give an example of a situation in which you would describe an object's position in

Answers

Answer 1
Incomplete question.  Full text is:

"Give an example of a situation in which you would describe an object's position in (a) one-dimension coordinates (b) two-dimension coordinates (c) three-dimension coordinates"

Solution
(a) One dimension example: a man walking along a metal plank. We just need to specify one coordinate, the distance from the beginning of the plank.

(b) Two-dimension example: a ball moving on a circle. In this case, we need two coordinates: (x,y) to specify the position of the ball at every instant, since it is moving on a 2-D plane.

(c) The position of an airplane in the air: in this case we need 3 coordinates, the height, the latitude and the longitude of the airplane.

Related Questions

An iron robot falls from rest at a great height. neglecting air resistance, what is its speed after it has fallen for 3.5 seconds? 13.3 m/s 9.8 m/s 34.3 m/s 9.8 m/s2

Answers

In an uniformly accelerated motion, the velocity of the object follows the law:
[tex]v(t) = v_0 + at[/tex]
where [tex]v_0[/tex] is the initial velocity, a the acceleration and t the time.

In our problem, the robot starts from rest, so the initial speed is zero: [tex]v_i =0[/tex]. The robot is in free fall, so the acceleraion is the gravitational acceleration [tex]g=9.81 m/s^2[/tex]. therefore, after a time [tex]t=3.5 s[/tex], the velocity is 
[tex]v(3.5 s)= 0 + (9.81 m/s^2)(3.5 s)=34.3 m/s[/tex]

If it takes a ball dropped from rest 2.069 s to fall to the ground, from what height h was it released?

Answers

i dont know the answer im sorry

A research van de graaff generator has a 2.00-mdiameter metal sphere with a charge of 5.00 mc on it. (a) what is the potential near its surface? (b) at what distance from its center is the potential 1.00 mv? (c) an oxygen atom with three missing electrons is released near the van de graaff generator. what is its energy in mev when the atom is at the distance found in part b?

Answers

(a) The potential on the surface of a charged sphere of radius R is equal to
[tex]V(R) = k_e \frac{Q}{R} [/tex]
where [tex]k_e = 8.99 \cdot 10^9 N m^2 C^{-2}[/tex] is the Coulomb's constant, [tex]Q [/tex] is the charge on the sphere's surface.
For the generator mentioned in the problem, the charge is [tex]Q= 5 mC=5 \cdot 10^{-3} C[/tex], while the radius is [tex]R= \frac{d}{2}= \frac{2.0 m}{2} =1.0 m [/tex]. Using these values in the formula, we can calculate the potential at the surface:
[tex]V(R)=8.99 \cdot 10^9 N m^2 C^{-2} \frac{5 \cdot 10^{-3} C}{1.0 m}=4.5 \cdot 10^7 V [/tex]

(b) The potential generated by the sphere at a certain distance r from the centre of the sphere is given by
[tex]V(r) = k_e \frac{Q}{r} [/tex]
the problem asks at which distance [tex]V(r) = 1 mV=1\cdot 10^{-3} V[/tex]. Substituting in the previous formula we can find the value of r:
[tex]r=k_e \frac{Q}{V(r)}= 8.99 \cdot 10^9 N m^2 C^{-2} \frac{5 \cdot 10^{-3}}{1\cdot 10^{-3} V}=4.5 \cdot 10^{10} m[/tex]

(c) An oxygen atom with 3 missing electrons has a positive charge of +3e, with e being the elementary charge.
The electric potential energy of a charged particle located at some point with voltage V is
[tex]U=q V[/tex]
where q is the charge of the particle, which is in our case [tex]q=+3e[/tex]. So we can calculate the energy of the oxygen atom at the distance found in part b, which corresponds to [tex]r=4.5 \cdot 10^{10}m[/tex] and a voltage of [tex]V=1 mV[/tex]:
[tex]U=(3 e)(1 mV) = 3 meV[/tex]

Part A: The potential on the surface of the charged sphere is [tex]4.5 \times 10^7[/tex] volts.

Part B: The distance is [tex]4.5 \times 10^{10}[/tex] m from the center of the sphere where the potential is 1 mv.

Part C: The energy of the oxygen atom found at the distance of [tex]x = 4.5 \times 10^{10} \;\rm m[/tex] is 3me V.

How do you calculate the potential?

Given that the diameter of the sphere is 2.00 m and the charge of 5.00 mc.

Part A

The potential on the surface of a charged sphere is given below.

[tex]V = k\dfrac {Q}{R}[/tex]

Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.

[tex]V = 8.99 \times 10^9\times \dfrac {5 \times 10^{-3}}{\dfrac {2}{2}}[/tex]

[tex]V = 4.5 \times 10^7 \;\rm Volts[/tex]

Hence the potential on the surface of the charged sphere is [tex]4.5 \times 10^7[/tex] volts.

Part B

The potential of 1 mv generated at a certain distance x from the centre of the sphere is given below.

[tex]V_x = k \dfrac {Q}{x}[/tex]

[tex]1 \times 10^{-3} = 8.99 \times 10^9 \times \dfrac{5 \times 10^{-3}} {x}[/tex]

[tex]x = 4.5 \times 10^{10} \;\rm m[/tex]

Hence the distance is [tex]4.5 \times 10^{10}[/tex] m from the center of the sphere where the potential is 1 mv.

Part C

Given that an oxygen atom with three missing electrons is released near the van de-Graaff generator. It means that the charge Q = +3e

The electric potential energy of a charged particle located at some point with voltage V is given below.

[tex]U = QV[/tex]

At the distance found in part b, which is [tex]x = 4.5 \times 10^{10} \;\rm m[/tex], the energy of the oxygen atom is,

[tex]U = +3e \times 1 \times 10^{-3}[/tex]

[tex]U = 3me \;\rm V[/tex]

Hence the energy of the oxygen atom found at the distance of [tex]x = 4.5 \times 10^{10} \;\rm m[/tex] is 3me V.

To know more about potential, follow the link given below.

https://brainly.com/question/1313684.

Which law of motion accounts for the following statement?

"The gravity of the Sun causes the planets to move in a circular path."

first law
second law
third law

Answers

i know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...

Answer:

First law

Explanation:

The gravity of the Sun causes the planets to move in a circular path. This is due to first law of motion. The first law states that an object will be at rest and an object will be in motion until no external force acts on it.

It is possible due to sun's gravity pull that the planets move in a circular path. Without sun's gravity the planet would move in a straight line. Hence, the correct option is (a) " first law of motion".

Read the article by Michael Fumento, writer for the New York Post editorial blog, who does not support global warming. Back in 2005 I and others reviewed the entire hurricane record, which goes back over a century, and found no increase of any kind. Yes, we sometimes get bad storms—but no frequently now than in the past. The advocates simply ignored that evidence. Fact is, the earth was cooling and warming long before greenhouse gases could have been a factor. The [global warming supporters] have been proved wrong time and time again. Which best describes the reliability of the source? Nationally certified organizations are considered an unreliable source because the public can access their information. Charities are considered a reliable source because the public makes financial contributions to them. Editorial blogs are considered an unreliable source because the author may not have a science background. Editorial blogs are considered a reliable source because authors contribute to them regularly.

Answers

The third choice best describes reliability: Editorial blogs are considered an unreliable source because the author may not have a science background.

The first statement is illogical, just because the public can access information does not make it unreliable. The second also is incorrect, if charities receive money from the public, they may have incentive to publish popular theories to get more support, so they are unreliable. The fourth is incorrect, because we don't have any background on who the authors are.

Answer:

the 3rd choice is the answer

Explanation:

(ENVIRONMENTAL SCIENCE NOT PHYSICS)
7. gradually taking over farmland over a long period of time is known as commodities. True or False
8. The 2002 farm bill gives money to farmers who grow crops like wheat and soybeans but not to fruit and vegetable farmers. True or False
9. some farmers have been selling their land to developers because it is more cost efficient to do so than to grow crops. True or False
10. The FBI regulates the use of pesticides in agricultural crops. True or False

Answers

1) False
2) True
3) True
4) True
5) False
6) True
7) False
8) True
9) True
10) False

100% : just took this :)

What is the internal resistance of a 12.0-v car battery whose terminal voltage drops to 8.3 v when the starter motor draws 89 a ?

Answers

The relationship between the terminal voltage V of a battery and its electromotive force [tex]\epsilon[/tex] is given by
[tex]V=\epsilon - Ir[/tex]
where I is the current and r the internal resistance.
In our problem [tex]\epsilon=12 V[/tex], and when a current of [tex]I=89 A[/tex] flows, the terminal voltage is [tex]V=8.3 V[/tex]. So we can find the value of the internal resistance:
[tex]r= \frac{\epsilon - V}{I}= \frac{12 V-8.3 V}{89 A}=0.042 \Omega [/tex]

Final answer:

To find the internal resistance of a 12.0-V car battery with specific measurements, use Ohm's Law.

Explanation:

Internal resistance of a battery can be calculated using Ohm's Law, where internal resistance = (emf - terminal voltage) / current. In this case, with an EMF of 12.0 V, terminal voltage of 8.3 V, and current of 89 A, the internal resistance would be calculated as (12.0 V - 8.3 V) / 89 A.

This gives an internal resistance of approximately 0.0427 ohms.

When the particles of a medium move with simple harmonic motion, this means the wave is a __________. when the particles of a medium move with simple harmonic motion, this means the wave is a __________. harmonic wave sinusoidal wave sound wave standing wave transverse wave?

Answers

When the particles of a medium move with simple harmonic motion, this means the wave is a sinusoidal wave.

Know that a sinusoidal curve can describe either sine or cosine functions (remember your cofunction identities for sine and cosine).

If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.

Explanation:

A body is considered to be performing the Simple Harmonic Motion if it repeats its motion in a particular path with a specific time period. The two and fro motion of the pendulum about a fixed mean position is termed as the Simple Harmonic Motion.

The motion of the simple pendulum repeats itself after a particular time period and it continuously retraces its path during the motion. Therefore, it is termed as the simple harmonic motion.

The wave depicting the motion of a body performing the simple harmonic motion is shown in the sinusoidal manner. The motion of the body from its mean position to its extreme and then from extreme position to its mean position shows the positive cycle of the sinusoidal waveform.

The motion of the pendulum on the other side of the mean position of the pendulum represents the other half of the sinusoidal waveform.

Thus, If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.

Learn More:

A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623The amount of kinetic energy an object has depends on its brainly.com/question/137098Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off. What is the net force acting on the refrigerator brainly.com/question/4033012

Answer Details:

Grade: High School

Chapter: Simple Harmonic Motion

Subject: Physics

Keywords:

simple, harmonic, SHM, motion, pendulum, oscillates, mean position, extreme, repeats, time period, sinusoidal.

Consider two copper wires. one has twice the length of the other. how do the resistivities of these two wires compare?

Answers

The resistivity [tex]\rho[/tex] of a wire is related to its length L by the following relationship:
[tex]\rho = \frac{RA}{L} [/tex]
where R is the resistance of the wire, and A its cross-sectional area. 
Assuming that the resistance R and the area A are the same for the two wires, we can see from the formula that, if the length L is doubled, then the resistivity [tex]\rho[/tex] becomes half of the original value. In fact, replacing L with 2 L we get
[tex]\rho '= \frac{RA}{2L}= \frac{1}{2} \frac{RA}{L}= \frac{\rho}{2} [/tex]

The resistivity of two copper wires remains the same regardless of their lengths because resistivity is an intrinsic property of the material.

Comparing resistivities of two copper wires of different lengths but the same material, we need to understand that resistivity is an intrinsic property of the material and does not depend on the geometry of the wire. Therefore, regardless of whether one wire is twice as long as the other, the resistivity of both wires remains the same. This is a fundamental concept in the study of electrical resistance and materials.

You hop on the carousel horse. The attendant flips the switch and you move up and down, around and around. When the ride ends, the attendant again flips the switch. The up and down motion stops, as you continue to move in a circular motion, gradually slowing to a stop. Why?

Answers

The reason why we gradualy slow untill we stop is acceleration. In this example we have two types of movement: vertical and circular.

The vertical movement does not have great speed. So when  we stop moving we do not experience great acceleration. Newton's second law states: F=m*a. This means that we do not experience great force.

The circular movement is a bit different. No matter where we stand on the carousel we have same angular speed. This means that we pass same angle in the same amount of time. But we also have linear speed. This speed depends on the distance from the center of carousel. If we are close to the center we have smaller speed than when we stand at the far end of carousel. If we stopped without slowing gradually we would experience great acceleration thus meaning we would experience great force. Sometimes this force could cause injuries.

A stone is thrown upward at an angle. what happens to the horizontal component of its velocity as it rises? as it falls?

Answers

Rising or falling, it does not change.
Final answer:

The horizontal component of the velocity of a stone thrown upward at an angle remains constant during its flight, as there is no horizontal force to affect it. This is due to the principles of projectile motion in physics. Gravity only affects the vertical velocity, not the horizontal.

Explanation:

In physics, the motion of a projectile thrown at an angle can be separated into its vertical and horizontal components. Both of these components operate independently of each other. When a stone is thrown upward at an angle, the horizontal component of its velocity remains constant throughout the flight, under ideal conditions, because there's no horizontal force to cause acceleration or deceleration.

So, as the stone rises and falls, the horizontal velocity remains unchanged because gravity only affects the vertical component of the velocity. In this process known as projectile motion, gravity pulls the object downward, causing the vertical component of velocity to decrease as the stone rises, and increase as it falls, but the horizontal component is unaffected by gravity. The effect of air resistance is typically ignored in basic physics problems, but in reality, it would gradually decrease the stone's velocity in both directions.

Learn more about Projectile Motion here:

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In a heat engine, if 500 j of heat enters the system, and the piston does 300 j of work, what is the final internal (thermal) energy of the system if the initial energy is 1500 j ?

Answers

The answer is 1,700 J.

During the forging process for a steel sword, the blacksmith places a hot iron blank into a cold bucket of water. Which of the following happens? A. The water molecules move faster. B. The steel molecules move faster. C. The water molecules move slower. D. The steel molecules do not change speed

Answers

Hello!

During the forging process for a steel sword, when the blacksmith places a hot iron blank into a cold bucket water A) The water molecules move faster. 

The iron blank molecules are at a higher temperature and move faster than the water molecules, which are colder. When the blacksmith places the hot iron blank into the water bucket, heat is transferred from the hot iron blank to the cold water causing water molecules to move faster, as their temperature (and kinetic energy) increases. This is described by the Second Law of Thermodynamics.

A woman wearing snowshoes stands safely in the snow. If she removes her snowshoes, she quickly begins to sink. Explain what happens in terms of force and pressure.

Answers

The purpose of snowshoes is to widen the area pressure is applied on. When you wear plain shoes, the area of distribution of force is concentrated into a small area, namely the area of the shoes you are wearing. Now when pressure is applied on snow surface, it tends to crumble. The force of you standing is concentrated on the space your shoe occupies, increasing the pressure on that specific area. 

Now when you wear snowshoes, you widen the area and the pressure is then distributed over that area lessening the force on specific points. 


The spacing of gravitational field lines indicates the _____ of the field.

Answers

The relative magnitude of a vectorial field is proportional to the density of field lines. This is true also for the gravitational field: so, the spacing between the gravitational field lines indicates the intensity of the gravitational field. The smaller is the spacing between the lines, the stronger is the field's intensity, and viceversa.

Consider a space pod somewhere between earth and the moon, at just the right distance so that the gravitational attractions to earth and the moon are equal. IS this location nearer earth or the moon?

Answers

look up   Lagrange points
there  are 5 of them
L1  is closer to the moon than earth
L3   and L4    are equal distance    from the earth to moon


Final answer:

The location in space where Earth's and the Moon's gravitational attractions are equal is closer to the Moon due to its significantly lesser mass compared to Earth. By applying Newton's law of universal gravitation, it can be deduced that this point must be nearer the Moon, as Earth's stronger gravitational force diminishes with increasing distance.

Explanation:

The gravitational attraction between two objects depends on both their masses and the distance between them, according to Newton's law of gravitation. The force of gravity is proportional to the product of the two masses and inversely proportional to the square of the distance between their centers of mass. Based on the data provided, the Earth's gravitational force is much stronger than that of the Moon due to its greater mass. However, as the distance from the Earth increases, its gravitational pull weakens.

Given that the mass of the Moon is about 1/81 of the Earth's mass and the distance from the Earth to the Moon is approximately 3.80×105 km, there exists a point where the gravitational forces exerted by Earth and the Moon on an object are equal, known as the Lagrange point L1. This point is closer to the Moon than to Earth because the Moon's weaker gravitational force requires a shorter distance to match the stronger gravitational force of the Earth. To find this exact point, one would use the formula from Newton's law of gravitation and set the forces equal to each other, solving for the distance from Earth at which this equilibrium occurs.

Considering the information provided about the distances and gravitational forces, we can infer that the space pod mentioned in the question, at the point where Earth's and the Moon's gravity cancel each other out, would indeed be closer to the Moon. This is a consequence of the vast difference in mass between the Earth and the Moon and the inverse-square law of gravity.

an expert is someone who

Answers

Google's definition: A person that has a prolonged or intense experience through practice and education in a particular field.
My words: I would say an expert is someone who knows something really well. About it and how to do it. They could be an expert on any subject.

Answer: D

expends the least amount of energy for the greatest result

Explanation:

edge 2020

A thermometer is taken from an inside room to the outside, where the air temperature is 30° f. after 1 minute the thermometer reads 80° f, and after 5 minutes it reads 55° f. what is the initial temperature of the inside room? (round your answer to two decimal places.)

Answers

Final answer:

To determine the initial temperature of the inside room, we can convert the given temperatures from Fahrenheit to Celsius and calculate the temperature change. By using the temperature change and the final temperature in Celsius, we can find the initial temperature in Celsius. The initial temperature of the inside room is approximately 27.22°C.

Explanation:

To find out the initial temperature of the inside room, we can use the relationship between Fahrenheit and Celsius scales. We know that 30°F is equal to -1.11°C, and 80°F is equal to 26.67°C. By converting these temperatures to Celsius, we can determine the temperature change. Then, using the final temperature of 55°F, we can calculate the initial temperature using the temperature change.



To convert Fahrenheit to Celsius, we use the formula:



TC = (TF - 32) × (5/9)



By plugging in the given temperatures, we find:



TC1 = (30 - 32) × (5/9) ≈ -1.11°C



TC2 = (80 - 32) × (5/9) ≈ 26.67°C



Next, we calculate the temperature change:



ΔT = TC2 - TC1 = 26.67 - (-1.11) = 27.78°C



Finally, we use ΔT and the final temperature (TC=55°C) to find the initial temperature:



Initial temperature = final temperature - ΔT



Initial temperature ≈ 55 - 27.78 ≈ 27.22°C

Learn more about converting temperatures, calculating temperature change here:

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A terrorist throws a grenade with a 6.00 second fuse off a building 150.0 m high at a speed of 10.0 m/s. If the angle at which the grenade is thrown is 30° below the horizontal, will the grenade explode before hitting the ground? What is the horizontal distance from the building at which the grenade will land.

Answers

Here we have a projectile motion. It is type of motion that is made of a vertical shot and a horizontal shot. This is how we will solve it.

Firste step is to find horizontal and vertical component of a speed.
[tex] v_{0x} =v_{0} * cos \alpha [/tex] \\ v_{0y} = v_{0} * sin \alpha [/tex]

We are given this information:
[tex]v_{0} = 10 m/s \\ h=150m \\ \alpha =-30°[/tex]
Angle is negative because it is below the horizontal.

VERTICAL SHOT
Time needed for a grenade to fall to the bottom of a building is given by a formula:
[tex]t= \frac{ v_{0y} }{g} \\ t= \frac{v_{0} * sin \alpha}{g} \\ t= \frac{-10*sin(-30)}{9.81} \\ t=0.51s[/tex]
We used negative value for a speed because it is considered that upwards shot has positive value and downwards shot has negative value.

The grenade will not explode before it hits the ground.


HORIZONTAL SHOT
The horizontal distance from the building at which the grenade will land is called range. The formula for a range is given by:
[tex]R= v_{0x} * \sqrt{ \frac{2h}{g} } \\ R=v_{0} * cos \alpha* \sqrt{ \frac{2h}{g} } \\ R=10*cos(-30)* \sqrt{ \frac{2*150}{9.81} } \\ R=47.89m[/tex] 

The grenade will hit the ground at distance of 47.89m.

You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible internal resistance. find the time constant of the circuit. what is the charge of the capacitor 1.95 time constants after the circuit is closed? what is the charge after a long time?

Answers

In a RC-circuit, with the capacitor initially uncharged,  when we connect the battery to the circuit the charge on the capacitor starts to increase following the law:
[tex]Q(t) = Q_0 (1-e^{-t/\tau})[/tex]
where t is the time, [tex]Q_0 = CV[/tex] is the maximum charge on the capacitor at voltage V, and [tex]\tau = RC[/tex] is the time constant of the circuit.
Using this law, we can answer all the three questions of the problem.

1) Using [tex]R=39.1 \Omega[/tex] and [tex]C= 65.7 mF=65.7\cdot 10^{-3}F[/tex], the time constant of the circuit is:
[tex]\tau = RC=(39.1 \Omega)(65.7 \cdot 10^{-3}F)=2.57 s[/tex]

2) To find the charge on the capacitor at time [tex]t=1.95 \tau[/tex], we must find before the maximum charge on the capacitor, which is
[tex]Q_0 = CV=(65.7 \cdot 10^{-3}F)(9 V)=0.59 C[/tex]
And then, the charge at time [tex]t=1.95 \tau[/tex] is equal to
[tex]Q(1.95 \tau) = Q_0 (1-e^{-t/\tau})=(0.59 C)(1-e^{-1.95})=0.51 C[/tex]

3) After a long time (let's say much larger than the time constant of the circuit), the capacitor will be fully charged, this means its charge will be [tex]Q_0 = 0.59 C[/tex]. We can see this also from the previous formule, by using [tex]t=\infty[/tex]:
[tex]Q(t) = Q_0 (1-e^{-\infty})=Q_0(1-0) = 0.59 C[/tex]

Elements may have similar properties and we can use the periodic table to help us determine what they are. These three elements are alike in many ways but they do not share ALL properties. What property do these elements NOT have in common? Mg, K, and Ca A) Same phase at room temperature. B) Good conductors of electricity. C) Same number of valence electrons. D) They form cations (positive ions).

Answers

C is the answer
potassium(K)has one electron in the valence shell
Ca and Mg has two

The properties that Mg, Ca and K do not have in common is "same number of valence electrons."

In the periodic table, elements are classified into groups and periods. The groups of elements show the relationships between them in terms of reactivity, valence electrons and physical properties.

Elements in the same group have the same number of valence electrons. However, Ca, K and Mg are not in the same group so they can not have the same number of valence electrons. Ca and Mg has two valence electrons while K has only one valence electron.

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Antagonistic muscles move a body part in _____.

1. the same direction

2. opposite directions

3. diagonal directions

Answers

Answer: Opposite direction

Skeletal muscles arise in antagonistic pairs where the muscles contract to produce opposite movements at the same joint. Antagonistic muscles move a body part in one direction by contraction, the other moves that part in opposite direction.

In addition, when a muscle contracts to produced movement, its antagonist relaxes to allow movement to take place such as biceps muscles is a flexor muscle for elbow joint and triceps is the antagonist.

 

2. Opposite directions

A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.02t3 (a) find the velocity at time t (in ft/s). v(t) = .04t3−.06t2 (b) what is the velocity after 1 second(s)? v(1) = -.02 ft/s (c) when is the particle at rest? t = s (smaller value) t = s (larger value) (d) when is the particle moving in the positive direction? (enter your answer using interval notation.) (e) find the total distance traveled during the first 12 seconds. (round your answer to two decimal places.) ft (f) find the acceleration at time t (in ft/s2). a(t) = find the acceleration after 1 second(s). a(1) = ft/s2

Answers

Final answer:

The velocity function can be found by differentiating the position function. The velocity after 1 second is -0.02 ft/s. The particle is at rest at t = 0 and t = 1.5 seconds.

Explanation:

(a) To find the velocity at time t, we can differentiate the position function. The derivative of f(t) = 0.01t^4 - 0.02t^3 is v(t) = 0.04t^3 - 0.06t^2. So, the velocity function is v(t) = 0.04t^3 - 0.06t^2 ft/s.

(b) To find the velocity after 1 second, we substitute t = 1 into the velocity function. v(1) = 0.04(1)^3 - 0.06(1)^2 = -0.02 ft/s.

(c) The particle is at rest when its velocity is equal to zero. To find the time(s) the particle is at rest, we set v(t) = 0 and solve for t. So, the particle is at rest at t = 0 and t = 1.5 seconds.

(d) The particle is moving in the positive direction when its velocity is positive. To find the time(s) the particle is moving in the positive direction, we look for the intervals where v(t) > 0. The particle is moving in the positive direction when 0 < t < 1.5 seconds.

(e) The total distance traveled during the first 12 seconds can be found by finding the area under the velocity-time graph. We integrate v(t) from 0 to 12 seconds. The total distance traveled during the first 12 seconds is approximately 96 ft.

(f) To find the acceleration at time t, we differentiate the velocity function. The derivative of v(t) = 0.04t^3 - 0.06t^2 is a(t) = 0.12t^2 - 0.12t ft/s^2.

(g) To find the acceleration after 1 second, we substitute t = 1 into the acceleration function. a(1) = 0.12(1)^2 - 0.12(1) = 0 ft/s^2.

A 0.450-kg hammer is moving horizontally at 7.00 m/s when it strikes a nail and comes to rest after driving the nail 1.00 cm into a board. (a) calculate the duration of the impact. (b) what was the average force exerted on the nail?

Answers

(a) The duration of impact of the hammer is [tex]\fbox{\begin\\1.43 \times {10^{ - 3}}\,{\text{s}}\end{minispace}}[/tex] .

(b) The average force exerted on the nail is [tex]\fbox{\begin\\2205\,{\text{N}}\end{minispace}}[/tex].

Further explanation:

When hammer hit the nail it got impacted by the hit and get into the board. This insertion in the board take time which is called duration of impact. The force exerted on the nail is directly proportional to the acceleration of the nail.

Given:

The speed of hammer is [tex]7\,{\text{m/s}}[/tex].

The distance of nail which is inserted in the board is [tex]1\,{\text{cm}}[/tex].

The mass of the hammer is [tex]0.450\,{\text{Kg}}[/tex].

Concept used:

The rate of change of displacement of a body in unit time is called speed of the body. It is a scalar quantity.

The expression for the speed of the body is given as.

[tex]v = \dfrac{s}{t}[/tex]

Rearrange the above expression for the time.

[tex]t=\dfrac{s}{v}[/tex]                                               …… (1)

Here, [tex]s[/tex]  is the distance covered, [tex]v[/tex]  is the speed of body and [tex]t[/tex]  is the time.

According to Newton’s second law of motion “the rate of change of momentum is equal to the force applied on the body.”

The expression for the newton’s law is given as.

[tex]F = ma[/tex]                                          ……. (2)

The expression for the acceleration of the body is given as.

[tex]\fbox{\begin\\a = \dfrac{{\left( {v - u} \right)}}{t}\end{minispace}}[/tex]                                           …… (3)

Here, [tex]u[/tex]  is the initial velocity and [tex]v[/tex]  is the final velocity.

Substitute [tex]1\,{\text{cm}}[/tex] for [tex]s[/tex] and [tex]7\,{\text{m/s}}[/tex]  for [tex]v[/tex] in equation (1).

[tex]\begin{aligned}t&=\frac{{1\,{\text{cm}}}}{{7\,{\text{m/s}}}}\\&=\frac{{1\,{\text{cm}}\left( {\frac{{1\,{\text{m}}}}{{100\,{\text{cm}}}}} \right)}}{{7\,{\text{m/s}}}}\\&=1.43 \times {10^{ - 3}}\,{\text{s}} \\ \end{aligned}[/tex]

Substitute [tex]1.43 \times {10^{ - 3}}\,{\text{s}}[/tex] for [tex]t[/tex], for[tex]0\,{\text{m/s}}[/tex]  and [tex]v[/tex]  for  in equation (3).

[tex]\begin{gathered}a= \frac{{\left( {0\,{\text{m/s}} - 7\,{\text{m/s}}} \right)}}{{\left( {1.43 \times {{10}^{ - 3}}\,{\text{s}}} \right)}} \\= \left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right) \\ \end{gathered}[/tex]

Substitute[tex]\left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)[/tex] for [tex]a[/tex]  and [tex]0.450\,{\text{Kg}}[/tex]  for [tex]m[/tex]  in equation (2).

[tex]\begin{aligned}F&=\left( {0.450\,{\text{Kg}}} \right)\left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)\\&=- 2209\,{\text{N}} \\ \end{aligned}[/tex]

Thus, the duration of impact is[tex]1.43 \times {10^{ - 3}}\,{\text{s}}[/tex]  and the force exerted on the nail is [tex]2209\,{\text{N}}[/tex]  in the opposite direction.

Learn more:

1.  Motion under friction https://brainly.com/question/7031524.

2.  Conservation of momentum https://brainly.com/question/9484203.

3. Force on a body https://brainly.com/question/6125929.

Answer Details:

Grade: College

Subject: Physics

Chapter: Kinematics

Keywords:

Acceleration, force, acceleration due to gravity, friction, normal, weight, mass, motion, impact, nail, hammer, acceleration, duration of impact, 0.450 kg, 7 m/s, 2205 N,1.429*10^-3 sec, 1.43*10^-3 sec.

The duration of the impact is 0.133 seconds.

The average force exerted on the nail was 5800 N.

(a) Let's use the following equations to solve this problem:

m = 0.450 kg

v_i = 7.00 m/s

v_f = 0 m/s

d = 0.01 m

where:

m is the mass of the hammer

v_i is the initial velocity of the hammer

v_f is the final velocity of the hammer (after it strikes the nail)

d is the distance that the nail is driven into the board

We know that the hammer comes to rest after it strikes the nail, so v_f = 0. We can also set the kinetic energy of the hammer before the impact equal to the work done by the force exerted by the nail on the hammer during the impact.

[tex]KE_i = W\dfrac{1}{2}mv_i^2 = Fd\dfrac{1}{2}(0.450 kg)(7.00 m/s)^2 = F(0.01 m)F = 5800 N[/tex]

The duration of the impact can be calculated using the following equation:

[tex]t = \dfrac{d}{v_i}t = \dfrac{0.01 m}{7.00 m/s}t = 0.0133 s[/tex]

(b) The average force exerted on the nail is equal to the force exerted by the hammer on the nail divided by the duration of the impact.

F_avg = F / t

F_avg = 5800 N / 0.0133 s

F_avg = 5800 N

Therefore, the average force exerted on the nail was 5800 N.

To know more about the Board, here

https://brainly.com/question/34682939

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A common cylindrical copper wire used in a lab is 841 m long. Find the radius (in mm) of a wire necessary to have 0.5 Ohms of resistance. (The resistivity of copper at room temperature is 1.68×10-8 Ohm × meter). Express the answer (only numerical value) to one decimal place.

Answers

The relationship between the resistance R of a wire and its resistivity [tex]\rho[/tex] is given by
[tex]R= \frac{\rho L}{A} [/tex]
where L is the length of the wire and A is its cross sectional area.

In the problem, we have [tex]R=0.5 \Omega[/tex], [tex]\rho = 1.68 \cdot 10^{-8} \Omega m[/tex] and [tex]L=841 m[/tex]. So we can solve the find the area A:
[tex]A= \frac{\rho L}{R}=2.83 \cdot 10^{-5} m^2 [/tex]

For a cylindrical wire, the cross sectional area is given by
[tex]A= \pi r^2[/tex]
where r is the radius. We know the value of the area A, so now we can find the radius of the wire:
[tex]r= \sqrt{ \frac{A}{\pi} }= \sqrt{ \frac{2.83 \cdot 10^{-5}m^2}{\pi} }=0.003 m=3.0 mm [/tex]

in gas exchange, oxygen passes from the alveoli into the blood . True or false ?

Answers

the answer is True .

The maximum allowed power dissipation for a 27.3-ω resistor is stated to be 10.0 w. find the largest current that this resistor can take safely without burning out.

Answers

The power dissipated on a resistor is related to the current I flowing through it and its resistance R by the relationship
[tex]P= I^2 R [/tex]
If the resistance is [tex]R=27.3 \Omega[/tex] and the maximum dissipated power is 10.0 W, then we can find the maximum allowed current by re-arranging the previous equation:
[tex]I= \sqrt{ \frac{P}{R} }= \sqrt{ \frac{10.0 W}{27.3 \Omega} }=0.6 A [/tex]

The amount of flow of charge per unit time is known as the current. The largest current that this resistor can take safely without burning out will be 0.6 amperes.

What is power dissipation in a resistor?

The process of losing power in the form of heat as a result of the main activity is known as power dissipation. Dissipation of power is a natural occurrence.

All of the circuit's resistors that have a voltage drop across them will dissipate power. Due to the conversion of electrical energy to thermal energy, all resistors will have a power rating.

The power dissipated on a resistor is given as

P = I²R

I is current  flowing through it  

R is the resistance

[tex]\rm {P = I^2R}\\\\I=\sqrt{\frac{P}{R} }\\\\I=\sqrt{\frac{10}{27.36\\}[/tex]

I = 0.6 A

Hence the largest current that this resistor can take safely without burning out will be 0.6 amperes.

To learn more about the power dissipated on a resistor refer to the link;

https://brainly.com/question/10728846

Which of these pollutants is transferred from soil to water by organic pesticides and fertilizer runoff from farms?

A coliform
B oxygen
C carbon
D phosphates

Answers

Answer: Option D

Explanation: The fertilizers consists of the phosphates and nitrates. These aids in the growth of the plant. Fertilizers used by the plants are sometimes carried away due to the rain.

The run off from the agricultural field contains phosphates that is transferred from the field to the nearby water bodies.

What current flows through a 2.62 cm diameter rod of pure silicon that is 23.5 cm long, when 1000 v is applied to it? (such a rod may be used to make nuclear particle detectors, for example.) the resistivity of pure silicon is 2.30 103 ω · m?

Answers

resistivity = resistance * Area / Length
resistance = ??
rho = 2.30 * 10^3 ohms meters.
l = 23.5 cm = 0.235 meters.
diameter = 2.62 cm = 0.0262 m
Radius = diameter / 2 = 0.0131 m
Area = pi r^2 where pi = 3.14
Area = 3.14 * 0.0131^2 = 0.000539 m^2

2.30 * 10^3 = R * 0.000539 /0.235
2.30 * 10^3 * 0.235/0.000539 = R
R = 1002783 which is about 1 meg ohm, but I'll use the calculation here.

E = 1000 V
R = 1 002 783 ohms
I = ???

E = I * R
1000 = I * 1002783 We should really round that resistor to 1 megohm or 1 * 10^6 ohms.

I = 1*10^3 / 1 * 10^6
I = 1 * 10^-3 amp = 1 milliamp. Pretty reasonable all things considered. 

When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What type of learning is Ian demonstrating?

Answers

This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.

ANSWER: Ian is demonstrating a typical example of Observational Learning. An observational learning is a learning pattern which happens by observing the behavior of others. People generally follows a role model such as parent, sibling, relative or teachers and imitate them while they are doing their work, particularly in childhood. There are four steps of observational learning which are Attention, Memory, Initiation and Motivation.

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