Given the function g(x)=x^2+10x+23g(x)=x
2
+10x+23, determine the average rate of change of the function over the interval -8\le x \le -4−8≤x≤−4.

Answers

Answer 1

The average rate of change of the function g(x) over the interval from x = -8 to x = -4 is -2.

The average rate of change of a function over a certain interval is similar to finding the slope of the secant line that passes through the points on the graph of the function corresponding to the end points of the interval. In this case, for the function g(x) = x^2 + 10x + 23, we want to find the average rate of change over the interval from x = -8 to x = -4.

To do this, we calculate the change in g(x) divided by the change in x (\(\Delta x\)).

The value of the function at x = -8 is g(-8) = (-8)^2 + 10(-8) + 23 = 64 - 80 + 23 = 7.

The value of the function at x = -4 is g(-4) = (-4)^2 + 10(-4) + 23 = 16 - 40 + 23 = -1.

Now, the average rate of change is given by the formula:

Average rate of change = (g(-4) - g(-8)) / (-4 - (-8))

= (-1 - 7) / (-4 + 8) = -8 / 4 = -2

So, the average rate of change of the function g(x) over the interval from x = -8 to x = -4 is -2.


Related Questions

Keely is planning a bridal shower for her best friend. At the party, she wants to serve 4 beverages, 3 appetizers, and 4 desserts, but she does not have time to cook. She can choose from 11 bottled drinks, 10 frozen appetizers, and 8 prepared desserts at the supermarket. How many different ways can Keely pick the food and drinks to serve at the bridal shower?

Answers

Answer:

The different ways in which Keely can pick the food and drinks to serve at the bridal shower is 2,772,000.

Step-by-step explanation:

Combinations is a mathematical procedure to determine the number of ways to select k items from n different items, without replacement and irrespective of the order of selection.

The formula to compute the combination of k items from n items is:

[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]

The menu for the bridal shower consists of:

Beverages: 4

Appetizers: 3

Dessert: 4

It is provided that Keely does not have time to cook. SO she goes to the supermarket and there she has the following options:

Beverages: 11

Appetizers: 10

Dessert: 8

Compute the number of ways Keely can select 4 beverages from 11 bottled drinks as follows:

[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]

[tex]{11\choose 4}=\frac{11!}{4!(11-4)!}[/tex]

      [tex]=\frac{11!}{4!\times 7!}[/tex]

      [tex]=\frac{11\times 10\times 9\times 8\times 7!}{4!\times 7!}[/tex]

      [tex]=330[/tex]

Keely can select 4 beverages in 330 ways.

Compute the number of ways Keely can select 3 appetizers from 10 frozen appetizers as follows:

[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]

[tex]{10\choose 3}=\frac{10!}{3!(10-3)!}[/tex]

      [tex]=\frac{10!}{3!\times 7!}[/tex]

      [tex]=\frac{10\times 9\times 8\times 7!}{3!\times 7!}[/tex]

      [tex]=120[/tex]

Keely can select 3 appetizers in 120 ways.

Compute the number of ways Keely can select 4 desserts from 8 prepared desserts as follows:

 [tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]

 [tex]{8\choose 4}=\frac{8!}{4!(8-4)!}[/tex]

      [tex]=\frac{8!}{4!\times 4!}[/tex]

      [tex]=\frac{8\times 7\times 6\times 5\times 4!}{4!\times 4!}[/tex]

      [tex]=70[/tex]

Keely can select 4 desserts in 70 ways.

Compute the total number of ways in which Keely can select 4 beverages, 3 appetizers, and 4 desserts for the party as follows:

Total number of ways = n (4 beverages) × n (appetizers) × n (dessert)

                                    [tex]={11\choose 4}\times {10\choose 3}\times {8\choose 4}[/tex]

                                    [tex]=330\times 120\times 70\\=2772000[/tex]

Thus, the different ways in which Keely  can pick the food and drinks to serve at the bridal shower is 2,772,000.

The area of a cross section at station 4+50 is 10.31 sq. in., and at station 5+00 is 14.18 sq. in. The horizontal scale of the cross section is 1" = 40’ and the vertical scale is 1" = 10’. What is the volume of earthwork between these two stations, in cubic yards, using the average end area method? Group of answer choices
A) 45
B) 18141
C) 9070
D) 907

Answers

Answer:

12233445555?????????

A comparative study of organic and conventionally grown produce was checked for the presence of E. coli. Results are summarized below. The Prevalence of E. Coli in Organic and Conventional Produce Sample Size E. Coli Prevalence Organic 200 5 Conventional 500 25 Is there a significant difference in the proportion of E. Coli in organic vs. conventionally grown produce? Test at α = 0.10. Be sure to report your hypotheses, show all work, and explain the meaning of your answer.

Answers

Answer:

The calculated z- value = 1.479 <  1.645 at 0.10 or 90% level of significance.

The null hypothesis is accepted at 90% level of significance.

There is no significant difference in the proportion of E. Coli in organic vs. conventionally grown produce.

Step-by-step explanation:

Step:-(i)

Given first sample size n₁ = 200

The first sample proportion     [tex]p_{1} = \frac{5}{200} = 0.025[/tex]

Given first sample size n₂= 500

The second sample proportion     [tex]p_{2} = \frac{25}{500} = 0.05[/tex]

Step:-(ii)

Null hypothesis :H₀:There is no significant difference in the proportion of E. Coli in organic vs. conventionally grown produce

Alternative hypothesis:-H₁

There is  significant difference in the proportion of E. Coli in organic vs. conventionally grown produce

level of significance ∝=0.10

Step:-(iii)

          The test statistic    

                                        [tex]Z =\frac{p_{1} - p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} } } }[/tex]

     where         p =   [tex]\frac{n_{1} p_{1} + n_{2}p_{2} }{n_{1}+n_{2} }= \frac{200X0.025+500X0.05 }{500+200}[/tex]

                     p = 0.0428

                     q = 1-p =1-0.0428 = 0.9572

                                   

                                      [tex]Z =\frac{0.025- 0.05}{\sqrt{0.0428X0.9571(\frac{1}{200 }+\frac{1}{500 } } }[/tex]

                                     Z = -1.479

                                    |z| = |-1.479|

                                    z = 1.479

The tabulated value z= 1.645 at 0.10 or 90% level of significance.

The calculated z- value = 1.479 <  1.645 at 0.10 or 90% level of significance.

The null hypothesis is accepted at 90% level of significance.

Conclusion:-

There is no significant difference in the proportion of E. Coli in organic vs. conventionally grown produce

                                 

A survey of UF students asked for their employment status and their year in school. The results appear below.

yr in school job no job
Freshman 16 22
Sophomore 24 15
Junior 17 20
Senior 25 19
Super Senior 8 5

What is the distribution of the test statistic under the null hypothesis

Answers

Answer:

There is no relationship between your year in school and having a job.

Step-by-step explanation:

In this instance, the chi sq test need to be performed.

Chi sq is used to determine if there is a significant relationship between two categorical variables.

The two variables here are year in school and employment status.

The two variables are independent(no relationship exists)

This implies that there is null hypothesis

Therefore, the Null Hypothesis is

There is no relationship between your year in school and having a job.

Use​ DeMoivre's Theorem to find the indicated power of the complex number. Write answers in rectangular form. [one half (cosine StartFraction pi Over 16 EndFraction plus i sine StartFraction pi Over 16 EndFraction )]Superscript 8

Answers

Answer:

[tex](\, \cos(\frac{\pi}{16}) + i\sin(\frac{\pi}{16}) \,)^{1/2} = \cos(\frac{\pi}{32}) + i\sin(\frac{\pi}{32}) = 0.99 + i0.09[/tex]

Step-by-step explanation:

The complex number given is

[tex]z = (\, \cos(\frac{\pi}{16}) + i\sin(\frac{\pi}{16}) \,)^{1/2}[/tex]

Now, remember that the DeMoivre's theorem states that

[tex]( \cos(x) + i\sin(x) )^n = \cos(nx) + i\sin(nx)[/tex]

Then for this case we have that

[tex](\, \cos(\frac{\pi}{16}) + i\sin(\frac{\pi}{16}) \,)^{1/2} = \cos(\frac{\pi}{32}) + i\sin(\frac{\pi}{32}) = 0.99 + i0.09[/tex]

A guitar had been marked down by 34% and sold for $825.
What is the original price of the guitar?

Answers

Final answer:

The original price of the guitar was $1250, calculated by taking the sale price of $825 and dividing it by 0.66, which represents the remaining percentage of the price after a 34% discount.

Explanation:

To find the original price of the guitar that has been marked down by 34% and sold for $825, we first need to consider that after the markdown, the guitar's price is equivalent to 100% - markdown percentage of the original price. In this case, it's 100% - 34% = 66% of the original price.

Let's denote the original price by P. Since 66% of P equates to $825, we can set up the following equation:

0.66  imes P = $825

Solving for P:

P = $825 / 0.66

P = $1250

Therefore, the original price of the guitar was $1250.

Suppose you are the CEO of a company that produces sheets of metal that are 1 centimeter thick. This metal is evaluated on the basis of its hardness which is determined by measuring the depth of penetration of a hardened point. Suppose that this depth of penetration is normally distributed with a mean of 1 millimeter and a standard deviation of .02 millimeters.

You are on trial for distributing faulty metal. If the metal is deemed faulty when the depth of penetration is more than 1.3 millimeters, what is the probability you are guilty?

Answers

Answer:

0% probability you are guilty

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 1, \sigma = 0.02[/tex]

If the metal is deemed faulty when the depth of penetration is more than 1.3 millimeters, what is the probability you are guilty?

This is 1 subtracted by the pvalue of Z when X = 1.3. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.3 - 1}{0.02}[/tex]

[tex]Z = 15[/tex]

[tex]Z = 15[/tex] has a pvalue of 1

1 - 1 = 0

0% probability you are guilty

Final answer:

We can use the z-score formula to calculate the probability of being guilty of distributing faulty metal based on the depth of penetration. The probability is practically zero.

Explanation:

To find the probability that you are guilty of distributing faulty metal, we need to calculate the probability that the depth of penetration is more than 1.3 millimeters. Since the depth of penetration is normally distributed with a mean of 1 millimeter and a standard deviation of 0.02 millimeters, we can use the z-score formula to standardize the value. The z-score is calculated as (x - μ) / σ, where x is the value we want to standardize, μ is the mean, and σ is the standard deviation.

Substituting the values into the formula, we have z = (1.3 - 1) / 0.02 = 15. Therefore, we need to find the probability that the z-score is greater than 15. Using a standard normal distribution table or calculator, we find that this probability is practically zero. Hence, the probability that you are guilty is practically zero.

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Gary has 63 counters.he pura them in an array with 9 columbs how many rows are there

Answers

There are 7 rows.
63/9 = 7.

What’s the answer to a^2b^2-100

Answers

Answer:

(ab - 10)(ab + 10)

Step-by-step explanation:

[tex] {a}^{2} {b}^{2} - 100 \\ = (ab) ^{2} - (10)^{2} \\ = (ab - 10)(ab + 10) \\ [/tex]

At a middle school, 30% of students buy lunch in the cafeteria and the remaining students bring lunch from home. A spinner with 10 equal-sized sections numbered 0-9 will be used to simulate the lunch trend. How can you design a simulation to guess whether the next 20 students buy lunch or bring lunch from home?

Answers

Allocating 3 portions to x and 7 portions to y.

Step-by-step explanation:

Given that,

The percentage of students buy lunch at cafeteria: 30% = x = 0.3

Hence, the students bringing the lunch from home would be = y = 1 - 0.3 = 0.7

Now, the spinner has that equal-sized sections. Also, the probability of x and y are 0.3 and 0.7.

After multiplying both the probability by 10, we get

x = 3

y = 7

It shows that for every three students who buy lunch from cafeteria, seven students bring food from home. Hence, we can allocate the side of spinner for simulation in such as way:

Section 0 = y

Section 1 = y

Section 2 = x

Section 3 = y

Section 4 = y

Section 5 = x

Section 6 = y

Section 7 = y

Section 8 = x

Section 9 = y

In 2014, the Community College Survey of Student Engagement reported that 32% of the students surveyed rarely or never use academic advising services. Suppose that in reality, 42% of community college students rarely or never use academic advising services at their college. In a simulation we select random samples from this population. For each sample we calculate the proportion who rarely or never use academic advising services. If we randomly sample 200 students from this population repeatedly, the standard error is approximately 3.5%. Is it unusual to see 32% who rarely or never use academic advising services in one of these samples

Answers

Answer:

[tex]Z = -2.865[/tex] means that it would be unusual to see 32% who rarely or never use academic advising services in one of these samples

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z scores below -2 are considered unusually low.

Z scores above 2 are considered unusually high.

For a sample proportion p in a sample of size n, we have that [tex]\mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this problem, we have that:

[tex]\mu = 0.42, \sigma = \sqrt{\frac{0.42*0.58}{200}} = 0.0349[/tex]

Is it unusual to see 32% who rarely or never use academic advising services in one of these samples

What is the z-score for X = 0.32?

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{0.32 - 0.42}{0.0349}[/tex]

[tex]Z = -2.865[/tex]

[tex]Z = -2.865[/tex] means that it would be unusual to see 32% who rarely or never use academic advising services in one of these samples

Final answer:

No, it is not unusual to see 32% of students rarely or never using academic advising services in one of these samples.

Explanation:

To determine if it is unusual to see 32% of students rarely or never using academic advising services in one of these samples, we can compare it to the range of values that would be considered usual. In this case, we can use the 95% confidence interval provided, which states that the true proportion of community college students who rarely or never use academic advising services is between 0.113 and 0.439. If the observed proportion falls within this interval, it would be considered usual; otherwise, it would be considered unusual.

Since 32% falls within the range of 0.113 and 0.439, it is considered a usual value. Therefore, it is not unusual to see 32% of students rarely or never use academic advising services in one of these samples.

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The average rainfall in Phoenix is 8.29 inches per year. The table shows recent data on the difference in annual rainfall from the average. Phoenix Annual Total Rainfall Year Rainfall compared to average yearly rainfall 2008 +6.57 inches 2009 –2.68 inches 2010 +12.26 inches 2011 –4.38 inches 2012 –4.46 inches Which list represents the years from driest to wettest?

Answers

Answer:

c

Step-by-step explanation:

survey on televisions requiring repairs within four years was conducted. Nineteen out of 200 televisions from company A and 25 out of 200 televisions from company B needed repairs. Do these data show that televisions from company A are more reliable than televisions from company B?

Answers

Answer:

[tex]z=\frac{0.095-0.125}{\sqrt{0.11(1-0.11)(\frac{1}{200}+\frac{1}{200})}}=-0.959[/tex]    

[tex]p_v =P(Z<-0.959)=0.169[/tex]    

Comparing the p value with the significance level assumed[tex]\alpha=0.05[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to to FAIL to reject the null hypothesis, and we can't conclude that company A are more reliable than televisions from company B at 5% of significance.

Step-by-step explanation:

Data given and notation    

[tex]X_{1}=19[/tex] represent the number of tvs who need a repair for A

[tex]X_{2}=25[/tex] represent the number of tvs who need a repair for B

[tex]n_{1}=200[/tex] sample 1 selected  

[tex]n_{2}=200[/tex] sample 2 selected  

[tex]p_{1}=\frac{19}{200}=0.095[/tex] represent the proportion estimated for the sample A  

[tex]p_{2}=\frac{25}{200}=0.125[/tex] represent the proportion estimated for the sample B

[tex]\hat p[/tex] represent the pooled estimate of p

z would represent the statistic (variable of interest)    

[tex]p_v[/tex] represent the value for the test (variable of interest)  

[tex]\alpha=0.05[/tex] significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if company A are more reliable than televisions from company B (that means p1<p2) , the system of hypothesis would be:    

Null hypothesis:[tex]p_{1} \geq p_{2}[/tex]    

Alternative hypothesis:[tex]p_{1} < p_{2}[/tex]    

We need to apply a z test to compare proportions, and the statistic is given by:    

[tex]z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}[/tex]   (1)  

Where [tex]\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{19+25}{200+200}=0.11[/tex]  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:    

[tex]z=\frac{0.095-0.125}{\sqrt{0.11(1-0.11)(\frac{1}{200}+\frac{1}{200})}}=-0.959[/tex]    

Statistical decision  

Since is a left sided test the p value would be:    

[tex]p_v =P(Z<-0.959)=0.169[/tex]    

Comparing the p value with the significance level assumed[tex]\alpha=0.05[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to to FAIL to reject the null hypothesis, and we can't conclude that company A are more reliable than televisions from company B at 5% of significance.    

Final answer:

To determine if televisions from company A are more reliable than televisions from company B, we can perform a hypothesis test.

Explanation:

To determine if televisions from company A are more reliable than televisions from company B, we can perform a hypothesis test. We will compare the proportions of televisions requiring repairs in the two companies.

Step 1: State the hypotheses:

H0: The proportion of televisions requiring repairs in company A is the same as in company B.

HA: The proportion of televisions requiring repairs in company A is less than in company B.

Step 2: Set the significance level, let's say α = 0.01.

Step 3: Calculate the test statistic. We will use the Z-test for comparing proportions.

Step 4: Calculate the p-value.

Step 5: Compare the p-value to the significance level. If the p-value is less than α, we reject the null hypothesis and conclude that televisions from company A are more reliable than televisions from company B.

By performing the above steps, we can determine if the data shows that televisions from company A are more reliable than televisions from company B.

The Harrisons drove 304.2 miles in 6.25 hours. What was their average speed, to the nearest tenth?

Answers

Answer:

The average speed was 48.7 miles per hour.

Step-by-step explanation:

The average speed v is given by the following formula:

[tex]v = \frac{d}{t}[/tex]

In which d is the distance, and t is the time.

The Harrisons drove 304.2 miles in 6.25 hours

This means that [tex]d = 304.2, t = 6.25[/tex]

We have the distance is miles and the time in hours, so the distance is in miles per hour.

So

[tex]v = \frac{304.2}{6.25} = 48.7[/tex]

The average speed was 48.7 miles per hour.

National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a desktop computer. Does this provide enough evidence to show a difference in the proportion of households that own a​ desktop? Identify the appropriate null and alternative hypotheses.

Answers

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, [tex]H_0[/tex] : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

                                  T.S.  = [tex]\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, test statistics  =  [tex]\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }[/tex]

                               =  2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

What is the missing angel in the triangle 69,34,

Answers

Answer:

77

Step-by-step explanation:

69+34=103

180-103=77

all triangles add up to 180

I hope this helps!

Answer:

The answer is 77

Step-by-step explanation: We know the angles add up to 180 in   a triangle. so we simply do 69+34=103 then we do 180-103= 77

There is a red, a green, and a yellow bulletin board hanging in the hallway. All of the bulletin boards are rectangular with a height of 4 feet. Their lengths are 6 feet, 5 feet, and 3 feet. The red bulletin board has the largest area and the yellow one has the smallest area. What is the area of the green bulletin board

Answers

Answer:

it would be 5 feet

Step-by-step explanation:

Need help with this question

Answers

Answer:

[tex] \overline{AB} \cong \overline{DB} \:\: and \:\: \overline{AC} \cong \overline{DC}[/tex]

Step-by-step explanation:

[tex] \red{ \boxed{ \bold{\overline{AB} \cong \overline{DB} \:\: and \:\: \overline{AC} \cong \overline{DC}}} }\\ \overline{BC} \cong \overline{BC}... (common\: side) \\ [/tex]

Dr. Potter provides vaccinations against polio and measles. Each polio vaccination consists of 4 doses and each measles vaccination consists of 2 doses. Last year Dr. potter gave a total of 60 vaccinations that consisted of a total of 184 doses. How many polio vaccinations did dr. potter give last year

Answers

Answer:

Dr. Potter gave 32 polio vaccinations and 28 measles vaccinations

Step-by-step explanation:

Total of 184 doses

Polio vaccination= 4 doses

Measles vaccination=2 doses

184=4p+2m

92=2p+m

Lets plug in 32+28

92=(2*32)+28

92=64+28

p=32, m=28

A total of 58 trophies will be given out at the swim meet each box holds 6 trophies how many boxes are needed to carry the trophies

Answers

Answer:

You will need 10 boxes

Step-by-step explanation:

Nine boxes will only hold 54 trophies so you need one more than nine.

Answer:

You will need 348 boxes for the trophies

Step-by-step explanation:

just multiply 58 and 6

uppose a small cannonball weighing 16 pounds is shot vertically upward, with an initial velocity v0 = 290 ft/s. The answer to the question "How high does the cannonball go?" depends on whether we take air resistance into account. If air resistance is ignored and the positive direction is upward, then a model for the state of the cannonball is given by d2s/dt2 = −g (equation (12) of Section 1.3). Since ds/dt = v(t) the last differential equation is the same as dv/dt = −g, where we take g = 32 ft/s2. If air resistance is incorporated into the model, it stands to reason that the maximum height attained by the cannonball must be less than if air resistance is ignored. (a) Assume air resistance is proportional to instantaneous velocity. If the positive direction is upward, a model for the state of the cannonball is given by m dv dt = −mg − kv, where m is the mass of the cannonball and k > 0 is a constant of proportionality. Suppose k = 0.0025 and find the velocity v(t) of the cannonball at time t.

Answers

Final answer:

Solving for the velocity v(t) of a cannonball considering air resistance involves integrating the differential equation m dv/dt = -mg - kv, where k is a constant of proportionality. Given initial conditions, this allows one to calculate the cannonball's velocity at any time.

Explanation:

A student has asked how to find the velocity v(t) of a cannonball, considering air resistance, modeled by m dv/dt = -mg - kv, where m is the mass of the cannonball, g is the acceleration due to gravity (32 ft/s2), and k is a constant of proportionality (0.0025). Given the initial velocity v0 = 290 ft/s, the solution involves solving this differential equation with the given initial condition.

However, solving this specific differential equation requires integration techniques that account for the linear dependence of the air resistance on the velocity, which will yield an expression for v(t) as a function of time t. This formula can then be used to calculate the velocity of the cannonball at any given time, illustrating how air resistance affects its ascent and eventual descent.

Suppose it is known that 10% of all people in Texas have a specific blood type. Suppose we take a random sample of 500 Texas residents. We want to find chance that fewer than 40 Texas residents in this sample have that blood type. In the next 4 questions, find the box model, the average and standard deviation of the box and use these values to find the expected value and standard error. Then calculate the associated chance of having fewer than 40 Texas residents in the sample with that specific blood type. Suppose you calculated EV and SE correctly in the previous two problems. The chance that fewer than 40 Texas residents in this sample have that blood type is the area under the normal curve to the:

Answers

Answer:

a) 50

b) 6.71

c) 0.0681

Step-by-step explanation:

check the attached file below

Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each other; objects of type B are indistinguishable from each other; and objects of type C are indistinguishable from each other. In how many ways can you Pick 5 of the 18 objects (order does not matter)

Answers

Answer:

[tex] \binom{18}{5}= 8568[/tex]

Step-by-step explanation:

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient [tex]\binom{n}{k})[/tex].

Therefore, in this case the total number of ways is just [tex]\binom{18}{5}=8568[/tex]

Answer:

Given:

Number of objects: n = 18

Type A objects: 10

Type B objects: 5

Type C objects: 3

To find:

In how many ways can you Pick 5 of the 18 objects (order does not matter)

Step-by-step explanation:

When the order does not matter we use Combination.

Formula to calculate combination:

C(n,r) = n! / r! ( n - r )!

n = 18

r = 5

Putting the values:

C(n,r)

= C(18,5)

= 18! / 5! ( 18 - 5 )!

= 18! / 5! ( 13 )!

= ( 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 ) / ( 5 * 4 * 3 * 2 * 1 ) * (13 * 12 * 11 * 10 *9* 8 * 7 *6 * 5 * 4 * 3 * 2 *1 )

Cancel 13!

= (18 * 17 * 16 * 15 * 14 ) / ( 5 * 4 * 3 * 2 * 1 )

= 1028160 / 120

= 8568

So you can pick 5 of the 18 objects in 8568 ways.

What is the solution of a system defined by 5x + 2y = 30 and -5x + 4y = 0?

Answers

Answer:

x=4 y=5

Step-by-step explanation:

5x + 2y = 30 and -5x + 4y = 0

Solve by adding the two equations together to eliminate x

5x + 2y = 30

-5x + 4y = 0

----------------------

   6y = 30

Divide each side by 6

6y/6 = 30/6

y =5

Now we solve for x

5x + 2y = 30

5x +2(5) = 30

5x+10 = 30

Subtract 10 from each side

5x+10-10 = 30-10

5x = 20

Divide each side by 5

5x/5 = 20/5

x = 4

A certain circle can be represented by the following equation. x2 + y2 + 10x + 12y + 25 = 0. What is the center of this circle? What is the radius of this circle? Please help!

Answers

Let's try to complete the squares.

The x-part starts with [tex]x^2+10x[/tex], which is the beginning of [tex]x^2+10x+25=(x+5)^2[/tex]. So, we'll think of [tex]x^2+10x[/tex] as [tex](x+5)^2-25[/tex]

Similarly, we have that

[tex]y^2+12y = (y+6)^2-36[/tex]

So, the equation becomes

[tex]x^2 + y^2 + 10x + 12y + 25 = 0 \iff (x+5)^2-25 + (y+6)^2-36+25=0 \iff (x+5)^2+ (y+6)^2-36=0 \iff (x+5)^2+ (y+6)^2=36[/tex]

Now we have writte the equation of the circle in the form

[tex](x-k)^2+(y-h)^2=r^2[/tex]

When the equation is in this form, everything is more simple: the center is [tex](k,h)[/tex] and the radius is [tex]r[/tex].

Answer:

Center// (-5,-6)

Radius// 6

In circle K with mLJKL = 112 and
JK = 7 units find area of sector JKL.
Round to the nearest hundredth.​

Answers

Area of the sector JKL is 47.89 unit²

How the area of the sector is calculated

From the figure

Given that

JKL is a sector that subtends ∠JKL at the center of the circle JL.

The radius of the circle is KL or JK

Area of a sector = θ/360 * πr²

where

r is the radius

θ is angle subtended at the center

m∠JKL = 112⁰ = θ

JK = 7 units = radius

Therefore,

Area = 112/360*π(7)²

A = 112/360 * 3.142 * 49

= 17243.296/360

= 47.89 unit²

Therefore, area of the sector JKL is 47.89 unit²

Write out the following sums, one term for each value of k. Simplify each term as much as possible, but do not enter decimals. For example, enter 1+4+9 instead of 12+22+32 or 14, or enter 1/2+1/2 instead of 0.5+0.5 or 1. The purpose of this problem is for you to show that you know how to interpret summation notation and write all of the terms in a sum, which is why you are being told not to reduce your answers very much.

Answers

The correct question is:

Write out the following sums, one term for each value of k. Simplify each term as much as possible, but do not enter decimals. For example, enter 1 + 4 + 9 instead of 1² + 2² + 3² or 14, or enter 1/2 + 1/2 instead of 0.5 + 0.5 or 1.

The purpose of this problem is for you to show that you know how to interpret summation notation and write all of the terms in a sum, which is why you are being told not to reduce your answers very much.

[tex](a) \sum_{k=0}^5 2^k \\ \\(b) \sum_{k=2}^7 \frac{1}{k} \\ \\(c) \sum_{k=1}^5 k^2 \\ \\(d) \sum_{k=1}^6 \frac{1}{6} \\ \\(e) \sum_{k=1}^6 2k[/tex]

Answer:

[tex](a) \sum_{k=0}^5 2^k = $1 + 2 + 4 + 8 + 16 + 32$ \\ \\(b) \sum_{k=2}^7 \frac{1}{k} = \frac{1}{2} + \frac{1}{3} + \frac{1}{4}+ \frac{1}{5}+ \frac{1}{6}+ \frac{1}{7} \\ \\(c) \sum_{k=1}^5 k^2 = 1 + 4 + 9 + 16 + 25 \\ \\(d) \sum_{k=1}^6 \frac{1}{6} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} \\ \\(e) \sum_{k=1}^6 2k = 2 +4 +6 +8 +10 +12[/tex]

Step-by-step explanation:

[tex](a) \sum_{k=0}^5 2^k\\For k = 0: 2^k = 2^0 = 1\\For k = 1: 2^1 = 2\\For k = 2: 2^2 = 4\\For k = 3: 2^3 = 8\\For k = 4: 2^4 = 16\\For k = 5: 2^5 = 32\\\sum_{k=0}^5 2^k = 1 + 2 + 4 + 8 + 16 + 32[/tex]

[tex](b) \sum_{k=2}^7 \frac{1}{k}\\For k = 2: 1/2\\For k = 3: 1/3\\For k = 4: 1/4\\For k = 5: 1/5\\For k = 6: 1/6\\For k = 7: 1/7\\ \sum_{k=2}^7 \frac{1}{k} = 1/2 + 1/3 + 1/4 + 1/5 + 1/6+ 1/7[/tex]

[tex](c) \sum_{k=1}^5 k^2\\For k = 1: 1^2 = 1\\For k = 2: 2^2 = 4\\For k = 3: 3^2 = 9\\For k = 4: 4^2= 16\\For k = 5: 5^2 = 25\\\sum_{k=1}^5 k^2 = 1 + 4 + 9 + 16 + 25[/tex]

[tex](d) \sum_{k=1}^6 \frac{1}{6}\\For k = 1: 1/6\\For k = 2: 1/6\\For k = 3: 1/6\\For k = 4: 1/6\\For k = 5: 1/6\\For k = 6: 1/6\\ \sum_{k=1}^6 \frac{1}{6} = 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6[/tex]

[tex](e) \sum_{k=1}^6 2k\\For k = 1: 2\times1 = 2\\For k = 2: 2\times2 = 4\\For k = 3: 2\times3 = 6\\For k = 4: 2\times4 = 8\\For k = 5: 2\times5 = 10\\For k = 6: 2\times6 = 12\\\sum_{k=1}^6 2k = 2 +4 +6 +8 +10 +12[/tex]

A box is 4 inches wide, 5 inches long and 3 inches tall. What’s the equation that would be used to find the surface area of the box?

Answers

Equation used to determine the surface area of the box : 2( lb + bh + lh)

Surface area of the box : 94in²

Given, A box is 4 inches wide, 5 inches long and 3 inches tall.

Formula of surface area of cuboid : 2( lb + bh + lh)

Here,

l = 5in

b = 4in

h = 3in

Substitute the values,

Surface area = 2(5×4 + 4×3 + 5×3)

Surface area = 94in²

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A florist charges ​$12.00 for delivery plus an additional ​$1.50 per mile from the flower shop. The florist pays the delivery driver ​$0.75 per mile and ​$4.50 for gas per delivery. If x is the number of miles a delivery location is from the flower​ shop, what expression models the amount of money the florist earns for each​ delivery?

Answers

Final answer:

The amount the florist earns for each delivery, with 'x' being the miles away from the flower shop, can be modeled with the equation: Earnings = (7.5 + 0.75x). This represents the fixed net income of $7.5 and $0.75 per mile after paying the driver.

Explanation:

The florist charges ​$12.00 for delivery and an additional ​$1.50 per mile from the flower shop. However, the florist also has costs to cover, namely $0.75 per mile to pay the driver, and ​$4.50 for gas per delivery. The net earning per delivery, with 'x' representing the number of miles a delivery location is from the flower shop, can be modeled by the following algebraic expression: Earnings = (12 + 1.5x) - (0.75x + 4.5).

This actually simplifies to: Earnings = (7.5 + 0.75x). The 7.5 is the fixed net income for each delivery (gross earnings minus the gasoline cost) and 0.75x is the per-mile net income after the driver is paid.

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What is the volume of this rectangular prism? 10/3 cm 4/5 cm 1/5 cm

Answers

Final answer:

The volume of the rectangular prism with dimensions 10/3 cm, 4/5 cm, and 1/5 cm is 8/15 cm³.

Explanation:

The volume of a rectangular prism can be found using the formula: Volume = length x width x height. In this case, the length, width, and height of the prism are given as 10/3 cm, 4/5 cm, and 1/5 cm respectively. Replace these dimensions in the formula:

Volume = (10/3 cm) x (4/5 cm) x (1/5 cm) = 8/15 cm³.

Therefore, the volume of the rectangular prism is 8/15 cm³.

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