The mass of NH3 produced from the complete reaction of 2.55g of H2 is calculated to be 14.45 g, based on the molar masses of H2 and NH3 and the stoichiometry of the given balanced chemical equation.
Explanation:To calculate the mass of NH3 produced by the complete reaction of 2.55g of H2, we first need to determine the molar mass of H2. Knowing that the atomic mass of hydrogen is 1.0, we can say that the molar mass of H2 is 2.0 g/mol. Next, we need to find out how many moles of H2 are in 2.55 g:
Number of moles of H2 = mass (g) / molar mass (g/mol) = 2.55 g / 2.0 g/mol = 1.275 mol
Using the stoichiometry of the balanced equation (N2(g) + 3H2(g) → 2NH3(g)), we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, we can set up a proportion to find the number of moles of NH3 that would be produced from 1.275 moles of H2:
(1.275 mol H2) * (2 mol NH3 / 3 mol H2) = 0.85 mol NH3
Now, to find the mass of NH3, we need to know its molar mass. The atomic mass of nitrogen is 14.0 and hydrogen is 1.0, so the molar mass of NH3 is 14.0 + (3 * 1.0) = 17.0 g/mol. Finally, we can calculate the mass of NH3 produced:
Mass of NH3 = number of moles * molar mass = 0.85 mol * 17.0 g/mol = 14.45 g
What is the formula for copper(ii) phosphate? capitalization and punctuation count!?
Part a ammonia can be produced via the chemical reaction n2(g)+3h2(g)⇌2nh3(g) during the production process, the production engineer determines the reaction quotient to be q = 3.56×10−4. if k = 6.02×10−2, what can be said about the reaction? view available hint(s) ammonia can be produced via the chemical reaction during the production process, the production engineer determines the reaction quotient to be = 3.56×10−4. if = 6.02×10−2, what can be said about the reaction? the reaction has reached equilibrium. the reaction is not at equilibrium and will proceed to the left. the reaction is not at equilibrium and will proceed to the right. the reaction is not at equilibrium, but it is not possible to determine whether the reaction needs to proceed right or left to reach equilibrium. submit
Write the chemical equation for the reaction of propylamine, c3h7nh2 with water. (include all phases in your answer)
Answer is:
CH₃-CH₂-CH₂-NH₂ + H₂O(l) ⇄ CH₃-CH₂-CH₂-NH₃⁺(aq) + OH⁻(aq).
Amine group (-NH₂) has neutral charge, bet when accepts one
proton (H⁺) has positive
charge.
Amines are compounds that contain a basic nitrogen atom with a lone pair of electrons. Amines are derivatives of ammonia, where is one or more hydrogen atoms replaced by a substituent such as an alkyl or aryl group (in this compound propyl group).
Propylamine accepts a proton from water according to the reaction equation; C3H7NH2(aq) + H2O(l) ------> C3H7NH3^+(aq) + OH^-
Propylamine is a base because it accepts a proton. Recall that according to Brownstead - Lowry, a base is any substance that accepts a proton while an acid is any substance that donates a proton. Propylamine accepts a proton because of the lone pair on nitrogen atom.
The reaction of propylamine with water is an acid base reaction because propylamine accepts a proton from water as follows;
C3H7NH2(aq) + H2O(l) ------> C3H7NH3^+(aq) + OH^-
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Co(g)+h2o(g)⇌co2(g)+h2(g) kp=0.0611 at 2000 k a reaction mixture initially contains a co partial pressure of 1320 torr and a h2o partial pressure of 1760 torr at 2000 k. calculate the equilibrium partial pressure of co2.
We use the expression for Kp in terms of partial pressures, set up an equation incorporating the given initial pressures and the changes in pressure that occur as the reaction proceeds, and solve that equation to find the equilibrium partial pressure of CO2.
Explanation:To answer this question, we need to use the expression for the equilibrium constant (Kp) in terms of partial pressures. Kp is defined as the ratio of the products of the partial pressures of the products, each raised to their stoichiometric coefficients in the balanced chemical equation, to the product of the partial pressures of the reactants, each raised to the power of their stoichiometric coefficients. Based on this, the expression is:
Kp = (pCO2 * pH2) / (pCO * pH2O)
where pCO, pH2O, pCO2 and pH2 are the equilibrium partial pressures of CO, H2O, CO2 and H2 at equilibrium, respectively. We know that initially, the partial pressure of CO2 and H2 is 0 because the reaction has not yet occurred. Also, the initial partial pressures of CO and H2O are given as 1320 torr and 1760 torr respectively.
As reaction proceeds to the right, the pressures of CO and H2O will decrease while that of CO2 and H2 will increase. Let's assume the decrease in the pressures of CO and H2O is by x.
Therefore, at equilibrium:
pCO = 1320 - xpH2O = 1760 - xpCO2 = xpH2 = x
So, plug these values into the Kp expression we get:
0.0611 = (x*x) / {[1320 - x]*[1760 - x]}
Solving this quadratic equation will give the value of x.
Substituting 'x' in pCO2 = x will give us the equilibrium partial pressure of CO2.
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The equilibrium partial pressure of CO2 in a chemical reaction can be calculated using an ICE table and the given Kp value in the application of Le Chatelier's principle.
Explanation:The subject of this question is the calculation of the equilibrium partial pressure of CO2 in a chemical reaction according to Le Chatelier’s principle. We first identify the given Kp value and initial partial pressures for CO and H20. Using the equation for the reaction, CO(g) + H2O(g) ⇌ CO2(g) + H2(g), we can create an ICE (Initial, Change, Equilibrium) table to track changes in the partial pressures during the reaction. As the reaction proceeds, the concentrations of CO and H2O decrease while those of CO2 and H2 increase until equilibrium is reached. The changes for CO and H2O are negative while those for CO2 and H2 are positive. Using the equilibrium expressions and the given Kp value, we can solve for the change and add this to the initial concentrations to get the equilibrium concentrations.
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A solution of hydrochloric acid is mixed with an equal volume solution of barium hydroxide. When pH paper is inserted into the resulting solution, the pH was determined to be 7.0. If the initial concentration of the hydrochloric acid solution was 0.5 M, what is the concentration of the barium hydroxide solution?
Please explain your steps and balanced equation.
Please help!
Explain what happens to the pitch of a cell phone ring when the amplitude of a sound wave increases. Justify your reasoning using complete sentences and key vocabulary.
Pitch is sometimes defined as the fundamental frequency of a sound wave. For most practical purposes, this is fine, and pitch and frequency can be thought of as equivalent. On the other hand, for most practical purposes, amplitude can be thought of as volume.
However, technically, pitch and volume are human perceptions. Thus, our perception of pitch and volume are not solely based on frequency and amplitude respectively, but are based on a combination of both. Frequency overwhelming dictates perceived pitch, but amplitude also does have some small, small effect on our pitch perception, especially when it is very large. For example, a very loud sound can have a different perceived pitch than you would predict from its frequency alone.
Hope that helps!
An experiment carries out the reaction a → products at three different initial concentrations of a and the initial reaction rate were measured, as indicated in the table. [a](m) initial rate (m/s) 0.15 0.010 0.30 0.040 0.45 0.090 based on this data, what is the rate law for the reaction? view available hint(s) an experiment carries out the reaction at three different initial concentrations of and the initial reaction rate were measured, as indicated in the table. initial rate 0.15 0.010 0.30 0.040 0.45 0.090 based on this data, what is the rate law for the reaction? rate = k[a]2 rate = k[a]3 rate = k[a] rate = k
name two fluid technologies that make use of water
Answer:
Fire extenguisher and refrigerator
Explanation:
Refrigerator : There are 5 basic components in refrigeration I.e. fluid refrigerant, a compressor which controls the flow of refrigerant; the condensor coil( on the outside of the fridge), evaporation coils( on the inside of the fridge) and something calls an expansion device.
The compressor constricts the refrigerant vapour,raising its pressure and pushes it in the coils on the outside of the refrigerator.When the hot gas in the coils meets the cooler air temperature of the kitchen it becomes a liquid.Now in the liquid form at high pressure, the refrigerant cools down as it flows into the coils inside the freezer and the fridge.The refrigerant absorbs the heat inside the fridge cooling down the air.Last the refrigerant evaporates to a gas then flows back to the compressor where the cycle starts all over.Fire Extinguishers: Water performs two functions; its conversion tosteam absorbs the heat, and the steam displaces the air from the vicinity of the flame. Many siimple fire extinguishers are quipped with hand pumps or sources of compressed gas to propel water through the nozzle.
Hydraulic systems and water turbines are two fluid technologies that make use of water. Hydraulic systems use water or other fluids to transmit force or energy, while water turbines use the flow of water to generate mechanical energy and produce electricity.
Explanation:Two fluid technologies that make use of water are hydraulic systems and water turbines.
Hydraulic systems: These systems use water or other fluids to transmit force or energy. They are commonly used in heavy machinery, such as bulldozers and cranes. The force applied to a small piston can be amplified to produce a much larger force on a larger piston. This is done by Pascal's law, which states that a change in pressure of an enclosed fluid is transmitted uniformly in all directions.Water turbines: These devices use the flow of water to generate mechanical energy, which is then converted into electrical energy. Water turbines are often used in hydroelectric power plants, where the force of flowing water is used to turn the blades of the turbine, which in turn spins a generator to produce electricity.Learn more about Fluid technologies that make use of water here:https://brainly.com/question/9035490
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What is the pH of a solution of 0.750 M KH2PO4, potassium dihydrogen phosphate?
Final answer:
The pH of a 0.750 M KH₂PO₄ solution cannot be accurately determined without additional information such as the pKa value of the dihydrogen phosphate ion (H₂PO₄₋).
Explanation:
The pH of a solution of 0.750 M KH₂PO₄, potassium dihydrogen phosphate, depends on the acid dissociation constants of phosphoric acid (H₃PO₄), as KH₂PO₄ is its conjugate salt. Typically, to calculate the pH of such a solution, one would use the Henderson-Hasselbalch equation which relates the pH of a buffer solution to the pKa of the acid and the concentrations of the acid and its conjugate base.
However, because there is no other species like phosphoric acid or its other salts present to form a buffer system, and because H₂PO₄₋ (from dissociation of KH₂PO₄) is a weak acid, we may need to approach this problem differently.
Since the direct calculation of pH in this context isn't possible without additional information such as the pKa value of the dihydrogen phosphate ion (H₂PO₄⁻), and because the problem does not ask for assumptions to be made or provide a relevant pKa value, the task cannot be completed.
In practical applications, a pKa value would be required to use the Henderson-Hasselbalch equation, or for the weak acid formula: pH = -log[H⁺] where [H⁺] can be obtained through the equilibrium expression involving the dissociation constant (Ka) and the concentration of H₂PO₄⁻.
The reaction of hydrogen peroxide with iodine, h2o2(aq)+i2(aq)⇌oh−(aq)+hio(aq) is first order in h2o2 and first order in i2. if the concentration of h2o2 was increased by half and the concentration of i2 was quadrupled, by what factor would the reaction rate increase?
The reaction rate for H₂O₂(aq) + I₂(aq) ⇌ OH⁻(aq) + HIO(aq) increases by a factor of 6 when the concentration of H₂O₂ is increased by half and the concentration of I₂ is quadrupled.
The rate of a reaction is influenced by the concentrations of the reactants. For the reaction H₂O₂(aq) + I₂(aq) ⇌ OH⁻(aq) + HIO(aq), the rate law is given by: Rate = k[H₂O₂][I₂]
This indicates that the reaction is first order with respect to both H₂O₂ and I₂.
Step-by-Step Explanation:
Initial Reaction Rate: The initial rate can be expressed as Rate_initial = k[H₂O₂]₀[I₂]₀.Change in Concentrations: The concentration of H₂O₂ is increased by half (1.5 times) and the concentration of I₂ is quadrupled (4 times).New Rate Calculation: The new rate can be expressed as Rate_new = k(1.5[H₂O₂]₀)(4[I₂]₀).Rate Increase Factor: To determine by what factor the rate increases, divide the new rate by the initial rate:Rate increase factor = (k(1.5[H₂O₂]₀)(4[I₂]₀)) / (k[H₂O₂]₀[I₂]₀) = 1.5 * 4 = 6.
Therefore, the reaction rate increases by a factor of 6.
Give the empirical formula of a compound that contains 11.6g iron and 5.01 g of oxygen
Calculate the [h+] in a solution that has a ph of 9.88.
The concentration of H⁺ ions present in the solution that has a pH of 9.88 is 1.3 × 10⁻¹⁰M.
What is pH?pH of any solution is define as the negative logarithm of the concentation of H⁺ ions present in the solution and it will be represented as:
pH = -log[H⁺]
After removing log equation becomes,
[H⁺] = [tex]10^{-pH}[/tex]
Given value of pH = 9.88
On putting this value of above equation we get,
[H⁺] = [tex]10^{-9.88}[/tex]
[H⁺] = 1.3 × 10⁻¹⁰M
Hence the concentration of H⁺ ions is 1.3 × 10⁻¹⁰M.
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The reaction 2a → a2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if the initial concentration of a was 4.00 m, what was the concentration of a (in m) after 180.0 min?
The integrated rate law for a second-order reaction is given by:
[tex] \frac{1}{[A]t} = \frac{1}{[A]0} + kt [/tex]
where, [A]t= the concentration of A at time t,
[A]0= the concentration of A at time t=0
k = the rate constant for the reaction
Given: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min
Hence, [tex] \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180) [/tex]
= 4.858
Therefore, [A]t= 0.2058 M.
Answer: Concentration of A, after 180 min, is 0.2058 M
: calculate the mass of the solute in 1.500 l of 0.30 m glucose, c6h12o6, used for intravenous injection
convert the following names to balanced formulas.
lead(IV) sulfide
why is it not Pb2S4 ?
The balanced chemical formula for lead(IV) sulfide is PbS₂, not Pb₂S₄. This correctly balances lead's +4 charge with two sulfur atoms, each with a -2 charge.
Lead(IV) sulfide is a chemical compound consisting of lead (Pb) and sulfur (S). The Roman numeral IV indicates that lead has an oxidation state of +4 in this compound. Sulfur commonly has an oxidation state of -2.
To form a neutral compound, we need to balance the charges. Lead(IV) has a charge of +4, and sulfur has a charge of -2. Therefore, it takes two sulfur atoms to balance one lead atom.
The balanced chemical formula for lead(IV) sulfide is PbS₂, not Pb₂S₄. The latter formula incorrectly represents the proportions since it can be simplified to PbS₂, as both share the same ratio.
Lead (IV) Sulfide: PbS₂Lead has an oxidation state of +4 (Pb₄+).Sulfur has an oxidation state of -2 (S₂-).The formula must balance to zero, i.e., 1(4+) + 2(2-) = 0.Thus, the correct balanced chemical formula is PbS₂.
Write balanced complete ionic equation for the reaction AgNO3(aq)+KCl(aq)→AgCl(s)+KNO3(aq).
Explanation:
A balanced equation is an equation in which number of reactants equal the number of products.
The given equation is as follows.
[tex]AgNO_{3}(aq) + KCl(aq) \rightarrow AgCl(s) + KNO_{3}(aq)[/tex]
Therefore, the ionic equation for the given reaction is as follows.
[tex]Ag^{+}(aq) + NO^{-}_{3}(aq) + K^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s) + K^{+}(aq) + NO^{-}_{3}(aq)[/tex] ....... (1)
Now, cancel [tex]NO^{-}_{3}(aq)[/tex] and [tex]K^{+}[/tex] from both left and right side of the equation (1).
Hence, the net ionic equation will be as follows.
[tex]Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)[/tex]
For the reaction of AgNO3(aq)+KCl(aq)→AgCl(s)+KNO3(aq), the balanced complete ionic equation is Ag+ (aq) + NO3- (aq) + K+ (aq) + Cl- (aq) → AgCl(s) + K+ (aq) + NO3- (aq), which shows the ions involved and distinguishes between the reacting ions forming the precipitate, and the spectator ions.
Explanation:The question is asking for a balanced complete ionic equation, which emphasizes the ions in a chemical equation. For the reaction of AgNO3(aq)+KCl(aq)→AgCl(s)+KNO3(aq), the balanced complete ionic equation would be written as:
Ag+ (aq) + NO3- (aq) + K+ (aq) + Cl- (aq) → AgCl(s) + K+ (aq) + NO3- (aq)
In this equation, Ag+ and Cl- are the ions reacting to form the precipitate AgCl(s), while K+ and NO3- are the spectator ions, which exist in the same form on both reactant and product side of the equation.
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Calculate the heat capacity, in joules per degree and in calories per degree, for 45.8 g of nitrogen gas. [heat capacity of n2(g)= 1.04j/g0c] [1 cal=4.184j]
Answer : The heat capacity in joules per degree Celsius and calories per degree Celsius is, [tex]47.6J/^oC[/tex] and [tex]11.4cal/^oC[/tex] respectively.
Explanation : Given,
Mass of nitrogen gas = 45.8 g
Heat capacity of nitrogen gas = [tex]1.04J/g^oC[/tex]
First we have to calculate the heat capacity in joules per degree Celsius.
As, 1 gram of nitrogen gas has heat capacity = [tex]1.04J/^oC[/tex]
So, 45.8 gram of nitrogen gas has heat capacity = [tex]45.8\times 1.04J/^oC=47.6J/^oC[/tex]
Thus, the heat capacity in joules per degree Celsius is [tex]47.6J/^oC[/tex]
Now we have to calculate the heat capacity in calories per degree Celsius.
As we are given the conversion:
[tex]1cal=4.184J\\\\1J=\frac{1}{4.184}cal[/tex]
So, the heat capacity of nitrogen gas = [tex]\frac{1}{4.184}cal\times 47.6\text{ per }^oC=11.4cal/^oC[/tex]
Thus, the heat capacity in calories per degree Celsius is [tex]11.4cal/^oC[/tex]
The heat capacity, in Joules per degree Celsius and in calories per degree Celsius are 47.632 J/g°C and 11.384 cal/g°C respectively.
Given the following data:
Mass of nitrogen gas = 45.8 gramsHeat capacity of nitrogen gas = 1.04 J/g°CTo find the heat capacity, in Joules per degree Celsius and in calories per degree Celsius:
By direct proportion:
1 gram of nitrogen gas = 1.04 J/g°C
45.8 grams of nitrogen gas = X J/g°C
Cross-multiplying, we have:
[tex]X = 45.8 \times 1.04[/tex]
X = 47.632 J/g°C.
Therefore, the heat capacity, in Joules per degree Celsius, for 45.8 grams of nitrogen gas is 47.632 J/g°C.
In calories per degree Celsius:
1 calorie = 4.184 Joules
Y calorie = 47.632 Joules
Cross-multiplying, we have:
[tex]Y \times 4.184 = 47.632\\\\Y = \frac{47.632}{4.184}[/tex]
Y = 11.384 cal/g°C.
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Why is the percentage of food eaten a good number to use ? Explain
The part of the flower that becomes a fruit to protect the seeds is the _______. stigma style ovary anther
ovary is your answer dude
classify correct or incorrect.
Convection only occurs in liquids?
All substances radiate heat?
our body temp. is always equal to the temp. around us?
Answer:
1. Incorrect, it occurs in gases as well or generally in fluids.
2. Correct.
3. Incorrect.
Explanation:
Hello,
1. Convection, is a heat transport phenomena which occurs when a fluid transfers energy in the form of heat to a surface or vice-versa, in such a way, it occurs fluid, say, in both gases and liquids.
2. In this case, radiation is a heat transfer phenomena which occurs by thermal waves transferring the heat; such waves are generated by a hot body which it is said to irradiate the waves by cause of its inner temperature, therefore, as it could be surrounded by a colder space, heat is transferred. As a result of the high temperature, all substances could radiate heat.
3. In this case, it is widely known that normal temperature is between 20 and 25 ºC while the body's inner temperature is about 37 ºC for our organism to work properly. In such a way, those temperatures are different.
Best regards.
The sticky top of the pistil that collects the pollen (sperm) is the _______. ovary
style
stigma
anther
This solution contains equal concentrations of both hf(aq) and naf(aq). write the proton transfer equilibrium (net ionic) reaction that includes f– as a reactant. include states of matter.
In a reaction of NaF and H₂O, NaOH and HF is produced.
The reaction can be shown as follows:
HF(aq.) + OH⁻(aq.) ----->F⁻(aq.) + H₂O(l)
Or it can be shown as below:
Here the reactants are: NaF, H₂O
While the product is: NaOH, HF
So the reaction in ionic can be shown as:
HF(aq.) + OH⁻(aq.) ----->F⁻(aq.) + H₂O(l)
So the reaction can be that includes the states of matter too can be:
HF(aq.) + OH⁻(aq.) ----->F⁻(aq.) + H₂O(l)
which is a dangerous thing to do when working with flames in a laboratory?
Write balanced chemical equations for the two ionization steps of sulfuric acid
Sulfuric acid ionizes in two steps, each releasing a hydrogen ion to form first the bisulfate ion and then the sulfate ion. The first is H2SO4 (aq) → H+ (aq) + HSO4- (aq) and the second is HSO4- (aq) → H+ (aq) + SO4^2- (aq).
Explanation:The ionization of sulfuric acid (H2SO4) in water occurs in two steps. Each step involves the release of a hydrogen ion (H+), and the corresponding production of the hydronium ion (H3O+) is generally implied when the acid ionizes in aqueous solution.
First Ionization: H2SO4 (aq) → H+ (aq) + HSO4- (aq).This is the first ionization step where one hydrogen ion is released, creating the bisulfate ion (HSO4-).
Second Ionization: HSO4- (aq) → H+ (aq) + SO4^2- (aq). In the second ionization step, the bisulfate ion (HSO4-) releases a second hydrogen ion, resulting in the sulfate ion (SO4^2-).
Both of these equations are balanced chemical equations that depict the stepwise ionization of sulfuric acid and the formation of its conjugate bases.
Two teaspoons of salt are added to a glass of water which is then stirred until no more salt grains can be seen. Two more teaspoons are added and stirring is continued, but the salt grains are still evident in the glass and settle to the bottom. After the addition of the last two teaspoons of salt the solution is ___________________________.
nonpolar
polar
saturated
unsaturated
Answer: C
Explanation: I got it right
dentify which stage of the listening process is occurring in the following scenario.
Janie excitedly told her mom about a party her friend Reeve had invited her to. She promised that there would be adult supervision and begged to be allowed to go. Her mom hesitated and then said she wanted to talk to Reeve's parents first.
selecting
understanding
evaluating
responding
remembering
In this situation, the listening process stage being implemented is 'evaluating'. Janie's mom is assessing the details of the party and deciding about its validity and reliability, which indicates this stage.
Explanation:In the given scenario, the stage of the listening process that is taking place is evaluating. The event happens as Janie's mom listens to Janie's account of the party and makes a judgment about it. It means she's weighing the information she has received and is deciding on its validity and reliability. After listening to the information, she makes an evaluation that requires her to speak to Reeve's parents first before making a decision. This is the evaluating stage, where she is assessing and judging the information she has received.
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if f(x)= 5x^3 -2 and g(x) =2x+1, find (f+g)(x)
a. 10x^3 -2
b. 3x^3 -1
c. 5x^3+2x-1
d. 3x^2 -1
Consider these reactions, where M represents a generic metal. 2M(s)+6HCl(aq)⟶2MCl3(aq)+3H2(g)ΔH1=−556.0 kJ HCl(g)⟶HCl(aq) ΔH2=−74.8 kJ H2(g)+Cl2(g)⟶2HCl(g) ΔH3=−1845.0 kJ MCl3(s)⟶MCl3(aq) ΔH4=−342.0 kJ Use the given information to determine the enthalpy of the reaction 2M(s)+3Cl2(g)⟶2MCl3(s)
The enthalpy of formation of [tex]\rm MCl_3[/tex] will be -5849 kJ.
The given reactions represent:
Enthalpy of reaction of M with HCl = [tex]\rm \Delta H_1[/tex] = -556 kJ
Enthalpy of sublimation of HCl = [tex]\rm \Delta H_2[/tex] = -74.8 kJ
Enthalpy of HCl formation = [tex]\rm \Delta H_3[/tex] = -1845 kJ
Enthalpy of sublimation of [tex]\rm MCl_3\;=\;\Delta H_4[/tex] = -342.0 kJ
The enthalpy of formation of [tex]\rm MCl_3[/tex] will be: [tex]\rm \Delta H_5[/tex]
[tex]\rm \Delta H_5[/tex] = [tex]\rm \Delta H_1\;+\;6\;\times\;\Delta H_2\;+\;3\;\times\;\Delta H_3\;-\;2\;\times\;\Delta H_4[/tex]
= -550 + 6 (-74.8) + 3 (-1845) - 2 (342)
= -5849 kJ.
The enthalpy of formation of [tex]\rm MCl_3[/tex] will be -5849 kJ.
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oxidation states of N2 + 3H2 --> 2NH3
liam uses a machine that counts waves on a metal cable. The machine counts 25 waves in 2 seconds. what is the frequency of the wave?
Final answer:
The frequency of the waves on the metal cable that Liam is using is calculated by dividing the number of waves, which is 25, by the time period over which they are counted, which is 2 seconds. This results in a frequency of 12.5 Hertz (Hz).
Explanation:
The question asks us to determine the frequency of a wave given the number of waves and the time it took for those waves to be counted. In this case, Liam's machine counts 25 waves in 2 seconds. Frequency is the number of waves that pass a given point in one second, and it is measured in Hertz (Hz).
To calculate the frequency, you divide the number of waves by the period. Using the information from the question:
Count of waves passing by 25 wavesTime period: 2 seconds.Frequency (f) = Number of waves / Time (T) = 25 waves / 2 s = 12.5 Hz. Hence, the frequency of the waves on the metal cable is 12.5 Hertz.