Given that the points (-3, 8), (2, 8), (2, -2), and (-3, -2) are vertices of a rectangle, what is the ratio of the rectangle's length to its width?

The author compare a melting ice cream cone to c. an atomic bomb.

In the essay ""How to Eat an Ice Cream Cone"" by Eugene Field, the author humorously compares the act of eating a melting ice cream cone to an atomic bomb.

The comparison is used to illustrate the chaotic and uncontrollable nature of trying to consume the ice cream before it melts, much like the destructive and rapid spread of an atomic bomb's explosion.

The author does not compare the melting ice cream cone to a runaway train, a machine gun, or a hand grenade, as these are not mentioned in the context of the essay.

The atomic bomb metaphor is used to emphasize the urgency and potential mess that can result from not eating the ice cream cone quickly enough, likening it to a catastrophic event that is difficult to contain once it starts."

To find the length of the pool, divide the volume (920 m³) by the product of the width (100 m) and depth (0.4 m), which gives a pool length of 23 meters.

The question asks to find the length of the pool given the volume, width, and depth of the pool. The volume of a rectangular prism (which is the shape of the pool) can be found using the formula Volume = length × width × depth. We can rearrange this formula to solve for the length by dividing the volume by the product of the width and depth.

Therefore, the length of the pool is calculated as follows:

So, the length of the pool is 23 meters.

the answer to this question is march

Answer:

The center of circle N is (0, 10).

Circle M and circle N are similar.

Step-by-step explanation:

It is given circle N is translation of circle M 1 unit left .The radius of circle M is (1,10) when it is translated 1 units left the circle N will have the center (0,10).The y value will remain same while the x coordinated is reduced by 1 that is 1-1=0.The center of circle N is (0, 10)

As the circle N is a dilation of circle M by scale factor 3 so the radius of the two circle will not be same and hence the diameter will also be different.

In translation  we have a similar figure ,So circle M and N will be similar.

We are given points on trig graph as

[tex](0,-4)[/tex]

[tex](\frac{\pi}{2} ,0)[/tex]

[tex](\pi ,4)[/tex]

[tex](\frac{3\pi}{2} ,0)[/tex]

[tex](2\pi ,-4)[/tex]

now, we can find rate of change from x = π to x = 2π

so, we will select two points

[tex](\pi ,4)[/tex]  and [tex](2\pi ,-4)[/tex]

we can also write as

[tex]a=\pi , f(a)=4[/tex]

[tex]b=2\pi , f(b)=-4[/tex]

now, we can use average rate of change formula

[tex]A=\frac{f(b)-f(a)}{b-a}[/tex]

now, we can plug values

and we get

[tex]A=\frac{-4-4}{2\pi -\pi}[/tex]

[tex]A=\frac{-8}{\pi }[/tex]

so, option-C.............Answer

Final answer:

If two angles of one triangle are congruent to two angles in another triangle, the third angles must also be congruent since the sum of angles in any triangle must equal 180 degrees. This principle is supported by geometric theorems about the properties of triangles and the requirements for their congruence and similarity.

Explanation:

If two angles of one triangle are congruent to two angles in another triangle, then the third angles in both triangles must also be congruent. This is because the sum of the angles in any triangle must equal 180 degrees or two right angles. Since two angles are congruent in both triangles, whatever is left from the 180 degrees after subtracting these two angles must be what is left for the third angle, making them congruent by necessity.

There are several related theorems in geometry that confirm this. Theorem 11, also known as the Side-Angle-Side (SAS) Postulate, states that if one side and the two adjacent angles of two triangles are congruent, then the triangles are congruent. While this theorem refers mainly to the congruency of triangles, it supports our understanding that if two angles are congruent, the third must be as well to satisfy the congruence of all three angles.

Furthermore, in the context of similar triangles, when two triangles have congruent angles, they are similar, meaning all their angles are congruent, and their sides are in proportion. However, if we only consider the angles, as in the original question, knowing that two angles are congruent across two triangles is enough to deduct that the third angles will be congruent, regardless of side lengths or overall similarity.

The answer would be 6,900 ft2. The equation to find the area is "a=1/2bx"

a= area b=base h=height. Hope this helps :D

Given that, a town plans to make a triangular park. The triangle has a base of 120 feet and a height of 115 feet.

We know that area of a triangle = [tex] \frac{1}{2} [/tex] x base x height

Given that base of triangle is 120 feet and height is 115 feet. From the given data, we calculate the area of the triangular park.

Area = [tex] \frac{1}{2}*120 *115 = 6900 [/tex]

Hence , Area of triangular park is 6900 square feet.

Final answer:

The ratio of the areas of two similar triangles with heights of 6 and 10 meters is 9/25.

Explanation:

To find the ratio of the areas of two similar triangles, △ABC and △DEF, with heights 6 meters and 10 meters respectively, we use the knowledge that the areas of similar triangles are proportional to the squares of the corresponding linear dimensions, such as their heights. For these triangles, the ratio of their heights is 6/10 or 3/5. Thus, the ratio of their areas is (3/5)2 or 9/25.

Value of k = 10

Triangles are flat fields bounded by 3 intersecting sides and 3 angles

This side can be the same length or different.

There are two angles that can form:

From picture: ∠Y = Supplementary Angles:

115 ° + ∠Y = 180 °

∠Y = 180 ° - 115 °

∠Y = 65 °

As we know, the sum of angles in a triangle = 180 °

So from the picture, the sum of  ∠Y + ∠X + ∠Z = 180 °

65 ° + 6k + 10 ° + 4k + 5 ° = 180 ° (combine like terms)

65 ° + 10 ° + 5 ° + 6k + 4k = 180 °

80 ° + 10 k = 180 °

10 k = 180 ° -80 °

10 k = 100 °

k = 10

the Sin rule

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Answer:

The value of k is 10.

Step-by-step explanation:

Triangles are flat fields bounded by 3 intersecting sides and 3 angles

This side can be the same length or different.

There are two angles that can form:

Supplementary Angles: if both angles are added = 180 °

Complementary Angles: if both angles are added = 90 °

From picture: ∠Y = Supplementary Angles:

115 ° + ∠Y = 180 °

∠Y = 180 ° - 115 °

∠Y = 65 °

As we know, the sum of all interior angles of a triangle = 180 °

So from the picture, the sum of  ∠Y + ∠X + ∠Z = 180 °

65 ° + 6k + 10 ° + 4k + 5 ° = 180 ° (combine like terms)

65 ° + 10 ° + 5 ° + 6k + 4k = 180 °

80 ° + 10 k = 180 °

10 k = 180 ° -80 °

10 k = 100 °

k = 10

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Answer:

B)C(b)= 2.75b + 10

Step-by-step explanation:

Answer:

1,-4

0,4

3,-724

Step-by-step explanation:

Therefore option B is correct.

When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their place. Similarly, when a point is reflected across the line y = -x, the x-coordinates and y-coordinates change their place and are negated. Therefore, The reflection of the point (x, y) across the line y = x is (y, x).

We have,

Coordinate of the vertex of the ΔFGH is F( -2 , -1 ) , G( 2 , 2 ) and H( 4 , -3 )

According to the question,

We know that when a point ( x , y ) reflected over y-axis , the y-coordinate remains the same but the x-coordinate is transformed into its opposite .i.e., ( -x , y )

So, Image of the Vertex F( -2 , -1 ) = F'( -(-2) , -1 ) = F'( 2 , -1 )

Image of the Vertex G( 2 , 2 ) = G'( -2 , 2 )

Image of the Vertex H( 4 , -3 ) = H'( -4 , -3 )

Hence, the  image of the vertexes is F'( 2 , -1 ) ,G'( -2 , 2 ) and H'( -4 , -3 )

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If the trend continues, 43% of babies will be born out of wedlock in the year 2015.

To find the year in which 43% of babies will be born out of wedlock, we can use the information given. In 1990, 28% of babies were born to unmarried parents. And throughout the 1990s, there was an increase of approximately 0.6% per year. So, we can set up an equation: 28 + 0.6x = 43, where x represents the number of years after 1990.

To solve for x, we can subtract 28 from both sides of the equation: 0.6x = 15. Then, divide both sides by 0.6 to isolate x: x = 15 ÷ 0.6. Using a calculator, we find that x is approximately 25. Therefore, if the trend continues, 43% of babies will be born out of wedlock in the year 1990 + 25 = 2015.

Final answer:

If the trend continues, 43% of babies will be born out of wedlock in the year 2015.

Explanation:

To find the year when 43% of babies will be born out of wedlock, we need to calculate how many years it will take for the percentage to reach 43% based on an initial value of 28% and an annual increase of approximately 0.6%.

Therefore, if the trend continues, 43 of babies will be born out of wedlock in 2015.

Answer:

Step-by-step explanation:

Since we have been given two points, P(4,1,1) and Q(0,-7,9), we can take the vector between the two toget the directional vector.

So, vector PQ = v = <-4, -8, 8>. Now, we find its UNIT VECTOR.

Since the UNIT VECTOR is just the vector divided by its magnitude, we get that the unit vector u = v / |v|

|v| = [tex]\sqrt{(-4)^2+(-8)^2+(8^2)}[/tex]  = [tex]\sqrt{144}[/tex] = 12

Dividing each part of the original vector v by 12 gives us the unit vector.

Now, we take the partial derivatives, Fx, Fy, and Fz.

Fx = [tex]y^2z^3[/tex]  

Fy = [tex]x(2y)z^3[/tex]

Fz = [tex]xy^2(3z^2)[/tex]

plugging in the original point P(4,1,1) gives us the following values for the gradient, which is just the vector of the partial derivatives.

ΔF = <1,8,12>

Now we just use the equation Duf = ΔF * u, where we take the DOT PRODUCT of the gradient at the given point with the direction unit vector.

This gives us <1,8,12> * <-1/3, -2/3, 2/3> = 7/3

The directional derivative of [tex]\( f \)[/tex] at point [tex]\( P(4, 1, 1) \)[/tex] in the direction of [tex]\( Q(0, -7, 9) \)[/tex] is [tex]\( \frac{7}{\sqrt{6}} \).[/tex]

To find the directional derivative of the function [tex]\(f(x, y, z) = xy^2z^3\)[/tex] at the point [tex]\(P(4, 1, 1)\)[/tex] in the direction of [tex]\(Q(0, -7, 9)\)[/tex], we'll use the formula for directional derivative:

[tex]\[ D_{\mathbf{u}} f(x, y, z) = \nabla f \cdot \mathbf{u} \][/tex]

where [tex]\( \nabla f \)[/tex] is the gradient vector of [tex]\( f \)[/tex] and [tex]\( \mathbf{u} \)[/tex] is the unit vector in the direction of [tex]\( Q \).[/tex]

First, let's find the gradient vector [tex]\( \nabla f \):[/tex]

[tex]\[ \nabla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right) \][/tex]

[tex]\[ = \left( y^2z^3, 2xyz^3, 3xy^2z^2 \right) \][/tex]

Now, evaluate [tex]\( \nabla f \)[/tex] at the point [tex]\( P(4, 1, 1) \):[/tex]

[tex]\[ \nabla f(P) = \left( (1)^2(1)^3, 2(4)(1)(1)^3, 3(4)(1)^2(1)^2 \right) \][/tex]

[tex]\[ = (1, 8, 12) \][/tex]

Next, find the unit vector in the direction of [tex]\( Q \):[/tex]

[tex]\[ \mathbf{u} = \frac{\mathbf{Q} - \mathbf{P}}{\|\mathbf{Q} - \mathbf{P}\|} \][/tex]

[tex]\[ = \frac{(0 - 4, -7 - 1, 9 - 1)}{\sqrt{(0 - 4)^2 + (-7 - 1)^2 + (9 - 1)^2}} \][/tex]

[tex]\[ = \frac{(-4, -8, 8)}{\sqrt{16 + 64 + 64}} \][/tex]

[tex]\[ = \frac{(-4, -8, 8)}{4\sqrt{6}} \][/tex]

[tex]\[ = \left( -\frac{1}{\sqrt{6}}, -\frac{2}{\sqrt{6}}, \frac{2}{\sqrt{6}} \right) \][/tex]

Now, calculate the dot product [tex]\( \nabla f \cdot \mathbf{u} \):[/tex]

[tex]\[ D_{\mathbf{u}} f(P) = \nabla f(P) \cdot \mathbf{u} \][/tex]

[tex]\[ = (1, 8, 12) \cdot \left( -\frac{1}{\sqrt{6}}, -\frac{2}{\sqrt{6}}, \frac{2}{\sqrt{6}} \right) \][/tex]

[tex]\[ = -\frac{1}{\sqrt{6}} + \left(-\frac{16}{\sqrt{6}}\right) + \frac{24}{\sqrt{6}} \][/tex]

[tex]\[ = \frac{7}{\sqrt{6}} \][/tex]

Therefore, the directional derivative of [tex]\( f \)[/tex] at point [tex]\( P(4, 1, 1) \)[/tex] in the direction of [tex]\( Q(0, -7, 9) \)[/tex] is [tex]\( \frac{7}{\sqrt{6}} \).[/tex]