For which pair of function is (g*f)(a)=|a|-2

1. f(a)=a^2-4 and g(a)= sqaureroot a
2. f(a)= 1/2a-1 and g(a)=2a-2
3. f(a)=5+a^2 and g(a) = sqaureroot (a-5)-2
4.f(a) =3 -3a and g(a)=4a-5

Answer:

Option A.

Step-by-step explanation:

The vertices of Polygon ABCD are A(0, 2), B(0, 8), C(7, 8), and D(7, 2).

Plot all vertices on the coordinate place.

If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the slope of the line is

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

First we need find the slope of each sides, using the above formula.

[tex]m_{AB}=\frac{8-2}{0-0}=\infty[/tex]

[tex]m_{BC}=\frac{8-8}{7-0}=0[/tex]

[tex]m_{CD}=\frac{8-2}{7-7}=\infty[/tex]

[tex]m_{AD}=\frac{2-2}{7-0}=0[/tex]

The slope of vertical lines is ∞ and slope of horizontal line is 0. It means sides AB and CD are vertical lines and sides BC and AD are horizontal lines.

Vertical and horizontal lines are perpendicular to each other. It means all interior angles of the polygon are right angles.

From the below figure it is clear that

[tex]AB=6[/tex]

[tex]BC=7[/tex]

[tex]CD=6[/tex]

[tex]AD=7[/tex]

Opposite sides are equal and interior angles are right angles, so the polygon is a rectangle.

Perimeter of the polygon is

[tex]Perimeter=AB+BC+CD+AD[/tex]

[tex]Perimeter=6+7+6+7=26[/tex]

Perimeter of polygon ABCD is 26 linear units.

Therefore, the correct option is A.

To solve the equation, it was first required to get rid of the fraction by multiplying both sides by 7 and then to isolate r, the running miles, you subtract 105 from both sides resulting in Gisele running 35 miles per week.

The question is asking to find the number of miles Gisele runs each week, which is represented by the variable r in the equation. We start with the equation: 1/7(105 + r) = 20. This equation is derived from the fact that Gisele covers a total of 20 miles each day, for 7 days, and that total comprises both her cycling and running mileages. If she cycles 105 miles each week, then the distance she runs is the remaining part of those total 20 miles she covers each day. We multiply both sides of the equation by 7 to get rid of the fraction: 105 + r = 140. Now, if we subtract 105 from both sides of the equation, we get the solution for r as; r = 140 - 105 = 35 miles. Hence, Gisele runs 35 miles each week.

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The sale price of the chair including tax is $185.5.

In mathematics, the tax calculation is related to the selling price and income of taxpayers. It is a charge imposed by the government on the citizens for the collection of funds for public welfare and expenditure activities. There are two types of taxes: direct tax and indirect tax.

Given that, Miles is buying a chair that regularly costs $250.

Today the chair is on sale for 30% off

So, the new cost is 250-30% of 250

= 250 - 30/100 ×250

= 250-75

= $175

The tax rate is 6%

Sale price = 175+6% of 175

= 175+6/100 ×175

= 175+0.06×175

= $185.5

Therefore, the sale price of the chair including tax is $185.5.

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Answer: 10

Step-by-step explanation:

Final answer:

The value of y, which directly varies with x, is found by first determining the constant of variation when x = 9 and y = 5.4. Using this constant, we calculate the value of y for x = -10, resulting in y = -6.

Explanation:

The value of y directly varies with x, which means the relationship between x and y can be described by the equation y = kx, where k is the constant of variation. Since y = 5.4 when x = 9, we first find the constant of variation as follows: k = y/x = 5.4/9 = 0.6. Now, to find y when x is -10, we use the constant of variation k in the equation: y = kx = 0.6(-10) = -6.

The relationship between y and x is one of direct variation, represented by the equation y = kx, where k is the constant of variation. Given that y = 5.4 when x = 9, the constant k is calculated as 0.6. Applying this constant, when x = -10, the value of y is found to be -6. This process showcases the direct variation principle in determining y based on the given x values and the constant of variation.

Answer:

Table 1

Step-by-step explanation:

We have the function [tex]f(x)=8(\frac{1}{4})^{x}[/tex].

Now, the function g(x) is obtained by reflecting f(x) across y-axis.

i.e. g(x) = f(-x)

i.e. [tex]g(x)=8(\frac{1}{4})^{-x}[/tex]

So, substituting the values of x in f(x) or g(x), we will discard some options.

2. For x=0, the value of [tex]f(0)=8(\frac{1}{4})^{0}[/tex] i.e. f(0) = 8.

As in table 2, f(0) = 0 is given, this is not correct.

3. For x=0, the value of [tex]g(0)=8(\frac{1}{4})^{-0}[/tex] i.e. g(0) = 8.

As in table 3, g(0) = -8 is given, this is not correct.

4. For x=0, the value of [tex]g(0)=8(\frac{1}{4})^{-0}[/tex] i.e. g(0) = 8.

As in table 3, g(0) = 0 is given, this is not correct.

Thus, all the tables 2, 3 and 4 do not represent these functions.

Hence, table 1 represents f(x) and g(x) as the values are satisfied in this table.

The fraction of the word 'Supercalifragilisticexpialidocious' that has the letter 'i' is 7/34, which is already in its simplest form.

The word 'Supercalifragilisticexpialidocious' contains 34 letters. To find what fraction of this word has the letter 'i' in it, we first need to count how many times the letter 'i' appears. The letter 'i' appears 7 times in the word. Therefore, the fraction of the word that has the letter 'i' in it is 7/34.

It is important to note that this fraction can be simplified. However, since both 7 and 34 are prime numbers with respect to each other (they have no common factors other than 1), the fraction 7/34 is already in its simplest form.

Answer:

Option C is correct.

Step-by-step explanation:

Given is :

The value of Ari's rolls of coins is = $113

The coins are pennies, dimes, nickels and quarters.

Total money is represented by = penny + nickle + dime + quarter  All values in dollars are represented by:

113 = .01* pennies + .05* nickles + 0.1* dimes + 0.25* quarters  

Further calculating we get,

113 = .01* 50*penny rolls + .05 * 40*nickle rolls + .1 * 50*dime rolls + .25 * 40*quarter rolls  

[tex]113=.5p+2n+5d+10q[/tex]

where p is the number of penny rolls, n is the number of nickle rolls, d is the number of dime rolls, and q is the number of quarter rolls  

Now checking all the options by putting values.

A. [tex]113=.5(5)+2(8)+5(4)+10(7)[/tex]

[tex]113\neq 108.5[/tex]

B. [tex]113=.5(4)+2(8)+5(7)+10(5)[/tex]

[tex]113\neq 103[/tex]

C. [tex]113=.5(4)+2(8)+5(5)+10(7)[/tex]

[tex]113=113[/tex]

D. [tex]113=.5(5)+2(8)+5(7)+10(4)[/tex]

[tex]113\neq 93.5[/tex]

Therefore, option C is the right option.

The range is 24 and the interquartile range is the difference between the median of the second-half to the first-half is 8.

The median of the data is the middle value of the data which is also known as the central tendency of the data and is known as the median.

The data set below represents the total number of touchdowns a quarterback threw each season for 10 seasons of play.

29, 5, 26, 20, 23, 18, 17, 21, 28, 20

Arrange in ascending order, we have

5, 17, 18, 20, 20, 21, 23, 26, 28, 29

The range will be given as

→ Range = 29 - 5 = 24

The interquartile range will be given as

→ Interquartile range = median of second-half - median of first-half

→ Interquartile range = 26 - 18

→ Interquartile range = 8

The range is 24 and the interquartile range is 8.

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The solution to the system of equations involving line A (y = 7x + 12) and a perpendicular line B passing through a given point involves finding the negative reciprocal of the slope of line A for line B, using the point-slope formula to get line B's equation, and solving the system to find their point of intersection.

The question revolves around finding the equation of line B, which is perpendicular to line A (y = 7x + 12) and passing through a given point, then solving the system of equations formed by lines A and B. First, we identify that the slope of line A is 7. Since line B is perpendicular to line A, its slope will be the negative reciprocal of 7, which is -1/7. Assuming the point it passes through is provided in the question, we can use the point-slope formula y - y1 = m(x - x1) to find the equation of line B. After determining the equation of line B, we solve the system of equations represented by lines A and B to find the point of intersection, which will be the solution to the system.

To solve the system of equations, we would set the equations equal to each other and solve for one variable, then substitute back to find the other variable. This process involves algebraic manipulation such as substitution or elimination method. The final solution will be the coordinates (x,y) where both lines intersect.

The answer to question 13 is (B). [tex]\(16x^2 - 48xy^3 + 36y^6\).[/tex]

The answer to question 14 is (A). [tex]\(x - 9\) and \(x + 3\)[/tex]

The answer to question 15 is (A). [tex]\((x - 6)\) and \((x - 5)\).[/tex]

The answer to question 16 is (A). [tex]\((x + 6y)(x + 4y)\).[/tex]

The answer to question 17 is (A).[tex]\(2x - 5\) and \(3x + 4\).[/tex]

The answer to question 18 is (B). [tex]\((5x + 7)\) and \((x - 2)\).[/tex]

To find a simpler form of the product [tex]\((4x - 6y^3)^2\)[/tex], we apply the formula for squaring a binomial, which is [tex]\((a - b)^2 = a^2 - 2ab + b^2\)[/tex]. Here, [tex]\(a = 4x\)[/tex] and [tex]\(b = 6y^3\).[/tex]

So, [tex]\((4x - 6y^3)^2 = (4x)^2 - 2(4x)(6y^3) + (6y^3)^2\).[/tex]

Calculating each term, we get:

[tex]\((4x)^2 = 16x^2\),[/tex]

[tex]\(-2(4x)(6y^3) = -48xy^3\),[/tex]

[tex]\((6y^3)^2 = 36y^6\).[/tex]

Putting it all together, we have:

[tex]\(16x^2 - 48xy^3 + 36y^6\).[/tex]

To find the possible dimensions of the rectangle, we need to factor the trinomial [tex]\(x^2 + 6x - 27\).[/tex] We look for two numbers that multiply to -27 and add up to 6. These numbers are 9 and -3.

So, [tex]\(x^2 + 6x - 27 = (x + 9)(x - 3)\).[/tex]

We factor the trinomial [tex]\(x^2 + x - 30\)[/tex] by finding two numbers that multiply to -30 and add up to 1. These numbers are 6 and -5.

So, [tex]\(x^2 + x - 30 = (x - 6)(x + 5)\).[/tex]

To factor [tex]\(x^2 - 10xy + 24y^2\)[/tex], we look for two numbers that multiply to \[tex](24y^2\)[/tex] and add up to -10y. These numbers are -6y and -4y.

So, [tex]\(x^2 - 10xy + 24y^2 = (x - 6y)(x - 4y)\)[/tex].

To find the possible dimensions of the barnyard, we factor the trinomial [tex]\(6x^2 + 7x - 20\).[/tex] We need two numbers that multiply to [tex]\(6 \times -20 = -120\)[/tex] and add up to 7. These numbers are 15 and -8. We then split the middle term accordingly and factor by grouping:

[tex]\(6x^2 + 15x - 8x - 20 = 0\),[/tex]

[tex]\(3x(2x + 5) - 4(2x + 5) = 0\),[/tex]

[tex]\((3x - 4)(2x + 5)\).[/tex]

We factor the trinomial [tex]\(5x^2 - 3x - 14\)[/tex] by finding two numbers that multiply to [tex]\(5 \times -14 = -70\)[/tex] and add up to -3. These numbers are -10 and 7. We then split the middle term accordingly and factor by grouping:

[tex]\(5x^2 - 10x + 7x - 14 = 0\),[/tex]

[tex]\(5x(x - 2) + 7(x - 2) = 0\),[/tex]

[tex]\((5x + 7)(x - 2)\).[/tex]

The statement "The value 3 is an upper bound for the zeros of the function f(x) = -3x^3 + 20x^2 - 36x + 16" is FALSE.

To determine whether the value 3 is an upper bound for the zeros of the function f(x) = -3x^3 + 20x^2 - 36x + 16, we need to check if the function has any real roots greater than 3.

One way to approach this is by analyzing the behavior of the function as x approaches infinity. We can check the sign of the leading coefficient (-3) and the constant term (16) to determine the overall behavior of the function.

Leading coefficient:

The leading coefficient of -3 indicates that the highest power of x in the function is negative. This means that as x approaches infinity, the function will decrease without bound.

Constant term:

The constant term of 16 indicates that the function intersects the y-axis at y = 16.

Considering these observations, we can infer that the function starts at a positive value (y = 16) and approaches negative infinity as x increases. This implies that the function f(x) = -3x^3 + 20x^2 - 36x + 16 will have at least one real root greater than 3.

Therefore, the statement "The value 3 is an upper bound for the zeros of the function f(x) = -3x^3 + 20x^2 - 36x + 16" is FALSE.

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Answer:

  P(z < 1.45) ≈ 0.92647

Step-by-step explanation:

Several forms of technology are available for finding the area under the standard normal curve. There are probability apps, web sites, spreadsheets, and calculator functions.

The area under the standard normal curve between two values of z is given on many spreadsheets and by many calculators using the normalcdf(a,b) function. In this form, 'a' is the lower bound, and 'b' is the upper bound of the z-values for which the area is wanted.

For the problem at hand, the value of 'a' is intended to be negative infinity. A calculator allows input of no such value, so some "equivalent" value must be used. (At least one calculator manual suggests -1e99.)

The area of the normal curve below z=-8 is less than 10^-11, so -8 is a suitable stand-in for -∞ on a calculator that displays a 10-decimal-digit result. All the decimal digits shown are accurate, not affected by our choice of lower bound.

The attachment shows the value of the expression is about ...

  P(z < 1.45) ≈ 0.92647

Answer with explanation:

We have to find , P (z< 1.45).

 Breaking ,z value into two parts, that is , In the column,the value at, 1.40 and in the row ,value at , 0.05,the point where these two value coincide,gives value of Z<1.45.

The value lies in the right of mean.

So, P(z<1.45)=0.9265

In the,Normal curve, at the mid point of the curve

Mean =Median =Mode

Z value at Mean = 0.5000

→So, if you consider , the whole curve,

P(Z<1.45)= 0.9265 × 100=92.65%=92%(approx) because we don't have to consider ,z=1.45.

→But, if you consider, the curve from mean ,that is from mid of the normal curve

P (z<1.45)=92.65% - 50 %

           =42.65% =42 %(approx) because we don't have to consider ,z=1.45.

Answer:  B

Step-by-step explanation:

Answer:

2475 cm

Step-by-step explanation:

We are given that Roberto's toy car travels 40 cm/sec at high speed and 25 cm/sec at low speed.

We have to find that the distance would have the car traveled

Speed of car at high speed=40 cm/sec

Speed of car at low speed=25 cm/sec

If car  takes time to travel at high speed=30 seconds

If car takes time to travel  at low speed=51 seconds

[tex]Distance=speed\times time[/tex]

Using this formula

Distance traveled by the car at high speed=[tex]40\times 30=1200 cm[/tex]

Distance traveled by the car at low speed=[tex]51\times 25=1275 cm[/tex]

Total distance traveled by the car =1200+1275=2475 cm

Hence, the distance  would have traveled by the car=2475 cm

Answer:

[tex]114.8\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of a trapezoid is equal to

[tex]A=\frac{1}{2}(b1+b2)h[/tex]

In this problem we have

[tex]b1=12\ ft[/tex]

[tex]b2=15\ ft[/tex]

[tex]h=8.5\ ft[/tex] ----> the height of the trapezoid is the perpendicular distance between the bases

substitute the values

[tex]A=\frac{1}{2}(12+15)(8.5)[/tex]

[tex]A=\frac{1}{2}(27)(8.5)=114.75\ ft^{2}[/tex]

Round to the nearest tenth

[tex]114.75=114.8\ ft^{2}[/tex]

Answer:

114.8 is the answer

Step-by-step explanation:

got it on edgen

Solution :

Given that, Celia earned $5.00.

She saved $1.00 and spent the rest.

To find the ratio of the amount saved to the amount spent , we must first calculate the amount spent.

To calculate the amount spent, subtract the amount saved from the total money earned.

Amount spent by Celia = amount earned - amount saved [tex] = 5-1 = 4 [/tex]

[tex] ratio= \frac{amount\:saved}{ amount\:spent} =\frac{1}{4} \\
\\
ratio= 1:4 [/tex]

Hence, 1:4 is the ratio of the amount saved to the amount spent.