Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 kg ), who is initially at rest. after the collision, jack is traveling at 5.00 m/s in a direction 34.0∘ north of east. ignore friction. part a what is the direction of the jill's velocity after the collision?
Using the law of conservation of momentum, it is determined that after her collision with Jack, Jill will move in a direction that is south of east.
Explanation:This problem involves the principle of conservation of momentum. In this case, we have a two-body collision, where Mass1 (Jack, with mass 52kg and initial velocity 8m/s due east) collides with Mass2 (Jill, with mass 49.0kg and initially at rest). After the collision, Jack is traveling at a direction 34.0° north of east (let's call this direction east') with a speed of 5m/s. The initial momentum (Mass1 + Mass2) should be equal to the final momentum if we ignore the friction.
Before the collision, the total momentum was Momentum1 initial = Mass1 x Velocity1 initial = 52kg x 8m/s = 416 kg m/s, all in an eastward direction. Momentum2 initial = 0, as Jill was at rest.
After the collision, the final momentum of Jack becomes Momentum1 final = Mass1 x Velocity1 final = 52kg x 5m/s = 260 kg m/s, directed 34° north of east.
According to the law of conservation of momentum, the total initial momentum must equal the total final momentum. Hence, the final momentum of Jill will be Momentum2 final = Momentum1 initial - Momentum1 final = 156 kg m/s. This quantity only gives us the magnitude of the momentum, but we can calculate the direction based on Jack’s final direction. Given that momentum is a vector quantity, the principle of vector composition lets us infer that Jill’s final direction must be south of east to balance the north-of-east component of Jack's final momentum.
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What are three machines that depend on gravity to work
Justin, with a mass of 50 kg, is going down an 8.0-m-high water slide. he starts at rest, and his speed at the bottom is 12 m/s. part a how much thermal energy is created by friction during his descent? express your answer with the appropriate units.
The converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.
Explanation:
Given information:
Mass of justin [tex]=50 \; \text{kg}[/tex]
Height of water slide [tex]=8\;\text{m}[/tex]
Speed at the bottom [tex]= 12 \;\text{m/s}[/tex]
Now, the total mechanical energy is:
[tex]E_i=U=mgh\\E_i=50\times 9.81\times 8\\E_i=3924\;J[/tex]
And, the kinetic energy :
[tex]E_f=K=(1/2)mv^2\\E_f=0.50\times 50\times 12\\E_f=3600\;\text{J}[/tex]
So, the energy lost by the justin:
[tex]\Delta\;E=E_i-E_f\\\Delta\;E=3924-3600\\\Delta\;E=324J\\[/tex]
Hence, this converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.
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Unlike metals, nonmetals exhibit high ______ and fractures easily when subjected to stress.
A) absorbance
B) brittleness
C) ductility
D) malleability
Answer: Option (B) is the correct answer.
Explanation:
Non-metals are the substance which are electron deficient in nature.
Some properties of non-metals are as follows.
Non-metals are dull.They are brittle, that is, they tend to break easily.They have low melting and boiling point.They do not conduct heat and electricity.The are not malleable or ductile.Thus, we can conclude that unlike metals, nonmetals exhibit high brittleness and fractures easily when subjected to stress.
Larry designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown below. Light a candle. Place palm of the hand about 6 inches above the flame. Feel the heat from the burning candle on the palm of the hand. What does Larry's experiment most likely demonstrate?
Answer:
heat transfer by convection
Explanation:
yeah the heat just goes to your hand like "hello" now your hand is warm just don't TOUCH the fire because then it will go "HELLO" and it will be painful
Have a fantastic life and just I don't know... live life and go outside it's beautiful.
Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of _______ on blood flow.
Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of gravity on blood flow.
Veins must counteract the force of gravity on blood flow. Unlike arteries that carry blood away from the heart under high pressure, blood in veins is under much lower pressure after passing through capillaries.
The presence of one-way valves in veins, particularly in the limbs, is crucial to ensure the unidirectional flow of blood back toward the heart. These valves, along with the help of muscle contractions, prevent backflow and assist venous return to the heart, overcoming the effects of gravity and the reduced pressure in the venous system.
By the time blood reaches the venules and veins, the pressure initially exerted by heart contractions has greatly decreased. The veins are equipped with thin walls, large lumens, and valves that work together with muscle contractions to promote the return of blood to the heart.
This system compensates for the low blood pressure and the pull of gravity that would otherwise hinder the upward movement of blood from the extremities.
A 20.0 μf capacitor initially charged to 30.0 μc is discharged through a 1.80 kω resistor. how long does it take to reduce the capacitor's charge to 15.0 μc
The time it would take for a 20.0 μF capacitor initially charged to 30.0 μC to discharge through a 1.80 kΩ resistor and reduce the capacitor's charge to 15.0 μC can be calculated using the formula for exponential decay and the time constant of the RC circuit.
Explanation:The time it takes for a capacitor to discharge to half of its original charge can be found using the formula for exponential decay, based on the time constant (t) of the RC circuit, which is given by t = RC, where R is the resistance and C is the capacitance. The time constant represents the time it takes for the charge to decrease to about 36.8% of its initial value. Since we are looking for the time it takes to reduce to half of the initial charge, we must solve the equation 0.5 = e^(-t/RC), where e is the base of natural logarithms.
To solve for t, we can rearrange the equation to get -ln(0.5) = t/RC. Given that R = 1.80KΩ = 1.80x10^3 Ω and C = 20.0 µF = 20.0x10^-6 F, we can substitute these into the equation to find t. Therefore, the time it takes for a 20.0 μF capacitor initially charged to 30.0 µC to discharge through a 1.80 kΩ resistor to reduce the capacitor's charge to 15.0 μC can be calculated using these formulas.
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A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7 kg which is initially stationary. the blocks stick together and encounter a rough surface. the blocks eventually come to a stop after traveling a distance d = 1.85 m . what is the coefficient of kinetic friction on the rough surface? μk =
The calculation involves combining the masses after collision, calculating the final velocity using the law of conservation of momentum and then finding the frictional work done. Using the work-energy theorem, we can solve for the coefficient of kinetic friction.
Explanation:The question is asking to find the coefficient of kinetic friction on the rough surface where two blocks m1 and m2 have collided and eventually come to a stop after traveling a certain distance. We first need to combine the mass of both blocks as they stick together and this results in a total mass (m1 + m2 = 3.5 kg + 1.7 kg = 5.2 kg). After collision, we can use the law of conservation of momentum to calculate the final velocity when both blocks stick together (m1*v1 + m2*v2 = (m1 + m2) * v_final).
Substituting known values (3.5 kg * 6.3 m/s + 1.7 kg * 0 m/s = 5.2 kg * v_final), we get v_final = 4.425 m/s.
Now, to find the coefficient of kinetic friction, we will use the equation of work-energy theorem where Workdone by friction = Change in kinetic energy. The work done by frictional force is equal to the force of friction multiplied by the distance, and force of friction equals the coefficient of kinetic friction times the normal force (which is mass times gravity in this case).
Thus, the equation would be: μk * m1 * g * d = ½ * m1 * v1^2 (since the final velocity is zero). Substituting the known values into this equation, we can solve to find the coefficient μk.
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An agitated llama may spit to assert dominance, or to ward off threats. llamas can spit a considerable distance, and people handling them need to keep this in mind. part a if the spittle from a llama is launched from an initial height of 1.8 m with a speed of 5.5 m/s, and at an angle of 13 ?? above horizontal, how far will it travel horizontally?
The horizontal distance traveled by the spittle is 2.62 m.
The given parameters;
height of projection, h = 1.8 minitial velocity, v = 5.5 m/sangle of projection, Ф = 13°The time of motion is calculated as;
[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\1.8 = (5.5\times sin(13))t + (0.5\times 9.8)t^2\\\\1.8 = 1.24t + 4.9t^2\\\\4.9t^2 + 1.24t - 1.8= 0\\\\solve \ the \ quadratic \ equation\ using \ formula \ method;\\\\a = 4.9, \ b = 1.24, \ c = -1.8\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-1.24 \ \ +/- \ \ \sqrt{(1.24)^2 - 4(4.9\times -1.8)} }{2(4.9)} \\\\t = 0.49 \ s[/tex]
The horizontal distance traveled by the spittle is calculated as;
[tex]X = v_0_x \times t\\\\X = 5.5\times cos (13) \times 0.49\\\\X = 2.62 \ m[/tex]
Thus, the horizontal distance traveled by the spittle is 2.62 m.
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Suppose you charge a 1.0 f capacitor with two 1.5 volt batteries. how much charge was on each plate?
If you charge a 1.0 f capacitor with two 1.5 volt batteries, the amount of charge on each of the plates is 3colombs
The formula for calculating the charge on a capacitor is expressed as:
[tex]Q = C \triangle v[/tex]
C is the capacitance of the capacitor in farads
Δv is the change in the potential difference
Given the following parameters
C = 1.0F
For a two 1.5V batteries, v = 2(1.5) = 3V
Substitute the given parameters into the formula as shown:
[tex]Q = 1.0 \times 2(1.5)\\Q=1 \times 3.0\\Q =3Coulumbs[/tex]
Hence the amount of charge on each of the plates is 3colombs.
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An experiment that produces waves on a string is analyzed, and the experimental value for the wave speed is found to be 66 m/s. If the accepted value for the wave speed is 63 m/s, what is the percent error? 0.045% 0.048% 4.5% 4.8%
4.8 is the correct answer
Answer:
4.8%
Explanation:
percentage error can be calculated as the difference between the theoretical and experimental value divided by the experimental value expressed in percentage.
The percentage error can be computed mathematically as
(accepted value - experimental value)/accepted value × 100
accepted value = 63 m/s
experimental value = 66 m/s
difference = 63 - 66 = -3 m/s
use the absolute value = 3 m/s
percentage error = (accepted value - experimental value)/accepted value × 100
percentage error = 3/63 × 100
percentage error = 300/63
percentage error = 4.76%
percentage error = 4.8%
Which stage of star development comes right after the long stable phase in the life cycle? A. Nova B. Red giant C. Red dwarf D. White dwarf
You apply a potential difference of 5.70 v between the ends of a wire that is 2.90 m in length and 0.654 mm in radius. the resulting current through the wire is 17.6
a. what is the resistivity of the wire?
A soccer ball is kicked with an initial speed of 23 m/s at an angle of 21° with respect to the horizontal. (a) find the maximum height reached by the ball. m (b) find the speed of the ball when it is at the highest point on its trajectory. m/s (c) where does the ball land
a. the maximum height reached by the ball is approximately 3.46 meters.
b. the speed of the ball when it is at the highest point is approximately 21.19 meters per second.
c. the ball lands 14.83 meters away from the launch point in the same direction as its horizontal component of velocity.
a)
Vertical component = Initial speed * sin(launch angle)
Vertical component = 23 m/s * sin(21°) = 8.23 m/s
The maximum height reached by the ball can be calculated using the equation:
Maximum height = (Vertical component²) / (2 * gravity)
Gravity = 9.81 m/s².
Maximum height = (8.23 m/s)² / (2 * 9.81 m/s²)
= 3.46 m
b)
At the highest point, the vertical component of velocity becomes zero because the ball stops momentarily before falling back down.
Horizontal component = Initial speed * cos(launch angle)
Horizontal component = 23 m/s * cos(21°) = 21.19 m/s
c)
Time to fall = (2 * Maximum height) / gravity
Time to fall = (2 * 3.46 m) / 9.81 m/s² = 0.70 s
Horizontal distance = Horizontal component * Time to fall
Horizontal distance = 21.19 m/s * 0.70 s = 14.83 m
A certain shade of blue has a frequency of 7.15 × 1014 hz. what is the energy of exactly one photon of this light?
An unmanned spacecraft leaves for Venus. Which statements about the spacecrafts journey are true?
A)The weight of the spacecraft keeps changing.
B)The mass of the spacecraft keeps changing
C)The weight of the spacecraft remains the same
D) The mass of the spacecraft remains the same
E)The gravotational pull on the spacecraft remains the same
Hint: There is more than one answer
Answer:
A)The weight of the spacecraft keeps changing.
D) The mass of the spacecraft remains the same
Explanation:
As we know that the acceleration due to gravity depends on the height from the surface
As we know that the force due to gravity on objects near the surface is given as
[tex]F = \frac{Gm_1m_2}{(R+h)^2}[/tex]
here we know that
R = radius of planet
h = height from the surface of planet
So as we move away at more height the gravitational attraction force will keep on decreasing.
This gravitational attraction force of planet is also known as weight so we can say that the weight of the object will keep on changing while object move away.
Also we know that mass of object is quantity of the matter which always remains constant.
Which statement explains why the moon's gravity is able to create high and low tides
Two charged parallel plates are 0.25 meters away from each other. The field between the plates is 600 . What is the electric potential difference?
Answer:
ΔV = 150 V
Explanation:
Brass is an alloy of copper and zinc the two metals are melted mixed and then solidified how would you best classify brass
Brass can be classified as [tex]\boxed{{\text{a}}{\text{. homogenous mixture and a solid solution}}}[/tex].
Further explanation:
Alloy:
An alloy is defined as combination of metals or a combination of one or more metals with non-metals. Alloys have a large range of applications, ranging from surgical tools, aerospace industry to automobile construction. Steel, solder, brass, pewter, bronze, and amalgams are some examples of alloys. Alloys can be either solid solution or a mixture of metallic phases.
Mixture:
The material that is made up of two or more substances is called a mixture. It has no fixed formula, and its composition is also varied. All the individual constituents retain their properties after the formation of the mixture.
Types of mixtures:
1. Homogeneous mixtures
Homogeneous is a Latin word that means the same. These mixtures have a uniform composition throughout. Air, orange juice, and blood are the examples of a homogenous mixture.
2. Heterogeneous mixtures
Heterogeneous is a Latin word that means different. These mixtures that have non-uniform composition throughout. Concrete, soda, and chocolate chip cookies are the examples of a heterogeneous mixture.
Characteristics of mixtures:
1. It has a variable composition and has no formula.
2. Mixtures are not formed by any chemical reactions.
3. Mixtures can be either homogeneous or heterogeneous.
4. The constituents of the mixtures can be separated by physical methods such as filtration, heating, drying, distillation, crystallization.
5. The properties of the individual particles of the mixture are retained even after the formation of mixtures.
Copper and zinc are the two metals that are first melted, mixed and then solidified to form brass. Their composition is the same throughout the whole part of brass. So brass is an example of homogeneous mixture. It is also known as solid solution where zinc acts as solute and copper is a solvent.
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Mixture
Keywords: mixture, characteristics, formula, composition, properties, chemical reactions, filtration, distillation, heating, crystallization, homogeneous, heterogeneous, brass, alloy, metals, non-metals, aerospace industry, automobile construction, surgical tools, solid solution, zinc and copper.
On the decibel scale, a “quiet whisper 1 meter away” is about ____________ decibels, where a “jackhammer 3 meters away” is _____________ decibels. a) 20, 100 b) 10, 100 c) 10‐15, 90
One side of the moon always faces Earth because the time it takes the moon to spin on its axis is blank the time it takes the moon to travel around Earth.
Answer: One side of the moon always faces Earth because the time it takes the moon to spin on its axis is "the same as" the time it takes the moon to travel around Earth.
500 ml of four different liquids are heated to 50oC. According to the specific heat data, which liquid will cool to 35oC in the shortest amount of time?
Answer:C) gasoline
Explanation:
Specific heat is the measure of the heat energy required to increase or decrease the temperature of a substance by a certain temperature interval. Gasoline has the lowest specific heat; that means it takes less energy to lower or raise the temperature of gasoline compared to the other three liquids.
two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n. what is the net force on the rope and what is its direction?
Explanation:
It is given that, two teams are playing tug of war.
Force applied by Team A, [tex]F_A=450\ N[/tex]
Force applied by Team B, [tex]F_B=415\ N[/tex]
We need to find the net force acting on the rope. It is equal to :
[tex]F_{net}=F_A-F_B[/tex]
[tex]F_{net}=450-415[/tex]
[tex]F_{net}=35\ N[/tex]
So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.
Answer:
20 N to the left
Explanation:
A bag of groceries has a weight of 44 newtons. Find its approximate weight in kilograms.
Final answer:
To convert the weight of a bag of groceries from newtons to kilograms, divide the weight in newtons (44 N) by the acceleration due to gravity (9.8 m/s²), which gives an approximate mass of 4.49 kg.
Explanation:
To find the approximate weight of a bag of groceries in kilograms when given a weight of 44 newtons, we need to use the relation between mass, weight, and gravitational acceleration. Weight is the force due to gravity, and it's measured in newtons (N). To convert newtons to kilograms, we divide the weight by the acceleration due to gravity, which is approximately 9.8 m/s². Therefore:
Weight in kilograms = Weight in newtons ÷ gravitational acceleration
Weight in kilograms = 44 N ÷ 9.8 m/s²
Weight in kilograms ≈ 4.49 kg
This is a physics problem involving the conversion of units between the weight (force) and mass, and it requires a basic understanding of the relationship between these concepts. The result, 4.49 kg, represents the mass of the groceries that causes a weight of 44 N.
The diagram below shows rock is affected when water enters cracks in rock,freezes and becomes ice
The question explores the concept of physical weathering known as frost wedging, which occurs when water freezes in rock cracks, causing the rocks to break apart. This process relates to the property of water expanding upon freezing, which explains ice's lower density and its effects on the environment and human-made structures.
Explanation:The student's question pertains to the process by which water enters cracks in rocks, freezes, and expands into ice, which is known as frost wedging or frost weathering. This process is a type of physical weathering that occurs in cold climates when temperatures fluctuate above and below 0°C (32°F). As water freezes, it expands by approximately 9%, exerting significant pressure on the surrounding rock, eventually causing it to break apart. The phenomenon of water expanding upon freezing is due to the unique structure of ice.
Understanding ice density is significant for explaining why ice floats and how it affects aquatic ecosystems and human constructions. When water transitions to ice, its molecules form a crystalline structure that is less dense than liquid water, causing ice to float. This property of ice provides crucial insulating effects in natural bodies of water, allowing life to persist beneath the ice layer during winter. Furthermore, the expansion of water when it freezes is why we use antifreeze in engines and why pipes can burst if not properly insulated.
Which of the following statements is true of taking responsibility?
A. If you correct a mistake quickly, no one else needs to know about it.
B. You can't expect people to respect you if you make too many mistakes.
C. Blaming another for your mistake is sensible when your accusation can be proven.
D. You're unlikely to get control of your life when you blame others for your mistakes.
Which of the following correctly describes the first animals that appeared?
A.) these were large creatures, similar to dinosaurs
B.) these were bony creatures that lived only in wet environments
C.) these were soft and boneless creatures
D.) these were large creatures that lived only in dry environments
Which of these is the best definition of a fuel cell?
(b) if we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? explain your reasoning.
A typical cell membrane in an animal maintains a potential difference across the membrane of ΔV = 70 mV and the membrane has a thickness of about 8 nm. The capacitance of the membrane is about 1 microFarad per square cm.
(B) If we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? Explain your reasoning.
Now, notice that:
[tex]Q=C\Delta V\\
\Delta V=E.L[/tex]
Where L is the thickness of the membrane.
We then can get the electric field by just using:
[tex]E=\frac{\Delta V}{L}=\frac{70\times10^{-3}}{8\times10^{-9}}=8.75\times10^{6}N.C^{-1}[/tex]
Now using the charge expression and plugging the the expression for [tex]\Delta V[/tex] into it and then solving for [tex]E[/tex] we get:
[tex]E=\frac{Q}{CL}[/tex]
Now let's multiply both denominator and numerator by [tex]\frac{1}{A}[/tex] this yields:
[tex]E=\frac{\sigma}{C_{\sigma}L}[/tex]
Where
[tex]\sigma=\frac{Q}{A}\\ C_{\sigma}=\frac{C}{A}[/tex]
Notice that the value in the wording of the problem is no actually the capacitance, but the capacitance per area [tex]C_{\sigma}[/tex], also [tex]\sigma[/tex] is the charge density.
Let's transform [tex]C_{\sigma}[/tex] to [tex]\frac{farad}{m^2}[/tex]:
[tex]\frac{1\mu F}{cm^2}=\frac{1\times10^{-2}F}{m^2}[/tex]
Solving for [tex]\sigma[/tex] we get:
[tex]sigma=E.C_{\sigma}.L=7\times10^{-4}\frac{Coulomb}{m^2}=7\times10^{-8}\frac{Coulomb}{cm^2}[/tex]
A 0.30-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. the well has a depth of 5.1 m. (a) relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stoneâearth system before the stone is released? j (b) relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stoneâearth system when it reaches the bottom of the well? j (c) what is the change in gravitational potential energy of the system from release to reaching the bottom of the well? j