces nitrogen oxides.
Hope this helped
Explain the characteristics scientist use when observing organisms and placing them in the six kingdoms.
Answer:
Mobility- When an organisms is able to physically move from place to place.
Cell Type- Having a nucleus and organelles or Not having them.
Cell Type - Prokaryotic. ...
Cell Type- Eukaryotic. ...
Cell Structure- Cell Wall. ...
Cell Structure- No Cell Walls. ...
Body Type- Unicellular. ...
Body Type- Multicellular.
Explanation:
Answer:
the simple answer
Explanation:
cell type – prokaryotic or eukaryotic
cell structure – cell wall
nutrition – autotrophic or heterotrophic
body type – unicellular or multicellular
which of the following is a scientific question
Explanation: whats the following ?
Answer: What are the options?
Explanation:
Which statement is true of mitosis?
A) mitosis plays a vital role in sexual reproduction
B) mitosis plays a vital role in an organisms growth
C) During the process of mitosis, new organisms are created
D) during the process of mitosis, haploid cells are created
Answer:Mitosis plays a vital role in an organism's growth.
Explanation:During reproduction, new organisms are created. Sometimes, the new organisms are created asexually through processes like binary fission, budding, or fragmentation. In other cases, new organisms are created sexually when a sperm cell fertilizes an egg cell.
Growth is different from reproduction. When an organism grows, it creates more of its own cells through the process of mitosis. No new organisms are created during growth, however.
Drag the missing word into place
When classifying living things,
is the largest division.
domain
class
kingdom
Answer:
Domain is the largest division. See the attachment for more help!
The color operon codes for structural genes that convert pigment A to pigment C. The operon is regulated by a gene called Paint. In wild type cells, the operon is transcribed in the presence of pigment A, but not in the absence of A. In Paint- mutants, the operon is constitutively transcribed. Is this operon inducible or repressible? Group of answer choices Inducible, because wild type transcription occurs in the presence of pigment A. Repressible, because wild type transcription is repressed in the presence of A. It cannot be determined because the number of structural genes is unknown. Inducible, because the operator in Paint- mutants can still bind to pigment A. Repressible, because Paint- transcription only occurs in the presence of pigment A.
Answer:
Inducible, because wild type transcription occurs in the presence of pigment A.
Explanation:
In the question, we were given that color operon codes for structural genes that convert pigment A to pigment C and is regulated by a gene called Paint. Since transcription occurs in the presence of pigment A then it means pigment A induces the transcription. This makes it Inducible, because wild type transcription occurs in the presence of pigment A.
The color operon, which is turned on in the presence of pigment A and constantly expressed in a Paint- mutant, is an example of an inducible operon.
Explanation:The color operon codes for structural genes that convert pigment A to pigment C is an example of an inducible operon. In wild type cells, the operon is transcribed in the presence of pigment A, indicating that the operon is induced when A is present. In Paint- mutants where the operon is constantly being expressed, regardless of the presence or absence of pigment A, this further suggests the operon is inducible since it can be turned on in the absence of a repressor.
Inducible operons are often associated with metabolic pathways where the end product is not constantly required (in contrast with repressible operons, which are typically associated with biosynthetic pathways that produce substances necessary for growth). In the case of this color operon, pigment A serves as the inducer, similar to how lactose acts as the inducer in the lactose (lac) operon.
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Pea plants have two traits: round or wrinkled seeds, and tall or short stems.
Round and tall are dominant, while wrinkled and short are recessive.
Two parent plants are crossed. One is heterozygous for both traits, the other is homozygous dominant for seed shape, and homozygous recessive for stem height.
What are the genotypes of the two parent plants? Use R or r for seed shape, and T or t for stem height.
The genotypes for seed shape are RR, RR, rR, and rR
For stem height they are Tt, Tt, tt, and tt
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2. The mRNA for a well-known secretory protein is isolated and placed in a test tube in the presence of all the substances required for in vitro protein synthesis. The sequence of the protein produced in vitro is then compared to the sequence of the secretory protein purified from the extracellular fluid. The sequences of the two proteins are not the same. What do you predict is the difference between the two proteins and why do you see this difference
Answer:
Post-transnational adjustment is a significant character of secretory protein which happens during translocation of protein through the endoplasmic reticulum and Golgi bodies. These proteins have some sign arrangement for this translocation and these successions are cut in the wake of moving toward the particular area of the cell.
If there should arise an occurrence of in vitro amalgamation of the above protein, the protein basically interpreted from the RNA and no cutting of the sign grouping and another succession which are cut in any case during translocation happens. Because of this succession of protein varies from the in vivo protein.
The difference in the protein sequences can be due to post-transcriptional and post-translational modifications in the cell, such as splicing, alternative gene splicing, and glycosylation.
Explanation:The difference between the proteins produced in vitro and purified from the extracellular fluid is likely due to post-transcriptional and post-translational modifications that occur in the cell but not in the test tube. For the protein made in the test tube, the sequence reflects the exact sequence of the mRNA. However, inside the cell, mRNA undergoes various modifications like splicing, addition of a 5' methylguanosine cap, and a 3' poly A tail.
Additionally, the sequence difference could also be attributed to alternative gene splicing, a mechanism that allows a single gene to code for multiple proteins by varying the sequence of exons enclosed within the mRNA. The sequences of these proteins will thus differ due to varying exon combinations. Another factor that could contribute to the sequence differences is post-translational modifications to the protein, such as glycosylation within the Golgi apparatus.
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The poly(A) sequence that is added to RNA during processing: helps prevent rapid breakdown of the messenger RNA. is needed for ribosomes to attach to messenger RNA. aids in the accuracy of translation of the messenger RNA into protein. helps prevent formation of complex three-dimensional structures in the messenger RNA.
Answer:
Option A, helps prevent rapid breakdown of the messenger RNA
Explanation:
The poly-A tail is a chain of adenine nucleotides which when get attached to the messenger RNA during RNA processing enhances the stability of the molecule and therefore prevents it from breaking down. This is required because after the transcription of gene in a eukaryotic cell, newly formed RNA molecule undergoes several modifications. It also helps is preventing the new RNA from enzymatic degradation in the cytoplasm and translation.
Hence, option A is correct
The poly(A) tail is added to mRNA to protect it from degradation, assist in its export from the nucleus, and support the initiation of translation. It does not directly influence the accuracy of translation or prevent the mRNA from forming complex structures.
The Function of the Poly(A) Tail in mRNA Processing
The poly(A) tail is a critical feature of messenger RNA (mRNA) in eukaryotic cells. Following the completion of transcription, the 3' end of pre-mRNA is processed to form a mature mRNA molecule. This processing includes the polyadenylation mechanism, where an enzyme known as poly(A) polymerase adds about 200 adenosine monophosphates to the mRNA creating a poly(A) tail. This sequence, traditionally located at the 3' end of the mRNA, serves several essential functions. It protects the mRNA from enzymatic degradation in the cytoplasm, aids in the export of mRNA from the nucleus, and is involved in the initiation of translation.
The addition of the poly(A) tail ensures the stability of the mRNA molecule by safeguarding it against rapid breakdown and thus prolongs its half-life, which is essential for producing proteins. Additionally, the poly(A) tail aids in the recognition and binding of proteins that are essential for exporting the processed mRNA to the cytoplasm. Here, ribosomes can attach and initiate translation, synthesizing the corresponding protein based on the mRNA sequence. The poly(A) tail does not, however, have a direct role in aiding the accuracy of translation or in preventing the formation of complex three-dimensional structures within the mRNA. Its primary role is in mRNA stability and facilitating protein synthesis
1. What are the possible reasons you would need to isolate human DNA?
2. How long is the DNA in each cell’s nucleus? _______
3. Identify the steps necessary to isolate DNA from cheek cells:
The possible reasons to isolate human DNA include genetic testing, forensic analysis, genealogy research, medical diagnostics, and scientific research. The length of DNA in each cell's nucleus is approximately 2 meters. The steps necessary to isolate DNA from cheek cells are:
1. Collecting the cells: Gently scrape the inside of the cheek with a cotton swab to collect cheek cells.
2. Lysing the cells: Add the collected cells to a solution that contains detergent and salt to break open the cells and dissolve the proteins and lipids.
3. Precipitating the DNA: Add cold alcohol to the solution to cause the DNA to precipitate out of the solution.
4. Spooling the DNA: Use a sterile stick or glass rod to twirl and collect the DNA that has formed a stringy, white precipitate.
5. Washing the DNA: Rinse the DNA with alcohol to remove impurities.
6. Dissolving the DNA: Place the DNA in a buffer solution to dissolve it, making it ready for further analysis or storage.
1. Isolating human DNA is essential for various applications. In genetic testing, it helps in identifying genetic disorders or predispositions to certain diseases. Forensic analysis uses DNA to match crime scene samples with suspects. Genealogy research involves tracing family histories and lineage. In medical diagnostics, DNA isolation aids in personalized medicine and understanding genetic factors in diseases. Scientific research often requires pure DNA samples for experiments and studying gene function.
2. The length of DNA in each cell is staggering when compared to the size of the cell itself. Human DNA is composed of approximately 3 billion base pairs, and when stretched out, it measures around 2 meters. This is possible because the DNA is highly coiled and packed within the cell nucleus.
3. The isolation of DNA from cheek cells involves several critical steps:
- Collecting the cells: Cheek cells are a convenient source of DNA because they can be easily obtained without invasive procedures.
- Lysing the cells: This step disrupts the cell membrane and nuclear envelope, releasing the DNA into the solution. The detergent helps to dissolve the lipid bilayer of the cell membrane, while the salt helps to dissociate the DNA from histones and other proteins.
- Precipitating the DNA: DNA is insoluble in alcohol, so when alcohol is added to the solution, the DNA strands clump together and precipitate out.
- Spooling the DNA: The precipitated DNA can be wound around a tool like a glass rod, making it easier to handle and transfer.
- Washing the DNA: This step removes any remaining salts, proteins, or detergents that might interfere with subsequent applications.
- Dissolving the DNA: Finally, the DNA is dissolved in a suitable buffer, typically Tris-EDTA (TE) buffer, which helps to maintain the pH and chelate any metal ions that could damage the DNA. The isolated DNA can then be used for various molecular biology techniques such as PCR, sequencing, or restriction digestion."
What is the function of a motor neuron?
O
A. Connects parts of the brain
O
B. Controls muscles
O
C. Connects spinal cord to brain
O
D. Connects other neurons
Answer: Controls Muscles
Explanation:
Apez
Answer:
Controls Muscles
Explanation:
A.P.E.X.
In a particular recessive genetic disorder, you find the allele frequency for this recessive allele in a population is 0.02. Assuming the population is in Hardy-Weinberg Equilibrium over the last generation, which of the following are possible statements about this population? Select all that apply. Select one or more: a. This genetic disorder could display severe and potentially fatal health complications only in individuals above 50 years of age. b. Most of the recessive alleles are found in heterozygous individuals. c. Any individuals in this population that are homozygous recessive are sterile. d. The population under investigation could have been formed by a founder event several hundred years ago.
Final answer:
In a recessively inherited disorder with a given allele frequency and an assumption of Hardy-Weinberg Equilibrium, complications appearing late in life, a higher presence of alleles in heterozygous individuals, and the possibility of a founder event are plausible statements. However, sterility in homozygous recessive individuals cannot be concluded without specific disorder information.
Explanation:
When considering the statements regarding a population with a recessive genetic disorder allele frequency of 0.02 and assuming Hardy-Weinberg Equilibrium (HWE), we can evaluate the given options:
a. This genetic disorder could display severe and potentially fatal health complications only in individuals above 50 years of age: This is possible since some disorders may have late onset or become symptomatic later in life.b. Most of the recessive alleles are found in heterozygous individuals: This is true given the low frequency of the allele (q), suggesting that homozygous individuals (q²) will be rare, making heterozygous carriers (2pq) more common in the population.c. Any individuals in this population that are homozygous recessive are sterile: This cannot necessarily be concluded from the allele frequency and the assumptions of HWE, as sterility would be a specific trait of the disorder, not a given for all recessive genetic disorders.d. The population under investigation could have been formed by a founder event several hundred years ago: This is possible as the founder effect is a form of genetic drift which can cause rare alleles to become prevalent in a population descended from a small ancestral group.Therefore, the correct statements that apply, based on the information provided and HWE, are a, b, and possibly d, but not c since it requires additional specific information about the genetic disorder.
The population could have late-onset severe complications, most recessive alleles are in heterozygotes, fertility depends on the disorder, and a founder event may explain allele frequencies.
a. This genetic disorder could display severe and potentially fatal health complications only in individuals above 50 years of age.
This statement is plausible as certain genetic disorders may manifest symptoms later in life, and the age of onset can vary. If the disorder in question has a late onset, individuals above 50 years may be more prone to severe health complications associated with the recessive allele.
b. Most of the recessive alleles are found in heterozygous individuals.
This statement is accurate based on the principles of Hardy-Weinberg Equilibrium. In a population in equilibrium, the frequency of homozygous recessive individuals is q^2, where q is the frequency of the recessive allele. The frequency of heterozygous individuals is 2pq, where p is the frequency of the dominant allele. If q is small (as indicated by the allele frequency of 0.02), then 2pq is much larger than q^2.
c. Any individuals in this population that are homozygous recessive are sterile.
This statement is not necessarily true. The fertility or sterility of homozygous recessive individuals depends on the specific genetic disorder. Some recessive genetic disorders may impact fertility, but it is not a general rule for all recessive alleles.
d. The population under investigation could have been formed by a founder event several hundred years ago.
This statement is plausible. A founder event, where a small group establishes a new population, can lead to a deviation from the allele frequencies in the larger source population. Over time, genetic drift in the smaller population can result in different allele frequencies, consistent with the observed frequency of the recessive allele in this scenario.
Characteristics of mitosis?
Answer:
see the explanation
Explanation:
The characteristics of Mitosis are:
- During mitosis one cell divides once to form two identical cells.
-The major purpose of mitosis is for growth and to replace worn out cells.
-It occurs only in somatic cells.
Chromosomal no. ...
-It does not allow genetic recombination.
Do you think humans belong in a food chain why or why not ? Help please due at 12
Answer:
I think he is
Explanation:
Because humans get their food from animals and plants therefore they are at the top of food chain and we conceder them as primary consumers.
How can rain and hail fall from the same cumulonimbus cloud?
When clouds get so full of water droplets that they can not hold any more, the water falls back to the ground as rain but sometimes water droplets freeze and fall to the ground as snow, sleet, or hail.
Big Bend National Park in Texas is mostly Chihuahuan desert, where rainfall averages about 10 inches per year. Yet, it is not uncommon when hiking in this bone-dry desert to encounter mosses and ferns. One such plant is called "flower of stone." It is not a flowering plant, nor does it produce seeds. Under arid conditions, its leaflike structures curl up. However, when it rains, it unfurls its leaves, which form a bright green rosette on the desert floor. Consequently, it is sometimes called the "resurrection plant." At first glance, it could be a fern, a true moss, or a spike moss.
What feature of both true mosses and ferns makes it MOST surprising that they can survive for many generations in dry deserts?
A. lack of cuticle
B. a gametophyte generation that is dominant
C. flagellated sperm
D. lack of true roots
Answer: Option C
Explanation:
There is no similarity seen in the ferns and mosses but biologically they have similarities. Both the plants are very primitive in nature and reproduce via sexual reproduction.
They cohabit with each other in moist and shady places. They produce motile sperm which swim through water ad reaches the egg. This is reason they are found in damp places.
Their ability of producing flagellated sperm makes them successful for their survival and called as resurrent plant. They have the ability to survive complete desiccation and grow as soon as they get favorable condition. They also have alternation of generation which also helps in its survival.
The most surprising feature of mosses and ferns that enables them to survive in deserts is their flagellated sperm, which requires water for fertilization. However, certain adaptations, like those seen in the resurrection plant, allow these plants to thrive in such conditions.
Explanation:The feature of both true mosses and ferns that makes it most surprising that they can survive for many generations in dry deserts is their flagellated sperm. Both mosses and ferns have flagellated sperm that requires water to reach the eggs for fertilization, which seems at odds with a desert environment where water is scarce.
However, many desert plants have adaptations to make the most of the limited water available. For example, the resurrection plant (or 'flower of stone') mentioned unfurls its leaves to collect rainfall when available and curls up to conserve water when conditions are arid.
These adaptations allow the plant to take advantage of the infrequent rainfalls in the desert and ensure the survival of these plants in this extreme environment.
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n mice, an allele for apricot (a) eyes is recessive to an allele for brown (A) eyes. At an independently assorting locus, an allele for tan (t) coat color is recessive to an allele for black (T) coat color. A mouse that is homozygous for brown eyes and black coat color is crossed with a mouse having apricot eyes and a tan coat. The resulting F1 are intercrossed to produce the F2. What is the probability of an F2 mouse having a black coat and apricot eyes?
Answer:
The probability of an F2 mouse having a black coat and apricot eyes is 3/16
Explanation:
Allele for apricot eyes (aa) is inherited in the recessive condition. Brown eyes can either be AA or Aa.
Allele for tan colour (tt) is inherited in the recessive condition. Black colour can either be TT or Tt.
Parents AATT x aatt
F1 AaTt
AaTt x AaTt
A-T- = 9
A-tt = 3
aaT- = 3
aatt = 1
the probability of an F2 mouse having a black coat and apricot eyes is 3/16
Irene and William are having their first child. Irene knows her blood type is A, but William does not know his blood type. However, William knows that his mother and father were B. Their first child is a boy named Gregory. Gregory has type O blood. Of course, Irene and William do not understand how this happened. You could explain this to them using which of the following choices?
a. B only
b. either B or O
c. O only
d. either AB or
e. A only
Answer:
Option C
So, for them to be able to produce an O type (genotype OO) child (Gregory), Both Irene and William have one copy each of O trait to be able to give birth to Gregory.
Explanation:
If Irene's bloodtype is A, her genotype could be either AO or AA. Since Williams does not know his bloodtype but knows his parents were both B which could be BO or BB. It is safe to assume that Williams could be a BO if is parents were BO and BB for him to produce a child with O type with Irene.
So, for them to be able to produce an O type (genotype OO) child, each has one copy each of O trait to give birth to Gregory.
Name the three structures of seed plants, and explain
their functions.
Answer:
The three principal organs of seed plants are roots, stems, and leaves. These organs perform functions such as the transport of nutrients, protection, and coordination of plant activities. Roots: absorb water and dissolved nutrients.
Explanation:
The three main structures of the seed plants are the roots, stem, and leaves. The different structures perform different functions in the plant.
What are seed plants?A seed plant is also called as the spermatophyte, or a phanogam. The spermatophyte is any plant which produces seeds, hence the alternative name for the plant is seed plant. Spermatophytes are a subset of the embryophytes or the land plants.
Three main structures of seed plant are the roots, stems, and the leaves. The roots are responsible for absorbing water and other minerals from the soil. The stem is the structure which provides strength to the plant body, and the leaves are responsible for performing photosynthesis and transpiration of water.
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In Andalusian fowls (Gallus gallus), black plumage (feathers) (P) is incompletely dominant to white (PW) and the heterozygous condition results in blue plumage. a. What phenotypes, and in what ratios, will result if you breed a blue Andalusian with a
i. black bird
ii. blue bird
ill. white bird
b. Is it possible to produce a flock of blue birds that will produce only blue offspring when mated with each other? Why or why not?
Answer:
i. Genotype - PP, PPW, PP, PPW
Phenotype - Blue Andalusian : black bird is 1:1
ii. Genotype - PP, PPW, PPW, PWPW
Phenotype - Black bird : Blue Andalusian : White bird - 1: 2: 1
iii. Genotype - PPW, PPW, PWPW, PWPW
Phenotye
Blue Andalusian : white bird
2: 2
1: 1
Explanation:
Given -
Black plumage (feathers) (P) is incompletely dominant to white (PW)
The heterozygous condition i.e PPW gives blue color to the feather.
i. Breeding a blue Andalusian with a black bird
Genotype of blue Andalusian - PPW
Genotype of black bird - PP
PPW * PP
PP, PPW, PP, PPW
Out of 4 two are blue Andalusian and two are black bird
Blue Andalusian : black bird is 1:1
ii. Breeding a blue Andalusian with a blue Andalusian
Genotype of blue Andalusian - PPW
PPW * PPW
PP, PPW, PPW, PWPW
Phenotype
Black bird - PP - 1
Blue Andalusian (PPW) - 2
White bird (PWPW) - 1
Black bird : Blue Andalusian : White bird - 1: 2: 1
iii. Breeding a blue Andalusian with a White bird
Genotype of blue Andalusian - PPW
Genotype of white bird - PWPW
PPW * PWPW
PPW, PPW, PWPW, PWPW
Two are Blue Andalusian and two are white bird
Blue Andalusian : white bird
2: 2
1: 1