Answer: b. A 90% confidence level and a sample of 24 observations. 1.714 1.714 Correct
Step-by-step explanation:
When the driver applies the brakes of a small-size truck traveling 10 mph, it skids 5 ft before stopping. How far will the truck skid if it is traveling 55 mph when the brakes are applied
Answer:
The truck will skid for 151 ft before stopping when the brakes are applied
Step-by-step explanation:
From the equations of motion, we will use
[tex]v^{2} = u^{2}-2aS[/tex]
We have to make sure that the parameters we are working with are in the same unit of length. Here, we will be converting from ft to miles
When the truck is travelling at 10 mph.
S = distance the truck skids = [tex]\frac{5ft}{5286ft/mile}= 0.00094697miles[/tex]
Final velocity of truck, v = 0 m/s (this is because the truck decelerates to a halt)
Initial velocity of truck u = 10 mph
Hence, we have
[tex]0^{2}=10^{2}-2a\times 0.00094697[/tex]
[tex]a= 52799.9miles/hr^{2}[/tex]
This is the deceleration of the truck
We will work based on the assumption that the car decelerates at the same rate each time the brakes are fully applied.
When the truck is travelling at u= 55 mph.
We will need to use the deceleration of the car to find the distance traveled when it skids.
[tex]0^{2}=55^{2}-2\times52799.98\times S[/tex]
[tex]S= 0.0286 miles\approx 151 ft[/tex]
∴The car skids for about 151 ft when it is travelling at 55 mph and the brakes are applied.
Arc Length and Radians question- please help! Will mark brainliest! Is 20pts!
The answer is shown but please give me an explanation so I can show my work!
Given:
Given that the radius of the merry - go - round is 5 feet.
The arc length of AB is 4.5 feet.
We need to determine the measure of the minor arc AB.
Measure of the minor arc AB:
The measure of the minor arc AB can be determined using the formula,
[tex]Arc \ length=(\frac{\theta}{360})2 \pi r[/tex]
Substituting arc length = 4.5 and r = 5, we get;
[tex]4.5=(\frac{\theta}{360})2 (3.14)(5)[/tex]
Multiplying the terms, we get;
[tex]4.5=(\frac{\theta}{360})31.4[/tex]
Dividing, we get;
[tex]4.5=0.087 \theta[/tex]
Dividing both sides of the equation by 0.087, we get;
[tex]51.7=\theta[/tex]
Rounding off to the nearest degree, we have;
[tex]52=\theta[/tex]
Thus, the measure of the minor arc AB is 52°
Answer:
52°
Step-by-step explanation:
Arc length = (theta/360) × 2pi × r
4.5 = (theta/360) × 2 × 3.14 × 5
theta/360 = 45/314
Theta = 51.59235669
Answer the question.
Sophie works as a computer programmer. she earns $28 per hour. If Sophie works 10 hours. how much money will she earn?
Victor has $40 in a savings account. The interest rate is 5%, compounded annually.
To the nearest cent, how much interest will he earn in 3 years?
Answer:
$6.31
Step-by-step explanation:
We are going to use the compound simple interest formula for this problem:
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
P = initial balance
r = interest rate (decimal)
n = number of times compounded annually
t = time
Our first step is to change 5% into its decimal form:
5% -> [tex]\frac{5}{100}[/tex] -> 0.05
Next, plug in the values:
[tex]A=40(1+\frac{0.05}{1})^{1(3)}[/tex]
[tex]A=46.31[/tex]
Lastly, subtract 40 (our original value) from 46.31:
[tex]46.31-40=6.31[/tex]
Victor earned $6.31 in interest after 3 years.
40% of students in a school wore blue on a spirit Day. If two
students are randomly selected, what is the probability that both
students will not be wearing blue?
The probability that both students will not wear blue is 0.36, obtained by multiplying the probability of one student not wearing blue, 0.60, by itself.
To find the probability that both students will not be wearing blue, we first need to determine the probability that one student is not wearing blue, and then multiply that probability by itself for two students.
Step 1: Calculate the probability that one student is not wearing blue.
Given that 40% of students wore blue, the probability that one student is not wearing blue is 1 - 0.40 = 0.60.
Step 2: Multiply the probability for one student by itself for two students.
The probability that both students will not be wearing blue is (0.60) ×(0.60) = 0.36.
So, the probability that both students will not be wearing blue is 0.36.
The mean per capita income is 16,44516,445 dollars per annum with a standard deviation of 397397 dollars per annum. What is the probability that the sample mean would differ from the true mean by greater than 3838 dollars if a sample of 208208 persons is randomly selected? Round your answer to four decimal places.
To calculate the probability that the sample mean would differ from the true mean by greater than $38, if a sample of 208 persons is randomly selected, we need to use the Central Limit Theorem. First, we determine the standard error of the mean (SEM) using the formula SEM = standard deviation / square root of sample size. Then, we calculate the Z-score using the formula Z = (sample mean - true mean) / SEM. Finally, we find the probability associated with the Z-score using a Z-table or calculator.
Explanation:To calculate the probability that the sample mean would differ from the true mean by greater than $38, if a sample of 208 persons is randomly selected, we need to use the Central Limit Theorem.
According to the Central Limit Theorem, the distribution of sample means will be approximately normal regardless of the shape of the population distribution, as long as the sample size is large enough.
Since the sample size is greater than 30, we can assume that the distribution of sample means will be approximately normal.
To calculate the probability, we first need to determine the standard error of the mean (SEM), which is the standard deviation divided by the square root of the sample size. In this case, the SEM = $397 / √208.
Next, we calculate the Z-score using the formula Z = (sample mean - true mean) / SEM = ($38 - 0) / ($397 / √208). Finally, we can use a Z-table or calculator to find the probability associated with the Z-score.
In this case, it is the probability that Z is greater than the calculated Z-score. Hence, the probability that the sample mean would differ from the true mean by greater than $38 is the probability that Z is greater than the calculated Z-score.
Daniel makes 16 more muffins than kris.
Daniel makes 34 muffins. How many muffins does kris make?
Solve the equation problem choose yes or no
Sam’s dry cleaning store has 3 employees who fold the clothes. Each employee can fold 45 shirts every hour. Assuming a level aggregate program how many more employees will Sam has to hire or fire to meet a demand of 1600 shirts per day if everyone works an 8 hour shift? Hire 5 more employees Hire 2 more employees Fire 1 employee Hire 17 more employees Fire 2 employee
Answer:
Hire 2 more employees.
Step-by-step explanation:
Multiply 45 by 8 to find out how many shirts 1 employee can fold for one day, one employee can fold 360 shirts in one day, then multiply that by 3 to see how many shirts they can fold a day with only the three employees. They can fold 1080 shirts in one day.
1600-1080= 520. Subtracting the demand by how many his store already can fold shows how many more he needs.
1 employee isn't enough because they can only fold 360 shirts a day so he would need to hire 2 employees because they can fold 720 shirts which meets the demand of shirts that need to be folded.
What is the probability that a domestic airfare is $560 or more (to 4 decimals)? b. What is the probability that a domestic airfare is $260 or less (to 4 decimals)? c. What if the probability that a domestic airfare is between $320 and $500 (to 4 decimals)? d. What is the cost for the 3% highest domestic airfares? (rounded to nearest dollar)
Without sufficient data, we cannot calculate the probabilities or the cost for the 3% highest domestic airfares. The calculations require details about the total number of observed airfares and the number that falls in the specified price ranges.
Explanation:I regret to inform you that I cannot provide a factual answer to your question regarding domestic airfares as you have not provided sufficient data. Probability depends on the sample space and given conditions which are not provided in your question. For instance:
For the probability of a domestic airfare being $560 or more, we need to know the total number of observed airfares and the number that were $560 or more. The same applies to a domestic airfare of $260 or less (to 4 decimals). The total fares and the ones falling under this range are required. The probability of a fare being between $320 and $500 is calculated from the total fares within this range divided by the total fares observed. For the 3% highest fares, we need to know the distribution of airfares to calculate this value. Learn more about Probability here:
https://brainly.com/question/22962752
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A watch cost $48 more than a clock. The cost for the clock is 4/7 the cost of the watch. You'll find the total cost of the two items
Final answer:
To find the total cost of the watch and the clock, set up equations based on the given relationships, solve for the individual costs, and then add them together. The total cost amounts to $176.
Explanation:
The student is asking to find the total cost of two items - a watch and a clock. The clock costs 4/7 of what the watch costs, and the watch costs $48 more than the clock. Let's denote the cost of the clock as c and the cost of the watch as w. The problem gives us two equations: w = c + $48 and c = (4/7)w. Now, we can solve these equations to find the individual costs of the clock and the watch, then sum them to find the total cost.
Step-by-step Solution
Substitute the value of c from the second equation into the first equation: w = (4/7)w + $48.
Multiply both sides of the equation by 7 to eliminate the fraction: 7w = 4w + $336.
Subtract 4w from both sides: 3w = $336.
Divide both sides by 3 to find the cost of the watch: w = $112.
Now that we have the cost of the watch, we can substitute it back into the equation c = (4/7)w to find the cost of the clock: c = (4/7) x $112 = $64.
The total cost of both items is the sum of the cost of the clock and the cost of the watch: w + c = $112 + $64 = $176.
Therefore, the total cost of the watch and the clock together is $176.
A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers" children on the verge of reading. There are 19 children in Mr. Grimace's kindergarten class. Of these, 13 are pre-readers. Using the plus four confidence interval method, a 90% confidence interval for the difference in proportions of children in these classes that are pre-readers is â0.104 to 0.336.
Which of the following statements is correct?
A) This confidence interval is not reliable because the samples are so small.
B)This confidence interval is of no use because it contains 0, the value of no difference between classes.
C)This confidence interval is reasonable because the sample sizes are both at least 5.
D) This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.
Answer:
Answer : D
Step-by-step explanation:
A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers" children on the verge of reading. There are 19 children in Mr. Grimace's kindergarten class. Of these, 13 are pre-readers. Using the plus four confidence interval method, a 90% confidence interval for the difference in proportions of children in these classes that are pre-readers is â0.104 to 0.336.
Which of the following statements is correct?
A) This confidence interval is not reliable because the samples are so small.
B)This confidence interval is of no use because it contains 0, the value of no difference between classes.
C)This confidence interval is reasonable because the sample sizes are both at least 5.
D) This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.
The Answer is D - This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.
In this setup, all the students are already involved in the data. This is not a sample from a larger population, but probably, the population itself.
The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fairly reliable. It gives a positive reaction in 94.5% of the people who have that disease. However, it erroneously gives a positive reaction in 1.5% of the people who do not have the disease. Consider the null hypothesis "the individual does not have the disease" to answer the following questions.
a. What is the probability of a Type I error?
b. What is the probability of a Type II error?
Answer:
a) Type 1 Error: 1.5%
b) Type 2 Error: 5.5%
Step-by-step explanation:
Probability of positive reaction when infact the person has disease = 94.5%
This means, the probability of negative reaction when infact the person has disease = 100- 94.5% = 5.5%
Probability of positive reaction when the person does not have the disease = 1.5%
This means,
Probability of negative reaction when the person does not have disease = 100% - 1.5% = 98.5%
Our Null Hypothesis is:
"The individuals does not have the disease"
Part a) Probability of Type 1 Error:
Type 1 error is defined as: Rejecting the null hypothesis when infact it is true. Therefore, in this case the Type 1 error will be:
Saying that the individual have the disease(positive reaction) when infact the individual does not have the disease. This means giving a positive reaction when the person does not have the disease.
From the above data, we can see that the probability of this event is 1.5%. Therefore, the probability of Type 1 error is 1.5%
Part b) Probability of Type 2 Error:
Type 2 error is defined as: Accepting the null hypothesis when infact it is false. Therefore, in this case the Type 2 error will be:
Saying that the individual does not have the disease(negative reaction) when infact the individual have the disease.
From the above data we can see that the probability of this event is 5.5%. Therefore, the probability of Type 2 error is 5.5%
What is the volume, in cubic in, of a rectangular prism with a height of 5in, a width of 12in, and a length of 14in?
Answer:
840
Step-by-step explanation:
the volume of a rectangular prism is the base(width)height
n monitoring lead in the air after the explosion at the battery factory, it is found that the amounts of lead over a 6 day period had a standard error of 1.91. Find the margin of error that corresponds to a 95% confidence interval. (Round to 2 decimal places)
Answer:
434.98
Step-by-step explanation:
Which graph represents the function f(x) = 2/(x - 1) + 4x
What is the best estimate of the difference between 48 and 21
Answer: 27?
Step-by-step explanation:
Answer
The best estimate for 48 and 21 is 50 and 20. 50-20= 30 so 30 is ur answer
Step-by-step explanation:
A fruit stand sells 6 oranges for $3.00 and 3 grapefruit for $2.40. Sherry buys 10 oranges and 11 grapefruit. How much does Sherry spend on the fruit?
Answer:
Step-by-step explanation:
FIRST FOR ORANGES SHE BOUGHT 10 SO 10 TIMES 3 IS 30 AND THEN 11 TIMES 2.40 IS 26.40. 30 PLUS 26.40 IS 56.40 THATS YOUR AWNSER
help, will give brainliest
Answer:
10.0
Step-by-step explanation:
4.0+8.0=12.0-2.0=10.0
Which sentence can represent the inequality One-half x + three-fourths greater-than-or-equal-to 5 and one-fourth?
The sum of half of a number and three-fourths is at least five and one quarter.
Half the sum of a number and three-fourths is not more than five and one quarter.
The sum of half of a number and three-fourths is at most five and one quarter.
Half the sum of a number and three-fourths is not less than five and one quarter.
Answer:
The sum of half of a number and three-fourths is at least five and one quarter
Step-by-step explanation:
It's all about making sense of an English sentence.
"half the sum ..." is different from "the sum of half ..."
And ...
"at least" and "not less than" mean the same (≥)
"not more than" and "at most" mean the same (≤)
_____
Since all of the expressions are written out in words, it is a matter of matching the ideas expressed. That's a problem in reading comprehension, not math.
__
"One-half x + three-fourths [is] greater-than-or-equal-to 5 and one-fourth"
means the same as ...
"The sum of half of a number and three-fourths is at least five and one quarter"
Final answer:
The correct sentence for the inequality one-half x + three-fourths ≥ 5 and one-fourth is 'The sum of half of a number and three-fourths is at least five and one quarter'.
Explanation:
The correct representation of the inequality one-half x + three-fourths ≥ 5 and one-fourth (0.5x + 0.75 ≥ 5.25) in a sentence is The sum of half of a number and three-fourths is at least five and one quarter. This means that when you take half of a certain number (which we call x), add three-fourths to it, the result should be no less than five and one quarter. The other options either incorrectly suggest that the inequality is an equation, or misrepresent the inequality by suggesting the sum is 'at most' or not more or less than the given value, which changes the meaning of the original inequality.
1. $10 coupon on a $50.00 dinner
Answer: It would make the meal $40.00 and with tax it would be $42.80
Step-by-step explanation: 50 - 10 = 40
40 / 0.07 = 2.8
40 + 2.8 = 42.8
Answer:
Step-by-step explanation:
If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then m(b − a) ≤ b f(x) dx a ≤ M(b − a). Use this property to estimate the value of the integral. π/6 5 tan(2x) dx π/8
Answer:
The final integration in the given limits will be 89.876
Given a family with four children, find the probability of the event.
The oldest is a girl and the youngest is a boy, given that there is at least one boy and at least one girl.
Answer:
28.57% probability that the oldest is a girl and the youngest is a boy, given that there is at least one boy and at least one girl.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
These are all the possible outcomes: from youngest to oldest, b is boy and g is girl
b - b - b - g
b - b - g - b
b - b - g - g
b - g - b - b
b - g - b - g
b - g - g - b
b - g - g - g
g - b - b - b
g - b - b - g
g - b - g - b
g - b - g - g
g - g - b - b
g - g - b - g
g - g - g - b
The nuber of total outcomes is 14.
Desired outcomes:
Oldest(last) girl, youngest(first) boy
b - b - b - g
b - b - g - g
b - g - b - g
b - g - g - g
So 4 desired outcomes
Probability:
4/14 = 0.2857
28.57% probability that the oldest is a girl and the youngest is a boy, given that there is at least one boy and at least one girl.
Final answer:
The probability that a family with four children will have the oldest being a girl and the youngest being a boy, given that there is at least one boy and one girl, is 1/4.
Explanation:
To solve this probability question, we need to consider all possible combinations of children while adhering to the given conditions: the oldest child must be a girl (G), the youngest must be a boy (B), and there must be at least one boy and at least one girl in the family.
The possible genders for the four children can be represented as a sequence of G (girl) and B (boy) like this: G---B. There are two positions in the middle that can be either a boy or a girl. Since each position can be filled independently with either a boy or a girl, there are 2 options for each of the middle children, giving us 2 x 2 = 4 combinations: GBGB, GBBB, GGBB, GGBG.
To calculate the probability of any single one of these combinations occurring, we need to remember that the probability of giving birth to a boy or a girl is equal, which means each event (birth of a child) has a probability of 1/2. Thus, the probability of each combination is (1/2)^4 since there are four independent events (births). However, since we have 4 combinations that meet the criteria, we multiply this probability by 4. So, the probability is 4 * (1/2)^4 = 1/4.
Therefore, the probability that a family with four children will have the oldest being a girl and the youngest being a boy, given that there is at least one boy and at least one girl, is 1/4.
What is the median of the following data set?
{6, 3, 9, 1, 7}
3
6
8
9
I know the answer just seeing what you guys know and giving points:)
Answer:
The median of the following set of data is 9 since the question is implying, which is the center of the data distribution.
Step-by-step explanation:
The boundary of a lamina consists of the semicircles y = 1 − x2 and y = 16 − x2 together with the portions of the x-axis that join them. Find the center of mass of the lamina if the density at any point is inversely proportional to its distance from the origin.
The center of mass of the lamina is located at the point (0, (39/12) (1 / ln(4))).
To find the center of mass of the given lamina, we need to calculate the moment about the x-axis and the y-axis, and then divide them by the total mass of the lamina.
Given information:
- The boundary of the lamina consists of the semicircles y = sqrt(1 - x^2) and y = sqrt(16 - x^2), and the portions of the x-axis that join them.
- The density at any point is inversely proportional to its distance from the origin.
Find the total mass of the lamina.
Let the density function be [tex]\[ \rho(x, y) = \frac{k}{\sqrt{x^2 + y^2}} \][/tex], where k is a constant.
The total mass, M, is given by the double integral of the density function over the region of the lamina.
M = ∫∫ ρ(x, y) dA
To evaluate this integral, we need to express the lamina in polar coordinates.
The semicircles can be represented as:
0 ≤ r ≤ 1, 0 ≤ θ ≤ π
0 ≤ r ≤ 4, π ≤ θ ≤ 2π
The total mass can be calculated as:
[tex]\[ M = \int_{0}^{\pi} \int_{0}^{1} \frac{k}{r} r \, dr \, d\theta + \int_{\pi}^{2\pi} \int_{0}^{4} \frac{k}{r} r \, dr \, d\theta \]\[ M = k \left( \pi \ln(1) + 2\pi \ln(4) \right) \]\[ M = 2\pi k \ln(4) \][/tex]
Calculate the moment about the x-axis.
The moment about the x-axis, Mx, is given by:
[tex]\[ M_x = \int_{0}^{\pi} \int_{0}^{1} \frac{k}{r} r^2 \sin(\theta) \, dr \, d\theta + \int_{\pi}^{2\pi} \int_{0}^{4} \frac{k}{r} r^2 \sin(\theta) \, dr \, d\theta \]\[ M_x = k \left( \frac{\pi}{2} + \frac{32\pi}{3} \right) \]\[ M_x = \frac{39\pi}{6} k \][/tex]
Calculate the moment about the y-axis.
The moment about the y-axis, My, is given by:
My = ∫∫ x ρ(x, y) dA
In polar coordinates:
[tex]\[ M_y = \int_{0}^{\pi} \int_{0}^{1} \frac{k}{r} r^2 \cos(\theta) \, dr \, d\theta + \int_{\pi}^{2\pi} \int_{0}^{4} \frac{k}{r} r^2 \cos(\theta) \, dr \, d\theta \][/tex]
My = 0 (due to symmetry)
Find the coordinates of the center of mass.
The coordinates of the center of mass (x_cm, y_cm) are given by:
x_cm = My / M
y_cm = Mx / M
Substituting the values, we get:
x_cm = 0 / (2πk ln(4)) = 0
y_cm = (39π/6) k / (2πk ln(4)) = (39/12) (1 / ln(4))
Therefore, the center of mass of the lamina is located at the point (0, (39/12) (1 / ln(4))).
Complete question:
The boundary of a lamina consists of the semicircles y=sqrt(1 − x^2) and y= sqrt(16 − x^2) together with the portions of the x-axis that join them. Find the center of mass of the lamina if the density at any point is inversely proportional to its distance from the origin.
The center of mass of the lamina is at the origin (0, 0)
To find the center of mass of the lamina, we first need to find the mass and the moments about the x- and y-axes.
The mass M of the lamina can be calculated by integrating the density function over the lamina. Since the density at any point is inversely proportional to its distance from the origin, we can express the density[tex]\( \delta \) as \( \delta(x, y) = \frac{k}{\sqrt{x^2 + y^2}} \)[/tex], where k is a constant.
Let's denote [tex]\( \delta(x, y) \) as \( \frac{k}{\sqrt{x^2 + y^2}} \)[/tex]. Then the mass M is given by the double integral of [tex]\( \delta(x, y) \)[/tex] over the region R bounded by the semicircles and the portions of the x-axis:
[tex]\[ M = \iint_R \delta(x, y) \, dA \][/tex]
Where dA represents the differential area element.
To find the moments about the x- and y -axes, we calculate:
[tex]\[ M_x = \iint_R y \delta(x, y) \, dA \]\[ M_y = \iint_R x \delta(x, y) \, dA \][/tex]
Then, the coordinates [tex]\( (\bar{x}, \bar{y}) \)[/tex] of the center of mass are given by:
[tex]\[ \bar{x} = \frac{M_y}{M} \]\[ \bar{y} = \frac{M_x}{M} \][/tex]
Now, let's proceed to find [tex]\( M \), \( M_x \), and \( M_y \)[/tex]
First, let's express the density [tex]\( \delta(x, y) \)[/tex] in terms of k:
[tex]\[ \delta(x, y) = \frac{k}{\sqrt{x^2 + y^2}} \][/tex]
Now, we'll find the mass M by integrating [tex]\( \delta(x, y) \)[/tex] over the region R :
[tex]\[ M = \iint_R \frac{k}{\sqrt{x^2 + y^2}} \, dA \][/tex]
Since the region R is symmetric about the x-axis, we can integrate over the upper half and double the result:
[tex]\[ M = 2 \iint_{R_1} \frac{k}{\sqrt{x^2 + y^2}} \, dA \][/tex]
Now, we'll switch to polar coordinates [tex]\( (r, \theta) \)[/tex]. In polar coordinates, the region [tex]\( R_1 \)[/tex]is described by [tex]\( 0 \leq \theta \leq \pi \) and \( 1 \leq r \leq 4 \).[/tex]
So, the integral becomes:
[tex]\[ M = 2 \int_{0}^{\pi} \int_{1}^{4} \frac{k}{r} \cdot r \, dr \, d\theta \]\[ = 2k \int_{0}^{\pi} \int_{1}^{4} 1 \, dr \, d\theta \]\[ = 2k \int_{0}^{\pi} (4 - 1) \, d\theta \]\[ = 2k \int_{0}^{\pi} 3 \, d\theta \]\[ = 6k \pi \][/tex]
For [tex]\( M_x \)[/tex], we integrate [tex]\( x \delta(x, y) \)[/tex] over the region R :
[tex]\[ M_x = \iint_R x \cdot \frac{k}{\sqrt{x^2 + y^2}} \, dA \]\[ = 2 \int_{0}^{\pi} \int_{1}^{4} r \cos(\theta) \cdot \frac{k}{r} \cdot r \, dr \, d\theta \]\[ = 2k \int_{0}^{\pi} \int_{1}^{4} \cos(\theta) \cdot r \, dr \, d\theta \]\[ = 2k \int_{0}^{\pi} \left[ \frac{1}{2} r^2 \cos(\theta) \right]_{1}^{4} \, d\theta \][/tex]
[tex]\[ = 2k \int_{0}^{\pi} \left( 8 \cos(\theta) - \frac{1}{2} \cos(\theta) \right) \, d\theta \]\[ = 2k \int_{0}^{\pi} \left( \frac{15}{2} \cos(\theta) \right) \, d\theta \]\[ = 2k \left[ \frac{15}{2} \sin(\theta) \right]_{0}^{\pi} \]\[ = 2k \cdot 0 \]\[ = 0 \][/tex]
Now, for[tex]\( M_y \)[/tex], we integrate [tex]\( y \delta(x, y) \)[/tex]over the region R :
[tex]\[ M_y = \iint_R y \cdot \frac{k}{\sqrt{x^2 + y^2}} \, dA \\\[ = 2 \int_{0}^{\pi} \int_{1}^{4} r \sin(\theta) \cdot \frac{k}{r} \cdot r \, dr \, d\theta \\\[ = 2k \int_{0}^{\pi} \int_{1}^{4} \sin(\theta) \cdot r \, dr \, d\theta \\\[ = 2k \int_{0}^{\pi} \left[ \frac{1}{2} r^2 \sin(\theta) \right]_{1}^{4} \, d\theta \\[/tex]
[tex]\[ = 2k \int_{0}^{\pi} \left( 8 \sin(\theta) - \frac{1}{2} \sin(\theta) \right) \, d\theta \\\[ = 2k \int_{0}^{\pi} \left( \frac{15}{2} \sin(\theta) \right) \, d\theta \\\[ = 2k \left[ -\frac{15}{2} \cos(\theta) \right]_{0}^{\pi} \\\[ = 2k \cdot 0 \\\[ = 0 \][/tex]
Now, we have [tex]\( M = 6k \pi \), \( M_x = 0 \), and \( M_y = 0 \).[/tex]
Finally, we can find the coordinates of the center of mass [tex]\( (\bar{x}, \bar{y}) \):[/tex]
[tex]\[ \bar{x} = \frac{M_y}{M} = \frac{0}{6k \pi} = 0 \]\[ \bar{y} = \frac{M_x}{M} = \frac{0}{6k \pi} = 0 \][/tex]
So, the center of mass of the lamina is at the origin (0, 0) .
Please help
What is the slope of a line that is parallel to the line shown?
Answer:
m=2/3
Step-by-step explanation:
your answer would be A.
Drag each tile to the correct cell in the table.
High school students were surveyed about which math and
science topics they preferred. They were asked to choose
algebra or geometry, and biology or chemistry. The results are
shown in the frequency table below.
QUI 73%DC 100%
C
70%
30%
30%
100%
100%
28%
72%
Use this table to create a relative frequency table by row.
27%
Algebra
Geometry
Total
Algebra
Geometry
Total
Biology
67
92
Biology
Chemistry
46
66
Chemistry
Total
113
45
158
Total
Answer:
Step-by-step explanation:
Table(2) shows the relative frequency opted from the table(1).
What is the frequency?It is defined as the number of waves that crosses a fixed point in one second known as frequency. The unit of frequency is per second.
We have a table in which data has shown:
To find the relative frequency:
For the first cell:
[tex]=\frac{67}{92} \times100 \approx 73\%[/tex]
For the second cell:
= 100 - 73 ⇒ 27%
For the third cell:
[tex]\rm = \frac{46}{66} \times 100 \approx 70\%[/tex]
For the fourth cell:
= 100 - 70 = 30%
Thus, table(2) shows the relative frequency opted from table(1).
Learn more about the frequency here:
brainly.com/question/27063800
3•(7+10)=G+30 use the distributive property to solve
Answer: G=21
Step-by-step explanation:
Solve for G by simplifying both sides of the equation, then isolating the variable.
The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12. The probability that the average sales per customer from a sample of 36 customers, taken at random from this population, exceeds $78 is:
Answer:
0.0668
Step-by-step explanation:
Assuming the distribution is normally distributed with a mean of $75,
with a standard deviation of $12.
We can find the z-score of 78 using;
[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]
[tex]\implies z=\frac{78-75}{\frac{12}{36} } =1.5[/tex]
Using our normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332
This is the area corresponding to the probability that, the average is less or equal to 78.
Subtract from 1 to get the complement.
P(x>78)=1-0.9332=0.0668
The probability that the average sales per customer from a sample of 36 customers, taken at random from this population, exceeds $78 is 0.0668.
Calculation of the probability:Since The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12.
Here we need to find out the z score
= [tex]78-75\div 12\div 36[/tex]
= 1.5
Here we considered normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332
So, the average is less or equal to 78.
Now
Subtract from 1 to get the complement.
So,
P(x>78)=1-0.9332
=0.0668
Learn more about probability here: https://brainly.com/question/24613748
Suppose 40% of DC area adults have traveled outside of the United States. Nardole wants to know if his customers are atypical in this respect. He surveys 40 customers and finds 60% have traveled outside of the U.S. Is this result a statistically significant difference?
Answer:
We conclude that % of DC area adults who have traveled outside of the United States is different from 40%.
Step-by-step explanation:
We are given that 40% of DC area adults have traveled outside of the United States. Nardole wants to know if his customers are typical in this respect. He surveys 40 customers and finds 60% have traveled outside of the U.S.
We have to test is this result a statistically significant difference.
Let p = % of DC area adults who have traveled outside of the United States
SO, Null Hypothesis, [tex]H_0[/tex] : p = 40% {means that 40% of DC area adults have traveled outside of the United States}
Alternate Hypothesis, [tex]H_a[/tex] : p [tex]\neq[/tex] 40% {means that % of DC area adults who have traveled outside of the United States is different from 40%}
The test statistics that will be used here is One-sample z proportion statistics;
T.S. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = % of customers who have traveled outside of the United States
in a survey of 40 customers = 60%
n = sample of customers = 40
So, test statistics = [tex]\frac{0.60-0.40}{\sqrt{\frac{0.60(1-0.60)}{40} } }[/tex]
= 2.582
Since in the question we are not given with the significance level so we assume it to be 5%. So, at 0.05 level of significance, the z table gives critical value of 1.96 for two-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.
Therefore, we conclude that % of DC area adults who have traveled outside of the United States is different from 40%.
During a fundraiser, Ms. Dawson’s class raised $560, which is 25% more than Mr. Casey’s class raised. How much money did Mr. Casey's class raise?
Answer:
$420
Step-by-step explanation:
To work this out you would need to find the 25% decrease of 560. To do this you would first divide 25 by 100, which gives you 0.25. Then you would minus 0.25 from 1, which gives you 0.75. This is because when finding percentage decreases you would first have to convert it into a decimal. Then you would have to minus it from 1 , to make sure that it will be a 25% decrease not a 75% decrease. Then you would multiply 560 by 0.75, which gives you 420.
1) Divide 25 by 100.
[tex]25/100=0.25[/tex]
2) Minus 0.25 from 1.
[tex]1-0.25=0.75[/tex]
3) Multiply 560 by 0.75.
[tex]560*0.75=$420[/tex]