Given the differential Equation y'+2y=2e^x ;solve this equation using the integration factor; solve for y to get the general solution.

Answer:

y=-3/4x-1/2

Step-by-step explanation:

Using the slope equation,

m=y₂-y₁

    ____

     x₂-x₁

you get the slope:

m=-5-1/6+2

m=-6/8

m=-3/4

We find that the intercept is -1/2.

The equation is y=-3/4x-1/2

The answer is:

The equation of the line that passes through the points (-2,1) and (6,-5) is:

[tex]y=-\frac{3}{4}x-\frac{1}{2}[/tex]

To solve the problem, we can use the following formula:

We have that:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)[/tex]

So, using the given points (-2,1) and (6,-5), we have:

[tex]y-1=\frac{-5-1}{6-(-2)}*(x-(-2))[/tex]

[tex]y-1=\frac{-6}{6+2}*(x+2)[/tex]

[tex]y-1=\frac{-6}{8}*(x+2)[/tex]

[tex]y-1=-\frac{3}{4}*(x+2)[/tex]

[tex]y=-\frac{3}{4}*(x+2)+1[/tex]

[tex]y=-\frac{3}{4}*(x)-\frac{3}{4}**(2)+1[/tex]

[tex]y=-\frac{3}{4}(x)-\frac{6}{4})+1[/tex]

[tex]y=-\frac{3}{4}(x)-\frac{3}{2})+1[/tex]

[tex]y=-\frac{3}{4}x-\frac{1}{2}[/tex]

Hence, we have that the equation of the line that passes through the points (-2,1) and (6,-5) is:

[tex]y=-\frac{3}{4}x-\frac{1}{2}[/tex]

Have a nice day!

Answer:

The probability that a randomly selected person is not color blind is 0.958

Step-by-step explanation:

Given,

C represents red-green color blindness,

Also, the probability that a randomly selected person is color blind,

P(C) = 0.042,

Thus, probability that a randomly selected person is not color blind,

P(C') = 1 - P(C) = 1 - 0.042 = 0.958

Answer: 0.074

Step-by-step explanation:

Given : The total number of U.S. adults in the sample = 800

The number of U.S. adults dine out at a restaurant more than once a week = 216

The probability for an adult dine out more than once per week :-

[tex]\dfrac{218}{800}[/tex]

If another person is selected without replacement ,then

Total adults left = 799

Total adults left who dine out at a restaurant more than once a week = 217

The probability for the second person dine out more than once per week :-

[tex]\dfrac{217}{799}[/tex]  

Now, the probability that both adults dine out more than once per week :-

[tex]\dfrac{218}{800}\times\dfrac{217}{799}=0.074[/tex]

Final answer:

To calculate the probability that both selected adults dine out more than once per week, multiply the probability of the first adult dining out more than once (218/800) by the probability of the second adult dining out more than once after the first has been selected (217/799).

Explanation:

The probability that both adults dine out more than once per week can be found using the formula for the probability of successive events without replacement. With 218 out of 800 US adults dining out more than once per week, the probability of the first adult dining out more than once is 218/800. If one adult who dines out more than once a week has been chosen, there are now 217 such adults left and 799 total adults. The probability of the second adult dining out more than once is 217/799. The joint probability of both events happening is calculated by multiplying these two probabilities together:

P(both dine out) = (218/800)
times (217/799)

Simplify this to find the requested probability.

Answer:

D. Stanley Kubrick

Step-by-step explanation:

Answer:

[tex]\Large\textnormal{(D.) Stanley Kubrick}[/tex]

Step-by-step explanation:

Stanley Kubrick directed to Dr. Strangelove. I hope this helps, and have a wonderful day!

Answer:

The correct dosage is 0.5 ml

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

We can solve this question by using the simple Rule of Three property. The Property is the following

[tex]\frac{a}{x} = \frac{b}{c}[/tex] ⇒ [tex]x = \frac{a*c}{b}[/tex]

Now we can use the property above using the values given to us to find the correct dosage for the patient.

[tex]\frac{0.2mg}{x} = \frac{0.4mg}{1ml}[/tex]

[tex]x = \frac{0.2mg*1ml}{0.4mg}[/tex]

[tex]x = \frac{0.2ml}{0.4}[/tex]

[tex]x = 0.5ml[/tex]

So Now we can see that the correct dosage is 0.5 ml

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

[tex]2 \frac{5}{8}[/tex], or [tex]\frac{21}{8}[/tex]

Use the Keep Change Flip method.  Change the sign to multiplication and flip the second fraction.  [tex]\frac{3}{8}*\frac{7}{1}[/tex]

Multiply the numerators and the denominators separatley.  [tex]\frac{3*7}{8*1}=\frac{21}{8}[/tex]

This cannot be simplified further, but it can be converted to a mixed number (as opposed to an improper fraction).  [tex]\frac{21}{8}=2 \frac{5}{8}[/tex]

Answer:

D.  2 5/8

Step-by-step explanation:

3/8÷1/7=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

3/8×7/1=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

3×7/8×1= 21/8

This fraction cannot be reduced.

The fraction

2/18

is the same as

21÷8

Convert to a mixed number using

long division for 21 ÷ 8 = 2R5, so

2/18= 2 5/8

Therefore:

3/8÷1/7= 2 5/8

Answer:

The current yield is 3.11%.

Step-by-step explanation:

Given - A $500 Treasury bond with a coupon rate of 2.8% that has a market value of $450.

Now the face value of the bond is = $500

The rate of interest is = 2.8%

Then interest on $500 becomes:

[tex]0.028\times500=14[/tex] dollars

The current market value is $450

So, current yield is = [tex]\frac{14}{450}\times100= 3.11[/tex]%

The current yield is 3.11%.

Final answer:

The current yield on a $500 Treasury bond with a 2.8% coupon rate and a market value of $450 is 3.11%, calculated by dividing the annual coupon payment by the market value of the bond and then converting to a percentage.

Explanation:

To calculate the current yield on the described $500 Treasury bond with a coupon rate of 2.8% that has a market value of $450, follow these steps:

Therefore, the current yield on the bond is 3.11% when rounded to two decimal places.

Answer:

(a) 2 × 10^9 kg/m^3; (b) roughly the mass of the Statue of Liberty.

Step-by-step explanation:

(a) Density of white dwarf:

D = m/V

Data:

 1 solar mass = 2 × 10^30 kg

1 Earth radius = 6.371 × 10^6 m

Calculations:

V = (4/3)πr^3 = (4/3)π × (6.371 × 10^6 m)^3 = 1.083 × 10^21 m^3

D = 2 × 10^30 kg/1.083 × 10^21 m^3 = 2 × 10^9 kg/m^3

2. Weight on a white dwarf

The formula for weight is

w = kMm/r^2

where

k = a proportionality constant

M = mass of planet

m = your mass

w(on dwarf)/w(on Earth) = [kM(dwarf)m/r^2] /[kM(Earth)m/r^2

k, m, and r are the same on both planets, so

w(on dwarf)/w(on Earth) = M(dwarf)/M(Earth)

w(on dwarf) = w(on Earth) × [M(dwarf)/M(Earth)]

Data:

M(Earth) = 6.0 × 10^24 kg

Calculation:

w(on dwarf) = w(on Earth) × (2 × 10^30 kg /6.0 × 10^24 kg)

= 3.3 × 10^5 × w(on Earth)

Thus, if your weight on Earth is 60 kg, your weight on the white dwarf will be

3.3 × 10^5 × 60 kg = 2 × 10^7 kg  

That's roughly as heavy as the Statue of Liberty is on Earth.

Answer:

The given statement is FALSE.

Step-by-step explanation:

If p1, p2, . . . , pn are prime, then A = p1p2 . . . pn1 + 1 is also prime.

No, this statement is false.

Let's take an example:

We take two prime numbers.

p1 = 3

p2 = 5

Now p1p2+1 becomes :

[tex](3\times5)+1=16[/tex]

And we know that 16 is not a prime number.

Note : A prime number is a number that is only divisible by 1 and itself like 3,5,7,11 etc.

Answer: 0.0018

Step-by-step explanation:

Binomial distribution formula :-

[tex]P(x)=^nC_xp^x(q)^{n-x}[/tex], here P(x) is the probability of getting success at x trial , n is the total number of trails, p is the probability of getting success in each trail.

Given : The probability that a child in the U.S. was living with both parents : p=0.70 ; q=1-0.70=0.30

If 25 children were selected at random in the U.S.,then the probability that at most 10 of them will be living with both of their parents will be :-

[tex]P(x\leq10)=P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)+P(9)+P(10)\\\\=^{25}C_{0}(0.7)^0(0.3)^{25}+^{25}C_{1}(0.7)^1(0.3)^{24}+^{25}C_{2}(0.7)^2(0.3)^{23}+^{25}C_{3}(0.7)^3(0.3)^{22}+^{25}C_{4}(0.7)^4(0.3)^{21}+^{25}C_{5}(0.7)^5(0.3)^{20}+^{25}C_{6}(0.7)^6(0.3)^{19}+^{25}C_{7}(0.7)^7(0.3)^{`18}+^{25}C_{8}(0.7)^8(0.3)^{17}+^{25}C_{9}(0.7)^9(0.3)^{16}+^{25}C_{10}(0.7)^{10}(0.3)^{15}\\\\=(0.7)^0(0.3)^{25}+25(0.7)^1(0.3)^{24}+300(0.7)^2(0.3)^{23}+2300(0.7)^3(0.3)^{22}+ 12650(0.7)^4(0.3)^{21}+53130(0.7)^5(0.3)^{20}+177100(0.7)^6(0.3)^{19}+480700(0.7)^7(0.3)^{`18}+1081575(0.7)^8(0.3)^{17}+2042975(0.7)^9(0.3)^{16}+3268760(0.7)^{10}(0.3)^{15}\\\\=0.00177840487034\approx0.0018[/tex]

Hence, the probability that at most 10 of them will be living with both of their parents is 0.0018.

The possible formula for a fourth degree polynomial g is:

         [tex]g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)[/tex]

We know that if a polynomial has zeros as a,b,c and d then the possible polynomial form is given by:

[tex]f(x)=m(x-a)(x-b)(x-c)(x-d)[/tex]

Here the polynomial g  has a double zero at -2, g(4) = 0, g(3) = 0.

This means that the polynomial g(x) is given by:

[tex]g(x)=m(x-(-2))^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x+2)^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x^2+2^2+2\times 2\times x)(x(x-3)-4(x-3))\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-3x-4x+12)\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-7x+12)\\\\i.e.\\\\g(x)=m[x^2(x^2-7x+12)+4(x^2-7x+12)+4x(x^2-7x+12)]\\\\i.e.\\\\g(x)=m[x^4-7x^3+12x^2+4x^2-28x+48+4x^3-28x^2+48x]\\\\i.e.\\\\g(x)=m[x^4-7x^3+4x^3+12x^2+4x^2-28x^2-28x+48x+48]\\\\i.e.\\\\g(x)=m[x^4-3x^3-12x^2+20x+48][/tex]

Also,

[tex]g(0)=12[/tex]

i.e.

[tex]48m=12\\\\i.e.\\\\m=\dfrac{12}{48}\\\\i.e.\\\\m=\dfrac{1}{4}[/tex]

Hence, the polynomial g(x) is given by:

[tex]g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)[/tex]

The formula for the fourth degree polynomial g(x) can be determined using the known roots and points. The polynomial will have form g(x) = a(x+2)² × (x-3) × (x-4). Value of 'a' is found by setting x=0 and solving for a.

The subject of the question is determining the formula for a fourth degree polynomial, g(x), based on provided conditions. From the question we know that g(x) must have a double root at -2 (-2, -2); roots 3 and 4 (3, 0) and (4, 0); and that g(0) = 12.

With this information, we know that a fourth degree polynomial will look something like this: g(x) = ax4 + bx3 + cx2 + d = 0. But, per the conditions, it looks like g(x) = a(x+2)2 × (x-3) × (x-4), because it has roots at x = -2 (twice, or 'double'), x = 3, and x = 4.

To find the value of 'a', we use the information that at x = 0, g(x) should equal to 12. The function can then be processed as follows:

g(0) = a(0+2)2 × (0-3) × (0-4) = 12.

This will give us 'a', and the desired polynomial formula.g(x).

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Answer:

a= 8 ways

b. 20

Step-by-step explanation:

Palindrome of length 6 means first three digits must be same as the last three in reverse. For example 123321 is palindrome of six digits.

There 2 bits 0 and 1

a.So each of first three digits can be filled in 2 ways

therefore, 2*2*2= 8 ways

number of different palindromes of 6 digits will be 8

b. In a 6 digit a palindrome there Are 6 spaces in which 3 spaces are to be filled with 1's

this cab be done in

[tex]_{6}^{3}\textrm{C}= \frac{6!}{3!\times3!}[/tex]

= 20

Answer: [tex]x+2y-7=0[/tex]

Step-by-step explanation:

We know that the equation of a line passing through points (a,b) and (c,d) is given by :-

[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]

Then , the equation of a line passing through points (3,2) and (1,3) is given by :-

[tex](y-2)=\dfrac{3-2}{1-3}(x-3)\\\\\Rightarrow\ (y-2)=\dfrac{1}{-2}(x-3)\\\\\Rightarrow\ -2(y-2)=(x-3)\\\\\Rightarrow\ -2y+4=x-3\\\\\Rightarrow\ x+2y-7=0[/tex]

Hence, the equation of a line passing through points (3,2) and (1,3) is : [tex]x+2y-7=0[/tex]

Answer:

Step-by-step explanation:

Let's rewrite this with dy/dx in place of y', since they mean the same thing.  But to solve a differential we will need to take the antiderivative by separation to find the general solution.

[tex]\frac{dy}{dx}+xy=x[/tex]

The goal is to get the x stuff on one side and the y stuff on the other side by separation.  But we have an xy term there that we need to be able to break apart.  So let's get everything on one side separate from the dy/dx and take it from there.

[tex]\frac{dy}{dx}=x-xy[/tex]

Now we can factor out the x:

[tex]\frac{dy}{dx}=x(1-y)[/tex]

And now we can separate:

[tex]\frac{dy}{(1-y)}=x dx[/tex]

Now we solve by taking the antiderivative of both sides:

[tex]\int\ {\frac{1}{1-y}dy }=\int\ {x} \, dx[/tex]

On the left side, the antiderivative of the derivative of y cancels out, and the other part takes on the form of the natural log, while we follow the power rule backwards on the right to integrate x:

[tex]ln(1-y)=\frac{1}{2}x^2+C[/tex]

That's the general solution.  Not sure what your book has you solving for.  Some books solve for the constant, C. Some solve for y when applicable.  I'm leaving it like it is.

Notice that

[tex](2x^3-xy^2-2y+3)_y=-2xy-2[/tex]

[tex](-x^2y-2x)_x=-2xy-2[/tex]

so the ODE is exact, and we can find a solution [tex]F(x,y)=C[/tex] such that

[tex]F_x=2x^3-xy^2-2y+3[/tex]

[tex]F_y=-x^2y-2x[/tex]

Integrating both sides of the first equation wrt [tex]x[/tex] gives

[tex]F(x,y)=\dfrac{x^4}2-\dfrac{x^2y^2}2-2xy+3x+g(y)[/tex]

Differentiating wrt [tex]y[/tex] gives

[tex]F_y=-x^2y-2x=-x^2y-2x+g'(y)\implies g'(y)=0\implies g(y)=C[/tex]

So we have

[tex]\boxed{F(x,y)=\dfrac{x^4}2-\dfrac{x^2y^2}2-2xy+3x=C}[/tex]

The solution to this complex differential equation requires knowledge in calculus and differential equations. Without additional context, it's impossible to provide a specific solution. However, exploring technique utilization such as exact differential equations, integrating factors and substitution would be beneficial.

To solve the given differential equation, which is (2x^3 - xy^2 - 2y + 3)dx - (x^2y + 2x)dy = 0, we will use an approach of factorization or grouping like terms to simplify the equation. In some cases, you might need to rearrange terms and identify if it's a special type of differential equation, like exact, separable, or homogeneous, and then apply the relevant techniques accordingly.

This difficult task requires excellent knowledge in calculus and differential equations. Unfortunately, due to the complexity of this particular equation, without additional context or information, it is impossible to provide a specific solution. I would recommend you to go through topics such as exact differential equations, as well as methods involving integrating factors and substitution. These may help you to analyze and solve this complex equation.

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Answer: [tex](2.20,\ 5.26)[/tex]

Step-by-step explanation:

The confidence interval for the standard deviation is given by :-

[tex]\left ( \sqrt{\dfrac{(n-1)s^2}{\chi^2_{n-1,\alpha/2}}},\ \sqrt{\dfrac{(n-1)s^2}{\chi^2_{n-1,1-\alpha/2}}} \ \right )[/tex]

Given : n= 12 ; s= 3.1

Significance level : [tex]\alpha=1-0.95=0.05[/tex]

Using Chi-square distribution table ,

[tex]\chi^2_{11,0.025}}=21.92\\\\\chi^2_{11,0.975}}=3.82[/tex]

Now, the 95% confidence interval for the standard deviation of the height of students at UH is given by :-

[tex]\left ( \sqrt{\dfrac{(11)(3.1)^2}{21.92}},\ \sqrt{\dfrac{(11)(3.1)^2}{3.82}} \ \right )\\\\=\left ( 2.19602743525, 5.26049188471\right )\approx(2.20,\ 5.26)[/tex]

To construct a 95% confidence interval for the standard deviation of the height of students at UH, use the chi-square distribution.

To construct a 95% confidence interval for the standard deviation of the height of students at UH, we can use the chi-square distribution. Since the population standard deviation is unknown, we need to use the sample standard deviation as an estimate. The formula to calculate the confidence interval is:

Lower limit = ((n-1) * s^2) / X^2

Upper limit = ((n-1) * s^2) / X^2

Where n is the sample size, s is the sample standard deviation, and X^2 is the chi-square critical value corresponding to the desired confidence level and degrees of freedom (n-1).

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Answer: 24

Step-by-step explanation:

The formula to calculate the sample size is given by :-

[tex]n=(\frac{z_{\alpha/2}\ \sigma}{E})^2[/tex]

Given : Margin of error : [tex]E=0.5[/tex]

The significance level : [tex]\alpha=1-0.90=0.1[/tex]

Critical value : [tex]z_{0.05}=\pm1.645[/tex]

Standard deviation : [tex]\sigma=1.5[/tex]

Now, the required sample size will be :-

[tex]n=(\frac{1.645\times1.5}{0.5})^2=24.354225\approx24[/tex]

Hence, the required sample size = 24

Answer:

A : 52-2

B : 0!

C : 312

D : 140608

Step-by-step explanation:

Part A:

It is given that that cards are selecting from a deck without replacing. So,

The number of ways to draw first card = 52

Now, one card is draw. The remaining cards are 51.

The number of ways to drawn second card = 52 - 1 =51

Now, one more card is drawn. The remaining cards are 50.

The number of ways to drawn third card = 52 - 2 =50

Therefore the number of ways to draw the 3 card is 52-2.

Part B:

Let a word has n letters and we need to find the number of permutations of all letters in a word, then the permutation formula is

[tex]^nP_n=\frac{n!}{(n-n)!}=\frac{n!}{0!}[/tex]

The denominator of the calculation is 0!.

Part C:

Total number of cards is a normal deck = 52

Total number sides in a die = 6

Total number of ways to draw a card from a normal deck and roll a number on a normal die = 52 × 6 = 312.

Therefore the total number of ways to draw a card from a normal deck and roll a number on a normal die is 312.

Part D:

It is given that we pick cards from a normal deck of cards, one at a time and replace the card and reshuffle the deck between draws.

Total number of ways to select each card = 52

Total number of ways to select 3 cards = 52³ = 140608

Therefore the total number of ways to select 3 cards is 140608.

Answer:5.8

Step-by-step explanation:

Given

weight of chair with person on it =2118 N

Barber applies a force of 63 N

Using pascal's law

we know pressure around both sides is equal

i.e. [tex]P_{chair}=P_{piston}[/tex]

pressure=[tex]\frac{force}{area}[/tex]

[tex]P_{chair}[/tex]=[tex]\frac{2118}{\pi \dot r_{plunger}^2}[/tex]

[tex]P_{piston}[/tex]=[tex]\frac{63}{\pi \dot r_{piston}^2}[/tex]

substituting values

[tex]\left [\frac{r_{plunger}^2}{r_{piston}^2}\right ][/tex]=[tex]\frac{2118}{63}[/tex]

[tex]\left [\frac{r_{plunger}}{r_{piston}}\right ][/tex]=[tex]\left [ \frac{2118}{63}\right ]^{0.5}[/tex]

[tex]\left [\frac{r_{plunger}}{r_{piston}}\right ][/tex]=5.798

Select all the levels of measurement for which data can be qualitative.A.Nominal.B.IntervalC.RatioD.Ordinal

ratio

Answer:

To find out how much trim you would need for the window, you would need to calculate the Circumference.

Step-by-step explanation:

Circumference is the length around a circle and is calculated using the following formula.

[tex]C = 2\pi r[/tex]

In which C is the circumference and r is the radius. Since we already know the radius all we have to do is plug it into the equation and solve for C.

[tex]C = 2\pi (4.2)[/tex]

[tex]C = 26.389 ft[/tex]

Answer: The window has a Circumference of 26.389 feet so you would need that amount of trim to fit the area around the window.

Hope my answer would be a great help for you.    

If you have more questions feel free to ask here at Brainly.  

Approximately 27 feet of trim would be needed to go around a window with a radius of 4.2 feet.

To calculate the amount of trim needed to go around a round window with a radius of 4.2 feet, we can use the formula for the circumference of a circle. The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle. In this case, the radius is 4.2 feet. Plugging in the value of the radius into the formula, we get C = 2π(4.2) = 8.4π feet. Since we want the amount of trim needed, we can simply round the answer to the nearest whole number. Therefore, approximately 27 feet of trim would be needed to go around the window.

Answer:

The quotient is: x-7

The remainder is: -2

Step-by-step explanation:

We need to divide (x^2 - 13x +40) divided by (x- 6)

The quotient is: x-7

The remainder is: -2

The division is shown in the figure attached

Answer:  [tex]\dfrac{1}{100,000}[/tex]

Step-by-step explanation:

Given : The total number of digits in number system (0 to 9) = 10

The number of digits in a social security number = 9

After last four digits are printed, the number of digits remaining to print = 9-4=5

Since , repetition of digits is allowed, then the total number of ways to print 5 remaining digits is given by :-

[tex]10\times10\times10\times10\times10=100,000[/tex]

Now, the probability of getting the correct Social Security number of the person who was given the​ receipt is given by:-

[tex]\dfrac{\text{Number of correct code}}{\text{Total number of codes}}\\\\=\dfrac{1}{100,000}[/tex]

Final answer:

The probability of correctly guessing an entire Social Security number with the last four digits known is 0.001%, calculated by multiplying the probability of guessing each of the five unknown digits correctly, which is 1/10, resulting in (1/10)^5 or 1/100,000.

Explanation:

The question asks about the probability of correctly guessing an entire Social Security number given the last four digits. A Social Security number has nine digits and the digits can be repeated. If you know the last four digits, you need to guess the first five correctly.

Since each digit can be any number from 0 to 9, there are 10 possibilities for each digit. The probability of guessing one digit correctly is 1 out of 10 (1/10). To find the probability of guessing all five correctly, you need to multiply the probability for each digit, so the probability for all five is (1/10) x (1/10) x (1/10) x (1/10) x (1/10), which equals 1/100,000 or 0.00001. Therefore, the probability of getting the correct Social Security number is 0.00001 or 0.001%.

Answer:

The cumulative percentage of fathers who completed only elementary school is nearle 33%.

Step-by-step explanation:

Among 30 fathers:

You can fill these numbers into the table:

[tex]\begin{array}{cccc}&\text{Frequency}&\text{Cumulative frequency}&\text{Cumulative percentage}\\\text{Elementary school}&10&10&\approx 33\%\\\text{El. and high school}&10&20&\approx 67\%\\\text{El., high schools and college}&7&27&90\%\\\text{El., high, college and grad. sch.}&3&30&100\%\end{array}[/tex]

The cumulative percentage of fathers who completed only elementary school is nearle 33%.

Answer: 33%

Step-by-step explanation:

Answer:

The answer is [tex]\frac{11}{26}[/tex]

Step-by-step explanation:

Total number of cards in the deck = 52

Number of clubs = 13

Number of picture cards = 12

Number of picture cards that are clubs = 3

So, number of picture cards or clubs = [tex]13+12-3=22[/tex]

P(club or picture) = [tex]\frac{22}{52} =\frac{11}{26}[/tex]

The answer is [tex]\frac{11}{26}[/tex].

To determine the probability of selecting a club or a picture card from a standard deck of 52 cards, calculate the number of favorable outcomes and divide it by the total number of possible outcomes.

To determine the probability that a card selected from a standard deck of 52 cards is a club or a picture card, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.

There are 13 clubs and 12 picture cards (Jacks, Queens, and Kings) in a deck. However, we need to subtract the Queen of Clubs, as it has already been selected. So, the number of favorable outcomes is 13 + 12 - 1 = 24.

The total number of possible outcomes is 52, as there are 52 cards in a standard deck.

Therefore, the probability of selecting a club or a picture card is 24/52, which simplifies to 6/13 or approximately 0.4615.

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Answer: 0.7506

Step-by-step explanation:

Given :Mean : [tex]\mu=\text{ 7.8 grams}[/tex]

Standard deviation : [tex]\sigma =\text{ 0.2 grams}[/tex]

The formula for z -score :

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x= 7.65 ,

[tex]z=\dfrac{7.65-7.8}{0.2}=-0.75[/tex]

For x= 8.2 ,

[tex]z=\dfrac{8.2-7.8}{0.2}=2[/tex]

The p-value = [tex]P(-0.75<z<2)=P(z<2)-P(z<-0.75)[/tex]

[tex]=0.9772498-0.2266274=0.750622\approx0.7506[/tex]

Hence, the probability that the amount of protein is between 7.65 and 8.2 grams=0.7506.

Final answer:

To calculate the probability of a Kashi GoLean Crisp Chocolate Caramel bar having a protein content between 7.65 and 8.2 grams, we use the Z-score formula. The probability is found to be approximately 75.06%.

Explanation:

To find the probability that a randomly selected Kashi GoLean Crisp Chocolate Caramel bar has a protein content between 7.65 and 8.2 grams, we use the Z-score formula for a normal distribution, where Z = (X - μ) / σ. Here, μ (mu) is the mean, and σ (sigma) is the standard deviation. The mean (μ) is 7.8 grams, and the standard deviation (σ) is 0.2 grams.

To find the Z-scores for 7.65 grams and 8.2 grams:

Next, we consult the standard normal distribution table to find the probabilities corresponding to these Z-scores. For Z = -0.75, the probability is approximately 0.2266, and for Z = 2, it's approximately 0.9772.

The probability that the protein is between 7.65 and 8.2 grams is the difference between these two probabilities: 0.9772 - 0.2266 = 0.7506 or 75.06%.

Answer:

[tex]6^4[/tex]

Step-by-step explanation:

We'd solve the exponents first:

[tex]6^5 = 7776[/tex]

[tex]6^4 = 1296[/tex]

Subtract:

7776 - 1296 = 6480

Divide:

[tex]6480\div5 = 1296[/tex]

We already know [tex]6^4 = 1296[/tex]

Our answer is [tex]6^4[/tex]

Answer:

6^4

Step-by-step explanation:

6^5 - 6^4 / 5 = ?

Factor out a 6^4

6^4(6-1)

---------------

5

Simplify

6^4(5)

---------------

5

Cancel the 5's

6^4

Answer:

[tex]30=2\: *3\:*5[/tex]

Step-by-step explanation:

We analyze between which prime numbers we can divide the number 30. The smallest prime number by which we divide is 2. Then:

[tex]\frac{30}{2}=15[/tex]

We now look for the smallest prime number that divides the 15. Since 15 is not a multiple of 2, we make the division with the number 3 that is divisor of 15.

[tex]\frac{15}{3}=5[/tex]

We now look for a number that divides to 5, but since 5 is a prime number, the only divisor other than 1 is 5. Then:

[tex]\frac{5}{5}=1[/tex]

This ends the decomposition of 30 and we find 3 prime factors:

2,3 and 5.

Answer:

250 minutes

Step-by-step explanation:

Given,

Cell phone charges for a month = $ 5.00,

Additional charges per minute = $0.20,

Let the cell phone is used for x minutes for a month such that the total bill is $ 55,

⇒ Cell phone charge for the month + additional charges for x minutes = $ 55

⇒ 5.00 + 0.20x = 55

Subtracting 5 on both sides,

0.20x = 50

x = 250,

Hence, the cell phone is used for 250 minutes.

Third option is correct.

Answer:

x = 5 cos 2t

Step-by-step explanation:

given equation

x'' + 4x = 0 ;     x(0) = 5,       x'(0) = 0

L{ x'' + 4 x } = 0

L{x''} + 4 L{x} = 0

s² . L(x) - s . x(0) - x'(0) + 4 L{x} = 0

( s² + 4 ).  L(x) - 5 s = 0

L(x) = [tex]\dfrac{5s}{s^2 +4}[/tex]

[tex]L(\dfrac{s}{s^2 +a^2})[/tex]  = cos at

so,

x = 5  [tex]L^{-1}(\dfrac{s}{s^2 +2^2})[/tex]

x = 5 cos 2t