Give 3 examples, from the lab, where potential energy was converted to kinetic energy.

true :) i took a science test and that question is correct

Answer : It experience the acceleration is, [tex]7.5m/s^2[/tex]

Explanation :

By the 1st equation of motion,

[tex]v=u+at[/tex] ...........(1)

where,

v = final velocity = 85 m/s

u = initial velocity  = 23 m/s

t = time = 8.3 s

a = acceleration = ?

Now put all the given values in the above equation 1, we get:

[tex]85m/s=23m/s+a\times (8.3s)[/tex]

[tex]a=7.5m/s^2[/tex]

Thus, it experience the acceleration is, [tex]7.5m/s^2[/tex]

the amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 10.2 sound C is louder than sound B. hope i helped!

(sorry if wrong)

here we can use energy conservation

like initial kinetic + potential energy is always conserved and it will be same at all points

so we can say

[tex]KE_i + PE_i = KE_f + PE_f[/tex]

[tex]\frac{1}{2}mv_i^2 + mgh_1 = \frac{1}{2}mv_f^2 + mgh_2[/tex]

now we can plug in all the given values in it

[tex]v_i = 0[/tex]

[tex]h_1 = 443 m[/tex]

[tex]h_2 = 221 m[/tex]

[tex]\frac{1}{2}m*0 + m*9.8*443 = \frac{1}{2} m*v_f^2 + m*9.8*221[/tex]

now divide whole equation by mass "m"

[tex]9.8*443 = \frac{1}{2} v_f^2 + 9.8*221[/tex]

[tex]2175.6 = \frac{1}{2}v_f^2[/tex]

[tex]v_f = 65.96 m/s[/tex]

so final speed will be 65.96 m/s

Tha conceptual model depends upon the process flow.

The conceptual model is actually used in the system to stimulate, understand or explore the subject for the better understanding of people. As it consists of different constituents as validation, implementation, accreditation etc. can be affected by the process flow. The process flow has actually consisted of the management, monitoring of objects for specific subject and scales under these monitoring or management are proceedings. As these scales of process flow effects, the objectives of the task impacts.

Answer:

a) Acceleration, a = -u/9, where u is the initial velocity

b) Acceleration = 0.741 m/s², Initial velocity = 6.67 m/s

Explanation:

 We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

a)  We have v = 0 m/s, t = 9 s

 So,    0 = u + a x 9

      Acceleration, a = -u/9, where u is the initial velocity

b) We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 s = 30 m , u = -9a, t =9 s

 So,  [tex]30= -9a*9+\frac{1}{2} *a*9^2\\ \\ 30=-40.5a\\ \\ a=-0.741m/s^2[/tex]

u = -9a = 6.67 m/s

So acceleration = 0.741 m/s², Initial velocity = 6.67 m/s

Final answer:

The answer explains how to calculate the acceleration of the puck given the distance it traveled and the time taken. It further details how to find the initial velocity of the puck using the acceleration obtained earlier.

Explanation:

A. To determine the acceleration of the puck, we can use the equation:

a = 2x / t^2

Substitute the values given: x = 30m and t = 9s.

b. To find the initial velocity of the puck, we first calculate the acceleration using the formula a = Δv / t, where Δv = final velocity - initial velocity.

Then, knowing the acceleration from part (a), we can calculate the initial velocity using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

Answer:

option a

Explanation:

Answer:

A ( 11; the number of protons

Explanation:

if the atomic mass is 11 that means there are also 11 protons

Final answer:

The potential energy gained by driving the car from sea level to Nu’uanu Pali lookout is approximately 3,589,260 joules.

Explanation:

To calculate the potential energy gained by driving your car from sea level up to the Nu’uanu Pali lookout, we can use the formula: PE = mgh, where m is the mass of the car, g is the acceleration due to gravity, and h is the change in height. In this case, the mass is 1000 kg, g is approximately 9.81 m/s², and h is 366 m. Plugging in the values, we get:

PE = 1000 kg * 9.81 m/s² * 366 m = 3,589,260 joules

So, driving your car up to the Nu’uanu Pali lookout increases its potential energy by approximately 3,589,260 joules.

The answer is kinetic friction.

Answer:

Kinetic friction

Explanation:

When body is in rest then static friction force will act in opposite direction .Ans this force will given as follows

[tex]fr_s=\mu _{st}mg[/tex]

[tex]\mu _{st}\ is\ the\ coefficient\ of\ static\ friction[/tex]

When body is in motion then kinetic friction force will act in opposite direction .Ans this force will given as follows

[tex]fr_k=\mu _{k}mg[/tex]

[tex]\mu _{k}\ is\ the\ coefficient\ of\ kinetic\ friction[/tex]

When body rolls then rolling friction will act.

When body will slid then sliding friction will act.

Final answer:

Gravity according to Newton is a pulling force between objects with mass, while Einstein's general relativity posits gravity as the warping of spacetime by mass. While Newton's theory works well for less extreme situations, Einstein's accommodates oddities in strong gravitational fields and explains anomalies like Mercury's orbit that Newton's law could not.

Explanation:

Understanding Gravity: From Newton to Einstein

In his universal law of gravitation, Sir Isaac Newton described gravity as a force that pulls any two objects with mass toward one another, proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This concept allowed Newton to explain both the motion of falling objects on Earth and the celestial movements of planets and moons. Objects are drawn towards each other along a line connecting their centers, similar to an invisible 'tug of war.'

Albert Einstein's theory of general relativity, on the other hand, provided a revolutionary understanding of gravity. Instead of viewing gravity as a force, Einstein described it as the warping of spacetime by mass. Massive objects distort the fabric of spacetime, creating what we perceive as gravitational attraction, akin to how a heavy object placed on a stretched-out sheet would cause it to curve and objects around it to roll towards the impression.

Newton's theory operates exceptionally well for everyday phenomena and has been crucial for developments like space travel. However, Einstein's general relativity illuminates peculiar behaviors in strong gravitational fields, such as around black holes, and accounted for the precession of Mercury's orbit, a detail classical physics could not explain. While Einstein's model modifies Newton's, both theories address the observed accelerations of massive bodies influenced by gravity.

It is essential to note that while Einstein's theory adjusts Newton's laws, it does not render them obsolete. Einstein's predictions coincide with Newton's in situations of weaker gravitational fields - a testament to the accuracy of Newton's calculations in familiar conditions. This congruence illustrates Einstein's respect for the robustness of Newtonian physics while extending our understanding to the cosmos's most extreme environments.

The reciprocal of resistance or measure of a devices ability to conduct is called Conductance. Conductance is the ability of material that allows electricity to pass through it. The unit of conductance is seimens. It can also be represented by "mho" , inverse of "ohm" which is unit of resistance. Best example of conductive metals are silver and copper. Materials that allows conductivity are called Conductor. Material that partially allows conductivity are called Semi-conductor. Material that does not allow conductivity are called Insulator.

Conductance can also be defined as ability to flow. The term conductance is not only used for electrical conductivity, but it is also used for thermal conductivity and fluid conductivity.

Answer:

conductance

Explanation:

Answer:

you’re correct i think

no. energy is not created or destroyed, just transformed.

a hot light source is less efficient than a cold one ... heat is not light ...

The term 'inefficient' in energy transformations does not mean that energy is destroyed. Instead, it refers to the second law of thermodynamics, where some energy is always lost in an unusable form, typically as heat, during the transformation process.

When scientists state that energy transformations are inefficient, they don't mean that energy is destroyed. Rather, they're referring to the fact that in every energy transfer or transformation, a portion of that energy is lost in a form that is unusable, most often as heat energy. This concept is based on the second law of thermodynamics, which states that no energy transfer is entirely efficient.

In an isolated system, according to the first law of thermodynamics, energy cannot be created or destroyed but only converted from one form to another. However, not all forms of energy are useful in doing work. During these energy transformations, some energy inevitably gets 'degraded' into a less useful form, such as waste heat.

For instance, when an airplane flies through the air, some of the plane's energy is lost as heat due to friction with the surrounding air. Similarly, during cellular metabolic reactions, some energy is lost as heat. This is beneficial for warm-blooded animals like us, as it helps in maintaining our body temperature.

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I'm pretty sure you can find it out by using a speed monitor and compass or just observing it

if there any answer choices tell me.

Answer:

vertical distance, s = 0.16 meters

Explanation:

It is given that,

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.

Dashboard is placed at a distance of 2.7 meters.

Calculating time from velocity and distance i.e. [tex]t=\dfrac{d}{s}=\dfrac{2.7}{15}\ s=0.18\ s[/tex]

Using second equation of motion for finding vertical distance :

[tex]s=ut+0.5gt^2[/tex]

Here, u = 0 (for vertical velocity )

[tex]s=0.5gt^2[/tex]  

[tex]s=0.5\times 10\times (0.18)^2[/tex]        

s = 0.162 meters

or s = 0.16 meters

Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.

Ball is thrown at an angle of 20 degree with velocity 18 m/s

so first we will find the two components of the velocity

[tex]v_x = 18 cos20[/tex]

[tex]v_x = 16.91 m/s[/tex]

similarly for other component

[tex]v_y = 18 sin20[/tex]

[tex]v_y = 6.16 m/s[/tex]

now the ball will cover horizontal distance of 30 m till it reach to other player

so here we can use the formula of time

[tex]x = v_x * t[/tex]

[tex]30 = 16.91 * t[/tex]

[tex]t = \frac{30}{16.91}[/tex]

[tex]t = 1.77 s[/tex]

so it will take 1.77 s to reach the other player

Answer:

1.77 on ed2020

Explanation:

Answer: The work OUTPUT of a simple machine can never exceed the work INPUT because FRICTION uses some of the work.

Explanation:

This concept is related to ideal machines and efficiency.

Only ideal machines can convert all the work input into useful work (work ouput).

The efficiency is a concept that tells you the proportion of input work that is transformed into output work.

         Efficiency = (output work / input work) × 100

Ideal machines, those where friction does not exist, have a 100% efficiency, and so ideal machines convert all the input work into useful output work.

Real machines have a efficiency less than 100%. Friction lowers the efficiency and the work outpu is less than the work input, because friction uses work which is converted, mostly, into heat energy or sound energy.

1) This method allows people to do orderly research.

2) This method allows people to make new Discoveries.

hope this helps you!

Answer: This method allows people to conduct orderly research.

This method allows people to make new discoveries.

Explanation:

Scientific method is a detailed experimental protocol is required to be followed in order to prove a reason of cause of natural phenomena occurring in nature.

By utilizing scientific methods people conduct research. If a proper methodology is followed till the end of the experimentation process it will result in new outcomes different from the preposed observations and results. This will lead to new innovations.

As a student, to reduce waste, you should recycle materials like old books, start a compost program at school, buy used items, and properly recycle electronics. Avoid actions that are against the reduce, reuse, and recycle principles like disposing reusable products, replacing items prematurely, or trashing computer equipment.

To reduce the amount of waste you make as a student, focus on actions that adhere to the Reduce, Reuse, and Recycle principles. Firstly, recycle your old books, newspapers, and magazines instead of throwing them away. Starting a compost program at school will help reduce food waste by turning it into nutrient-rich soil instead of contributing to landfill mass.

Other actions include buying used or fewer items, maintaining and repairing products to extend their lifespan, and borrowing or sharing infrequently used items. Always avoid disposing of products that can still be reused, and do not replace items before they wear out. Moreover, never throw away computer equipment; recycle it properly as electronic waste can be hazardous to the environment.

Recycling efforts in your community are important; participate by separating recyclables like aluminum, plastics, glass, and paper. Encourage and join initiatives at school to promote recycling and conservation.

When Amelia apply brakes the car will start reducing its speed and then finally stop

So here as per Newton's First law we can say all object continue its state of motion until and unless some unbalanced external force act upon its.

This property is due to inertia of the object which is the property of mass. Here inertia is the property which resist the change in state of motion of an object.

If brakes are applied and an object stops after some time (let say t = 5 s) and on applying brakes other object stop in other time (let say t = 10 s) then if other object took longer time to stop then it means its inertia will be more.

So its all depends on inertia of object that how much time it will take to stop after applying brakes

So correct answer is

B.  inertia

Answer:

B

Explanation:

Inertia

Here's the formula to use:

D = 1/2 A T²

Distance = (1/2) (Acceleration) (time)²

Now let's use it:

Distance = (1/2) (9.8 m/s² for Earth gravity) (1.2 seconds)²

Distance = (4.9 m/s²) (1.44 sec²)

Distance = (4.9 x 1.44) (m-s² / s²)

Distance = 7.06 meters

The star is moving at about [tex]\(906.6 \, \text{km/s}\)[/tex] away from the Earth

Why is this correct?

The calcium H line typically appears at a wavelength of 396.9 nm. However, in the spectrum of a particular star, it registers at 398.1 nm. To determine the star's velocity, we'll employ the Doppler effect formula for wavelength shift:

[tex]\[\frac{\Delta \lambda}{\lambda_0} = \frac{v}{c}\][/tex]

Where:

[tex]\(\Delta \lambda\)[/tex] represents the change in wavelength.

[tex]\(\lambda_0\)[/tex] denotes the rest wavelength (396.9 nm for the calcium H line).

[tex]\(v\)[/tex] stands for the star's velocity.

[tex]\(c\)[/tex] is the speed of light.

The calculation involves finding [tex]\(v\)[/tex], the star's velocity. Rearranging the formula yields:

[tex]\[v = \frac{\Delta \lambda}{λ_0} \times c\][/tex]

Starting with the difference in wavelengths:

[tex]\[\Delta \lambda = \lambda - λ_0 = 398.1 \, \text{nm} - 396.9 \, \text{nm} = 1.2 \, \text{nm}\][/tex]

Substituting the values into the equation:

[tex]\[v = \frac{1.2 \, \text{nm}}{396.9 \, \text{nm}} \times 299,792 \, \text{km/s}\][/tex]

This computation yields:

[tex]\[v \approx 0.003021 \times 299,792 \approx 906.4 \, \text{km/s}\][/tex]

Therefore, the star is moving at about [tex]\(906.6 \, \text{km/s}\)[/tex] away from the Earth.

Complete question:

The h line in calcium is normally at 396.9 nm. however, in a star's spectrum, it is measured at 398.1nm. how fast is the star moving and is it moving towards the earth or away from the earth?

Answer:

[tex]T_2 = 1.40 hours[/tex]

Explanation:

As per kepler's law of time period we know that

square of time period is proportional to the cube of the distance

so here we can say

[tex]\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}[/tex]

so we know that

for moon

[tex]T_1 = 27.4 days[/tex]

[tex]r_1 = 384,400 km[/tex]

[tex]r_2 = 6370 km[/tex]

now from above formula we have

[tex]\frac{27.4^2}{T_2^2} = \frac{384,400^3}{6370^3}[/tex]

[tex]T_2 = 0.058 days[/tex]

[tex]T_2 = 1.40 hours[/tex]

Using Kepler's third law and the period of the Moon, we find that an artificial satellite very close to Earth has a period of approximately 1.41 hours. This involves comparing the orbital radii and periods using the proportional relationship given by Kepler's law. Substituting values and simplifying yields the final period.

To determine the period of an artificial satellite orbiting very near the Earth’s surface using Kepler’s laws, we will use Kepler's third law, which states that the square of the orbital period (T) is proportional to the cube of the average orbital radius (r). Given the following:

Now, add the radius of the Earth to get the orbital radius of the satellite, r2 = rE + 0 = 6.38 × 106 m. According to Kepler’s third law ([tex]T_2[/tex] ∝ [tex]r_3[/tex]), we have:

Substitute the known values:

Simplifying the right side:

Taking the square root of both sides to solve for [tex]T_2[/tex] :

Converting days to hours (1 day = 24 hours):

Therefore, the period of an artificial satellite orbiting very near the Earth’s surface is approximately 1.41 hours.

Answer: Based on the weather station symbols shown below, what is the most likely location of the low pressure system?

A.Just West of City A.

Answer:

The acceleration of the rabbit is 2[tex]\frac{m}{s^{2}}[/tex].

Explanation:

A rabbit starts from a resting position and moves at 6 m/s after 3 seconds.

Applying first equation of motion we get,

v = u + a t

v = final velocity = 6 m/s

u = initial velocity = 0 m/s

t = time = 3 s

a = acceleration

6 = 0 + a (3)

a = 2[tex]\frac{m}{s^{2}}[/tex]

The acceleration of the rabbit is 2[tex]\frac{m}{s^{2}}[/tex].

Answer:

Applying first equation of motion we get,

v = u + a t

v = final velocity = 6 m/s

u = initial velocity = 0 m/s

t = time = 3 s

a = acceleration

6 = 0 + a (3)

a = 2

The acceleration of the rabbit is 2.

Explanation:

Apply the first equation of motion

The answer to this question is conductor.

The substance contains different physical properties are the transfer of energy, conductivity, density, melting and freezing etc. Any object that can transfer the energy in the form of heat or electrical conductivity can be called as conductors. It is the property of conductors to transfer the energy of heat from one side to another side of the object. The conductors have the follows the rule of the conduction process to perform this specific function.

So, the right answer to this question is the conductor.

Answer:imagine Bohr coming up to you and saying i have 2 atoms; it sticks together and becomes a compound.

Explanation:

materials, metals, gold

Final answer:

The movement of heat or electricity occurs through materials called conductors, with metals like copper and silver being excellent examples due to their high number of free electrons that facilitate this transfer.

Explanation:

The movement of heat or electricity through materials. Metals are good conductors, particularly copper and silver.

Good electrical conductors are often good heat conductors, too. This is because large numbers of free electrons can carry electrical current and can transport thermal energy. Materials like copper, aluminum, gold, and silver are excellent conductors of both electricity and heat due to their high number of free electrons, which allow them to transfer thermal energy efficiently. On the other hand, insulators such as wood, plastic, and rubber are poor heat conductors because they lack these free electrons.

Understanding the conduction of electricity and heat is fundamental in industries and applications that require efficient energy transfer, including electronic components and cooking utensils. Metals are frequently employed in these applications; for example, metals like copper are used in wires for electricity transmission, while cooking utensils are made of metals because of their superior heat conduction abilities.