The cross products property states that the product of the ___ equals the products of the ___
Can someone please help me
Answer:
Convert to inches to solve and then convert back. The first solution is 1 foot 10 inches.
Step-by-step explanation:
To solve convert feet inches into inches by multiplying the number of feet by 12 and adding it to the inches. Then subtract and convert back.
For example: 5 feet is 5*12=60 inches. So 5 feet 7 inches is 60+7=67.
3 feet is 3*12=36 inches. So 3 feet 9 inches is 36+9=45 inches.
Subtract the two.
67-45= 22 inches.
22 inches is 12+10. 12 inches is 1 foot. This is 1 foot 10 inches.
I need 21 centimeters but i need to translate that into millimeters wht is the answer in milli eters
The formula for the volume of a cone is v=1/3pir^2h. Find the radius, to the nearest hundredth, of a cone with a height of 3 in. and a volume of 12in.^3.Show your steps to finding the radius to receive credit.
The radius of the cone with a height of 3 in and a volume of 12 in is 1.95 in.
What is radius?Radius is the line that connects any point of the circumference of a circle to the center of that circle.
Given:
V = 1/3(πr²h)............... Equation 1Where:
V = Volume of the coner = radius of the coneh = height of the coneMake r the subject of the equation
r = √(3V/πh)................ Equation 2From the question,
Given:
V = 12 in³h = 3 inSubstitute these values into equation 2
r = √[(3×12)/(3.14×3)]r = √(12/3.14)r = √(3.82)r = 1.95 in.Hence, the radius of the cone with a height of 3 in and a volume of 12 in is 1.95 in.
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Final answer:
The radius to the nearest hundredth is 1.38
Explanation:
To find the radius of a cone with a given height and volume, use the formula [tex]V = 1/3 * \pi * r^2 * h[/tex], where V is the volume, r is the radius, and h is the height.
In this case, the volume is given as 12 in^3 and the height is given as 3 in.
Substituting these values into the formula:
[tex]12 = 1/3 * \pi * r^2 * 3[/tex]
Multiply both sides of the equation by 3:
[tex]36 = \pi * r^2 * 3[/tex]
Divide both sides of the equation by 3π:
[tex]12/\pi = r^2[/tex]
Take the square root of both sides of the equation:
[tex]r = \sqrt{(12/\pi )[/tex]
Approximating it to nearest hundredth -
r ≈ 1.38
When Marsha went shopping, she decided to buy some nuts to take home. She bought 1 3/4 lbs. of cashews, 5/8 lbs. of almonds, and 2 1/2 lbs. of peanuts. How many pounds of nuts did she buy?
Answer: 4 7/8
Step-by-step explanation:
i just took the test
Which of the following is a polynomial function in factored form with zeros at 0, –3, and 4?
A. f(x) = x^3 + x^2 – 12x
B. f(x) = x(x – 3)(x + 4)
C. f(x) = x^3 – x^2 – 12x
D. f(x) = x(x + 3)(x – 4)
what is area of a parallelogram that has a base of 12 3/4 in. and a height 2 1/2in.?
Find the lateral area of the square pyramid.
One base angle of an isosceles triangle measures 33 degrees. What is the number of degrees in the vertex angle?
Find (fxf)(0)
F(x)+3x-2
To find (fxf)(0), substitute 0 into the given function f(x) = x + 3x - 2. The resulting value is -2.
Explanation:To find (fxf)(0), we need to substitute 0 into the given function. The function is f(x) = x + 3x - 2. Substituting 0 for x, we get f(0) = 0 + 3(0) - 2 = -2. Therefore, (fxf)(0) = f(f(0)) = f(-2).
What metric unit would be appropriate to measure a length of two cities?
This figure is made up of a triangle and a semicircle.
What is the area of this figure?
Use 3.14 for pi. Round only your final answer to the nearest tenth.
Enter your answer as a decimal
Given is a composite figure where we have a semicircle and a triangle.
To find the area of the semicircle, we need diameter of the circle which is the distance between two given points (2,4) and (2,-3). So the diameter is 4-(-3) = 7 and radius would be 3.5 units.
Area of circle = π·r² = 3.14 × (3.5)² = 38.465 squared units.
So, area of semicircle = 38.465 ÷ 2 = 19.2325 squared units.
To find the area of the triangle, we need base and height of the triangle. The base is same as diameter = 7 and the height would be distance between given point (5,0) and (2,0), so height is 5-2 = 3.
Area of triangle [tex] =\frac{1}{2} bh = \frac{1}{2} (7)(3) = 10.5 [/tex] 1/2 * 7 * 3 = 10.5 squared units.
Total area = Area of triangle + Area of semicircle = 10.5 + 19.2325 = 29.7325 squared units.
So, final answer is 29.7325 squared units.
Solve the system of equations using the substitution method.
{2x+8y=4
x=−3y+5
Enter your answers in the boxes.
x=
y=
Answer:
Step-by-step explanation:
X=14
y=-3
Answer:
(14,-3)
Step-by-step explanation:
PLEASE HELP, 40 points, absurd answers will be reported, good answers will get brainliest
8.03b
(PART 1)
Find at least three examples of conic sections in the real world (marketing, architecture, nature, etc.). Make sure your collage demonstrates at least two of the conic categories you have learned. You may use circles, ellipses, parabolas, or hyperbolas. Arrange your images on paper or in a document.
(PART 2)
Respond to each of the following prompts in a word processing document.
Write a brief description about one of the conics from your collage.
Write the equation that represents your conic in its standard form. To do this either find the measurements of your conic example to create the equation or guess the measurements of the conic.
Your assignment must include:
Your conics collage.
A description about one conic from your collage.
The standard form equation of one of the conics.
An explanation of how the equation for the conic was found.
The width of a rectangle is 6 less than twice its length. if the area of the rectangle is 110 cm^2, what is the length of the diagonal?
Final answer:
The length of the rectangle is 10 cm and the width is 11 cm. Using the Pythagorean theorem, the length of the diagonal can be calculated to be √221 cm.
Explanation:
The length of the rectangle is 10 cm and the width is 11 cm.
To find the length of the diagonal, we can use the Pythagorean theorem:
Diagonal2 = Length2 + Width2
Diagonal = √(102 + 112) = √(100 + 121) = √221 cm.
The length of the rectangle is 10 cm and the width is 11 cm. Using the Pythagorean theorem, the length of the diagonal can be calculated to be √221 cm.
Please help asap! lots of points
Answer:
The answer is D.
Hope I helped :)
Have a blessed day <3
~Michael~
a flyer on a reconnaissance flight has 4 hours for a round trip. his blade can fly 200 mph in still air. he flies out from his base against a 20 mph wind and immediately returns to his base, flying with the same wind. how many hours did he take for his fight out?
A prism with a base area of 5 ft² and a height of 10 ft is dilated by a factor of 6/5 .
What is the volume of the dilated prism?
Enter your answer, as a decimal, in the box.
Find the height of the top of the goal post, rounded to the nearest tenth of a foot
Due to insufficient and irrelevant information, the height of the goal post can't be determined.
Explanation:Unfortunately, the provided information does not allow us to ascertain the height of the goal post. The information presented primarily consists of measurements and heights of trees and people. Without any relevant information specific to the height of the goal post on which the question is based, it's not possible to provide a thorough answer. If further details were provided, such as the angle of the viewer's line of sight toward the top of the post and their distance from the post, then we could use trigonometric principles to resolve the answer.
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Too many nutrients is not good for bodies of water. This man-made is called what?
A. Cultural eutrophication
B. Point-source pollution
C. Eutrophication
PLEASE HELP
6.02B
Respond to the following prompt in a word processing document.
Describe, in detail, when to use the law of cosines, the law of sines, and the law of sines with the ambiguous case. Provide general guidelines, in your own words, for each law that can be applied to any triangle situation with which you are presented. To aid in your explanation, you may refer to specific problems from the text.
Your response must include:
A discussion of
The law of cosines
The law of sines
The ambiguous case (law of sines)
General guidelines in your own words that can be applied to any triangle.
Law of cosines :
The law of cosines establishes:
[tex] c ^ 2 = a ^ 2 + b ^ 2 - 2*a*b*cosC.
[/tex]
general guidelines:
The law of cosines is used to find the missing parts of an oblique triangle (not rectangle) when either the two-sided measurements and the included angle measure are known (SAS) or the lengths of the three sides (SSS) are known.
Law of the sines:
In ΔABC is an oblique triangle with sides a, b, and c, then:
[tex] \frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC} [/tex]
The law of the sines is the relation between the sides and angles of triangles not rectangles (obliques). It simply states that the ratio of the length of one side of a triangle to the sine of the angle opposite to that side is equal for all sides and angles in a given triangle.
General guidelines:
To use the law of the sines you need to know either two angles and one side of the triangle (AAS or ASA) or two sides and an opposite angle of one of them (SSA).
The ambiguous case :
If two sides and an angle opposite one of them is given, three possibilities may occur.
(1) The triangle does not exist.
(2) Two different triangles exist.
(3) Exactly a triangle exists.
If we are given two sides and an included angle of a triangle or if we are given 3 sides of a triangle, we can not use the law of the sines because we can not establish any proportion where sufficient information is known. In these two cases we must use the law of cosines
The Law of Sines, Law of Cosines, and the Ambiguous Case are used to solve triangles depending on the given information. The Law of Sines is used when you have angles and sides but no right angle, the Law of Cosines is used when you have at least one side and angles, and the Ambiguous Case is used when you have one angle and two sides with two possible triangles. General guidelines are provided for each law.
Explanation:The Law of Sines:
The law of sines is used to solve triangles when you have information about the measures of angles and sides, but do not have a right angle. It relates the ratios of the lengths of the sides of a triangle to the sines of its angles.
The Law of Cosines:
The law of cosines is used to solve triangles when you have information about the measures of angles and sides, and at least one side is known. It relates the lengths of the sides of a triangle to the cosine of one of its angles.
The Ambiguous Case:
The ambiguous case, also known as the law of sines with the ambiguous case, is used to solve triangles when you have information about the measures of angles and sides, and want to find all possible solutions. It occurs when you have one angle and two sides given, but there are two possible triangles that can be formed.
General Guidelines:
Use the law of sines when you have the measure of an angle and the length of its opposite side, or two pairs of an angle and its opposite side.Use the law of cosines when you have the length of one side and the measures of the other two sides or when you have two sides and the included angle.Use the law of sines with the ambiguous case when you have the measure of an angle and the length of its opposite side, and there are two possible triangles that can be formed.
A company need to package hazardous chemicals in special plastic rectangular prism containers that had 80 cubic feet. Find the whole number dimensions of the container that would use the least amount of plastic.
To package hazardous chemicals in special plastic containers the dimensions of the container should be 4 × 4 × 5 feet.
A rectangular prism with a volume of 80 cubic feet needs to be designed to use the least amount of plastic. To do this, we need to find the dimensions (length, width, height) that, while maintaining the given volume, result in the minimum surface area.
The volume of a rectangular prism is given by:
Volume = length × width × height
For our case: length × width × height = 80 cubic feet
To minimize the surface area, the dimensions should be close to a cube as this shape has the smallest surface area-to-volume ratio. We will seek integer dimensions. The formula for the surface area (SA) of a rectangular prism is:
SA = 2(length × width + width × height + height × length)
We start by considering potential combinations of whole numbers whose product is 80:
1 × 1 × 801 × 2 × 401 × 4 × 201 × 5 × 161 × 8 × 102 × 2 × 202 × 4 × 102 × 5 × 84 × 4 × 5Calculating the surface area for each configuration:
1 × 1 × 80: SA = 2(1×1 + 1×80 + 80×1) = 2(1 + 80 + 80) = 322 sq. feet1 × 2 × 40: SA = 2(1×2 + 2×40 + 40×1) = 2(2 + 80 + 40) = 244 sq. feet1 × 4 × 20: SA = 2(1×4 + 4×20 + 20×1) = 2(4 + 80 + 20) = 208 sq. feet1 × 5 × 16: SA = 2(1×5 + 5×16 + 16×1) = 2(5 + 80 + 16) = 202 sq. feet1 × 8 × 10: SA = 2(1×8 + 8×10 + 10×1) = 2(8 + 80 + 10) = 196 sq. feet2 × 2 × 20: SA = 2(2×2 + 2×20 + 20×2) = 2(4 + 40 + 40) = 168 sq. feet2 × 4 × 10: SA = 2(2×4 + 4×10 + 10×2) = 2(8 + 40 + 20) = 136 sq. feet2 × 5 × 8: SA = 2(2×5 + 5×8 + 8×2) = 2(10 + 40 + 16) = 132 sq. feet4 × 4 × 5: SA = 2(4×4 + 4×5 + 5×4) = 2(16 + 20 + 20) = 112 sq. feetThus, the dimensions 4 × 4 × 5 feet are the ones that use the least amount of plastic, giving a surface area of 112 sq. feet.
A mortgage broker charges $4000 plus 1.8% of the mortgage amount. What is the mortgage broker fee for a $309,000 mortgage?
The answer is 9,562. Thank you very much.
The mortgage broker fee for a $309,000 mortgage is calculated by multiplying the mortgage amount by 1.8% and then adding a fixed charge of $4000, resulting in a total fee of $9,562.
Explanation:The mortgage broker fee for a $309,000 mortgage can be calculated by taking 1.8% of the mortgage amount and adding the fixed charge of $4000. To find 1.8% of $309,000, we multiply 0.018 by 309,000.
0.018 \( \times \) $309,000 = $5,562.
Then we add the fixed charge:
$5,562 + $4,000 = $9,562.
So, the mortgage broker fee for a $309,000 mortgage is $9,562.
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After running for 54 minutes, she completes 6 kilometers. Her trainer writes an equation letting t, the time in minutes, represent the independent variable and k, the number of kilometers, represent the dependent variable. Which equation can be used to represent k, the number of kilometers Julissa runs in t minutes? k – 2 = 1/9(t – 18) k – 18 = 1/9(t – 2) k – 2 = 9(t – 18) k – 18 = 9(t – 2)
Answer:
the answer is C
Step-by-step explanation:
using her first part 2 kilometers in 18 minutes
total kilometers - 2
and total time - 18
so you would get:
k – 2 = (t – 18)
16 POINTS. Find the x and y intercepts of number 8 show work. I think my points are wrong.
If two quantities are added and the sum is zero, what do you know about the quantities?
Triangle ABC is congruent to triangle XYZ. Angle A measures 50 degrees, angle B measure 2x+40 degrees, and angle Z measures 4x+8 degrees. Find the value of x.
20.5
13.67
16
10.5
Final answer:
To find the value of x, we use the fact that the angles of a triangle sum up to 180 degrees. By setting an equation with the given angle measurements and solving for x, we find the value of x to be 13.67.
Explanation:
The student asks about determining the value of x in two congruent triangles, ABC and XYZ, given the measurements of the angles. If triangles are congruent, their corresponding angles are equal. Using the fact that the sum of the angles in a triangle is 180 degrees, and given Angle A is 50 degrees, Angle B is 2x+40 degrees, and Angle Z is 4x+8 degrees, we can set up an equation because Angle B corresponds to Angle Z in congruent triangles:
50 + (2x + 40) + (4x + 8) = 180
Combine like terms:
50 + 2x + 40 + 4x + 8 = 180
6x + 98 = 180
Subtract 98 from both sides:
6x = 82
Divide both sides by 6:
x = 13.67
Therefore, the value of x is 13.67.
The radius r of a circle can be written as a function of the area A with the following equation:
[tex]r= \frac{A}{ \pi } [/tex]
What is the domain of this function? Explain why it makes sense in this context.
4/5 are girls. Today 3/5 brought there lunch. What fraction of the students are girls who brought there lunch today?
1. Real numbers that cannot represent as a quotient of two integers are ____ numbers.
2. The sum of a number and it’s ____ equals zero.
3. You can simplify an expression by combining it’s ____.
4. ____ is a numbers distance from zero on a number line.
5. when you make conclusions based on patterns you observe, you use ____.